Trey went to the batting cages to practice hitting. he rented a helmet for $4 and paid $0.75 for each group of 20 pitches. if he spent a total of $7 at the batting cages, how many groups of pitches did he pay for?

Answers

Answer 1
My man paid for 4 groups of 20.

Related Questions

Find the sum of the arithmetic sequence. 15, 17, 19, 21, ..., 33

Answers

as formula says:

sum = [tex] n *\frac{ a_{1} + a_{n} }{2} [/tex]

in our case n = 10, a1 = 15 and An = 33 so the answer will be:

sum = 10 * (33 + 15)/2 = 10 * 48 / 2 = 10 * 24 = 240

Answer:

240

Step-by-step explanation:

Hope this helps! :)

What is the problem to this

Answers

4:9
24:x
Set up a proportion
4/9=24/x
4x=216
x=54
a) 54 is your answer
hope this helps, and please give brainliest if it does!
The answer is:  [A]:  " 54 " .
__________________________
Given: "For every 4 people that made the team, 9 people did not make the team.  24 people made the team.  How many did NOT make the team?

24 people made the team.  How many groups of 4 people is that?

24 divided by 4 equals:  "6".
__________________________
  6 * 9 = 54 .
__________________________
  The answer is:  [A]:  " 54 " .
__________________________

Suppose a youth organization wants to choose a president, vice-president and secretary for the upcoming year from its 35 person membership. In complete sentences, explain why this is a permutation. Determine how many different ways the youth board can be chosen.

Answers

P(n, r)=[tex] \frac{n!}{(n-r)!} [/tex]

is the formula which gives the total number of permutations of r objects out of n.

A permutation means an arrangement in a list, be it horizontally, or vertically.

So there is a first place, a second and so on.

Example: a, b, c and a, c, b are 2 different permutations.


with these in mind:


the problem described is a permutation problem, because the order is important. 

We do not only care whether a certain person is chosen among the 3, we also care what position he/she will hold.

The total number of permutations of 3 objects out of 35 is calculated by the formula:

[tex]P(35, 3)=\frac{35!}{(35-3)!}=\frac{35!}{(32)!}= \frac{35*34*33*32!}{32!}=35*34*33=39,270[/tex]


Answer: 39, 270


On a blueprint, the scale indicates that 7 cm represent 16 ft. What is the length of a room that is 9.8 cm long and 5 cm wide on the blueprint?

Answers

7/16 =9.8/ x =156.8/7 = 22.4 feet long

7/16 = 5/x = 80/7 = 11.428 feet wide round to 11.43 or 11.4 feet

Simplify 12 to the 16th power over 12 to the 4th power

Answers

Hello there!

[tex] \frac{ 12^{16}}{12^{4} } [/tex]

Do solve for this, we actually just have to do one thing since our number is the same - subtract the exponents.

When you divide by exponents, you are subtracting them. 

For example;

[tex] \frac{ x^{5} }{x^{2} } [/tex]

Subtract the exponents.

[tex] x^{3} [/tex] is your answer for this example.

Let's apply this to our current expression.

[tex] \frac{ 12^{16}}{12^{4} } [/tex]

Subtract the exponents.

[tex] 12^{12} [/tex] is your simplified expression with exponents.

I hope this helps!

What is recorded in section 24 of cms-1500?

Answers

Procedures performed for a patient.

If a seed is planted, it has a 90% chance of growing into a healthy plant. if 7 seeds are planted, what is the probability that exactly 4 don't grow?

Answers

Answer:

0.098415

Step-by-step explanation:

The way the question is worded is odd and you should probably actually include “don’t grow into a healthy plant” or something. You can use the binomial distribution. Suppose ∼Bin(6,0.1)  so the probability that k trees don’t grow into a healthy plant is

Pr( = ) = (6 / ) 0.16^ 0.9^6−

Then the probability that two don’t grow into healthy plants is

Pr( = 2) = (6/2) 0.1^2 0.9^4

this is equal to 0.098415

Final answer:

To calculate the probability of exactly 4 out of 7 seeds failing to grow, use the binomial probability formula with n = 7, p = 0.10, and k = 4. The calculation involves combinations and exponentiation.

Explanation:

The question is asking for the probability of exactly 4 seeds out of 7 failing to grow. Given that each seed has a 90% chance of growing into a healthy plant, which means each seed has a 10% (1 - 0.90) chance of not growing. To solve this, we can use the binomial probability formula: P(X = k) = C(n, k) * (pk) * ((1 - p)n - k), where n is the number of trials, p is the probability of success, and k is the exact number of successes. In this case, n = 7, p = 0.10 and k = 4. So, we get:

P(X = 4) = C(7, 4) * (0.104) * (0.907 - 4)

The calculation of this probability requires the use of combinations and exponentiation, providing the specific likelihood of having exactly 4 seeds out of 7 not growing into a healthy plant.

