Water has a high heat capacity. What does this term mean? a) Water is relatively resistant to an increase in temperature. b) Water heats up or cools down readily c) Water provides a useful source of stored kilocalories. d) Water provides excellent insulation for the body.

Answer:

      v = 14.88 m / s

Explanation:

For this exercise let's use energy conservation. We place the reference system on the ground

Start. Tarzan before jumping

         Em₀ = U = m g h

Final. Upon reaching the ground

        [tex]Em_{f}[/tex]= K = ½ m v²

Energy is conserved

       Em₀ = [tex]Em_{f}[/tex]

        m g h = ½ m v²

        v² = 2gh

        v = √ 2gh

Let's calculate

        v = √ (2 9.8 11.3)

        v = 14.88 m / s

Answer:

Earl needs to touch the pan to the burner.

Explanation:

Earl is demonstrating heat transfer by conduction.

Conduction is the transition of heat energy by direct contact. Hotter molecules have more momentum and they move faster.These hot molecules collide with the cooler ones, transfer their energy to cooler particles , this process is continued to pass it on to other molecule near to them.

Earl needs to touch the pan to the burner.

Answer:

D the answer is D

Explanation:

Answer:

This is a table of common chemicals that produce nice crystals. The color and shape of the crystals are included. Many of these chemicals are available in your home. Other chemicals in this list are readily available online and are safe enough for growing crystals at home or in a school. Recipes and specific instructions are available for hyperlinked chemicals.

Ionic compounds, held together by electrostatic forces, form crystalline structures that exhibit rigid and brittle properties. They tend to have high melting and boiling points, reflecting the strength of the ionic bonds. Though ionic solids are poor conductors in their solid state, they readily dissolve in water, becoming good conductors when melted or dissolved.

Compounds composed of ions are called ionic compounds (or salts), and their constituent ions are held together by ionic bonds: electrostatic forces of attraction between oppositely charged cations and anions. The properties of ionic compounds shed some light on the nature of ionic bonds. Ionic solids exhibit a crystalline structure and tend to be rigid and brittle; they also tend to have high melting and boiling points, which suggests that ionic bonds are very strong. Ionic solids are also poor conductors of electricity for the same reason the strength of ionic bonds prevents ions from moving freely in the solid state. Most ionic solids, however, dissolve readily in water. Once dissolved or melted, ionic compounds are excellent conductors of electricity and heat because the ions can move about freely.

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Answer:

v = 2 m/s (West)

Explanation:

Given

m = 2 Kg

v initial = 4 m/s (East)

F = 6 N (West)

t = 2 s

We can use the formula

v = v initial + a*t

if F = m*a  ⇒   a = F/m = 6 N / 2 Kg

a = 3 m/s² (West)

then

v = v initial + a*t = (4 m/s) + (-3 m/s²)(2 s)

v = - 2 m/s = 2 m/s (West)

The velocity is a vector quantity. The velocity of the given cart is 2 m/s to the west.  

To solve the given problem, use the kinematic equation,

[tex]v = s + at[/tex]........................1

Where,

[tex]s[/tex] - initial speed = 4 m/s

[tex]a[/tex] - acceleration

[tex]t[/tex] - time - 2 s  

Acceleration can be calculated by the formula,

[tex]F = ma[/tex]   or

[tex]a = \dfrac Fm[/tex]

Where,

m = mass =  2 Kg    

F = force = 6 N  

So,

[tex]a = \dfrac {6}2\\\\a = 3\rm \ m/s^2[/tex]

Put the values in equation 1,

[tex]v = 4 +3\times 2\\\\v = \bold {2 m/s}[/tex]

Therefore, the velocity of the given cart is 2 m/s.

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Answer:31.62 m/s

Explanation:

Given

mass of body [tex]m=400 kg[/tex]

Pull on chain is [tex]F_1=6000g N=60 kN[/tex]

Pull get smaller at the rate of [tex]F_2=360g N/m[/tex]

Net Upward Force [tex]F=6000 g-360 g\times 10=24 kN[/tex]

net acceleration [tex]a=\frac{F}{m}[/tex]

[tex]a=\frac{24\times 1000}{m}[/tex]

[tex]a=\frac{24000}{400}[/tex]

[tex]a=60 m/s^2[/tex]

but g is acting downward

[tex]a_{net}=a-g=60-10=50 m/s^2[/tex]

using [tex]v^2-u^2=2 as[/tex]

here initial velocity is zero

[tex]v^2=2\times 50\times 10[/tex]

[tex]v=31.62 m/s[/tex]

The velocity of the body will be "31.62 m/s".

