what is (13x+9k)+(17x+6k) simplified

Answers

Answer 1
Final answer:

The expression (13x+9k)+(17x+6k) simplifies to 30x + 15k. This is done by adding the coefficients of the like terms which in this case are 13x with 17x, and 9k with 6k.

Explanation:

The expression (13x+9k)+(17x+6k) is a mathematical expression in algebra with two variables, x and k. The goal here is to simplify the expression by combining like terms. In mathematics, 'like terms' refer to the terms that have the same variables and powers. The coefficients of the like terms can be different.

Now to simplify this expression, we add the coefficients of the like terms. The like terms here are 13x and 17x, and also 9k and 6k.

Add 13x and 17x, you get 30x. And when you add 9k and 6k, you get 15k.

So, the simplified version of the given expression (13x+9k)+(17x+6k) is 30x + 15k.

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Related Questions

If the resistance of one component of a series circuit is 3+j5  ohms, and the resistance of the second component of the circuit is 5−j8  ohms, and the resistance of the third component of the circuit is 6+j4  ohms, what is the total resistance in the circuit?

Answers

Final answer:

The total resistance in a series circuit is found by summing the resistances of individual components. For the given resistors of 3+j5 ohms, 5-j8 ohms, and 6+j4 ohms, the total resistance is 14+j1 ohms.

Explanation:

In a series circuit, the total resistance (Rtotal) is the sum of the individual resistances. We have three resistors with complex resistance values: R1 = 3 + j5 ohms, R2 = 5 - j8 ohms, and R3 = 6 + j4 ohms. Adding these together will give us:

Rtotal = R1 + R2 + R3

Calculate the real parts of each resistor and the imaginary parts separately:

Real part = 3 + 5 + 6 = 14 ohms,
Imaginary part = j5 - j8 + j4 = j1 ohm.

Thus, the total resistance in the circuit is Rtotal = 14 + j1 ohms.

At the movie theatre, child admission is $6.20 and adult admission is $9.80 . On Monday, twice as many adult tickets as child tickets were sold, for a total sales of $593.40 . How many child tickets were sold that day?

Answers

x= child

2x = adult


6.20x +9.80(2x) =593.40

6.20x +19.6x=593.40

25.80x =593.40

x=593.40/25.80 = 23

 23 childrens tickets were sold


Find H to the nearest degree.

Answers

sin(angle) = opposite/hypotenuse
sin(H) = GF/HF
sin(H) = 5/13
arcsin(sin(H)) = arcsin(5/13)
H = 22.61986 ... which is approximate
H = 23 degrees ... round to the nearest whole number

Answer is choice A

Find s10 for a geometric series with first term 10 and a common ratio 4

Answers

[tex]\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\ S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ n=10\\ r=4\\ a_1=10 \end{cases} \\\\\\ S_{10}=10\left( \cfrac{1-4^{10}}{1-4} \right)[/tex]
the sum of a geometric sequence where the first term is a1 and the common ratio is r and n is which term is
[tex]S_{n}=\frac{a_1(1-r^n)}{1-r}[/tex]

so
given first term of 10 and common ratio 4 and n=10

[tex]S_{10}=\frac{10(1-4^{10})}{1-4}[/tex]
[tex]S_{10}=\frac{10(1-1048576)}{-3}[/tex]
[tex]S_{10}=\frac{10(-1048575)}{-3}[/tex]
[tex]S_{10}=\frac{-10485750}{-3}[/tex]
[tex]S_{10}=3495250[/tex]

The number of hours walked varies inversely with the speed of the walker. if it takes sam 12 hours to complete his walking goal at 5 miles per hour, how long would it take him at 3 miles per hour?

Answers

We let k be the proportionality constant for the relationship between number of hours, h and speed of the walker, s. 

                        h = k/s
Substituting the known values,
                        12 = k/5
                          k = 60

For the second scenario,
                          h = k/s
Substituting the calculated value for k and the given value for speed,
                          h = (60)(3 miles/hour)
                         h = 20 hours
                         h = 20 hours

Therefore, it will take 20 hours to walk with a speed of 3 miles per hour. 

f f(x)=2(x)^2+5 sqrt (+2) complete the following statement: The domain for f(x) is all real numbers greater than or equal to _____.

Answers

f(x) = 2x^2 + 5sqrt(2)

Then since the minimum of x^2 is 0, so f(x) must be greater or equal to 5sqrt(2)

The domain for the function f(x) = 2x² + 5√(x + 2) is all real numbers greater than or equal to -2.

