Two train whistles have identical frequencies of 1.64 102 Hz. When one train is at rest in the station and the other is moving nearby, a commuter standing on the station platform hears beats with a frequency of 4.00 beats/s when the whistles operate together. What are the two possible speeds that the moving train can have?

The spin quantum number (ms) describes the orientation of the spin of the electron: TRUE

The magnetic quantum number (ml) describes the size and energy associated with an orbital. An orbital is the path that an electron follows during its movement in an atom: FALSE

The angular momentum quantum number (l) describes the orientation of the orbital: FALSE

The principal quantum number (n) describes the shape of an orbital: FALSE

Explanation:

The statement contains mixed truths and falsehoods. The spin quantum number describes the orientation of electron spin, the magnetic quantum number pertains to orbital orientation, and the angular momentum quantum number concerns orbital shape, while the principal quantum number describes orbital size and energy.

The statement is false. The spin quantum number (ms) does describe the orientation of the spin of the electron, either up or down. The magnetic quantum number (ml) describes the orientation of the orbital in space. An orbital is defined as a region in space where there's a high probability of finding an electron, not their path. The angular momentum quantum number (l) determines the shape of the orbital. The principal quantum number (n) describes the size and energy level of an orbital.

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Answer:

110 cm

Explanation:

Gradpoint

Answer:

The ball's initial kinetic energy

The ball comes to a stop at B. At this point its initial kinetic energy is converted into potential energy

Explanation:

A ball is fixed to the end of a string, which is attached to the ceiling at point P. As the drawing shows, the ball is projected downward at A with the launch speed v0. Traveling on a circular path, the ball comes to a halt at point B. What enables the ball to reach point B, which is above point A? Ignore friction and air resistance.

From conservation of energy which states that energy can neither be created nor be destroyed, but can be transformed from one form to another.

Ki+Ui=Kf+Uf

Ki=initial kinetic energy

Ui=initial potential energy

Kf=final kinetic energy

Uf=final potential energy

we know that [tex]\frac{1}{2} mu^{2} +mgha=\frac{1}{2} mv^{2} +mghb[/tex]

m=mass of the ball

ha=downward height a

hb=upward height b

u=initial velocity u

v=final velocity v, which is 0

g=acceleration due to gravity

v=0 at final velocity

1/2mu^2+mgha=0+1/2mv^2

ha=hb+Ki/mh

From the above equation, we can conclude that the ball's initial kinetic energy  is responsible for making the ball reach point B.

Point B is higher than point A from the motion gained by the ball

Answer:

C- ±37.6°

Explanation:

This is the case of a single slit diffraction. In this case, the dark fringe occurs at

sin θ = ± mλ/a

where m = 1

θ = ± 30°

Hence we have sin ± 30° = ± λ/a

±0.5 = ± λ/a

Hence, we have a = 2λ

For a circular aperture, the condition for the first dark fringe is

D = diameter of circle = a = 2λ

so we have sin θ1 = 1.22λ/a

sin θ1 = 1.22λ/2λ

hence sin θ1 = 0.61

θ1 = sin⁻¹0.61 = ±37.6°

Answer:

Answer Choose “Faster response” in the sampling pull-down menu

Explanation:

At the top of the report, below the date range selector, select faster response,

This option uses a smaller sampling size to give you faster results. In order to get a better understanding lets define sampling, according to Google analytics website  

In data analysis, sampling is the practice of analyzing a subset of all data in order to uncover the meaningful information in the larger data set.  

For example, if you wanted to estimate the number of trees in a 100-acre area where the distribution of trees was fairly uniform, you could count the number of trees in 1 acre and multiply by 100, or count the trees in a half acre and multiply by 200 to get an accurate representation of the entire 100 acres.

To speed up Go_ogle Analytics reports, you can reduce the date range and complexity of the report, or increase server resources.

To increase the speed at which Go_ogle Analytics compiles reports, several actions could be taken. First, one can reduce the amount of data that is being processed by adjusting the date range of the reports. By analyzing a smaller chunk of data, the report can be generated much faster.

Secondly, one can adjust the complexity of the report. The more complex the report, the more data needs to be processed, hence it will take longer. Reducing the complexity and only focusing on the key metrics can help speed up the report compilation.

