Answer:
C.) 23/21
Step-by-step explanation:
just took the test on edge
Jane is going to walk once around the edge of a rectangular park. The park is 300 yards long and 200 feet wide. How far will Jane walk?
Jane will walk 733.34 yards around the edge of the rectangular park after converting the width from feet to yards and calculating the perimeter.
Jane is going to walk once around the edge of a rectangular park. The park is 300 yards long and 200 feet wide. To determine how far Jane will walk, we need to calculate the perimeter of the rectangle. First, let's convert all measurements to the same unit. Since the length is given in yards and the width in feet, we can convert the width to yards (1 yard = 3 feet).
Width in yards: 200 feet \/ 3 feet per yard = 66.67 yards.
Now that both measurements are in yards, we can calculate the perimeter:
Perimeter = 2 ×(length + width) = 2 × (300 yards + 66.67 yards) = 2 ×366.67 yards = 733.34 yards.
Therefore, Jane will walk 733.34 yards around the edge of the park.
F(x,y)=eâ8xâx2+8yây2. find and classify all critical points of the function. if there are more blanks than critical points, leave the remaining entries blank.
To find and classify critical points of a two-variable function, calculate and set the first partial derivatives to zero to find critical points. Then, use the second derivatives to classify these points. The determinant of the Hessian matrix, made up of the second derivatives, contributes to this classification.
Explanation:To find the critical points of the function F(x,y)=e^8x - x^2 + 8y - y^2, you first need to find the partial derivatives F_x and F_y and set them both equal to zero.
F_x = 8e^8x - 2x and F_y = 8 - 2y. By setting these equal to zero and solving for x and y, you will find the critical points.
Once the critical points are found, we classify them using the second derivative test. This involves computing the second partial derivatives F_xx, F_yy, and F_xy, and evaluating them at the critical points.
Finally, we calculate the determinant D of the Hessian matrix, composed of the second derivatives, at the critical points. The signs and values of these results and the determinants help classifying the critical points.
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Which of the following statements is true? A 6.75 < 6.759 < 6.751 < 6.85 B 5.55 < 5.559 < 5.65 < 5.69 C 4.11 < 4.12 < 4.17 < 4.15 D 7.42 < 7.41 < 7.40 < 7.39
A package contains 3 cups of trail mix. A serving of trail mix is ⅓ cup. How many servings of trail mix is in the package?
What is the area of parallelogram ABCD in square units
13 square units
Further explanationConsider attachment for details.
We make a KLMN rectangle that touches all the vertices of the ABCD parallelogram. Consequently, the ABCD parallelogram is right inside the KLMN rectangle.
Let us take the following strategic steps:
Calculate the area of KLMN.Calculate the area of the triangles ABL, CDM, ADK, and BCN.Subtract the area of the KLMN rectangle with the area of all triangles.The difference in the area above is the area of the ABCD parallelogram.The Process:
The area of KLMN = 4 x 5 = [tex] \boxed{ \ 20 \ square \ units. \ }[/tex]The ADK triangle is congruent to the BCN triangle, and each area is [tex]\boxed{ \ \frac{1}{2} \times 4 \times 1 = 2 \ square \ units. \ }[/tex] Thus the total area of ADK and BCN is [tex]\boxed{ \ 2 + 2 = 4 \ square \ units. \ }[/tex]The ABL triangle is congruent to the CDM triangle, and each area is [tex]\boxed{ \ \frac{1}{2} \times 3 \times 1 = 1.5 \ square \ units \ }.[/tex] Thus, the combined area of ABL and CDM is [tex]\boxed{ \ 1.5 + 1.5 = 3 \ square \ units. \ }[/tex]Finally, the area of ABCD = 20 - 4 - 3 = 13.As a result, we get the area of the parallelogram ABCD is 13 square units.
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A music company executive must decide the order in which to present 6 selections on a compact disk. how many choices does she have
find the quotient of 0.34 and 0.2.
Two consecutive odd integers have a sum of 44 . Find the integers.
standard form of the equation of a hyperbola that has vertices at (-10, -15) and (70, -15) and one of its foci at (-11, -15).
Final Answer:
The standard form of the equation of the hyperbola with vertices at (-10, -15) and (70, -15) and one of its foci at (-11, -15) is (x - 30)^2 / 1600 - (y + 15)^2 / 81 = 1
Explanation:
To write the standard form of the equation of a hyperbola with the given vertices and a focus, we'll follow these steps:
1. Determine the center of the hyperbola.
2. Calculate the distance between the vertices and the center to find the length of the transverse axis (2a).
3. Calculate the distance between a focus and the center to find the focal distance (c).
4. Use the relationship c^2 = a^2 + b^2 to determine the length of the conjugate axis (2b).
5. Write the standard form equation based on the orientation of the hyperbola.
Step 1: Determine the center of the hyperbola.
The center of the hyperbola is the midpoint of the line segment joining the two vertices. Since the vertices are at (-10, -15) and (70, -15), the center (h, k) can be found as follows:
h = (-10 + 70) / 2 = 60 / 2 = 30
k = (-15 + (-15)) / 2 = -30 / 2 = -15
So, the center of the hyperbola is at (30, -15).
Step 2: Calculate the length of the transverse axis (2a).
The distance between the vertices is the length of the transverse axis. The vertices are 80 units apart because they are at (-10, -15) and (70, -15). This means:
2a = 80
a = 40
Therefore, the length of the semi-transverse axis a is 40 units.
Step 3: Calculate the focal distance (c).
The focal distance is the distance between the center and one of the foci. We were given one focus at (-11, -15). Since the center is at (30, -15), the focal distance c is:
c = |30 - (-11)| = |30 + 11| = 41
Step 4: Use the relationship c^2 = a^2 + b^2 to determine b.
We know that a = 40 and c = 41. Plugging these values into the relationship gives us:
41^2 = 40^2 + b^2
1681 = 1600 + b^2
b^2 = 1681 - 1600
b^2 = 81
b = 9
Therefore, the length of the semi-conjugate axis b is 9 units.
Step 5: Write the standard form equation.
Since the hyperbola is horizontal (the vertices have the same y-coordinate), the standard form of its equation is:
(x - h)^2 / a^2 - (y - k)^2 / b^2 = 1
Plugging in the values for h, k, a, and b, we get:
(x - 30)^2 / 40^2 - (y + 15)^2 / 9^2 = 1
Simplify further by squaring the values of a and b:
(x - 30)^2 / 1600 - (y + 15)^2 / 81 = 1
This is the standard form of the equation of the hyperbola with vertices at (-10, -15) and (70, -15) and one of its foci at (-11, -15).
the longest runway at an airport has the shape of a rectangle with an area of 2181600sqft. this runway is 180 ft wide. how long is the runway
The widrh of a rectangle is w yards and the length of a rectangle is (6w-4) yards. The perimeter of the rectangle is given by the algebraic expression 2w+2(6w-4). Simplify the algebraic expression 2w+2(6w-4) and determine the perimeter of a rectangle whose width w is 4 yards
p=2w+2(6w-4) can be simplified to:
p=2w+12w-8
p=14w-8
if w=4
p=14(4)-8
p=56-8 = 48 yards
check:
w = 4
length = 6w-4= 6(4)-4 = 24-4=20
perimeter = 4*2 + 20*2 = 8+40 = 48
it checks out, perimeter = 48 yards
is the graph of y=sin(x^6) increasing or decreasing when x=12
Show that the series is convergent. how many terms of the series do we need to add in order to find the sum to the indicated accuracy? sum_(n=1)^(infinity) (-1)^(n+1)/( n^7)text( ) \(|text(error)| < 0.00005 \)
The series is convergent, but the number of terms needed to find the sum to a specific accuracy cannot be determined.
Explanation:To determine the convergence of the series sum_(n=1)^(infinity) (-1)^(n+1)/( n^7), we can use the Alternating Series Test. The Alternating Series Test states that if the terms of a series alternate in sign and decrease in absolute value, then the series is convergent. In this case, the terms of the series alternate in sign and decrease as n increases, so the series is convergent.
To find the number of terms needed to achieve a sum with an error less than 0.00005, we need to use the Remainder Estimation Theorem. However, this theorem requires that the terms of the series decrease in absolute value, which is not the case in this series. Therefore, we cannot determine the number of terms needed to reach the desired accuracy.
Overall, the series is convergent, but we cannot determine the number of terms needed to reach a specific accuracy.
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What is the standard form of 8 hundreds + 2 hundreds
The standard form of 8 hundred + 2 hundred will be 1000.
What is the standard form of the number?A number can be expressed in a fashion that adheres to specific standards by using its standard form. Standard form refers to any number that may be expressed as a decimal number between 1.0 and 10.0 when multiplied by a power of 10.
Given that the number is 8 hundred + 2 hundred the standard form of the number will be:-
Standard form = 8 hundreds + 2 hundreds
Standard form = 800 + 200
Standard form = 1000
Therefore, the standard form of 8 hundred + 2 hundred will be 1000.
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solve for m
2m = -6n -5; n = 1, 2 ,3
Evaluate the surface integral s f · ds for the given vector field f and the oriented surface s. in other words, find the flux of f across s. for closed surfaces, use the positive (outward) orientation. f(x, y, z) = x i + y j + 10 k s is the boundary of the region enclosed by the cylinder x2 + z2 = 1 and the planes y = 0 and x + y = 2
What expression is equivalent to 10x2y+25x2
A section of land has an area of 1 square mile and contains 640 acres. determine the number of square meters in an acre
An acre, a unit of area commonly used in the Imperial and U.S. customary systems, is approximately 4047 square meters. This is calculable by using the known conversions between acres, square miles, and square meters.
Explanation:To determine the number of square meters in an acre, it's helpful to understand the relationship between these units. A square mile is equivalent to 640 acres. Therefore, the area of one acre is 1/640 of a square mile. However, these are both Imperial measurements, and we want to convert to a metric measurement - square meters.
To make this conversion, we need to identify the conversion factor between square miles and square meters. There are 2,589,988.11 square meters in a square mile.
Our starting point is that 1 acre = 1/640 square mile. Next, we substitute the number of square meters in a square mile:
1 acre = 1/640 x 2,589,988.11 square meters = 4046.86 square meters.
Therefore, there are approximately 4047 square meters in an acre.
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The Center of the Circle is at the origin on a coordinate grid. The vertex of a Parabola that opens upward is at (0,9). If the Circle intersects the parabola at the parabola's vertex, which Statement must be true?
The parabola and the circle have the same axis of symmetry, and can intersect at one point only.
The statement that must be true is; The maximum number of solution is one
Reason:
The given parameters are;
Location of the center of the circle = The origin (0, 0)
Location of the vertex of the parabola opening upwards = (0, 9)
Point where the circle intersects the parabola = The vertex
Required:
The statement that must be true
Solution;
The equation of the circle is x² + y² = r²
The vertex (0, 9) is a point on the circle, therefore;
0² + 9² = r²
The radius, r = 9
The highest point on the circle is the point with the maximum vertical
distance from the center, which is the point (0, 9), which is also the lowest
point on the parabola.
Therefore, the parabola and the circle can intersect at only the point (0, 9),
which gives;
The maximum number of solution is one.
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In the first 120 miles over 240 mile journey a truck driver maintained an average speed of 50 mph what was his average featuring the next 120 miles if the average speed of the entire trip with 60 mph
If 5x=17, what is the value of 15x-11
5x=17
x=17/5 = 3.4
15x-11 =
15(3.4)-11 = 51-11 = 40
If 2^m = 4x and 2^w = 8x, what is m in terms of w?
Select the correct inequality for the graph below: A solid line passing through points (1, 2) and (2, 5) has shading below. y < 3x − 1 y ≤ 3x − 1 y ≥ 3x − 1 y > 3x − 1
Here is your answer:
Solving the equation:
[tex] (5-2)\div(2-1)= 3 [/tex][tex] \frac{y - y1}{(x - x1) } [/tex][tex] y-5=3(x-2) [/tex][tex] y= 3x- 6+ 5 [/tex]" [tex] y= 3x-1 [/tex] " or option B.Hope this helps!
Step 1
Find the equation of the line that passes through points [tex](1, 2)[/tex] and [tex](2, 5)[/tex]
Find the slope of the line
The formula to calculate the slope is equal to
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
substitute the values
[tex]m=\frac{5-2}{2-1}[/tex]
[tex]m=\frac{3}{1}[/tex]
[tex]m=3[/tex]
Find the equation of the line
The equation of the line into slope-point form is equal to
[tex]y-y1=m(x-x1)[/tex]
we have
[tex]m=3[/tex]
[tex](1, 2)[/tex]
substitutes
[tex]y-2=3(x-1)[/tex]
[tex]y=3x-3+2[/tex]
[tex]y=3x-1[/tex]
Step 2
Find the equation of the inequality
we know that
The solution is the shaded area below the solid line
therefore
the inequality is
[tex]y\leq 3x-1[/tex]
the answer is
[tex]y\leq 3x-1[/tex]
see the attached figure to better understand the problem
What is greater: a half dozen dozen pair of shirts or a half of two dozen dozen shirts
From the computation, a half of two dozen shirts will be greater.
A dozen = 12
It should be noted that a half dozen pair of shirts will be:
= 1/2 × 12
= 6 shirts
A half of two dozen shirts will be:
= 1/2 × (2 × 12)
= 12 shirts
Therefore, a half of two dozen shirts will be greater.
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The average winter snowfall in City A is 105 cm. City B usually gets 2.8 m of snow each winter. Compare the yearly snowfall in the two cities. Complete parts a and b. (A) the difference in one year is __ m. (B) the difference over two years is ___ cm
A carpenter is assigned the job of expanding a rectangular deck where the width is one-fourth the length. The length of the deck is to be expanded by 6 feet, and the width by 2 feet. If the area of the new rectangular deck is 68 ft2 larger than the area of the original deck, find the dimensions of the original deck.
A ship traveled at an average rate of 22 miles per hour going east. It then traveled at an average rate of 17 miles per hour heading north. If the ship traveled a total of 212 miles in 11 hours, how many miles were traveled heading east?
The price of an item has been reduced by 15% . The original price was $51 .
The question is about calculating the new price of an item after a discount. The original price of the item was $51.00, and it was reduced by 15%, making the new price $43.35.
Explanation:The subject of this question is Mathematics and it is looking for a solution to a percentage price reduction problem. The item had an original price of $51.00 and its price has been reduced by 15%. To find the new price after the discount, we have to calculate the amount of the reduction and subtract it from the original price.
First, let's calculate the amount of the discount: 15/100 * 51 = $7.65.}
Now, we subtract this amount from the original price: 51 - 7.65 = $43.35.
Therefore, the new price of the item after a 15% discount is $43.35.
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Derek and Mia place two green marbles and one yellow marble in a bag. Somebody picks a marble out of the bag without looking and records its color (G for green and Y for yellow). They replace the marble and then pick another marble. If the two marbles picked have the same color, Derek loses 1 point and Mia gains 1 point. If they are different colors, Mia loses 1 point and Derek gains 1 point. What is the expected value of the points for Derek and Mia?
Answer:
Thus, the expected value of points for Derek and Mia are [tex]\dfrac{-1}{9}[/tex] and [tex]\dfrac{1}{9}[/tex] respectively.
Step-by-step explanation:
Number of green marbles = 2 and Number of Yellow marbles = 1
Then, total number of marbles = 2+1 = 3
A person selects two marbles one after another after replacing them.
So, the probabilities of selecting different combinations of colors are,
[tex]1.\ P(GG)=P(G)\times P(G)\\\\P(GG)=\dfrac{2}{3}\times \dfrac{2}{3}\\\\P(GG)=\dfrac{4}{9}[/tex]
[tex]2.\ P(GY)=P(G)\times P(Y)\\\\P(GY)=\dfrac{2}{3}\times \dfrac{1}{3}\\\\P(GY)=\dfrac{2}{9}[/tex]
[tex]3.\ P(YG)=P(Y)\times P(G)\\\\P(YG)=\dfrac{1}{3}\times \dfrac{2}{3}\\\\P(YG)=\dfrac{2}{9}[/tex]
[tex]4.\ P(YY)=P(Y)\times P(Y)\\\\P(YY)=\dfrac{1}{3}\times \dfrac{1}{3}\\\\P(YY)=\dfrac{1}{9}[/tex]
Now, we have that,
If two marbles are of same color, then Mia gains 1 point and Derek loses 1 point.
If two marbles are of different color, then Derek gains 1 point and Mia loses 1 point.
Also, the expected value of a random variable X is [tex]E(X)=\sum_{i=1}^{n} x_i\times P(x_i)[/tex].Then, the expected value of points for Derek is,
[tex]E(D)= (-1)\times \dfrac{4}{9}+1\times \dfrac{2}{9}+1\times \dfrac{2}{9}+(-1)\times \dfrac{1}{9}\\\\E(D)= \dfrac{-5}{9}+\dfrac{4}{9}\\\\E(D)=\dfrac{-1}{9}[/tex]
And the expected value of points for Mia is,
[tex]E(M)= 1\times \dfrac{4}{9}+(-1)\times \dfrac{2}{9}+(-1)\times \dfrac{2}{9}+1\times \dfrac{1}{9}\\\\E(M)= \dfrac{5}{9}-\dfrac{4}{9}\\\\E(M)=\dfrac{1}{9}[/tex].
Thus, the expected value of points for Derek and Mia are [tex]\dfrac{-1}{9}[/tex] and [tex]\dfrac{1}{9}[/tex] respectively.
Answer: P(GG)= 4/9
P(GY)= 2/9
P(YG)= 2/9
P(YY)= 1/9
Derek, E(X) = -1/9
Mia, E(X) = 1/9
Step-by-step explanation: just did it on edge
Definition 7.1.1 laplace transform let f be a function defined for t ≥ 0. then the integral {f(t)} = ∞ e−stf(t) dt 0 is said to be the laplace transform of f, provided that the integral converges. to find {f(t)}. f(t) = cos t, 0 ≤ t < π 0, t ≥ π