What is the area in square inches 3/8 inch 2/3 inch

Answer:

B. Only the monthly rental cost of apartments in Lowell is changing exponentially.

Step-by-step explanation:

To identify how the values ​​of the monthly costs of the departments are changing, we must do a test.

The test consists of taking an element [tex]n_{-1}[/tex] and the element n of the series, and dividing [tex]\frac{n}{n_{-1}} = a[/tex]

Then take the element [tex]n_{+1}[/tex] and the element n and divide [tex]\frac{n_{+1}}{n} = b[/tex]

If b = a, then the exponential function of base "b"

But if b> a, then the rate of change of the function is not exponential

For example. For the cost of apartments in Beverly

[tex]n_{-1} = 1870\\n = 1890\\n_{+1} = 1950\\\\\frac{n}{n_{-1}} = \frac{1890}{1870} = 1.011\\\\\frac{n_{+1}}{n} = \frac{1950}{1890} = 1.032\\\\1,032> 1,011[/tex]

So, the cost of apartments in Beverly does not increase at an exponential rate.

We do the same for the cost of the apartments in Lowell.

[tex]n_{-1} = 1600\\n = 1680\\n_{+1} = 1764\\\\\frac{n}{n_{-1}} = \frac{1680}{1600} = 1.05\\\\\frac{n_{+1}}{n} = \frac{1764}{1680} = 1.05\\\\1.05 = 1.05[/tex]

The rate is the same, so the prices increase exponentially.

Finally, the correct answer is option B: B. Only the monthly rental cost of apartments in Lowell is changing exponentially.

Answer:

B. Only the monthly rental cost of apartments in Lowell is changing exponentially.

Step-by-step explanation:

Answer:

the correct answer is c

Step-by-step explanation:

Answer:

the real answer is A.ONLY(1,4)

Answer:

No, the solution discussed in question is not correct.

Step-by-step explanation:

Length of the garden ,l= 80 feet

Breadth of the garden ,b= 40 feet

Area of the rectangle = l × b

Area of the garden = A

[tex]A=l\times b = 80 ft\times 40 ft = 3,200 ft^2[/tex]

Area covered by 1 bag of seeds of grass = [tex]25 yard^2=225 ft^2[/tex]

[tex]1 yard^2 = 9 ft^2[/tex]

Bags of seed of grass covering area of [tex]3,200 ft^2[/tex]:

[tex]\frac{3200 ft^2}{225 ft^2}=14.22[/tex]

14.22 bags of seed of grass will occupy the area covered by the garden.

Answer:

3z(3w - 2)(3w + 2)(9w² + 4)

Step-by-step explanation:

take out a common factor 3z from both terms

= 3z(81[tex]w^{4}[/tex] - 16)

81[tex]w^{4}[/tex] - 16 ← is a difference of squares

• a² - b² = (a - b)(a + b)

81[tex]w^{4}[/tex] = (9w²)² → a = 9w² and 16 = 4² → b = 4

= 3z(9w² - 4)(9w² + 4)

9w² - 4 ← is also a difference of squares with a = 3w and b = 2

= 3z(3w - 2)(3w + 2)(9[tex]w^{4}[/tex] + 4)

Answer:

8.3

Step-by-step explanation:

it is the opposite because -8.3 is a negative, so the only opposite of this number would be its positive

"n" and "-n" are opposite numbers.

The sum of a opposite numbers is equal 0: n + (-n) = n - n = 0.

Opposite numbers have the same distance to number 0 (look at the picture).

Opposite of -8.3 is -(-8.3) = 8.3

Answer:

1. No

2. The image of ZE is LA, the preimage of point M is point W

Step-by-step explanation:

This transformation maps quadrilateral ZOWE onto quadrilateral LFMA.

1. An isometry is a tansformation that preserves lengths. This transformation is not isometry, because lengths of quadrilatrel LFVA sides are greater than lengths of quadrilateral ZOWE sides.

2. This transformation is a dilation by a factor greater than 1 about some center of dilation. The image of ZE is LA (the image of ZO is LF, of OW - FM, EW - AM). Thus, the preimage of point M is point W.

Answer:

1. NO

2. The image of ZE is LA, the preimage of point M is point W

Step-by-step explanation:

Hello.

The answer is: Bounded.

This is correct because 32 is the endpoint and the real number of Y.

