To read and understand electrical blueprints, you need to know

A. the fundamentals of electrical engineering.
B. how buildings are constructed.
C. how to sketch a plan view.
D. the meaning of electric symbols.

Answer: 9 × 10¹⁶ m²/s² (square of speed of light in vacuum)

Explanation:

Einsteins' energy mass relation:

E = mc²

Where, E is energy, m is mass and c is the speed of light.

The ratio of rest energy to rest mass:

[tex]\frac{E_o}{m_o} = c^2[/tex]

speed of light in vacuum is 3 × 10⁸ m/s

Hence, the numerical quantity of the ratio of rest energy/ rest mass = (3 × 10⁸ m/s)² = 9 × 10¹⁶ m²/s².

The Arctic fox is well adapted to its environment with seasonal coat color changes for camouflage and longer, denser winter fur for insulation against the cold.

The Arctic fox is a highly adapted species that thrives in the cold climates of the Arctic region. These foxes have developed several adaptations that make them well-suited for survival in their environment. Changing coat color with the seasons is one such adaptation, allowing Arctic foxes to maintain camouflage against snowy backgrounds in winter and rocky terrains in other seasons.

Furthermore, the longer fur that these animals grow in winter helps them to trap heat more effectively, ensuring they stay warm despite the freezing temperatures. This fur is not just longer, but also denser, adding an extra layer of insulation. Such physical adaptations, alongside behavioral ones like burrowing and hunting tactics, have equipped Arctic foxes to be masterful inhabitants of their harsh and unrelenting environment.

T = half life of cobalt-60 = 5.3 years

λ = decay constant for cobalt-60 = ?

decay constant is given as

λ = 0.693/T

inserting the values

λ = 0.693/5.3 = 0.131

N₀ = initial amount of cobalt-60 = 10 g

t = time of decay = 21.2 years

N = final amount of cobalt-60 after time "t"

final amount of cobalt-60 after time "t" is given as

N = N₀ [tex]e^{-\lambda t}[/tex]

inserting the values

N = 10 [tex]e^{-(0.131) (21.2)}[/tex]

N = 10 [tex]e^{-(0.131) (21.2)}[/tex]

N = 10 x 0.0622 g

N = 0.63 g

hence

C. 0.63 g

POWER OF CIRCUIT

P=VI

While,

VOLTAGE OF CIRCUIT

V=IR

THEN,

P=I^R

P/R=I^

2.00/30.0=I^

I=0.258A.

Answer:0.258

Explanation:

Hi there,

the following injuries that include instability of the knee with pain and swelling is ACL Tear.

The ACL tear is common especially in sports like football one wrong move and you fall and tear your ACL

Hope this helped :)

Have a great day

A.) Light waves can travel through a vacuum.

The answer is A, light waves eliminate

Well, if there were no air resistance, then a helicopter couldn't fly.  But let's do the physics and the Math anyway:

The way gravity works, the speed of a falling object increases at the rate of 9.8 m/s every second.

So, after falling for 12 seconds, its speed is (12 x 9.8) = 117.6 m/s .

After 12 seconds of her jump from th helicopter, her velocity would be 117.6 m/s.

The second and third equations of motion are -

S = ut + 1/2 at²

v² - u² = 2aS

Given is a skydiver who jumps from a helicopter hovering at high altitude.

We can write -

[a] = 9.8 m/s²

[t] = 12 s

[u] = 0 m/s

Using the second equation of motion, we get -

S = ut + 1/2 at²

S = 1/2 at²

putting values -

S = 1/2 x 9.8 x 12 x 12

S = 705.6 m

Using the third equation of motion, we get -

v² - u² = 2aS

v² = 2aS

putting values -

v² = 2 x 9.8 x 705.6

v² = 13829.7

v = 117.6 m/s

Therefore, after the 12 seconds of her jump from the helicopter, her velocity would be 117.6 m/s.

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Answer:

Centripetal force

Explanation:

The object that keeps an object in a circle is called uniform circular motion. In this type of motion, the distance covered by an object is equal to the circumference of the circle. The mathematical form of centripetal force is given by,

From second law of motion,

F = m × a

a is the centripetal acceleration

[tex]F=\dfrac{mv^2}{r}[/tex]

So, the correct option is (a) '' centripetal force''.

