Water tank A has a capacity of 250 gallons and is 77% full. Water Tank B is 68% full. The ratio of the capacity of tank A to tank B is 5 : 14. What is the capacity of tank B?

Answer:

no solution

Step-by-step explanation:

8(2f-3)=4(4f-8)

16f-24=16f-32

16f=16f-8

0=-8

Answer:

No solution

Step-by-step explanation:

8(2f-3)=4(4f-8)

16f-24=16f-32

8=0f

Answer:

x=1.75

Step-by-step explanation:

Answer:

7/10 is the larger fraction

Step-by-step explanation:

use cross multiplication

which fraction has the largest number above it.

8 x 7 = 56

5 x 10 = 50

you could also use a common denominator such as 40

5/8 = x/40

25/40

7/10 = x/40

28/40

28>25 so 7/10 is larger

Answer:

The simplified expression to the given expression is [tex]\frac{4x^6}{y^2}[/tex]

Therefore [tex]\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}[/tex]

Step-by-step explanation:

Given fractional expression is [tex]\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}[/tex]

To simplify the given expression as below :

[tex]\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}[/tex]

[tex]=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}[/tex]

[tex]=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}[/tex]  ( using the property [tex](a^m)^n=a^{mn}[/tex])

[tex]=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}[/tex]

[tex]=2[(2)^4(x^{12})(y^{16})](2)^{-3}(x^{-6})(y^{-18})[/tex]  (  ( using the property [tex]a^m=\frac{1}{a^{-m}}[/tex] )

[tex]=2[2^{4-3}x^{12-6}y^{16-18}][/tex]( using the property [tex]a^m.a^n=a^{m+n}[/tex] )

[tex]=2[2^1x^6y^{-2}][/tex]

[tex]=\frac{4x^6}{y^2}[/tex] ( using the property [tex]a^m=\frac{1}{a^{-m}}[/tex] )

Therefore the simplified expression is [tex]\frac{4x^6}{y^2}[/tex]

Therefore [tex]\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}[/tex]

When any given number greater than 0 is multiplied by a fraction greater than 1 Option 1  the product is always greater than the given number.

A fraction is a part of a whole. In arithmetic, the number is expressed as a quotient, in which the numerator is divided by the denominator. In a simple fraction, both are integers. A complex fraction has a fraction in the numerator or denominator. In a proper fraction, the numerator is less than the denominator.

In Maths, there are three major types of fractions. They are proper fractions, improper fractions and mixed fractions. Fractions are those terms which have numerator and denominator.

If any given number greater than 0 is multiplied by a fraction greater than 1 then the product is always greater than the given number.

The product is always greater than the given number because the top of the fraction i.e., the numerator is already greater than the bottom of the fraction i.e., denominator which results in a greater product than the given number.

For example, let us consider that the given number is 5 and the fraction is 6/5. So, if we multiply it together then we will get 6 as a result which is greater than the given number.

Hence, the product is always greater than the given number.

To learn more about fraction  refer to:

https://brainly.com/question/1622425

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Answer:

Step-by-step explanation:

Good evening

Answer:

x = 6

y = 2

Step-by-step explanation:

Look at the photo below for the details.

:)

Answer:

A. 30

Step-by-step explanation:

The answer is 30 because x= 12 so that means that x-2 is 10 because x is 12, so since its in parenthesizes that means you do that part of the problem first. So, after we have 10 we will do times 3 since the 3 is also there and it says what is the value. So, therefore the answer is A. 30.

Answer:

Ella should add [tex]32\dfrac{5}{6}[/tex] lbs of water.

Total weight of syrup [tex]33\dfrac{1}{3}[/tex] lbs

Step-by-step explanation:

Weight:

Weight of sugar = 0.5 lbs.

Weight of water added = x lbs

Total weight = 0.5 + x lbs

Percentage:

0.5 + x  --  100%

0.5  --  1.5%

Write a proportion:

[tex]\dfrac{0.5+x}{0.5}=\dfrac{100}{1.5}[/tex]

Cross multiply:

[tex]1.5(0.5+x)=0.5\cdot 100\\ \\0.75+1.5x=50\\ \\1.5x=50-0.75\\ \\1.5x=49.25\\ \\x=\dfrac{49.25}{1.5}=\dfrac{4,925}{150}=\dfrac{197}{6}=32 \dfrac{5}{6}\ lbs[/tex]

Ella should add [tex]32\dfrac{5}{6}[/tex] lbs of water.