Given:

Mass of body,

Pull on chain,

The net upward force will be:

→ [tex]F = 6000-360\times 10[/tex]

      [tex]= 6000-3600[/tex]

      [tex]= 2400[/tex]

or,

      [tex]= 24 \ kN[/tex]

Now,

The net acceleration will be:

→ [tex]a = \frac{F}{m}[/tex]

     [tex]= \frac{24\times 1000}{400}[/tex]

     [tex]= 60 \ m/s^2[/tex]

But,

"g" is acting downwards then,

→ [tex]a_{net} = a -g[/tex]

          [tex]= 60-10[/tex]

          [tex]= 50 \ m/s^2[/tex]

By using,

→ [tex]v^2-u^2=2as[/tex]

          [tex]v^2= 2\times 50\times 10[/tex]

               [tex]= 1000[/tex]

            [tex]v = \sqrt{1000}[/tex]

               [tex]= 31.62 \ m/s[/tex]

Thus the above answer is right.

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Answer:

Utilize the Private VLAN feature to segregate network traffic at Layer 2, and

Utilize the ARP inspection feature to help prevent the misuse of gARP.

Explanation:

An Engineer designing layer 2 and layer 3 network, must Utilize the Private VLAN feature to segregate network traffic at Layer 2 and Utilize the ARP inspection feature to help prevent the misuse of gARP.

Answer:

Explanation:

According to ohm's law current flowing in a conductor is directly proportional to the voltage applied across two end of conductor.

i.e. [tex]V\propto R[/tex]

[tex]V=R I[/tex]

where R=resistance

[tex]R\propto L[/tex]

[tex]R\propto \frac{1}{d^2}[/tex]

whee L and d are length and Diameter

thus [tex]R=k \frac{L}{d^2}[/tex]

where k=constant of Variation

Answer:

[tex]4.91803\times 10^{-7}\ m[/tex]

Explanation:

[tex]\theta[/tex] = Angular seperation = [tex]3\times 10^{-5}\ rad[/tex]

[tex]\lambda[/tex] = Wavelength

We have relation

[tex]sin\theta=1.22\dfrac{\lambda}{d}\\\Rightarrow \lambda=\dfrac{dsin\theta}{1.22}\\\Rightarrow \lambda=\dfrac{2\times 10^{-2}sin(3\times 10^{-5})}{1.22}\\\Rightarrow \lambda=4.91803\times 10^{-7}\ m[/tex]

The maximum wavelength of the telescope is [tex]4.91803\times 10^{-7}\ m[/tex]

The maximum wavelength λ at which the two sources can be resolved is of  [tex]1.49 \times 10^{-10} \;\rm m[/tex].

Given data:

The diameter of the telescope is, d = 2 cm = 0.02 m.

The angular separation of the two point source of light is, [tex]\theta = 3.0 \times 10^{-5} \;\rm radians = 3.0 \times 10^{-5} \;\rm radians \times \dfrac{\pi}{180}\\\theta = 5.23 \times10^{-7}^{\circ}[/tex].

The angular separation of two point source is also known as apparent distance between the sources, and it is defined as the angle between the two  objects as viewed directly by the observer.

The standard relation for the angular separation of telescope is given as,

[tex]sin \theta = 1.22 \times \dfrac{\lambda}{d}[/tex]

here, [tex]\lambda[/tex] is the maximum wavelength of light.

Solving as,

[tex]sin (5.23 \times 10^{-7}) = 1.22 \times \dfrac{\lambda}{0.02}\\\\\lambda = \dfrac{sin (5.23 \times 10^{-7}) \times 0.02}{1.22} \\\\\lambda = 1.49 \times 10^{-10} \;\rm m[/tex]

Thus, we can conclude that  the maximum wavelength λ at which the two  sources can be resolved is of [tex]1.49 \times 10^{-10} \;\rm m[/tex].

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Answer:

C.inertia

Explanation:

Inertia is a property of matter to maintain its state of motion.

In this case, if the car was moving along with the people in it when the car stopped, the inertia of the people will cause them to continue moving.

This is why in a crash a person can be shot from the car, due to the inertia he has from his previous state of motion.

The complete sentence is: Unrestrained occupants of a car keep moving during the time the car takes to stop due to inertia. (option C)

Unrestrained occupants of a car continue moving forward when the car stops due to inertia, as an object in motion remains in motion unless acted upon by an external force.

