Two passenger train, A and B, 450 km apart, star to move toward each other at the same time and meet after 2hours.
If train B, travels 8/7 as fast as train A. Find the speed of each train

Answer:

Step-by-step explanation:

C.35%

If you divide the number of hearts drawn by the number of total draws you get your answer.

14/20=0.35

Answer:

A) f(x) = -3x+7

Step-by-step explanation:

f(x) is interchangeable with y when writing a function, so the functions are the same.

The function that corresponds to the equation -3x + 7 = y is f(x) = -3x + 7, which maintains the same relationship between x and y as the given equation.

The equation -3x + 7 = y can be rewritten in function notation, which typically uses the format f(x) = some expression involving x. The correct corresponding function is one that maintains the relationship between x and y as displayed in the original equation. Therefore, among the options provided:

The correct answer indicates that the function of x (f(x)) is given by the linear equation -3x + 7.

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The solution of quadratic equation  [tex]3x^2 + 15x=0[/tex] is x =0 or -5.

Given Equation: [tex]3x^2 + 15x=0[/tex]

Now, factories each term as

3x² = 3 × x × x

15x = 3 × 5 × x

Now, taking the common term 3x as

[tex]3x^2 + 15x=0[/tex]

3 × x × x+ 3 × 5 × x =0

3x (x + 5)=  0

Now, equate each factor to 0 as

3x =0

x= 0/3

x= 0

or, x + 5= 0

x = -5

Thus, the value of x is -5 or 0.

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Answer:

1st pic: 4

2nd pic: 70

3rd pic: 5

Step-by-step explanation:

Answer:

[tex]5y^{6}\sqrt{2}[/tex]

Step-by-step explanation:

We want to  simplify:

[tex]\sqrt{50y^{12}}[/tex]

We rewrite as:

[tex]\sqrt{2\times25 \times (y^{6})^2}[/tex]

We split the radical sign to obtain:

[tex]\sqrt{25} \times \sqrt{(y^{6})^2} \times \sqrt{2}[/tex]

Simplify the square root for the perfect squares to get:

[tex]5y^{6}\sqrt{2}[/tex]

Therefore the simplified form is: [tex]5y^{6}\sqrt{2}[/tex]

Answer:

y = 179x +1999

y = 249x

Step-by-step explanation:

Given:

down payment of cool cars= $1999

monthly lease rate of cool cars= $179

down payment of awesome autos= $0

monthly lease rate of awesome autos= $249

Number of months=x

total amount paid towards the lease after x months=y

Now creating a system of linear equations that describes the total amount, y, paid towards the lease after x months:

the slope intercept form of any linear function is given as y=mx +b

where m= slope  of function and b=y-intercept

In given case, slope m gives the monthly lease rate and y-intercept b gives the down payment.

So the equations for the two linear functions will be:

cool cars:

Putting the values of m=179 and b=1999, we get

y = 179x +1999

awesome autos:

Putting the values of m=249 and b=0, we get

y = 249x !

Answer:

Step-by-step explanation:

I think its 823 ppm?

I'm not sure

Answer:

volume  =  (1/3)(area of base)(height)

area of base  =  pi * radius2  =  pi * (10/2)2  =  pi * 52  =  25pi   cm2

volume  =  (1/3)( 25pi )( 9 )   cm3

volume  =  75pi   cm3

volume  ≈  236  cm3  

ANSWER

[tex]Volume = 235.6 {cm}^{3} [/tex]

EXPLANATION

The volume of a cone is calculated the using the formula:

[tex]Volume = \frac{1}{3} \pi {r}^{2} h[/tex]

From the given information the height of the cylinder is, h=9cm.

The diameter of the base is 10cm.

The radius is half of the diameter of the base, r=5cm.

We plug in the values into the formula to get:

[tex]Volume = \frac{1}{3} \times \pi \times {5}^{2} \times 9[/tex]

[tex]Volume = 75\pi {cm}^{3} [/tex]

[tex]Volume = 235.6 {cm}^{3} [/tex]

Answer:

2 gallons per mile

The ratio of the room's length to its area is 1:12, derived from length (22 feet) divided by area (264 square feet).

let's break it down step by step.