Lastly, one can increase the capacity of their server resources. If a company has the means, it can invest in dedicated server resources for Go_ogle Analytics, allowing it to process reports faster.

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Answer:

If the stone is thrown from the ground, the correct answer is A. If it is thrown from a height h, the correct answer is D.

Explanation:

Hi there!

I can´t see the drawing but let´s assume that initially, the stone is on the ground level. If that is the case, initially, the potential energy will be zero and when it returns to Earth it will also be zero. The potential energy depends on the height of the stone. If the final and initial height of the stone is zero, then the change in potential energy will also be zero:

ΔPE = final PE - initial PE

ΔPE = m · g · hf - m · g · hi (where hf and hi are the final and initial height respectively)

ΔPE = m · g (hf - hi)

ΔPE = m · g (0)

ΔPE = 0

Initially, the kinetic energy (KE) of the stone is the following:

KE = 1/2 · m · v0²

As the stone goes up, the kinetic energy is transformed into potential energy; but as the stone starts to fall, the acquired potential energy is transformed again into kinetic energy, so that the final and initial kinetic energy of the stone is the same.

Then:

ΔKE = final KE - initial KE = 0 (because final KE = initial KE).

Then, the correct answer is A.

Always ΔKE = -ΔPE due to the conservation of energy. Potential energy can´t be acquired by the stone if there is no loss of kinetic energy and vice-versa.

Let´s assume now that the stone is thrown from a height hi to the ground.

The final potential energy will be zero (becuase h = 0) but the initial PE will be:

PE = m · g · h1

Then:

ΔPE = final PE - initial PE = 0 - m · g · h1

Then ΔPE will be negative.

The initial kinetic energy will be:

KE = 1/2 · m · v0²

But the final kinetic energy will be equal to the initial kinetic energy plus the loss of potential energy (remember: if potential energy decreases, another type of energy has to increase, in this case, kinetic energy and vice-versa):

ΔKE = final KE - initial KE

ΔKE = 1/2 · m · v0² + m · g · h1 - 1/2 · m · v0²

ΔKE = m · g · h1

Then ΔKE will be positive and the correct answer would be D.

Answer:

The count rate at the end of four days will be 7.5 counts per minute.

Explanation:

First it is important to know that half-life is the time to a piece of radioactive material to decay 50%. So if we know we start with 120 counts per minute and we already know the half-life of the isotope is 1 hour we expect that past 1 hour the material decays 50% (it's halved) so we will count 60 counts per minute, now if we wait another hour 60 counts will decay in to 30 counts per minute and so on. That should be translate to a math equation as:

final counts = initial counts * [tex](\frac{1}{2})^{\#half\,life\,periods}[/tex]

After 4 days we have 4 half-life periods passed so:

final counts= 120 counts per minute * [tex](\frac{1}{2})^{4}[/tex]

final material = 7.5 counts per minute

Answer:

Option A.

Explanation:

In quantum physics there is a law to relate the position and the momentum of the particle, it says that if we know with precision where is a quantum particle, we can not know the momentum of this particle, in other words, the velocity of the particle. So, when we measure the velocity of the particle we find the correct value of the particle, but we can not determine with accuracy where is the particle. This law is known as the Heisenberg's uncertainty principle and, its expressed as follows:    

[tex] \Delta x \Delta p \geq \frac{h}{4 \pi} [/tex]

where Δx: is the position's uncertainty, Δp: is the momentum's uncertainty and h: is the Planck constant.  

Therefore, the correct answer is A: measuring the velocity of a tiny particle with an electromagnet has no effect on the velocity of the particle. It only affects the determination of the particle's position.      

I hope it helps you!

Answer:

1.0 M HNO3 at 40°C

Explanation:

Rate of chemical reaction: This can be defined as the number of moles of reactant, converted or product formed per unit time.

Factors that affect rate of chemical reaction:

(a) Temperature:  Generally, an increase in temperature increase the rate of chemical reaction by (1) increasing the number of particles with energy equal to or greater than the activation energy, (2) Increasing the average speed of all the reactant particles, due to greater kinetic energy, leading to higher frequency of collision.

