What mass of HCl is contained in 45.0 mL of an aqueous HCl solution that has a density of 1.19 g cm–3 and contains 37.21% HCl by mass?

Answers

Answer 1
When the concentration is expressed in percentage, that is the ratio of the mass of solute to the mass of the total solution. Since the given amount of solution is in terms of volume, let's use the density to find the mass. Note that 1 mL is just equal to 1 cm³.

45 mL * 1.19 g/cm³ = 53.55 g HCl solution

Mass Percent = Mass Solute/Mass Solution * 100
37.21% = Mass Solute/53.55 g * 100
Mass Solute = 19.93 g HCl 
Answer 2

Final answer:

To find the mass of HCl in a 45.0 mL aqueous solution with a specific density and concentration, the volume is converted to mass using the given density, and then the mass of HCl is calculated based on its percentage concentration, resulting in 19.93 g of HCl.

Explanation:

The question asks to find the mass of HCl contained in 45.0 mL of an aqueous HCl solution with a density of 1.19 g cm–3 and a concentration of 37.21% HCl by mass. First, we convert the volume of the solution to mass using the given density. Calculating the mass of the solution: 45.0 mL × 1.19 g/mL = 53.55 g. Next, to find the mass of HCl, we use the percentage concentration of HCl in the solution. Calculating the mass of HCl: 53.55 g × 0.3721 = 19.93 g. Therefore, the mass of HCl in the 45.0 mL solution is 19.93 g.


Related Questions

You are on an alien planet where the names for substances and the units of measures are very unfamiliar.

Nonetheless, you obtain 29 quibs of a substance called skvarnick.

You can trade this skvarnick for gold coins, but the vendors all measure skvarnick in units of sleps; not quibs.

10 quibs is equal to 4 sleps.

If you have 29 quibs of skvarnick, how many sleps do you have?

Round your answer to the nearest tenth (one decimal place).

Answers

so a quib seems to be a unit of measure

and we have another unit called sleps

so sleps:quibs is some ratio
oh nice, 10quibs:4sleps



yo have 29 quibs

easy

29quibs:?sleps=10quibs:4sleps
ratio and proportion
29/?=10/4
times both sides by 4?
(4)(29)=10?
116=10?
divide both sides by 10
11.6=?


you have 1 11.6 sleps


anohter way

10quibs=4sleps
divide by 10 both sides
1quib=4/10 sleps=2/5 sleps
times 29 both sides
29 quibs=(29*2)/5=58/5=11.6 sleps


yo has 11.6 sleps

Answer:

If we have 29 quibs of skvarnick they will be equal to 11.6 sleps.

Explanation:

Mass of a substance called skvarnick = 29 quibs

10 quibs is equal to 4 sleps. This means that 1 quibs is equal to 0.4 sleps.

10 quibs = 4 sleps

1 quibs = [tex]\frac{4}{10} sleps = 0.4 sleps[/tex]

Then 29 quibs will be:

[tex]29 quibs=29\times 0.4 sleps =11.6 sleps[/tex]

If we have 29 quibs of skvarnick they will be equal to 11.6 sleps.

Draw two lewis structures for a compound with the formula c4h10. no atom bears a charge, and all carbon atoms have complete octets.

Answers

There are 2 possible isomers of C4H10. We have to show both. Below is the figure attached.

All the carbon and hydrogen has complete octet.

The two Lewis structure for a compound with the formula [tex]\rm C_4H_{10}[/tex] are shown below in the attached image.

In a Lewis structure, an element's chemical symbol shows its nucleus and inner electrons, while dots or lines represent valence electrons. Valence electrons are the atom's outermost electrons and are important in chemical bonding.

Shown below are the two Lewis structures of the compound with molecular formula [tex]\rm C_4H_{10}[/tex]. The two structures are the isomers of each other.The number of sigma bonds = 5, and number of pi bonds = 3 in the given compound.

Therefore, the two structure of [tex]\rm C_4H_{10}[/tex] are isomers of each other (refer to the attached image).