Learn more about Probability here:

https://brainly.com/question/22962752

#SPJ13

If EF = HG and HG = 16, find the diameter of K

Answers

The diameter of K would be 20. 

Answer:

Diameter of the circle K = 20 units

Step-by-step explanation:

Given that : EF = HG

Also, HG = 16 units

⇒ EF = 16 units

Now, any line drawn perpendicular to the chord always bisects the chord

⇒ KI will bisect the chord EF

⇒ EI = 8 units

Now, in ΔEIK using Pythagoras theorem we have :

⇒ EK² = 8² + 6²

⇒ EK² = 100

⇒ EK = 10 units

So, Radius of the circle K = 10 units

Now, Diameter of the circle K = 2 × 10

                                                  = 20 units

Find the product.

(-5a ^2)^3 · a ^5

-15a^10
-125a^11
15a^6
-125a^10

Answers

[tex](-5a ^2)^3 * a ^5 = (-5)^3 * a^5 * a^5 = -125* a^{10} [/tex]

Hence, the answer is D. 

A farmer kept 96 kilograme of animals feed inhis barn the barn leaked and 1/10 of the feed was waisted , how mych animal feed was left

Answers

To solve you will multiply the total starting feed by the amount remaining. In this case it would be 96 * (9/10) = 86.4kg of feed left. I hope this helped. :)

Find P(organic | oranges)
Find P(Non-organic | oranges)

Answers

Answer to part A: 0.63
Answer to part B: 0.37
Answer to part C: organic oranges

---------------------------------------------------------------------
---------------------------------------------------------------------

Work Shown:

Part A
P(Organic|Oranges) = P(Organic AND oranges)/P(Oranges)
P(Organic|Oranges) = 0.19/0.30
P(Organic|Oranges) = 0.63

Part B
P(Non-organic|Oranges) = P(non-organic AND oranges)/P(oranges)
P(Non-organic|Oranges) = 0.11/0.30
P(Non-organic|Oranges) = 0.37

Part C
The probability in part A is larger compared to the answer in part B, so it's more likely to have someone pick organic oranges rather than non-organic oranges. Melina should restock organic oranges for the next sale.

The next four batters on a baseball team have hitting percentages of 0.400,0.325, o.250, and 0.300, respectively The team currently has two outs. If any player gets an out, the next player or players will not get an opportunity to bat. What is the probability that the fourth player will have an opportunity to bat?

Answers

So the first three batters will have to get a hit...

.4(.325)(.25)=0.0325

Which should be expressed as a fraction as this is probabilities :P

325/10000

13/400

(This of course is not true as we only know their hitting averages not the on-base averages...they can be walked or beaned for example and still get on base :P)


B for online school yuhp

What is the domain of y = tan x, where n is any integer?

Answers

now   [tex]\bf tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}[/tex]   so, if the cosine of the angle, ever becomes 0, the rational becomes undefined. so hmmm other than those points, the values the angle can take on are pretty much anything, positive or negative ones... and the cosine is 0 at [tex]\bf \frac{\pi }{2}\qquad \frac{3\pi }{2}\qquad \textit{on the range of }[0,2\pi ][/tex]

so.. one can say the domain of tangent, is all angles EXCEPT those where cosine turns to 0

[tex]\bf \{x|x\in \mathbb{R}; x\ne \frac{\pi }{2}\pm\pi n\}\qquad \textit{\underline{n} being an integer}[/tex]

Answer:

x is not equal to pi/2 + n*pi

Step-by-step explanation:

just got it right on a pex

Hosting a breakfast for 25 people you plan to serve scrambled eggs the grocery store sells eggs in cartons and each carton can feed people. how many cartoons of eggs must you buy to ensure each guest a serving

Answers

3 for 25 people because if you buy 2 one person would be left out.

The number of egg cartons required to serve 25 people with scrambled eggs is 3 cartons, assuming each carton serves 12 people and we cannot purchase partial cartons.

To calculate the number of egg cartons needed to serve scrambled eggs to 25 people, we first need to know how many people each carton can serve. However, it appears there's a typo or missing information in the question regarding the number of people an egg carton can serve. Assuming that one egg carton can serve a certain number of people, we'd use that information to determine the total number of cartons required.

If we refer to the related information provided about pancakes - where one egg is needed for 8 pancakes - we can draw a parallel for eggs for scrambled eggs. If one egg serves one person in the case of scrambled eggs, and typically there are 12 eggs in a carton, then one carton would serve 12 people.