Total weight of syrup

[tex]32\dfrac{5}{6}+\dfrac{1}{2}=32\dfrac{5}{6}+\dfrac{3}{6}=33\dfrac{1}{3}\ lbs[/tex]

Answer:

Ella should add 32 5/6 lb of water, and she will have 33 1/3 lb of syrup.

Step-by-step explanation:

Tree casts a shadow 30 feet long. A MHS student standing near the tree casts a shadow 9 feet long. The  student is 6 feet tall. What is the height of the tree? Show all work

Answer:

Option D

The height of tree is 20 feet tall

Solution:

From given question,

Shadow of tree = 30 feet

Height of tree = ?

Height of student = 6 feet

Shadow of student = 9 feet

We have to find the height of tree

We can solve the sum by proportion

[tex]\frac{\text{height of tree}}{\text{shadow of tree}} = \frac{\text{height of student}}{\text{shadow of tree}}[/tex]

This forms a proportion and we can solve the sum by cross multiplying

[tex]\frac{\text{height of tree}}{30} = \frac{6}{9}\\\\\text{height of tree} = 30 \times \frac{6}{9} = 30 \times \frac{2}{3}\\\\\text{ height of tree } = 10 \times 2 = 20[/tex]

Thus height of tree is 20 feet tall

Answer:

1/10 the value is 100% right!

Step-by-step explanation:

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Answer:

she will be paid $480 for one week and $960 for two

Step-by-step explanation:

let P = paycheck

let d = days

let h = hours

P = d (8*h)

P = 5(8*12)

P = $480

to find two weeks multiply week one by 2

Answer:

[tex]21.43\%[/tex]

Step-by-step explanation:

we know that

To find out the percent of robots which are defective, divided the number of defective robots by the total number of robots and multiply the result by 100

Let

x ----> the number of defective robots

y ----> the total number of robots

p ---> percentage of robots which are defective

so

[tex]p=\frac{x}{y} (100)[/tex]

we have

[tex]x=30\\y=140[/tex]

substitute

[tex]p=\frac{30}{140}(100)[/tex]

[tex]p=21.43\%[/tex]

Answer:

B C and E

Step-by-step explanation:

The easiest way to know if the graph was a function is the vertical line test

If you can draw a verticle line that interests the graph two or more times it is not a function and if you can't it is a function

Answer:

-1/2 or/also known as. -0.5

Answer:

$812.5

Step-by-step explanation:

Given: Ethan need to save at least $500.

          He has saved so far $175

          Ethan hope to use two-fifths of his next paycheck to cover the remaining amount.

Lets assume Ethan´s paycheck amount be "x"

First finding the remaining amount to be covered.

Remaining amount= [tex]\$ 500 - \$ 175= \$ 325[/tex]

∴ The remaining amount to be covered is $325.

As given, Ethan hope to use two-fifths of his next paycheck to cover the remaining amount.

Now, using the inequality to find the amount of paycheck.

⇒ [tex]x\times \frac{2}{5} \geq \$ 325[/tex]

multiplying both side by 5

⇒ [tex]x\times 2\geq 325\times 5[/tex]

divinding both side 2

⇒ [tex]x\geq \frac{1625}{2}[/tex]

∴ [tex]x\geq \$ 812.5[/tex]

Hence, Ethan must make at least $812.5 in his paycheck to cover his remaining anount to buy dirt bike.

Answer:

3. times 2 divided by 36

Answer:

L=6

Step-by-step explanation:

3 x 2= 6

36 divided by 6= 6

so L= 6

Answer:

The answer to the given equation -g+2(3+g)=-4(g+1) is g=-2

Step-by-step explanation:

Given -g+2(3+g)=-4(g+1)

To solve the given equation :

-g+2(3+g)=-4(g+1)

Applying the distributive property we get

-g+2(3)+2(g)=-4(g)+(-4)(1)

-g+6+2g=-4g-4

g+6=-4g-4 ( adding the like terms )

g+6-(-4g-4)=-4g-4-(-4g-4)

Applying the distributive property we get

g+6-(-4g)-(-4)=-4g-4-(-4g)-(-4)

g+6+4g+4=-4g-4+4g+4

5g+10=0 ( adding the like terms )

5g+10-10=0-10

5g=-10 ( adding the like terms )

[tex]g=-\frac{10}{5}[/tex]

[tex]g=-2[/tex]

Therefore g=-2

The answer to the given equation -g+2(3+g)=-4(g+1) is g=-2

Answer:

216 cm^2.

Step-by-step explanation:

There are 6 faces on the prism . 3 pairs with the same area.

The surface area = 2*6*10 + 2 * 6*3 + 2*3*10

=  120 + 36 + 60

= 216 cm^2.

Answer:

Step-by-step explanation:

let

x = kg of mocha beans

y = kg of java beans

so

(1)   x + y = 50

(2)   20x + 15y = 18(50)

solve by substitution (or whatever method you prefer):

(x, y) = (30, 20)

Width = w cm

Length = 2w-7

The domain of the given relation (-2,4), (1,3), (0,-4), (3,2) is the set of the first elements from each ordered pair, which results in the set {-2, 1, 0, 3}.

The question asks about the domain of a relation consisting of ordered pairs. A relation is a set of ordered pairs, and the domain of a relation is the set of all the first elements from each pair. In the given relation (-2,4), (1,3), (0,-4), (3,2), the domain comprises the first elements of each pair, which are -2, 1, 0, and 3. Therefore, the domain of this relation is the set {-2, 1, 0, 3}.

Answer:

3(-6 + 2) = -12

Step-by-step explanation:

If a negative is multiplied by another negative we will have a positive, t is -3 and when a negative is in the way the equation is now 3(r - s).

S is - 2 with the negative in the way its now 3(r + 2) ad last r = -6 with no negative in the way the equation is now 3(-6 + 2) which equals 12.

Hope it helps.

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The solution of the expression of 13 and three-fourths + x = 7 and one-fourth equation is x = [tex]6\frac{1}{2}[/tex]

To solve this equation, we need to find the value of x (unknown variable) in the given equation:

13 and three-fourths + x = 7 and one-fourth

First, we need to convert the mixed numbers to improper fractions.

13 and three-fourths = [tex]13 + \frac{3}{4} = 13\frac{3}{4}[/tex]

7 and one-fourth = [tex]7 + \frac{1}{4} = 7 \frac{1}{4}[/tex]

Now, the equation becomes:

[tex]13\frac{3}{4} + x =7\frac{1}{4}\\ x = 13\frac{3}{4} - 7\frac{1}{4}\\\\x = 6\frac{1}{2}[/tex]

Answer:

A parallelogram has opposite sides parallel and equal in length.

Step-by-step explanation:

Hope this helps. :)

Answer:

d.

Step-by-step explanation:

To convert a root to a fraction in the exponent, remember this rule:

[tex]\sqrt[n]{a^{m}}=a^{\frac{m}{n}}[/tex]

The index becomes the denominator in the fraction. (The index is the little number in front of the root, "n".) The original exponent remains in the numerator.

In this question, the index is 4.

The index is applied to every base in the equation under the root. The bases are 16, 'x' and 'y'.

[tex]\sqrt[4]{16x^{15}y^{17}} = (\sqrt[4]{16})(\sqrt[4]{x^{15}})(\sqrt[4]{y^{17}}) = (2)(x^{\frac{15}{4}}})(y^{\frac{17}{4}}) = 2x^{\frac{15}{4}}}y^{\frac{17}{4}}[/tex]

To find the quad root of 16, input this into your calculator. Since 2⁴ = 16, [tex]\sqrt[4]{16}[/tex] = 2.

For the "x" and "y" bases, use the rule for converting roots to exponent fractions. The index, 4, becomes the denominator in each fraction.

[tex]2x^{\frac{15}{4}}y^{\frac{17}{4}}[/tex]