When you sneeze, the air in your lungs accelerates from rest to 155 km/h in approximately 0.70 s . what is the acceleration of the air in m/s2?

Answers

Answer 1
62 m/s^2 First, convert 155 km/h to m/s 155 km/h * 1000 m/km / 60 min/h / 60 s/h = 43.05556 m/s Now take the speed in m/s and divide by the number of seconds it took to accelerate it to that speed. 43.05556 m/s / 0.70 s = 61.5 m/s^2 Since we only have 2 significant figures, round the result to 2 figures. 61.5 m/s^2 = 62 m/s^2
Answer 2

Final answer:

Acceleration is the rate of change of velocity over time. The acceleration of the air in m/s² when sneezing at 155 km/h in 0.70 s is approximately 61.51 m/s².

Explanation:

Acceleration is the rate of change of velocity over time. In this case, the air in your lungs accelerates from rest to 155 km/h in approximately 0.70 s. To calculate the acceleration in m/s², we convert the final velocity to m/s and use the formula for acceleration.

Given: Initial velocity = 0 m/s, Final velocity = 155 km/h = 43.06 m/s, Time = 0.70 s. Acceleration = (Final velocity - Initial velocity) / Time.

Substitute the values: Acceleration = (43.06 m/s - 0 m/s) / 0.70 s = 61.51 m/s².


Related Questions

A projectile is launched horizontally from a height of 8.0 m. The projectile travels 6.5 m before hitting the ground.

Answers

You can find

1) time to hit the ground
2) initial velocity
3) speed when it hits the ground

Equations

Vx = Vxo

x = Vx * t

Vy = Vyo + gt

Vyo = 0

Vy = gt

y = yo - Vyo - gt^2 / 2

=> yo - y = gt^2 / 2

1) time to hit the ground

=> 8.0 = g t^2 / 2 => t^2 = 8.0m * 2 / 9.81 m/s^2 = 1.631 s^2

=> t = √1.631 s^2 = 1.28 s

2) initial velocity

Vxo = x / t = 6.5m / 1.28s = 5.08 m/s

3) speed when it  hits the ground

Vy = g*t = 9.81 m/s * 1.28s = 12.56 m/s

V^2 = Vy^2 + Vx^2 = (12.56 m/s)^2 + (5.08 m/s)^2 = 183.56 m^2 / s^2

=> V = √ (183.56 m^2 / s^2) = 13.55 m/s

Answer:

5.09 m/s

Explanation:

The velocity of the projectile the moment it was launched, rounded to the nearest hundredth, is

5.09 m/s.

Correct On EDG

If you have an effusive personality, then it __________ of you. motor oil will __________ across the gravel if it spills out of the can.

Answers

The first answer in the blank is pours out of you, the second answer in the space provided is diffuse. It is because a person who has an effusive personality will likely pour out his or her emotions while the motor oil will likely diffuse if this has been spilled out of the can.

An 18.0 kg box is released on a 34.0° incline and accelerates down the incline at 0.270 m/s2. find the friction force impeding its motion. how large is the coefficient of friction?

Answers

Final answer:

The friction force impeding the box's motion is 4.24 N. The coefficient of friction is 0.106.

Explanation:

To find the friction force impeding the motion of the box, we need to use the equation:

Ffriction = μmgcosθ

Where Ffriction is the friction force, μ is the coefficient of friction, m is the mass of the box, g is the acceleration due to gravity, and θ is the angle of the incline.

Using the given values, we can substitute them into the equation:

Ffriction = (0.0300)(18.0 kg)(9.8 m/s²)cos(34.0°) = 4.24 N

So, the friction force impeding the motion of the box is 4.24 N. To find the coefficient of friction, we need to rearrange the equation:

μ = Ffriction / (mgcosθ)

Substituting the known values:

μ = 4.24 N / (18.0 kg)(9.8 m/s²)cos(34.0°) = 0.106

Therefore, the coefficient of friction is 0.106.

An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 N/m.
N=?