Have a nice day.

Answer:c. bounded,

Step-by-step explanation: got it correct on edge.

Answer: C. 45

Step-by-step explanation:

1. You know that there are 6 tulips for every 9 daisies. Then, if there are 30 tulips, you can write the following expresion, where [tex]x[/tex] is the number of daisies when there are 30 tulips:

[tex]\frac{6}{9}=\frac{30}{x}[/tex]

2. Then, you must solve for x as following:

[tex]6x=30*9\\6x=270\\x=\frac{270}{6}\\x=45[/tex]

3. Therefore, the answer is 45 daisies.

By creating and solving a ratio based on the given relationship of 6 tulips to 9 daisies, it is determined that if there are 30 tulips, there must be 45 daisies in the flower garden. Thus, the correct choice to the student's question is option C) 45 daisies.

To solve this problem, we can set up a ratio based on the information given: there are 6 tulips for every 9 daisies. The ratio of tulips to daisies is therefore 6:9. If there are 30 tulips, this ratio must be multiplied by a certain factor to reach 30. To find this factor, we divide 30 (the actual number of tulips) by 6 (the number of tulips in the ratio), giving us a factor of 5. We then multiply the daisy part of the ratio (9) by 5 to find the actual number of daisies.

6 tulips : 9 daisies = 30 tulips : x daisies
30 / 6 = 5
9 daisies * 5 = 45 daisies

Therefore, if there are 30 tulips in the garden, there are 45 daisies, which corresponds to choice C.

Answer:

Step-by-step explanation:

The table tells you that for every 1 package, you have 16 tortillas. Thus, the function is y = 16x.

y = amount of tortillas and x = number of packages

To find the number of packages for 64 tortillas, divide 64 by 16-- which gives you 4. Instead of "3" packages, change that number to "4".

To find the amount of tortillas in 8 packages, multiply 8 by 16-- which gives you 128 tortillas. Instead of "46", replace that amount with 128.

Divide 144 tortillas by 16, which gives you 9. The answer you gave is correct.

Multiply 10 packages by 16, which gives you 160-- your answer is also correct here.

Answer: Hello mate!

The formula is  [tex]F = G\frac{m1*m2}{r^{2} }[/tex]

and we want to solve it for r, which means that we need to isolate r.

The first step is multiply both sides by r squared:

[tex]r^{2}*F = G*m1*m2[/tex]

now we divide both sides by F

[tex]r^{2} =G\frac{m1*m2}{F}[/tex]

now we aply square root in both sides:

[tex]\sqrt{ r^{2} } = r = \sqrt{G\frac{m1*m2}{F} }[/tex]

And now you have r isolated.

Then the right answer is option C.

Hi there! :)

Answer:

4/7 times 35, minus 8.5 is no more than 11.5

The number is : 35

Step-by-step explanation:

Let's replace "a number" by the letter "x" because that's what we are looking for.

4/7 × x = 4/7x

4/7x MINUS 8.5 = 4/7x - 8.5

The expression "no more than" is represented by this sign: ≤

"No more than" can also be "less than or equal to".

The final inequality should look like this:

4/7x - 8.5 ≤ 11.5

Now all you need to do is solve the inequality by isolating "x":

4/7x - 8.5 ≤ 11.5

Add 8.5 to each side of the inequality → 11.5 + 8.5 = 20

4/7x ≤ 20

Divide each side of the inequality by "4/7" → 20 ÷ 4/7 = 35

x ≤ 35

There you go! I really hope this helped if there's anything just let me know! :)

Answer:

D. 343 Hope this helps! ;)

Step-by-step explanation:

7^3=343

7*7=49

49*7=343

Hi there!

Answer:

D. 343

*The answer must have a positive sign.*

Step-by-step explanation:

It stands for:

Parenthesis

Exponents

Multiply

Divide

Add

Subtract

Left too right

First, you do exponent.

[tex]7^3=7*7*7=343[/tex]

[tex]7*7=49[/tex]

[tex]49*7=343[/tex]

Final answer is 343

I hope this helps you!

Thanks!

-Charlie

Have a nice day! :)

:D

Answer:

156.86

Step-by-step explanation:

We start by dividing 136.40 by 100 so we can figure how much 1 percent,(1.364) once we have that we multiply by 15 (20.46), we add that to the total

Answer:

Total bill including the tip = $156.86  .

