What is the kinetic energy of an object that has a mass of 30 kg and moves with a velocity of 20 m/s?

Something is missing in question. But I will try to explain you about Doppler effect to reach your answer.

Answer:

If you on USA TEST prep the answer was "RIGHT"

Positive acceleration increases speed, negative acceleration is decreasing speed.

For example on a car the gas pedal would be positive acceleration and brake would be negative.

Answer:  Positive acceleration represents an object speeding up; negative acceleration represents an object slowing down.

Explanation:

hope it helped xx

Anything that says burned is a chemical reaction or a chemical change. Here's a burning reaction.

C2H5OH + 302 ===>  2CO2 +  3H2O

This is the equation for burning alcohol (the kind you drink). When burned, the alcohol's reaction leaves a beautiful blue flame along with CO2 and H2O on the right side.

So B is the answer.

You're not doing anything to paper if you shred it except make it smaller. It retains all of its chemical properties and almost all its physical properties.

Ice melting doesn't do anything to the water when it changes phase except you now have a puddle on the table where the ice (cube) was.  But you are still dealing with water.

Metal foil is heated, again the foil is left with all its chemical properties in tact. You can reuse the foil if you are cooking potatoes  in an open fire. Nothing has altered the chemical properties of the foil.  

18 hours 770

770/18 average speed.

Answer:

The average speed for both days, while driving is 42.77 miles/hr.

Explanation:

Given that,

Distance first day = 500 miles

Distance second day = 270 miles

According to question,

The distance covered by the john in 10 hours = 500 miles

Next day ,

The distance covered by the john in 8 hours = 270 miles

We need to calculate the average speed for both days

Using formula of the average speed

[tex]v_{avg}=\dfrac{D}{T}[/tex]

Where, D = total distance

T = total time

Put the value into the formula

[tex]v_{avg}=\dfrac{500+270}{10+8}[/tex]

[tex]v_{avg}=\dfrac{770}{18}[/tex]

[tex]v_{avg}=42.77\ miles/hr[/tex]

Hence, The average speed for both days, while driving is 42.77 miles/hr.

Given data

mass (m) = 185 g  = 0.185 Kg ,

temperature (T₁) = 200°C = 200 + 273 = 473 K

temperature (T₂) = 10°C = 10+273 = 283 K

Specific haet at constant pressure (Cp) = 2.108 Kj/Kg k

                Heat transfer (Q) = m.Cp.( T₂- T₁) J

                                            = 0.185 × 2.108 × (283 - 473)

                                         Q = -74.09 KJ

Heat rejected from ice is 74 J

Well, let's see.  I'll call the distance between the two towns ' D '.

Time to cover the distance = (distance/speed) .  I'll call the scheduled number of hours ' t ' .

16 minutes = 4/15 of an hour, and 10 minutes = 1/6 of an hour.

So . . .

(t + 1/6) = D/40.   Multiply by 4:  4t + 4/6 = D/10

(t + 4/15) =  D/30. Multiply by 3: 3t + 12/15 = D/10

Great.  The left sides are both equal to D/10, so we can say

4t + 4/6 = 3t + 12/15

Subtract 3t from each side:  t + 4/6 = 12/15

Subtract 4/6 from each side:  t = 12/15 - 4/6

Simplify the right side:  t = 4/5 - 2/3

Make a common denominator:  t = 12/15 - 10/15

t = the scheduled time = 2/15 of an hour  (8 minutes)

Looking back up above, we found that 3t + 12/15 = D/10

Plug in 2/15 in place of 't' : 3(2/15) + 12/15 = D/10

Simplify the left side:  18/15 = D/10

Multiply by 10:  D = 180/15 . . . . D = 12 miles

============================

This is such a dog of a bear of a problem, I think I ought to check my answer:

== Somewhere up above, I calculated that the scheduled time is supposed to be 8 minutes.

== Time = (distance) / (speed)

== At 40 mph, time = (12 miles) / (40 mi/hr) = 12/40 hr = 18 minutes ... 10 minutes late !

-- At 30 mph, time = (12 mi) / (30 mi/hr) = 12/30 hr = 24 minutes ... 16 minutes late !

YAY !

QED !

Unbelievable

distance traveled by the object is given as

[tex]x = v_i t + \frac{1}{2} at^2[/tex]

given that

[tex]v_i = 3.50 m/s[/tex]

[tex]a = 1.80 m/s^2[/tex]

[tex] t = 5 s[/tex]

now plug in all the values above

[tex]x = (3.50)(5) + \frac{1}{2}(1.80)(5)^2[/tex]

[tex]x = 40 m[/tex]

so here it will move total distance of 40 m

The distance covered by the object while it is accelerating is 40 meters.

