What is the stoichiometric coefficient for oxygen when the following equation is balanced using the lowest, whole-number coefficients? ________ C2H6O (l) + ________ O2(g) → ________ CO2(g) + ________ H2O(l)

The major species when ammonium bromate is dissolved in water are ammonium ions, bromate ions, hydronium ions, and ammonia.

When solid ammonium bromate is dissolved in water, the major species in solution are ammonium ions (NH₄⁺) and bromate ions (BrO₃⁻). In an aqueous solution, the ammonium ion is a weak acid, which can donate a proton to water, forming hydronium ions (H₃O⁺) and ammonia (NH₃), hence making the solution slightly acidic. The bromate ion is a stable species that does not further react in water. Therefore, the major species in solution are NH₄⁺, BrO₃⁻, H₃O⁺, and some unreacted NH₃.

the correct answer is 2

The complete electron configuration for the common monatomic ion formed by calcium (Ca) is [Ar]4s².

Calcium (Ca) is located in the second column of the s block. We would expect its electron configuration to end with 4s². The complete electron configuration for calcium is [Ar]4s². When calcium forms a monatomic ion, it loses its two valence electrons, resulting in a 2+ charge and an electron configuration of 1s²2s²2p⁶3s²3p⁶. The calcium ion (Ca²+) is therefore isoelectronic with the noble gas argon (Ar).

The answer is there are 9.57 x 10²⁰ number of Cl atoms are in 0.0728 g of PCl₃.

Number of moles = mass / molar mass

Mass of PCl₃ = 0.0728 g and molar mass of PCl₃ = 137.33g/mol

Number of moles of PCl₃ = 0.0728 / 137.33 = 5.3 x 10⁻⁴

In one mole there are Avogadro’s number of molecules that is 6.02 x 10²³

So, in 5.3 x 10⁻⁴ moles of PCl₃, there are =5.3 x 10⁻⁴ x 6.02 x 10²³ = 3.19 x 10²⁰

Now there is 3 atoms of Cl in PCl₃ so in 3.19 x 10²⁰ molecules of PCl₃, number of Cl atoms = 3.19 x 10²⁰ x 3 = 9.57 x 10²⁰ atoms

To find the number of chlorine atoms in a given mass of PCl3, you calculate the number of moles of PCl3, using its molar mass. Then, multiply the number of moles by three (since there are three chlorine atoms in each molecule of PCl3), and then use Avogadro's number to convert the number of moles to atoms. The resulting number is 9.56 x 10^20 Cl atoms.

First, determine the molar mass of PCl3. Phosphorus (P) has an atomic mass of about 31g/mol, and Chlorine (Cl) has an atomic mass of about 35.5 g/mol. Since there are three chlorine atoms in PCl3, the molar mass of PCl3 becomes 31 + 3 * 35.5 = 137 g/mol.

Then, calculate the number of moles in 0.0728 g of PCl3. This is done by dividing the mass of the sample by the molar mass of PCl3: 0.0728 g / 137 g/mol = 0.000531 moles of PCl3.

Since each mole of PCl3 contains three moles of Cl, we multiply the number of moles of the compound by three to get the number of moles of Cl: 0.000531 moles * 3 =  0.00159 moles of Cl.

Then, using Avogadro's number (6.02 x 10^23), we can convert the number of moles to the number of atoms. 0.00159 moles * 6.02 x 10^23 atoms/mol = 9.56 x 10^20 atoms.

So, there are around 9.56 x 10^20 atoms of chlorine (Cl) in a 0.0728 g sample of PCl3.

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The electron configuration of carbon atom in its ground state is 1s² 2s² 2p². After sp hybridization, one 2s electron gets excited to the 2p orbital forming four unpaired electrons ready for bonding. These form two sp hybrid orbitals, leaving the remaining two 2p orbitals with single electrons.