In interval notation, we can express this as:

Domain: x ∈ [-2, ∞)

Given is a function f(x) = 2x² + 5√2, we need to determine the domain of the function,

To complete the statement, we need to determine the domain for the function f(x) = 2x² + 5√(x + 2).

The domain of a function represents all the possible values of x for which the function is defined.

In this case, we need to consider two factors that can restrict the domain:

For a real number to be a valid input for the square root (√), the expression inside the square root (x + 2) must be greater than or equal to 0.

Otherwise, we would encounter the issue of taking the square root of a negative number, which is not defined in the real number system.

There are no other restrictions in the function that would cause it to be undefined for certain values of x.

Since x² is defined for all real numbers, there are no issues there.

Let's solve the inequality for the square root expression:

x + 2 ≥ 0

Subtract 2 from both sides:

x ≥ -2

So, the domain for the function f(x) = 2x² + 5√(x + 2) is all real numbers greater than or equal to -2.

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which of the following correctly describes the end behavior of the polynomial function, f(x)=3x^4+2x^2-x

Answers

Answer:

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow -\infty[/tex]

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow +\infty[/tex]

Step-by-step explanation:

Given polynomial function is,

[tex]f(x)=3x^4+2x^2-x[/tex]

Since, the end behavior of a polynomial is same as the end behavior of leading term,

Here, the leading term = [tex]3x^4[/tex]

[tex]\text{As }x\rightarrow -\infty[/tex]

The leading term is positive,

[tex]\text{While, as }x\rightarrow +\infty[/tex]

The leading term is positive,

Hence, the end behavior of the given polynomial is,

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow -\infty[/tex]

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow +\infty[/tex]

⇒ In the graph of f(x), both ends will go upward.

Answer:both ends go down !

Step-by-step explanation:

A bakery sold apple pies for $11 and blueberry pies for $13. One Saturday they sold a total of 38 pies and collected a total of $460. How many apple pies did they sell and how many blueberry pies did they sell?

Answers

A= apple pie

B = blueberry pie

a+b=38

a=38-b

11a + 13b =460

11(38-b) + 13b = 460

418-11b +13b = 460

2b=42

b=42/2 =21

they sold 21 blueberry pies and 17 apple pies

17 Apple pies and 21 blueberry pies

If the factors of a polynomial are x-2 and x-5, what values of x make that polynomial 0?

A. 1 and 2
B. -2 and -5
C. 2 and 5
D. Cannot be determined

Answers

C since you just make the factors equal to 0. x-5=0 and x-2=0 and then you just solve for x

!!! HELP What values for (picture of equation) satisfy the equation?

Answers

The values of 0 ≤ θ ≤ 2π are π/6, π/4, π/3, π/2, 2π/3, 3π/4, 5π/6, π, 7π/6, 5π/4, 4π/3, 5π/3, 7π/4 and 11π/6. It can be inputted into trigonometric functions. Tangent is sine over cosine. Since sine and cosine are periodic, then tangent has to be, as well.–π to –π/2: The tangent will be zero wherever its numerator (the sine) is zero. This happens at 0, π, 2π, 3π, etc, and at –π, –2π, –3π, etc. The tangent will be undefined wherever its denominator (the cosine) is zero. A zero in the denominator means you'll have a vertical asymptote. So the tangent will have vertical asymptotes wherever the cosine is zero

(a) a pizza parlor has a choice of 11 toppings for its pizzas. from these 11 toppings, how many different 7 -topping pizzas are possible?

Answers

To solve for the number of different possible pizzas with 7 toppings out of 11 and the arrangement of these toppings is not important, therefore we use the combination formula.

The formula for combination is:

n C r = n! / r! (n – r)!

where,

n = is the total number of toppings = 11

r = the number of toppings in a pizza = 7

Substituting the values into the equation:

11 C 7 = 11! / 7! (11 – 7)!

11 C 7 = 11! / 7! * 4!

11 C 7 = 330

 

Therefore there are a total different 330 pizzas with 7 different combinations toppings.

Final answer:

330 different combinations.

Explanation:

The student's question is about combinations in Mathematics, specifically how many 7-topping pizzas can be made from a choice of 11 toppings. This is a combinatorics problem, and the solution involves the use of the combination formula, which is given as:

C(n, k) = n! / (k!(n-k)!)

where n is the total number of items to choose from, k is the number of items to choose, n! denotes the factorial of n, and C(n, k) represents the number of combinations.

