two trains start from towns 240 mi apart and travel towards each other on parallel tracks. they pass each other 1.6 hr later. If one train travels 10 mph faster than the other, find the speed of each train ...?

Answer : [tex]L=66.18\ kgm^2/s[/tex]

Explanation :

It is given that,

Mass, m = 5.7 kg

radius, R = 0.43 m

frequency, f = 20 rev/s

Angular momentum, [tex]L=I\omega[/tex]

I is the moment of inertia of disk, [tex]I=\dfrac{MR^2}{2}[/tex]

we know that, [tex]\omega = 2\pi \nu[/tex]

so, [tex]L=MR^2\pi \nu[/tex]

[tex]L= 5.7\ kg\times (0.43\ m)^2\times3.14\times 20\ rev/s[/tex]

[tex]L=66.18\ kgm^2/s[/tex]

Hence, the magnitude of angular momentum of spinning disk is [tex]66.18\ kgm^2/s[/tex].

Answer: The true statement form the given statements is "the athlete is not doing any work because he does not move the weight.".

Explanation:

The formula for work done is as follows,

[tex]W = Fscos\theta[/tex]

Here, F is the force, s is the displacement and theta is the angle between force and displacement.

In the given problem, an athlete holds 50 kg on his head for 10 seconds. The angle between force and displacement is 90 degree.

In this case, the work done is zero.

Therefore, the athlete is not doing any work because he does not move the weight.

Answer:

D. surface wave

Explanation:

A) Transverse Waves

As the energy is propagated through the medium and then medium particles moves to and fro perpendicular to wave propagation then this is known as transverse waves.

B) Longitudinal waves

As energy is propagated through the medium and then medium particles oscillates in direction of wave propagation then it is known as longitudinal waves.

C) Primary waves

these waves are due to compression and expansion of medium and it can travel at high speed. It is moreover similar to longitudinal waves

D) Surface Waves

In these type of waves the disturbance or energy is propagated through the medium particles on the surface of the water in the shape of concentric circles.

So surface wave is characterized by circular motion

the independent varible is old and new and the dependent variable is 20 T-shirts can I get brainliest

Explanation:

An independent variable is a variable whose value does not depend on any other factor. Whereas a dependent variable is a variable whose value depends on another factor.

Hence, in the given situation old and new detergent are independent variables as they do not depend on any other factor.

On the other hand, 20 dirty T-shirts are dependent variable because they get clean only if the detergent is strong enough.

Answer;

-Reference point

The x represents the reference point on a motion map.

Explanation;

-Motion maps are another way to represent the motion of an object.  (other representations are graphical and mathematical models).

-Motion maps are a visual way to represent an object’s motion at various time

-. A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point.

-The relationships between motion and reference point is that When an object changes position over time relative to a reference point, the object is in motion. This means that there relationship is they are similar.

The x represents a reference point on a motion map. The correct option is A.

Another technique to depict an object's motion is motion maps. Models in mathematics and graphics are alternative forms of representation. A visual representation of an object's motion through time is called a motion map.

A reference point is a location or object that is used as a point of comparison to ascertain whether something is moving. When an object shifts in relation to a fixed point, it is said to be in motion.

The relationship between motion and reference point is that an object is in motion when its position with respect to a reference point varies over time. This indicates that they have a similar relationship.

Therefore, the value x represents a reference point on a motion map. The correct option is A.

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The answer is A. Hope this helps! :)

For this case what we must do is calculate the centripetal force of the object.

By definition, the centripetal force is given by:

[tex] F = m(\frac{v^2}{r})
[/tex]

Where,

v: tangential speed

r: radius of the circular path

m: mass of the object

Substituting values we have:

[tex] F = 0.25 * (\frac{12.2 ^ 2}{1.6})

F = 23.26
[/tex]

Answer:

The centripetal force of the ball is given by:

[tex] F = 23.26 N [/tex]

Answer:

The answer is B) 23 N

Explanation:

I got the correct answer on the pre-test.

the answer to the question is A.

Answer:

a

Explanation:

Answer:

a = 0

Explanation:

When a baseball is thrown straight upward, it moves upward under the action of gravity. We know that at the highest point, the speed of the object is equal to 0. The rate of change of velocity is called acceleration of an object.