Unrestrained occupants of a car keep moving during the time the car takes to stop due to inertia. This phenomenon occurs because, according to Newton's first law, an object in motion tends to stay in motion with the same speed and in the same direction unless acted upon by an unbalanced force. In the context of a car, when it suddenly stops, the passengers inside will continue moving forward because their bodies were initially in motion and there is no forward force directly applied to them to cause a deceleration similar to that of the car.

Centripetal force is the force that causes an object moving in a circular path to move towards the center of the path. However, when the force disappears, inertia is what carries the object in a straight line, tangent to the circular path. While centrifugal force is often used in common language to describe the sensation of being pushed outward in a rotating system, it is not an actual force but rather a perceived effect due to inertia.

Balanced forces are equal and opposite, causing no change in an object's movement, leading to static equilibrium. On the contrary, unbalanced forces change an object's velocity or direction, causing it to move or accelerate.

The primary difference between balanced and unbalanced forces lies in their effects on the motion of an object. Balanced forces are equal and opposite forces that act on an object, resulting in no change in its velocity or direction. An example would be a static car or an ice hockey stick lying flat with two equal and opposite forces applied to it. Friction is negligible and the gravitational force is balanced by the support, leading to static equilibrium.

On the other hand, unbalanced forces are not equaled.

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Answer:

[tex]\Delta l=0.015m[/tex]

Explanation:

We have given initial length of the steel guitar l = 1 m

Cross sectional area [tex]A=0.5mm^2=0.5\times 10^{-6}m^2[/tex]

Young's modulus [tex]\gamma=2\times 10^{11}Pa[/tex]

Force F = 1500 N

So stress [tex]=\frac{force}{area}=\frac{1500}{0.5\times 10^{-6}}=3000\times 10^{-6}=3\times 10^{9}Pa[/tex]

We know that young's modulus [tex]=\frac{stress}{strain}[/tex]

So [tex]2\times 10^{11}=\frac{3\times 10^{9}}{strain}[/tex]

[tex]strain=1.5\times 10^{-2}=0.015m[/tex]

Now strain [tex]=\frac{\Delta l}{l}[/tex]

[tex]0.015=\frac{\Delta l}{1}[/tex]

[tex]\Delta l=0.015m[/tex]

Answer:

Explanation:

L = 1 m

A = 0.5 mm² = 0.5 x 10^-6 m²

Y = 2 x 10^11 Pa

F = 1500 N

ΔL = ?

Use the formula for the young's modulus

[tex]Y = \frac{FL}{A\Delta L}[/tex]

[tex]\Delta L = \frac{FL}{AY}[/tex]

[tex]\Delta L = \frac{1500\times 1}{0.5\times10^{-6}\times 2\times 10^{11}}[/tex]

ΔL = 0.015 m

ΔL = 0.02 m

Question:

The theory of force generation proposed is best supported by which of the following observations about Amoeba locomotion?

a. amoeboid movement stops upon expose to cytochalasins

b. amoeboid movement cannot occur if mitosis is blocked

c. moving amoeba cells produce more troponin than do stationary ones

d. the rate of movement is inversely proportional to the viscosity of the medium in the Amoeba moves

Answer:

The amoeba location can be supported by :The amoeboid movement stops upon expose to cytochalasins

Explanation:

The amoeboid movement common in eukaryotic cells.  cytochalasins are the type of drug that inhibits the growth of the micro filaments,  micro filaments capability to elongate are both implemented as important to make the force for movement in amoeba. further Cytochalasins are  known as the fungal metabolites which can bind the actin filaments and also restrict polymerization and elongation of actin. It can also permeate cell membranes, preventing the cellular translocation and cause cells to enucleate.

Answer:

The magnitude of the acceleration of the box is 2.01 m/s².

Explanation:

Hi there!

Please, see the attached figure for a graphical description of the problem.

We have the following horizontal forces:

Fr = friction force.

Fx = Horizontal component of the applied force, F.

And we have the following vertical forces:

Fy = vertical component of the applied force.

N = normal force exerted on the box.

W = weight of the box.

According to Newton´s second law:

∑F = m · a

Then, in the horizontal direction:

Fx - Fr = m · a

Where "m" is the mass of the box and "a" its acceleration.

Fx can be obtained by trigonometry (see figure):

Fx = F · cos 30°

Fx = 90.0 N · cos 30°

Fr is calculated as follows:

Fr = μ · N

Where μ is the coefficient of friction and N the normal force.