Using this assumption, since we have 25 people to serve, we can calculate the number of cartons needed as follows:

25 people
Since we cannot purchase a partial carton, we would need to round up to the nearest whole number. Therefore, we would need to purchase 3 cartons of eggs to ensure each guest has a serving.

A committee consisting of 6 people is to be selected from eight parents and four teachers. find the probability of selecting three parents and three teachers.

Answers

All in all, there are 12 people including 8 parents and 4 teachers. To choose 6 out of this 12 people, we use the concept of combination.

                             n = 12C6 = 924

To choose, 3 parents out of the 8 parents, we use again the concept of combination.

                            x = 8C3 = 56

Similarly, we use the same concept for choosing 3 teachers out of 4 teachers.

                            y = 4C3 = 4

The probability required in this item can be solved through the equation,

                          P = xy/n

Substituting,

                         P = (56)(4) / 924 = 0.2424

Thus, the probability is 24.24%. 

Answer with explanation:

→Total Number of People which are in the group =8 parents + 4 Teacher=12 People

→Probability of an Event

                            [tex]=\frac{\text{Total Favorable Outcome}}{\text{Total Possible Outcome}}[/tex]

→Probability of selecting three parents and three teachers

        = Selecting 3 parents from 8 Parents +Selecting 3 teacher from 4 teacher

As order of Arrangement is not Important ,so we will use the concept of Combinatorics.

→→ Required Probability

 [tex]=\frac{_{3}^{8}\textrm{C}\times _{3}^{4}\textrm{C}}{_{6}^{12}\textrm{C}}\\\\=\frac{\frac{8!}{3!\times 5!}\times \frac{4!}{3!\times 1!}}{\frac{12!}{6!\times 6!}}\\\\=\frac{56 \times 4}{7\times 4 \times 3\times 11}\\\\=\frac{8}{33}[/tex]

                                           

True or false the rules of two dimensional geometry can be applied to three dimensional solids

Answers

Answer:

the answer is TRUE.

Step-by-step explanation:

we can coclude that the three-dimensional geometry is more or less the extension of a two-dimensional geometry as many of the same principles imply.

two points determine a straight line no matter whether the points are two-dimensional or three-dimensional.

hence the following statements holds true that the rules of two dimensional geometry can be applied to three dimensional solids.


Answer:

The answer is false.

Step-by-step explanation:

What is the correct name for this circle?

Answers

the circled is named for the letter in the center

 so this one is named circle C

Solve using perfect square factoring patterns. x2 – 8x + 16 = 25

Answers

x^2 – 8x + 16 = 25
-25 both sides
x^2-8x-9=0
(x-9)(x+1)
x=9,-1

Write an equation of the line that passes through the given point and has the given slope. Write the equation in slope-intercept form.(–5, –6), m = –3 Show your work :)

Answers

see picture for answer

Given the following linear function sketch the graph of the function and find the domain and range.
F(x)=2/7x-2

Answers

Hopefully the picture loads, but the x-int is (7,0) and the y-int is (0,-2)

Domain and range are from negative infinity to positive infinity or all real numbers


At the frozen yogurt shop, a machine fills cups with 4 ounces of frozen yogurt before adding the toppings. After the cups are filled, customers add as many toppings as they want without exceeding a total weight of 6 ounces. Which of the following represent the acceptable weights for the frozen yogurt options? Select all that apply:
A.) 0 < x ≤ 6
B.) 0 < x ≤ 3
C.) 4 ≤ x ≤ 6
D.) x ≤ 6
E.) |x - 5| ≤ 1
F.) |x - 2| ≤ 6

Answers

The yogurt can weigh above or equal to 4 ounces or less or equal to 6 ounces.

By writing an inequality and then converting it to an absolute value equation, we will see that the correct options are C and E.

How to find an inequality?

To find the inequality, we need to find the lower and upper bounds.

First, we know that the machine fills the cups with 4 oz of yogurt, so this is the minimum value allowed, we will have:

4 ≤ x

Then we can add toppings to a maximum value of 6 ounces, this will be the maximum, then we have:

4 ≤ x ≤ 6

We can also write this an absolute value equation, we define:

m = half of the difference of the bounds.M = lower bound + m

Then the absolute value equation is:

|x - M| ≤ m

By replacing what we found before, we have:

m = (6 - 4)/2 = 1M = 4 + 1 = 5

So the absolute value equation is:

|x - 5| ≤ 1

Finally, we can conclude that the correct options are C and E.

If you want to learn more about inequalities, you can read:

https://brainly.com/question/11234618

What is the arc length when Θ = pi over 3 and the radius is 5 cm?