Step 1: Calculate the area of the room.

To find the area of a rectangle, you multiply its length by its width.

So, Area = Length × Width

Area = 22 feet × 12 feet

Area = 264 square feet

Step 2: Calculate the ratio of the length of the room to its area.

The ratio of length to area is:

[tex]\[ \text{Ratio} = \frac{\text{Length}}{\text{Area}} \][/tex]

Substituting the values:

[tex]\[ \text{Ratio} = \frac{22 \, \text{feet}}{264 \, \text{square feet}} \][/tex]

Step 3: Simplify the ratio.

[tex]\[ \text{Ratio} = \frac{22}{264} \][/tex]

Step 4: Simplify the fraction.

[tex]\[ \text{Ratio} = \frac{1}{12} \][/tex]

So, the ratio of the length of the room to its area is [tex]\( \frac{1}{12} \)[/tex].

Answer:

Point Q is (3 , 4)

Step-by-step explanation:

* Lets revise the rule of the point which divides of a line segment in

 a ratio

- If point (x , y) divides the line segment AB, where A is (x1 , y1) and

 B is (x2 , y2) in the ratio m1 : m2

∴ x = [m2(x1) + m1(x2)]/(m1 + m2)

∴ y = [m2(y1) + m1(y2)]/(m1 + m2)

* Now lets solve the problem

- Point Q divides ST in the ratio 5 : 2 where S (-2 , -6) and T (5 , 8)

- To find the coordinates of point Q use the same rule above

# Q is (x , y)

# S is (x1 , y1) and T is (x2 , y2)

# m1 : m2 is 5 : 2

∵ x1 = -2 and y1 = -6

∵ x2 = 5 and y2 = 8

∵ m1 = 5 and m2 = 2

- Substitute these values in the rule

∵ x = [m2(x1) + m1(x2)]/(m1 + m2)

∴ x = [2(-2) + 5(5)]/(5 + 2) ⇒ multiply the numbers

∴ x = [-4 + 25]/7 ⇒ add

∴ x = [21]/7 ⇒ Divide

∴ x = 3

* The x-coordinate of Q is 3

∵ y = [m2(y1) + m1(y2)]/(m1 + m2)

∴ y = [2(-6) + 5(8)]/(5 + 2) ⇒ multiply the numbers

∴ y = [-12 + 40]/7 ⇒ add

∴ y = [28]/7 ⇒ Divide

∴ y = 4

* The y-coordinate of point Q is 4

∴ Point Q is (3 , 4)

Answer:

not geometric

Step-by-step explanation:

If the sequence is geometric then the common ratio r between consecutive terms should be equal

[tex]\frac{42}{21}[/tex] = 2

[tex]\frac{126}{42}[/tex] = 3

[tex]\frac{504}{126}[/tex] = 4

There is no common ratio between consecutive terms

Hence the sequence is not geometric

Answer:

A=36

Step-by-step explanation:

A=s^2

A=6^2

A=36

Answer:

36

Step-by-step explanation:

Formula ⇒ A = s²

We know that s = 6, so we substitute into A = s²

A = s²

A = 6²

A = 36

C. 5 and seventy-six hundredths sorry If I'm wrong, but I'm pretty sure I'm right

please rate my answer

Answer:

Five and seventy six hundredths

Your Welcome :3

Answer:

60

Step-by-step explanation:

Answer:

About 57.48

Step-by-step explanation:

Answer:

Part 1) [tex]P=[2\sqrt{29}+\sqrt{18}]\ units[/tex] or [tex]P=15.01\ units[/tex]

Part 2) [tex]P=2[\sqrt{20}+\sqrt{45}]\ units[/tex] or [tex]P=22.36\ units[/tex]

Part 3) [tex]P=4[\sqrt{13}]\ units[/tex] or [tex]P=14.42\ units[/tex]

Part 4) [tex]P=[19+\sqrt{17}]\ units[/tex] or [tex]P=23.12\ units[/tex]

Part 5) [tex]P=2[\sqrt{17}+\sqrt{68}]\ units[/tex] or [tex]P=24.74\ units[/tex]

Part 6) [tex]A=36\ units^{2}[/tex]

Part 7) [tex]A=20\ units^{2}[/tex]

Part 8) [tex]A=16\ units^{2}[/tex]

Part 9) [tex]A=10.5\ units^{2}[/tex]

Part 10) [tex]A=6.05\ units^{2}[/tex]

Step-by-step explanation:

we know that

The formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

Part 1) we have the triangle ABC

[tex]A(0,3),B(5,1),C(2,-2)[/tex]

step 1

Find the distance AB

[tex]A(0,3),B(5,1)[/tex]

substitute in the formula

[tex]AB=\sqrt{(1-3)^{2}+(5-0)^{2}}[/tex]

[tex]AB=\sqrt{(-2)^{2}+(5)^{2}}[/tex]

[tex]AB=\sqrt{29}\ units[/tex]

step 2

Find the distance BC

[tex]B(5,1),C(2,-2)[/tex]

substitute in the formula

[tex]BC=\sqrt{(-2-1)^{2}+(2-5)^{2}}[/tex]

[tex]BC=\sqrt{(-3)^{2}+(-3)^{2}}[/tex]

[tex]BC=\sqrt{18}\ units[/tex]

step 3

Find the distance AC

[tex]A(0,3),C(2,-2)[/tex]

substitute in the formula

[tex]AC=\sqrt{(-2-3)^{2}+(2-0)^{2}}[/tex]

[tex]AC=\sqrt{(-5)^{2}+(2)^{2}}[/tex]

[tex]AC=\sqrt{29}\ units[/tex]

step 4

Find the perimeter

The perimeter is equal to

[tex]P=AB+BC+AC[/tex]

substitute

[tex]P=[\sqrt{29}+\sqrt{18}+\sqrt{29}]\ units[/tex]

[tex]P=[2\sqrt{29}+\sqrt{18}]\ units[/tex]

or

[tex]P=15.01\ units[/tex]

Part 2) we have the rectangle ABCD

[tex]A(-4,-4),B(-2,0),C(4,-3),D(2,-7)[/tex]

Remember that in a rectangle opposite sides are congruent

step 1

Find the distance AB

[tex]A(-4,-4),B(-2,0)[/tex]

substitute in the formula

[tex]AB=\sqrt{(0+4)^{2}+(-2+4)^{2}}[/tex]

[tex]AB=\sqrt{(4)^{2}+(2)^{2}}[/tex]

[tex]AB=\sqrt{20}\ units[/tex]

step 2

Find the distance BC

[tex]B(-2,0),C(4,-3)[/tex]

substitute in the formula

[tex]BC=\sqrt{(-3-0)^{2}+(4+2)^{2}}[/tex]

[tex]BC=\sqrt{(-3)^{2}+(6)^{2}}[/tex]

[tex]BC=\sqrt{45}\ units[/tex]

step 3

Find the perimeter

The perimeter is equal to

[tex]P=2[AB+BC][/tex]

substitute

[tex]P=2[\sqrt{20}+\sqrt{45}]\ units[/tex]

or

[tex]P=22.36\ units[/tex]

Part 3) we have the rhombus ABCD

[tex]A(-3,3),B(0,5),C(3,3),D(0,1)[/tex]

Remember that  in a rhombus all sides are congruent

step 1

Find the distance AB

[tex]A(-3,3),B(0,5)[/tex]

substitute in the formula

[tex]AB=\sqrt{(5-3)^{2}+(0+3)^{2}}[/tex]

[tex]AB=\sqrt{(2)^{2}+(3)^{2}}[/tex]

[tex]AB=\sqrt{13}\ units[/tex]

step 2

Find the perimeter

The perimeter is equal to

[tex]P=4[AB][/tex]

substitute

[tex]P=4[\sqrt{13}]\ units[/tex]

or

[tex]P=14.42\ units[/tex]

Part 4) we have the quadrilateral ABCD

[tex]A(-2,-3),B(1,1),C(7,1),D(6,-3)[/tex]

step 1

Find the distance AB

[tex]A(-2,-3),B(1,1)[/tex]

substitute in the formula

[tex]AB=\sqrt{(1+3)^{2}+(1+2)^{2}}[/tex]

[tex]AB=\sqrt{(4)^{2}+(3)^{2}}[/tex]

[tex]AB=5\ units[/tex]

step 2

Find the distance BC

[tex]B(1,1),C(7,1)[/tex]

substitute in the formula

[tex]BC=\sqrt{(1-1)^{2}+(7-1)^{2}}[/tex]

[tex]BC=\sqrt{(0)^{2}+(6)^{2}}[/tex]

[tex]BC=6\ units[/tex]

step 3

Find the distance CD

[tex]C(7,1),D(6,-3)[/tex]

substitute in the formula

[tex]CD=\sqrt{(-3-1)^{2}+(6-7)^{2}}[/tex]

[tex]CD=\sqrt{(-4)^{2}+(-1)^{2}}[/tex]

[tex]CD=\sqrt{17}\ units[/tex]

step 4

Find the distance AD

[tex]A(-2,-3),D(6,-3)[/tex]

substitute in the formula

[tex]AD=\sqrt{(-3+3)^{2}+(6+2)^{2}}[/tex]

[tex]AD=\sqrt{(0)^{2}+(8)^{2}}[/tex]

[tex]AD=8\ units[/tex]

step 5

Find the perimeter

The perimeter is equal to

[tex]P=AB+BC+CD+AD[/tex]

substitute

[tex]P=[5+6+\sqrt{17}+8]\ units[/tex]

[tex]P=[19+\sqrt{17}]\ units[/tex]

or

[tex]P=23.12\ units[/tex]

Part 5) we have the quadrilateral ABCD

[tex]A(-1,5),B(3,6),C(5,-2),D(1,-3)[/tex]

step 1

Find the distance AB

[tex]A(-1,5),B(3,6)[/tex]

substitute in the formula

[tex]AB=\sqrt{(6-5)^{2}+(3+1)^{2}}[/tex]

[tex]AB=\sqrt{(1)^{2}+(4)^{2}}[/tex]

[tex]AB=\sqrt{17}\ units[/tex]

step 2

Find the distance BC

[tex]B(3,6),C(5,-2)[/tex]

substitute in the formula

[tex]BC=\sqrt{(-2-6)^{2}+(5-3)^{2}}[/tex]

[tex]BC=\sqrt{(-8)^{2}+(2)^{2}}[/tex]

[tex]BC=\sqrt{68}\ units[/tex]

step 3

Find the distance CD

[tex]C(5,-2),D(1,-3)[/tex]

substitute in the formula

[tex]CD=\sqrt{(-3+2)^{2}+(1-5)^{2}}[/tex]

[tex]CD=\sqrt{(-1)^{2}+(-4)^{2}}[/tex]

[tex]CD=\sqrt{17}\ units[/tex]

step 4

Find the distance AD

[tex]A(-1,5),D(1,-3)[/tex]

substitute in the formula

[tex]AD=\sqrt{(-3-5)^{2}+(1+1)^{2}}[/tex]

[tex]AD=\sqrt{(-8)^{2}+(2)^{2}}[/tex]

[tex]AD=\sqrt{68}\ units[/tex]

step 5

Find the perimeter

The perimeter is equal to

[tex]P=\sqrt{17}+\sqrt{68}+\sqrt{17}+\sqrt{68}[/tex]

substitute

[tex]P=2[\sqrt{17}+\sqrt{68}]\ units[/tex]

or

[tex]P=24.74\ units[/tex]

Answer:

need points

Step-by-step explanation:

Answer:

Not a factor

Step-by-step explanation:

If (x - 3) is a factor then f(3) = 0

f(x) = x² - 4x + 30

f(3) = 2(3)² - 4(3) + 30 = 18 - 12 + 30 = 36 ≠ 0

Since f(3) ≠ 0 then (x - 3) is not a factor of f(x)

( x - 3 ) is not a factor of the polynomial 2x² - 4x + 30

What is Factor Theorem?