Step-by-step explanation:

Given:Bill at a restaurant came to $136.40 the patrons decide to leave a 15% tip .

To find:  What is the total bill including the tip.

Solution: we have given that

A restaurant bill came = $136.40 .

Tip percentage = 15% of bill

Tip cost = 15% of $136.40 .

Tip cost = $20.46 .

So, total bill including the tip = $136.40 + tip cost

                                                 = $136.40 + $20.46

                                                  = $156.86 .

Therefore , Total bill including the tip = $156.86  .

Answer:

Is there a picture?

Answer:

1.  A = 59

2.  A = 43

Step-by-step explanation:

If we have a right triangle  we can use sin, cos and tan.

sin = opp/ hypotenuse

cos= adjacent/ hypotenuse

tan = opposite/ adjacent

For the first problem, we know the opposite and adjacent sides to angle A

tan A = opposite/ adjacent

tan A = 8.8 / 5.2

Take the inverse of each side

tan ^-1 tan A = tan ^-1 (8.8/5.2)

A = 59.42077313

To the nearest degree

A = 59 degrees

For the second problem, we know the  adjacent side and the hypotenuse to angle A

cos A = adjacent/hypotenuse

cos A = 15.3/21

Take the inverse of each side

cos ^-1 cos A = cos ^-1 (15.3/21)

A = 43.23323481

To the nearest degree

A = 43 degrees

|a| = a for a ≥ 0

|a| = -a for a < 0

|x| = 74 ⇒ x = 74 or x = -74

check:

|-74|=-(-74) = 74

|74| = 74

CORRECT

Dividing the weight of the radioactive isotope from 4 halves that is 16, the left weight of the radioactive isotope after 4 half-lives is

⇒ 10.3 grams

Given that,

The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass.

Here, Starting weight of the radioactive isotope is, 165 grams

Hence, the left weight of the radioactive isotope after 4 half-lives is,

⇒[tex]\frac{165}{(2\times2\times2\times2) }[/tex]

⇒ [tex]\frac{165}{(16) }[/tex]

⇒ 10.3 grams

To learn more about the divide visit:

https://brainly.com/question/28119824

$SPJ4

only know number 1 sorryyyy

1 . 11^2⋅√58

Answer:

1. [tex]18 \cdot \sqrt{638}[/tex]

2. [tex]\frac{y^{3}}{2 x^4}[/tex]

3. [tex]\frac{2 x^2}{3 y z^{−7}} [/tex]

Step-by-step explanation:

1. Assuming the expression is:

[tex]3 \cdot \sqrt{22} \cdot \sqrt{58} \cdot \sqrt{18}[/tex]

Express the radicands as multiplication of prime numbers:

[tex]3 \cdot \sqrt{11 \cdot 2} \cdot \sqrt{2 \cdot 29} \cdot \sqrt{3^2 \cdot 2}[/tex]

Distribute the radicals over the multiplication where a power is present:

[tex]3 \cdot \sqrt{11 \cdot 2} \cdot \sqrt{2 \cdot 29} \cdot \sqrt{3^2} \cdot \sqrt{2}[/tex]

[tex]3 \cdot \sqrt{11 \cdot 2} \cdot \sqrt{2 \cdot 29} \cdot 3 \cdot \sqrt{2}[/tex]

[tex]9 \cdot \sqrt{11 \cdot 2} \cdot \sqrt{2 \cdot 29} \cdot \sqrt{2}[/tex]

Apply the inverse of distributive property of radicals over multiplication:

[tex]9 \cdot \sqrt{11 \cdot 2 \cdot 2 \cdot 29\cdot 2}[/tex]

[tex]9 \cdot \sqrt{11 \cdot 2^2 \cdot 29\cdot 2}[/tex]

[tex]9 \cdot \sqrt{11 \cdot 29\cdot 2} \cdot \sqrt{2^2} [/tex]

[tex]9 \cdot \sqrt{638} \cdot 2 [/tex]

[tex]18 \cdot \sqrt{638}[/tex]

2. Assuming the expression is:

[tex](2 x^4 y^{-3})^{-1}[/tex]

Distribute the exponent over the multiplication

[tex]2^{-1} \cdot {(x^4)}^{-1} \cdot {(y^{-3})}^{-1}[/tex]

