Answer:
60.1 kJ
Explanation:
Enthalpy change ΔH = m x Δt x cρ
Given that:
100 grams water = 5.56 moles water
The enthalpy change needed to raise 100 g water from 50°C to 0°C is calculated as :
ΔH = 100g x ( 0-50) x 4.18J/gC = -2.09 X 10⁴ Joules
The Freezing water
ΔH = ΔH fusion * mol
ΔH fus for water is = 6.01 kJ/mol
ΔH = 6.01 kJ/mol × 5.56 moles = -33.4 kJ (since heat is released when water freezes)
Finally, The enthalpy Change during the process pf changing the ice from 0°C to -30.0°C is:
ΔH = m x Δt x cp
= 0.100 kg × (-30 -0)°C × 2.00 × 10³ J/kgC
= - 6 × 10³ J
Total heat lost = -2.09 × 10⁴ J + (-33.4 × 10³ J) + (-6 × 10^3J)
= - 6.01 × 10⁴ J
= 60.1 kJ
The enthalpy change during the process in which 100.0 g of water at 50.0 °C is cooled to ice at -30.0 °C is -60.570 kJ, involving three energy changes: cooling water from 50°C to 0°C, transition from water to ice, and cooling from 0°C to -30°C.
Explanation:The calculation of the enthalpy change in converting 100.0 g water at 50.0 °C to ice at -30.0 °C involves calculating energy changes at different stages: cooling water from 50°C to 0°C, changing water at 0°C to ice at 0°C (enthalpy of fusion), and cooling ice from 0°C to -30°C. Below is step be step calculation.
Cooling of water: Using the formula Q = m * C * ΔT (where Q is energy, m is mass, C is specific heat, and ΔT is temperature change), we calculate: Q1 = 100.0 g * 4.18 J/(g*K) * -50.0 K = -20900 J. Water to ice: Enthalpy of fusion for water is 334 J/g, so Q2 = 100.0 g * -334 J/g = -33400 J. Cooling of ice: The specific heat of ice is 2.09 J/(g*K), Q3 = 100.0 g * 2.09 J/(g*K) * -30.0 K = -6270 J.
The total enthalpy change is therefore Q total = Q1 + Q2 + Q3 = -20900 J - 33400 J - 6270 J = -60570 J, or -60.570 kJ.
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how is the periodic table of the elements arranged
a) alphabetically
b)in a neat grid with 11 rows and 10 columns
c) by aligning groups with common properties
d) in a neat grid with 10 rows and 11 columns
Answer:
I am pretty sure the answer is c)
Explanation:
Alkali Metals, Alkaline Earth Metals, Transition Metals, Metalloids or Semimetals, Nonmetals, Halogens, and Noble Gases are the groups.
HOPE I HELPED :)
Final answer:
The periodic table is arranged by aligning groups with common properties, based on atomic number, into periods and groups. Elements in the same group share similar chemical properties, aiding in the study of chemical behavior.
Explanation:
The question asks how the periodic table of the elements is arranged. The correct answer is that the elements in the periodic table are arranged by aligning groups with common properties. In more detail, the periodic table is organized based on the atomic number of elements, and they are placed in a layout where they form rows called periods and columns known as groups. These groups are numbered 1-18, and elements within the same group share many chemical properties. This organization allows for the grouping of elements with similar properties and helps in the study of their chemical behavior.
For instance, the alignment is such that the elements are ordered in terms of increasing atomic number from left to right across the table. This arrangement makes it easy for us to identify elements with similar properties because they are positioned in the same column. The periodic table includes seven horizontal rows (periods) and 18 vertical columns (groups), making it a powerful tool for understanding chemical reactions and properties of elements. This systematic arrangement reflects the periodic law, which states that the properties of elements are periodic functions of their atomic numbers.
Draw the products of the acid-base reaction between stearic acid and OH-
Answer:
Products are stearate anion and water.
Explanation:
Stearic acid is a 18-carbon chain molecule containing -COOH group. IUPAC name of stearic acid is octadecanoic acid.
Molecular formula of stearic acid is [tex]C_{17}H_{35}CO_{2}H[/tex].
When [tex]OH^{-}[/tex] is added into stearic acid, [tex]OH^{-}[/tex] removes a proton ([tex]H^{+}[/tex]) from acidic -COOH group and forms stearate anion and water as products.
The balanced acid-base reaction is given as:
[tex]C_{17}H_{35}CO_{2}H+OH^{-}\rightleftharpoons C_{17}H_{35}CO_{2}^{-}+H_{2}O[/tex]
Structure of products are given below.
How many joules of heat are lost by 1000g of granite as it cools from 41.2 Celsius to -12.9 Celsius?
Answer: The amount of heat released is 42739 Joules
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat released =?
c = heat capacity of granite = [tex]0.790J/g^0C[/tex]
Initial temperature = [tex]T_i[/tex] = [tex]41.2^0C[/tex]
Final temperature of the calorimeter = [tex]T_f[/tex] = [tex]-12.9^0C[/tex]
Change in temperature ,[tex]\Delta T=T_f-T_i=(-12.9-41.2)^0C=-54.1^0C[/tex]
Putting in the values, we get:
[tex]Q=1000g\times 0.790J/g^0C\times -54.1^0C=-42739J[/tex]
As heat comes out to be negative, that means the heat has been released and the amount of heat released is 42739 Joules
Placing a slightly soluble ionic solid in a solution containing common ions will Select the correct answer below:
increase the molar solubility of the solid relative to its molar solubility in pure water.
decrease the molar solubility of the solid relative to its molar solubility in pure water.
have no effect on the molar solubility of the solid.
depends on the solid
Answer:
decrease the molar solubility of the solid relative to its molar solubility in pure water.
Explanation:
The common ion effect is defined as a decrease in the solubility of a solute because of the addition of a second solute with which it has a common ion. If a solution already contains a solute MX and another ionic solid containing BX is added to the solution, the X^- anion is common to the both species. Hence the presence of MX will decrease the solubility of BX compared to the solubility of BX in pure water.
Generally, when a soluble ionic solid is placed in a solution containing a common ion, the molar solubility of the solid decreases compared to its molar solubility in pure water.
Compare and contrast the causes and effects of ocean-continent
and ocean-ocean convergent plate boundaries.
EXTRA HELP
How are the causes of ocean-continent and ocean-ocean convergent
plate boundaries similar?
How are the causes of ocean-continent and ocean-ocean convergent
plate boundaries different?
How are the effects of ocean-continent and ocean-ocean convergent
plate boundaries similar?
How are the effects of ocean-continent and ocean-ocean convergent
plate boundaries different?
Answer:seen below
Explanation:
The effects of an ocean-ocean subduction zone are the same as those of an ocean-continent subduction zone in that, the subduction zone where an oceanic plate subducts beneath another oceanic plate are the same as a continent-ocean subduction zone.
They oceanic plate and the continental plate are both convergent zones, but when an oceanic plate converges with a continental plate, the oceanic plate is forced underneath the continental plate this is because oceanic crust is thinner and denser than the continental crust. The difference is that the volcanic arc formed will be a set of islands known as an island arc.
If two plates meet at a convergent plate boundary both are of oceanic crust, the older, denser plate will subduct beneath the less dense plate into a trench, resulting in earthquakes.
Finally, When two continents meet head-on, neither is subducted under, this is because the continental rocks are relatively light and are like two colliding icebergs they resist downward motion. Instead, the crust tends to buckle and be pushed upward or sideways.
The driving forces behind ocean-continent and ocean-ocean convergent plate boundaries are similar, involving the movement of lithospheric plates due to mantle convection, the specific outcomes of these collisions differ based on the types of plates involved.
The causes of ocean-continent and ocean-ocean convergent plate boundaries are similar in that both are driven by the movement of lithospheric plates due to the convection currents in the asthenosphere. The differences in their causes lie in the density and composition of the colliding plates. Ocean-continent convergence occurs when a dense oceanic plate collides with a less dense continental plate, while ocean-ocean convergence involves the collision of two oceanic plates.
The effects of both types of convergent boundaries include the formation of mountains or island arcs, earthquakes, and volcanic activity. However, the specific effects differ due to the nature of the colliding plates. Ocean-continent convergence typically results in the subduction of the oceanic plate under the continental plate, leading to the formation of mountain ranges like the Andes and volcanic activity such as the Cascade Range. In contrast, ocean-ocean convergence leads to the creation of island arcs like the Aleutian Islands and deep ocean trenches such as the Mariana Trench. Additionally, the volcanic activity at ocean-ocean convergent boundaries tends to produce less explosive eruptions compared to the more explosive eruptions that can occur at ocean-continent boundaries.
Convergent plate boundaries are areas where two or more tectonic plates collide. The movement of these plates is driven by convection currents in the Earth's mantle, specifically the asthenosphere, which is a more ductile layer beneath the lithosphere. These currents cause the overlying lithospheric plates to move, and when this movement is convergent, it leads to collision.
In the case of ocean-continent convergence, the denser oceanic plate is forced beneath the less dense continental plate in a process known as subduction. This subduction can cause melting of the subducting plate, leading to the formation of magma that rises through the continental crust, resulting in volcanic activity. The collision also causes the continental crust to crumple and fold, creating mountain ranges.
Ocean-ocean convergence, on the other hand, involves two oceanic plates. When these plates collide, one plate is typically subducted under the other due to the higher density of the oceanic crust compared to the mantle below. This subduction also leads to volcanic activity, but because the volcanoes form in the ocean, they often create island arcs. The subduction of one oceanic plate beneath another also results in the formation of deep ocean trenches.
The similarities in effects between the two types of convergent boundaries include the creation of topographic highs (mountains or island arcs), seismic activity due to the release of energy as the plates move and collide, and volcanic activity from the melting of the subducting plate.
The differences in effects are primarily due to the different densities and compositions of the colliding plates. Ocean-continent convergence can lead to more dramatic mountain building and more explosive volcanic eruptions because of the interaction between the dense oceanic crust and the less dense continental crust. In contrast, ocean-ocean convergence tends to produce less explosive volcanic eruptions and the creation of island arcs and ocean trenches rather than large mountain ranges on continents.
4. If an experimental value for a given observation was 415 nm while the theoretical value
was 435.8 nm, what is the percent error of the observation?
Answer: % error of observation is 4.77%
Explanation:
Given:
Observation value = 415nm
theoretical value= 435.8nm
Percent error of observation = theoretical value- observation value/ theoretical value x 100 %
= 435.8-415/435.8= 0.04772 x 100 = 4.77%
therefore % error of observation is 4.77%
Pyridine, C5H5N, is a commonly used reagent in the lab. It is a highly flammable, weakly basic, water-miscible liquid with a distinctive, unpleasant fish-like smell. Suppose now in a buffer solution, the concentration of [C5H5N] is 0.01 M and the concentration of [C5H6N+] (the conjugate acid) is 0.02M. What pH is the buffer? (Given that the Kb for C5H5N is 1.8 x 10−9 )
Answer:
5.0
Explanation:
We have a buffer system formed by a weak base (C₅H₅N) and its conjugate acid (C₅H₆N⁺). We can calculate the pOH using the Henderson-Hasselbach's equation.
pOH = pKb + log [acid]/[base]
pOH = -log 1.8 × 10⁻⁹ + log 0.02/0.01
pOH = 9.0
Then, we will calculate the pH.
pH + pOH = 14
pH = 14 - pOH = 14 - 9.0 = 5.0
Which phrases identify the names of the main wind belts? Check all that apply.
polar easterlies
polar westerlies
prevailing westerlies
tropical easterlies
trade breezes
Answer:
polar easterliesprevailing westerliestropical easterliesExplanation:
Global winds are the winds that occur in the belts that are found all over the planet. Like local winds, global winds are caused by differences in heat in the atmosphere.
Polar Easterlies, from 60-90 degrees latitude.
Prevailing Westerlies, from 30-60 degrees latitude.
Tropical Easterlies, from 0-30 degrees latitude.
Answer:
A,C,D
Explanation:
I was very confused because I wasn't sure for this question so i went on brainly to find a answer and all of them said A,B,C and i was confused cause that was not right low and behold i put in this as a geuss and it was right hope this helped anyone wondering!! but correct answer is A,C,D
The flavor of beer can be tainted by a trace contaminant, called ortho-bromophenol. To reduce the incidents of contamination, beer manufacturers have used certified beer flavor standards to train professional beer tasters to recognize the flavor of ortho-bromophenol. Preparing these certified standards requires pure samples of ortho-bromophenol. Propose a synthesis of ortho-bromophenol starting from phenol. (Org. Synth. 1934, 14, 14.)
Choose from the reagents below.
A. dilute NaOH
B. conc. fuming, 1 mol H2SO4
C. HBr
D. Br2, FeBr3
E. Zn
F. Dilute H2SO4
G. HNO3
H. Hcl
I. Br2
Answer:
conc. fuming, 1 mol H2SO4
Dilute NaOH
Br2
Dilute H2SO4
Explanation:
The synthesis of ortho-bromophenol follows the reaction sequence shown in the image attached.
First of all, the phenol is sulphonated using concentrated sulphuric acid at 100°C. Carrying out the reaction at 100°C ensures that the para-isomer predominates. Lower temperatures favour the formation of the ortho isomer. Dilute sodium hydroxide is added before the addition of bromine.
Bromine molecule is then added. The incoming electrophile now attaches to the ortho position. Dilute acid is added at 100°C to remove the -SO3H thereby obtaining the Ortho-bromophenol
Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
The Earth's biosphere is consists of
Answer:
The Earth's bioshere consist of the parts of Earth where life exists. Ecosystems.
Explanation:
What the first song come to your mind?
Answer: Hey Brother by Avicii
How much heat should be transferred when 20.1 g of hydrogen bromide is formed during the reaction of hydrogen gas with liquid bromine?
Answer:
9.1 KJ
Explanation:
We must first put down the reaction equation;
H2(g) + Br2(g) ----> 2HBr(g)
Secondly we find the number of moles of HBr involved;
number of moles of HBr= mass of HBr/ molar mass of HBr
But molar mass of HBr= 80.91 g/mol
Given mass of HBr as given in the question= 20.1g
Hence;
Number of moles of HBr= 20.1 g/80.91g
Number of moles of HBr= 0.25 moles of HBr
Lastly we calculate the heat transferred from the number of moles involved;
If 2 moles of HBr has a heat of formation of 72.80KJ
Then 0.25 moles of HBr will have a heat of formation of 0.25× 72.80/2= 9.1 KJ
Then; 20.1 g of HBr will have a heat of formation of 9.1 KJ
Is HSO4 polar or no polar
Answer:
It is polar
Explanation:
Hydrogensulfate is an oxoanion of sulphur , conjugate base of a sulfuric acid and conjugate acid of a sulfate
Please see the structure of HSO4 in the attached image
Polar molecules have electronegativity difference between the bonded atoms.
In case of Hydrogensulfate, hydrogen is positive while sulfate is negative ion.
Electronegativity of hydrogen is 2.2 while that of sulfur and oxygen is 2.58 and 3.44 respectively
Thus, it is a polar molecule.
Which of the following would you expect to be elastomers and which thermosetting polymers at room temperature? (a) Linear and highly crystalline polyethylene (b) Phenol-formaldehyde (c) Heavily crosslinked polyisoprene having a glass-transition temperature of 50oC (122oF) (d) Lightly crosslinked polyisoprene having a glass-transition temperature of -60oC (-76oF) (e) Linear and partially amorphous poly(vinyl chloride)
Answer: Please see below for answer
Explanation:A thermosetting polymer is a polymer that consists a of cross-linked structure or heavily network of branched molecules.
Elastomers are loosely cross-linked polymers which are highly flexible and elastic which can make them stretch easily and return to thier original shapes.
a) Linear and highly crystalline polyethylene is a linear thermoplastic it will not be an elastomer or themoset.
.
(b) Phenol-formaldehyde is anetwork structured thermosetting resin which is regarded as the most useful thermosetting resin especially in the production of wood based panels.
(c) Heavily crosslinked polyisoprene having a glass-transition temperature of 50 deg C is a thermoset since it is heavily cross linked above room temperature.
(d) Lightly crosslinked polyisoprene having a glass-transition temperature of -60 deg C is both an elastomer and thermoset since it has both characteristics .
(e) Linear and partially amorphous poly (vinyl chloride) is a thermoplastic and not an elastomer or a thermoset.
In polymers the crystalline order is often set up by a regular arrangement of the chains. Therefore what you would expect to be elastomers and which thermosetting polymers at room temperature are;
a. Linear and crystalline polyethylene would be neither an elastomer nor a thermoset because it is a linear polymer.
b. Phenol-formaldehyde is said too have a network structure called thermosetting polymer because it has a network structure. It would therefore not be an elastomer as it does not have a crosslinked chain structure.
c. Heavily crosslinked polyisoprene having a glass transition temperature of 50°C can be a said to be a thermosetting polymer due to the fact that it is heavily crosslinked. It cannot not be an elastomer because it is heavily crosslinked and room temperature is below its Tg.
d. Linear and partially amorphous poly(vinyl chloride) is said to be neither an elastomer nor a thermoset. If it want to be any of thee both, it must have some crosslinking.
Polymers is said to be crystallized from a solution or upon evaporation of a solvent but it based on the degree of dilution.
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The heart is an example of which level of organization within an organism?
O
cell
organ
tissue
organ system
O
O
why earth not flat and why we live in this country not yours
Answer:
Earth is not flat because the spheroidical shape provides a more effective shape in terms of exposed surface area for absorbing and radiating radiation, and also for a relatively more uniform gravity pull on different points on its surface which might not be so for a flat surface.
You live in your country, not mine because you have evolved over time to be more adapted to living in your own kind of envoirment. Members of a certain species (like you and me as humans) have been spread to maximize the survivability of their species compared to if they were clustered to a particular place.
The pKa of propanoic acid (propionic acid), CH3CH2COOH, is 4.87. Consider an equilibrium mixture of propanoic acid and its conjugate base with a pH of 4.87. Draw the structure of the form (acid or conjugate base) that predominates after a decrease in [H3O ]. Include all hydrogen atoms and any appropriate formal charges.
Answer:
Explanation:
check below for explicit explanation.
When the number of hydronium ions decreases in a solution containing propanoic acid and its conjugate base, the solution shifts towards the acidic side. Therefore, the structure that would predominate in this circumstance is the acidic form, that is, propanoic acid itself.
Explanation:The equilibrium pH of a solution is equal to the pKa of the acid when the concentrations of the acid and its conjugate base are equal. In this case, where the propanoic acid has a pKa of 4.87 and the pH of the mixture is also 4.87, we have an equal concentration of the acid and its conjugate base. When a decrease in [H₃O⁺] occurs, the equilibrium of the solution shifts to compensate, and shifts towards the acidic side because the concentration of [H₃O⁺] (hydronium ions) has decreased. This means that the form of the propanoic acid that would predominate after a decrease in [H₃O⁺], would be the acidic form. Therefore, the structure that predominates is that of propanoic acid, CH₃CH₂COOH, not its conjugate base.
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What type of decay occurs during the fission of 240pu? 240 94 Pu 236 92 U+\ \ Select one Y, B-, A, or B +
Answer:
Alpha decay
Explanation:
Observing the question given, we discovered that the mass number of 240 94 Pu reduced by 4 and the atomic number reduce by 2 in the product obtained from the reaction. This clearly indicates that 240 94 Pu is undergoing alpha decay because atoms that ungoes alpha decay has a decrease of 4 in the mass number and a decrease 2 in the atomic number.
The attached photo gives further explanation...
How are transition metals named in metal compounds?
Answer:
Explanation:em metais alcalinos, acho
Answer:
A roman numeral in parentheses follows the name of the metal.
Explanation:
Ammonia gas combines with excess oxygen gas to produce nitric oxide and water. How many grams of ammonia gas would have to react in order to release 154 kJ of energy
Answer:
11.6g of NH₃(g) have to react
Explanation:
For the reaction:
4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g) ΔH = -905kJ
4 moles of ammonia produce 905kJ
Thus, if you want to produce 154kJ of energy you need:
154kJ × (4 mol NH₃ / 905kJ) = 0.681moles of NH₃. In mass -Molar mass ammonia is 17.031g/mol-
0.681mol NH₃ × (17.031g / mol) = 11.6g of NH₃(g) have to react
under a pressure of 1.0 atm , a confined gas has a volume of 750mL. at constant temperature, the pressure is increased until the gas has a volume of 610 mL. what is the new pressure
Using Boyle's Law which states that P1V1 = P2V2 for a gas at constant temperature, and given the initial conditions of 1.0 atm and 750 mL, when the volume decreases to 610 mL, the new pressure is calculated to be 1.23 atm.
Explanation:The question relates to the behavior of gases under different pressures and volumes, which is generally described by Boyle's Law. Boyle's Law states that for a given mass of gas at constant temperature, the volume of the gas varies inversely with the pressure. We use the formula P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.
Given that the initial pressure (P1) is 1.0 atm and the initial volume (V1) is 750 mL, and the final volume (V2) is 610 mL, we want to find the new pressure (P2). Rearranging the formula to solve for P2 gives us P2 = P1V1/V2. Substituting our known values in we get:
P2 = (1.0 atm * 750 mL) / 610 mL = 1.23 atm (rounded to two decimal places).
Therefore, the new pressure when the volume is decreased to 610 mL while maintaining a constant temperature is 1.23 atm.
HELP MY TEST IS TIMED: A sample of methane gas is 22.8 L at 313 Kelvin and 4.00 atm. What will its pressure be at 341 K and constant volume?
3.7 atm
4.4 atm
2.4 atm
.15 atm
Answer:
option B.
Explanation:
Given,
Volume,V₁ = 22.8 L
T₁ = 313 K
P₁ = 4 atm
T₂ = 341 K
P₂ = ?
Volume is constant.
Using ideal gas law
[tex]\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]
[tex]\dfrac{4}{313}=\dfrac{P_2}{341}[/tex]
[tex]P_2 = \dfrac{4}{313}\times 341[/tex]
[tex]P_ 2 = 4.36\ atm[/tex]
Pressure of the tank is equal to 4.36 atm.
Hence, the correct answer is option B.
The lead-containing reactant(s) consumed during recharging of a lead-acid battery is/are ________. The lead-containing reactant(s) consumed during recharging of a lead-acid battery is/are ________. PbSO4 (s) only Pb (s) only PbO2 (s) only both PbO2 (s) and PbSO4 (s) both Pb (s) and PbO2 (s)
Answer:
PbSO4 (s) only
Explanation:
Determine the electron geometry (eg), molecular geometry (mg), and polarity of SO2. Determine the electron geometry (eg), molecular geometry (mg), and polarity of SO2. eg=trigonal planar, mg=bent, polar eg=tetrahedral, mg=bent, polar eg=linear, mg=linear, nonpolar eg=trigonal pyramidal, mg=trigonal pyramidal, polar eg=tetrahedral, mg=tetrahedral, nonpolar
Answer:
See explaination
Explanation:
The electrons geometry shows the special distribution of the electrons around of the central atom of the molecule.
The molecular geometry shows the special distribution of the atoms that form the molecule.
Please kindly check attachment for further solution.
For the reaction: N2(g) + 2 O2(g) ⇌ 2 NO2(g), Kc = 8.3 × 10-10 at 25°C. What is the concentration of N2 gas at equilibrium when the concentration of NO2 is twice the concentration of O2 gas? For the reaction: N2(g) + 2 O2(g) ⇌ 2 NO2(g), Kc = 8.3 × 10-10 at 25°C. What is the concentration of N2 gas at equilibrium when the concentration of NO2 is twice the concentration of O2 gas? 4.2 × 10-10 M 2.1 × 10-10 M 2.4 × 109 M 4.8 × 109 M 1.7 x 10 -9 M
Answer: Concentration of N₂ is 4.8.[tex]10^{9}[/tex] M.
Explanation: [tex]K_{c}[/tex] is a constant of equilibrium and it is dependent of the concentrations of the reactants and the products of a balanced reaction. For
N2(g) + 2 O2(g) ⇄ 2 NO2(g)
[tex]K_{c}[/tex] = [tex]\frac{[NO2]^{2} }{[N2][O2]^{2} }[/tex]
From the question concentration of NO2 is twice of O2:
[NO2] = 2[O2]
Substituting this into [tex]K_{c}[/tex]:
[tex]K_{c}[/tex] = [tex]\frac{[2O2]^{2} }{[N2][O2]^{2} }[/tex]
8.3.[tex]10^{-10}[/tex] = [tex]\frac{4O2^{2} }{[N2].O2^{2} }[/tex]
[N2] = [tex]\frac{4O2^{2} }{8.3.10^{-10}.O2^{2} }[/tex]
[N2] = [tex]\frac{4}{8.3.10^{-10} }[/tex]
[N2] = 4.8.[tex]10^{9}[/tex]
The concentration of N2 in the equilibrium is [N2] = 4.8.[tex]10^{9}[/tex]M.
The concentration of [tex]N_2[/tex] is [tex]4.8.10^9M[/tex]
Calculation of concentration:Since k_e represent the equilibrium constant and based on the concentrations of the reactants and the products of a balanced reaction.
Also, the reaction: N2(g) + 2 O2(g) ⇌ 2 NO2(g), And, the concentration of NO2 is twice the concentration of O2 gas
Kc = 8.3 × 10-10 at 25°C.
NO2 is twice of O2.
Now
[tex]8.310^{-10} = \frac{4O_2^2}{N_2O_2^2} \\\\N_2 = \frac{4O_2^2}{8.3.10^{-10}O_2^2}\\\\ = 4\div 8.3.10^{-10}\\\\= 4.8.10^9[/tex]
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The electron configurations of two unknown elements are x and y. X: 1s2 2s2 2p6 Y: 1s2 2s2 2p6 3s2 3p5 which statement is most likely correct about the two elements
Answer:
X: 2,8 = Neon
Y: 2,8,7= Chlorine
Neon has an atomic number of 10. It is referred to as a noble gas and it’s a mono atomic element.
Chlorine has an atomic number of 17. It is referred to as an Halogen. Chlorine exists in nature as a diatomic molecule.
However the question is incomplete and will need more information.
A gas sample occupies 8.77 L at 20 degrees Celsius and 3.98 atm. What is
the amount of mols of gas in the sample? *
Answer:
1.45 mol
Explanation:
Given data
Volume of the gas (V): 8.77 LTemperature of the gas (T): 20 °CPressure of the gas (P): 3.98 atmStep 1: Calculate the absolute temperature (Kelvin)
We will use the following expression.
[tex]K = \°C + 273.15\\K = 20\°C + 273.15 = 293K[/tex]
Step 2: Calculate the number of moles (n) of the gaseous sample
We will use the ideal gas equation.
[tex]P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{3.98atm \times 8.77L}{\frac{0.0821atm.L}{mol.K} \times 293K} = 1.45 mol[/tex]
I need help pls.!!!
The [OH-] of an aqueous solution is 6.4 x 10-5 M. What is the [H3O+]?
Answer: The [tex][H_3O^+][/tex] is [tex]1.55\times 10^{-10}M[/tex]
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pOH is calculated by taking negative logarithm of hydroxide ion concentration.
[tex]pOH=-\log [OH^-][/tex]
Putting in the values:
[tex]pOH=-\log[6.4\times 10^{-5}][/tex]
[tex]pOH=4.19[/tex]
[tex]pH+pOH=14[/tex]
[tex]pH=9.81[/tex]
[tex]9.81=-\log [H_3O^+][/tex]
[tex][H_3O^+]=1.55\times 10^{-10}[/tex]
Thus the [tex][H_3O^+][/tex] is [tex]1.55\times 10^{-10}M[/tex]
The value of [H₃O⁺] will be "1.55 × 10⁻¹⁰ M". To understand the calculation, check below.
Aqueous solutionAccording to the question,
The value of [OH⁻] = 6.4 × 10⁻⁵
By taking hydroxide ion concentration log,
→ pOH = log[OH⁻]
By putting the value of [OH⁻],
pOH = log[6.4 × 10⁻⁵]
= 4.19
hence,
→ pH + pOH = 14
9.81 = log [H₃O⁺]
[H₃O⁺] = 1.55 × 10⁻¹⁰ M
Thus the above answer is correct.
Find out more information about aqueous solution here:
https://brainly.com/question/14554879
Calculate the concentration in M) of hydroxide ions in a solution with a pOH of 2.468
A) 2.94 x 102
B) 3.40 x 1011
OC) 3.40 x 10-3
OD) 2.94 x 10-12
Answer:
C) 3.40 x 10-3
Explanation:
Hello,
In this case, for the given pOH, we are able to compute the concentration of hydrixide ions by applying the following formula:
[tex]pOH=-log([OH^-])[/tex]
[tex][OH^-]=10^{-pOH}=10^{-2.468}\\[/tex]
[tex][OH^-]=0.0034M=3.4x10^{-3}M[/tex]
Therefore, answer is C).
Best regards.
Answer:
3.40 × 10⁻³ M
Explanation:
The pOH scale is used to express the acidity or basicity of a solution.
If pOH < 7, the solution is basic.If pOH = 7, the solution is neutral.If pOH > 7, the solution is acid.The pOH of this solution is 2.468, so it is basic. We can calculate the concentration of hydroxide ions in the solution using the following expression.
[tex]pOH = -log [OH^{-} ]\\\[[OH^{-}] = antilog-pOH = antilog-2.468 = 3.40 \times 10^{-3} M[/tex]