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Table salt contains 39.33 g of sodium per 100 g of salt. The U.S. Food and Drug Administration (FDA) recommends that adults consume less than 2.40 g of sodium per day. A particular snack mix contains 1.24 g of salt per 100 g of the mix.What mass of the snack mix can you consume and still be within the FDA limit?

Answers

 First set up the equation 39.33g/100g = x/1.28g and that'll give you how much sodium is in each 100g of the mix. 

39.33g *1.28g= 100g * x 
x = 0.503424g 
x = Amount of sodium per 100g of the mix 

Now 2.4g / 0.503424 = 4.7674 
Multiply by 100 and you get 476.7353g

The answer is: mass of the snack mix can you consume and still be within the FDA limit is 491 grams.

ω(Na) = m(Na) ÷ m(salt).

ω(Na) = 39.33 g ÷ 100 g.

ω(Na) = 0.3933; mass percentage of sodium in salt.

m(salt) = 2.4 g ÷ 0.3933.

m(salt) = 6.10 g; mass of salt recommended for consumation.

Make proportion: 1.24 g : 100 g = 6.10 g ÷ m(mix).

m(mix) = 491.93 g; mass of the snack mix.

A 5.23 g sample of a metal occupies 0.27 ml. identify the density of the metal.

Answers

Final answer:

The density of a metal given a mass of 5.23 g and a volume of 0.27 mL is calculated using the formula density = mass / volume, resulting in a density of 19.37 g/mL, with the final answer limited to four significant figures.

Explanation:

To identify the density of a metal given its mass and volume, you can use the formula for density, which is density = mass / volume. Given a 5.23 g sample of metal that occupies 0.27 mL, you first ensure the units are correct for density in g/mL. You then simply divide the mass by the volume.

So, density = 5.23 g / 0.27 mL = 19.37 g/mL.

This calculation gives us the density of the metal. Remember, when calculating density, it's important to ensure that your units are consistent, and for density, g/mL is a common unit. Additionally, when expressing your final answer, it matches the number of significant figures from the given data, in this case, being limited to four significant figures due to the precision of the volume measurement.

Draw the structure of the 1 isomer of c7h16 that contains 3 methyl branches on the parent chain

Answers

Answer:

2,2,3-trimethyl-butane

Explanation:

Hello,

On the attached picture, you will find one isomer with chemical formula C₇H₁₆ which is 2,2,3-trimethyl-butane as it has the required three methyl brances on the parent chain, therefore, they must be arranged in the inner carbons otherwise, they will be considered as part of the parent chain.

Best regards.

Final answer:

The structure of the 1 isomer of C7H16 with three methyl branches on the parent chain can be represented as 2,2,3-trimethylbutane, which has a butane backbone with two methyl groups on the second carbon and one on the third.

Explanation:

The student asked to draw the structure of the 1 isomer of C7H16 that contains 3 methyl branches on the parent chain. For heptane (C7H16), one possible isomer with three methyl branches on the parent chain could be 2,2,3-trimethylbutane. In this structure, we have a four-carbon (butane) chain as the parent, with methyl groups attached to the second and third carbons (two on the second and one on the third).

Here's how you could write it out in steps:

Start with a straight chain of four carbons, which is your butane base.Attach two methyl groups to the second carbon on the chain.Attach one methyl group to the third carbon on the chain.

please help asap

Which has the greater density? (Refer to "Densities of Common Substances" table.) air at sea level
air at 20 km altitude

Answers

Density of any substance is defined as mass per unit volume of that substance.

Density of air is inversely proportional to the altitude. This means that as the altitude increases, the density of air decreases, and vice versa.

Based on this, examining the choices given, we can conclude that the density of air is greater at sea level.
 the density of air is greater at sea level hope this helps

In a combustion experiment, it was found that 12.096 g of hydrogen molecules combined with 96.000 g of oxygen molecules to form water and released 1.715 × 103 kJ of heat. Calculate the corresponding mass change in this process. (1 J = 1 kg · m2/s2)

Answers

The mass change, or the mass defect, can be calculated by the formula that is very known to be associated with Albert Einstein. 

E = Δmc²
where
E is the energy gained or released during the reaction
c is the speed of light equal to 3×10⁸ m/s
Δm is the mass change

(1.715×10³ kJ)(1,000 J/1 kJ) = Δm(3×10⁸ m/s)²
Δm = 1.91×10⁻¹¹ kg

Fission occurs when the nucleus of an atom captures a subatomic particle

Answers

the process of using a neutron to split a heavy nucleus into 2 nuclei to smaller mass numbers: nuclear power

Without doing any calculations, determine which mass is closest to the atomic mass of carbon. without doing any calculations, determine which mass is closest to the atomic mass of carbon. 12.00 amu 12.50 amu 13.00 amu

Answers

The mass closest to the mass of carbon is 12.00 amu

This is because carbon is used as a standard compound in chemistry, and its mass is defined as being 12.00 amu per mole of carbon. Its definition as a standard is such that the mole is defined as, "the amount of substance containing the same number of atoms as 12 grams of carbon-12".

Final answer:

The atomic mass closest to carbon without calculations is 12.00 amu since carbon's average atomic mass is listed as 12.011 amu on the periodic table, and it mostly consists of carbon-12.

Explanation:

The atomic mass of an element like carbon is the weighted average of the masses of its naturally occurring isotopes. Carbon is predominantly composed of carbon-12, which has an atomic mass of exactly 12 amu (atomic mass units), as this isotope makes up about 98.90% of naturally occurring carbon. Because of this, the average atomic mass of carbon is close to 12 amu, but slightly higher due to the presence of the carbon-13 isotope. The periodic table lists carbon's atomic mass as 12.011 amu, making 12.00 amu the mass closest to carbon's atomic mass without doing any calculations.

Why do gamma rays have no charge? they are not made of protons, neutrons, or electrons they have equal numbers of protons and neutrons charge is balanced out by their intense frequency they are constantly emitting all their protons and electrons

Answers

they are not made of protons, neutrons, or electrons. gamma rays are electromagnetic radiation that emitted during radioactive process in the form of light. light is protons and protons have no charge. hope this helps good luck

Because they haare not made up of protons nuetrons or electrons

If some unknown solid weighs 84.0 grams and occupies 30.0 cm3 of space, what is its density?

Answers

The density is 2.8 grams/cm³.

The density of an object is the ratio between the mass of the object and the volume occupied by that mass of the object. Therefore, the formula:

density = mass / volume
density = 84 / 30

density = 2.8 g/cm³

The density of some unknown solid whose weight is 84.0 grams and volume is 30.0 cm3 is 2.8 g/mL.

What is Density?

Density may be defined as a type of physical property that significantly deals with the description of how much space an object or substance takes up with respect to the amount of matter in that object or substance.

In a more simple sense, it is characterized as the measurement of quantity or mass per unit of volume in a particular substance.

According to the question,

The mass of the unknown solid =  84.0 grams.

The volume of the unknown solid = 30.0 cm3.

Now, the formula for calculating the density is as follows:

Density = Mass/Volume.

                     = 84.0 g / 30.0 mL (1 cubic centimeter = 1 mL).

                     = 2.8 g/mL.

Therefore, the density of some unknown solid whose weight is 84.0 grams and volume is 30.0 cm3 is 2.8 g/mL.

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Given 8.50 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?

Answers

Ethyl butyrate is also more commonly known as the ethyl butanoate with chemical formula of C₆H₁₂O₂. The equation of the butanoic acid (C₄H₈O₂)  and ethanol (C₂H₆O) to form this substance can be written off as,
                            C₄H₈O₂ + C₂H₆O --> C₆H₁₂O₂ + H₂O
Note that the given equation is already balanced. Using dimensional analysis and conversion factors,
                (8.5 g C₄H₈O₂)(1 mol/88.11 g)(1 mol C₆H₁₂O₂/1 mol C₄H₈O₂)(116.16 g / mol)
                  =  112.06 grams of ethyl butyrate

ANSWER: 112. 06 grams
                  

Answer:

Amount of ethyl butyrate formed = 11.3 g

Explanation:

The reaction between butanoic acid (C3H7COOH) and excess ethanol (C2H5OH) is:

[tex]C3H7COOH + C2H5OH \rightarrow C3H7COOC2H5 + H2O[/tex]

Since ethanol is the excess reagent, the formation of the product i.e. ethyl butyrate is influenced by the amount of butanoic acid present

Based on the reaction stoichiometry:

1 mole of butanoic acid produces 1 mole of ethyl butyrate

Mass of butanoic acid = 8.50 g

Molar mass of butanoic acid = 88 g/mol

[tex]Moles\ of \ butanoic\  acid = \frac{Mass}{Molar\ mass} =\frac{8.50g}{88g/mol}=0.097 moles[/tex]

Moles of ethyl butyrate = 0.097

Molar mass of ethyl butyrate= 116 g/mol

[tex]Mass\ of\ ethyl\  butyrate= 0.097*116 = 11.3 g[/tex]

Name the compound P4O10

Answers

I believe the compound is Phosphorus pentoxide
Phosphorus Pentoxide

An atom has three full orbitals in its second energy level. How many electrons are present in the second energy level of the atom

Answers

SIX ELECTRONS are present in the second energy level of the atom.
Atomic orbitals possess different energy level. In the second energy level of atoms, there are three dumbbell shaped P orbitals and each orbital has two electrons. The electrons in the three P orbitals correspond to 2 *3 = 6

Answer:

6 electrons are in the third level if the atom.

How many grams of sodium sulfate react with 20.8 of barium chloride?

Answers

Convert mass of BaCl2 to moles:
20.8 g BaCl2 / 208.23 = 0.100 mol
Because BaCl2 and Na2SO4 react in a 1:1 ratio, you will need 0.100 mol Na2SO4
Mass Na2SO4 = 0.100 mol X 142 g/mol = 14.2 g Na2SO4
Final answer:

To determine the number of grams of sodium sulfate that can react with 20.8 g of barium chloride, we use the balanced chemical equation and molar masses of the compounds. The number of moles of Na2SO4 that can react with 20.8 g of BaCl2 is 15.44 g Na2SO4.

Explanation:

To determine the number of grams of sodium sulfate that can react with 20.8 g of barium chloride, we need to use the balanced chemical equation and the molar masses of the compounds involved.

The balanced chemical equation for the reaction is:

BaCl2 (aq) + Na2SO4 (aq) → BaSO4 (s) + 2NaCl (aq)

The molar mass of BaCl2 is 208.23 g/mol and the molar mass of Na2SO4 is 142.04 g/mol.

From the balanced equation, we can see that the ratio of BaCl2 to Na2SO4 is 1:1. Therefore, the number of moles of Na2SO4 that can react with 20.8 g of BaCl2 is:

20.8 g BaCl2 × (1 mol BaCl2 / 208.23 g BaCl2) × (1 mol Na2SO4 / 1 mol BaCl2) × (142.04 g Na2SO4 / 1 mol Na2SO4) = 15.44 g Na2SO4.

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A transmission electron microscope was used to examine a microscopic organism. No nucleus was foumnd. Which of the following correctly describes the organism

Answers

if prokaryotic is an option that's the answer

All atoms are _____.positively charged, with the number of protons exceeding the number of electrons negatively charged, with the number of electrons exceeding the number of protons neutral, with the number of protons equaling the number of electrons neutral, with the number of protons equaling the number of electrons, which is equal to the number of neutrons description

Answers

All atoms, in their ground state without the interference of external factors like other atom's electronegativity or other instability, are neutral with equal numbers of protons and electrons. 

Answer: I think it’s: Neutral, with The number of protons equaling to the number of electrons

Explanation:

what is the density of an unknown if 7.82g of it occupies a volume of 3.63ml

Answers

just divide 7.82 by 3.63
=2.15 g/ml

The valence shell holds up to two electrons in which 2 elements? a. H and C b. H and Li c. H and He d. He and Be

Answers

The answer is C. H and HE

Answer : The correct option is, (d) He and Be

Explanation :

First we have to determine the electronic configuration of the following elements.

The electronic configuration of hydrogen (H) is:

[tex]1s^1[/tex]

The electronic configuration of carbon (C) is:

[tex]1s^22s^22p^2[/tex]

The electronic configuration of lithium (Li) is:

[tex]1s^22s^1[/tex]

The electronic configuration of helium (He) is:

[tex]1s^2[/tex]

The electronic configuration of beryllium (Be) is:

[tex]1s^22s^2[/tex]

From the electronic configuration of the elements we conclude that, the hydrogen element has '1' valence electron, carbon element has '4' valence electrons, lithium element has '1' valence electron, helium element has '2' valence electrons and beryllium element has '2' valence electrons.

Thus, the helium and beryllium are the elements that holds up to two electrons in their outermost shell.

Hence, the correct option is, (d) He and Be

A dilute solution is prepared by transferring 40.00 ml of a 0.3433 m stock solution to a 750.0 ml volumetric flask and diluting to mark. what is the molarity of this dilute solution?

Answers

We are given with the initial volume of the substance and the molarity. The first thing that needs to be done is to multiply the equation in order to obtain the number of moles such as shown below.
  
    number of moles = (40 mL) x (1 L / 1000 mL) x (0.3433 moles / L)
           number of moles = 0.013732 moles

To get the value of the molarity of the diluted solution, we divide the number of moles by the total volume.
          molarity = (0.013732 moles) / (750 mL / 1000 mL/L) = 0.0183 M

Similarly, we can solve for the molarity by using the equation,
           M₁V₁ = M₂V₂
Substituting the known values in the equation,
     (0.3433 M)(40 mL) = M₂(750 mL)
              M₂ = 0.0183 M

What are the necessary steps to prevent oxidation during high temperature

Answers

CZTS film remains stoichiometric up to 400C.However, the composition of the thin film becomes Zn-poor above 450 C because Zn vaporizes at the elevated temperatures.This leads to the loss of zinc.It can be compensated by spraying Zn and S vapors. But then the sulphur vapours may oxidize.In order to avoid it, CZTS films are taken out of the deposition chamber and are exposed to the atmosphere before sulphurization is performed to grow thin CZTS polycrystalline thin films. Moisture gets adsorbed on the surface and prohibits oxidation of S. The adsorbed moisture later leaves during annealing.This, IN LINE, sulphurization prevents oxidation.JIMBO ET AL employed this method with sputtered CZTS precursor films to prevent oxidation.

In 1928, 47.5 g of a new element was isolated from 660 kg of the ore molybdenite. the percent by mass of this element in the ore was:

Answers

To take the percent by mass of this element, we use the formula:

% mass = (mass of element / mass of ore) * 100%

% mass = (47.5 g / (660 kg * 1000 g / kg)) * 100*

% mass = 7.20 x 10^-3 %

Answer: The mass percent of element in the ore is 0.0072 %

Explanation:

To calculate the mass percentage of element in ore, we use the equation:

[tex]\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of ore}}\times 100[/tex]

Mass of element = 47.5 g

Mass of ore = 660 kg = 660000 g    (Conversion factor:  1 kg = 1000 g)

Putting values in above equation, we get:

[tex]\text{Mass percent of element}=\frac{47.5g}{660000g}\times 100=0.0072\%[/tex]

Hence, the mass percent of element in the ore is 0.0072 %

When aqueous solutions of lead(ii) nitrate (pb(no3)2) and potassium phosphate (k3po4) are mixed, the products are solid lead(ii) phosphate and aqueous potassium nitrate. write the balanced chemical equation for this reaction. (include states-of-matter under the given conditions in your answer. use the lowest possible whole number coefficients.)?

Answers

Hello)
3Pb(NO3)2 + 2K3PO4 = Pb3(PO4)2↓ + 6KNO3

Answer: The balanced chemical equation is written below.