[tex]\frac{1}{2} \cdot x^{-4} \cdot y^{3}[/tex]

[tex]\frac{1}{2} \cdot \frac{1}{x^4} \cdot y^{3}[/tex]

[tex]\frac{y^{3}}{2 x^4}[/tex]

3. Assuming the expression is:

[tex]\frac{2 x^4y^{-4}z^{-3}}{3 x^2 y^{-3} z^4}[/tex]

Group by similar terms and simplify:

[tex]\frac{2}{3} \cdot \frac{x^4}{x^2} \cdot \frac{y^{-4}}{y^{-3}} \cdot \frac{z^{-3}}{z^4}[/tex]

[tex]\frac{2}{3} \cdot x^2 \cdot y^{-1} \cdot z^{-7}[/tex]

[tex]\frac{2 x^2}{3 y z^{-7}} [/tex]

Answer:

G(-1, 3)

Step-by-step explanation:

You need to try each point in the given equation to see which one does not work.

The definition of the function is that it has two different expressions. The upper expression is used for values of x that are less than or equal to -1.

For values of x less than or equal to -1, the expression is f(x) = 2x + 3.

Look at point F. Its x-coordinate is -1.5. Since -1.5 is less than or equal to -1, use the upper expression. Plug in -1.5 for x and find f(-1.5).

f(x) = 2x + 3

f(-1.5) = 2(-1.5) + 3 = -3 + 3 = 0

That gives point (-1.5, 0), so point F is on the graph of f(x).

Now let's look at point G(-1, 3). For point G, x is -1. Since -1 is also less than or equal to -1, you still use the upper expression for x = -1.

f(x) = 2x + 3

f(-1) = 2(-1) + 3 = -2 + 3 = 1

The point that contains x-coordinate -1 is point (-1, 1). Point G is (-1, 3), so point G is not on the graph of function f.

You already know the answer is point G, but let's continue to show how the other two points are part of the graph of the function.

Point H is (0, 4). For this point, the x-coordinate is 0. The lower expression is used for x greater than -1, and 0 is greater than -1, so you must use the second expression. Now we evaluate the function at x = 0 using the second expression.

f(x) = 4 + x

f(0) = 4 + 0 = 4

giving us point (0, 4).

Point H is (0, 4), so point H is on the graph of the function.

Now we do point J(4, 8). Like for point H, the x-coordinate of point H is greater than -1, so you use the second expression.

f(x) = 4 + x

f(4) = 4 + 4 = 8

giving point (4, 8).

Point J is (4, 8), so it is on the graph.

The only point not on the graph is point G.

Answer: G(-1, 3)

Answer:CD

Step-by-step explanation:

There is a line from A-B and the fastest way to get there is to go "down" c

Answer: The answer is (A) CD.

Step-by-step explanation: We are given to choose the correct option that represents the distance from point D to AB.

We know that the distance between a point and a line is the length of the perpendicular drawn from the point to the line.

So, here CD will be the required distance from point D to AB, because CD is perpendicular from point D to AB.

Thus, (A) is the correct option.

Answer:

55%

Step-by-step explanation:

Create an equation.

p = votes received / total members

Solve

p = 33 / 60

p = .55

Multiply

Multiply the decimal by 100 to convert the decimal into a whole number.

.55 * 100 = 55

Answer

55 percent of the club members voted for Isabel.

Answer:

55% is your answer

Step-by-step explanation:

Isabel received 33 of 60 votes.

Divide 33 with 60: 33/60 = 0.55

Move the decimal point to the right two place value and attach the percent sign to get the percentage.

0.55 = 55%

55% is your answer

~

to find the slope for the first one, use the formula [tex]\frac{y2-y1}{x2-x1}[/tex]

(It's the slope formula)

so... [tex]3=y2, 3=y1, 2=x2, 10=x1[/tex]

then plug in... [tex]\frac{3-3}{2-10} =\frac{0}{-8} = 0[/tex]

this line has a slope of 0

As for the miles problem, to find mph, the miles have to be at 1.

so... [tex]4x=242\\x=60.5[/tex]

therefore, he drove 60.5 mph

Just to clarify, here are the answer choices:

A. {(–3,–17), (4,11), (7,19)}

B. {(3,22), (2,3), (8,27)}

C. {(4,29), (–6,–58), (7,19)}

D. {(–2,–18), (4,37), (5,15)}

And all of the points in the set must satisfy y ≤ 8x – 3.