In this case, n is 11 (the total number of toppings) and k is 7 (the number of toppings on the pizza).

Therefore, the number of different 7-topping pizzas possible is:

C(11, 7) = 11! / (7!(11-7)!) = 11! / (7!4!) = (11x10x9x8)/(4x3x2x1) = 330

Hence, 330 different 7-topping pizzas are possible.

Solve x 2 + 9x + 8 = 0 by completing the square. What are the solutions?

Answers

x^2+9x+8=0

 (x+1)(x+8)=0

x+1=0

x=-1

x+8 = 0

x=-8


 solutions are -1 and -8

Which features describe the graph of y^2/96^2 - x^2/40^2 =1? Check all that apply.

a focus at (104, 0)
a focus at (0,−96)
a vertex at (−40, 0)
a vertex at (0, 96)
the center at (0, 0)

Answers

The given equation is 
[tex] \frac{y^{2}}{96^{2}} - \frac{x^{2}}{40^{2}} =1[/tex]

From the given equation,
a = 40
b = 96
(h,k) = (0,0), the center

The vertices are at (0,96) and at (0, -96).
The curves open upward and downward.

c² = a² + b² = 40² + 96² = 10816
c = 104
Therefore the foci are at (0, -104) and (0, 104).

Check the given answers:
1. a focus at (104, 0) is INCORRECT
2. a focus at (0, -96) is INCORRECT
3. a vertex at (-40, 0) is INCORRECT
4. a vertex at (0, 96) is CORRECT
5. the center at (0, 0) is CORRECT

Two angles are supplementary and one of the angles is 8 times the other. find the measure of the larger angle.

Answers

supplementary angles add up to 180 degrees

 angle 1 = x

 angle 2 = 8x

 x +8x = 180

9x = 180

x = 180/9 = 20 degrees

larger angle = 8*20 = 160 degrees


Final answer:

To find the measure of the larger angle, set up an equation. Solve the equation to find the value of the smaller angle. Multiply the smaller angle by 8 to find the measure of the larger angle.

Explanation:

To find the measure of the larger angle, we need to set up an equation based on the given information. Let's say the smaller angle is x degrees. The larger angle is then 8 times the smaller angle, which means it is 8x degrees. We know that two angles are supplementary, meaning they add up to 180 degrees. So we can set up the equation x + 8x = 180. Simplifying this equation gives us 9x = 180. Dividing both sides by 9, we find that x = 20 degrees. Therefore, the larger angle is 8x = 8 * 20 = 160 degrees.

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Given the ordered pairs (-1,1), (0,3), (1,5), (2,7), what is the equation of the line

Answers

slope  is  7-5 / 2-1 = 2/1  = 2  
and y intercept is y = 3  ( because of the point (0.,3) being on the line 

the  equation   in slope intercept form is
y = mx + c   where m =2 and c = 3
answer is:-

y = 2x + 3

The equation of the line with the given ordered pairs is y = 4x + 3.

What is an equation of a line?

The equation of a line is given by:

y = mx + c

where m is the slope of the line and c is the y-intercept.

Example:

The slope of the line y = 2x + 3 is 2.

The slope of a line that passes through (1, 2) and (2, 3) is 1.

We have,

The ordered pairs:

(-1,1), (0,3), (1,5), and (2,7)

The equation of the line is y = mx + c.

Pick any two ordered pairs.

(-1, -1) and (0, 3)

m = (3 - (-1)) / (0 - (-1)) = (3 + 1)/1 = 4/1 = 4

Now,

(0, 3) = (x, y)

3 = 4 x 0 + c

c = 3

Thus,

The equation of the line is y = 4x + 3

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identify the maximum and minimum values of the function y = 3 cos x in the interval [-2π, 2π]. Use your understanding of transformations, not your graphing calculator.

Answers

The "vanilla" y=cos(x) function oscillates between -1 and +1. In the given function, only a multiplication with 3 is applied. The min and max scale accordingly, so the maximum becomes +3 and the minimum -3.

The x interval of [-2π, 2π] ensures that all y values are enclosed; the cosine makes two full sweeps.

The maximum value of the function y = 3 cos x will be 3.

The minimum value of the function y = 3 cos x will be - 3.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The function is,

⇒ y = 3 cos x

In the interval [-2π, 2π].