So, we have to find the magnitude of the normal force.

Using Newton´s second law in the vertical direction:

∑F = N + Fy - W = m · a

Notice that the box has no vertical acceleration, then:

N + Fy - W = 0

Solving for N:

N = W - Fy

The weight is calculated as follows:

W = m · g

Where g is the acceleration due to gravity:

W = 20.0 kg · 9.8 m/s² = 196 N

And the vertical component of the applied force can be obtained by trigonometry:

Fy = F · sin 30°

Fy = 90.0 N · sin 30°

The normal force will be:

N = W - Fy = 196 N - 90.0 N · sin 30°

N = 151 N

Now, we can calculate the friction force:

Fr = μ · N

Fr = 0.250 · 151 N

Fr = 37.8 N

And now, we can obtain the acceleration of the box:

Fx - Fr = m · a

(Fx - Fr) / m = a

(90.0 N · cos 30° - 37.8 N ) / 20.0 kg = a

a = 2.01 m/s²

The magnitude of the acceleration of the box is 2.01 m/s².

Answer:

3,000 stars.

Explanation:

Subtract the magnitude of the single star from the magnitude of the star cluster.

(+4) - (+1) = +3

Then multiply your answer by 1000

= 3,000 is a stars.

Answer:

Tilt of the Earth

Explanation:

The Earth's rotational axis is titled at an angle 23.4°. When then northern hemisphere is pointed towards the Sun it is summer in the northern hemisphere and winter in the southern hemisphere.

In the northern hemisphere a day would be longer and gets more sunlight than the southern hemisphere.

The same happens when it is summer in the southern hemisphere.

Answer:

The sun is father away during the winter.

Explanation:

In the northern hemisphere, during the winter it is summer in the southern hemisphere. The sun is farther away for us so the days get shorter in the winter since the sun inches away faster.

Answer:

Mercury - hydrargyrum (Hg)

Explanation:Mercury is a chemical element with the symbol Hg and atomic number 80. It is commonly known as quicksilver and was formerly named hydrargyrum.  

Symbol: Hg

Atomic number: 80

Atomic mass: 200.59 u

Melting point: -38.83 °C

Boiling point: 356.7 °C

Electron configuration: [Xe] 4d^14 5d^10 6s^2

Group :12

Ionization energy 1007.1J

Electronegativity :2

Crust Abundance : 0.085ppm

Electron Affinity : Unknown eV

Name: Mercury , the first planet in the solar system (Hg from former name hydrargyrum , from greek  hydr - water and  argyros silver .

I hope it helps. :).

Answer:

All of the following are true EXCEPT, the angle of refraction is 30 degrees

Explanation:

It is given that,        

The index of refraction of the water is 1.33 and the angle of incidence is 30 degrees. We know that when a ray of white light moves through the air and strikes the surface of water in a beaker, refraction occurs. Let r is the angle of refraction. It can be calculated using Snell's law as :

[tex]n=\dfrac{sin\ i}{sin\ r}[/tex]

[tex]sin\ r=\dfrac{sin\ i}{n}[/tex]

[tex]sin\ r=\dfrac{sin(30)}{1.33}[/tex]

[tex]r=22.08^{\circ}[/tex]

So, the angle of refraction is 22.08 degrees.

According to the law of reflection, the angle of incidence is equal to the angle of reflection. Since, it is incident at an angle of 30 degrees, so the angle of reflection will be 30 degrees. Also, total internal reflection will result, depending on the critical angle.

So, the wrong statement is the angle of refraction is 30 degrees. It is equal to 22.08 degrees.

Question:

Listed following are several objects in the solar system. Rank these objects from left to right based on their orbital period around the Sun from shortest to longest.

A typical asteroid in the asteroid belt, a trojan asteroid, a typical kuiper belt object, a typical oort cloud object

Answer:

Ranking of the objects from left to right based on their orbital period around the sun from shortest to longest

Explanation:

Half the mass of the belt is present in the largest four asteroids, they are ceres, vesta, pallas and hygiea. The asteroid belt total mass is 4% than that of moon, 22% Pluto. The three dwarf planets  are present in the Kuiper belt Pluto, Haumea and Makemake. The spherical layer of icy objects around the sun are Oort cloud. Objects in the Oort cloud  are made up of water ice, ammonia, and methane.  It is spherical from outer and and torous shaped from inside.