The only way is to go through each answer choice, eliminating each that is wrong.

A) -17 ≤ -3*8-3

-17 ≤ -21 ✘

B) 22 ≤ 3*8-3

22 ≤ 21 ✘

C) a) 29 ≤ 8*4-3

29≤29 ✔

   b) -58 ≤ 8*(-6)-3

-58 ≤ -49 ✔

   c) 19 ≤ 7*8-3

19 ≤ 53  ✔

It becomes clear that the answer is C. But just to make sure, we must check D to make sure C is really the answer.

D) -18 ≤ 8(-2)-3

-18 ≤ -19 ✘

That means that C is the answer.

Final answer:

After evaluating each set of points for the inequality y ≤ 8x – 3, it is found that set C satisfies the inequality for all its points, making it the correct set of points containing the solutions to the inequality.

Explanation:

The student's question is related to solving a linear inequality, specifically finding which set of points satisfies the inequality y ≤ 8x – 3.

To find the correct set of points that contain the solutions to this inequality, we must check each pair of (x, y) coordinates provided in the options. A coordinate pair is a solution to the inequality if substituting the x and y value into the inequality makes it a true statement.

B. {(3,22), (2,3), (8,27)}

C. {(4,29), (–6,–58), (7,19)}

D. {(–2,–18), (4,37), (5,15)}

After checking each set, we can conclude that set C contains all the solutions to the inequality y ≤ 8x – 3.

Answer:

[tex]-2,\ -1,\ -\dfrac{1}{2},\ 3.[/tex]

Step-by-step explanation:

Consider polynomial [tex]2x^4+x^3-14x^2-19x-6.[/tex]

If x=-2 is its zero, then you can divide the polynomial [tex]2x^4+x^3-14x^2-19x-6[/tex] by [tex]x+2[/tex] and get

[tex]2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).[/tex]

If x=-1, then the polynomial [tex]2x^4+x^3-14x^2-19x-6[/tex] can be rewritten as

[tex]2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).[/tex]

The quadratic polynomial has roots

[tex]x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.[/tex]

Then the polynomial [tex]2x^4+x^3-14x^2-19x-6[/tex] has zeros [tex]-2,\ -1,\ -\dfrac{1}{2},\ 3.[/tex]

Answer:

D) |x| = a and |y| = b

Step-by-step explanation:

Given the numbers x = a and y = –b

Absolute function always gives the output as a positive number

Absolute function of |-x|= x

For example |5|= 5  and |-5| = 5

Given x=a

|x| = |a| = a, so |x| = a

Given y=-b

|y| = |-b| = b , so |y| = b

Hence, |x| = a and |y| = b

Answer:

i believe its A because were learning that right now

Step-by-step explanation:

Answer:

[tex]y=cos(x+\pi )[/tex]

Step-by-step explanation:

We are a given a graph from which we can clearly see that y = -1 when x  = 0.

Next, to find out which of the options is the equation of the given graph, we need to set our calculator to the radian mode and then we will put the value of x to be 0.

1. y = cos(x + pi/2) = cos(0 + pi/2) = 0

2. y = cos(x+2pi) = cos(0+2pi) = 1

3. y = cos(x+pi/3) = cos(0+pi/3) = 1/2 = 0.5

4. y = cos(x+pi) = cos(0+pi) = -1

We get y = -1 when x = 0 in equation number 4, y = cos(x+pi) = cos(0+pi) = -1. so that is the equation of the given graph.

Answer:

Step-by-step explanation:

An estimate is usually a guess, but I somehow think that's not what you want.

She starts with 4 2/3 cups of batter. When she divides it into two, one of the batters has 2 1/4 cups. That's the one she puts blueberries in.

The other batter is the one you are interested in. How big is it?

Estimate: One

The estimated size would be 4 2/3 - 2 1/3 = 2 1/3 which is an estimate. It is just taking the closest number to use so you don't have to grab your calculator.

Actual Size: Two

4 2/3 - 2 1/4 is the size of the second batter. Since 2/3 is greater than 1/4 you need only subtract the whole numbers and then the fractions.

Whole number subtraction: 4 - 2 = 2

Fraction subtraction: 2/3 - 1/4

Find the Lowest common multiple between 3 and 4: It is 12. 3 and 4 are prime to each other. They have nothing in common.