Since, the speed is 0 at the height point, so, its acceleration at its greatest height is 0. Hence, this is the required solution.

When a baseball is thrown straight upward, its acceleration at its greatest height is equal to: c. 0 [tex]m/s^2[/tex]

In Physics, the acceleration of an object or body is calculated by subtracting its initial velocity from the final velocity and dividing by the time.

Mathematically, acceleration is given by the formula;

[tex]Acceleration = \frac{V\; - \;U}{t}[/tex]

Where:  

A baseball that is thrown thrown straight upward, experiences motion due to the acceleration of gravity.

Also, the final speed of an object is equal to zero (0) at the greatest height because it came to a stop while the initial velocity is equal to zero (0), since it would accelerate from rest.

Deductively, the rate of change of velocity with respect to time is equal to zero (0) and this is the value of baseball's acceleration.

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was the answer even right

The solution to arctan[tan(7π/4)] is -(π/4).

To solve the expression arctan[tan(7π/4)], simplify it using the properties of trigonometric functions and inverse trigonometric functions.

First, examine the value of tan(7π/4). The tangent function has a period of π, meaning it repeats its values every π radians.

Therefore, find an equivalent angle within the range of one period (0 to π) that has the same tangent value.

7π/4 can be reduced to 3π/4 by subtracting 2π, as it falls within the same period.

Now, arctan[tan(3π/4)].

The arctan function (or inverse tangent) "undoes" the tangent function, giving us the original angle. However, it's important to note that arctan has a range of -π/2 to π/2.

The angle 3π/4 falls within the range of π/2 to 0, so its corresponding angle within the range of arctan is -(π/4).

Therefore, the solution to arctan[tan(7π/4)] is -(π/4).

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The final speed of the 100-g ball is about 5.3 m/s to the left

The final speed of the 200-g ball is about 1.7 m/s to the right

[tex]\texttt{ }[/tex]

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

[tex]\large {\boxed {F = ma }[/tex]

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

mass of ball 1 = m₁ = 100 g

initial velocity of ball 1 = u₁ = 4.0 m/s

mass of ball 2 = m₂ = 200 g

initial velocity of ball 2 = u₂ = -3.0 m/s

Asked:

final velocity of ball 1 = v₁ = ?

final velocity of ball 2 = v₂ = ?

Solution:

Firstly , we will use Conservation of Momentum Law as follows:

[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2[/tex]

[tex]100(4.0) + 200(-3.0) = 100v_1 + 200v_2[/tex]

[tex]-200 = 100v_1 + 200v_2[/tex]

[tex]-2 = v_1 + 2v_2[/tex] → Equation 1

[tex]\texttt{ }[/tex]

If the collision is perfectly elastic , then:

[tex]u_1 - u_2 = v_2 - v_1[/tex]

[tex]4.0 - (-3.0) = v_2 - v_1[/tex]

[tex]7.0 = v_2 - v_1[/tex] → Equation 2

[tex]\texttt{ }[/tex]

Let's solve the two Equations above:

(Equation 1) + (Equation 2) ↓

[tex]-2 + 7.0 = (v_1 + 2v_2) + (v_2 - v_1)[/tex]

[tex]5.0 = 3v_2[/tex]

[tex]v_2 = 5.0 \div 3[/tex]

[tex]v_2 = 1\frac{2}{3} \texttt{ m/s}[/tex]

[tex]v_2 \approx 1.7 \texttt{ m/s}[/tex]

[tex]\texttt{ }[/tex]

[tex]-2 = v_1 + 2v_2[/tex]

[tex]-2 = v_1 + 2(1\frac{2}{3})[/tex]

[tex]v_1 = -2 - 3\frac{1}{3}[/tex]

[tex]v_1 = -5\frac{1}{3} \texttt{ m/s}[/tex]

[tex]v_1 \approx -5.3 \texttt{ m/s}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Dynamics

[tex]\texttt{ }[/tex]