The Factor Theorem states that if f(x) is a polynomial of degree n greater than or equal to 1, and 'a' is any real number, then ( x - a ) is a factor of f ( x ) if f ( a ) = 0

Given data ,

f ( x ) = 2x² - 4x + 30

If ( x - 3 ) is a factor of f ( x ) , then by factor theorem f ( x ) = f ( 3 ) = 0

And , f ( 3 ) = 2 x 3 x 3 - 4 x 3 + 30

                            = 18 - 12 + 30

                            = 36

Therefore , f ( 3 ) ≠ 0 , so ( x - 3 ) is not a factor of 2x² - 4x + 30

Hence , ( x - 3 ) is not a factor of the polynomial 2x² - 4x + 30

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Answer:

11.2

Step-by-step explanation:

Calculate the length using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = B(4, 7) and (x₂, y₂ ) = C(2, - 4)

d = [tex]\sqrt{(2-4)^2+(-4-7)^2}[/tex]

   = [tex]\sqrt{(-2)^2+(-11)^2}[/tex]

   = [tex]\sqrt{4+121}[/tex]

   = [tex]\sqrt{125}[/tex] ≈ 11.2

The lenght of each side is 24cm, 24cm, and 8cm.

In order to solve this problem, we know that the perimeter of a triangle equation is P = a + b + c, where a, b, and c are the sides of the triangle.

The perimeter is 56cm, we can write the equation as follow:

a + b + c = 56cm (1)

If each of the two longer sides of the triangles is three times as long as the shortest side, we can assume:

c = shortest side = x

a = b = longer sides = 3x

Substituting the values in the equation (1):

3x + 3x + x = 56cm

7x = 56cm

x = 56cm/7 = 8cm

c = shortest side = 8cm

a = b = longer sides = 3(8cm) = 24cm

Answer:

x = 30.

Step-by-step explanation:

The angle next to the 60 degree angle = 180 - 60 = 120 degrees (adjacent angles are supplementary).

Let the angle  just above 3x be y.  The sum of 3x and y = 120 degrees (as opposite angles of a parallelogram are equal).

We have the following equations.

3x + y = 120............(1)

2x + 90 + y = 180

2x + y = 90.............(2)

Subtracting, (1) - (2):

x = 30.

Answer:

The interior angles are 70°,65°,80°,155° and 170°

Step-by-step explanation:

step 1

Find the sum of the interior angles of the pentagon

The sum is equal to

S=(n-2)*180°

where

n is the number of sides of polygon

n=5 (pentagon)

substitute

S=(5-2)*180°=540°

step 2

Find the value of x

Sum the given angles and equate to 540

x+(x-5)+(x+10)+(2x+15)+(2x+30)=540°

7x+50=540°

7x=490°

x=70°

step 3

Find all the angles

x=70°

(x-5)=(70-5)=65°

(x+10)=(70+10)=80°

(2x+15)=(2*70+15)=155°

(2x+30)=(2*70+30)=170°

Answer:

8 in

Step-by-step explanation:

Area of a square is given by

A = s^2 where s is the side length

64 in^2 = s^2

Taking the square root of each side

sqrt(64 in^2) = sqrt(s^2)

8 in =s

Answer:

Step-by-step explanation:

The formula of an area of a square:

[tex]A=s^2[/tex]

s - side length

We have the area

[tex]A=64\ in^2[/tex]

Substitute:

[tex]s^2=64\to s=\sqrt{64}\\\\s=8\ in[/tex]

[tex]\sqrt{64}=8[/tex] because [tex]8^2=64[/tex]

Here you don’t need to solve the equation,the value of the problem is zero

For both methods I will use the quadratic formula. Look at the image below

Hope this helped!    

Your answer is correct

I guess you wrote the correct answer

Answer:

What you have to do is add all of the sums up and put 2 over it. it is 2/20 which is 1/10.

Step-by-step explanation:

in a percent it is 0.1

Can I get brainiest

The probability that Alina selects 2 cans of lemonade is

How to calculate probability?

