60 is 300% of what number
find the value of y when x equals 0 . -7x+3y=30
What is the length of one side of a square if its area is 100 square centimeters?
a. 100 cm
b. 40 cm
c. 25 cm
d. 10 cm user: the cost of one textbook is $14.90. which expression below can be used to compute the cost of 8 textbooks?
a. 8($15.00 $0.90)
b. 8($15.00 $0.10)
c. 8($15.00 – $0.90)
d. 8($15.00 – $0.10)
Answer:
The anser is D. I just had this question
Polygon ABCD, shown in the figure, is dilated by a scale factor of 8 with the origin as the center of dilation, resulting in the image A′B′C′D′.The slope of C'D' is
The slope doesn't change after dilation, it would still be 2.
You have $80 and your brother has $275 dollars. You save $10 of your allowance each week. Your brother spends his allowance plus $15 each week.
1. Write an equation to model this.
2. How long before you have as much money as your brother?
3. How much have you saved when you catch up to him?
The pilot of an airplane traveling 190 km/h wants to drop supplies to flood victims isolated on a patch of land 100 m below.
How many seconds before the plane is directly overhead should the supplies be dropped? ...?
What is the y-intercept of y=1.5x?
write y=2x+3 using function notation
Answer:
[tex]f(x) = 2x+3[/tex]
Step-by-step explanation:
The function f(x) is the another way of representing the y-values in the function
i.e
[tex]y=f(x)[/tex]
Then y-axis be labeled with f(x)
Also; the ordered pair is written as: (x, f(x)) instead of (x, y)
Given the equation:
[tex]y = 2x+3[/tex]
replace y = f(x)
then;
[tex]f(x) = 2x+3[/tex]
therefore, the equation y=2x+3 using function notation is, [tex]f(x) = 2x+3[/tex]
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Which is a correct comparison of the fractions?
15/18 and 25/30
A.15/18 < 25/30
B.15/18 > 25/30
C.15/18 = 25/30
Therefore, the correct option is C. 15/18 = 25/30. The fractions 15/18 and 25/30 were simplified to 5/6, proving they are equal.
Comparison of Fractions 15/18 and 25/30
To compare the fractions 15/18 and 25/30, we can first simplify them to make the comparison easier. We simplify each fraction by dividing the numerator and denominator by their greatest common divisor (GCD).
1. Simplify 15/18:
GCD of 15 and 18 is 3.
→ 15 ÷ 3 = 5
→ 18 ÷ 3 = 6
So, 15/18 = 5/6.
2. Simplify 25/30:
GCD of 25 and 30 is 5.
→ 25 ÷ 5 = 5
→ 30 ÷ 5 = 6
So, 25/30 = 5/6.
Therefore, 15/18 = 25/30. The correct comparison is:
C. 15/18 = 25/30
which method could be used to prove triangle PVU is congruent to triangle QVS?
1. Choose the correct solution in roster form.
S is the set of prime numbers that are less than 15.
A.{2,3,5,7,11,13}
B.{2,3,5,7,9,11,13}
C.{1,3,5,7,9,11,13}
D.{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}
Answer:
A. {2,3,5,7,11,13}
Step-by-step explanation:
Since, prime numbers are the whole numbers which have only two multiple which are 1 and itself.
Thus, the prime numbers are,
2, 3, 5, 7, 11, 13, 17, 19, 23, ..................
Note : 1 is not a prime number because it has only one multiple i.e. 1.
or it does not satisfy the definition of prime number.
Thus, the prime numbers that are less than 15,
2, 3, 5, 7, 11, 13
Which are the elements of the set S,
Hence, S = { 2, 3, 5, 7, 11, 13 }
OPTION A is correct.
What is the solution of the system?
Use the substitution method.
{y+7=3x
{6x−2y=12
A) (14, 12)
B) (12, 14)
C)There is no solution.
D)There are an infinite number of solutions.
S=(1 r)
c. find c if s = r 174 and r= 45%
25 m equals how many feet
help please.
What is the common difference d of the sequence?
−15, −4, 7, 18, 29, ...
d = ?
Expand 3(-5q + 4).
A.5q + 12
B.-15q + 4
C.-15q + 12
D. 5q + 12
Similar triangles. Solve for x
Liana started to evaluate the function f(x) = 2x^2 – 3x + 7 for the input value 2.
f(x) = 2(2)2 – 3(2) + 7
= 2(4) – 3(2) + 7
What is the value of the function when x = 2?
a) 9
b) 10
c) 16
d) 17
Answer:
9 is the right answer on edge
Step-by-step explanation:
for each of the values of h given, when x is increased from 1 to 1+h, work out:
Differential equation: In solving equations involving x, y, and z, taking steps with various values of h optimizes the process.