(b) Concentration: An increase or decrease in the concentration of the reactant will  result to a corresponding increase or decrease in the effective collision of the reactant and hence in the reaction rate.

other factors that affect the rate of chemical reaction are

(i) Nature of the reactant

(ii) Surface area of reactant

(iii) presence of light

(iv) presence of catalyst.

From the question above,

The condition with the highest temperature and concentration will produce the GREATEST reaction rate.

And that is  1.0 M HNO3 at 40 °C

Answer:

The magnitude of the flux is  [tex]2.00 N m^2/C[/tex]

Explanation:

The electric flux through a planar area is defined as the product of electric field and the  component of the area perpendicular to the field.

Electric flux = Electric field * Area * (angle between the planar area and the electric flux)

The equation is

[tex]\phi = E A cos(\theta)[/tex]

Where:

[tex]\phi[/tex]is the Electric Flux

A is the  Area

E is the Electric field

[tex]\theta[/tex] is  angle between a perpendicular vector to the area and the electric field

Now substituting the values,

[tex]\phi = 5.00 \times 4.00 \times cos(0)[/tex]

[tex]\phi = 5.00 \times 4.00 \times 1[/tex]

[tex]\phi = 2.00 N m^2/C[/tex]

The flux of a constant electric field in the z-direction through a rectangle in the xy-plane is zero, because the angle between the direction of the electric field and the direction of the normal to the area is 90 degrees, which makes the dot product zero.

To calculate the magnitude of the flux of an electric field, we use the equation: Φ = E . A where Φ is the electric flux, E is the electric field, and A is the area of the surface. The dot (.) represents a dot product, which means we consider the angle between the field and the area. In this problem, the electric field (E) is given as 5.00 N/C and the area of the rectangle (A) is 4.00 m². Also, because the electric field is in the z-direction (up and down), and the rectangle is in the xy-plane (flat), the angle between the field and the area is 90 degrees.

However, the dot product for angles of 90 degrees is zero because cos(90°) = 0. So, regardless of the magnitudes of the electric field and the area, the flux is zero because Φ = E . A = EAcos(90°) = 0. Therefore, the correct answer is (a) 0.

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Answer:

Explanation:

A) Initial speed, u = 12 m/s

   Acceleration, a = -7 m/s²

   Final velocity, v = 0 m/s

   We have equation of motion v² = u² + 2as

                0² = 12² + 2 x -7 x s

                s = 10.29 m

  He need 10.29 m to stop.

  Remaining distance = 43 - 10.29 = 32.71 m

  We have

            Remaining distance = Reaction Time x Initial velocity

            32.71 = Reaction Time x 12

            Reaction Time = 2.73 seconds.

B) Distance traveled in 1.1333 s = 1.1333 x 12 = 13.60 m

   Remaining distance = 41 - 13.6 = 27.4 m

    Initial speed, u = 12 m/s

   Acceleration, a = -7 m/s²

   Displacement, s = 27.4 m

                      v² = 12² + 2 x -7 x 27.4

                      v² =  -239.6

   Not possible.

   Motorist will not hit deer.

  He will not reach the deer.

Answer:

The answer is B

Explanation:

Density of the element lead (Pb) is:

[tex]d_{Pb} =11,3kg/dm^3[/tex]

Density of the element Copper (Cu) is:

[tex]d_{Cu} =7,9kg/dm^3[/tex]

First we need o find the volume of both materials:

[tex]V_{Pb}=5/11,3=440cm^3[/tex]

[tex]V_{Cu}=5/7,9=630cm^3[/tex]

And the buoyant forces on elements are:

[tex]P_{Pb}=440*1*9,81/1000=4,32N[/tex]

[tex]P_{Pb}=630*1*9,81/1000=6,18N[/tex]

Answer:

A. The horizontal velocity vector points to the right & equals v cos θ.

Explanation:

The motion describes a parabolic path, where the horizontal speed is constant and the horizontal velocity vector always points to the right and equals v*cos θ.

Final answer:

About 8,960 atoms of carbon-14 were present in the object when it was made 18,000 years ago, based on its current carbon-14 content and the known half-life of carbon-14.