The given question has concept of conditional probability.

Conditional probability is applied when we have to find the possibility of an event given the another event already occurred.

Conditional probability is calculated by multiplying the probability of the preceding event by the updated probability of the succeeding, or conditional, event.

Here, the first event is selecting the lemonade can and second event is also selecting lemonade can given one lemonade is already selected.

The probability to select 1st lemonade= 7/20

The probability to select 2nd lemonade=6/19

Multiplying them we get:

Probability:7*6/20*19=21/190

Therefore, the probability to select two lemonades is 21/190.

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Answer:

5√2

Step-by-step explanation:

The question is on geometry

The formula for distance between two points is;

[tex]d= \sqrt{(X2-X1)^2 + (Y2-Y1)^2}[/tex]

where d is distance.

Given points;

(0,5)    and   (-5,0) ;

X1=0 ,X2= -5 , Y1= 5, Y2= 0

X2-X1 = -5 - 0= -5

Y2-Y1= 0-5= -5

[tex]d= \sqrt{(-5)^2 + (-5)^2}[/tex]

[tex]d=\sqrt{25+25}[/tex]

[tex]d=\sqrt{50}[/tex]

[tex]d=\sqrt{2*25} =\sqrt{2} *\sqrt{25} =\sqrt{2} *5\\\\\\\\d=5\sqrt{2}[/tex]

Answer:

[tex]d=5\sqrt{2}[/tex]

Step-by-step explanation:

Given : (0, 5) and (-5, 0)

To Find : Distance between the given points

Solution:

We will use distance formula :

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex](x_1,y_1)=(0,5)[/tex]

[tex](x_2,y_2)=(-5,0)[/tex]

Substitute the values in the formula .

[tex]d=\sqrt{(-5-0)^2+(0-5)^2}[/tex]

[tex]d=\sqrt{(-5)^2+(-5)^2}[/tex]

[tex]d=\sqrt{25+25}[/tex]

[tex]d=\sqrt{50}[/tex]

[tex]d=5\sqrt{2}[/tex]

Hence the distance between the given points is 5√2 units

Answer:

84 ft²

Step-by-step explanation:

Solve for Volume. Volume of a box is:

V = Length (base) x Width (base) x Height (of rectangular prism/square)

Change each measurement to have the same measurement (ft -> in, or vice versa).

Note that 1 ft = 12 in.

6 in = 1/2 ft, because 6/12 = 1/2

Length = 12 ft

Width = 14 ft

Height = 1/2 ft

Solve. Plug in the corresponding number to the corresponding words.

V = 12 x 14 x 1/2

Simplify. Solve.

V = 12 x (14 x 1/2)

V = 12 x (14/2)

V = 12 x 7

V = 84

84 ft² is your answer.

~

Answer:

1,008

Step-by-step explanation:

You multiply all three numbers to get your answer.

For this case we have that by definition, the slope of a line is given by:

[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]

We need two points through which the line passes.

[tex](x_ {1}, y_ {1}) :( 1,4)\\(x_ {2}, y_ {2}) :( 3,2)[/tex]

Substituting:

[tex]m = \frac {2-4} {3-1} = \frac {-2} {2} = - 1[/tex]

Answer:

[tex]m = -1[/tex]

Final answer:

Jordan spent $14.85 in total, of which $2.85 was spent on snacks. After subtracting the cost of snacks, it's found that she spent $12.00 on bus fares.

Explanation:

The student asked how much Jordan spent on bus fares to and from the zoo if she spent a total of $14.85, including $2.85 on snacks. To find out the amount spent on bus fares, one needs to subtract the cost of the snacks from the total amount spent. Therefore, the calculation would be $14.85 (total spent) - $2.85 (snacks) = $12.00.

Hence, Jordan spent $12.00 on bus fares.

You start with the equation V = IR, plug the value 0.5 for I and you have

V = 0.5*R

So, the first three options are equivalent and correct.

V=IR

And current, Ampere is given as 0.5 so substituting it back in the main equation gives V = 0.5R