What is the area? i need help please im timed and don't know how to do this

Answer:

Check the explanation

Step-by-step explanation:

Use the below R Code

Sales=c(245,138,352,322,228,275,560,366)

Advertising=c(16.5,18,22.3,17.4,19,20,32,18.6)

Commission=c(10.5,2,4,3.5,4.5,1.8,9,8.5)

data=as.data.frame(cbind(Sales,Advertising,Commission))

model1=lm(Sales~Advertising+Commission, data = data)

dat2=data.frame(Advertising=25,Commission=8)

predict(model1,dat2)

The predicted value of Sales for 25000 dollar on Advertising and 8% on Commission is 424685 dollars approximately (rounded to 0 decimal places)

Answer:

60. Got it wrong, but oh well.

Step-by-step explanation:

Answer:

Conclusion

    The average rental rate in Hong Kong are higher than in Paris

Step-by-step explanation:

From the question we are told that

  The sample size for Hong Kong is  [tex]n_1 = 30[/tex]

  The mean for Hong Kong is [tex]\mu_h = 1,114 \ m^2[/tex]

   The standard deviation for Hong Kong is[tex]s = 230[/tex]

   The sample size for Paris is  [tex]n_2 = 40[/tex]

      The mean for Paris is [tex]\mu_p = 989 \ m^2[/tex]

    The standard deviation for Paris is [tex]s_p = 195[/tex]

      The level of significance is  [tex]\alpha = 0.05[/tex]

The Null Hypothesis is  

          [tex]H_o : \mu_1 - \mu_2 = 0[/tex]  

The alternative hypothesis is

          [tex]H_a: \mu_1 - \mu_2 >0[/tex]

The test statistics is mathematically represented as

          [tex]t = \frac{\mu _1 - \mu_2 - d }{\sqrt{(\frac{s^2}{n1} )+(\frac{(s_p^2}{n_2} )}}[/tex]

Substituting values

        [tex]t = \frac{1114 - 989 - 0 }{\sqrt{(\frac{230^2}{30} )+(\frac{(195^2}{40} )}}[/tex]  

       [tex]t = 2.399[/tex]

Since the value of the test statistics is higher than the  significance level then there  is enough evidence to conclude that the average rental rate in Hong Kong are higher than in Paris

Using the t-distribution, it is found that since the test statistic is more than the critical value, there is enough evidence to conclude that the mean annual lease rate is higher in Hong Kong than in Paris.

At the null hypothesis, it is tested if the average is not higher in Hong Kong, that is, the result of the subtraction if not greater than 0.

[tex]H_0: \mu_H - \mu_P \leq 0[/tex]

At the alternative hypothesis, it is tested if it is higher, that is:

[tex]H_1: \mu_H - \mu_P > 0[/tex]

The standard errors for both samples are:

[tex]s_H = \frac{230}{\sqrt{30}} = 42[/tex]

[tex]s_P = \frac{195}{\sqrt{40}} = 30.83[/tex]

The distribution of the differences has mean and standard deviation given by:

[tex]\overline{X} = \mu_H - \mu_P = 1114 - 989 = 125[/tex]

[tex]s = \sqrt{s_H^2 + s_P^2} = \sqrt{42^2 + 30.83^2} = 52.1[/tex]

The test statistic is:

[tex]t = \frac{\overline{X} - \mu}{s}[/tex]

In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis.

Hence, the value is:

[tex]t = \frac{125 - 0}{52.1}[/tex]

[tex]t = 2.4[/tex]

The critical value, for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05 and 30 + 40 - 2 = 68 df, is [tex]t^{\ast} = 1.67[/tex]

Since the test statistic is more than the critical value, there is enough evidence to conclude that the mean annual lease rate is higher in Hong Kong than in Paris.

A similar problem is given at https://brainly.com/question/16402495

Answer:Harriet

Step-by-step explanation:

Answer:

The aNSWER IS d

Step-by-step explanation: i JUST DID THE TEST

Answer:

  D. 12 in²

Step-by-step explanation:

The area of a parallelogram is given by the formula ...

  A = bh

Substituting the given values for the length of the base (b) and the height (h), we have ...