Answer:

  v₂ = 2 v₁   blood velocity in the built zone is twice the speed of the normal zone,   so the correct response is c

Explanation:

For that problem we must use the fluid continuity equation

          A₁ v₁ = A₂ v₂

Where point 1 is in the normal artery and point 2 in the contraction

         v₂ = v₁  A₁ / A₂

In the exercise indicates

          A₂ = ½ A₁

          v₂ = 2 v₁

The blood velocity in the built zone is twice the speed of the normal zone, so the correct response is c

Answer: the element is Oxygen.

Explanation: Earth's troposphere hydrosphere and lithosphere contain large amounts of Oxygen. it is the most abundant element in the Earth's crust. Oxygen makes up 467,100 ppm (parts per million) of the Earth's crust, or 46.6%.

Oxygen is the primary element found in Earth's troposphere, hydrosphere, and lithosphere, as part of the air, water (H2O), and silicate materials in many minerals and rocks.

The Earth's troposphere, hydrosphere, and lithosphere all contain large amounts of the element oxygen. The troposphere, part of the atmosphere, contains oxygen in the air we breathe, while the hydrosphere, which encompasses all water on Earth, would have oxygen as a component of H2O. In the lithosphere, which covers the crust and the upper part of the mantle, oxygen is found in many minerals and rocks as part of silicate materials.

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Answer:

a little less than 6 micrograms

Explanation:

The half-life of an element is defined as the time in which half of the isotope emits its radiation and becomes a different element. Therefore after 4.5 billion years the meteoroid will contain 12 micrograms of uranium,  after 9 billion years will contain 6 micrograms. After 10 billion years will contain a little less than 6 micrograms.

Answer: True

Explanation: A knowledge engineer is a professional who works to improve and builds with the aid of science and also implements advanced logic and AI( artificial intelligence) in computer systems in order to investigate particular issues.

A knowledge engineer also helps tries to emulate the judgements of man.

Since you are part of the team involved in discovering errors in the electronic spread sheet you are a knowledge engineer.

Answer:

Technician A

Explanation:

Often referred to as the profile or series, the aspect ratio of a tire is determined by dividing a tire’s section height by its section width when the tire is: inflated to maximum air pressure, mounted on the approved measuring rim, and under no load. This rules out Technician B.

A tire with a lower aspect ratio responds to lateral force more effectively than a tire with a higher aspect ratio. The aspect ratio affects steering stability. Generally, the shorter the sidewall, or the lower the aspect ratio, the less time it takes to transmit the steering input from the wheel to the tread. The result is quicker steering response. Aspect ratio also affects the tread contact patch. As a rule, a low-profile tire produces a wider tread contact patch. This wider tread contact patch creates a stiffer footprint that reduces distortion and provides improved cornering traction. Aspect ratio also impacts ride. A low-profile tire usually has a stiffer ride than the standard aspect ratio of 75 or more.

Final answer:

A. Technician A is correct about the aspect ratio of a tyre, while Technician B is incorrect about the impact of low aspect ratios on ride softness.

Explanation:

Technician A is correct. The aspect ratio of a tyre indeed represents the relationship between the tyre's cross-sectional height to its cross-sectional width. The aspect ratio is a critical factor in determining the tyre's performance and characteristics. Technician B is incorrect. Low aspect ratios do not provide a softer ride because they will deflect more over irregular surfaces.

In the given case, the aspect ratio primarily affects the tyre's handling, stability, and sidewall height. In conclusion, Technician A provides an accurate explanation regarding the aspect ratio of a tyre in relation to its dimensions and characteristics.

Answer:

3. at new Moon only when the Moon is on the ecliptic.

Explanation:

A solar eclipse occurs during a new Moon, exclusively when the Moon is on the ecliptic path. This is when the Moon moves between the Earth and the Sun and blocks the sunlight. A solar eclipse can't occur during a full Moon.

A solar eclipse happens during a new Moon when the Moon is on the ecliptic path. This event occurs when the Moon moves between the Earth and the Sun and blocks the Sun's light. The Moon must be on the ecliptic, which is the apparent path of the Sun's motion on the celestial sphere, for the alignment to be precise. If the Moon is not on this path, then it will not block the Sun, and a solar eclipse will not occur. It's also important to note that during a full Moon, the Moon is opposite the Sun in our sky, so a solar eclipse cannot occur.

