What is the value of x? 3 /4 x+5− 1 /2 x=3

Answer:

Last graph is the answer.

Step-by-step explanation:

The inequalities are y < [tex]\frac{2}{3}x[/tex] and y ≥ -x + 2

Now first inequality y < [tex]\frac{2}{3}x[/tex] will represent a dotted line passing through origin and a point (3, 2)

This inequality will be in the form a dotted line and shaded area will be below the line.

Second inequality is y ≥ -x + 2

Line representing the inequality will be solid in shape and shaded area will be above this line.

Common shaded area of both the inequalities matches with the last option.

Therefore, Last option (second row last figure) will be the answer.

Answer:

the answer is c} 375

(5,-1) because it would turn the points to their opposite "charge" and turn the positive to a negative and a negative to a positive

For the function f (x) = 15x - 7, the value of f ⁻¹ (x) is,

⇒ f ⁻¹ (x) = (x + 7) / 15

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that;

The function is,

⇒ f (x) = 15x - 7

Now, We can find the inverse of f (x) as;

⇒ f (x) = 15x - 7

Substitute y = f (x),

⇒ y = 15x - 7

Solve for x;

⇒ y + 7 = 15x

⇒ x = (y + 7) / 15

Hence, We get;

⇒ f ⁻¹ (x) = (x + 7) / 15

Thus, The inverse function is,

⇒ f ⁻¹ (x) = (x + 7) / 15

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Answer:

The tip of the minute hand moves approximately 37.7 inches in 15 minutes.

Explanation:

To find how far the tip of the minute hand moves in 15 minutes, we can use the formula for the circumference of a circle:

[tex]\[ \text{Circumference} = 2 \pi r \][/tex]

Where:

- [tex]\( r \)[/tex] is the length of the minute hand (radius of the circle).

Given:

- The length of the minute hand, [tex]\( r = 6 \)[/tex] inches.

Substitute the given value into the formula:

[tex]\[ \text{Circumference} = 2 \pi \times 6 \][/tex]

[tex]\[ \text{Circumference} = 12 \pi \][/tex]

So, the tip of the minute hand moves a distance of [tex]\( 12 \pi \)[/tex] inches in 15 minutes.

To approximate this value:

[tex]\[ 12 \pi \approx 37.7 \][/tex] inches (rounded to one decimal place).

1/2 x 80 x 60 = 2400 square feet was the area

log(35) = 1.544

 rounded to nearest tenth = 1.5

Answer: The magnitude of the earthquake that is 35 times more intense than a standard earthquake=1.5

Step-by-step explanation:

Given : The magnitude M of an earthquake is defined to be  [tex]M=\log \frac{I}{S}[/tex]---(1)

, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and

S is the intensity of a “standard” earthquake, which is barely detectable.

If  the magnitude of an earthquake that is 35 times more intense than a standard earthquake

⇒Intensity of earthquake I=35 S

Substitute the value of I in (1), we get [tex]M=\log(\frac{35S}{S})=\log(35)=\log(5\times7)=1.544068[/tex] [tex]\approx1.5[/tex]

∴ The magnitude of the earthquake that is 35 times more intense than a standard earthquake=1.5

Answer:

A) Variables

A) Independent

A) X

Step-by-step explanation:

The expression for the 1 less than the quotient of a number n and 6 is n/6 - 1.

It is defined as the combination of constants and variables with mathematical operators.

It is given that:

The word expression:

1 less than the quotient of a number n and 6:

Here n is the number:

A number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56 etc. are the numbers.

The quotient of a number n and 6 = n/6

1 less than the quotient of a number n and 6:

n/6 - 1

If in the linear expression, one variable is present, then the expression is known as the linear expression in one variable.

Thus, the expression for the 1 less than the quotient of a number n and 6 is n/6 - 1.

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Answer:50 percent

Step-by-step explanation:You need to subtract 2.25 and 1.50 and get 0.75 then divide it to 1.5 and 0.5 then convert it into decimal form and its 50%.

Answer:  The required measure of angle ABD is 148°.  

Step-by-step explanation:  Given that ray BD bisects angle CBE, ray BC is transparent to ray BA.

Also,

[tex]m\angle CBD=(3x+25)^\circ,~~m\angle DBE=(7x-19)^\circ,~~m\angle ABC=90^\circ.[/tex]

We are to find the measure of angle ABD.

Since ray BD bisects angle CBE, so we have

[tex]m\angle CBD=m\angle DBE\\\\\Rightarrow (3x+25)^\circ=(7x-19)^\circ\\\\\Rightarrow 3x+25=7x-19\\\\\Rightarrow 7x-3x=25+19\\\\\Rightarrow 4x=44\\\\\Rightarrow x=\dfrac{44}{4}\\\\\Rightarrow x=11.[/tex]

So, we get

[tex]m\angle CBD=(3\times11+25)^\circ=58^\circ.[/tex]

Therefore,

[tex]m\angle ABD=m\angle ABC+m\angle CBD=90^\circ+58^\circ=148^\circ.[/tex]

Thus, the required measure of angle ABD is 148°.  

Answer:

Option C. [tex]BC=31.2\ units[/tex]

Step-by-step explanation:

step 1

In the right triangle ABD find the length side AB

Applying the Pythagoras Theorem

[tex]AB^{2}=5^{2}+12^{2}[/tex]

[tex]AB^{2}=169[/tex]

[tex]AB=13\ units[/tex]

step 2

In the right triangle ABD

we know that

[tex]m<ABD=m<BCD[/tex]

[tex]sin(<ABD)=\frac{5}{13}[/tex] -------> equation A

step 3

In the right triangle ABC

[tex]sin(<BCD)=\frac{13}{5+DC}[/tex] ------> equation B

Remember that

[tex]m<ABD=m<BCD[/tex]

so equate equation A and equation B solve for DC

[tex]\frac{5}{13}=\frac{13}{5+DC}[/tex]

[tex]5(5+DC)=13*13[/tex]

[tex]25+5DC=169[/tex]

[tex]5DC=169-25[/tex]

[tex]5DC=144[/tex]

[tex]DC=144/5=28.8\ units[/tex]

step 4

In the right triangle BDC find the length side BC

Applying the Pythagoras Theorem

[tex]BC^{2}=28.8^{2}+12^{2}[/tex]

[tex]BC^{2}=973.44[/tex]

[tex]BC=31.2\ units[/tex]