  A = (4 in)(3 in)

  A = 12 in²

The area is 12 square inches.

Answer:

D 12

Step-by-step explanation:

I just did the lesson and got it right.

Answer:

lol good luck with that but you add them

Step-by-step explanation:

Answer:

  (2/9)cis(30°)

Step-by-step explanation:

We can express the two numbers in magnitude∠angle form, then find their ratio.

  |z1| = 3√((-1)² +(√3)²) = 3√4 = 6

  ∠z1 = arctan((3√3)/(-3)) = -arctan(√3) = 120°

  z2 = 27∠90°

So, the ratio is ...

  z1/z2 = (6∠120°)/(27∠90°) = (6/27)∠(120°-90°)

  z1/z2 = (2/9)∠30°

Answer:

The depreciation expense of the truck in 2008 and 2009 are $14,000 and $8,400 respectively.

Step-by-step explanation:

The double declining depreciation method depreciates assets twice as fast as the traditional declining balance method.

The method records larger depreciation expenses during the earlier years of an asset’s useful life, and smaller ones in later years.

As a result, companies opt for the method for assets that are likely to lose most of their value early on, or which will become obsolete faster.

For double declining depreciation method,

- Divide “100%” by the number of years in the asset’s useful life, this is the straight-line depreciation rate.

- Then, multiply that number by 2 and that is the Double-Declining Depreciation Rate. - In this method, depreciation continues until the asset value declines to its salvage value.

Number of useful lives = 5 years.

- Divide 100% by 5 years

100% / 5 = 20%

- Then, multiply that percentage by 2

20% x 2 = 40%

The Double-Declining Depreciation rate is 40%.

Value of the truck at the start of 2008 = $35,000

Depreciation in 2008 = 40% × 35000 = $14,000

Book Value of the truck at the start of 2009 = $35000 - $14000 = $21000

Depreciation in 2009 = 40% × 21000 = $8,400

Hope this Helps!!!

Answer:

0.05

Step-by-step explanation:

The production of black potatoes is 6000 kg, the production of sweet potatoes is 7200 kg, and the total production of both types of potatoes is 13200 kg.

To find the total production of black potatoes and sweet potatoes, we need to multiply the weekly production by the number of weeks (12 weeks).

For black potatoes:

Weekly production = 500 kg

Total production of black potatoes = Weekly production * Number of weeks

= 500 kg/week * 12 weeks

= 6000 kg

For sweet potatoes:

Weekly production = 600 kg

Total production of sweet potatoes = Weekly production * Number of weeks

= 600 kg/week * 12 weeks

= 7200 kg

Now, to find the total production:

Total production = Total production of black potatoes + Total production of sweet potatoes

= 6000 kg + 7200 kg

= 13200 kg

So, the production of black potatoes is 6000 kg, the production of sweet potatoes is 7200 kg, and the total production of both types of potatoes is 13200 kg.

Complete question:

Carlos has a weekly production of 500kg of black potatoes and 600kg of sweet potatoes after 12 weeks. How much will the production of potatoes be? And of sweet potatoes? How much will the total production be?

Answer:

5

Step-by-step explanation:

so you can think of it as b is 5 and 2 times by 5 is 10. you can then make 10 - 5 which is 5. so a is 5

Answer:

  499,153.0 cm^3

Step-by-step explanation:

The volume of a sphere is given by the formula ...

  V = (4/3)πr^3

The volume of a hemisphere will be half that, or ...

  (2/3)πr^3 = (2/3)π(62 cm)^3 = (158885 1/3)π cm^3

  ≈ 499,153.0 cm^3

_____

Comment on this result

We have used a value of pi sufficiently accurate to give the result to 7 significant figures. If you use 3.14, you will get an answer somewhat different from this.

Answer:  499,153.0 cm^3

Answer:

∅ = 50°

Step-by-step explanation:

YOU NEED A CALCULATOR TO SOLVE THIS!