Given the following data:

To determine the distance covered by the object while it is accelerating, we would apply the second equation of motion:

Mathematically, the second equation of motion is given by this formula:

[tex]S=ut+\frac{1}{2} at^2[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]S=3.5(5)+\frac{1}{2} \times 1.80 \times 5^2\\\\S=17.5+0.9 \times 25\\\\S=17.5+22.5[/tex]

S = 40 meters.

Read more on acceleration here: brainly.com/question/24728358

Given that

time (t) = 10 s ,

         (S) = ?

We know that  S = ut+ 1/2 a.t²  m

                         since free fall and no air friction,

                               a = g = 9.81 m/s² ; initial velocity u= 0

                         S = 0 + [1/2 × 9.81 ×10²]

                          S = 490.5 m

Answer: liquid A flows slower i got it right on the exam

Explanation:

Quarks are fundamental particles that make up other subatomic particles such as protons and neutrons. Quarks are not made up of any other particles.

The slope of a line is calculated by taking two points on the line, finding the differences in their y-values and x-values, and then dividing the change in y  by the change in x.

The slope of a line is a measure of its steepness or incline and is defined as the ratio of the vertical change to the horizontal change between two points on the line. Mathematically, the slope (often denoted by the letter m) is calculated using the following formula:

[tex]\text { Slope }(m)=\frac{\text { Change in vertical direction }}{\text { Change in horizontal direction }}[/tex]

If you have two points [tex]x_1, y_1[/tex] and [tex]x_2, y_2[/tex] on the line, the formula for calculating the slope (m) is:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Follow these steps to calculate the slope:

1) Identify the coordinates of the two points: Let the coordinates of the first point be [tex]x_1, y_1[/tex] and the coordinates of the second point be [tex]x_2, y_2[/tex].

2) Calculate the differences: Subtract [tex]y_1[/tex] from [tex]y_2[/tex]  to find the change in the vertical direction, and subtract [tex]x_1[/tex] from [tex]x_2[/tex] to find the change in the horizontal direction.

Vertical change = [tex]y_2[/tex] - [tex]y_1[/tex]

Horizontal change = [tex]x_2[/tex] - [tex]x_1[/tex]

3) Plug the differences into the formula: Substitute the vertical and horizontal changes into the slope formula.

[tex]\text { Slope }(m)=\frac{\text { Change in vertical direction }}{\text { Change in horizontal direction }}[/tex]

4) Calculate the slope: Perform the division to get the numerical value of the slope.

5) Interpret the result: If the slope is positive, it indicates an upward direction from left to right. If negative, it indicates a downward direction. A slope of 0 represents a horizontal line, and an undefined slope indicates a vertical line.

We can solve this via the kinematic equation:

[tex]h=v_{y}t+\frac{1}{2}gt^2[/tex]

Where the vertical velocity is zero and so:

[tex]h=0 \times t +\frac{1}{2}gt^2\\\\h=\frac{1}{2}gt^2\\\\t=\sqrt{\frac{2h}{g}}[/tex]

Since the height of the building is 29.3 meters then:

[tex]t= \sqrt{\frac{2(29.3)}{9.8}}\\\\t \approx 2.45s[/tex]

The ball was in motion for approximately 2.45 seconds

The ball was in motion for approximately 2.44 seconds. This was calculated using the equation for displacement in physics, considering only the vertical motion due to gravity.

This question is about physics, specifically kinematics. In this case, we'll focus on the motion of a ball thrown horizontally from a building. Although the ball is thrown horizontally, it's also influenced by gravity, which pulls it vertically downwards.

Considering only the vertical motion, an object dropped or thrown vertically has an initial velocity of 0. The building's height gives us the displacement. We can calculate the time the ball is in motion using the equation for displacement: d = 1/2 * g * t^2, where g is the acceleration due to gravity (approximately 9.8 m/s^2).

If we plug the given data (d = 29.3 m and g = 9.8 m/s^2) into the equation, we then need to solve for 't'. The rearranged equation is t = sqrt(d / 0.5g). This gives us a time of approximately 2.44 seconds, which is the time the ball was in motion.

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Answer:

The wave is moving from left to right (as indicated by the arrow), so, given that at the current instance the amplitude of the position V is 0 (or whatever midpoint the dashed line corresponds to), in the immediately next instance the position will continue increasing as the wave moves from left to right. The peak currently shown at U will at some point "arrive" at V. At that point the location V will have the maximum amplitude. After that the direction at position will be downward, etc.

Excuse are not acceptable

Answer:

59.2 N

Explanation:

According to Newton's second law, the resultant of the forces acting on the box must be equal to the product between the box's mass and its acceleration:

[tex]F_{net}=ma[/tex]

However, the box is moving at constant velocity, so its acceleration is zero:

a = 0

Therefore, the net force along the direction of motion (parallel to the surface) must be zero.