Step size h: When h=0.5 over the interval 0 to 2, solutions can be calculated by incrementing x from 1 to 1+h.
Optimizing procedures: By choosing appropriate values for h, the iterative process can be streamlined for better efficiency.
True or False? A secant is a line or segment that passes through a point on the circle and the center of the circle.
A. True
B. False
Answer:
B.False.
Step-by-step explanation:
A secant is a line or segment which passes through two points or more points and cut the curve at atleast two points.
We are talking about of secant of circle
Secant: A secant is a line that passe through two points of circle and it intersect the circle at two points.
Therefore,given definition of secant is
A secant is a line or segment that passes through a point on the circle and the cente rof the circle.
By definition of secant , we can say the given define in question is false.
Because that segment which passes through a point on circle and center of the circle is radius not secant.
Select the GCF of these numbers. 2^5 · 5· 11 and 2^3· 5^2 · 7
The greatest common factor (GCF) of the expressions 2^5 · 5· 11 and 2^3· 5^2 · 7 is 2^3 · 5, or 40. This is determined by comparing the exponents of the common base terms in both expressions and selecting the lowest exponents.
Explanation:The student's question is about finding the greatest common factor (GCF) of two different mathematical expressions, namely: 2^5 · 5· 11 and 2^3· 5^2 · 7. In this context, 'GCF' refers to the greatest number that is a factor of two or more numbers. For these expressions, we will look at the shared factors of the two expressions.
Steps to find the GCF:
Compare the exponents of the common base terms in the two expressions. Here, the common base terms are '2' and '5'. In the first expression, '2' is raised to the power of '5' and '5' is raised to the power of '1'. In the second expression, '2' is raised to the power of '3' and '5' is raised to the power of '2'. For each base, select the lowest exponent. Therefore, for base '2', we select '3' as the exponent and for base '5', we select '1'. Therefore, the GCF of the two expressions is 2^3 · 5 or 40. Learn more about Greatest Common Factor here:
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One number is six times another number. their difference is 35. what are the two numbers? 5 and 30 8 and 48 7 and 42 6 and 41
Answer: The answer is (c) 7 and 42.
Step-by-step explanation: We are given that one number is six times another number and their difference is 35. We are to find the two numbers.
Let 'x' and 'y' be the two numbers. Then, we have
[tex]y=6x,\\\\y-x=35.[/tex]
Substituting the value of 'y' from first equation in the second, we have
[tex]6x-x=35\\\\\Rightarrow 5x=35\\\\\Rightarrow x=7,[/tex]
and
[tex]y=6\times 7=42.[/tex]
Therefore, the numbers are 7 and 42.
Thus, the answer is (c) 7 and 42.
A meteorological office keeps records of the annual precipitation in different cities. For one city, the mean annual precipitation is 15.3 and the standard deviation of the annual precipitation amounts is 4.2. Let x represent the annual precipitation in that city. Determine the standardized version of x.
To find the standardized version of x in a given city's annual precipitation data, use Z = (x - mean) / standard deviation.
Explanation:The standardized version of x (annual precipitation in a city) can be calculated using the formula: Z = (x - mean) / standard deviation. Substituting the given values, Z = (x - 15.3) / 4.2. This helps in determining how many standard deviations a particular precipitation amount is from the mean.
A high school athletic department bought 40 soccer uniforms at a cost of$3,000. after soccer season, they returned some of the uniforms but only received $40 per uniform. what was the difference between what they paid for each uniform and what they returned
Write one way to break apart the array. Then fine the product. 7x8
Break apart the factor 8 into 5 and 3, and then use the distributive property to calculate 7x5 and 7x3. Add the two products together to find that the product of 7 and 8 is 56.
Explanation:To find the product of 7 and 8, you can break apart the array into more manageable pieces. One way to do this is by using the distributive property, which in this case lets you split one of the factors and multiply each part separately before adding the results. For example, you can break the number 8 into 5 and 3 because 5 + 3 equals 8. Then you multiply 7 by each part:
7 × 5 = 357 × 3 = 21
After calculating these two products, you add them together to find the final product:
35 + 21 = 56
Therefore, the product of 7 and 8 is 56. This approach can make multiplication easier, especially when dealing with larger numbers or when trying to calculate in your head.
The construction method used to construct a perpendicular through a point not on a line could also be used to construct a perpendicular bisector.
True
False ...?
The construction method for creating a perpendicular line through a point not on a line is indeed useful for constructing a perpendicular bisector, based on the principle that all right angles are equal to one another. Therefore given statement is true.
Explanation:The construction method used to construct a perpendicular through a point not on a line can indeed be used to construct a perpendicular bisector. This is true because both constructions rely on the same geometric principles. E4, which states that all right angles are equal to one another, supports this fact. In constructing a perpendicular line through a point not on the line, one essentially finds the point on the existing line that is closest to the external point and constructs a right angle there. This same method can be adapted for a segment to create a perpendicular bisector. By selecting the midpoint of the segment and then constructing a right angle using the segment as one side, this similarly results in a perpendicular bisector.
Final answer:
The construction method used to construct a perpendicular through a point not on a line being also applicable for constructing a perpendicular bisector is True. Both involve similar steps of drawing arcs with a compass that intersect and then drawing a line through those intersections, leveraging the properties of equidistant points and perpendicular bisectors.
Explanation:
The statement that the construction method used to construct a perpendicular through a point not on a line could also be used to construct a perpendicular bisector is True. The basic geometrical constructions used for both are quite similar. To construct a perpendicular through a point not on a line, one would typically use the following process:
Place the compass at the given point and draw an arc that crosses the line twice.
Without changing the compass width, move the compass to each intersection point and draw two arcs that intersect above and below the line.
Draw a line connecting the intersection points of these arcs. This is the perpendicular line through the point.
To construct a perpendicular bisector, one would:
Place the compass at one end of the line segment and draw an arc above and below the line.
Without changing the compass width, repeat from the other end of the line segment so that the arcs cross.
Connect the intersection points of the arcs to form the perpendicular bisector.
In both cases, we utilize the property that the perpendicular bisector of a line segment is the set of all points equidistant from the segment's endpoints, and similarly, through a point not on a line, we can construct two such points that are equidistant from it on the line, therefore satisfying Corollary regarding points equidistant from the extremities of a straight line determining a perpendicular to the line at its middle point.
For f(x)=4x+1 and g(x)=x^2-5 , find (f-g) (x) .
Keywords:
Functions, subtraction, operation of functions
For this case, we are given two functions of the form [tex]y_ {1} = f (x)[/tex], where [tex]f (x) = 4x + 1[/tex] and[tex]y_ {2} = g (x)[/tex], where [tex]g (x) = x ^ 2-5[/tex]. We must find the subtraction (f-g) (x). So, by definition of operation of functions we have to:
[tex](f-g) (x) = f (x) -g (x)[/tex]
So, we have:
[tex](f-g) (x) = 4x + 1- (x ^ 2-5)[/tex]
Knowing that: [tex]- * + = -\ and\ - * - = +[/tex]
[tex](f-g) (x) = 4x + 1-x ^ 2 + 5\\(f-g) (x) = - x ^ 2 + 4x + 6[/tex]
Answer:
[tex](f-g) (x)[/tex]is given by[tex]-x ^ 2 + 4x + 6[/tex]
A triangle inscribed in a semicircle can be identified as a/an _______ triangle.
A triangle inscribed in a semicircle can be identified as a right triangle.
Explanation:A triangle inscribed in a semicircle can be identified as a right triangle.
To see why, consider that when a triangle is inscribed in a semicircle, one of its sides will coincide with the diameter of the circle. Since the diameter of a circle is always a straight line, it forms a right angle (90 degrees) with the semicircle's arc. Therefore, the triangle that is inscribed in the semicircle has a right angle as one of its angles, making it a right triangle.
Which represents the empirical formula for A3B9?
AB3
AB2
A3B9
A9B27
Answer:
[tex]AB_{3}[/tex]
Step-by-step explanation:
Given : [tex]A_{3}B_{9}[/tex]
To Find : Which represents the empirical formula for[tex]A_{3}B_{9}[/tex]?
Solution:
Definition of Empirical Formula - A formula that gives the simplest whole-number ratio of atoms in a compound.
[tex]A_{3}B_{9}[/tex]
To reduce it in simplest form
Divide the subscript numbers by 3
So, the resultant : [tex]AB_{3}[/tex]
Thus the empirical formula for [tex]A_{3}B_{9}[/tex] :
[tex]AB_{3}[/tex]
A 16 ounce jar of peanut butter costs $1.98. What is the price per ounce, rounded to the nearest hundredths place?