Answers

The circumference of the total circle is 10pi. The fraction of the circumference we want is [tex] \frac{ \frac{ \pi }{3} }{ 2 \pi } = \frac{1}{6} [/tex]. One sixth of 10pi is 5/3pi, which is the length of the arc

Answer:

Arc length = 5.23 cm  

Step-by-step explanation:

Given : Radius = 5 cm

             Angle = [tex]\theta=\frac{\pi}{3}[/tex]

To find : Arc length(A)

Solution: The formula of arc length is

                 A = radius × angle(in radian)

                [tex]A= 5\times\frac{\pi}{3}[/tex]

                          ⇒[tex]\frac{5\pi}{3}[/tex]

                      A  ⇒15.70/3 = 5.23 cm

please help!!!! question is/.........

Answers

Area of circle = 3.14 x 6^2 = 3.14 x 36 = 113.04

1/2 circle = 113.04 / 2 = 56.52

Area of rectangle = 8 x 6 = 48

Area of figure = 48 + 56.52 = 104.52 

answer
104.52 ft^2

There is a traffic light at the intersection of walnut street and Lawrence avenue. The traffic light in walnut street follows a cycle. It is green for 50 seconds, yellow for 10 seconds, and red for 30 seconds, as you travel along walnut and approach the intersection, what is the probability that the first color you see is red?

Answers

P(R)=30/(30+10+50)

P(R)=30/90

P(R)=1/3

Answer: The probability that the first color we see is red is 0.34.

Step-by-step explanation:

Since we have given that

Time taken by green color on the traffic light = 50 seconds

Time taken by yellow color on the traffic light = 10 seconds

Time taken by red color on the traffic light = 30 seconds

Total number of seconds = 50+10+30=90

So, Probability that the first color we see is red is given by

[tex]\dfrac{\text{Time alloted for red color}}{\text{Total number of seconds}}\\\\=\dfrac{30}{90}\\\\=\dfrac{1}{3}\\\\=0.3333...\\\\\approx 0.34[/tex]

Hence, the probability that the first color we see is red is 0.34.

Class a has x students and class b has y students. the average of class a is 85 and class b is 90. when the scores of class a and b are combine the average is 88, what is the ratio of x to y

Answers

The total scores of the x students from class A can be calculated by multiplying x and the average which is equal to 85. That is 85x.

In similar manner, we are able to find for the total scores of the students from Class B. That would be, 90y.

Combining the scores, the new average then becomes 88. This is equal to,

                                 (85x + 90y) / (x + y ) = 88

Cross-multiplying,
                            85x + 90y = 88x + 88y

Combine all the x's and y's in each side of the equation.

                        85x - 88x = 88y - 90y

Combining terms,
                              -3x = -2y

The ratio is obtained through the step below,
                         -3x/-3y = -2y/-3y

                            x/y = 2/3

Thus, the ratio is 2/3. 

Teh width of a rectangle is 2 cm less than 7 times the length. the perimeter is 60 cm. determine the length and the width of the rectangle

Answers

P=2(L+W)
60=P=2(L+W)
60=2(L+W)
divide by 2
30=L+W

given
W=-2+7L
subsitute
30=L+W
30=L-2+7L
30=8L-2
add 2
32=8L
divide by 8
4=L


sub back
W=-2+7L
W=-2+7(4)
W=-2+28
W=26

width is 26cm
length is 4cm

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) and (7, –13), and the center of the arch on the bridge is located at (0, 0). Find the equation of the arch of the bridge.

Answers

The equation of the arch is y = (-13/49)x².

The equation of an arch can be described by a parabola when one side of the arch mirrors the other side. This is the case for the bridge problem given.

The center of the bridge is at the origin (0, 0), and it is the vertex of the parabola. Since the arch is symmetrical and the x-coordinate of the vertex is 0, the parabola is a vertical one. Thus, the equation will be in the form y = ax². To find the value of a, we will use the fact that one end of the bridge is at (7, -13).

Since (7, -13) is a point on the parabola, by plugging these values into the equation y = ax², we get:

-13 = a(7²)

-13 = 49a

a = -13/49

Thus, the equation  is y = (-13/49)x².

What is the data path width for a dimm that supports ecc?

Answers

Normally, the data path width for DIMMs is 64 bits but for the DIMMs that support ECC, the data path is 72 bits.

To add, error checking uses the extra 8 bits. ECC memory is more reliable than non-ECC memory but it costs more than a non-ECC memory. Comprising the DIMMS are a series of dynamic random-access memory integrated circuits. Mounted on a printed circuit board, these modules are designed for use in personal computers, workstations and servers.

