What point in the feasible region maximizes the objective function constraints: x>=0 y>=0 -x+3>=y y<=1/3 x+1 Objective function: C=5x-4y Please explain!

Answers

Answer 1
c= o because the c=5x-4y the x is 0 and the y is 0 so your answer is zero 

Answer 2

Answer:

So, the maximum of C is 15 at (3,0) and the minimum value is 0 at (0,0)

Step-by-step explanation:

When you graph all of the constraint functions, the vertices of the shape that is made are at the points above. Now you plug those points into the function equation C=5x-4y and see where you get a max or min.

(0,1)

(1.5,1.5)

(0,0)

(3,0)



(1,1)=C=1

(1.5,1.5)=C=1.5

(0,0)=C=0

(3,0)=C=15

So, the maximum of C is 15 at (3,0) and the minimum value is 0 at (0,0)


Related Questions

√10, π, 3.5
order least to greatest

Answers

π, √10, 3.5

3.14, 3.16, 3.5
From least to greatest, we have:
___________________________________
π , √10 , 3.5 " .
___________________________________

We have:  "3.5" (given) ;

                 " π " = 3.14159...

                "√10" = 3.162277660168379
___________________________________
So, from least to gretest, we have:
___________________________________
 " π , √10 , 3.5 " .
___________________________________

Simplify 6 - 23 + (-9 + 5) · 2
A. -10
B. -12
C. 6
D. -8

I've been told the answer is A. -10, but I need to know how to get that answer.
Thanks.

Answers

at least u tried to help but the answer is -10  bro


what is the solution of -8/2y-8=5/y+4 - 7y+8/y^2-16? y = –4 y = –2 y = 4 y = 6

Answers

Please clarify whether you meant (-8/2)y or   -8 / (2y - 8).

It's always a good idea to use parentheses for clarity; it reduces or removes the need for guessing.

Here is my interpretation of your equation:

-8/2y-8=5/y+4 - 7y+8/y^2-16  becomes

-8 / (2y-8) = 5 / (y+4) - 7y + 8 / (y^2-16)   (note use of parentheses)

Factoring all of the denominators results in:

-8 / [2(y-4)] = 5 / (y+4) - 7y  + 8 / [(y-4)(y+4)]

The LCD is 2(y-4)(y+4).  You must multiply each and every term in the above equation by this LCD to clear fractions:

-8(y+4) = 5(2)(y-2) - 7(y+4)(y-4) + 8/2

Then -8y - 32 = 10y -20 -7y^2 + 4

I believe the "-7y^2" term is incorrect.


In retrospect, you could simply substitute each of the given answers (y-values), one at a time, to determine which, if any, makes the equation true:

-8 / (2y-8) = 5 / (y+4) - 7y + 8 / (y^2-16)   (note use of parentheses)

Let's test y = 4.  Is this a solution?  Subst. 4 for y in the above equation, we get:

-8 / (8-8) and several more terms.  No, 4 is not a solution, because 
-8 / (0) is undefined.  Eliminate y = 4 as a solution.  Try y = -4 and the other given possible solutions.  Do any of them make this equation true?

Answer:

d. 6

Step-by-step explanation:

just took the pretest:) have such a fantastic day loves, you're doing AMAZING!

n=6x35+4 what does n represent in a division problem

Answers

 answer is 214 - n = 214

How do i know that the variable x has a uniform distribution function?

Answers

you will have to solve for x to know what x equals 

Calculate the mean of the number set 5 10 12 4 6 11 13 5

Answers

For calculating the mean, you want to add up all of the numbers then divide by how many numbers there are. So you'd do:

5+10+12+4+6+11+13+5 then divide that by 8

The answer to your question is: 8.25

What is the meaning of the function of h = f(50, t)? describe the behavior of this function?

Answers

Dependent variable h depends upon two independent variaables, one of which is represented by 50 and the other by the letter t.  In other words, h is a function of two variables.  Without further detail it is impossible to describe the behavior of this function h=f(50,t).

Suppose that h = f(x,t) = 2x - 1/t.  This is my invention.