You need to use Law of Sines

[tex]\frac{a}{sinA} =\frac{b}{sinB} = \frac{c}{sinC}[/tex]

Here you will be doing [tex]\frac{a}{sinA} =\frac{c}{sinC}[/tex]

a and c are the lengths, while A and C are the angles

[tex]\frac{3.46}{sinA} = \frac{2.54}{sin43}[/tex] you want to get the denominators out from underneath so multiply both sides by sinA and sin43

[tex]3.46sin43 = 2.54sinA[/tex]

Now you want to get sinA alone so divide both sides by 2.54

[tex]\frac{3.46sin43}{2.54} = sinA[/tex] now get A alone

[tex]sin^{-1} (\frac{3.46sin43}{2.54}) = A[/tex] put that into the calculator

[tex]49.61741033 = A[/tex]

Answer:

51 + 29+ 80

Step-by-step explanation:

she got this by adding 51 + 29

Answer:62

Step-by-step explanation:

Answer:

[tex]t=\frac{282-280}{\frac{38}{\sqrt{89}}}=0.497[/tex]    

Now we can calculate the p value for the test

We are conducting a right tailed test so then the p value is given by:  

[tex]p_v =P(z>0.497)=0.310[/tex]  

Since the p value is higher than the significance level we have enough evidence to conclude that the true mean is not significantly higher than 280 so then the administrator claim is not true

Step-by-step explanation:

Data provided

[tex]\bar X=282[/tex] represent the mean for the assesment test

[tex]\sigma=38[/tex] represent the population deviation

[tex]n=89[/tex] sample size  

[tex]\mu_o =280[/tex] represent the value to verify

[tex]\alpha=0.05[/tex] represent the significance level

t would represent the statistic

[tex]p_v[/tex] represent the p value

Hypothesis to test

We want to determine if the mean score for the​ state's eighth graders on this exam is more than 280, so then the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 280[/tex]  

Alternative hypothesis:[tex]\mu > 280[/tex]  

Since we know the population deviation we can use a z test for the true mean and the statistic is given by:

[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex]  (1)  

Replacing the info given by the problem we got:

[tex]t=\frac{282-280}{\frac{38}{\sqrt{89}}}=0.497[/tex]    

Now we can calculate the p value for the test

We are conducting a right tailed test so then the p value is given by:  

[tex]p_v =P(z>0.497)=0.310[/tex]  

Since the p value is higher than the significance level we have enough evidence to conclude that the true mean is not significantly higher than 280 so then the administrator claim is not true

To determine if there is enough evidence to support the administrator's claim, we need to perform a hypothesis test. By comparing the z-score to the critical value at α=0.05, we can reject the null hypothesis and conclude that there is enough evidence to support the administrator's claim.

To determine if there is enough evidence to support the administrator's claim, we need to perform a hypothesis test. The null hypothesis (H0) is that the mean score for the state's eighth graders is <=280. The alternative hypothesis (Ha) is that the mean score is >280.

To conduct the test, we can calculate the z-score using the formula z = (x - μ) / (σ / sqrt(n)), where x is the sample mean, μ is the hypothesized population mean (280), σ is the population standard deviation (38), and n is the sample size (8989). Plug in the given values, we get z = (282 - 280) / (38 / sqrt(8989)) = 3.055.

Next, we compare the z-score to the critical value at α=0.05. For a one-tailed test, the critical value is 1.645. Since 3.055 > 1.645, we reject the null hypothesis and conclude that there is enough evidence to support the administrator's claim that the mean score for the state's eighth graders on this exam is more than 280.

Answer:

15 small bottles

30 large bottles

Step-by-step explanation:

Let the number of small bottle sold=s

Let the number of large bottle sold=l

She sold all 45 of the hand sanitizer bottles, therefore:

The small bottle sells for $5.00

The large sells for  $12.00

She collected a total of $435

We solve the two equations simultaneously to obtain s and l.

From the first equation, s=45-l

Substitute s=45-l into 5s+12l=435

5(45-l)+12l=435

225-5l+12l=435

7l=435-225

7l=210

Divide both sides by 7

l=30

Recall: s=45-l

Therefore, s=45-30=15

Allanah sold 15 small bottles and 30 large bottles of hand sanitizer.