 

The most common kinds of internal data corruption are detected and corrected by a type of computer data storage called error-correcting code memory.

Determine whether the sequence converges or diverges. If it converges, give the limit. 60, 10, five divided by three, five divided by eighteen, ...

Answers

[tex]A_n = 60, 10, \frac{5}{3}, \frac{5}{18}[/tex]

Using geometric sequence form, we can rewrite it as:
[tex]A_n = a_1 \cdot r^{n-1}[/tex]
[tex]A_n = 60 \cdot \frac{1}{6}^{n - 1}[/tex]

Since r < 1, there exists a limit, and thus, it is said to converge.
[tex]\lim_{n \to \infty} 60 \cdot (\frac{1}{6})^{n - 1}[/tex]
[tex] = 0[/tex]

Since the ratio is still positive, as n tends towards infinity, the graph of the sequence will never go below the horizontal. Thus, we say that the limit of the function is zero, which means that as we increase the size of n, eventually after the infinite-th time, it will hit zero.

The variable Z is directly proportional to X. When X is 3, Z has the value 54. Wha is the value of Z when X= 12

Answers

The variable Z is directly proportional to X
Z = kX (Where k is the constant of proportionality)
To find k
54 = k3
 
k = 54/3
k = 18
 

now find new Z


 Z = 18X
Z = 18(12)
Z = 216

Other Questions
4n-3 Read the excerpt from "The Miracle Worker" and answer the question: 50 points!!!75 if you get brainliest!!!Kate (cuts in). Miss Annie, before you came we spoke of putting her in an asylum.[ANNIE turns back to regard her. A pause.]Annie. What kind of asylum?Keller. For mental defectives.Kate. I visited there. I cant tell you what I saw, people likeanimals, withrats, in the halls, and(She shakes her head on her vision.) What else are we to do, if you give up?Annie. Give up?Kate. You said it was hopeless.Annie. Here. Give up, why, I only today saw what has to be done, to begin! (She glances from KATE to KELLER, who stare, waiting; and she makes it as plain and simple as her nervousness permits.) Iwant complete charge of her.Keller. You already have that. It has resulted inAnnie. No, I mean day and night. She has to be dependent on me.Kate. For what?Annie. Everything. The food she eats, the clothes she wears, fresh(She is amused at herself, though very serious.)air, yes, the air she breathes, whatever her body needs is aprimer,9 to teach her out of. Its the only way, the one who lets her have it should be her teacher. (She considers them in turn; they digest it, KELLER frowning, KATE perplexed.) Not anyone who loves her, you have so many feelings they fall over each other like feet, you wont use your chances and you wont let me.Kate. But if she runs from youto usAnnie. Yes, thats the point. Ill have to live with her somewhere else.Keller. What!Annie. Till she learns to depend on and listen to me.Kate (not without alarm). For how long?Annie. As long as it takes. (A pause. She takes a breath.) I packed half my things already.Keller. MissSullivan![But when ANNIE attends him he is speechless, and she is merely earnest.]Annie. Captain Keller, it meets both your conditions. Its the one way I can get back in touch with Helen, and I dont see how I can be rude to you again if youre not around to interfere with me.Keller (red-faced). And what is your intention if I say no? Pack the other half, for home, and abandon your charge totoAnnie. The asylum? (She waits, appraises KELLERS glare and KATES uncertainty, and decides to use her weapons.) I grew up in such an asylum. The state almshouse. (KATEs head comes up on this, and KELLER stares hard; ANNIES tone is cheerful enough, albeit level as gunfire.) Ratswhy, my brother Jimmie and I used to play with the rats because we didnt have toys. Maybe youd like to know what Helen will find there, not on visiting days? One ward was full of theold women, crippled, blind, most of them dying, but even if what they had was catching there was nowhere else to move them, and thats where they put us. There were younger ones across the hall, prostitutes mostly, with T.B.,10 and epileptic fits, and a couple of the kind whokeep after other girls, especially young ones, and some insane. Some just had the D.T.s.11 The youngest were in another ward to have babies they didnt want, they started at thirteen, fourteen. Theyd leave afterward, but the babies stayed and we played with them, too, though a lot of them hadsores all over from diseases youre not supposed to talk about, but not many of them lived. The first year we had eighty, seventy died. The room Jimmie and I played in was the deadhouse, where they kept the bodies till they could digKate (closes her eyes). Oh, my dearAnnie. the graves. (She is immune to KATES compassion.) No, it made me strong. But I dont think you need send Helen there. Shes strong enough. (She waits again; but when neither offers her a word, she simply concludes.) 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