What is the answer to this question?

What Is The Answer To This Question?

Answers

Answer 1

2A on 2A + 3B + 3C = 8 pieces

The probability:

[tex]\dfrac{2}{8}=\dfrac{2:2}{8:2}=\dfrac{1}{4}[/tex]

[tex]\dfrac{1}{4}=\dfrac{1}{4}\cdot100\%=25\%[/tex]

Answer: 25%

Related Questions

At the city park there were 15 blue jays, 6 cardinals, and 9 mockingbirds. For each of the following questions set up a proportion equation and solve for the unknown. 1. If there were 6 mockingbirds, how many cardinals would there be at the park? 2. If there were 5 blue jays, how many cardinals would there be at the park? 3. If there were 20 cardinals, how many mockingbirds would there be at the park?

Answers

1. 4 cardinals because: 6 mockingbirds : x cardinals = 9 mockingbirds : 6 cardinals 6*6 / 9 = 4 2. 2 cardinals because: 5 blue jays : x cardinals = 15 blue jays : 6 cardinals 5*6 / 15 = 2 3. 30 mockingbirds because; 20 cardinals : x mockingbirds = 6 cardinals : 9 mockingbirds 20*9 / 6 = 30

write words to match the expression
3+(4×12)

Answers

3 plus the quotient of 4 and 12. Hope this helps!

Kristin jogs around a park that has a perimeter of 12 mile. Kristin jogged around the park 4 times in 50 minutes.

What is the unit rate of Kristin's speed?


Answers

Kristin jogs 48 miles in 50 minutes, so her unit rate is 48miles/50 minutes

12 *4 = 48 total miles in 50 minutes

48 / 50/60 =  57.6 miles per hour

WILL GIVE BRAINEST
Costumers can pick their own berries at the gooseberry farm....

Answers

y = 2.5x + 3

answer is
C. y = 2.5x + 3
I think its C. but im not so sure...

It is estimated that light takes 110,000 years to travel the full distance across our galaxy

In the picture please read the rest of the question.

Answers

[tex]\bf \stackrel{light~speed}{3.0\times 10^8}ms^{-1}\implies \stackrel{light~speed}{3.0\times 10^8}~\frac{m}{s}\implies 300,000,000~\frac{m}{s}\\\\ -------------------------------\\\\ \textit{how many seconds in a minute?}\qquad 60 \\\\\\ \textit{how many seconds in }\stackrel{1~hr}{60~minutes?}\qquad 60\cdot 60 \\\\\\ \textit{how many seconds in }\stackrel{1~day}{24~hrs}?\qquad 60\cdot 60\cdot 24 \\\\\\ \textit{how many seconds in }\stackrel{1~year}{365~days}?\qquad 60\cdot 60\cdot 24\cdot 365[/tex]

now, it takes 1 second for light to travel 300,000,000 meters.

if we know it takes light 1 second to go 300 million meters, then in 365 days or a year, or 60*60*24*365 seconds, it will then travels

300,000,000 * 60 * 60 * 24 * 365 meters in 1 year,

how about in 110,000 years, how many meters has it travelled?

300,000,000 * 60 * 60 * 24 * 365 * 110,000   that many meters.

we know she travels the Milky Way in 110,000 years  or 60 * 60 * 24 * 365 * 110,000  seconds

and we know that 110,000 years is 3468960000000 seconds, so

if it travels 300000000 meters in only 1 second, in 3468960000000 seconds, it will travel then (300000000) * (3468960000000) meters

or  1040688000000000000000 meters.

A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind the other 4 doors are consolation prizes. Find the probability that the contestant wins exactly 1 car? no car? or atleast one car?

what if they had to pick 3 doors? and all of the other information wast the same

Answers

The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (https://brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120

the formula of the area of a triangle is A=1/2bh what is the length of the base if the area is 22cm and the height is 8cm

Answers

The length of the base is 5.5
Put the numbers into the equation. 22=.5(b)8 The right hand side should read 4b, and the left should read 22. Divide both sides by 4 to get b=5.5

Number of solutions to equations -2+10+7z=16z+7

Answers

The given equation resulting in one solution, which is z = 1/9.

To find the number of solutions to the equation -2 + 10 + 7z = 16z + 7, we first simplify and solve for z. Start by combining like terms on the left side:

-2 + 10 = 8, so the equation becomes 8 + 7z = 16z + 7.