Answer:

The total area of the figure is 52 in²

Step-by-step explanation:

This figure requires you to find the area of the square and the triangle separately, and then subtract the area of the triangle from the area of the square.

Find the area of the square

l=8in

A=l²

A=8²

A=64 in²

The area of the square is 64 in²

Find the area of the triangle

b=8in

h=3in

A=(bh)/2

A=(8*3)/2

A=24/2

A=12 in²

The area of the triangle is 64 in²

Now we need to subtract the areas

64-12=52 in²

The total area of the figure is 52 in²

Answer:

a. Ignacio recibió $9000. Mariela recibió $2400 y Laura, $3600. b. Ignacio y Mariela recibieron [tex] \\ \frac{19}{25}[/tex] del total del premio (diecinueve veinticincoavos) ($11400).

Step-by-step explanation:

Tenemos un total de $15000, que fue el premio del concurso, el cual fue repartido entre tres personas: Ignacio, Mariela y Laura.

Lo que tenemos que hacer es multiplicar cada fracción por la totalidad del premio ($15000), para determinar cuánto recibió cada uno.

Recordemos que para resolver estos casos, la regla general es que sólo tenemos que multiplicar el numerador de la fracción por dicho total ($15000) y luego dividir el producto resultante entre el denominador de la fracción.

De esta manera, procedemos a resolver cada caso.

Lo recibido por Ignacio

Si Ignacio recibió las 3/5 partes del premio: ¿cuánto recibió Ignacio?

Como ya sabemos, la respuesta es multiplicar la fracción por el total del premio. Es decir:

[tex] \\ \frac{3}{5}*15000[/tex]

[tex] \\ \frac{3*15000}{5}[/tex]

[tex] \\ \frac{45000}{5}[/tex]

[tex] \\ 9000[/tex]

Que podemos también resolver de la siguiente manera, considerando que es más fácil dividir 15000 entre 5, por ser 5 un divisor de 15000:

[tex] \\ \frac{15000}{5}*3[/tex]

[tex] \\ 3000*3[/tex]

[tex] \\ 9000[/tex]

Es decir, Ignacio recibió $9000.

Lo recibido por Mariela

Para el caso de Mariela, aplicamos el mismo procedimiento.

Como Mariela recibió las 4/25 (cuatro veinticincoavos) del premio, tenemos entonces:

[tex] \\ \frac{4}{25}*15000[/tex]

[tex] \\ \frac{4*15000}{25}[/tex]

[tex] \\ \frac{60000}{25}[/tex]

[tex] \\ 2400[/tex]

También lo hubiéramos resuelto, sin tener que hacer una multiplicación y división extensas, si consideramos que 15000 y 25 son múltiplos de 5. Por lo tanto:

[tex] \\ \frac{4}{25}*15000[/tex]

[tex] \\ \frac{15000}{25}*4[/tex]

Es decir, dividir 15000 entre 25, y luego multiplicamos por cuatro. Así:

[tex] \\ 600*4[/tex]

[tex] \\ 2400[/tex]

Obteniendo el mismo resultado

De esta manera, Mariela recibió $2400.

Lo recibido por Laura

Laura recibió el resto de lo dejado por Ignacio y Mariela. Podemos resolver ésto de diversas formas. Una de ellas es restar del total del premio la suma de lo recibido por Ignacio y Mariela.

[tex] \\ 15000 - (9000 + 2400)[/tex]

[tex] \\ 15000 - 11400[/tex]

[tex] \\ 3600[/tex]

De esta manera, Laura recibió $3600.

¿Qué parte del premio recibieron Ignacio y Mariela?

En otras palabras, qué parte del premio recibieron Ignacio y Mariela en conjunto, en forma de fracción.

Una manera de resolver esta pregunta es sumando las fracciones que recibió cada uno, es decir, [tex] \\ \frac{3}{5} + \frac{4}{25}[/tex].

Hay varias maneras de sumar ambas fracciones. Una de ellas (la manera más general) es multiplicar el denominador de cada fracción por el numerador de la otra fracción, sumar cada producto obtenido y luego dividirlo entre el producto de los denominadores de cada fracción.