Given data

          mass (m) = 0.2 Kg ,

       velocity (v) =300 m/s ,

      calculate momentum (p) = m × v  

                                                = 0.2 × 300

                                              P  = 60 Kg. m/s

Momentum of the bullet is 60 Kg. m/s..

a=Δv/Δt=(30.0-18.0)/8.0=12.0/8.0=1.5 m/s²

Final answer:

The magnitude of the car's acceleration is calculated using the change in velocity over the time taken. With a change in velocity of 12.0 m/s over 8.0 seconds, the car's acceleration is 1.5 m/s².

Explanation:

To find the magnitude of the car's acceleration, we can use the formula for acceleration, which is the change in velocity (Δv) divided by the time (Δt) it takes for that change. In this case, the car's velocity increases from 18.0 m/s to 30.0 m/s over 8.0 seconds.

We calculate acceleration (a) as follows:

a = Δv / Δt

Δv = final velocity - initial velocity = 30.0 m/s - 18.0 m/s = 12.0 m/s

Δt = 8.0 s

Thus, a = 12.0 m/s / 8.0 s = 1.5 m/s².

The magnitude of the car's acceleration is 1.5 m/s².

Answer:

a = -.51 m/s²

coefficient of friction = .05

fk= 12.25 N

Explanation:

mass = 20 + 5kg

weight = 25kg ·9.8 = 245 N

There are many ways to do this I am sure but I did this:

1.  found a by using vf²=vi²-2aΔx. accel is - because it is slowing down.

started at 4.5 m/s, final = 0 and Δx=20....a=-.51 m/s²

2.  the force acting on the object is the friction force which has to equal the mass(accel).

-fk (going to left on free body diagram) = ma

-mu·n = ma

-mu·245N = 25 (-.51)

mu=.05

fk= .05(245N) = 12.25 N

The kinematics and Newton's second law allow to find the results for the questions of the movement of the child and the skateboard are:

  a) the deceleration is a = 0.51 m / s²

  b) The friction force is: fr = 12.75 N

  c) The friction coefficient is equal to: μ = 0.052

Given parameters

To find

    a) Acceleration.

    b) The friction force.

    c) The coefficient of friction.

a) Kinematics studies the movement of bodies, finding relationships between their position, speed and acceleration.

Since the child ends up at rest, his final velocity is zero (v = 0), let's use the relation.

       v² = v₀² - 2 a x

       0 = v₀² - 2ax

       a = [tex]\frac{v_o^2}{2x}[/tex]  

       a = [tex]\frac{4.5^2 }{2 \ 20}[/tex]

       a = 0.51 m / s²

b) Newton's second law states that the net force is proportional to the product of the mass and the acceleration of the body.

A free-body diagram in a diagram of the forces without the details of the body, in the attached we can see the free-body diagram of the system.

Let's write Newton's second law, since the boy and the scooter do not separate, we use the total mass.

y-axis

     N-W = 0

     N = W

     N = (M + m) g

     N = (20 +5) 9.8

     N = 245 N

x-axis

     fr = [tex]m_{total} \ a[/tex]  

     Fr = (20+ 5) 0.51

     fr = 12.75 N

c) Friction force is a macroscopic force of the interactions between the two surfaces and has the formula.

       fr = μ N

       μ = [tex]\frac{fr}{N}[/tex]

       μ = 12.75 / 245

       μ = 0.052

In conclusion, using kinematics and Newton's second law we can find the results for the questions of the movement of the boy and the skateboard are:

  a) The deceleration is a = 0.51 m / s²

  b) The friction force is: fr = 12.75 N

  c) The friction coefficient is equal to: μ = 0.052

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The answer will be letter B.

Answer:

b

Explanation:

the box moves toward gina

Answer:

3.99 kg

Explanation:

The period of a harmonic oscillator is given by:

[tex]T=2 \pi \sqrt{\frac{m}{k}}[/tex]

where

m is the mass attached to the spring

k is the spring constant

In this problem, we know:

k = 712 N/m

T = 0.47 s

Therefore, we can re-arrange the equation to find the mass that should be attached to the oscillator:

[tex]m=\frac{k T^2}{(2 \pi)^2}=\frac{(712 N/m)(0.47 s)^2}{(2 \pi)^2}=3.99 kg[/tex]

A mass of 3.97 kg should be attached.