Then f(50,t) would come out as 2(50) - 1/t, which is a function of just 1 variable.


equivalent ratios number 1 to 50

Answers

are you meaning something like 1 to 50= 2 to 100 or something like 1 to 50, 1:50,1/50 they all r the same??
2:100 will be equivalent to 1:50

If the test for a disease is accurate 65% of the time, how often will it come back positive if a patient doesn't have the disease?

Answers

Answer:

35% of the time

Step-by-step explanation:

A P E X

What is the answer to this question ?

Answers

A is not commutative with the above expression
your answer is A

A boat was sailing for 4 hours and covered 224 miles. A jet is ten times as fast as the boat. Find the jet’s speed.

Answers

First, you would need to find out how many miles the boat can sail in 1 hour. To do this, you would divide the total number of miles traveled by the time it took to travel it. 
224 ÷ 4 = 56
56 mi/1 h

Next, you would multiply the number of miles the boat traveled, 56, by 10. 

56 x 10 = 560

The jet flew 560 mi/per hour

I hope this helps!

224/4 = 56 miles per hour
56 x 10 = 560 miles per hour

Jasmine finished the bike trail in 2.5 hours at an average rate of 2.5 miles per hour.Lucy biked the same trail at a rate of 6 1/5 mile per hour.How long did it take lucy to bike the trail?

Answers

2.5 hours at a rate of 2.5 miles per hour = 2.5 * 2.5 = 6.25 miles

the trail was 6.25 miles long

Lucy rode at 6 1/5 mile per hour

 so 6.25 / 6 1/5 = 1.008 = 1.01 hours

How would you express as a unit rate: morag typed 60 words in one minute

Answers

Hello There!

I'm not sure what else you need to do as this answer is already in unit rate.

Hope This Helps You!
Good Luck :) 

- Hannah ❤

Morag would be typing at a rate of 60 words per minute (wpm) in order to type 60 words in one minute.

What is Unit conversion?

A statement of the connection between units that are used to alter the units of a measured quantity without affecting the value is called a conversion factor. A conversion ratio (or unit factor), if the numerator and denominator have the same value represented in various units, always equals one (1).

To express Morag's typing speed as a unit rate, we would divide the number of words by the number of minutes.

Therefore, the unit rate for Morag typing 60 words in one minute would be 60 words per minute (60 wpm).

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how many solutions are in 6x+4x-6=24+9x

Answers

One.

To solve this, first combine like terms.

6x + 4x - 6 = 24 + 9x

10x - 6 = 24 + 9x

Then move all like terms to one side.

10x - 9x = 24 + 6

x = 30
10x-6=9x+24
x=30
..........

Write a problem saying a single load of laundry cost $2 and a double load costs $4 the machine only accept quarters what is the answer

Answers

The problem is: A laundromat charges $2 for a single load of laundry and $4 for a double load. The machine only accepts quarters. How many quarters are needed to wash two double loads of laundry?

To solve this problem, we first need to determine the total cost of washing two double loads. Since each double load costs $4, two double loads will cost 2 * $4 = $8.

Next, we need to determine how many quarters are in $8. Since there are 4 quarters in a dollar, there are 4 * 8

= 32 quarters in $8.

Therefore, 32 quarters are needed to wash two double loads of laundry

Find the gradient of the function at the given point. function point f(x, y, z) = x2 + y2 + z2 (3, 9, 8)

Answers

Answer:

[tex]\displaystyle \nabla f(3, 9, 8) = 6 \hat{\i} + 18 \hat{\j} + 16 \hat{\text{k}}[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Multivariable Calculus

Differentiation

Partial DerivativesDerivative Notation

Gradient:                                                                                                             [tex]\displaystyle \nabla f(x, y, z) = \frac{\partial f}{\partial x} \hat{\i} + \frac{\partial f}{\partial y} \hat{\j} + \frac{\partial f}{\partial z} \hat{\text{k}}[/tex]

Gradient Property [Addition/Subtraction]:                                                          [tex]\displaystyle \nabla \big[ f(x) + g(x) \big] = \nabla f(x) + \nabla g(x)[/tex]

Gradient Property [Multiplied Constant]:                                                            [tex]\displaystyle \nabla \big[ \alpha f(x) \big] = \alpha \nabla f(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle f(x, y, z) = x^2 + y^2 + z^2[/tex]

[tex]\displaystyle P(3, 9, 8)[/tex]

Step 2: Find Gradient

[Function] Differentiate [Gradient]:                                                             [tex]\displaystyle \nabla f = \frac{\partial}{\partial x} \Big( x^2 + y^2 + z^2 \Big) \hat{\i} + \frac{\partial}{\partial y} \Big( x^2 + y^2 + z^2 \Big) \hat{\j} + \frac{\partial}{\partial z} \Big( x^2 + y^2 + z^2 \Big) \hat{\text{k}}[/tex][Gradient] Rewrite [Gradient Property - Addition/Subtraction]:                [tex]\displaystyle \nabla f = \bigg[ \frac{\partial}{\partial x}(x^2) + \frac{\partial}{\partial x}(y^2) + \frac{\partial}{\partial x}(z^2) \bigg] \hat{\i} + \bigg[ \frac{\partial}{\partial y}(x^2) + \frac{\partial}{\partial y}(y^2) + \frac{\partial}{\partial y}(z^2) \bigg] \hat{\j} + \bigg[ \frac{\partial}{\partial z}(x^2) + \frac{\partial}{\partial z}(y^2) + \frac{\partial}{\partial z}(z^2) \bigg] \hat{\text{k}}[/tex][Gradient] Differentiate [Derivative Rule - Basic Power Rule]:                  [tex]\displaystyle \nabla f = 2x \hat{\i} + 2y \hat{\j} + 2z \hat{\text{k}}[/tex][Gradient] Substitute in point:                                                                     [tex]\displaystyle \nabla f(3, 9, 8) = 2(3) \hat{\i} + 2(9) \hat{\j} + 2(8) \hat{\text{k}}[/tex][Gradient] Evaluate:                                                                                     [tex]\displaystyle \nabla f(3, 9, 8) = 6 \hat{\i} + 18 \hat{\j} + 16 \hat{\text{k}}[/tex]

∴ the gradient of the function at the given point is <6, 18, 16>.

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Topic: Multivariable Calculus

Unit: Directional Derivatives

At a speed of 45 yards per minute, a 120 pound swimmer burns 420 calories per hour and a 172 pound swimmer burns 600 calories per hour. write an equation that models the number of calories burned per hour as a function of the swimmer's weight.

Answers

c = w*45/13 + 60/13 I will be assuming that the equation will be linear since there are only 2 data points available. The form of the equation will be c = aw + b where c = calories burned a = some constant w = weight b = some other constant. If you look at the equation, you'll notice that it looks like the equation for a line i slope intercept form. So first, let's calculate the slope of the desired equation. a = (600-420)/(172-120) = 180/52 = 45/13 = 3.461538462 Now we have the equation c = w*45/13 + b Substitute the values for a known point, giving 420 = 120*45/13 + b Now solve for b 420 = 120*45/13 + b 420 = 5400/13 + b 420 - 5400/13 = b 5460/13 - 5400/13 = b 60/13 = b So now the equation is c = w*45/13 + 60/13

What number is 1/10 greater than 7962

Answers

792.6
just divide the number by 1/10


792.6 
just divide the number by 1/10

PLZ HELP I WILL MAKE YOU BRAINLIEST!! IT IS GOOD FOR YOUR PROFILE!

Rewrite as a square or a cube:
1 11/25

Answers

1 11/25 = 36/25
= (6/5)^2

Answer:

1 11/25 = 36/25

= (6/5)^2


Step-by-step explanation:


Help Algebra Question

Answers

The solution is option D.

  0     4
- 6     1
  3    -4
 
Rember row times column.

=>
a11 = 4*0 + 0*(-3) = 0

a12 = 4*1 + 0*1 = 4 + 0 = 4

a21 = -1*0 + 2*(-3) = 0 - 6 = -6

a22 = -1*1 + 2*1 = -1 + 2 = 1

a31 = -3*0 + (-1)*(-3) = 0 + 3 = 3

a32 = -3*1 + (-1)*1 = -3 - 1 = -4

I need help with this question... phenobarbital elixir contains 2 grams in 1 liter of elixir. How many milligrams of phenobarbital are contained in 1 teaspoon of elixir?