So the actual size of the batter containing the walnuts is 2 5/12

[tex]f(x)=25-x^2,\ g(x)=x+5\\\\\dfrac{f(x)}{g(x)}\cdot x=\dfrac{25-x^2}{x+5}\cdot x=\dfrac{x(25-x^2)}{x+5}\\\\\text{Domain:}\ x\neq-5\\\\25-x^2=5^2-x^2=(5-x)(5+x)\\\\\dfrac{f(x)}{g(x)}\cdot x=\dfrac{x(5-x)(5+x)}{x+5}=x(5-x)=5x-x^2\to\text{simplified form}[/tex]

Answer: Approximately 3.42857142857142 inches

Round this value however you need to. For instance, if you need to round to 2 decimal places, then the answer would be 3.43 inches.

====================================================

How I got this answer:

A square has side lengths that are the same value and it has four right angles. For example, a square could have all four sides equal to 7 inches. We want this square to fit snugly inside a right triangle. Put another way, we want this square as big as possible without it overflowing outside the triangle.

If one vertex of the square is at (0,0) then the opposite vertex will be on the line y = x meaning this opposite vertex's location is (x,x). The x refers to the side length of the square. Replace x with any number. Going back to the previous example, if x = 7 then the square has two opposite vertices at (0,0) and (x,x) = (7,7), so this square has side length of 7. We will use the equation y = x later on (see figure 2 in the attached images below). I marked (0,0) as point A and (x,x) as point D in figure 3.

We will also use the equation of the line that goes through the two points B(0,6) and C(8,0) as shown in figure 3. The line that goes through points B and C is the line that forms the hypotenuse of the right triangle. If we can find the equation of this line, then we can use algebra to find the intersection point D (see figure 3)

It turns out that the equation of the line through B and C is y = (-3/4)x + 6. Check out figure 1 in the attached images below to see how I got that.

Then head over to figure 2 to see how I'm using the two equations to solve for x. The exact solution is the fraction x = 24/7 which approximates to x = 3.42857142857142 and you can round this however you want for the final answer.

The side length of the square inscribed in the right triangle with legs 6 inches and 8 inches is  [tex]\(\frac{24}{7}\)[/tex] inches.

Let's denote the side length of the square as ( s ). Since the square is inscribed in the right triangle with a common right angle, the triangle can be split into two smaller right triangles and a rectangle.

Consider the right triangle with legs of lengths 6 inches and 8 inches. When a square is inscribed in such a triangle, the side of the square, ( s ), will align with one leg and the other leg, forming two smaller right triangles and a rectangle.

We can solve this problem by using the properties of similar triangles. Let’s break down the larger right triangle into the smaller components formed when the square is inscribed.

Step-by-Step Solution:

1. Draw the square inscribed in the right triangle. Denote the point where the side ( s ) of the square touches the leg of length 6 inches as point ( A ), and the point where it touches the leg of length 8 inches as point ( B).

2. Let the triangle's right angle be at point ( C ). Place the square such that one vertex coincides with point ( C). Let the opposite vertex of the square that lies on the hypotenuse be point ( D).

3. The length of the segment along the 6-inch leg outside the square is ( 6 - s ). Similarly, the length of the segment along the 8-inch leg outside the square is ( 8 - s ).

Using Similar Triangles:

The smaller triangles formed by the inscribed square and the segments  [tex]\( 6 - s \) and \( 8 - s \)[/tex] are similar to the original right triangle (by AA similarity).

The ratio of the sides of these similar triangles remains the same:

[tex]\[\frac{s}{6 - s} = \frac{8}{6}\][/tex]

Now solve for  [tex]\( s \):[/tex]

[tex]\[\frac{s}{6 - s} = \frac{4}{3}\][/tex]

Cross-multiplying gives:

[tex]\[3s = 4(6 - s)\]\[3s = 24 - 4s\]\[3s + 4s = 24\]\[7s = 24\]\[s = \frac{24}{7}\][/tex]

So, the side length of the square is:

[tex]\[s = \frac{24}{7} \approx 3.43 \text{ inches}\][/tex]

Thus, the length of the side of the square inscribed in the right triangle with legs 6 inches and 8 inches is  [tex]\( \boxed{\frac{24}{7}} \)[/tex]  or approximately 3.43 inches.