What is the scale factor from figure A to figure B?

Hello There!

So we know Some number added to 27 gets a sum of -12

We can figure this out by subtracting 27 from -12 so we would go back.

Once we subtract, -39 will be x and that is our answer.

The correct answer is -39

Nicole has 25 ten-dollar bills.

To find out how many ten-dollar bills Nicole has, we can divide the total amount of money she has by the value of each bill.

$250 / $10 = 25

Therefore, Nicole has 25 ten-dollar bills.

Answer in detail:

Nicole has $250 in ten-dollar bills. This means that she has 25 groups of $10.

We can divide $250 by $10 to find out how many groups of $10 she has.

$250 / $10 = 25

Therefore, Nicole has 25 ten-dollar bills.

Another way to look at it is this way:

If Nicole has 1 ten-dollar bill, then she has $10.

If Nicole has 2 ten-dollar bills, then she has $20.

If Nicole has 3 ten-dollar bills, then she has $30.

And so on.

So, to find out how many ten-dollar bills Nicole has, we can simply divide the total amount of money she has by the value of each bill.

Answer:

y=9

Step-by-step explanation:

(9,-1) is the answer.

Answer

b

Step-by-step explanation:

Answer:

− -10x^2-33x+1

Step-by-step explanation:

Answer:

The distance reduces to 0 as you go from 0° to 90°

Step-by-step explanation:

The question requires you to find the distance using different values of L and check the trend of the values.

Given C=2×pi×r×cos L where L is the latitude  in ° and r is the radius in miles then;

Taking r=3960 and L=0° ,

C=2×[tex]\pi[/tex]×3960×cos 0°

C=2×[tex]\pi[/tex]×3960×1

C=7380[tex]\pi[/tex]

Taking L=45° and r=3960 then;

C= 2×[tex]\pi[/tex]×3960×cos 45°

C=5600.28[tex]\pi[/tex]

Taking L=60° and r=3960 then;

C=2×[tex]\pi[/tex]×3960×cos 60°

C=3960[tex]\pi[/tex]

Taking L=90° and r=3960 then;

C=2×[tex]\pi[/tex]×3960×cos 90°

C=2×[tex]\pi[/tex]×3960×0

C=0

Conclusion

The values of the distance from around the Earth along a given latitude decreases with increase in the value of L when r is constant

i think it is m because it simply the vertex

The greatest common factor is 2x

2 can go into both 10 and 12

and so can x

ANSWER

See attachment.

EXPLANATION

The given function is

[tex]y = \sqrt[3]{x + 1} - 2[/tex]

The parent function is

[tex]y = \sqrt[3]{x} [/tex]

When we shift the parent graph to the left one unit, and down 2 units, we obtain the graph of the given function.

The graph of this function is shown in the attachment.

Answer:

Step-by-step explanation:

Function g(x) = x - 2 is in the denominator.  We cannot divide by zero, so the domain of (f/g)(x) is x ≠ 2.

To find the domain of f(x)/g(x), consider where g(x) is not zero as division by zero is undefined. The domain is all real numbers except x = 2.

The domain of f(x)/g(x) is determined by the values of x that make the expression defined while avoiding division by zero. To find the domain, we need to consider where g(x) is not equal to zero, as division by zero is undefined.

Given: f(x) = (x+1)⁻¹ and g(x) = x-2. As g(x) is not zero at x = 2, the domain of f(x)/g(x) is all real numbers except x = 2.

Answer:

[tex]\large\boxed{A==\dfrac{3-\sqrt6}{12}\ cm^2}[/tex]

Step-by-step explanation:

The shaded region is the triangle with base b and height h.

[tex]b=BD-CD\to b=\dfrac{\sqrt2}{2}-\dfrac{\sqrt3}{3}=\dfrac{3\sqrt2}{(2)(3)}-\dfrac{2\sqrt3}{(2)(3)}=\dfrac{3\sqrt2-2\sqrt3}{6}\\\\h=AD\to h=\dfrac{\sqrt2}{2}[/tex]

The formula of an area of a triangle:

[tex]A=\dfrac{bh}{2}[/tex]

Substitute:

[tex]A=\dfrac{\frac{3\sqrt2-2\sqrt3}{6}\cdot\frac{\sqrt2}{2}}{2}=\left(\dfrac{3\sqrt2-2\sqrt3}{6}\right)\left(\dfrac{\sqrt2}{2}\right)\left(\dfrac{1}{2}\right)\\\\\text{use the distributive property}\ a(b+c)=ab+ac\\\\=\dfrac{(3\sqrt2-2\sqrt3)(\sqrt2)}{(6)(2)(2)}=\dfrac{(3\sqrt2)(\sqrt2)-(2\sqrt3)(\sqrt2)}{24}\\\\\text{use}\ \sqrt{a}\cdot\sqrt{a}=a\ \text{and}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\dfrac{(3)(2)-2\sqrt6}{24}=\dfrac{2(3-\sqrt6)}{24}=\dfrac{3-\sqrt6}{12}[/tex]

Answer:

see explanation

Step-by-step explanation:

The area of the shaded triangle = area of ΔABD - area of ΔADC

A of ΔABD = [tex]\frac{1}{2}[/tex] × AD × BD

A = [tex]\frac{1}{2}[/tex] × [tex]\frac{\sqrt{2} }{2}[/tex] × [tex]\frac{\sqrt{2} }{2}[/tex]

   = [tex]\frac{2}{8}[/tex] = [tex]\frac{1}{4}[/tex]

--------------------------------------------------------------------------

A of ΔACD = [tex]\frac{1}{2}[/tex] × AD × DC

A = [tex]\frac{1}{2}[/tex] × [tex]\frac{\sqrt{2} }{2}[/tex] × [tex]\frac{\sqrt{3} }{3}[/tex]

A = [tex]\frac{\sqrt{6} }{12}[/tex]

-------------------------------------------------------------------------

shaded area = [tex]\frac{1}{4}[/tex] - [tex]\frac{\sqrt{6} }{12}[/tex]

= [tex]\frac{3}{12}[/tex] - [tex]\frac{\sqrt{6} }{12}[/tex] = [tex]\frac{3-\sqrt{6} }{12}[/tex]

Answer:

The value of the expression is [tex]0.1544[/tex]

Step-by-step explanation:

we have

[tex][(38*\frac{1}{4})+(33\%*18)]/100[/tex]

we know that

[tex](38*\frac{1}{4})=\frac{38}{4}=9.5[/tex]

[tex](33\%*18)=(33/100)*18=0.33*18=5.94[/tex]

substitute

[tex][9.5+5.94]/100[/tex]

[tex][15.44]/100[/tex]

[tex]0.1544[/tex]

Answer:

The simplest form of (a + b - c )(a + b + c ) is a² + 2ab + b² - c²

Step-by-step explanation:

* Lets revise how to multiply two brackets with three terms

∵ (a + b - c)(a + b + c)

- Multiply the first term of the first bracket by the three terms of the

 second bracket

∵ a × a = a²

∵ a × b = ab

∵ a × c = ac

- Then multiply the second term in the first bracket by the three terms

 of the second bracket

∵ b × a = ba

∵ b × b = b²

∴ b × c = bc

- Then multiply the third term term in the first bracket by the three terms

 of the second bracket

∵ -c × a = -ca

∵ -c × b = -cb

∵ -c × c = -c²

- Now add all these terms together

∴ a² + ab + ac + ba + b² + bc + -ca + -cb + -c²

- We have like terms lets add them

∵ ab = ba  , ac = ca , bc = cb

∴ a² + (ab + ba) + (ac + -ca) + (bc + -cb) + b² + -c²

∴ a² + 2ab + 0 + 0 + b² - c²

∴ a² + 2ab + b² - c²

∴ The simplest form of (a + b - c )(a + b + c ) is a² + 2ab + b² - c²

The answer is:

[tex]a^{2} +b^{2} -c^{2} +2ab[/tex]

To solve the problem, we need to remember the distributive property.

The distributive property is defined by the following way:

[tex](a+b)(c+d)=ab+ad+bc+bd[/tex]

Also, we need to remember how to add like terms. The like terms are the terms that share the same variable and the same exponent, for example:

[tex]x+x^{2}+x=x^{2} +2x[/tex]

We were able to add the first and the third term because they share the same variable and the same exponent.

Now, we are given the following expression to simplify:

[tex](a+b-c)(a+b+c)[/tex]

So, applying the distributive property and adding like terms, we have:

[tex](a+b-c)(a+b+c)=(a*a)+(a*b)+(a*c)+(b*a)+(b*b)+(b*c)-(c*a)-(c*b)-(c*c)\\\\(a+b-c)(a+b+c)=a^{2}+ab+ac+ba+b^{2} +bc-ac-bc-c^{2}\\\\(a+b-c)(a+b+c)=a^{2} +b^{2} -c^{2} +2ab[/tex]

Hence, we have that the given expression is equal to:

[tex]a^{2} +b^{2} -c^{2} +2ab[/tex]

Have a nice day!

Answer:

[tex]\displaystyle \frac{54}{5405}[/tex].

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

[tex]\displaystyle \left(50\atop 5\right) = 2,118,760[/tex].

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

[tex]\displaystyle \left( 28\atop 2\right) = 378[/tex].

Number of ways to choose 3 green candies out of a batch of 8:

[tex]\displaystyle \left(8\atop 3\right)=56[/tex].

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

[tex]\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168[/tex].

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

[tex]\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}[/tex].

Answer:

[tex]\large\boxed{x=-1\ or\ x=1}[/tex]

Step-by-step explanation:

[tex]x^4+3x^2-4=0\\\\x^{(2)(2)}+3x^2-4=0\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(x^2)^2+3x^2-4=0\qquad\text{substitute}\ x^2=t\geq0x=\\\\t^2+3t-4=0\\\\t^2+4t-t-4=0\\\\t(t+4)-1(t+4)=0\\\\(t+4)(t-1)=0\iff t+4=0\ \vee\ t-1=0\\\\t+4=0\qquad\text{subtract 4 from both sides}\\t=-4<0\\\\t-1=0\qquad\text{add 1 to both sides}\\t=1>0\to x^2=1\\\\x^2=1\to x=\pm\sqrt1\to x=-1\ \vee\ x=1[/tex]

Answer: Last option

Step-by-step explanation:

Note that when the point is not included in the function is marked with an empty circle, and when the point is included in the function is marked with a filled circle.

From the interval [tex]0\leq x <3[/tex] f(x) is represented by the slanted line [tex]-x +4[/tex] that cuts the y-axis at [tex]y = 4[/tex]

The starting point of the line must be filled and the end point must be empty.

Then, from the interval [tex]x \geq 3[/tex] f(x) is defined by the horizontal line [tex]y = 6[/tex]. The starting point of this line is marked with a filled circle because it includes the point [tex]x = 3[/tex]

Therefore the correct option is option D or the last graph (from left to right)

Answer:

last one

Step-by-step explanation:

[tex]\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\displaystyle\sum \limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\bf S_{20}=\displaystyle\sum \limits_{n=1}^{\stackrel{\stackrel{n}{\downarrow }}{20}}~\stackrel{\stackrel{a_1}{\downarrow }}{3}(\stackrel{\stackrel{r}{\downarrow }}{1.5})^{n-1}\implies S_{20}=3\left(\cfrac{1-1.5^{20}}{1-1.5} \right)\implies S_{20}=3\left(\cfrac{1-\stackrel{\approx}{3325.3}}{-0.5} \right) \\\\\\ S_{20}=3\left(\cfrac{-3324.3}{-0.5} \right)\implies S_{20}=3(6648.6)\implies S_{20}=19945.8[/tex]

19945.8 to simplify, the answer is

Answer:

Step-by-step explanation:

A direct variation suggest that the value of x in the equation would greatly affect the value of y such that when x is increasing, y also increases and the other way around. The equation for a direct variation is that,

                              y  = kx

Substituting the given values in the ordered pair,

                          5 = k(4)   ; k = 5/4

answer: y = kx hope this helps

The probability of obtaining at random without replacement two gum balls is 3/11.

Probability is the chance of occurrence of a certain event out of the total no. of events that can occur in a given context.

Given, A gumball machine contains six yellow gumballs and five orange gumballs.

So, N(Y) = 6 and N(O) = 5 and the number of sample space N(S) = 11.

Therefore, The probability of obtaining at random without replacement two gum balls is,

P(YY) = (6/11)×(6 - 1)/(11 - 1).

P(YY) = (6/11)×(5/10).

P(YY) = 30/110.

P(YY) = 3/11.

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The median is 8. You have to arrange it and then since it’s an even number add the two middle numbers and divide by 2.

ANSWER

The median is 8

EXPLANATION

The given date set is 3,10,1, 6, 10,3,11,14

We rearrange the data set in ascending order of magnitude to get:

1,3,3,6,10,10,11,14

There are two numbers {6,10} in the middle of the data set after arranging in ascending order.

The median is the mean of thesecond two numbers.

The median is

[tex] \frac{6 + 10}{2} = \frac{16}{2} = 8[/tex]

Therefore the median is 8

so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant

[tex]\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\bf cos(\theta )=\cfrac{\stackrel{adjacent}{9}}{\stackrel{hypotenuse}{\sqrt{90}}}\implies \stackrel{\textit{rationalizing the denominator}}{\cfrac{9}{\sqrt{90}}\cdot \cfrac{\sqrt{90}}{\sqrt{90}}\implies \cfrac{9\sqrt{90}}{90}}\implies \cfrac{\sqrt{90}}{10}\implies \cfrac{3\sqrt{10}}{10}[/tex]

Answer:

The average rate of change is 3

Step-by-step explanation:

0 to 5 is 5 in difference then the change on the next one: 1 to 9 the difference is 8 so the change is 3 and it increases by three on the rest of them.

I'm pretty sure the average rate of change would be 3

Answer:

x=1+2√2 or x=1−2√2

Step-by-step explanation:

Let's solve your equation step-by-step.

3x2−6x=21

Step 1: Since the coefficient of 3x^2 is 3, divide both sides by 3.

3x2−6x

3

=

21

3

x2−2x=7

Step 2: The coefficient of -2x is -2. Let b=-2.  

Then we need to add (b/2)^2=1 to both sides to complete the square.

Add 1 to both sides.

x2−2x+1=7+1

x2−2x+1=8

Step 3: Factor left side.

(x−1)2=8

Step 4: Take square root.

x−1=±√8

Step 5: Add 1 to both sides.

x−1+1=1±√8

x=1±√8

x=1+2√2 or x=1−2√2

Answer:

-6.47+4.70i.  

Brainliest

Step-by-step explanation:

100% sure

Answer:-6.47+4.70i

Step-by-step explanation:

Took test ,, good luck !!!

Answer:

Y = W = 15 ft.

X= L = 60 ft.

So width is 15 and the length is 60.

Answer: A. 15 feet

Step-by-step explanation:

The formula used to calculate the perimeter of a rectangle is:

[tex]P=2l+2w[/tex]

Where "l" is the lenght of the rectangle and "w" is the width.

You know that the length of this rectangle is 4 times its width. This means that:

[tex]l=4w[/tex]

And you know that the perimeter is 150 feet.

Then, you need to substitute  [tex]l=4w[/tex] and the value of the perimeter into the formula and solve for "w":

[tex]150=2(4w)+2w\\\\150=10w\\\\w=\frac{150}{10}\\\\w=15feet[/tex]

Answer:

50 Students

You can find the number of boys and girls by dividing the total, so there are a total of 20 boys and 30 girls in the choir of 50. The ratio 2 boys : 3 girls means we can divide the chorus into groups.

Answer:

The median is 72.

Answer:

72

Step-by-step explanation:

68  69  71  71  72  72  74  74  76

68  76  69  74  71  74  71  72  72

72 is the median

Answer:

17.C

18.A

Step-by-step explanation:

17. Slope=(y2-y1)/(x2-x1)

=(-1-(-2))/(4-(-3))

=1/7

18.Slope=(y2-y1)/(x2-x1)

=(9-6)/(2-0)

=3/2

Do you want 19 and 20 too?

Question 1:

For this case we have that by definition, the slope of a line is given by:

[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]

Where:

[tex](x_ {1}, y_{1}) and (x_ {2}, y_{2})[/tex]are two points through which the line passes.

[tex](x_ {1}, y_{1}) = (- 3, -2)\\(x_ {2}, y_{2}) = (4, -1)[/tex]

Substituting in the equation:

[tex]m = \frac {-1 - (- 2)} {4 - (- 3)} = \frac {-1 + 2} {4 + 3} = \frac {1} {7}[/tex]

ANswer:

Option C

Question 2:

For this case we have that by definition, the slope of a line is given by:

[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]

Where:

[tex](x_ {1}, y_{1}) and (x_ {2}, y_{2})[/tex] are two points through which the line passes.

[tex](x_ {1}, y_{1}) = (0,6)\\(x_ {2}, y_{2}) = (2,9)[/tex]

Substituting in the equation:[tex]m = \frac {9-6} {2-0} = \frac {3} {2}[/tex]

ANswer:

Option A

Question 3:

For this case we have that by definition, the slope of a line is given by the following formula:

[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]

Where:

[tex](x_ {1}, y_{1}) and (x_ {2}, y_{2})[/tex]are two points through which the line passes.

We have as data:

[tex]m = \frac {7} {8}\\(x_ {1}, y_{1}) = (- 2,1)[/tex]

Substituting in the formula:

[tex]\frac {7} {8} = \frac {y_ {2} -1} {x_ {2} - (- 2)}\\\frac {7} {8} = \frac {y_ {2} -1} {x_ {2} +2}[/tex]

We substitute each of the points and see if the equality is met:

Point A: (6,8)

[tex]\frac {7} {8} = \frac {8-1} {6 + 2}\\\frac {7} {8} = \frac {7} {8}[/tex]

Equality is met.

Answer:

Option A

Question 4:

For this case we have that by definition, the slope of a line is given by the following formula:

[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]

Where:

[tex](x_ {1}, y_{1}) and (x_ {2}, y_{2})[/tex]are two points through which the line passes.

We have as data:

[tex]m = \frac {1} {6}\\(x_ {1}, y_{1}) = (0, -3)[/tex]

Substituting in the formula:

[tex]\frac {1} {6} = \frac {y_ {2} - (- 3)} {x_ {2} -0}\\\frac {1} {6} = \frac {y_ {2} +3} {x_ {2} -0}[/tex]

We substitute each of the points and see if the equality is met:

Point A: (-3,0)

[tex]\frac {1} {6} = \frac {0 + 3} {- 3-0}\\\frac {1} {6} = \frac {3} {- 3}[/tex]

It is not fulfilled!

Point B: (6, -2)

[tex]\frac {1} {6} = \frac {-2 + 3} {6-0}\\\frac {1} {6} = \frac {1} {6}[/tex]

Equality is met!

ANswer:

Option B

Answer:

The diagram is shown in the attached image

Explanation:

We are given that Yin labelled her diagram a rectangle

This means that the shape she drew:

1- Is a four sided closed polygon

2- Has equal opposite sides (each two opposite sides are equal)

3- Has parallel opposite sides (each two opposite sides are parallel)

4- Has 4 right angles (all its interior angles are 90°)

This is shown in the attached image

Hope this helps :)

[tex]\bf (\stackrel{x_1}{10}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{-10}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-5)}{-10-10}\implies \cfrac{-1+5}{-20}\implies \cfrac{4}{-20}\implies -\cfrac{1}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-5)=-\cfrac{1}{5}(x-10) \\\\\\ y+5=-\cfrac{1}{5}x+2\implies y=-\cfrac{1}{5}x-3[/tex]

Answer:

Given,

f(x)=x^2+6

g(x)=2x-1

Now,

g[f(x)]=g(x^2+6) since f(x)=x^2+6

=2(x^2+6)-1 since x > x^2+6

=2x^2+12-1

=2x^2+11

In order to find g[f(x)], we substitute the equation for f(x) into the equation for g(x). We replace every 'x' in g(x) with f(x) to get g(f(x)) = 2*(x^2 + 6) - 1. After simplification, we get g[f(x)] = 2x^2 + 11.

In the world of mathematics, g[f(x)] represents the composition of two functions, f(x) and g(x). In this case, f(x) = x^2 + 6, and g(x) = 2x - 1. The composition of these two functions, expressed as g[f(x)], involves plugging the equation for f(x) into the equation for g(x).

Here's how we do it:

First, we take the f(x) = x^2 + 6. Then we put this into g(x), replacing every 'x' in g(x) with our function f(x). So, g(f(x)) = 2*(x^2 + 6) - 1. Simplifying, we find:

g(f(x)) = 2x^2 + 12 - 1 = 2x^2 + 11.

Therefore, the content loaded f(x) = x^2 + 6, g(x) = 2x - 1, g[f(x)] = 2x^2 + 11.

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