Explanation:

To calculate how many atoms of carbon-14 (14C) were present in an object that was created 18,000 years ago, we use the half-life of 14C, which is 5,730 years. Given that there are 1,000 atoms of 14C present now, we need to find out how many half-lives have passed to work backwards and determine the initial quantity of 14C atoms.

First, we divide the age of the object by the half-life of 14C:

18,000 years / 5,730 years per half-life ≈ 3.14 half-lives

Now, we apply the formula for exponential decay, taking into account the number of half-lives:

Initial Quantity = Present Quantity × (2⁰ of half-lives)

Initial Quantity = 1000 atoms × (2≈ 3.14)

Initial Quantity ≈ 1000 atoms × 8.96

Initial Quantity ≈ 8960 atoms of 14C were present when the object was made.

Answer:

b. activity interrelations are not considered

Explanation:

A bar chart schedule or Gantt chart is used to visualize task that scheduled over time.

Answer:

If the cell is placed in a surrounding solution which is hypotonic in nature.

Then the water from outside of the cell to the inside of the cell. The water will keep on moving from the outside of the cell to the inside of the cell.

The flow of water will take place until the outside environment of the cell and the inside of the cell becomes equal.

The flow of water will take place from the outside of the cell to the inside of the cell.

Answer:

The direction of motion of water molecules will be into the cell.

Explanation:

Explanation:

Given that

             [tex]rA(t)=(3.00 m/s)t\hat{i}+ (1.00 m/s^2)t^2\hat{j}\texttt{ and }rB(t)=(4.00 m/s)t\hat{i}+ (-1.00 m/s^2)t^2\hat{j}[/tex]

We need to find distance when t = 3 s

Substituting t = 3 s

             [tex]rA(t)=(3.00 m/s)\times 3\hat{i}+ (1.00 m/s^2)\times 3^2\hat{j}=9\hat{i}+9\hat{j}\\\\rB(t)=(4.00 m/s)\times 3\hat{i}+ (-1.00 m/s^2)\times 3^2\hat{j}=12\hat{i}-9\hat{j}[/tex]

[tex]\texttt{Displacement = }12\hat{i}-9\hat{j}-(9\hat{i}+9\hat{j})=3\hat{i}-18\hat{j}[/tex]

[tex]\texttt{Magnitude = }\sqrt{3^2+(-18)^2}=18.3m[/tex]

Option C is the correct answer.

The distance between object A and object B is approximately 18.248 meters. (Choice C)

In this question we must apply the concepts of vector difference, dot product and norm to determine the distance between objects A and B, in meters:

[tex]r_{B/A} = \sqrt{(\vec r_{B}-\vec r_{A})\,\bullet\,(\vec r_{B}-\vec r_{A})}[/tex] (1)

Where:

If we know that [tex]\vec r_{A} = (3\cdot t, t^{2})\,\left[m\right][/tex], [tex]\vec r_{B} = (4\cdot t,-t^{2})\,\left[m\right][/tex] and [tex]t = 3\,s[/tex], then the distance of B relative to A is:

[tex]r_{B/A}=\sqrt{t^{2}+4\cdot t^{4}}[/tex]

[tex]r_{B/A} = t\cdot \sqrt{1+4\cdot t^{2}}[/tex]

[tex]r_{B/A} = 3\cdot \sqrt{1+4\cdot 3^{2}}[/tex]

[tex]r_{B/A} \approx 18.248\,m[/tex]

The distance between object A and object B is approximately 18.248 meters. (Choice C) [tex]\blacksquare[/tex]

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Answer:

Tm = 1,728.38 °C

Explanation:

mass of metal forging (Mm) = 67.2 kg

specific heat capacity of metal forging (Cm) = 438 J/kg°C

initial temperature of metal forging (Tm) = ?

final equilibrium temperature (Te) = 58.3 °C

mass of oil (Mo) = 786 kg

specific heat capacity of oil (Co) = 2950 J/kg°C

temperature of oil (To) = 37.1 °C

Mm × Cf × (Tm - Te) = Mo × Co × (Te - To)

Tm = [tex]\frac{Mo x Co x (Te - To) }{Mm x Cf}[/tex] + Te

Tm = [tex]\frac{786 x 2950 x (58.3 - 37.1) }{67.2 x 438}[/tex] + 58.3

Tm = 1,728.38 °C

Answer:

The frequency of the standing wave in the second case is higher than that in the first case

Explanation:

The frequency and wavelength of a wave are related.