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Answer:

The stratosphere

Explanation:

In the lower portion of the stratosphere there is a high concentration of ozone in relation to other parts of the atmosphere. This region is known as the ozone layer. This layer absorbs most of the Sun's ultraviolet radiation, especially ultraviolet B rays, allowing ultraviolet A rays to pass.

Answer:

TROPOSPHERE

Explanation:

Answer: the correct option is B ( on the half of the road that the vehicle is traveling).

Explanation: according to Georgia Code About Pedestrians; The driver must stop and remain stopped to let a pedestrian cross at a crosswalk when the pedestrian is

on the half of the road that the vehicle is traveling.

Answer:

B

Explanation:

The driver must stop and remain stopped to let a pedestrian cross at a crosswalk when the pedestrian is _____________.

A. on the half of the road with traffic going in the opposite direction

B. on the half of the road that the vehicle is traveling

C. anywhere on a two-way street

According to the law regrading pedestrian, the pedestrian has the right of way immediately she is crossing on the crosswalk and is half of the road that the vehicle is travelling.

These rules are there for the safety of the driver, pedestrians  and other road users

Answer:

C. The initial momentum should be equal to the final momentum due to the conservation of momentum.

[tex]P_{initial} = mv_0\\P_{final} = (M+m)v_1\\v_1 = \frac{m}{M+m}v_0[/tex]

Since m/(M+m) < 1, v_1 > v_0.

Explanation:

Wrong -> A. Since the smaller particle still moves after the collision, it has a kinetic energy.

Wrong -> B. The total initial momentum is equal to the momentum of the smaller particle. Therefore, the momentum of the objects that stuck together is equal to that of the smaller object.

Wrong -> D. Since the bigger object is initially at rest and the surface is frictionless, the direction of motion will be the same as the direction of the smaller particle.

Answer:

Stooping more Quickly

Explanation: Stooping more quickly means that Motor cycles can easily bend and stop,this is due to it's design, Motor cycle have only two wheels,they contain just two tyres one in front and one at the back,they are not as firm on the ground when compared to other vehicles such Motor car. They have a lower weight which makes them easily bent or stopped once there's any barrier.

Motorcycles can stop quicker than other vehicles.

When following a motorcycle, drivers must remember that motorcycles can stop quicker than other vehicles. Due to their smaller size and weight, motorcycles have a shorter stopping distance. This means that drivers should maintain a safe following distance to avoid rear-ending the motorcycle.

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Answer and Explanation:

Let the velocity of the car at a point is A is v

We have to tell about the acceleration at that point

Acceleration at that point will be perpendicular to the velocity and directed inside of the track

We can tell anything about the magnitude of the acceleration as magnitude of acceleration is the rate of change of velocity and here we have no information about time

While a car's velocity at a given point only describes its speed and direction at that moment, its acceleration at that point accounts for changes in speed and direction over time. To ascertain acceleration at a point, the velocities before and after that point need to be compared.

The velocity of a car at a given point, such as point A, tells us it's direction and speed at that instant. However, the acceleration of the car at that point is a different matter. Acceleration is defined as the change in velocity per unit time, and it doesn't only involve speed, but also direction. A car could be moving at a constant speed, but if it's changing direction, it's considered to be accelerating. Therefore, to ascertain acceleration at point A, we would need to know not just the velocity at point A, but also at points immediately before and after.

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Answer:

option B

Explanation:

given,

spring constant = k = 100 N/m

distance of unstretched length = 0.5 m

distance after stretched length =  0.65 m

magnitude of weight = ?

We know,

W  = K x

x is the displacement

x = 0.65 - 0.5 = 0.15 m

W = K x

W  = 100 x 0.15

W  = 15 N

Hence, the correct answer is option B

Final answer:

The weight of the attached object is found by multiplying the spring constant (100 N/m) by the stretch in the spring (0.15 m), which equals 15 N. Therefore, the weight of the object is 15 N.

Explanation:

The weight of the attached object can be calculated using Hooke's Law, which states that the force exerted by the spring (F) is equal to the spring constant (k) multiplied by the displacement from the rest position ( extDelta x): F = k extDelta x. In this case, the spring has a spring constant of 100 newtons per meter and the displacement from the original length of 0.50 meters to the new length of 0.65 meters is 0.15 meters.

Thus, F = 100 N/m exttimes 0.15 m, which gives us a force of 15 N. Since the weight of the object is the force exerted by the spring and these two forces are equal and opposite when the spring is at rest with the object hanging, the weight of the attached object is 15 N. Therefore, the correct answer is (b) 15N.