Answers

F = Ke
F = 39200×(25÷100)
F= 9800 N

Answer : F = 9800 N

Explanation :

It is given that,

The spring constant  for the industrial scale at the junkyard, k = 39,200 N/m

Displacement of spring, x = 25 cm = 0.25 m

According to Hooke's law, the force applied on spring is given by the following relation :

F = -k x

Negative sign shows the force is applied in opposite direction.

[tex]F = -39,200\ N/m\times 0.25\ m[/tex]

So, [tex]F=-9800\ N[/tex]

[tex]|F|=9800\ N[/tex]

Hence, this is the required solution.

What's the difference between inplicit and explicit solvent?

Answers

hi 

Explicit- and implicit-solvent molecular dynamics simulations are performed to study complexation in two polyelectrolyte systems: poly(styrene sulfonate)/poly(allylamine hydrochloride) (PSS/PAH) and poly(acrylic acid)/poly(allylamine hydrochloride) (PAA/PAH). Both these systems have been used in layer-by-layer assembly of polyelectrolyte films, with the first of these typically yielding linear growth in film thickness with increasing numbers of layers and the second yielding exponential growth. In both the systems, the polyelectrolytes have the same number of monomers and are present in stoichiometric proportion, and water is used as solvent. Simulations give important insights into the structure and composition of the complexes. We found that the PSS/PAH complex is more compact and has a smaller fraction of water than the PAA/PAH complex due to the presence of phenyl rings in the PSS chain and the hydrophilic nature of the charged group in the PAA chain. Either an increase in salt concentration or a decrease in partial charge fraction increases swelling and the water content in the complex. To overcome the computational limitations associated with the explicit-solvent simulation, a simple strategy to develop the force field for an implicit-solvent simulation is proposed. In the absence of salt and for fully charged polyelectrolytes, the radius-of-gyration and the various radial distribution functions predicted by the implicit-solvent simulation match well with those predicted by the explicit-solvent simulation, while reasonable agreement is obtained in the other cases. The implicit-solvent simulation was performed for bigger system sizes, and we observed trends similar to those observed for smaller system sizes, suggesting that the simulation results are independent of system size.

hope it helps..

A net force f is required to give an object with mass m an acceleration
a. if a net force 6f is applied to an object with mass 2m. what is the acceleration in this object

Answers

net force = mass × acceleration
F= ma
a = F/M
a = 6f/2m
a= {3f/m} ms-²

Answer:

net force = mass × acceleration

F= ma

a = F/M

a = 6f/2m

a= {3f/m} ms-²

Explanation:

Randy observed that cooked onions in his food taste very differently from the raw onions that he had on his salad. He wondered why that was so. He thinks that he has an idea, but he is not sure.

What has he developed in his mind?

Answers

It's called a hypothesis :D

Answer:

Hypothesis.

Explanation:

Hypothesis is defined as the assumption or can be say that an idea that is proposed for the sake of an argument so that it can be tested or might be occur in future.

A hypothesis is basically tentative. It is usually made an assumption for the experiment to be tested.

Basically Randy made a hypothesis by which he thinks that he has an idea but he is not sure about that.

You have landed on an unknown planet, newtonia, and want to know what objects will weigh there. you find that when a certain tool is pushed on a frictionless horizontal surface by a 12.7 n force, it moves 16.1 m in the first 2.50 s , starting from rest. you next observe that if you release this tool from rest at 10.3 m above the ground, it takes 2.88 s to reach the ground.

Answers

Refer to the diagram shown.

Because the surface is frictionless, the resistive for, R, is zero.

Let m = the mass of the object.
Let a =  acceleration due to the applied force.
Therefore
12.7 N = (m kg)*(a m/s²)
a = 12.7/m  m/s²

The object travels  16.1 m in 2.5 s, starting from rest. Therefore
16.1 N = (1/2)*(12.7/m m/s²)*(2.5 s)² = 39.6875/m  N
m = 16.1/39.6875 = 0.4057 kg

For freefall, let g =  acceleration due to gravity.
The time to fall from 10.3 m is 2.88 s, therefore
10.3 m = (1/2)*(g m/s²)*(2.88 s)² = 4.1472g m
g = 10.3/4.1472 = 2.484 m/s²

Answer:
The gravitational acceleration on the planet is 2.5 m/s² (nearest tenth)


Final answer:

The question involves applying Newton's laws of motion and universal gravitation in a physics context to determine the gravitational acceleration and accordingly the weight of objects on an unknown planet.

Explanation:

The situation described involves calculating forces and understanding the principles of motion and gravity on an unknown planet, which falls under the subject of physics. Specifically, it looks at the application of Newton's laws of motion and universal gravitation.

Using the given information from the question, we can deduce certain characteristics of the planet's gravitational field. The force exerted, in combination with the mass of the tool and distance traveled, allows us to calculate acceleration using Newton's second law of motion, F = ma. Additionally, the time taken for the object to fall a certain distance on this planet will enable us to determine the planet's gravitational acceleration, which can be compared to Earth's acceleration due to gravity of approximately 9.80 m/s².

It is important to calculate the acceleration correctly because it impacts subsequent calculations involving force and weight. For instance, with Newton's second law, the net force on a free-falling object without air resistance is simply its weight. This relationship is crucial for determining an object's weight on the unknown planet.

To apply these principles to the scenario, it is essential to use the provided data to determine the gravitational acceleration on the unknown planet. Let's take the second part of the question, which describes an object falling from a given height in a specific amount of time. This would directly give us the gravitational acceleration of the planet, using the formula for the motion of objects under gravity: s = ut + ½at². Once we have the gravitational acceleration, we could then find the weight of objects on the planet using the formula w = mg.

A block of metal has a width of 3.2 cm, a length of 17.1 cm, and height of 3.8 cm . its mass is 1.3 kg . calculate the density of the metal.express your answer to two significant figures and include the appropriate units.

Answers

density(rho) = m/v
(1.3)/((3.2)(17.1)(3.8))
since density is given in kg/m^3 you should convert the blocks dimensions to meters

1.3/(0.032*0.038*0.171)

plugging in these numbers would give you the density

1.3/0.000208
6250
with sigfigs= 6300kg/m^3

When an electron falls from a higher energy level to a lower energy level how is the energy released?

Answers

When a valence electron absorbs energy in the form of heat or light it uses that energy to jump to an excited state (outer level)

A physician has a patient that he believes has had foul play. What type of autopsy would the physician request?

Question 15 options:

Medical- legal autopsy


Investigation Autopsy


Medical Autopsy


Evidence Autopsy

Answers

Medical- legal autopsy would help determine the cause of death and confirm or reject the doctors suspicions. This is also more broadly defined as a forensic autopsy as well. This type covers death by suspicion, death without a doctor present, and also death while in surgery.
Final answer:

If a physician believes that foul play may have been involved in a patient's death, they would typically request a medical-legal autopsy.

Explanation:

If a physician believes that foul play may have been involved in a patient's death, they would typically request a medical-legal autopsy. This type of autopsy is performed to investigate the cause and manner of death, with a focus on documenting any forensic evidence that could be relevant to a legal investigation. Medical-legal autopsies differ from regular medical autopsies because they involve more detailed examination and documentation to determine if any crimes were committed.

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The strength of the electric field 0.5 m from a 6 µC charge is positive N/C. (Use k = 8.99 × 109 N• and round answer to the nearest whole number.)

Answers

according to e2020 the answer is 215760                                                                                            

Answer:

[tex]2.16 \cdot 10^5 N/C[/tex]

Explanation:

The strength of the electric field produced by the single charge is given by

[tex]E=\frac{kq}{r^2}[/tex]

where

[tex]k=8.99\cdot 10^9 N m^2 C^{-2}[/tex] is the Coulomb's constant

[tex]q = 6 \mu C = 6 \cdot 10^{-6} C[/tex] is the charge

[tex]r = 0.5 m[/tex] is the distance from the charge at which we want to calculate the field strength

Substituting the numbers into the equation, we find

[tex]E=\frac{(8.99\cdot 10^9 )(6 \cdot 10^{-6} C)}{(0.5 m)^2}=2.16\cdot 10^5 N/C[/tex]

What is the maximum altitude of Denman Orchard?

Answers

Essentially, denman is an island.  11,000 feet is the maximum altitude of Denman Orchard.

What is orchard?

An orchard is indeed a planned planting of shrubs or trees that is kept up for the purpose of producing food. Trees that produce fruit or nuts are often cultivated in orchards for commercial purposes.

Large gardens may include orchards as a feature, where they serve both a decorative and functional function. Although it is situated on a smaller, non-commercial scale or may emphasis berry bushes rather than fruit trees, a fruit garden and an orchard are typically interchangeable terms. Essentially, Denman is an island. 11,000 feet is the maximum altitude of Denman Orchard.

Therefore, 11,000 feet is the maximum altitude of Denman Orchard.

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Denman Orchard reaches an altitude of about 200 yards in a fictional context, while the tallest real tree in Canada mentioned is 314 feet tall.

The maximum altitude of the fictional location known as Denman Orchard, described in a fantastical passage, is approximately 200 yards above the level plateau mentioned. This is part of an imaginative narrative and not a real-world geographical feature.

In contrast, a real-world example is provided by Randy's search for a tall tree on Vancouver Island. The tree's reported height is 314 feet, which, if accurate, would make it the tallest tree in Canada.

Which of the following is the best definition of energy?

A) The ability to produce fusion.

B) the ability to do work

C) the ability to generate heat

D) the ability to generate electricity


Is it B?

Answers

Yeah I would think B) is the best answer

Rank them from fastest to slowest in how quickly each warms up: (a) steel, 450 j/kgââc ; (b) aluminum, 910 j/kgââc ; (c) copper, 390 j/kgââc .

Answers

The rate of conductivity is different among different substances, like aluminum, steel, and copper. Aluminum conducts heat the fastest at 910 j/kgaac. Steel is next and conducts heat at 450 j/kgaac. Copper conducts heat the slowest at 390 j/kgaac.

A motorist drives 200 km from one city to another in 2.50 h but makes the return trip in only 1.60 h. what is the average speed for the total trip?

Answers

Average speed = (total distance) divided by (total time).

Total distance = 400 km
Total time = (2.5 + 1.6) = 4.1 hr

Average speed = 400/4.1 = 97.56 km/hr

If the rock has a mass of 1 kg which is the speed of the rock after it has fallen for two seconds

Answers

If the rock has a mass of 1 kg then the speed of the rock would have been 19.6 m / s after it has fallen for two seconds.

What are the three equations of motion?

There are three equations of motion given by  Newton ,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem If the rock has a mass of 1 kg , we have to find out  which is the speed of the rock after it has fallen for two seconds

By using the second equation of the motion for the vertical direction,

v = u + gt

v = 0 + 9.8 × 2

v = 19.6 m / s

Thus , If the rock has a mass of 1 kg then the speed of the rock would have been 19.6 m / s after it has fallen for two seconds.

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Adam EvilKeynevil is a daredevil. As part of his act, Adam gets into his cannon and shoots himself at a 25.0 degrees angle at an initial velocity of 30.0 m/s. How far away from his initial position does he land?

Answers

The delta “x” is 29.8 meters.
Final answer:

Using the principles of projectile motion, we calculate the horizontal distance travelled by Adam using his initial velocity, launch angle, and the constant for gravitational acceleration.

Explanation:

To calculate the distance Adam lands from his initial position, we need to use the principles of physics, specifically those of projectile motion. The horizontal distance (range) in a projectile motion can be calculated using the formula R = (v²sin(2θ))/g, where v is the initial velocity, θ is the launch angle, and g is the gravitational acceleration (9.8 m/s²).

Substituting the given values, we get R = ((30 m/sec)²sin(2*25))/9.8 m/s². This should give you the horizontal distance Adam travels in meters.

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What would be a good reason to increase friction between surfaces?

Answers

A good reason would be to keep something stationary and from sliding.

Answer:

Explanation: Increasing friction between surface have so many good reasons such as - generating more heat between surfaces, avoiding slippage from smooth surfaces, reducing speed of vehicles. Friction force is the force automatically acting in opposite direction of motion. Friction can be dry friction force and fluid friction force depending upon the medium of motion of object.

The force of gravity on a 2-kg rock is twice as great as that on a 1-kg rock. why then doesn't the heavier rock fall faster?

Answers

It takes twice the force to produce the same acceleration in the 2kg rock. 

"find the ratio of the gravitational force between two planets if the masses of both planets are tripled but the distance between them stays the same."

Answers

The gravitational force between two planets would increase by a factor of nine if the masses of both planets are tripled, while the distance between them stays the same.

The student is asking about the effect on gravitational force when the masses of two planets are tripled but the distance between them remains constant. According to Newton's law of gravity, the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

If both masses are tripled, the gravitational force becomes 3  imes 3 times larger because the force depends on the product of the two masses. Since the distance does not change, the ratio of the gravitational force after tripling the masses would be 9:1 when compared to the initial force (3 imes 3 = 9). Therefore, the gravitational force increases by a factor of nine

How are the frequency and wavelength of light related?

Answers

The relationship between frequency and wavelength of light is given by:

[tex]f=\frac{c}{\lambda}[/tex]

where

f is the frequency

c is the speed of the light

[tex]\lambda[/tex] is the wavelength

Therefore, from this equation we see that frequency is inversely proportional to wavelength: the longer the wavelength, the smaller the frequency, and the shorter the wavelength, the higher the frequency.

Final answer:

The wavelength and frequency of light are inversely proportional to each other. The higher the frequency of light, the shorter its wavelength. Also, high-frequency waves carry more energy than lower-frequency waves.

Explanation:

The wavelength and frequency of light are inversely proportional to each other. This means if the wavelength of light increases, its frequency decreases, and vice versa. This relationship can be expressed as λf = c, where λ represents wavelength, f represents frequency, and c is the speed of light. For instance, the different colors of visible light have specific frequencies and wavelengths associated with them. Radio waves, which have longer wavelengths, have lower frequencies, while visible light with shorter wavelengths have higher frequencies. This relationship remains constant irrespective of the moving source or observer.

In a given medium under fixed conditions, the higher the frequency, the smaller the wavelength. Also, waves with higher frequencies carry more energy than lower-frequency waves. This energy is delivered as elementary particles called photons. Therefore, higher-frequency waves deliver more energetic photons compared to lower-frequency waves.

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Two carts, a and b, are connected by a rope 39 ft long that passes over a pulley p. the point q is on the floor h = 12 ft directly beneath p and between the carts. cart a is being pulled away from q at a speed of 3 ft/s. how fast is cart b moving toward q at the instant when cart a is 5 ft from q? (round your answer to two decimal places.)

Answers

Final answer:

To find the speed at which cart B is moving toward point q, we can set up a proportion using the distances and speeds of the two carts connected by a rope. By substituting the known values into the equation, we can solve for the speed of cart B.

Explanation:

To find the speed at which cart B is moving toward point q, we can use the concept of relative motion. Since there is a rope connecting the carts, their speeds are related. We can set up a proportion using the distances and speeds:

(Distance traveled by cart A) / (Speed of cart A) = (Distance traveled by cart B) / (Speed of cart B)

Since we know that cart A is being pulled away from q at a speed of 3 ft/s and is 5 ft from q, we can substitute these values into the equation and solve for the speed of cart B:

(5 ft) / (3 ft/s) = (Distance traveled by cart B) / (Speed of cart B)

From here, we can solve for the speed of cart B.

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What is the relationship between mass and momentum? Be specific as you describe the relationship between mass and linear momentum as well as how mass affects the moment of inertia in angular momentum.

Answers

The momentum is calculated by multiplying the mass by the velocity. This can be translated into the following equation:
p = m*v
Therefore, at constant v, the momentum is directly proportional to the mass.
In other words, at constant velocity, the momentum increases with the increase of mass and decreases with the decrease of mass.

As for the inertia, it depends radially on the momentum where:
L = r * m * v
L = r * p where r is the radius.

The National Ambient Air Quality Standards (NAAQS) are maximum allowable levels for _____ harmful pollutants. sixteen six sixty ten

Answers

6

I hope this helps (:

Answer;

-Six

The National Ambient Air Quality Standards (NAAQS) are maximum allowable levels for six harmful pollutants. sixteen six sixty ten.

Explanation;

-The Clean Air Act requires EPA to set National Ambient Air Quality Standards (NAAQS)  for six common air pollutants (also known as "criteria air pollutants.  These pollutants are found all over the U.S. They can harm your health and the environment, and cause property damage.

-These pollutants are particulate matter, photochemical oxidants, carbon monoxide, sulfur oxides, nitrogen oxides and lead. They are called criteria air pollutants because its sets NAAQS for them based on the criteria, which are characterizations of the latest scientific information regarding their effects on health or welfare.

How do rocks along the central valley of the mid oceanic ridges provide evidence of seafloor spreading?

Answers

These rocks allow you to know the ages of the rocks. If the rocks are farther from the ridge, they are considered old. The rocks near the ridges are considered the young rocks. Aside from the rock ages, it also helps determine the Earth's magnetic field. Scientists can determine this one with the help of the iron substances in the sea floor. It also helps determine the movements of active volcanoes and heat flow of the lave with the use of MOR

What prevents geologists from exploring earth's interior?

Answers

Maybe the Earth's core.
As it has high energy......

If an object weighs 40 n on earth what would it weigh on the moon

Answers

it would weigh 1/6 (weight on the earth )
= 1/6×40 = 6.67N

Filling in the blanks
A) moments are measured of the --------- effect of a force.
B) the moment is increased if the size of the force -----------
C) the moment is also increased if the force acts at a ----------- distance
D) moments are calculated using:
Moment= ------------- multiplied by -----------
E) moments are measured in -------------

Answers

a) turning
b)greater 
c) greater
d) force*distance
e)Nm

Without the wheels, a bicycle frame has a mass of 8.47 kg. each of the wheels can be roughly modeled as a uniform solid disk with a mass of 0.820 kg and a radius of 0.343 m. find the kinetic energy of the whole bicycle when it is moving forward at 3.55 m/s.

Answers

Final answer:

To calculate the kinetic energy of the whole bicycle, use the formulas for kinetic energy of the frame and wheels. The kinetic energy of the frame is calculated using mass and velocity, while the kinetic energy of each wheel is calculated using moment of inertia and angular velocity. Sum up the kinetic energies of the frame and the wheels to get the total kinetic energy of the bicycle.

Explanation:

To calculate the kinetic energy of the whole bicycle, we need to consider the kinetic energy of the frame and the kinetic energy of the wheels.

The kinetic energy of the frame can be calculated using the formula: KE = 0.5 * m * v^2, where m is the mass of the frame (8.47 kg) and v is the velocity of the bicycle (3.55 m/s).The kinetic energy of each wheel can be calculated using the formula: KE = 0.5 * I * w^2, where I is the moment of inertia of the wheel and w is the angular velocity of the wheel.The moment of inertia of a solid disk can be calculated using the formula: I = 0.5 * m * r^2, where m is the mass of the wheel (0.820 kg) and r is the radius of the wheel (0.343 m).The angular velocity of the wheel can be calculated using the formula: w = v / r, where v is the velocity of the bicycle (3.55 m/s) and r is the radius of the wheel (0.343 m).Plug in the values to calculate the kinetic energy of each wheel and sum them up with the kinetic energy of the frame to get the total kinetic energy of the bicycle.

The kinetic energy of the whole bicycle when it is moving forward at 3.55 m/s is approximately 139.279 J.

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