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

C. Acceleration Increases As Mass Decreases.

Answer:

t = 0.55 s and t = 1.14 s

Explanation:

as we know that height in terms of time is given as

[tex]h = 3 + 27t - 16 t^2[/tex]

now we have to find the time at which its height is h = 13 ft

so here we can say

[tex]13 = 3 + 27 t - 16 t^2[/tex]

[tex]16 t^2 - 27 t + 10 = 0[/tex]

[tex]t = \frac{27 \pm \sqrt{27^2 - 4(16)(10)}}{2(16)}[/tex]

[tex]t = \frac{27 \pm 9.43}{32}[/tex]

[tex]t = 1.14, 0.55[/tex]

so it will be at h = 13 ft height at t = 0.55 s and t = 1.14 s

Answer:

A. Mark's physics book is on the desk. Mark pushes horizontally (from the side) on the book, but the book does not move.

DIAGRAM B

B. Kendall's physics book is on the desk. Kendall pushes horizontally (from the side) on the book, and the book moves across the desk at a constant speed. |

DIAGRAM B

C. Jenny pushes a cart at constant velocity down the grocery store aisle.

DIAGRAM B

D. Eddy is driving his Camaro down a straight, level road while on cruise control.

DIAGRAM B

E. Ryan is accelerating his Dakota down a straight, level road.

DIAGRAM C

F. Jackie's Viper is parked on the shoulder of the road while she changes a flat tire.

DIAGRAM A

Explanation:

A. Since the book does not move even after being pushed it is leveled in all forces.

B. Since it is pushed at a constant speed, all forces are equal.

C. Since it is pushed at a constant speed, all forces are equal.

D. Since it is driven at a constant speed on cruise control, all forces are equal.

E. Since he is accelerating, which means it is being driven much faster than the friction that is pushing the car back, the forces are unequal.

F. The only forces acting on the is the car on the ground and the ground on the car, there is no other forces of friction pushing it back or the car being pushed forward. It is parked.

In option A, the book does not move, so the force diagram would show the normal force and the force of friction. In option B, the book moves at a constant speed, so the force diagram would show the normal force and the force of friction in the same direction as the applied force. Option C involves a cart moving at constant velocity, which would have a force diagram showing the forward push and the force of friction. Options D and E involve cars on level roads, with D having a balanced force diagram and E having unbalanced forces causing acceleration. Option F involves a parked car with a balanced force diagram.

The force diagram that best represents the scenario described in option A, where Mark's physics book is on the desk and Mark pushes horizontally on the book but it does not move, would be a free-body diagram showing only the normal force and the force of friction acting on the book. Since the book does not move, the forces are balanced, with the force of friction equal in magnitude and opposite in direction to the horizontal force applied by Mark.

In option B, where Kendall's physics book is on the desk and Kendall pushes horizontally on the book and it moves across the desk at a constant speed, the force diagram would also include the normal force and the force of friction, but the force of friction would be in the same direction as Kendall's applied force, since the book is moving. The forces are balanced and the net force is zero.

In option C, where Jenny pushes a cart at constant velocity down the grocery store aisle, the force diagram would include a force in the forward direction representing Jenny's push, as well as the force of friction opposing the motion. The forces are balanced and the net force is zero.

In option D, where Eddy is driving his Camaro down a straight, level road while on cruise control, there would be a force diagram showing the force of the engine pushing the car forward, the force of friction opposing the motion, and the normal force. The forces are balanced and the net force is zero.

In option E, where Ryan is accelerating his Dakota down a straight, level road, the force diagram would include the force of the engine pushing the car forward, the force of friction opposing the motion, and the normal force. The net force is non-zero, as the forces are unbalanced and causing the acceleration.

In option F, where Jackie's Viper is parked on the shoulder of the road while she changes a flat tire, there would be a force diagram showing only the force of gravity acting on the car, the normal force from the ground, and the force of friction from the ground. The forces are balanced and the net force is zero.

The atom underwent alpha decay, emitting 2 protons and 2 neutrons, transforming from polonium (Po-170) to lead (Pb-166).

The atom originally was a polonium (Po) atom with 84 protons and 86 neutrons (Po-170). It underwent alpha decay, a type of radioactive decay where it emitted an alpha particle, consisting of 2 protons and 2 neutrons. As a result, the atom transformed into a lead (Pb) atom with 82 protons and 84 neutrons (Pb-166).