Now,

Since, The function is,

⇒ y = 3 cos x

Hence, We get;

The maximum value of the function y = 3 cos x is,

⇒ y = 3 cos2π

⇒ y = 3 × 1

⇒ y = 3

And, The minimum value of the function y = 3 cos x is,

⇒ y = 3 cos(-2π)

⇒ y = 3 × - 1

⇒ y = - 3

Thus, The maximum value of the function = 3.

The minimum value of the function = - 3.

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A gardener wants to enclose a circular garden with a square fence. If the circumference of the circular garden is about 99 feet, about how many feet of fencing would be needed? Use 3.14 to approximate for\pi π . Round your answer to the nearest tenth.

Answers

The square will be equal to the diameter of the circle.  The circumference of a circle is π times the diameter, and the perimeter of the square is four times times that diameter...

C=πd

d=C/π

p=4d so

p=4C/π feet, since C≈99 ft and π≈3.14

p≈4(99)/(3.14)

p≈126.1 ft  (to nearest tenth of a foot)

Which of the following is an arithmetic sequence?
a -7/11,6/11, -5/11, 4/11
b -3/4, -3/5, -3/6, -3/7
c 1/2,2,7/2,5
d 3/4,-3/2, 3, -6

Answers

I think it's D, because 3/4 x 2 = - 3/2
and then - 3/2 x - 2 = 3
3 x - 2 = - 6

Hope that helps <3

The sequence 3/4,-3/2, 3, -6 is the arithmetic sequence.

Common difference

The difference between two successive terms of an arithmetic progression is known as a common difference.

How to check the common difference?

(a)

We will find the common difference between each term of the given sequences by subtracting a term and its previous term.

[tex](\frac{6}{11}- \frac{-7}{11}) \neq (\frac{-5}{11} -\frac{6}{11} )\neq (\frac{4}{11} -\frac{-5}{11})[/tex]

[tex]\frac{13}{11}\neq \frac{-11}{11}\neq \frac{9}{11}[/tex]

So, option (a) is incorrect.

(b)

We will take the common difference between the terms.

[tex](\frac{-3}{5} -\frac{-3}{4} )\neq (\frac{-3}{6} -\frac{-3}{5} )\neq (\frac{-3}{7} -\frac{-3}{6} )\\[/tex]

[tex]\frac{3}{20} \neq \frac{3}{30}\neq \frac{3}{42}[/tex]

So, option (b) is also incorrect.

(c)

We will take the common difference between the terms.

[tex](2-\frac{1}{2} )= ( \frac{7}{2}-2 )= (5 - \frac{7}{2} )[/tex]

[tex]\frac{3}{2}= \frac{3}{2} = \frac{3}{2}[/tex]

Since the difference between the terms is common.

Thus, option (c) is correct.

(d)

We will take the common difference between the terms.

[tex](\frac{-3}{2}- \frac{3}{4})\neq (3-\frac{3}{2})\neq (-6-3)[/tex]

[tex]\frac{-18}{2}\neq \frac{9}{2}\neq (-9)[/tex]

So, option (d) is incorrect.

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find an ordered pair that is a solution to the equation x-4y=4

Answers

Ordered pairs that are solutions to the equation x-4y=4 is (4, 0) and (0, -1).

The given equation is x-4y=4.

We need to find an ordered pair that is a solution to the equation.

How to find the solution to an equation?

The solutions of linear equations are the points at which the lines or planes representing the linear equations intersect or meet each other. A solution set of a system of linear equations is the set of values to the variables of all possible solutions.

From the graph, we can observe that (4, 0) and (0, -1) are solutions.

Verification of the solution (4, 0):

4-4y=4

⇒-4y=0

⇒y=0

Verification of the solution (0, -1):

0-4y=4

⇒-4y=4

⇒y=-1

Therefore, ordered pairs that are solutions to the equation x-4y=4 is (4, 0) and (0, -1).

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Find the value tan 39 degrees. Round to the nearest ten-thousandth

A ) 0.8098
B ) 0.6293
C ) 0.7771
D ) 3.6146

Answers

You can do this using a scientific calculator

mine gives tan 39  =  0.8097840332

which is 0.8098 to nearest ten thousandth.

What set of transformations is performed on LMNO to form L'M'N'O

Answers

In order to answer this question I need to see a diagram. Do you have one?

Is it for 8th grade pre-algebra?

determine whether a relation shown represents a function and justify your answer. domain 6, 10, 12 and range 7, 32

Answers

Yes because multiple domain values can have the same range value, but not vice versa.

