what kinds of face shapes are the results from cuts made from parallel and perpendicular to the bases of right rectangular prisms and pyramids

Final answer:

The product of 7 times 300 is 2100, which can be expressed as 7 times 21 hundreds when considering that 300 equals 3 hundreds.

Explanation:

The student asked to find the product of 7 times 300, which can be represented algebraically as 7 × 300. To express this in terms of hundreds, we would have 7 × 3 hundreds, since 300 is the same as 3 hundreds. Following the multiplication of 7 and 3, we get 21 hundreds, which is equal to 2100. Therefore, the completed statement would be 7 × 300 = 7 × 21 hundreds.

This multiplication utilizes the concept where multiplying by a power of ten, like hundreds (102), is equivalent to moving the decimal point to the right in this case by two places.

the answer is 2(y-12)

Answer:

Sample response: The number 4 only has three factors: 1, 2, and 4. Adam probably counted the factor 2 twice.

Step-by-step explanation:

The approximate instantaneous rate of change in the intensity of light at exactly 3m from the flash bulb is -20/27 lux per meter.

The photographer uses a light meter to measure the intensity of light from a flash bulb. The intensity of the flash bulb, I, in lux, can be represented by the function I(d) = 10/d^2, where d is the distance from the light in meters.

To determine the approximate instantaneous rate of change in the intensity of light at exactly 3m from the flash bulb, we need to find the derivative of the intensity function with respect to d. Taking the derivative, we get dI/dd = -20/d^3.

Substituting d = 3 into the derivative, we get dI/dd = -20/3^3 = -20/27.

Therefore, the approximate instantaneous rate of change in the intensity of light is -20/27 lux per meter at exactly 3m from the flash bulb.

The approximate instantaneous rate of change in the intensity of light at exactly 3m from the flash bulb is approximately -0.741 lux/m.

To determine the instantaneous rate of change in the intensity of light at exactly 3m from the flash bulb, we need to find the derivative of the intensity function with respect to distance.

The intensity function is given as I(d) = 10/d^2, where d is the distance from the light in meters. To find the derivative, we can use the power rule for differentiation.

Taking the derivative of the intensity function gives us: dI/d(d) = -20/d^3.

At exactly 3 meters, the instantaneous rate of change in the intensity of light can be calculated by substituting d=3 into the derivative equation: dI/d(d) = -20/3^3 = -20/27. Therefore, the approximate instantaneous rate of change in the intensity of light at exactly 3m from the flash bulb is approximately -0.741 lux/m.

A satellite makes 26 revolutions of the earth in 6 1/2 days.

"A number expressed as a quotient, in which a numerator is divided by a denominator. "

"It is a method of finding the value of a single unit, and based on that value we can find the required value."

For given question,

A satellite makes 4 revolutions of the earth in one day.

⇒ 1 day = 4 revolutions

We need to find the number of revolutions in 6 1/2 days.

We can write the fraction [tex]6 \frac{1}{2}[/tex] as,

[tex]6 \frac{1}{2}[/tex] days

= [tex]\frac{13}{2}[/tex] days

= 6.5 days

By unitary method, for 6.5 days the number of revolutions would be,

= 6.5 × 4

= 26

Therefore, a satellite makes 26 revolutions of the earth in 6 1/2 days.

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The correct answer is:

12 rides

Explanation:

You have $35 to spend.  Taking away the admission price, $12.99, we have

35-12.99 = $22.01 left.

Each ride costs $1.75.  This means you can ride

22.01/1.75 = 12.577 or 12 rides.  (This does not round up, as you would not have enough money to ride 13 rides.)

Answer:

If the two triangles are congruent (not just similar), then QS and TV would be equal.  Thus, 3v + 2 = 7v - 6.

Solving this equation for v:  4v = 8, and v = 2.

Then QS = 3(2) + 2, or 8, and TV should be the same:  7(2) - 6 = 8.

Step-by-step explanation:

-6 because you keep change and flip the equation so....

8/-3 stays the same

you change the equation from a divide to a times

and u flip the -4/9 to get 9/-4

8/-3 X 9/-4

you can then just times the top and bottom to get

72/-12= -6

The given question is a comparison of fractions and decimals to determine the smallest number. When all values are converted to decimals for easier comparison, we find that the smallest number is 0.125, which represents the people who chose yogurt as a breakfast food, hence, yogurt got the least number of votes.

The given values in the problem represent different proportions of people's choices for breakfast. The question wants to find the breakfast food with the least number of votes. To do this, we need to understand the numerical values. All are fractions and decimal numbers that represent parts of 1 whole (or 100 percent). Here, the numbers are 3/8 for cereal, 0.125 for yogurt, 0.1875 for fruit, and 5/8 for toast. Converting all to either decimals or fractions for comparison, we get 0.375 for cereal, 0.125 for yogurt, 0.1875 for fruit, and 0.625 for toast.

Comparing these numbers, 0.125 (yogurt) is the smallest number. Therefore, among the given choices, the least number of people chose yogurt for their breakfast food.

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Option A is correct.  For mowing the neighbor's yard, Jessy was paid $12.50. If he now has $55.75, how much money did he have before?

Two or more expressions with an Equal sign is called as Equation.

The given equation is

x + 12.50 = 55.75

x=55.75-12.5

x=43.25

We need to find among the given options which corresponds the given equation

A) For mowing the neighbor's yard, Jessy was paid $12.50. If he now has $55.75, how much money did he have before?

B) For mowing the neighbor's yard, Jessy was paid $55.75. If he now has $12.50, how much money did he have before?

C) For mowing the neighbor's yard, Jessy was paid $43.25. If he now has $55.75, how much money did he have before?

D) For mowing the neighbor's yard, Jessy was paid $12.50. If he now has $68.25, how much money did he have before?

In these options, option A corresponds the equation x + 12.50 = 55.75

The amount Jessy has now is 55.75, 12.75 is paid, x is the money before jessy have.

Hence, Option A is correct.  For mowing the neighbor's yard, Jessy was paid $12.50. If he now has $55.75, how much money did he have before?

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To solve the equation C = 5b + 200 for b in terms of C, subtract 200 from both sides of the equation and then divide both sides by 5.

To solve the equation C = 5b + 200 for b in terms of C, we need to isolate the variable b. First, subtract 200 from both sides of the equation:

C - 200 = 5b

Next, divide both sides of the equation by 5:

b = (C - 200)/5

So, the equivalent equation when solved for b in terms of C is b = (C - 200)/5.

The transformation of a function may lead to the rigid motion based on what type of transformation you applied in it. Thus, option D is correct.

We need to check the transformation that is the rigid motion for the function f(x).

Now, the different transformation is given below:

Let us take the transformations of the function from the top to the bottom.

(1) In the first transformation, we changed our function f(x) to 2f(x)+3.

When we used multiplication of division operations towards any functions then it will change the amplitude of the function, and hence it is not a rigid motion.

(2) In the second transformation, we changed our function f(x) to f(x/2)+1.

When we used multiplication of division operations towards any functions then it will change the amplitude of the function, and hence it is not a rigid motion.

(3) In the third transformation, we changed our function f(x) to 2f(x/2).

When we used multiplication of division operations towards any functions then it will change the amplitude of the function, and hence it is not a rigid motion.

(4) In the fourth transformation, we changed our function f(x) to f(x-1/2)+3.

When we used multiplication of division operations towards any functions then it will change the amplitude of the function, and when we use addition or subtraction towards any function then the amplitude remains constant. Hence, it is a rigid motion.

Thus, option D is correct.

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