Explanation:

Balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side will be equal to the total number of individual atoms on the product side. These equations follow law of conservation of mass.

The chemical equation for the reaction of lead (II) nitrate and potassium phosphate follows:

[tex]3Pb(NO_3)_2(aq.)+2K_3PO_4(aq.)\rightarrow Pb_3(PO_4)_2(s)+6KNO_3(aq.)[/tex]

By Stoichiometry of the reaction:

3 moles of aqueous lead (II) nitrate reacts with 2 moles of aqueous solution of potassium phosphate to produce 1 mole of solid lead (II) phosphate and 6 moles of aqueous solution of potassium nitrate.

Hence, the balanced chemical equation is written above.

Ryan hypothesizes that darker colors heat up faster. He places a thermometer inside a red wool sock, a green cotton glove, and a black nylon hat. What's wrong with his procedure?

Answers

he should've used one item in different colors.
they are all different materials. If he wants a clean experiment, he needs all three to be the exact same

88.5 mol of P4O10 contains how many moles of P?

Answers

Looking at the formula, each mol of P4O10 contains 4 mol of P, so 
(58.5 mol P4O10) x (4 mol P/ 1 mol P4O10) = 234 mol

How many picograms are in 1 Megagram?

Answers

1 x 10^18 picograms
I hope it helps you

How many grams of hydrogen gas can be obtained from 0.373 grams of magnesium? Note that the equation is NOT balanced.
Mg(s) + HCl(aq) → MgCl2(aq) + H2(g)

Answers

The first step to answering this item, is to balance first the chemical reaction. This is shown below.

      Mg(s) + 2HCl (aq) --> MgCl₂(aq) + H₂(g)

 

HCl is multiplied by 2 to equalize the number of the hydrogen and chlorine.

The molar masses of magnesium and hydrogen gas are 24.3 g and 2 g, respectively. Using dimensional analysis and conversions, mass of hydrogen is calculated through the equation,

 Mass of H₂ =    (0.373 g Mg)(1 mol Mg/24.3 g Mg)(1 mol H₂/ 1 mol Mg)(2 g H₂/1 mol H₂)

             Mass of hydrogen = 0.031 g of hydrogen

 

ANSWER: 0.031 g H₂

The number of molecules in 1.0 mole of H2O is _____ as in one mole of O2.

Answers

"the same";
One mole of any given thing is 6 * 10²³ of it;
One mole of H₂O is 6 * 10²³ molecules;
One mole of O₂ is also 6 * 10²³ molecules;
Therefore for both substances, there are the same number of molecules.

Sodium hydroxide, NaOH; sodium phosphate, Na3PO4; and sodium nitrate, NaNO3, are all common chemicals used in cleanser formulation. Rank the compounds in order from largest mass percent of sodium to smallest mass percent of sodium.

Answers

NaOH:
 (1x23) / (1x23 + 1x16 + 1x1) = 57.5 %

Na3PO4 
 (3x23) / (3x23 + 1x31 + 4x16) = 42.07%

NaNO3
 (1x23) / (1x23 + 1x14 + 3x16) = 27.05%

So, NaOH > Na3PO4 > NaNO3 

You have a racemic mixture of (+)-2-butanol and (-)-2-butanol. the (+) isomer rotates polarized light by +13.5∘. what is the observed rotation of your mixture?

Answers

 The rotation of the polarized of the light of your mixture is 0, (+) isotopes spins it one way and l spins it equally back the other way. Racemic mixture or racemate is one that has equal amounts right- and left-handed enantiomers of a chiral molecule.

Answer:

The degree of rotation of racemic mixture will equal 0° 

Explanation:

Hello,

(-) isomer is in other words the Enantiomer of (+) isomer and as long as the statement indicates that (+)-isomer optical rotation is + 13.5°, the optical rotation of (-)-isomer will be the same value and degree but with the inverse sign which is -13.5°.

In such a way, the degree of rotation of the taken into account racemic mixture will equal 0° 

This is in this way due to the fact that the racemic mixture has equal amount of both enantiomers.

Best regards.

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