Can someone help me & my 7th grader w problem?
A factory produces widgets at a constant rate.After 4 hours,3,120 widgets have been produced.At what rate are the widgets being produced ?
Answer:
1-xy
Step-by-step explanation:
A factory produces widgets at a constant rate.After 4 hours,3,120 widgets have been produced.At what rate are the widgets being produced ?
If [tex] \frac{1}{10}m[/tex]=[tex] \frac{1}{11}m[/tex]+[tex] \frac{1}{1100}[/tex], than what is the value of m
Find the area of this figure. Please show work if you can!
Which of the following would be equivalent to 11 to the 8th power over 11 to the 3rd power?
A)11 to the 7th power over 11 to the 7th power
B)11 ⋅ 114
C)11 to the 0 power over 11 to the 5th power
D)110
Option: B is the correct answer.
[tex]B)\ 11\cdot 11^4[/tex]
Step-by-step explanation:We are given a numerical expression as:
11 to the 8th power over 11 to the 3rd power.
i.e. mathematically it is given by:
[tex]\dfrac{11^8}{11^3}[/tex]
Now, we know that if the numerator and the denominator terms are power terms such that both the terms are of same base then the resultant is the same base and the exponent of the base is: exponent of numerator minus exponent of denominator.
i.e.
[tex]\dfrac{a^m}{a^n}=a^{m-n}[/tex]
Here we have:
[tex]a=11,\ m=8\ and\ n=3[/tex]
Hence, we get:
[tex]\dfrac{11^8}{11^3}=11^{8-3}[/tex]
i.e.
[tex]\dfrac{11^8}{11^3}=11^5[/tex]
Now, this could also be written as:
[tex]\dfrac{11^8}{11^3}=11\cdot 11^4[/tex]
( since,
[tex]a^m\cdot a^n=a^{m+n}\\\\i.e.\\\\11^1\cdot 11^4=11^{4+1}=11^5[/tex] )
the left and right page numbers of an open book are two consecutive integers whose sum is 329. Find these page numbers.
Follow below steps:
The student is seeking to find two consecutive integers whose sum is 329. This is a mathematics problem and involves understanding of even and odd numbers as well as basic algebra. Since the numbers are consecutive, we can represent them as n and n + 1. The sum of these numbers given in the problem is 329, so we have the equation n + (n + 1) = 329.
Solving this equation:
Combine like terms: 2n + 1 = 329
Subtract 1 from both sides: 2n = 328
Divide both sides by 2: n = 164
Thus, the two consecutive page numbers of the book are 164 and 165
help me please I'm stuck
7.4p - 9.2p = -2.6 + 5.3
List three numbers that are divisible by 3, 4 and five
To find numbers divisible by 3, 4, and 5, we need to find common multiples of these three numbers. One example is 30, and other possible numbers include 60 and 90.
Explanation:When we need to find numbers that are divisible by 3, 4, and 5, we can look for numbers that are common multiples of these three numbers. In other words, we need to find numbers that can be divided evenly by 3, 4, and 5 without any remainder. Let's take a look at the first few numbers and see if they satisfy this condition.
15: 15 is divisible by 3 (15 ÷ 3 = 5), divisible by 5 (15 ÷ 5 = 3), but not divisible by 4 (15 ÷ 4 = 3 remainder 3), so it is not a solution.20: 20 is not divisible by 3 (20 ÷ 3 = 6 remainder 2), not divisible by 4 (20 ÷ 4 = 5 remainder 0), but divisible by 5 (20 ÷ 5 = 4), so it is not a solution.30: 30 is divisible by 3 (30 ÷ 3 = 10), divisible by 4 (30 ÷ 4 = 7 remainder 2), and divisible by 5 (30 ÷ 5 = 6), so it is a solution.From our analysis, we found that the number 30 is divisible by 3, 4, and 5. We can list two more numbers by finding common multiples of these three numbers.
6090A container holds 70,000 ounces of water. There is a small leak in the container. Every 96 minutes 0.2 ounces of water leak out. Represent the total change in the amount of water in the container after 8 hours.
How many students in all scored 100 or 95
Water is leaking from a tank. After t minutes, the volume of the water in the tank is 16(200-9t) milliliters. What is the volume of water left in the tank after 18 minuets?
Mike earned $11.76 per hour for working 23.5 hours last week.How much money did Mike earn last week?
There 22,869 children,49,563 men and 2,872 more women than men st the fair.how many people were at the fair?
1. If one letter is chosen at random from the word combed, what is the probability that the letter chosen will be a "d"?
2. The sides of number cube have the numbers 2,4,8,9,4, and 7. If the cube is thrown once, what is the probability of rolling a 7?
3. A bag contains 12 red marbles, 10 green marbles, 2 yellow marbles, 19 blue marbles, and 9 purple marbles. What is the probability of pulling out a green marble?
Answer:
Probability that the chosen letter is d is [tex]\frac{1}{6}[/tex]Probability of rolling a 7 is [tex]\frac{1}{6}[/tex]Probability of picking a green is [tex]\frac{5}{21}[/tex]Step-by-step explanation:
Probability of choosing d in the word "combed"Given:
Alphabet: d
Word: combed
First, we note down the length of the word "combed";
The length is 6 characters
The we check the number of occurrence of d in the word "combed"
Occurrence of d = 1
Probability is then calculated as;
Probability of choosing d = [tex]\frac{Number of Occurrence}{Total Observation}[/tex]
By Substitution; Probability = [tex]\frac{1}{6}[/tex]
Probability of rolling a 7 in a cube of side numbers 2,4,8,9,4, and 7Given:
Roll number = 7
Sample Space= {2,4,8,9,4, 7}
Sample Size, n(S) = 6
We check the number of occurrence of 7 in the sample space
Number of occurrence = 1
Probability is then calculated as;
Probability of rolling a 7 = [tex]\frac{Number of Occurrence}{Sample Size}[/tex]
By Substitution; Probability = [tex]\frac{1}{6}[/tex]
Probability of pulling out a green marbleGiven
Red = 12
Green = 10
Yellow = 2
Blue = 19
Purple = 9
Total = 12 + 10 + 2 + 19 + 9 = 42
Probability of picking a green marble is then calculated as;
Probability of choosing d = [tex]\frac{Number of Green}{Total}[/tex]
By Substitution; Probability = [tex]\frac{10}{42}[/tex]
Probability = [tex]\frac{5}{21}[/tex]
What is the value of 4 in the number 546 210
The wait time of a line t hours after a store opens is given by the expression.
40x−12x+2340x−1 x+23
What does the value 23 represent?
A.the total number of people in line
B. the total rate of change in people per hour
C.the rate at which people join the line
D.the number of people in line when the store opened
The sides of a hexagon are equal in length. The perimeter of the hexagon is at most 42 in. Find the possible side lengths of the hexagon
What is the answer to 3/8r=15/16
What is 10 percent higher than 39
four of these points lie on a straight line. which one is the odd one out?
(-3,-3) (-2,-1) (2,5) (4,11) (5,13)
1/2 +2/3=?
What's the answer?
How is mode different from the median?
Susie drew the line of best fit on the scatter plot shown
What is the approximate equation of this line of best fit in slope-intercept form?
A. Y=6/5x+3
B. Y=3x+6/5
C. Y=5/6x+3
D. Y=3x+5/6
Jasmine has a budget of $800 for catering. The catering company charges $12.50 per person. Write and solve an inequality to show the number of guests Jasmine can invite.
Which are partial products for 89 × 25?
A. 9 X 2 = 18
B. 8 X 5 = 40
C. 9 X 5 = 45
D. 80 X 20
write 45% as a fraction in simplest form
find Two consecutive odd intergers such that 44 more than the lesser is three times the greater
Tom went on a bike ride to the store 3 miles away if it took Time 1/2 hour to get there in 2/3 of an hour to get back what was his average rate of speed miles per hour for the entire trip
In order to achieve the times that he did in going to and from the store, Tom went at an average speed of 5.14 miles per hour.
The store was 3 miles away which means that the distance of the entire trip is:
= Distance going + Distance coming
= 3 + 3
= 6 miles in total
The time he took was:
= Time going + Time coming
= 1/2 hours + 2/3 hours
= 0.5 + 0.67
= 1.17 hours
His average speed for the entire journey is:
= Distance / Time
= 6 / 1.17
= 5.14 miles per hour
In conclusion, Tom's average speed was 5.14 miles per hour.
Find out more at https://brainly.com/question/14523120.
Suppose you have developed a scale that indicates the brightness of sunlight each category in the table is five times brighter than the category above it for example a day that is dazzling is five times brighter than a day that is radian how many times brighter is a dazzling day then a dim day
Dim=2
Illuminated=3
Radiant=4
Dazzling=5
Answer:
Basicly all you do is Multiply Dazzling 4 times by 5, so 5*5*5*5 and your answer is 125.
EXAMPLE ;
IF it was 2 times brighter you would count the catagories. There are 4. So you would do 2*2*2*2 and you answer is 16.