Answers

Answer:

9.86 milligrams

Step-by-step explanation:

It is given that 1 liter f elixir contains 2 grams of phenobarbital elixir.

Since 202.884 teaspoons = 1 liter

so 1 teaspoon of elixir =  [tex]\frac{1}{202.884}[/tex] liter

∵ 1 liter of elixir contains phenobarbital = 2 gms.

∴  [tex]\frac{1}{202.884}[/tex] liter of elixir contains phenobarbital =  [tex]\frac{2*1}{202.884}[/tex] = 0.009858 grams

or 0.009858 × 10³ milligrams

 = 9.86 milligrams.

Therefore, 9.86 milligrams of phenobarbital will be required.

Final answer:

The milligrams of phenobarbital in one teaspoon of elixir, multiply the milligrams per milliliter (2 mg/mL) by the volume of one teaspoon (5 mL), resulting in 10 milligrams per teaspoon.

Explanation:

The milligrams of phenobarbital in one teaspoon of elixir by first understanding the concentration of the solution and then using the volume conversion. Since 1 liter of the phenobarbital elixir contains 2 grams (2000 mg), we need to find out how many milligrams are contained in a smaller volume, specifically in one teaspoon, which is 5 milliliters. milligrams, so 2 grams = 2000 milligrams.

Next, consider the volume conversion: There are 1000 milliliters in 1 liter. So if 2000 mg is in 1000 milliliters, there would be 2 mg in 1 milliliter (since 2000 ÷ 1000 = 2).

Finally, since 1 teaspoon equals 5 milliliters, we multiply the amount of milligrams in 1 milliliter by 5.

Mathematically: 2 mg/mL * 5 mL = 10 mg

Therefore, there are 10 milligrams of phenobarbital in 1 teaspoon of elixir.

Write twelve and sixteen thousand as a mixed decimal

Answers

12.016

hope this helps

How does the throughput of pci express version 3.0 compare to pcie version 2.0?

Answers

PCI(e) version 3.0 has a throughput twice as fast as that of its predecessor. Version 2.0 had a maximum throughput of 16Gb/second, while version 3.0 increased the maximum theoretical speed to 32Gb per second. This allows for much faster data transfer when using objects like solid state hard drives and ethernet cards.

What is the reason for each step in the solution of the inequality?

−2(x+3)−4>4x+30

Select the reason for each step from the drop-down menus.

2nd picture is drop down box answers.

Answers

-2(x + 3) - 4 > 4x + 30 : Given
-2x - 6 - 4 > 4x + 30 : distributive property
-2x - 10 > 4x + 30 : combine like terms
-6x - 10 > 30 : subtraction property
-6x > 40 : addition property
x < -20/3 : division property

[tex]-2(x + 3) - 4 \ \textgreater \ 4x + 30[/tex] : Given
[tex]-2x - 6 - 4 \ \textgreater \ 4x + 30[/tex] : Distributive property
[tex]-2x - 10 \ \textgreater \ 4x + 30[/tex] : Combine like terms
[tex]-6x - 10 \ \textgreater \ 30[/tex] : Subtract
[tex]-6x \ \textgreater \ 40[/tex] : Add 
[tex]x \ \textless \ - \dfrac{20}{3} [/tex] : divide 

How do you solve an inequality

Answers

We can often solve inequalities by adding or subtracting a number from both sides

Answer:

you solve an inequality by doing the inverse equation on each side of the equation.

Step-by-step explanation:

two pounds of peaches cost 4.50 5 pounds cost 11.25and 10 pounds cost 22.50 what is the constant of proportionality

Answers

4.50 /2 = 2.25

11.25/5 = 2.25

22.50/10 = 2.25

 the constant is the price per pound which is 2.25

Answer:

c

Step-by-step explanation:

What is the area of a triangle with verticies at (-2,1), (2,1) and (3,4)

Answers

check the picture below.

notice, is just a triangle with a base of 4, and an altitude of 3.

Help with Precalc Vectors? Medal and fan v = (-7,8) Find the magnitude of vector v. Express your answer in radical form sqrt of 113 is what I got for that. second part: use the magnitude and the angle of vector v to write it in the form (lvlcostheta, lvl sin theta). I don't know how to determine the single angle for one vector. Earlier in a different part of the problem, I was asked to find the angle between two vectors, but I don't think you use that here since no second vector is provided. So how would I answer the second part? Thanks(:

Answers

Hello Kaviipik!
Lets find the mag of v = (-7,8). Since we have one order pair we are finding the mag from the origin.
Yes we are using Pythagorean Theorem to calculate the magnitude
[tex]a^2 + b^2 = c^2[/tex] 

[tex]\sqrt{v^2} = \sqrt{(-7)^2 + (8)^2}[/tex]
[tex]v = \sqrt{(-7)^2 + (8)^2}[/tex]
[tex]v = \sqrt{49 + 64}[/tex]
[tex]v = \sqrt{113}[/tex]
[tex]v = \sqrt{113} = 10.6301458[/tex]
Now  we use 
[tex]\theta = tan^{-1} (\frac{b}{a})[/tex]
[tex]\theta = tan^{-1} (\frac{8}{-7})= 48.8[/tex]
[tex](\sqrt{113} \times cos(48.8) , \sqrt{113} \times sin(48.8) )[/tex]

Final answer:

To express the vector v = (-7,8) in the form (|v|cosθ, |v|sinθ), you first correctly found the magnitude |v| using the Pythagorean theorem. Then, to find the angle θ, use the arctangent function applied to the y/x components of your vector. Ensure the angle is in the correct quadrant by modifying it if necessary.

Explanation:

To find the magnitude of the vector v = (-7,8), you've correctly done the Pythagorean theorem and found sqrt(113), which is the absolute value of your vector, written as |v|. Now, to express the vector in the form (|v|cosθ, |v|sinθ), we need to find the angle θ. This is found using the arctangent function (also known as the inverse tangent or atan). θ = atan(y/x), where x and y are the x and y components of your vector respectively. Be careful with the sign as atan can only return values from -π/2 to π/2.

In your case θ = atan(8/-7), but since this gives a negative answer and the vector is in the second quadrant where angles are positive, you should add π to your result to get the correct angle. Then you can substitute |v| and θ into the expressions for the x and y components.

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Simplyfy (x - 5 / x^3 + 27) + (2 / x^2 - 9)

Answers

The answer simplified should be x-5/x^3+18+2/x^2. Hope that is helpful.
[tex]\bf \textit{difference of squares} \\ \quad \\ (a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\\ \quad \\ \textit{difference of cubes} \\ \quad \\ a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad (a+b)(a^2-ab+b^2)= a^3+b^3 \\\\ -------------------------------\\\\[/tex]

[tex]\bf \cfrac{x-5}{x^3+27}+\cfrac{2}{x^2-9}\implies \cfrac{x-5}{x^3+3^3}+\cfrac{2}{x^2-3^2} \\\\\\ \cfrac{x-5}{(x+3)(x^2-3x+3^2)}+\cfrac{2}{(x-3)(x+3)}\\\\\\ \cfrac{x-5}{(x+3)(x^2-3x+9)}+\cfrac{2}{(x-3)(x+3)} \\\\\\ \textit{so, we'll use the LCD of }(x-3)(x+3)(x^2-3x+9) \\\\\\ \cfrac{(x-3)(x-5)~~+~~(x^2-3x+9)2}{(x-3)(x+3)(x^2-3x+9)} \\\\\\ \cfrac{x^2-8x+15~~+~~2x^2-6x+18}{(x-3)(x+3)(x^2-3x+9)}\implies \cfrac{3x^2-14x+33}{(x-3)(x+3)(x^2-3x+9)}[/tex]

Kristina invests $5,000 at 15% simple interest for 2 years.How much interest did Kristina earn over the 2 years?

Answers

using
SI = PRT/100
=( 5000 × 15 × 2)/100
= 50×15×2= 1500$
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