This process reduced the atomic number by 2 and the mass number by 4, leading to the formation of a different element. Alpha decay occurs when an unstable nucleus emits an alpha particle, reducing both its atomic number and mass number. It is a natural process observed in certain heavy and unstable elements as they strive to achieve a more stable configuration, often resulting in the formation of a different element.

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Final answer:

An object in free-fall near Earth's surface experiences a constant acceleration due to gravity, denoted by 'g' and averaging 9.80 m/s². This allows for uniform predictions of an object's motion when air resistance is negligible.

Explanation:

An object moving with constant acceleration near the surface of the Earth is primarily influenced by the acceleration due to gravity. This acceleration, commonly represented by the symbol g, has an average value of 9.80 m/s². It is important to note that this value can be considered constant when air resistance is negligible, thus letting us apply kinematics equations to any such falling object to predict its motion. The constant nature of acceleration due to gravity allows for a wide range of interesting physical problems and applications.

It is essential to understand that the force of gravity causes objects to fall towards the Earth's center, and it is this force that imparts uniform acceleration to free-falling objects. Furthermore, gravity's influence is such that even varying factors like latitude, altitude, and geographical differences only slightly alter its magnitude, and for most practical purposes in high school physics, the average value of 9.80 m/s² is used.

Answer: Law of Conservation of Mass

Explanation:

A balanced chemical equation represents the 'Law of Conservation of Mass '

Law of Conservation of Mass states that  'in chemical reaction mass can neither be created nor be destroyed '.The total mass of the reactant in chemical reaction is equal to the total mass of the products formed in a chemical reaction.

For example : [tex]2H_2+O_2\rightarrow 2H_2O[/tex]

Mass of reactants = Mass of the products

mass of the reactants = 2(2 × 1) + (2 × 16) = 36 g/mol

Mass of the products = 2[(2 × 1 ) + (1 × 16)] = 36 g/mol

As from the above calculations, we find that the mass of the reactants is equal to the mass of the products. Hence, this equation follows law of conservation of mass.

A balanced chemical equation adheres to the law of conservation of mass, which asserts that matter is neither created nor destroyed in a chemical reaction.

Law Behind Balanced Chemical Equations:

The law that is represented by a balanced chemical equation is the law of conservation of mass. This fundamental law states that matter cannot be created or destroyed in a chemical reaction. Therefore, a balanced chemical equation ensures that the number of atoms for each element is equal on both sides, reflecting the unchanging total mass in the reaction.

To illustrate, look at the equation for the reaction of hydrogen with oxygen to form water: 2H₂(g) + O₂(g) → 2H₂O(l). This equation is balanced because it has the same number of hydrogen atoms (4 H atoms) and oxygen atoms (2 O atoms) on both the reactant and product sides.

Balancing chemical equations involves adjusting the coefficients before each substance so that the total number of atoms of each element is the same on both sides of the equation. This practice aligns with the law of conservation of matter, ensuring that the mass before and after the reaction remains constant, and only the arrangement of atoms changes to form new substances.

To solve this we must be knowing each and every concept related to mass. Therefore, 705.6N is the weight of a person whose mass is 72kg.

The density and kind of atoms in any particular item are described by mass, which is a scientific word. The kilogram (kg) is the SI measurement of mass, however mass could also be measured using pounds (lb).

Consider a pillowcase packed with feathers as well as a comparable pillowcase loaded with bricks to rapidly grasp the notion of mass. The bricks have a higher mass because of atoms in them are heavier and denser. As a result, even when the pillowcases have the same size and therefore are filled with the same extent, one has significantly more mass compared to the other.

weight= mass× acceleration due to gravity

weight= 72kg×9.8

          =705.6N

Therefore, 705.6N is the weight of a person whose mass is 72kg.

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Answer: Option A.

Explanation: When you turn on your laptop, you are allowing the electrical energy to flow in the components of the laptop.

Once it is on, you can see that your laptop is generating light (from the screen) and sound (maybe if you are listening to music or something). And as the electricity is passing through the components of the laptop, the components start to raise their temperature, and then you also are generating thermal energy.