In spherical geometry, which indicates the possible number of right angles a triangle may have?
1
2
3
All of the above

Answers

In planar geometry, we know that the sum of all angles of a triangle is exactly 180°, However, in spherical geometry, different rules apply. When three arcs drawn on the surface of the sphere are connected together through vertices, that is called a spherical triangle. In that case, the sum of all three angles of a spherical triangle is between 180° and 540°.

So, if a triangle has one 90° angle, there are still excess angles to make up for a maximum of 540°. The same is true for two 90° angles. You would exceed 180° but that is just the lower limit so that is still acceptable. If you have three 90° angles, you form a spherical triangle with a total of 270°, which is within the given range. Thus, the answer is all of the above.

find the x intercepts of the parabola with vertex (2,13) and y-intercept (0,5) write your answer in this form: (x1,y1),(x2,y2) if necessary, round to the nearest hundredth

Answers

The standard formula for a parabola are

(x-h)^2 = +/- 4a (y-k) or (y-k)^2 = +/- 4a(x-h)

where
(h,k) is the coordinates of the vertex
a is the length of the focus from the vertes
+4a if the parabola opens upwards or to the right
-4a if the parabola opens downwards or to the left

The vertex (2,13) is situated in the 1st quadrant of the Cartesian plane. It only has y-intercept. This means that it only passes the y-axis once. Therefore, the parabola must open downwards and it passes the x-axis twice. The intersections at the x-axis are the x-intercepts. If the parabola has 2 x-intercepts, then the equation would be (x-h)^2 = -4a(y-k).

Let's use the y-intercept (0,5) to determine 4a:

(0-2)^2=-4a(5-13)
4a = 0.5

Therefore, the equation of the parabola is (x-2)^2 = -1/2(y-13). To find the x-intercepts, let y=0.

(x-2)^2 = -1/2(0-13) = 6.5
x-2 = +/- √6.5 = +/- 2.55
x = 4.55 and and -0.55

The x-intercepts are (-0.55,0) and (4.55,0).

Answer:

(-0.55,0),(4.55,0)

The function g(x) is defined as g(x) = 6x2 + 23x – 4. When does g(x) = 0?

A.) x = –6 or x = 1/4

B.) x = –4 or x = 1/6

C.) x = -1/4 or x = 6

D.) x = -1/6 or x = 4

*The answer is B, but if there's anyone looking to earn Brainliest, please answer with a full explanation.*

Answers

Solving for x
6x^2 + 23x - 4 = 0
Factoring
(6x - 1)(x + 4) = 0
6x - 1 = 0 or x+ 4 = 0

X = 1/6 or x = -4

Answer:

B.) x = –4 or x = 1/6 .

Step-by-step explanation:

Given  : g(x) = 6x² + 23x – 4.  

To find : Solve.

Solution : We have given that

g(x) = 6x² + 23x – 4.  

If g(x) = 0

6x² + 23x – 4 = 0 .

On factoring

6x² + 24x - 1x – 4 = 0

Taking common 6x from first two terms and -1 from last two terms.

6x ( x + 4 ) -1 (x + 4) = 0.

On grouping

(6x -1) ( x +4) = 0

For 6x -1 = 0

6x = 1

on dividing by 6

x = 1/6.

For x +4 = 0

On subtracting 4 from both sides

x = -4.

Therefore, B.) x = –4 or x = 1/6 .

Is the relation {(3, 5), (–4, 5), (–5, 0), (1, 1), (4, 0)} a function? Explain. Type your answer below

Answers

Yes this is a function. The reason why is because there are no repeated x values. Each x value leads to exactly one y value. Put another way, for any given input, there is EXACTLY ONE output.

If you had something like {(1,2),(4,5),(1,7)} then it wouldn't be a function since x = 1 repeats itself. In this example, x = 1 leads to more than one output.

 {(3, 5), (–4, 5), (–5, 0), (1, 1), (4, 0)}

As long as there are the same x-value does not have multiple y-value results, it will be a function. This data array doesn't contain any recurring x-values. Therefore, this is a function (in simple terms of speaking).

100 POINTS!!!! Create a table of values for a linear function. A drone is in the distance, flying upward in a straight line. It intersects the rainbow at two points. Choose the points where your drone intersects the parabola and create a table for at least four values for the function. Remember to include the two points of intersection in your table. Can you just give me the X and Y values? 

Answers

Based on the docx you showed me, the equation for the parabola is [tex]y = x^2 + 36[/tex] and you want a table of values for a linear equation that intersects the parabola at (5, 6) and (-2, 34).

If you use these two points to create a line we get the equation:

[tex]y - 6 = \frac{34 - 6}{-2 - 5}(x - 5)[/tex] (I just used point slope form)

This can be simplified to:

[tex]y = \frac{40}{-7}x + \frac{242}{7}[/tex]

Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept: [tex](0, \frac{242}{7})[/tex] and the x-intercept: [tex](\frac{121}{20}, 0)[/tex].

So our table of value can be:

x          | y
______|________
-2         | 34
0          | 242 / 7
5          | 6
121/20 | 0

Five members of the soccer team and five members of the track team ran the 100-meter dash. Their times are listed in the table below: Soccer Track 12.3 12.3 13.2 11.2 12.5 11.7 11.3 12.2 14.4 13.7 What is the difference of the means for the two groups? 0.52 12.22 12.74 24.96

Answers

soccer : (12.3 + 13.2 + 12.5 + 11.3 + 14.4) / 5 = 63.7 / 5 = 12.74
track : (12.3 + 11.2 + 11.7 + 12.2 + 13.7) / 5 = 61.1 / 5 = 12.22

difference is : 12.74 - 12.22 = 0.52 <=

Answer:

Hence, the difference in Mean of two teams is:

0.52

Step-by-step explanation:

Five members of the soccer team and five members of the track team ran the 100-meter dash.

Their time is listed as:

Soccer          Track

   12.3              12.3

   13.2               11.2

   12.5               11.7

   11.3                12.2

    14.4               13.7

The mean of the soccer team is given by:

[tex]Mean_1=\dfrac{12.3+13.2+12.5+11.3+14.4}{5}\\\\Mean_1=12.74[/tex]

The mean of track team is given by:

[tex]Mean_2=\dfrac{12.3+11.2+11.7+12.2+13.7}{5}\\\\Mean_2=\dfrac{61.1}{5}\\\\Mean_2=12.22[/tex]

Hence, the Difference in Mean is:

[tex]Mean_1-Mean_2\\\\=12.74-12.22\\\\=0.52[/tex]

Hence, the difference in Mean of two teams is:

0.52

Find x and RS if S is between R and T 
RS=6x,ST=12,and RT=72

Answers

ah, ok

RST

so RS+ST=RT
6x+12=72
minus 12 both sides
6x=60
divide both sides by 6
x=10


x=10

The value of x is 10 and RS is 60 units.

It is required to find the value of x  and RS.

What is length ?

Length is defined as the measurement or extent of something from end to end. It is the larger of the two or the highest of three dimensions of geometrical shapes or objects.

Given:

S is between R and T

RS=6x,  ST=12,    RT=72

We know that ,

RS + ST = RT

6x + 12 = 72

Substract 12 on both sides we have,

6x + 12 - 12= 72 - 12

6x = 60

x = 10 units.

Put the value of x in RS we have,

RS = 6x

RS = 6(10)

RS = 60 units.

Therefore, the value of x is 10 and RS is 60 units.

Learn more about length here:

brainly.com/question/4709424

#SPJ2

59:26 What is the length of the hypotenuse, x, if (20, 21, x) is a Pythagorean triple? 22 29 41 42

Answers

if the legs are length a and b and hyptonuse is c then
a²+b²=c²

so
if the legs are 20 and 21 and the hypotnuse is x then
20²+21²=x²
400+441=x²
841=x²
29=x

Answer:  the correct option is (B) 29.

Step-by-step explanation:  We are given to find the length of the hypotenuse x, if (20, 21, x) is a Pythagorean triple.

We know that

in a right-angled triangle, the lengths of the sides (hypotenuse, perpendicular, base) is a Pythagorean triple, where

[tex]Hypotenuse^2=Perpendicular^2+base^2.[/tex]

So,  for the given Pythagorean triple, we have

[tex]x^2=20^2+21^2\\\\\Rightarrow x^2=400+441\\\\\Rightarrow x^2=841\\\\\Rightarrow x=\sqrt{841}~~~~~~~~~~~~~~~~~[\textup{taking square root on both sides}]\\\\\Rightarrow x=\pm29.[/tex]

Since the length of the hypotenuse cannot be negative, so x = 29.

Thus, the length of the hypotenuse, x = 29.

Option (B) is CORRECT.

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