The electron configuration for a carbon atom (C) in its ground state is 1s² 2s² 2p², represented by an orbital diagram with two arrows in the 1s box, two in the 2s, and two single arrows in two of the three 2p boxes, indicating paired and unpaired electrons respectively.

During sp hybridization, one of the 2s electrons gets excited and moves to the 2p orbital, leading to four unpaired electrons ready for bonding. These mix to form two sp orbitals. In the electron configuration diagram, the two sp hybrid orbitals would have a single electron each, leaving the remain two 2p orbitals also with single electrons. Remember, these are depicted as boxes, each with a single upward arrow.

The distinction between the carbon atom's electron configurations before and after sp hybridization is essential in understanding its bonding behaviour and the formation of diverse organic compounds.

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Answer is:

A. Real gases may be expected to deviate from Charles's law at high pressures.

C. Real gases may be expected to deviate from Charles's law near the liquefaction temperature.

At high pressure gas molecules are close to one another and near the liqueffaction temperature energy is very low.

Charles' Law (The Temperature-Volume Law) - the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:  

V₁/T₁ = V₂/T₂.  

When temperature goes down, the volume also goes down.

The formula for ideal gas law is:

P V = n R T

where

P is pressure = ?

V is volume = 1.50 L

n is number of moles = 1.57 mol

R is gas constant = 0.08205746 L atm / mol K

T is temperature = 273 K

P = 1.57 mol * 0.08205746 L atm / mol K * 273 K / 1.50 L

P = 23.45 atm

To solve this problem, we use the formula:

M1 V1 = M2 V2

To calculate for the total final volume V2:

V2 = M1 V1 / M2

V2 = 1.65 M * 12 mL / 0.495 M

V2 = 40 mL

Since final volume is 40 mL so water needed is:

water volume = 40 mL – 12 mL

water volume = 28 mL

The dehydration of 2-heptanol would yield 2-heptene as the major product along with 1-heptene as a minor product, while the dehydration of 2-methyl-1-cyclohexanol would yield 1-methyl-1-cyclohexene as the major product along with other isomeric alkenes as minor products.

The products obtained by the dehydration of 2-heptanol and 2-methyl-1-cyclohexanol can be predicted based on the rules of alkene formation during dehydration reactions.

For 2-heptanol, the dehydration follows Zaitsev's rule, which states that the more substituted alkene is the major product. In this case, dehydration of 2-heptanol would yield a mixture of alkenes, with the most substituted alkene, 2-heptene, as the major product, and the less substituted alkene, 1-heptene, as a minor product. The reaction can be represented as follows:

[tex]\[ \text{CH}_3\text{CH}(\text{OH})\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_3 \rightarrow \text{CH}_3\text{CH}=\text{CHCH}_2\text{CH}_2\text{CH}_3 + \text{CH}_3\text{CH}_2\text{CH}=\text{CHCH}_2\text{CH}_3 \][/tex]

For 2-methyl-1-cyclohexanol, the dehydration would also follow Zaitsev's rule. However, since the hydroxyl group is on a cyclohexane ring, the dehydration would lead to the formation of an alkene within the ring. The most substituted alkene that can be formed is 1-methyl-1-cyclohexene. The reaction can be represented as follows:

[tex]\[ \text{C}_6\text{H}_{11}\text{CH}(\text{OH})\text{CH}_3 \rightarrow \text{C}_6\text{H}_{11}\text{C}(\text{CH}_3)=\text{CH}_2 + \text{isomeric alkenes} \][/tex]

In summary, the dehydration of 2-heptanol would yield 2-heptene as the major product along with 1-heptene as a minor product, while the dehydration of 2-methyl-1-cyclohexanol would yield 1-methyl-1-cyclohexene as the major product along with other isomeric alkenes as minor products.

Pressure that is exerted by one gas as if it occupied a container by itself

Considering the Dalton's partial pressure, the correct answer is the second option: "pressure that is exerted by one gas as if it occupied a container by itself" defines partial pressure in a mixture of gases.

The pressure exerted by a particular gas in a mixture is known as its partial pressure.

So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

[tex]P_{T}=P_{1} +P_{2} +...+P_{n}[/tex]

where n is the amount of gases present in the mixture.

This relationship is due to the assumption that there are no attractive forces between the gases.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture. The mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component to the number of moles of all the components present.

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

[tex]P_{A} =x_{A} P_{T}[/tex]

In summary, the correct answer is the second option: "pressure that is exerted by one gas as if it occupied a container by itself" defines partial pressure in a mixture of gases.

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A neutral atom of potassium (K) has an average mass of 39 amu and 19 electrons. It has 20 neutrons. Thus, the correct option for this question is C.

Electrons may be characterized as the type of subatomic particles which are consistently revolving within the orbitals around the nucleus. These subatomic particles are negatively charged in nature. J.J. Thomson is known as the discoverer of these subatomic particles.

It is clearly mentioned in the question that an atom is neutral which means the number of positively charged particles (protons) is equal to the number of negatively charged particles (electrons). So, the number of protons is also 19.

Now, the number of neutrons is determined by the following formula:

The number of neutrons = Atomic mass - Number of protons.

                                  = 39 - 19 = 20.

Therefore, a neutral atom of potassium (K) has an average mass of 39 amu and 19 electrons. It has 20 neutrons. Thus, the correct option for this question is C.

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In the integumentary system, the white reaction is caused by vasoconstriction, which is the narrowing of blood vessels. The red reaction is caused by vasodilation, which is the widening of blood vessels.

The white reaction and the red reaction are two types of skin reactions that can occur in response to an injury or irritation.

The white reaction is usually a temporary reaction that goes away on its own within a few minutes or hours. The red reaction can last longer, depending on the severity of the injury or irritation. The triple reaction is usually caused by a more severe injury or irritation than the white or red reactions. It can also be a sign of an allergic reaction.

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The integumentary system undergoes changes as a person ages, resulting in a thinner epidermis and slower wound healing. Both the white and red reactions are affected by these changes.

The integumentary system undergoes changes as a person ages, leading to a thinner epidermis and slower wound healing. These changes are reflected in both the white and red reactions of the integumentary system. The white reaction refers to decreased mitosis in the stratum basale, resulting in a thinner epidermis. The red reaction relates to the reduced ability of the dermis to regenerate, leading to slower wound healing.

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The bond enthalpy is the energy required to break a chemical bond. The bond enthalpy of NO2 is lower than NO because NO2 has a double bond which is stronger and thus requires more energy to break compared to the single bond in NO.

The bond enthalpy, or energy, is a measure of the strength of a chemical bond. It is identified by the energy required, in joules or kilojoules per mole (kJ/mol), to break a chemical bond. In this case, we are comparing the bond enthalpy of NO, a molecule with a single bond, and that of NO2, a molecule with double bonds between the atoms.

The bond enthalpy in NO is 632 kJ/mol and that of each NO bond in NO2 is 469 kJ/mol. The difference in bond enthalpies is due to the difference in the number of electron pairs in the bond. The strength of a bond between two atoms increases as the number of electron pairs in the bond increases. Simply put, a single covalent bond (as in NO) is typically weaker than a double bond (as present in NO2), and therefore, requires less energy to break. Hence the bond enthalpy is lower for NO2 as it is harder to break its double bond.

It's important to remember that the exact values of bond enthalpy also depend on the specific atoms in the bond and their electronegativity, which is why there are some discrepancies seen in bond enthalpies in different molecules.

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By following these steps, you can prepare 40 liters of 0.02 M phosphate buffer with a pH of 6.9 using solid Na3PO4 and 1M HCl:

Step 1: Calculate the amount of Na3PO4 required

Step 2: Prepare the Na3PO4 solution

Step 3: Calculate the amount of HCl required

Step 4: Adjust the pH

To prepare 40 liters of 0.02 M phosphate buffer solution with a pH of 6.9, starting from solid Na3PO4 and 1M HCl, we can follow these steps:

Step 1: Calculate the amount of Na3PO4 required

The phosphate buffer will be prepared using the following equilibrium reaction:

Na3PO4 + 3HCl → 3NaCl + H3PO4

We need to calculate the amount of Na3PO4 required to make a 0.02 M solution in 40 liters.

First, calculate the moles of phosphate ions required:

Moles of phosphate ions = Molarity × Volume

Moles of phosphate ions = 0.02 mol/L × 40 L = 0.8 moles

Since Na3PO4 dissociates into three moles of phosphate ions, the moles of Na3PO4 needed will be one-third of the moles of phosphate ions:

Moles of Na3PO4 = 0.8 moles / 3 = 0.2667 moles

Step 2: Prepare the Na3PO4 solution

Weigh out the calculated amount of Na3PO4 and dissolve it in water to make up the 40 liters of solution.

Step 3: Calculate the amount of HCl required

The pH of the buffer is adjusted using HCl. To achieve a pH of 6.9, we need to calculate the amount of 1M HCl needed.

Step 4: Adjust the pH

Add the calculated amount of 1M HCl to the Na3PO4 solution while monitoring the pH using a pH meter or pH paper. The pH should be adjusted to 6.9 by adding small amounts of HCl at a time and then checking the pH until the desired pH is reached.

By following these steps, you can prepare 40 liters of 0.02 M phosphate buffer with a pH of 6.9 using solid Na3PO4 and 1M HCl.

The probable question may be:

Describe the preparation of 40 liters of 0.02 M phosphate buffer, pH 6.9, starting from solid Na3PO4 and 1M HCl.

Explosion of fireworks represents a chemical change because explosion causes chemical reaction due to which chemical properties change.

Chemical changes occur when chemical reactions take place.During chemical reactions, bonds between atoms break due to which properties change.

Bending of wire only causes change in physical property that is shape and there is no change in chemical properties or constituents of wire.Freezing of water changes the state of water to solid but does not change it's properties.

Melting of wax candle  only changes the state of candle from solid to molten form it does not alter its chemical properties.During explosion of fireworks there is chemical change taking place along with which large amount  of energy is released.

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Prokaryotic cells are found in bacteria and archaea.

Prokaryotic cells are a type of cell that lacks a nucleus and other membrane-bound organelles. They are found in bacteria and archaea, which are two domains of microorganisms.

Prokaryotic cells are structurally simpler compared to eukaryotic cells, which are found in plants, animals, fungi, and protists.

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Answer:

C, E, H, A, B, F, K, D, L, G, J, I.

Explanation:

Hello,

In this case we are dating each layer based on its deepness as the deeper the layer is, the farther back in time it is (older). In such a way, the youngest layer is C and henceforth by going down, we find older and older layers no matter if the layer is horizontal or diagonal, we just go down by straight line, therefore, from youngest to oldest, the order turn out into:

C, E, H, A, B, F, K, D, L, G, J, I.

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A lithium atom always contains three protons located in its nucleus, defining its atomic number as 3, regardless of the isotope.

The number and location of protons in a lithium atom is universally three within its nucleus. This constant feature defines the element lithium (Li) and gives it an atomic number of 3. Lithium atoms can, however, have different numbers of neutrons, resulting in isotopes with different mass numbers such as Lithium-6 (three neutrons) and Lithium-7 (four neutrons). Despite these differences, the number of protons remains constant at three, which is a characteristic trait of the lithium element.

After heating, approximately 15.65 g of anhydrous magnesium sulfate will remain from the original 32.0 g of magnesium sulfate heptahydrate.

Identify the Molar Masses:

Calculate the Moles of MgSO₄·7H₂O:

Determine the Moles of Anhydrous MgSO₄:

Calculate the Mass of Anhydrous MgSO₄: