Answer:
The answer is 10
Explanation:
5+5=10
Answer:
10 is your answer um that's it
To find the number of neutrons in To find the number of neutrons in and
you would subtract
Answer:
To find the number of neutrons we would subtract the number of protons from mass number of an atom.
Explanation:
An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.
All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.
For example:
The mass number of carbon is 12 amu and it has six protons thus to find the number of neutrons we would subtract the 6 from 12 and get number of neutrons.
12- 6 = 6 neutrons
A 0.20 mol sample of MgCl(s) and a 0.10 mol sample of KCl(s) are dissolved in water and diluted to 500 mL. What is the concentration of Cl- in the solution?
Answer:
0.6 Molar
Explanation:
According to the Question,
In 500 mL of water ,
0.2 mol sample of MgCl is present and 0.1 mol of KCl is present.
Thus ,
Concentration of Cl anion in the solution will be the sum of Cl anion concentration from MgCl and KCl.
From MgCl , 0.2 mol of Cl anion will come and 0.1 mol of KCl anion will come ,
Thus , 0.3 mol of Cl anion will come totally .
So, Cl anion concentration will be [tex]\frac{0.3}{0.5}[/tex] = 0.6 M
The concentration of Cl⁻ in the solution, after dissolving 0.20 mol MgCl₂ and 0.10 mol KCl and diluting to 500 mL, is 1.0 M.
To determine the concentration of Cl⁻ ions in the solution, we need to calculate the total moles of Cl⁻ ions from both MgCl₂ and KCl after dissolving them in water.
Magnesium chloride (MgCl₂) provides two moles of Cl⁻ for every mole of MgCl₂. Hence, 0.20 moles of MgCl₂ will produce 0.20 x 2 = 0.40 moles of Cl⁻.
Potassium chloride (KCl) provides one mole of Cl⁻ for every mole of KCl. Therefore, 0.10 moles of KCl will give 0.10 moles of Cl⁻.
Adding the total moles of Cl⁻ from both salts gives us 0.40 moles + 0.10 moles = 0.50 moles.
To find the concentration of Cl⁻ in the final solution, divide the total moles of Cl⁻ by the volume of the solution in liters. Since the solution volume is 500 mL, which is equivalent to 0.500 L, we perform the following calculation:
Concentration of Cl⁻ = 0.50 moles / 0.500 L = 1.0 M.
Therefore, the correct answer is that the concentration of Cl⁻ in the solution is 1.0 M.
Which reacts with metals to form H2 gas
Answer: acid react with metals to form H2.
Explanation: metals which are more electropositve than hydrogen will always displaced hydrogen from acids. The equation below show how hydrogen is displaced from acid
Zn + 2HCl -—> ZnCl2 + H2
Whatlis the maximum number of electrons the n =
4 shell can contain
Answer:
32
Explanation:
The maximum number of electrons can be calculated by using the expression 2n2
when n = 4
substitute n for 4
2(4)2
2(16) = 32
Answer:
32
Explanation:
How does one recognize a periodic trend on the periodic table?
Answer:
Look for predictable changes and patterns - Apex
Answer:
Look for predictable changes and patterns
Explanation:
Ap3x
if your body need alot of immediate energy, what carbon compound would you eat
Answer:
Carbohydrates
Explanation:
You would eat carbohydrates as they supply your body with lots of short-term energy that can be burned at a fast rate.
Q10.An aqueous solution contains 5.00x10-2 mol/L of Ca2+ and 7.00x10-3 mol/L of SO4
2-
. Show whether
this solution would precipitate anhydrite CaSO4 or not provided that the Ksp for anhydrite is equal to 10-4.5.
Answer:
The precipitate will form.
Explanation:
Let's write the equilibrium expression for the solubility product of calcium sulfate:
[tex]CaSO_4(s)[/tex] ⇄ [tex]Ca^{2+}(aq)+SO_4^{2-}(aq)[/tex]
The solubility product is defined as the product of the free ions raised to the power of their coefficients, in this case:
[tex]K_{sp}=[Ca^{2+}][SO_4^{2-}]=10^{-4.5}[/tex]
Our idea is to find the solubility quotient, Q, and compare it to the K value. A precipitate will only form if Q > K. If Q < K, the precipitate won't form. In this case:
[tex]Q_{sp}=[Ca^{2+}][SO_4^{2-}]=5.00\cdot10^{-2} M\cdot7.00\cdot10^{-3} M=3.5\cdot10^{-4}[/tex]
Now given the K value of:
[tex]K_{sp}=10^{-4.5}=3.2\cdot10^{-5}[/tex]
Notice that:
[tex]Q_{sp}>K_{sp}[/tex]
This means the precipitate will form, as we have an excess of free ions and the equilibrium will shift towards the formation of a precipitate to decrease the amount of free ions.
How would adding the catalyst nitrogen monoxide (NO) affect this reaction? 2SO2(g) + O2(g) → 2SO3(g)
Answer:
NO decreases the activation energy and increases the rate of a reaction
Explanation:
To fully comprehend this problem, we wish to understand the role of a catalyst in a chemical reaction. Catalyst is a substance which is essentially consumed and then reproduced (that said, its mass remains the same and the net mass consumed is equal to 0) in a chemical reaction which:
decreases the activation energy barrier – that is, the minimum amount of energy required for a successful collision between molecules leading to a chemical reaction;increases the rate of a reaction: the reaction proceeds faster. This is achieved based on the fact that the activation energy is decreased.Addition of a nitrogen monoxide catalyst would therefore decrease the activation energy and increase the rate of a reaction.
Now, in terms of equilibrium (if the reaction is at equilibrium, as just a right arrow is indicated), since nitrogen monoxide is a gas, there would be no shift in equilibrium towards the products or reactants, as addition of an inert gas to an equilibrium system would decrease the partial pressures of each component equally.
“While electroplating is most commonly viewed as a finishing process for metals, it can be used with great success on non-conductive material as well”. Justify this statement with suitable examples.
Answer:
ls most commonly viewed as a metals
What’s the answer to this science problem?
Answer:
The image is not accurate because
the heavier atoms are moving faster than the lighter ones
but the lighter ones must move faster than the heavier ones.
Explanation:
The image depicts the atoms of two different elements; atoms of lighter and heavier elements.
And the rate of diffusion (movement of atoms) of an element is inversely proportional to the square root of its molecular.
⇒ As the weight increases, the rate of diffusion (movement of atoms) decreases.
And as the weight decreases, the rate of diffusion (movement of atoms) increases.
so, heavier atoms move slowly compared to lighter atoms.
The image is not accurate because
the heavier atoms are moving faster than the lighter ones
but the lighter ones must move faster than the heavier ones.
Determine the mass number of an element that contains 26 protons, 22 electrons, and 30 neurons
Answer:
56 is the mass
Explanation:
You would add 26 and 30(the protons and neutrons). I didn't add the electrons because they are so small their mass is negligible in this situation.
Answer:
Mass = 56
Explanation:
for the reaction: magnesium atom + oxygen atom --> magnesium oxide. draw the Lewis electron dot diagram for each substance and use arrows to illustrate electron movement.
Answer:
Explanation:
Magnesium is present in second group of periodic table. It has two valance electrons. Oxygen us present in group sixteen it has six valance electrons.
Magnesium need to lose two valance electrons to complete the octet while oxygen needed two electrons to complete the octet.
When magnesium loses it two electrons it form magnesium cation Mg²⁺ and its two electrons transfer to the oxygen thus oxygen becomes anion O²⁻.
Both negative and positive charges attract each others and form magnesium oxide. MgO.
Chemical equation with electron dot illustration:
Reaction is given in attached file.
it takes 60 days for 1024 grams of element XY to decay to 32 grams. what is the half life of element XY
Answer:
The half life of element XY is 12 days
Explanation:
Given:
Time taken for 1024 grams to decay into 32 grams = 60 days
To Find:
The half life of element XY = ?
Solution:
The Half life is calculated by
[tex]N = N_0 (\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}[/tex]
[tex]t_{\frac{1}{2}}[/tex] =[tex]\frac{t}{log_{\frac{1}{2}}( \frac{N(t)}{N_0})}}[/tex]
Substituting the values,
[tex]t_{\frac{1}{2}}[/tex] =[tex]\frac{60}{log_{\frac{1}{2}}( \frac{32}{1024})}}[/tex]
[tex]t_{\frac{1}{2}}[/tex] =[tex]\frac{60}{log_{\frac{1}{2}}(0.03125)}}[/tex]
[tex]t_{\frac{1}{2}}[/tex] =[tex]\frac{60}{5}[/tex]
[tex]t_{\frac{1}{2}}[/tex] = 12
What can you tell by tracking oxidation numbers?
Answer:
By tracking oxidation numbers we can identify the number electron in the atom
Explanation:
Tracking of electrons helps us to know when and how many electrons get transferred from one atom to other atom . Oxidation referred as the “loss of one or more electrons” by an atom. When the oxidation number of an element increases, there is a loss of electrons and that element is being oxidized. Oxidation numbers are usually written with the sign (+plus or −minus) followed by the magnitude, which is the opposite of charges on ions. In their elemental stage oxidation number of an atom is zero.
Final answer:
Oxidation numbers are used to track electrons in atoms. By assigning oxidation numbers based on certain rules, we can determine what is being oxidized and what is being reduced in a redox reaction.
Explanation:
Oxidation numbers are used to keep track of electrons in atoms. They are assigned to atoms based on four rules. Oxidation is an increase in oxidation number (loss of electrons), while reduction is a decrease in oxidation number (gain of electrons). By tracking oxidation numbers, we can determine what is being oxidized and what is being reduced in a redox reaction. For example, in the reaction where carbon reacts with oxygen to form carbon dioxide, the oxidation number of carbon changes from zero in the reactants to +4 in the product, indicating that carbon is being oxidized. On the other hand, the oxidation number of oxygen changes from zero to -2, indicating that oxygen is being reduced.
Consider the following reaction:
2HCl(g) + 185 kJ → H2(g) + Cl2(g)
Describe the change in energy according to the Law of Conservation of Energy.
A) There is a net gain of 185 kJ of energy when decomposing HCl.
B) It takes more energy to break the bonds of HCl than form H2(g) + Cl2(g).
C) The energy required to decompose HCl and produce H2(g) + Cl2(g) are equal.
D) It takes less energy to break the bonds of HCl than form the bonds of H2(g) + Cl2(g.)
For the given reaction, according to the Law of Conservation of Energy, the energy required to decompose Hcl and produce [tex]H_{2}+c l_{2}[/tex] are equal.
Answer: Option C
Explanation:
According to law of conservation's of energy, energy can only be transferred from reactants to product side. So in this process, it is stated that 185 kJ of energy will be needed to decompose it. So that 185 kJ of energy will be getting transferred to produce the creation of hydrogen and chloride in the product side.
So if we see from the reactants side, the energy of 185 kJ is required for decomposition of hydrogen chloride. Similarly, if we see from the product side, the 185 kJ utilized for decomposition is transferred as energy required to create hydrogen and chlorine atoms. This statement will be in accordance with the law of conservation's of energy.
Answer:
the answer is b ^ that person is wrong
Explanation:
Describe the electron distribution in a polar-covalent bond and it's effect on the partial charges of the compound?
Answer:
In polar Covalent bonds, the electrons which are in bonded shifts towards an atom which has more valance electrons.
Explanation:
We know if an atom takes the electron it acquires a negative charge whereas if it gives an electron it acquires a positive charge in the ionic bond. But here we are talking about covalent bonds. Covalent bonds are those in which atoms share the electron instead of completely giving off the electron. If the atoms are identical in case of covalent bond that is 2 hydrogen atoms then this type of bonding is called pure covalent bonds but if the atoms linked in covalent bonds are different then it is called polar covalent bonds.
In this, the bonding electrons will shift towards an atom which has more valence electron thereby acquiring the partial negative charges and the other atom will acquire a partial positive charge. For example, HCl. In this the Chlorine atom is having more valence electron than hydrogen atom, and hence Chlorine atom has a partial negative charge and Hydrogen atom has a partial positive charge.
In polar Covalent bonds, the electrons that are in bonded shifts towards an atom that has more valance electrons.
The following information should be considered:
We know that the atom takes the electron it acquires a negative charge while on the other hand if it gives an electron it acquires a positive charge in the ionic bond. But Covalent bonds are those in which atoms share the electron instead of completely giving off the electron. In the case when the atoms are same in case of covalent bond that is 2 hydrogen atoms so this type of bonding is called pure covalent bonds. But if the atoms linked in covalent bonds are distinct so it is called polar covalent bonds. In this, the bonding electrons will shift towards an atom which has more valence electron thereby acquiring the partial negative charges and the other atom will acquire a partial positive charge.Learn more: https://brainly.com/question/13013054?referrer=searchResults
Why is it not possible to just consume only pure ATP and thus eliminate some steps in
metabolism?
Our digestive has the steps of digestion and absorption associated with it. So all the compounds taken in as food are first broken down into simpler components before absorption.
Explanation:ATP or Adenosine Triphosphate is a compound containing a molecule of adenine as nitrogen base, a ribose sugar and three molecules of phosphate attached with the adenine in a chain. Its unable to get absorbed into the system as ATP itself. In intestine, it will be broken down into Adenine, ribose, and phosphates and then absorbed individually into blood.
Thus even if we consume raw ATP, we can't bypass the process of ATP formation. So, there's no significance. And secondly, ATP is very expensive and not suitable for consumption itself.
NaOH (aq) + H2SO4 (aq) > H2O + NaSO4 (aq)
Answer:
[tex]2 NaOH (aq) + H_2SO_4 (aq)\rightarrow 2 H_2O (l) + Na_2SO_4 (aq)[/tex]
Explanation:
Let's correct and balance the given equation:
[tex]NaOH (aq)[/tex] is sodium hydroxide, charge of sodium is +1, charge of hydroxide is -1, so it's fine;[tex]H_2SO_4 (aq)[/tex] is sulfuric acid, charge of hydrogen cation is +1, charge of sulfate is -2, sulfate is balanced by the two protons;[tex]H_2O (l)[/tex] is firstly a molecule, it's water, in its liquid state, the oxidation state of +1 for the two hydrogens is balanced by the oxidation state of -2 for oxygen;sodium sulfate should be [tex]Na_2SO_4 (aq)[/tex], since sulfate has a charge of -2, this would require two sodium cations to balance it.The equation becomes:
[tex]NaOH (aq) + H_2SO_4 (aq)\rightarrow H_2O (l) + Na_2SO_4 (aq)[/tex]
We require 2 NaOH in order to balance the two sodium cations on the right, this would yield a total of 4 hyrogens on the left, so we also need two water molecules to balance it fully:
[tex]2 NaOH (aq) + H_2SO_4 (aq)\rightarrow 2 H_2O (l) + Na_2SO_4 (aq)[/tex]
1. If you have a 1-g sample of Po-218, how many grams would you
have after 6 minutes? After 18 minutes?
Answer:
a) 0.25 g b) 0.01542 g
Explanation:
Half life of Po-218 = 3.04 minutes
initial mass = 1 g
after 3.04 minutes it will remain 0.5 g
after another 3.04 minutes it will remain 0.25 g
After 6 minutes it will remain approx 0.25 g
B) after another 3.04 minutes it will remain 0.125 g
after another 3.04 minutes it will remain 0.0625 g
after another 3.04 minutes it will remain 0.03125 g
after another 3.04 minutes it will remain 0.015625 g
After 18 minutes it will remain approx 0.01542 g
balancing the reaction by oxidation number method k2cr2o7+sncl2+hcl
Answer:
[tex]K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)[/tex]
Explanation:
The products of this reaction are given by:
[tex]K_2Cr_2O_7 (aq) + SnCl_2 (aq) + HCl (aq)\rightarrow KCl (aq) + SnCl_4 (aq) + CrCl_3 (aq) + H_2O (l)[/tex]
Firstly, dichromate anion becomes chromium(III) cation, let's write this change:
[tex]Cr_2O_7^{2-} (aq)\rightarrow Cr^{3+} (aq)[/tex]
The following steps should be taken:
balance the main element, chromium: multiply the right side by 2 to get 2 chromium species on both side:[tex]Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq)[/tex]
balance oxygen atoms by adding 7 water molecules on the right:[tex]Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)[/tex]
balance the hydrogen atoms by adding 14 protons on the left:[tex]Cr_2O_7^{2-} (aq) + 14 H^+ (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)[/tex]
balance the charge (the total net charge on the left is 12+, on the right we have 6+, so 6 electrons are needed on the left):[tex]Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)[/tex]
Similarly, tin(II) cation becomes tin(IV) cation:
[tex]Sn^{2+} (aq)\rightarrow Sn^{4+} (aq) + 2e^-[/tex]
Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:
[tex]Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)[/tex]
[tex]3 Sn^{2+} (aq)\rightarrow 3 Sn^{4+} (aq) + 6e^-[/tex]
Add them together:
[tex]Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 3 Sn^{2+} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l) + 3 Sn^{4+} (aq)[/tex]
Adding the ions spectators:
[tex]K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)[/tex]
If solid NaCl is added to a saturated water solution of PbCl2 at 20o C, a precipitate is formed. How would this affect the value of the Ksp for [Pb2+][Cl-] in solution? The Ksp increases. The Ksp decreases. The Ksp remains the same. none of the above.
Answer:
The [tex]K_{sp}[/tex] remains the same
Explanation:
Let's look at what actually happens in this scenario. Before we dive into the explanation, remember the principle of Le Chatelier: for a system at equilibrium, a specific disturbance in molarity/volume/pressure of any species in equilibrium would cause the equilibrium to shift towards the side that minimizes such a disturbance.
To begin with, we have a saturated water solution of lead(II) chloride. A saturated solution means that at the given temperature we have a maximum amount of lead(II) chloride that could dissolve in the given volume of water.
Since lead(II) chloride is not highly soluble, we have an equilibrium between the precipitate and the dissociated ions:
[tex]PbCl_2(s)[/tex]⇄[tex]Pb^{2+}(aq)+2Cl^-(aq)[/tex]
Now we're adding NaCl to this solution. Sodium chloride is a sparingly soluble salt which readily dissociates into sodium and chloride ions:
[tex]NaCl(aq)\rightarrow Na^+ (aq)+Cl^- (aq)[/tex]
Notice that sodium chloride increases the concentration of chloride ions in the solution, so the equilibrium between the precipitate and its ions is disturbed.
According to the principle of Le Chatelier, due to an increase in chloride ions, the equilibrium would be disturbed and the system would tend to decrease it in order to restore the equilibrium. Hence, the equilibrium shifts towards the precipitate forming more of the precipitate and decreasing the amount of lead(II) cation, as well as the excess of chloride ions. This is also called the common ion effect: the common ion decreases the solubility of a salt.
However, it only decreases the solubility of the salt but not the solubility product constant defined as:
[tex]K_{sp}=[Pb^{2+}][Cl^-]^2[/tex]
A decrease in lead(II) concentration is compensated by the excess of chloride. The solubility product is only temperature-dependent, just as any other equilibrium constant, so it doesn't depend on the molarity of chloride or lead(II) ions.
Solubility, on the other hand, is equal to:
[tex]S=[Pb^{2+}]=\frac{K_{sp}}{[Cl^-]^2}[/tex]
And, as you can see, it decreases, as K is kept constant and we have an increase in chloride.
Answer:
The answer is the Ksp remains the same.
Explanation:
I got this answer right on an assignment.
Hi:) anyone able to explain the last column? Thanks !!
I'll try to explain this in the simplest way I've learned it.
What the last column basically meant was that if the second word of the compound has a negative ion charge
and contains oxygen it will give the the compound a name ending with -ate
5. Express the composition of each atom in shorthand form.
a. zinc-64
b. chlorine-37
c. hydrogen-3
d. calcium-40
Answer:
Explanation:
Zinc-64 = 30 proton, 30 electron and 34 neutron
chlorine-37 = 17 proton, 17 electron and 20 neutron
hydrogen-3 = 1 proton, 1 electron and 2 neutron
calcium-40 = 20 proton, 20 electron and 20 neutron
The numbers in front are the mass number, the number of proton equal number of electron in a neutral atom and these atoms do carry charge which means they are neutral. To calculate the number of neutron simply subtract the number of proton from the mass number
The shorthand composition of atoms is represented as Element-Mass number. Examples include Zinc-64 as ^64Zn, Chlorine-37 as ^37Cl, Hydrogen-3 as ^3H, and Calcium-40 as ^40Ca.
Explanation:The composition of each atom can be expressed using shorthand notation based on the atomic number and mass number. This format is usually represented as Element-Mass number.
Zinc-64 is expressed as ^64Zn, where 64 is the mass number and Zn is the atomic symbol for Zinc.Chlorine-37 is expressed as ^37Cl, where 37 is the mass number and Cl is the atomic symbol for Chlorine.Similarly, Hydrogen-3 is represented as ^3H, where 3 is the mass number and H is the atomic symbol for Hydrogen.Calcium-40 is denoted as ^40Ca, where 40 is the mass number and Ca is the atomic symbol for Calcium.Learn more about Atomic Composition here:https://brainly.com/question/34710113
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VIOUS
Namella
Part 1: Molar Mass
Use the periodic table to find the molar masses of the following
HCI
K2CO₃
Ca(OH)2
Na3PO4
Answer:
Explanation:
Molar mass:
Molar mass of substance is sum of atomic weight of all the atoms of elements present in it.
HCl
Atomic weight of hydrogen = 1.008 amu
Atomic weight of chlorine = 35.5 amu
Atomic weight of HCl = 1.008+ 35.5 = 36.508 g/mol
K₂CO₃:
Atomic weight of potassium = 39.0893 × 2 = 78.1786 amu
Atomic weight of carbon = 12 amu
Atomic weight of oxygen = 16×3 = 48 amu
Atomic weight of K₂CO₃ = 48+12+ 78.1786 = 138.178 g/mol
Ca(OH)₂:
Atomic weight of calcium = 40 amu
Atomic weight of oxygen = 16× 2 amu = 32 amu
Atomic weight of hydrogen = 1.008× 2 = 2.016 amu
Atomic weight of Ca(OH)₂ = 74.016 g/mol
Na₃PO₄:
Atomic weight of sodium = 23×3= 69 amu
Atomic weight of phosphorus = 31 amu
Atomic weight of oxygen = 16 × 4 = 64 amu
Atomic weight of Na₃PO₄= 69+31+64 = 164 g/mol
Part A
CHACHACHCH,CO K+
CH,CH
Spell out the full name of the compound.
Answer:
potassium 3-ethylpentanoate
or
potassium 3-ethylpentanoic acid
Explanation:
This is an organic compound.
This is a salt of carboxylic acid
This compound have 5 carbon main chain
There is an ethyl group is attached on carbon 3
K (Potassium) substituted the H (hydrogen) of pentanoic acid and form salt of it.
This compound shown in ionic form as salt solution written in ionic form.
So,
the name will be
Potassium 3-ethylpentanoate
it is also named as potassium 3-ethylpentanoic acid
Note: you can write any one of them both are right
the structure and name is given in attachment
1. What types of evidence might be found at a bomb scene that could help
investigators catch the bomber? Choose one of the types of evidence that
you've identified and discuss how forensic scientists might find this type of
evidence at the scene and what information it might give them.
Answer:
Substances used to make the bomb
The area it was placed
Which people were in that area
How the bomb was set off
Explanation:
Examining the residues left at the scene by the bomb could tell forensics what the bomb was made out of, and the police could investigate possible leads about people who purchased (or have access to) such materials.
The area should give clues because security cameras could be used to trace who was there that should not be. There would be a possible suspect.
If it is a public place, then we can see if there is anyone of importance (to the suspect) that was there at that time.
If a remote detonator was used to set off the bomb, then the suspect would have to be relatively close to the bomb.
Answer:
Substances used to make the bomb
The area it was placed
Which people were in that area
How the bomb was set off
how many paired and unpaired electrons are in magnesium?
Answer:
Paired = 12
Unpaired = 0
Explanation:
Magnesium is alkaline earth metal.
It is present in second group.
Its atomic number is 12 and atomic mass 24 amu.
Electronic configuration:
Mg₁₂ = 1s² 2s² 2p⁶ 3s²
It can seen from electronic configuration that all electrons are paired because s subshell have one orbital and it can accomodate two electrons. Each s subshells in magnesium have two electrons so these are filled and have paired electrons. While p subshell have three orbitals and can accomodate six electrons two by each orbital with opposite spin thus 2p is also filled and have paired electrons.
Gizmo Student exploration feel the heat
Answer:?
Explanation:?
What is the mathematical formula expressing Newton's Second Law of Motion?
p=mv
F=ma
A=v2-v1/t
Speed=distance/time
Answer:
The mathematical formula expressing Newton's Second Law of Motion is :
F = ma
Explanation:
Second Law of Motion : It states that external unbalanced force is directly proportional to rate of change of momentum.
Its formula becomes : F = ma
[tex]F = \frac{m(v-u)}{t}[/tex]
Put,
[tex]\frac{(v-u)}{t} = a[/tex]
F = ma
Answer:
F = ma
Explanation:
Which of the following is an example of parasitism: Question 3 options: Two males lions fighting for dominance of a pride. A goby fish warning a shrimp about danger so that they both retreat to the burrow the shrimp maintains. A roundworm living inside a dog and producing eggs which then get distributed to the environment through the dog's feces. A fox hunting and eating a rabbit for food
Answer:
Around worm because it gets bebefits such as food and habitat without killing its host..
Answer:
A roundworm living inside a dog and producing eggs which then get distributed to the environment through the dog's feces.
Explanation:
Parasitism is said to be an interaction between two organism whereby one organism benefit from the relationship and the other organism suffers. Most times the organism that suffers do not die instantly.
In the case of roundworm living inside a dog and producing eggs , the dog provides the necessary environment for the roundworm to strife. The roundworm enjoys the ingested foods from the dog and also comfortable environment devoid of predators. Even when the roundworm lay eggs the dog assist in the growth of the next generation by releasing it to the environment through feces. other animals later ingest the developed egg and the cycle continues.