What is the pH of a 1.0 molar solution of HCl?

Answers

Answer 1

Answer:

0.

Explanation:

For 1.0 M HCl:

[H⁺] = 1.0 M.

∵ pH = - log[H⁺]  

∴ pH = - log(1.0 M) = 0.

Answer 2

Final answer:

The pH of a 1.0 molar solution of HCl is 0.

Explanation:

The pH of a 1.0 molar solution of HCl can be calculated using the formula pH = -log[H3O+]. Since HCl is a strong acid, it completely ionizes in water to form H3O+ ions. Therefore, the hydrogen ion concentration is equal to the molar concentration of HCl.

Thus, the pH of a 1.0 molar solution of HCl would be -log(1.0) = 0.

Therefore, the pH of the solution is 0.


Related Questions

When 50 ml (50 g) of 1.00 m hcl at 22oc is added to 50 ml (50 g) of 1.00 m naoh at 22oc in a coffee cup calorimeter, the temperature increases to 28.87oc. how much heat is produced by the reaction between hcl and naoh? (the specific heat of the solution produced is 4.18 j/goc)?

Answers

Answer:

[tex]\boxed{\text{2700 J}}[/tex]

Explanation:

HCl + NaOH ⟶ NaCl + H₂O

There are two energy flows in this reaction.  

Heat of reaction + heat to warm water = 0  

           q₁             +              q₂                 = 0  

           q₁             +          mCΔT              = 0  

Data:

    m(HCl) = 50 g

m(NaOH) = 50 g

           T₁ = 22       °C

          T₂ = 28.87 °C

           C = 4.18 J·°C⁻¹g⁻¹

Calculations:

 m = 50 + 50 = 100 g

ΔT = 28.87 – 22 = 6.9 °C

 q₂ = 100 × 4.18 × 6.9 = 2900 J

q₁ + 2900 = 0

q₁ = -2900 J

The negative sign tells us that the reaction produced heat.

The reaction produced [tex]\boxed{\textbf{2900 J}}[/tex].

Final answer:

The reaction between HCl and NaOH in the situation described produced 2.87 kJ of heat.

Explanation:

The question is asking how much heat is produced by the reaction between 1.00 M hydrochloric acid (HCl) and 1.00 M sodium hydroxide (NaOH) in a coffee cup calorimeter when the initial temperature is 22ºC and the final temperature is 28.87ºC. The heat released in a chemical reaction can be calculated from the formula q = mcΔT, where q is heat, m is mass, c is specific heat, and ΔT is the change in temperature. In this case, the mass of the solution is 100g (50g HCl + 50g NaOH), the specific heat of the solution is given as 4.18 J/gºC, and the change in temperature is 28.87ºC - 22ºC = 6.87ºC.

Applying the numbers in the formula we get:

q = 100g * 4.18 J/gºC * 6.87ºC = 2872.6 J

Since the question requires the answer in kJ, we divide the result by 1000: Q = 2.87 kJ. The reaction between HCl and NaOH in the calorimeter produced 2.87 kJ of heat.

Learn more about Heat of Reaction here:

https://brainly.com/question/30464598

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An ionic bond can be formed when one or more electrons are 1) equally shared by two atoms 2) unequally shared by two atoms 3) transferred from the nucleus of one atom to the nucleus of another atom 4) transferred from the valence shell of one atom to the valence shell of another atom

Answers

Answer:

4) transferred from the valence shell of one atom to the valence shell of another atom

Explanation:

Electrons are located outside of the nucleus which contains the protons and the neutrons.

For bonds to form, valence electrons located in the outermost shell electrons are involved. These are the valence electrons. These outer shell electrons can be shared or transferred between two combining atoms to form stable atoms.

In ionic bonds, the electrons are transferred from one specie to another. The atom that loses the electrons becomes positively charged and the receiving atom becomes negatively charged. This is the crux of ionic bonds.

Why does alkali elements react vigorously with water?

Answers

Answer:

Explanation:

Because the alkali metal is really willing to give up its electron much more so than Hydrogen.

The redox reaction looks like this

K ===> K+   +    1 e-    The reduction vo is very high which means that the K really does want to give up that electron.

2H+  +2e- ====> H2  The oxidation vo is almost 0 but the Hydrogen is the perfect recipient for the 2 electrons.

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