The student asks what mass should be attached to a spring for a horizontal spring oscillator to oscillate with a period of 0.47 seconds, given the spring constant is 712 N/m and there is no friction. To find the mass, we use the formula for the period T of a simple harmonic oscillator: T = 2π√(m/k), where m is the mass in kilograms and k is the spring constant in newtons per meter. Rearranging the formula to solve for m gives us m = (T/(2π))2 × k.

Plugging in the given values:

Calculate (0.47 / (2π))2 = 0.005577... (rounded to nine decimal places).

Multiply this by the spring constant 712 N/m gives us 0.005577 × 712 = 3.970544 kg.

Therefore, the mass that should be attached to the spring is approximately 3.97 kg.

Answer:

The type of current described by the given statements is D.C. (or direct Current).

Explanation:

There are two different types of currents. They are Alternating Current (AC) and Direct current (DC) . Alternating current varies alternately, as the name suggests. DC is used for devices that need low voltage, like the chargers of a mobile phone. Domestic power supply is  AC .

The type of current described by these statements is direct current (DC).

The type of current described by these statements is direct current (DC). Direct current flows in one direction from the negative terminal to the positive terminal. It is commonly created by batteries. However, it is generally not found in U.S. electrical outlets, which typically provide alternating current (AC). Alternating current changes direction periodically.

Direct current (DC) is an electric current that flows consistently in one direction. In a DC circuit, electrons move from the negative terminal to the positive terminal of a voltage source, such as a battery. DC is used in many electronic devices while alternating current (AC) periodically changes direction and is typically used for power distribution.

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Given data

Source temperature (T₁) = 177°C = 177+273 = 450 K

Sink temperature (T₂) = 27°C = 27+273 = 300 K

Energy input (Q₁) = 3600 J ,

Work done = ?

                We know that, efficiency (η) = Net work done ÷ Heat supplied

                                                           η =   W ÷ Q₁  

                                                           W = η × Q₁

               First determine the efficiency ( η ) = ?

                                Also, we know that ( η ) = (T₁ - T₂) ÷ (T₁)

                                                                        = 33.3% = 0.333

               Now, Work done is W = η × Q₁

                                                    = 0.33 × 3600

                                                   W = 1188 J

Work done by the engine is 1188 J

A. Formula: F=ma or F/m=a

10,000N/1,267kg≈7.9m/[tex]s^{2}[/tex]

B. Formula: a=[tex]\frac{V-V_{0} }{t}[/tex] and s=d/t

speed= 394.6/15

s=26.3m/s

a=[tex]\frac{26.3-0}{15}[/tex]

a=1.75m/[tex]s^{2}[/tex]

C. 7.9-1.75=difference of 6.15m/[tex]s^{2}[/tex]

D. The force that most likely caused this difference is friction forces

Answer:

Part a)

[tex]a = 7.89 m/s^2[/tex]

Part b)

[tex]a = 3.51 m/s^2[/tex]

Part c)

[tex]\Deltra a = 4.38 m/s^2[/tex]

Part d)

This difference in acceleration  is due to some frictional force on the surface.

Part e)

[tex]F_f = 5552.8 N[/tex]

Explanation:

Part a)

As we know by newton's II law

[tex]F = ma[/tex]

here we know that

[tex]m = 1267 kg[/tex]

[tex]F = 10,000 N[/tex]

Now we have

[tex]a = \frac{F}{m}[/tex]

[tex]a = \frac{10,000}{1267}[/tex]

[tex]a = 7.89 m/s^2[/tex]

Part b)

distance covered by the car

[tex]d = 394.6 m[/tex]

t = 15 s

now by kinematics we have

[tex]d = \frac{1}{2}at^2[/tex]

[tex]394.6 = \frac{1}{2}a(15^2)[/tex]

[tex]a = 3.51 m/s^2[/tex]

Part c)

Difference of acceleration is given as

[tex]\Delta a = a_{expected} - a_{real}[/tex]

[tex]\Delta a = 7.89 - 3.51 [/tex]

[tex]\Deltra a = 4.38 m/s^2[/tex]

Part d)

This difference in acceleration  is due to some frictional force on the surface.