[tex] \\ \frac{3}{5} + \frac{4}{25}[/tex]

[tex] \\ \frac{3*25 + 5*4}{5*25}[/tex]

[tex] \\ \frac{75 + 20}{125}[/tex]

[tex] \\ \frac{95}{125}[/tex]

Podemos observar que 95 y 125 son múltiplos de 5, así que podemos simplificar el numerador y el denominador de la fracción dividiendo a ambos entre 5:

[tex] \\ \frac{95}{125}[/tex]

[tex] \\ \frac{\frac{95}{5}}{\frac{125}{5}}[/tex]

[tex] \\ \frac{19}{25}[/tex]

El número 19 es un número primo y no podemos simplificar más la fracción.

De esta manera, Ignacio y Mariela recibieron [tex] \\ \frac{19}{25}[/tex] del total del premio (diecinueve veinticincoavos), lo cual podemos comprobar si multiplicamos esta fracción por el total del premio y lo comparamos con la suma de los resultados para Ignacio y Mariela:

[tex] \\ \frac{19}{25}*15000[/tex]

[tex] \\ \frac{15000}{25}*19[/tex]

[tex] \\ 600*19[/tex]

[tex] \\ 11400[/tex]

Lo que es igual a la suma de lo recibido por Ignacio ($9000) y Mariela ($2400), es decir $11400.

Laura, por lo tanto recibió [tex] \\ \frac{6}{25}[/tex]

Por cuanto

[tex] \\ \frac{6}{25} + \frac{19}{25} = \frac{6+19}{25} = \frac{25}{25} = 1[/tex]

Es decir, la suma de las fracciones de lo recibido por Ignacio y Mariela más lo que recibió Laura debe sumar la totalidad, es decir, la unidad (1).

Answer:25

Step-by-step explanation:

Because 5x5 equals 25

Answer:

25 Count by five with your five fingers

Step-by-step explanation:

5x5=25

Answer:

3.008 km or 3.0 km

Step-by-step explanation:

According to the Pythagoras theorem:

[tex] {c}^{2} = {a}^{2} + {b}^{2} \\ \therefore \: {a}^{2} = {c}^{2} - {b}^{2} \\ \therefore \: {a}^{2} = {(9.3)}^{2} - {(8.8)}^{2} \\ \therefore \: {a}^{2} = {(9.3 + 8.8)}{(9.3 - 8.8)} \\ \therefore \: {a}^{2} = 18.1 \times 0.5 \\ \therefore \: {a}^{2} = 9.05 \\ \therefore \: {a} = \sqrt{9.05} \\ \therefore \: {a} = 3.00832179 \\ \therefore \: {a} = 3.0 \: km[/tex]

Answer:

  P'(-6, -4)

Step-by-step explanation:

The (x, y) coordinates of the plotted point P are (-2, 2).

Putting those values into the translation formula, you get ...

  (x, y) ⇒ (x -4, y -6)

  (-2, 2) ⇒ (-2 -4, 2 -6) = (-6, -4)

The coordinates of the translated point P' are ...

  P'(-6, -4)

Answer:

3150^3

Step-by-step explanation:

Answer:

Check the explanation

Step-by-step explanation:

1) probability for odd or 00 = (18+1)/38 = 0.5

2) expected value can be calculated as follows :

14 * win probability - 13 * lose probability

=14 * (18/38) - 13*(20/38)

= -0.21

Using it's concept, it is found that there is a 0.5 = 50% probability of the marble landing on a 00 or even slot.

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem:

The desired probability is:

[tex]p = \frac{D}{T} = \frac{19}{38} = 0.5[/tex]

0.5 = 50% probability of the marble landing on a 00 or even slot.

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Answer: the answer is i think* A, Translate the pre-image down 4 and right 3 and then reflect the figure over the x-axis.

Step-by-step explanation: it's the only one that makes sense im takin the test

Answer:

A, Translate the pre-image down 4 and right 3 and then reflect the figure over the x-axis.

Step-by-step explanation:

I took the test hope this helps!!!!!!!!!!!!!!

Answer:

The answer is 8.3 repeating. If you round it the answer is 8.