The moment you sliced the bottle, you've reduced the wavelength of the bottle.

When wavelength decreases, frequency increases and vice versa.

So, When frequency increases in the second case, more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.

Answer:

this description is valid for mediadle displacement, bone is an acceptable description

Explanation:

The description of a person's position must be done with a position vector. These vectors must have magnitude, a given direction and a starting point.

In the description this has a starting point corner NO of pine and 675.

Each displacement occurs with respect to the previous one, indicating the magnitude of the displacement and its direction.

After analyzing  this description is valid for mediadle displacement, bone is an acceptable description

Answer:

a) [tex]t=2.6\ s[/tex]

b) [tex]s=43.7747\ m[/tex]

Explanation:

Given:

length of inclined roof, [tex]l=54\ m[/tex]

inclination of roof below horizontal, [tex]\theta=17^{\circ}C[/tex]

acceleration of hammer on the roof, [tex]a_r=2.87\ m.s^{-2}[/tex]

height from the lower edge of the roof, [tex]h=46.5\ m[/tex]

Now, we find the final velocity when leaving the edge of the roof:

Using the equation of motion:

[tex]v^2=u^2+2.a_r.l[/tex]

[tex]v^2=0^2+2\times 2.87\times 54[/tex]

[tex]v=17.6057\ m.s^{-1}[/tex]

The direction of this velocity is 17° below the horizontal.

∴Vertical component of velocity:

[tex]v_y=v.sin\ \theta[/tex]

[tex]v_y=17.6057\times sin\ 17^{\circ}[/tex]

[tex]v_y=5.1474\ m.s^{-1}[/tex]

a.

So, the time taken to fall on the ground:

[tex]h=ut+\frac{1}{2} g.t^2[/tex]

here:

initial velocity, [tex]u=v_y=5.1474\ m.s^{-1}[/tex]

putting respective values

[tex]46.5=5.1474\times t+0.5\times 9.8\times t^2[/tex]

[tex]t=2.6\ s[/tex]

b.

Horizontal component of velocity, [tex]v_x=v.cos\ \theta=17.6057\ cos\ 17^{\circ}=16.8364\ m.s^{-1}[/tex]

Since there is no air resistance so the horizontal velocity component remains constant.

∴Horizontal distance from the edge of the roof where the hammer falls is given by:

[tex]s=v_x.t[/tex]

[tex]s=16.8364\times 2.6[/tex]

[tex]s=43.7747\ m[/tex]

Using equations of motion, it's calculated that it takes about 3.07 seconds for the hammer to fall to the ground from the roof. The hammer also travels approximately 89.2 meters horizontally from the roof to the ground.

The question is related to physics concepts of motion under gravity and kinematics. For simplicity, let's ignore air resistance.

The time it takes for the hammer to fall to the ground from the edge of the roof can be calculated using the equation of motion: h = 0.5gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s²), and t is the time. Solving the equation for time (t): t = sqrt(2h/g). Substituting the given values, we get t = sqrt((2*46.5)/9.8) ≈ 3.07 s.

The horizontal distance travelled by the hammer can be calculated using the formula: distance = speed × time. The horizontal speed of the hammer when it falls off the roof will be the same speed it had just as it left the roof due to the roof slope acting on it with constant acceleration. This can be gotten from the equation v = u + at, where u is the initial velocity (0 m/s), a is the acceleration (2.87 m/s²) and t is the time. The time here is the time it takes for the hammer to slide down the roof, gotten by time = distance/speed = 54.0/v. Solving all these gives a distance of approximately 89.2 m.

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Answer:

D. 6 m/s²

Explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (60 m/s − 0 m/s) / 10 s

a = 6 m/s²

The acceleration of the car is 6m/s².

To find the correct option among all the options, we need to know about the acceleration.

Acceleration = ∆V/∆t = 60/10= 6 m/s².

Thus, we can conclude that the option (D) is correct.

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Answer:

P=133.71mmHg

Explanation:

the standard free energy of formation for liquid ethanol is -174/9 kj/mol and that for gaseous ethanol is -168.6 kj/mol. calculate the vapour pressure of ethanol at

assumption:

is that temperature is at 25C, at standard pressure of 1bar(750mmHg)

ethanol is an ideal gas

The free energy of ethanol liquid does not vary with pressure,

C2H5OH(l)⟶C2H5OH(g)

free energy of formation on the reactant side is  -174.9 kj/mol

fro the product side is  -168.6 kj

∅Gvap-∅G(l)=-168.6kj/mol-(-174.9kj/mol)

+6.3kj/mol

∅G=∅Gvap+RTlnK-∅Gliq

∅G=0

0=+6.3kj/mol+8.314Jk/mol/k(298)InK

-6.3/(RT)=Lnk

taking the exponential of both sides

[tex]e^{-6300/(8.314*298)} =K[/tex]

0.178=k

k=p/[tex]p^{0}[/tex]

P^0=refers to the pressure of ethanol vapour at its standard state

partial pressure , which is 750 mmHg

P=0.178*750

P=133.71mmHg

Final answer:

The vapor pressure of ethanol at a given temperature can be calculated using the Clausius-Clapeyron equation.

Explanation:

The vapor pressure of a substance is related to its standard free energy of formation and temperature. To calculate the vapor pressure of ethanol at a given temperature, we can use the Clausius-Clapeyron equation:

ln(P₂/P₁) = △Hvap/R × (1/T₁ - 1/T₂)

Where P₁ and P₂ are the vapor pressures at temperatures T₁ and T₂ respectively, △Hvap is the enthalpy of vaporization, R is the gas constant, and ln denotes the natural logarithm.

By substituting the given values for △Hvap = -174/9 kJ/mol, T₁ = 20.0 °C (293 K), and T₂ = desired temperature, we can solve for P₂.

Answer:

Approximately [tex]\rm 11.2 \; N \cdot kg^{-1}[/tex] at that distance from the center of the planet.

Option A) The low value of [tex]g[/tex] near the cloud top of Saturn is possible because of the low density of the planet.

Explanation:

The value of [tex]g[/tex] on a planet measures the size of gravity on an object for each unit of its mass. The equation for gravity is:

[tex]\displaystyle \frac{G \cdot M \cdot m}{R^2}[/tex],

where

To find an equation for [tex]g[/tex], divide the equation for gravity by the mass of the object:

[tex]\displaystyle g = \left.\frac{G \cdot M \cdot m}{R^2} \right/\frac{1}{m} = \frac{G \cdot M}{R^2}[/tex].

In this case,

Calculate [tex]g[/tex] based on these values:

[tex]\begin{aligned} g &= \frac{G \cdot M}{R^2}\cr &= \frac{6.67\times 10^{-11}\; \rm N \cdot kg^{-2} \cdot m^2\times 5.68\times 10^{26}\; \rm kg}{\left(5.82\times 10^7\; \rm m\right)^2} \cr &\approx 11.2\; \rm N\cdot kg^{-1} \end{aligned}[/tex].

Saturn is a gas giant. Most of its volume was filled with gas. In comparison, the earth is a rocky planet. Most of its volume was filled with solid and molten rocks. As a result, the average density of the earth would be greater than the average density of Saturn.

Refer to the equation for [tex]g[/tex]:

[tex]\displaystyle g = \frac{G \cdot M}{R^2}[/tex].

The mass of the planet is in the numerator. If two planets are of the same size, [tex]g[/tex] would be greater at the surface of the more massive planet.

On the other hand, if the mass of the planet is large while its density is small, its radius also needs to be very large. Since [tex]R[/tex] is in the denominator of [tex]g[/tex], increasing the value of [tex]R[/tex] while keeping [tex]M[/tex] constant would reduce the value of [tex]g[/tex]. That explains why the value of [tex]g[/tex] near the "surface" (cloud tops) of Saturn is about the same as that on the surface of the earth (approximately [tex]9.81\; \rm N \cdot kg^{-1}[/tex].

As a side note, [tex]5.82\times 10^7\rm \; m[/tex] likely refers to the distance from the center of Saturn to its cloud tops. Hence, it would be more appropriate to say that the value of [tex]g[/tex] near the cloud tops of Saturn is approximately [tex]\rm 11.2 \; N \cdot kg^{-1}[/tex].

concept is gravitational force. Saturn's low value of g on its surface is possible because of its low average density, which is less than the density of water.

The value of g on the surface of Saturn is determined by its mass and radius. The low value of g on Saturn is possible because of its low average density. Saturn's mass is much larger than Earth's, but its density is much lower, resulting in a lower value of g on its surface.

The low density of Saturn, which is only 0.7 g/cm³, is less than the density of water. This means that Saturn would be light enough to float if placed in water. Therefore, despite its large mass, the low density of Saturn allows for a low value of g on its surface.

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Answer:

B) The cosmic background radiation is expected to contain spectral lines of hydrogen and helium, and it does.

Explanation:

Answer:

a.large particles such as gravel

Explanation:

High energy environments are typically associated with larger particles such as gravel due to the ability of these environments to move larger matter. Smaller particles are generally found in lower energy environments.

High energy environments, such as fast-flowing rivers or coastal areas with strong waves, are most capable of moving larger particles. So, among these options, the environments with high energy are most likely to contain large particles such as gravel (a). The other particles listed (silt, manganese nodules, cosmogenous sediments, clay) require less energy to be moved, so they are likely to be found in lower energy environments.

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Answer:

Time taken to cover the distance 11.45 s.

Explanation:

The given parameters:

Initial Velocity(u)=24 m/s

Acceleration (a)=8 [tex]m/s^{2}[/tex]

Distance or Displacement(s)=800 m

Displacement or Distance is equal in the above because it travels in a straight line.

We have to apply Second Equation of Motion,

s=ut+[tex]\frac{1}{2} at^{2}[/tex]

800=24t + 4[tex]t^{2}[/tex]

200=6t + [tex]t^{2}[/tex]

[tex]t^{2}[/tex] + 6t - 200=0

Solving, the quadratic equation to find out the roots, we get that the possible values of t will be 11.45 s and a negative value.

The negative value will be neglected as time cannot be negative.

Hence, the time taken is 11.45 s.

Answer:

The Correct Option is C (coarse lithogenic sediment)

Explanation:

This is because all other options are found on sea floors, except for coarse lithogenic sediments that are as a result of erosion on land. Both calcareous and siliceous ooze are common sea sediments. Abyssal clay and manganese nodule are red clay and rock concretion respectively found in the bottom of the sea.

Answer: the car on the right should yield to the car that arrived first. That is When the car on the left arrives first

Explanation:

It must be noted that the law did not grant the 'right-of-way'. The law only says when the right of way must be yielded. The law does state who must yield the right of way neither does the law give right of way to anyone.

Yielding the right of way to another vehicle simply means that you are letting them go before you in a traffic situation.

Therefore, When two vehicles approaches an intersection without no traffic signs or signals, (that is, an uncontrolled intersection) the two vehicles must slow down. Always Yield to vehicles already in the uncontrolled intersection and drivers who arrive at the uncontrolled intersection before you.

The vehicle on the left should always yield to the right of the way to the vehicle on the right. The driver with ''right-of-way'' must pay attention to avoid a collision.

Answer:

Explanation:

Given

mass of gas [tex]m=8000 gm=8 kg[/tex]

Area of Piston [tex]A=5 cm^2[/tex]

[tex]T_1=15^{\circ}C[/tex]

[tex]T_2=27^{\circ}C[/tex]

no of moles [tex]n=0.28[/tex]

Work done on the gas is given by

[tex]W=-P\Delta V[/tex]

[tex]P\Delta V[/tex] can also be written as [tex]nR\Delta T[/tex]

as PV=nRT

[tex]W=-nR\Delta T[/tex]

[tex]W=-0.28\times 8.314\times (27-15)[/tex]

[tex]W=-27.93 J[/tex]

negative sign indicates that work is done on the system i.e. surrounding done a positive work on the gas