We have two forces acting along the direction parallel to the ground:

- The applied force, F

- The frictional force, [tex]\mu mg[/tex], in the opposite direction, with [tex]\mu = 0.3021[/tex] being the coefficient of friction, m = 20 kg the mass of the box and g = 9.8 m/s^2

Therefore, the equation of motion becomes:

[tex]F-\mu mg=0[/tex]

And solving for F, we find:

[tex]F=\mu mg=(0.3021)(20 kg)(9.8 m/s^2)=59.2 N[/tex]

As we know the time period of pendulum is given by the equation

[tex]T = 2\pi \sqrt{\frac{L}{g}}[/tex]

so here

L = length of the pendulum

Now on increasing the temperature due to thermal expansion the length of the pendulum will increase and due to this the time period of the pendulum will also increase

Now due to increase in time period of the pendulum the clock will become slow and it will give incorrect time due to this increase in temperature

Thermal expansion increases the pendulum period, and the clock will lose time

Simple Harmonic Motion is the motion of an object (repetitive movement) through its equilibrium point where the frequency of vibrations / oscillation per second is constant

The motion that occurs in the pendulum is one example of simple harmonic motion

Terms used:

Whereas the relationship T and f:

[tex]\displaystyle T=\frac{1}{f}\\\\f=\frac{n}{t}[/tex]

n = number of vibrations / oscillation

t = time (s)

Formula used:

[tex]\large{\boxed{\bold{T=2\pi \sqrt{\frac{L}{g} }}}\rightarrow \frac{1}{f}=2\pi \sqrt{\frac{L}{g} }[/tex]

From this formula shows that the period is proportional to the length of the pendulum rod . The longer the pendulum rod , the greater the amount of time in one vibration

If thermal expansion occurs in the pendulum clocks, the pendulum rod changes in length ,proportional to the temperature change, and increases the pendulum period, so the clock will lose time

The distance of the elevator  

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Rank the pendulums according to the number of complete cycles

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the average velocity  

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Under the condition of no pressure, water will change into gas. This phase change can occur by boiling if the water is in a liquid state or sublimation if it is a solid, as there is no liquid phase at extremely low pressures.

If there is no pressure, water will change into gas. This process is understood through the physical properties of water and its behavior under different temperature and pressure conditions. When energy is added into a system containing water, the water molecules begin to move faster. As more energy is put in, the temperature rises until it reaches the boiling point, which is a fixed temperature specific to each substance where it changes from liquid to gas.

However, at extremely low pressures, the scenario changes. There is no liquid phase for water below 0.00600 atm, implying that water can either be a gas or a solid. In these conditions, water undergoes a phase change known as sublimation, where it transitions directly from a solid to a gas without becoming liquid.

Thus, under the condition of 'no pressure,' which is an extreme low-pressure scenario, water will opt for the gaseous state, either by boiling from the liquid state if it originally was a liquid, or by sublimating if it was a solid.

In the absence of pressure, water will turn into a gas through the process of sublimation, where at extremely low pressures below 0.00600 atm, it can directly transition from a solid to a gas.

If there is no pressure, water will change into gas. This phenomenon is because, at sufficiently low pressures, water has no liquid phase and can exist either as a gas or as a solid. When water molecules receive enough kinetic energy, such as at their boiling point, they overcome intermolecular forces and transition to the gas phase. At pressures below approximately 0.00600 atm, this transition happens directly from a solid to a gas, a process known as sublimation. This accounts for effects like the dry ice sublimating at standard pressure and the routine defrosting of a freezer.

Answer:

Efficiency of wedge is the ratio of "work done by the machine to the work supplied to the machine".

           Efficiency (η) = Work done by machine ÷ Work supplied

                                  = 65 ÷ 75

                                 = 0.86%

Efficiency of wedge is 86%

Answer: Option (A) is the correct answer.

Explanation:

When a substance like sand gets carried away along with the flow of wind then this process is known as erosion.

When a substance is kept in air for too long and this exposure causes change in appearance or texture of the substance then it is known as weathering.

When rocks gets deposited on a land then this is known as deposits rocks on.

Thus, we can conclude that when Sam blew out through a straw and directed his breath at a pan of sand. Sam is showing the rest of his class how the wind erodes the land.

v=v2-v1=15-10=5 cm/s

p=mv=0.15•5=0.75 kg•cm/s

Answer : The correct option is, (A) 7.5 mN.s

Explanation :

Impulse : It is defined as the force applied to an object for a certain amount of time.

Formula used :

[tex]I=F\times \Delta t[/tex]

As we know that:

[tex]F=m\times \Delta a\\\\\Delta a=\frac{\Delta v}{\Delta t}[/tex]

Thus, formula of impulse will be:

[tex]I=m\times \Delta v[/tex]

where,

I = impulse  = ?

m = mass = 0.15 kg

[tex]\Delta v[/tex] = change in speed of velocity = [tex]v_{final}-v_{initial}=15cm/s-10cm/s=5cm/s=0.05m/s[/tex]     (1 m = 100 cm)

Now put all the given values in the above formula, we get:

[tex]I=(0.15kg)\times (0.05m/s)[/tex]

[tex]I=0.0075kg.m/s=0.0075N.s=7.5mN.s[/tex]      (1 N.s = 1000 mN.s)

Therefore, the impulse acting on the car is, 7.5 mN.s

For any wave,  Wavelength = (speed) / (frequency).

So the Slinky Wavelength = (6.6 m/s) / (3 / sec)

Wavelength = 2.2 meters .

It takes the compression in the wave 2.2 seconds to travel the length of the classroom.

Question: The part of the eye responsible for most of the refraction of incoming light is the _____.

Answer: lens

Explanation: this is because your eye lens reflects of light from your eyes like when the sunlight shines aff a pair of glasses it makes fire

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Answer:

Explanation:

The momentum of a 1200 kg car moving west at a speed of 25 m/s is 30000 kg×m/s in the westward direction.

Momentum, in physics, is the product of the mass and velocity of an object. To calculate momentum, we multiply the mass of the object by its velocity. For a 1200 kg car moving west at a speed of 25 m/s, the momentum would be 30000 kg×m/s. Note that momentum is a vector quantity, so it has both magnitude (size) and direction. Here, the direction would be west because that's the way the car is moving.

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B looks closest ...

move tail of down pointing vector to tail of other one and make a parallelogram ... join junctions of first tails to final arrowheads ...

Or

join tail of right hand vector to tip of left hand vector to get two sides of a vector triangle.

then join tail of left hand vector to tip of right vector for third side of triangle and the resultant.

either way should work, both give same answer

Vector 'a' is made out of some 'up' and some 'right'.

Vector 'b' cancels most or all of the 'up' part of 'a', leaving only the 'right' part and maybe a slight bit of 'up'.

The only choice that is mostly 'right' with maybe a slight bit of 'up' is choice-B.

Choice-A has too much 'up' in it.

Choices C and D both have some 'left' in them. They couldn't get any 'left' from 'a' or 'b'.

Electromagnetic waves are the waves which can also travel through the vacuum. Example of electromagnetic waves are - Radio waves , micro waves, Infrared waves, Light (visible portion of electromagnetic spectrum), Ultraviolet rays, Xrays and gamma rays.

Hence A that is light waves is the correct option.  

The answer is A! I hope this helps!

Answer:

The kinetic energy of the animal is 45 Joule.

Explanation:

Kinetic energy of the animal is given by,

Kinetic energy = [tex]\frac{1}{2} m v^{2}[/tex]

Given: m = 10 kg , v = 3 m/s

Thus,

Kinetic energy = [tex]\frac{1}{2} (10) (3)^{2}[/tex]

Kinetic energy = 45 Joule,

The kinetic energy of the animal is 45 Joule.

Resistance per 1000 feet for gauge 14 wire is given as

R = 2.525 ohm

now if wire is of length 50 feet only then the resistance is given as

[tex]R = \frac{2.525}{1000}\times 50[/tex]

[tex]R = 0.126 ohm[/tex]

now if 11 A current flows through the wire then the voltage drop is given by ohm's law

[tex]V = iR[/tex]

[tex]V = 11 \times 0.126[/tex]

[tex]V = 1.4 Volts[/tex]

so most appropriate answer in given options is

A. 1.8 Volts

[tex]\bf{Given : Hubble\;Constant(H_0) = 73(\frac{km}{s \times Mpc})}[/tex]

[tex]\bf{Given : Conversion\;Factor = (\frac{1Mpc}{3.086 \times 10^1^9\;km})}[/tex]

[tex]\bf{\implies Resulting\;Hubble\;Constant = 73(\frac{km}{s \times Mpc})(\frac{1Mpc}{3.086 \times 10^1^9\;km})}[/tex]

[tex]\bf{\implies Resulting\;Hubble\;Constant = 73(\frac{1}{s \times 3.086 \times 10^1^9})}[/tex]

[tex]\bf{\implies Resulting\;Hubble\;Constant = (\frac{23.65}{s \times 10^1^9})}[/tex]

[tex]\bf{\implies Resulting\;Hubble\;Constant = 2.365 \times 10^-^1^8(1/s)[/tex]