Next, we get all the terms with z on one side and the constants on the other:

Subtract 7z from both sides:

8 = 16z - 7z + 7

Combine z terms:

8 = 9z + 7

Subtract 7 from both sides:

1 = 9z

Divide both sides by 9:

z = 1/9

For a certain bathtub, the hot water faucet can fill the tub in 13 minutes. The cold water faucet can fill the tub in 12 minutes. If both faucets are used together, how long will it take to fill the tub?

Answers

It will take approximately 6.24 minutes for both faucets to fill the bathtub when used simultaneously.

To solve this problem, we need to find the combined rate at which both faucets can fill the bathtub. The hot water faucet can fill the tub in 13 minutes, and the cold water faucet can fill it in 12 minutes. We can express their rates as fractions of the tub they can fill per minute as 1/13 and 1/12, respectively.

When we add these rates together, we get the combined rate:

Rate of hot water faucet + Rate of cold water faucet = combined rate

1/13 + 1/12 = (12 + 13) / (13  imes 12) = 25 / 156

The combined rate is 25/156 tubs per minute. To find out how long it will take for both faucets to fill the tub together, we take the reciprocal of the combined rate:

Time to fill the tub = 1 / (combined rate) = 156 / 25 = 6.24 minutes

Therefore, it will take approximately 6.24 minutes for both faucets to fill the bathtub when used simultaneously.

The sum of three numbers is 45 the second of the three numbers is three more than twice the first number, ×. The thurd number is two more than the first number, ×. Which equation can be used to solve the first number

Answers

Answer:

Step-by-step explanation:

We know that the 1st equation + 2nd equation + 3rd equation = 45.  Now we just need to identify from the infor given what these equations are, then set them to equal 45.

It has already been determined that the 1st equation is x.

The second equation is "3 more than twice the first".  Twice the first is 2x, and 3 more is +3; therefore, the second equation is: 2x + 3.

The third equation is "2 more than the first".  2 more than is +2, so the third equation is x + 2.

Now we have all 3:

1st:  x

2nd:  2x + 3

3rd:  x + 2

Add them all up and set them equal to 45:

x + 2x + 3 + x + 2 = 45.

You don't have choices listed, so it's either that one above, or simplified down to:

4x + 5 = 45

After that, any simplification done will be solving the equation.

''Please Help!!'' says Kuku and Yaya

A middle-school band holds a car wash to raise money. The sixth-grade band members wash 16 cars. The seventh-grade band members wash 75% as many cars as the sixth-graders. The eighth-grade band members wash half as many cars as the sixth- and seventh-grade band members combined.
If the band charges $5 per car, how much money did the members raise altogether?

Answers

6th grade wash 16 cars
7th grade was 75% as many as 6th grade....0.75(16) = 12 cars washed
8th grade wash half as many as 6th and 7th combined...(12 + 16) / 2 =
28/2 = 14 cars washed

total cars washed : (16 + 12 + 14) = 42 cars
at $ 5 per car.....42 * 5 = $ 210 <===

Estimate how many times larger 7 x 10^10 is than 13 x 10^8. A.50 B.100 c.200 d.400

Answers

7 x 10^10 = 70,000,000,000
13 x 10^8 = 1,200,000,000

70,000,000,000/1,200,000,000 = 58.3333333

I would go with A :)

The circular base of a cone has a radius of 5 centimeters. The height of the cone is 12 centimeters, and the slant height is 13 centimeters. What is the approximate surface area of the cone? Use 3.14 for π and round to the nearest whole number. 267 cm2 283 cm2 456 cm2 487 cm2

Answers

Answer:

Option B. is the correct option.

Step-by-step explanation:

The circular base of a cone has a radius of 5 cm. The height of the cone is 12 cm. Slant height of the cone is 13 cm.

We have to calculate the approximate surface area of the cone.

Since we know Surface area of a cone = Area of circular base + lateral area of the cone

Now Surface area of a cone = πr² + πrl = πr(r + l)

By putting the values of the dimensions of a cone in the formula.

S.A. = π (5² + 5×13) = 3.14×(25 + 65) = 3.14×(90) = 282.60 ≈ 283 cm²

Therefore, Option B is the correct option.

what is the 3sqaure root of 0.027y^9 = ?

Answers

[tex]\bf \sqrt[3]{0.027y^9}\qquad \begin{cases} 0.027=\frac{0027}{1000}\\ 27=3^3\\ 1000=10^3\\ y^9=(y^3)^3 \end{cases}\qquad \sqrt[3]{\cfrac{27}{1000}y^9}\implies \sqrt[3]{\cfrac{3^3}{10^3}(y^3)^3} \\\\\\ \sqrt[3]{\cfrac{3^3(y^3)^3}{10^3}}\implies \cfrac{\sqrt[3]{3^3(y^3)^3}}{\sqrt[3]{10^3}}\implies \cfrac{3y^3}{10}\implies 0.3y^3[/tex]

What is 4 - ( -h ) = 68?