Part e)

Now for magnitude of force is given as

[tex]F - F_f = ma[/tex]

[tex]10,000 - F_f = ma[/tex]

[tex]10,000 - F_f = 1267\times 3.51[/tex]

[tex]F_f = 5552.8 N[/tex]

You haven't told us the "wattage" rating of the bulb.  We'll just have to call it ' W ' .

The bulb uses energy at the rate of W watts, or 0.001W kilowatts.

In 12 hours, it uses 0.012W kilowatt-hours of energy.

= = = = =

W watts = W Joules/second

1 hour = 3600 seconds

12 hours = (12 x 3600) seconds

Energy = (W Joule/sec) x (12 x 3600 sec)

Energy =  43,200W Joules

Final answer:

The energy used by a 100W incandescent bulb is 4,320,000 joules

Explanation:

Calculating Energy Use of an Incandescent Bulb

To calculate the energy used by an incandescent bulb left on for 12 hours, we need to know the power rating of the bulb. However, if we take a typical 100W incandescent bulb as an example, we can use the formula for electrical energy (Energy = Power *Time) to find out the energy consumption in watt-hours (Wh) and then convert it to joules (J). The power rating is usually mentioned on the bulb itself.

For a 100W bulb left on for 12 hours:

Energy in watt-hours = Power*Time

Energy in watt-hours = 100 W * 12 h = 1200 wh

Since 1 watt-hour is equal to 3600 joules,

Energy in joules == 4320000 J

Therefore, a 100W incandescent bulb uses 4320000 joules of energy when left on for 12 hours.

Graphite is great lubricant because each carbon atom forms weak covalent bonds with three other carbon atoms.

Diamond and graphite both are entirely made up of carbon but both the elements are completely different because of the bonding of carbon atoms. In graphite the carbon atoms form weak covalent with the other three carbon atom due to which there is less or no force between the atoms, and makes the graphite very soft and slippery, and graphite act as lubricant.

Answer:

Carbon atoms form strong bonds within each graphite layer but weak bonds between layers.

Explanation:

Graphite is known as solid lubricant which means it is a lubricant which is in the solid state form.

Here we know that lubricant has function to make the relative movement very smooth or easy.

So here in structure of graphite it is formed in such a way that all carbon atoms in graphite layer are bonded strongly with each other. While two layers of graphite are weakly bonded to each other

So here two layers of graphite can easily slide over each other which is useful for the function of lubricants

So correct answer will be

Carbon atoms form strong bonds within each graphite layer but weak bonds between layers.

The enclosed may help ....

Final answer:

The tension force is the force transmitted through a flexible connector, like a rope or cable, when it is pulled on both ends. To solve for the tension force, consider the forces acting on the object connected by the rope and apply Newton's laws of motion.

Explanation:

In physics, tension force refers to the force that is transmitted through a flexible connector, such as a rope or a cable, when it is pulled on both ends.

To solve for the tension force, you need to consider the forces acting on the object connected by the rope or cable. This can be done by applying Newton's laws of motion.

For example, if you know the weight of the object and the angle at which the rope or cable is inclined, you can use trigonometry to calculate the tension force.

Answer: option B: Power is the rate at which work is done.

Explanation:

Power can be defined as the amount of work done or amount of energy transferred in a unit time.

[tex]P = \frac{W}{t}[/tex]

Its unit is J/s.

SI unit of power is kg⋅m²⋅s⁻³

Hence, the best expression of power out of the given options is rate at which work is done. Option B is correct.

Answer:  The correct answer is "The food cooks inside the foil".

Explanation:

In conduction , there is no actual movement of matter. Heat flows from the hotter body to the colder body but when the two bodies are placed in contact with each other.

In convection, there is a physical movement of matter.

Radiation is the emission of the energy. Heat travels through a vacuum in the radiation.

In the given problem, Devon places sliced potatoes in a package of aluminum foil. He puts a metal grate over a campfire and sets the package on the grate.  

When he removes the foil package, the grate and foil are hot, and the food is cooked. Here, the heat is transferred from the campfire to the metal grate to the aluminium fire and then to the food. The metal grate and the aluminium foil are in contact with each other. Here, the conduction takes place.

Therefore, the scenario, "The food cooks inside the foil" represents the conduction from the given option.

Answer:

the food makes contact with the foil wich represents conduction so the answer is  A, hope this helps ( ;w;)

Explanation: