What is the value of c? 14=2c−6+3c Enter your answer in the box.

Answer: B) 5, −3, 1 over 2 are the zeros of f(x).

Step-by-step explanation:

Given function f(x)=[tex]2x^3-5x^2-28x+15[/tex]

If a is a zero of f(x) then f(a)=0

Let's check all the options

[tex]f(5)=2(5)^3-5(5)^2-28(5)+15\\=2(125)-5(25)-28(5)+15=250-125-140+15=0[/tex]

[tex]f(-3)=2(-3)^3-5(-3)^2-28(-3)+15\\=2(-27)-5(9)-28(-3)+15=-54-45+84+15=0[/tex]

[tex]f(\frac{-1}{2})=2\frac{-1}{2}()^3-5(\frac{-1}{2})^2-28(\frac{-1}{2})+15\\=2(\frac{-1}{8})-5(\frac{-1}{4})+14+15=\frac{-1}{4}-\frac{5}{4}+29=\frac{110}{4}=\frac{55}{2}\neq 0[/tex]

Therefore , 5 and -3 are zeroes of f(x).but -1/2 is not.

[tex]f(\frac{1}{2})=2\frac{1}{2}()^3-5(\frac{1}{2})^2-28(\frac{1}{2})+15\\=2(\frac{1}{8})-5(\frac{1}{4})-14+15=\frac{1}{4}-\frac{5}{4}-14+15=0[/tex]

⇒ 1/2 isthe third zero of f(x).

Here we got our three zeroes as 5,-3,1/2,rest other will not satisfy f(a)=0

Therefore B represents the zeroes of f(x).

Answer:

To find the area of a rectangle, you do Length times width. 11 times 8 equals 88, so the width would have to be 8. To find the perimeter, you add up all of the sides. If the width is 8, and the perimeter is 46, 8+8=16 and 48-16 = 30 then the length is 15.

Answer:

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Step-by-step explanation:

some 4 u to do

tell me answer after ur done

Answer: 24 Units squared

Step-by-step explanation:

The equation of the required line is: y=-x-1.

y=2x-1 is in slope intercept form. So the y-intercept = -1.

Given that the line intersects with y=2x-1 on the y-axis. It means the required line also has y-intercpt =b= -1.

Given that: The line is parallel to y=-x.

The slope of y=-x is -1. By comparing with y=mx+b.

Since the lines are parallel. So the required line will also have slope = m= -1.

So the equation of the required line is: y=mx+b or y = -1x + (-1) or y=-x-1.

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Answer:

1. B. (8 x 20) - (8 x 1)

2. D. (2 x 9) + (2 x 3)

3. A. (7 x 50) - (7 x 2) = 350 - 14 = 336

4. C. (9 x 80) + (9 x 1) = 729

Answer:

The given graph is : f(x) = [tex]3^x[/tex]

The  graph g(x) is transformation of graph f(x).

The curve g(x) passes through (-2,2) and (-1,4).

Let (a,b) be any point on f(x).After translation  new curve g(x) is obtained which is parallel to line, y=1 or asymptode is ,y=1 or when y becomes 1 the graph becomes parallel to x axis.

g(x)= y-1=[tex]3^{x+2}[/tex]

g(x) = y = [tex]3^{x+2} +1[/tex] is the graph of translated curve.

The two graph is depicted below.

On simplification of inequality x + 10 > 2, we get x>-8.

The given question is related to algebra and inequalities.

To solve the inequality 'x + 10 > 2', we need to isolate x.

Subtract 10 from both sides: x + 10 - 10 > 2 - 10.

This simplifies to: x > -8.

The expression to represent the temperature 'h' hours after 1 p.m. given an initial temperature of 73°F and a decrease rate of 1.5°F per hour is 73 - 1.5h. This allows us to calculate the temperature at any given hour where 'h' is the number of hours after 1 p.m.

The problem involves dealing with linear equations, specifically those representing changes over time. In this situation, the temperature starts at 73°F at beginning of the time, i.e., at 1 pm and then decreases at a steady rate of 1.5°F per hour.

So, the decrease in temperature can be represented by 1.5h, where h is the number of hours elapsed since 1 p.m. As the temperature starts at 73°f, we subtract this decrease from the initial temperature. Therefore, the expression to determine the temperature after h hours is 73 - 1.5h.

This equation tells us that for each hour after 1 p.m., we simply subtract 1.5 from 73 and this would give the temperature at that time. For example, at 2 p.m., h equals 1, and the equation 73 - 1.5(1) gives us 71.5°F.

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The loss of each owner of the catering company is 22 dollars.

Average is the sum of the total weights of each individual divided by the number of individuals.

Given that a catering company loses 110 dollars as a result of the delay and the company has 5 owners and they share the loss equally.

As the loss has been shared by the owners equally we have to divide the total loss occurred by the total no. of owners to obtain the amount of loss for each individual which is,

= 110/5 dollars.

= 22 dollars.

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Answer:

[tex]2 a^3 b^4 (a^3 - 11 a b + 8 b^3)[/tex]

Step-by-step explanation:

The given expression is

[tex]16a^3b^7 + 2a^6b^4 -22a^4b^5[/tex]

We need to find the factored form of the given expression.

In the given expression [tex]2 a^3 b^4[/tex] is the greatest common factor of all terms.

Taking GCF we get.

[tex]2 a^3 b^4 (8 b^3+a^3 - 11 a b)[/tex]

In can be written as

[tex]2 a^3 b^4 (a^3 - 11 a b + 8 b^3)[/tex]

This expression is the complete factored form of the given expression because [tex]a^3 - 11 a b + 8 b^3[/tex] can not be factored further.

Therefore, the factor form of given expression is [tex]2 a^3 b^4 (a^3 - 11 a b + 8 b^3)[/tex].

Total time driving to and from beach: 12.3 hours; averaging 58 mph there, 65 mph returning home.

To find the total time Paul's family spent driving to and from the beach, we can calculate the time for each leg of the trip and then add them together.

1. Time taken for the trip to the beach:

[tex]\[ \text{Time}_1 = \frac{\text{Distance}_1}{\text{Speed}_1} \][/tex]

2. Time taken for the return trip:

[tex]\[ \text{Time}_2 = \frac{\text{Distance}_2}{\text{Speed}_2} \][/tex]

Given:

[tex]- Distance to the beach, \( \text{Distance}_1 = 377 \) miles\\- Speed to the beach, \( \text{Speed}_1 = 58 \) mph\\- Speed returning home, \( \text{Speed}_2 = 65 \) mph[/tex]

Let's calculate:

[tex]1. \[ \text{Time}_1 = \frac{377}{58} \][/tex]

[tex]2. \[ \text{Time}_2 = \frac{377}{65} \][/tex]

Now, let's compute:

[tex]\[ \text{Time}_1 = \frac{377}{58} \approx 6.5 \text{ hours} \]\[ \text{Time}_2 = \frac{377}{65} \approx 5.8 \text{ hours} \][/tex]

Finally, to find the total time spent driving to and from the beach, we add these times:

[tex]\[ \text{Total time} = \text{Time}_1 + \text{Time}_2 \]\[ \text{Total time} \approx 6.5 + 5.8 \]\[ \text{Total time} \approx 12.3 \text{ hours} \][/tex]

So, Paul's family spent approximately 12.3 hours driving to and from the beach.