Answers

4 + h = 68

h = 68 - 4

h = 64

hope this helps
First reduce brackets

Next subtract 4 from both sides

And lastly subtract 68 - 4 and u have your answer which is 64.

Find the mean of the given set of numbers. 3, 3, 8, 6, 7, 3

Answers

The answer is 5. The mean is the average you get when you add up all of the numbers and divide by the number of numbers.

Kyra typed 140 words in 5 minuets. Then, she typed 196 words in 7 minutes. Was her rate of words per minute constant? If so, what is the constant of proportionality?

Answers

Hello lamdravenox! There are a few ways to tell if the rate of words per minute are constant but we can divide 140/5 and 196/7 to tell if the rate of words per minute are constant.

First divide 140 / 5 = 28 words per min
Second divide 196 / 7 = 28 words per min

So we can see the rate of words per minute is constants and her rate is at 28 words per min so the constant of proportionality is 28 words per minute.

Will the standard form 3.2 × 10^–4 be more or less than 1? Explain what effect the negative exponent has.

Answers

[tex]\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\ a^{-{ n}} \implies \cfrac{1}{a^{ n}} \qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \qquad \qquad a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\ -------------------------------\\\\ 3.2\cdot 10^{-4}\implies 3.2\cdot \cfrac{1}{10^4}\implies \cfrac{3.2}{10^4}\implies \cfrac{3.2}{10000}\implies 0.00032~\ \textless \ ~1[/tex]

Kent caught an 8 pound 3 ounce trout in Pike Lake. The season's record catch so far is 129 ounces. Did Kent's fish beat the record?

Answers

Yes Kent Did beat the record. There are sixteen ounces in one pound. 16•8=128+3 sooooo..131

a 204 inch board is cut into two pieces. one piece is five times the length of the other.find the lengths of the two pieces

Answers

Solution along with work is included in attachment.

Describe two situations in which opposite quantities combine to make zero

Answers

When one number is negative and the other is positive. 

In the situation, x + (-x) is combined making zero and other y + (-y) is making zero.

What is the arithmetic operator?

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.

Summation = addition of two or more numbers or variable

Subtraction = Minus of any two or more numbers with each other called subtraction.

Division = divide any two numbers or variable called division.

Multiplication = to multiply any two or more numbers or variables called multiplication.

If we combine any two opposite quantities then their summation must be zero.

For example,

if you combine 5 and -5 then it will be 0.

If you combine 10 and -10 then it will be 0.

So,

The first situation ⇒

Combining x and -x

x + (-x) = 0

The second situation ⇒

Combining y and -y

y + (-y) = 0

Hence, In the situation, x + (-x) is combined making zero and other y + (-y) makes zero.

To learn more about the arithmetic operators,

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Which of the following functions are homomorphisms?

Answers

Part A:

Given [tex]f:Z \rightarrow Z, [/tex] defined by [tex]f(x)=-x[/tex]

[tex]f(x+y)=-(x+y)=-x-y \\ \\ f(x)+f(y)=-x+(-y)=-x-y[/tex]

but

[tex]f(xy)=-xy \\ \\ f(x)\cdot f(y)=-x\cdot-y=xy[/tex]

Since, f(xy) ≠ f(x)f(y)

Therefore, the function is not a homomorphism.



Part B:

Given [tex]f:Z_2 \rightarrow Z_2, [/tex] defined by [tex]f(x)=-x[/tex]

Note that in [tex]Z_2[/tex], -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular [tex]f(x)=x[/tex]

[tex]f(x+y)=x+y \\ \\ f(x)+f(y)=x+y[/tex]

and

[tex]f(xy)=xy \\ \\ f(x)\cdot f(y)=xy[/tex]

Therefore, the function is a homomorphism.



Part C:

Given [tex]g:Q\rightarrow Q[/tex], defined by [tex]g(x)= \frac{1}{x^2+1} [/tex]

[tex]g(x+y)= \frac{1}{(x+y)^2+1} = \frac{1}{x^2+2xy+y^2+1} \\ \\ g(x)+g(y)= \frac{1}{x^2+1} + \frac{1}{y^2+1} = \frac{y^2+1+x^2+1}{(x^2+1)(y^2+1)} = \frac{x^2+y^2+2}{x^2y^2+x^2+y^2+1} [/tex]

Since, f(x+y) ≠ f(x) + f(y), therefore, the function is not a homomorphism.



Part D:

Given [tex]h:R\rightarrow M(R)[/tex], defined by [tex]h(a)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right) [/tex]

[tex]h(a+b)= \left(\begin{array}{cc}-(a+b)&0\\a+b&0\end{array}\right)= \left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right) \\ \\ h(a)+h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)+ \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)=\left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right)[/tex]

but

[tex]h(ab)= \left(\begin{array}{cc}-ab&0\\ab&0\end{array}\right) \\ \\ h(a)\cdot h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)\cdot \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)= \left(\begin{array}{cc}ab&0\\-ab&0\end{array}\right)[/tex]

Since, h(ab) ≠ h(a)h(b), therefore, the funtion is not a homomorphism.



Part E:

Given [tex]f:Z_{12}\rightarrow Z_4[/tex], defined by [tex]\left([x_{12}]\right)=[x_4][/tex], where [tex][u_n][/tex] denotes the lass of the integer [tex]u[/tex] in [tex]Z_n[/tex].

Then, for any [tex][a_{12}],[b_{12}]\in Z_{12}[/tex], we have

[tex]f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\ \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)[/tex]

and

[tex]f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)[/tex]

Therefore, the function is a homomorphism.

100.6 - 30.06 show me it in vertically form (show work)so I can understand how to regroup it.

Answers

Final answer:

To vertically subtract 30.06 from 100.6, start by borrowing 1 from the tens place and adding it to the ones place. Then, borrow 10 from the hundreds place and add it to the tens place. Finally, combine the result to get 70.54.

Explanation:

To vertically subtract 30.06 from 100.6, you'll need to line up the decimal points vertically. Start by subtracting the hundredths place (0.06) from the hundredths place (0.00). Since 6 is bigger than 0, you'll need to regroup. Borrow 1 from the tens place by making it 9, and add it to the ones place, making it 10. Then, you can subtract 6 from 10, which gives you 4. Next, subtract the whole number part (30) from the whole number part (100). Since 0 is smaller than 3, regroup again by borrowing 10 from the hundreds place and adding it to the tens place, making it 20. Then, subtract 3 from 10, which gives you 7. Finally, combine the result by placing the decimal point in the correct position, which gives you the answer: 70.54.

Javier By 48 cards at a yard sale. Of the cards 3/8 were basketball cards how many cards were baseball card

Answers

The answer is 18, Hope you get it right!

Simplify 7x+3y-2+6x-1-y^2

Answers

-y² +13x + 3y - 3

is your answer

hope this helps

Algebraically determine if the relation y = x3 − 4x is symmetric with respect to the x-axis, y-axis, the origin or has no symmetry.

Answers

[tex]\bf y=x^3-4x \\\\\\ \textit{check for y-axis symmetry}\\\\ \stackrel{x=-x}{y=(-x)^3-4(-x)}\implies y=(-x)(-x)(-x)+4x\implies \boxed{y=-x^3+4x} \\\\\\ \textit{checking for x-axis symmetry}\\\\ \stackrel{y=-y}{(-y)=x^3-4x}\implies -y=x^3-4x\implies \boxed{y=-x^3+4x} \\\\\\ \textit{checking for origin symmetry}\\\\ \stackrel{x=-x\qquad y=-y}{(-y)=(-x)^3-4(-x)}\implies -y=(-x)(-x)(-x)+4x \\\\\\ -y=-x^3+4x\implies y=\cfrac{-x^3+4x}{-1}\implies \boxed{y=x^3-4x}\quad \checkmark[/tex]

notice, if you replace x = -x and y = -y accordingly for each test for symmetry, if the resulting function, is equal to the original function, then it has that type of symmetry.

Final answer:

Algebraically, the relation y = x^3 - 4x is not symmetric to the x-axis or y-axis but is symmetric with respect to the origin when both x and y are replaced with their negatives.

Explanation:

To determine if the relation y = x3 − 4x is symmetric with respect to the x-axis, y-axis, or the origin, we perform a series of tests substituting -x for x (to test y-axis symmetry), -y for y (to test x-axis symmetry), and both -x for x and -y for y (to test origin symmetry).

Y-axis symmetry test:

Replace x with -x:

y = (-x)3 - 4(-x)

y = -x3 + 4x ≠ x3 − 4x (not symmetric to y-axis)

X-axis symmetry test:

Replace y with -y:

-y = x3 - 4x ⇒ y = -x3 + 4x ≠ x3 − 4x (not symmetric to x-axis)

Origin symmetry test:

Replace both x with -x and y with -y:

-y = (-x)3 - 4(-x)

-y = -x3 + 4x

y = x3 − 4x (symmetric to origin)

A model for the population in a small community after t years is given by P(t)=P0e^kt.
a)If the initial population doubled in 5 years, how long will it take to have tripled its initial population?
b)In addition, if the population of the community is 10,000 in 3 years, what was its initial population?

Answers

[tex]\bf \textit{Amount of Population Growth}\\\\ A=Ie^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ I=\textit{initial amount}\\ r=rate\to r\%\to \frac{r}{100}\\ t=\textit{elapsed time}\\ \end{cases}[/tex]

a)

so, if the population doubled in 5 years, that means t = 5.  So say, if we use an amount for "i" or P in your case, to be 1, then after 5 years it'd be 2, and thus i = 1 and A = 2, let's find "r" or "k" in your equation.

[tex]\bf \textit{Amount of Population Growth}\\\\ A=Ie^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\to &2\\ I=\textit{initial amount}\to &1\\ r=rate\\ t=\textit{elapsed time}\to &5\\ \end{cases} \\\\\\ 2=1\cdot e^{5r}\implies 2=e^{5r}\implies ln(2)=ln(e^{5r})\implies ln(2)=5r \\\\\\ \boxed{\cfrac{ln(2)}{5}=r}\qquad therefore\qquad \boxed{A=e^{\frac{ln(2)}{5}\cdot t}} \\\\\\ \textit{how long to tripling?}\quad \begin{cases} A=3\\ I=1 \end{cases}\implies 3=1\cdot e^{\frac{ln(2)}{5}\cdot t}[/tex]

[tex]\bf 3=e^{\frac{ln(2)}{5}\cdot t}\implies ln(3)=ln\left( e^{\frac{ln(2)}{5}\cdot t} \right)\implies ln(3)=\cfrac{ln(2)}{5} t \\\\\\ \cfrac{5ln(3)}{ln(2)}=t\implies 7.9\approx t[/tex]

b)

A = 10,000, t = 3

[tex]\bf \begin{cases} A=10000\\ t=3 \end{cases}\implies 10000=Ie^{\frac{ln(2)}{5}\cdot 3}\implies \cfrac{10000}{e^{\frac{3ln(2)}{5}}}=I \\\\\\ 6597.53955 \approx I[/tex]

What is the factorization of 49b2 − 81? (7b – 9)(7b – 9) (7b – 9)(7b + 9) (7b2 – 9)(7b2 – 9) (7b2 – 9)(7b2 + 9)

Answers

49b^2 − 81 =  (7b + 9)(7b – 9)

answer
(7b – 9)(7b + 9)
Final answer:

The factorization of 49b² - 81 using the difference of squares formula is (7b - 9)(7b + 9).

Explanation:

The question is asking to factorize the expression 49b² - 81, which is a difference of two squares. The difference of squares formula is a² - b² = (a - b)(a + b). In your question, a² is 49b² and b² is 81. Therefore, a would be 7b (since square root of 49b² is 7b) and b would be 9 (since square root of 81 is 9).

Thus, using the formula, the factorization of 49b² - 81 will be (7b - 9)(7b + 9). This provides an explanation of the concepts involved and the steps followed in the solution.

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how would i write y= -7x+25 In Standard form?

please help:)

Answers

7x+y=25

nohpihot7 ggyfffffff
y = -7x + 25

Isolate the constant to write is in standard form.

You want it in the form

Ax + By = C

7x + y = 25

Done!

1/4x + 1/3 = 1/6x - 1/4

Answers

1/4x + 1/3 = 1/6x - 1/4

We simply want to isolate x.

So, we must get x onto it's own side of the equal sign.

To do that, we subtract 1/3 from both sides.

1/4x = 1/6x - 1/4 - 1/3


Then, subtract 1/6x from both sides.

1/4x - 1/6x = -1/4 - 1/3

Simplify.

1/4x → 3/12x  ; -1/6x → -2/12x   ; -1/4 → -3/12  ; -1/3 → -4/12

Plug these into our equation.

3/12x - 2/12x = -3/12 - 4/12 

Simplify.

1/12x = -7/12

Multiply everything by 12.

12 · 1/12x = -7/12 · 12

Simplify.

x = -7

~Hope I helped!~



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