Answer:

8.3... grams in each cupcake

Step-by-step explanation:

you basically divide 100 by 12

Answer:       equation = dA/dt = K₁ (M - A) - K₂A

Step-by-step explanation:

Let us follow this carefully to get our equation right.

From the question we are told to (Assume the constants of proportionality for the rate at which material is memorized and the rate at which material is forgotten are k1 > 0 and k2 > 0, respectively. Use A for A(t) ).

The Rate of memorizing the material is ∝ [Total amount to be memorized]  - [Amount memorized]

remember using A for A(t).

where A rep the amount memorized at a time t and M is the Total amount memorized.

so we have that dA/dt  ∝ M - A

which is dA/dt = K₁ (M - A) ---------------(*)

remember it was stated that forgetfulness is taken into account

Forgetfulness, F ∝ A

F = K₂A --------------- (**)

which implies the rate of memorization is decreased as a result of forgetting;

this leads to

dA/dt = K₁ (M - A) - K₂A

The  rate of differential equation is  ⇒  dA/dt = K₁ (M - A) - K₂A

cheers i hope this helped!!!!

Answer:

The point estimate is 0.391 and the margin of error is 0.042.

Step-by-step explanation:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the absolute value of the difference between the point estimate and any of the two bounds.

In this problem, we have that:

Lower bound: 0.349

Upper bound: 0.433

Point estimate:

(0.349+0.433)/2 = 0.391

Margin of error:

|0.391 - 0.433| = |0.391 - 0.349| = 0.042

The point estimate is 0.391 and the margin of error is 0.042.

Final answer:

The midpoint of the confidence interval (0.349, 0.433) provides the point estimate, which is 0.391. The margin of error is calculated by subtracting the point estimate from the upper bound of the interval, resulting in 0.042.

Explanation:

The confidence interval (0.349, 0.433) can be used to find the point estimate and margin of error for the proportion of customers interested in a breakfast menu at a fast food restaurant. To find the point estimate, we take the midpoint of the confidence interval, which is the average of the lower and upper bounds.

Point Estimate = (Lower Bound + Upper Bound) / 2
Point Estimate = (0.349 + 0.433) / 2
Point Estimate = 0.391

To find the margin of error, we subtract the point estimate from either the upper or lower bound of the confidence interval.

Margin of Error = Upper Bound - Point Estimate
Margin of Error = 0.433 - 0.391
Margin of Error = 0.042

Therefore, the point estimate is 0.391 and the margin of error is 0.042 for the proportion of customers interested in the breakfast menu.

The student's GPA for that term would be 3.16.

Given that;

A student had these grades:

3.9 in a 5 credit Math course

2.4 in a 2 credit Music course

2.7 in a 4 credit Chemistry course

3.1 in a 6 credit Journalism course

Now for the student's GPA for the term, calculate the weighted average of the grades.

First, calculate the total grade points earned by multiplying each grade by the corresponding number of credits:

Grade points for Math course = 3.9 × 5

                                                  = 19.5

Grade points for Music course = 2.4 × 2

                                                   = 4.8

Grade points for Chemistry course = 2.7 × 4

                                                          = 10.8

Grade points for Journalism course = 3.1 × 6

                                                            = 18.6

Hence, the total grade points earned:

Total grade points earned = 19.5 + 4.8 + 10.8 + 18.6

                                            = 53.7

Finally, divide the total grade points earned by the total number of credits:

Total credits = 5 + 2 + 4 + 6

                     = 17

Use the formula;

GPA = Total grade points earned / Total credits

GPA = 53.7 / 17

GPA = 3.16

Therefore, the student's GPA for that term is 3.16.

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To compute a student's GPA, we need to calculate the weighted average of their grades. Multiply each grade by the corresponding number of credits, sum the products, and divide by the total number of credits.

To compute the student's GPA for the term, we need to calculate the weighted average of their grades. The weighted average is calculated by multiplying each grade by the corresponding number of credits and then summing up these products. Finally, we divide the sum by the total number of credits.

For the student in question, let's calculate their GPA:

The student's GPA for that term is 3.16 when rounded to two decimal places.

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