Answer:
Explanation:
D
if you were trying to locate a single star that was less luminous than the sun, but with hotter surface temperature, which group would you look in?
A. Super Giants
B. White Dwarfs
C. Main Sequence
D. Giants
Answer = ???
What do you guys think?
White Dwarfs are less luminous than the sun, but with hotter surface temperatures. Therefore, option (B) is correct.
What are White Dwarfs?A white dwarf can be described as a stellar core remnant made mostly of electron-degenerate matter. A white dwarf is dense because its mass is comparable to the Sun's and volume is comparable to the Earth's.
A white dwarf has faint luminosity which comes from the emission of residual thermal energy and no fusion occurs in a white dwarf. There are currently eight white dwarfs among the 100 star systems nearest the Sun.
The material in a white dwarf has no fusion reactions, so there is no source of energy. It cannot support itself by the energy generated by fusion but is supported by electron degeneracy pressure.
A carbon-oxygen white dwarf approaches this mass limit by mass transfer from a companion star and may explode as a kind Ia supernova via a process called carbon detonation.
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Problem 2.1 (closed system) a piston-cylinder device contains 25 g of saturated water vapor that is maintained at a constant pressure of 300 kpa. a resistance heater within the cylinder is turned on and passes a current i) of 0.2 a for 5 min for a 120 v source. at the same time, a heat loss of 3.7 kj occurs. determine the final temperature of the steam.
Questioning is the beginning of the scientific inquiry process. True or False
If the forces acting upon an object are balanced, then the object
A) All of these
B) Might be stopped.
C) Might be moving at a constant velocity
D) Is not accelerating
The first "lunar olympics" is to be held on the Moon inside a huge dome. Of the usual Olympic events-track and field, swimming, gymnastics, and so on- which would be drastically affected by the Moon's lower gravity? (Select all that apply.)
Jumping
Bicycling
Swimming (on a level track)
Throwing things
Running races (on a level track)
Weight lifting
Jumping, throwing, and weight lifting Olympic events would be drastically altered by the Moon's lower gravity in a hypothetical lunar Olympics. Athletes could jump higher and throw further due to gravity being 1/6th of earth's. Similarly, weights would feel lighter during weight lifting.
Explanation:In the context of the lunar olympics, it's critical to understand how the Moon's lower gravity would drastically impact certain sports events. The Moon's gravity is about 1/6th of Earth's gravity, which would significantly influence events involving lifting, jumping and throwing.
Jumping events would drastically change because the lower gravity would allow participants to jump about six times higher than on Earth. Throwing events would also see remarkable enhancements as objects would travel a greater distance before dropping.
Moreover, Weight lifting would be greatly impacted as the same weights would feel much lighter on the Moon. Interestingly, sports such as bicycling, swimming on a level track, and running races on a level track would not be significantly affected because these activities are less dependent on gravity relative to the others mentioned. Nonetheless, athletes might perform differently due to the reduced atmospheric pressure and possible difficulties in maintaining balance because of lower gravity.
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Final answer:
The lunar olympics would see drastic changes in events such as jumping, throwing, and weight lifting due to the Moon's 1/6th Earth gravity, while bicycling would be less affected. Swimming would also change, but it assumes the presence of water in a lunar environment.
Explanation:
The "lunar olympics" concept highlights how sports would be drastically affected by the Moon's reduced gravity. Given that gravity on the Moon is about 1/6th of that on Earth, events such as jumping, throwing things, and weight lifting would be greatly altered. With lower gravity, athletes could jump much higher, throw objects much farther, and lift heavier weights with less effort, compared to Earth. Running races might see a difference in athletes' strides and suspension period off the ground, potentially leading to faster times. However, activities like bicycling would be less affected as they rely more on the rider's strength and endurance than on gravitational forces. Swimming is not practical without substantial water, which is currently not present on the Moon, but if somehow managed in a dome, the reduced gravity could affect water dynamics and a swimmer's buoyancy, thereby affecting the execution of strokes and turns.
Ike is cutting the grass using a human-powered lawn mower. he pushes the mower with a force of 45 n directed at an angle of 41° below the horizontal direction. calculate the work that mike does on the mower each time he pushes it 9.1 m across the yard.
Which will result in positive buoyancy and cause the object to float?
When the force of gravity is more than the buoyant force
When the buoyant force is greater than the force of gravity
When the buoyant force is equal to the force of gravity
When the buoyant force is less than the force of gravity
the answer should be:
When the buoyant force is equal to the force of gravity
(stagnation pressure) a hang glider soars through standard sea-level air with an airspeed of 11.8 m/s. what is the gage pressure at a stagnation point on the structure?
The pressure at a hang glider's stagnation point is the sum of atmospheric pressure and dynamic pressure due to airflow collision, resulting in higher than atmospheric pressure. Using Bernoulli's equation with provided values, the stagnation pressure is 95430 Pa, and at 150 m/s, the pressure is approximately 82920 Pa.
The calculation of the gage pressure at a stagnation point involves understanding the flow dynamics around the structure of a hang glider as it moves through air. The stagnation point is where the airflow comes to a complete stop at the leading edge of the wing, causing the pressure to be higher than the atmospheric pressure due to the dynamic pressure of the colliding air mass. Using the provided stagnation pressure of 95430 Pa and the density of air at sea-level conditions (1.14 kg/m³), and given that the airspeed is 11.8 m/s, we would apply Bernoulli's equation to confirm the dynamic pressure at the stagnation point. But for the second part of the question, we adjust the equation to account for the higher speed of 150 m/s over the wing and determine that the pressure is 82920 Pa, acknowledging that turbulent flow makes these results approximate.
The stagnation pressure on a hang glider's stagnation point at sea-level conditions and an airspeed of 11.8 m/s can be calculated as 95430 Pa using the sea-level air density (1.14 kg/m³) and standard atmospheric pressure (8.89 × 10⁴ N/m²).
The concept being discussed in the question is the stagnation pressure which is the pressure at a point on a structure where the fluid (air) velocity is zero because the fluid there has been brought to rest abruptly. This pressure is higher than the atmospheric pressure because it includes both the atmospheric pressure and the additional pressure resulting from the air hitting the structure. The stagnation pressure (Pstagnation) at a hang glider's stagnation point can be calculated using Bernoulli's equation.
Given that the airspeed is 11.8 m/s, the sea-level air density is 1.14 kg/m³, and standard atmospheric pressure is 8.89 × 10⁴ N/m², we can find the stagnation pressure on the structure. Using the provided values:
Pstagnation = Po + (1/2) ρV²
Pstagnation = 8.89 × 10⁴ Pa + (1/2)(1.14 kg/m³)(11.8 m/s)²
Pstagnation = 8.89 × 10⁴ Pa + (1/2)(1.14)(139.24)
Pstagnation = 8.89 × 10⁴ Pa + 79.37 Pa
Pstagnation = 95430 Pa
What is an area of land in which all freshwater converges into the largest stream, ultimately draining into the largest body of water? hints what is an area of land in which all freshwater converges into the largest stream, ultimately draining into the largest body of water? estuary wetland spring watershed?
The answer is watershed. It is an area of land that drains all the rainfall and streams to a shared passage for instance, mouth of a bay, the outflow of a reservoir, or any point alongside a stream network. The word watershed is occasionally used interchangeably with catchment or drainage basin. This contains surface water like reservoirs, streams, lakes, and wetlands.
Answer:
THe answer is watershed
Explanation:
A heavy 2.0Kg ball is moving at 10m/s when it is caught. A light 1.5Kilogram ball is travelling at 20m/s when it caught. Which ball required the greater impulse?
Two passenger trains are passing each other on adjacent tracks. train a is moving east with a speed of 13 m/s, and train b is traveling west with a speed of 28 m/s.(a) what is the velocity (magnitude and direction) of train a as seen by the passengers in train b? (b) what is the velocity (magnitude anddirection) of train b as seen by the passengers in train a?
Since the two trains are passing in opposite directions, so this means that their relative velocities will be the sum of the two trains that is:
relative velocity = (13 + 28) = 41m/s
a. The passengers aboard on train B will see that train A is
moving at 41m/sec due east
b. The passengers aboard on train A will see that train B is moving at 41m/sec due west
Answer:
B and C
Explanation:
A rocket is launched at an angle of 56.0 degrees above the horizontal with an initial speed of 105 m/s. The rocket moves for 3.00 s along its initial line of motion with an acceleration of 28.0 m/s^2. At the time, it’s engines fail and the rocket proceeds to move as a projectile
A hiker leaves her camp and walks 3.5 km in a direction of 55° south of west to the lake. After a short rest at the lake, she hikes 2.7 km in a direction of 16° east of south to the scenic overlook. What is the magnitude of the hiker’s resultant displacement? Round your answer to the nearest tenth. km What is the direction of the hiker’s resultant displacement? Round your answer to nearest whole degree. ° south of west
1) Magnitude
Let's take south as positive y-direction and east as positive x-direction. Then we have to resolve both displacements into their respective components:
[tex]d_{1x} = -(3.5 km) cos 55^{\circ}=-2.0 km[/tex]
[tex]d_{1y} = (3.5 km) sin 55^{\circ}=2.87 km[/tex]
[tex]d_{2x} = (2.7 km) sin 16^{\circ}=0.74 km[/tex]
[tex]d_{2y} = (2.7 km) cos 16^{\circ}=2.60 km[/tex]
So, the components of the total displacement are
[tex]d_x = d_{1x}+d_{2x}=-2.0 km +0.74 km=-1.26 km[/tex] east (so, 1.26 km west)
[tex]d_y=d_{1y}+d_{2y}=2.87 km + 2.60 km=5.47 km[/tex] south
So, the magnitude of the resultant displacement is
[tex]d=\sqrt{d_x^2+d_y^2}=\sqrt{(1.26)^2+(5.47)^2}=5.61 km[/tex]
2) Direction
the direction of the hiker's displacement is
[tex]\theta= arctan(\frac{d_y}{d_x})=arctan(\frac{5.47}{1.26})=arctan(4.34)=77.0^{\circ}[/tex] south of west.
The magnitude of the hiker's resultant displacement is 5.8 km south of west.
Explanation:To find the magnitude of the hiker's resultant displacement, we need to first find the x and y components of the displacement vectors.
Path 1, the hiker walks 3.5 km in a direction of 55° south of west. The x component of this displacement is -3.5 * cos(55°) = -2.503 km, and the y component is -3.5 * sin(55°) = -2.845 km.
Path 2, the hiker walks 2.7 km in a direction of 16° east of south. The x component of this displacement is 2.7 * sin(16°) = 0.732 km, and the y component is -2.7 * cos(16°) = -2.606 km.
The total x component is -2.503 + 0.732 = -1.771 km, and the total y component is -2.845 - 2.606 = -5.451 km. Using the Pythagorean theorem, the magnitude of the resultant displacement is sqrt((-1.771)^2 + (-5.451)^2) = 5.797 km.
The direction can be found using the inverse tangent function, atan((-5.451)/(-1.771)) = 73°. Since the displacement is south of west, the direction is 180 - 73 = 107° south of west.
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Morgan has a mass of 85 kg and is on top of a bed in such a position that she can apply a pressure of 9530 n/m^2 on the mattress. would you calculate that morgan is standing sitting or lying on the bed.
To determine Morgan's position on the bed (whether standing, sitting, or lying), one must calculate the area of contact she has with the bed using her mass and the pressure she exerts. By comparing the calculated contact area with typical areas for different positions, one can infer her position.
Explanation:The question asks to determine whether Morgan is standing, sitting, or lying on the bed based on the pressure she exerts on the mattress and her mass of 85 kg. Pressure is defined as the force applied per unit area; in this case, force is due to Morgan's weight. Given that Morgan's weight (W) is the product of her mass (m) and Earth's gravity (g), we can write W = m * g = 85 kg * 9.81 m/s2. The weight finds us the force Morgan exerts downward.
To find the area of contact (A), we rearrange the pressure formula P = F/A, to A = F/P. Inserting the given pressure (P = 9530 N/m2) and her weight calculated earlier, we can find the area. A smaller contact area would suggest standing, while a larger area would suggest sitting or lying down. For example, if calculated area is around the size of feet, she's likely standing; if it's larger - similar to a body's contact area when sitting or much larger - she's sitting or lying down, respectively.
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A 5000 kg truck is parked on a 7.0â slope. how big is the friction force on the truck?
A thermos bottle has two layers, a glass layer and a vacuum layer. The vacuum layer is the better _____.
If an object mechanical energy is equal to its potential energy how much Connecticut energy does the object have
Why do ultraviolet rays from the sun reach earth
Because not all stars are the same distance from the earth, it can be difficult to determine
"Giant Swing", the seat is connected to two cables as shown in the figure (Figure 1) , one of which is horizontal. The seat swings in a horizontal circle at a rate of 37.0 rev/min .
For general projectile motion, which of the following best describes the horizontal component of a projectile's acceleration? Assume air resistance is negligible.
-The horizontal component of a projectile's acceleration continually decreases.
-The horizontal component of a projectile's acceleration is zero.
-The horizontal component of a projectile's acceleration remains a nonzero constant.
-The horizontal component of a projectile's acceleration continually decreases.
-The horizontal component of a projectile's acceleration initially decreases and then increases.
Answer:
The horizontal component of a projectile's acceleration is zero
Explanation:
When calculating all the different components of a projectile (acceleration, initial velocity, final velocity, etc.), you need to break it up into its X and Y directions.
During free fall, the only force acting on the projectile is gravity, and since gravity acts down (in the Y direction), there is no force acting in the X direction. Hence, the acceleration in the X direction is zero.
find the velocity vb for the case where the acceleration is 7.66 m/s2. Anawer in units of m/s
Find the speed at which Superman (mass=76.0 kg) must fly into a train (mass = 19969 kg) traveling at 65.0 km/hr to stop it.
Running into the train at that speed would severely damage both train and passengers. Calculate the minimum time Superman must take to stop the train, if the passengers experience an average horizontal force of 0.540 their own weight.
How far does the train then travel while being slowed to a stop?
the blank secrets chemical messages that circulate through the blood and also communicates messages that influence behavior and many aspects of the biological functioning
What’s the velocity of an 11-kilogram object with 792 joules of kinetic energy?
7 m/s
8 m/s
9 m/s
11 m/s
12 m/s
Answer:
12 m/s bye
Explanation:
The velocity of the object is 12 m/s. The correct answer is 12 m/s. The correct option is (e).
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 0.5 × m × v²
Where:
KE is the kinetic energy
m is the mass of the object
v is the velocity of the object
The object has a mass of 11 kilograms and kinetic energy of 792 joules, we can rearrange the formula to solve for velocity:
v² = (2 × KE) / m
v = √((2 × KE) / m)
v = √((2 × 792) / 11)
v = 12 m/s
So, the correct answer is 12 m/s. The correct option is (e).
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You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the earth with enough speed to make it to the moon. Some information that will help during this problem: mearth = 5.9742 x 1024 kg rearth = 6.3781 x 106 m mmoon = 7.36 x 1022 kg rmoon = 1.7374 x 106 m dearth to moon = 3.844 x 108 m (center to center) G = 6.67428 x 10-11 N-m2/kg2 1) On your first attempt you leave the surface of the earth at v = 5534 m/s. How far from the center of the earth will you get?
The distance from the center of the earth that you will get, given that you leave the surface of the earth with a velocity of 5534 m/s, is [tex]6.5099\times10^6\ m[/tex]
How to calculate the distance from the earth you will get to?
The distance from the center of the earth that you will get, knowing that you leave the surface of the earth with a velocity of 5534 m/s can be calculated as shown below:
Velocity of takeoff (v) = 5534 m/sMass of earth (M) = 5.9742×10²⁴ KgGravitational constant (G) = 6.67428×10¯¹¹ Nm²/Kg²Distance you will get considering your takeoff velocity (d) =?[tex]d = \frac{GM}{2v^2} \\\\d = \frac{6.67428\times10^{-11}\ \times\ 5.9742\times10^{24}}{2\ \times\ 5534^2} \\\\d = 6.5099\times10^6\ m[/tex]
From the above calculation, we can conclude that the distance you will get is [tex]6.5099\times10^6\ m[/tex]
A large plate is fabricated from a steel alloy that has a plane strain fracture toughness of 82.4 mpa1m (75.0 ksi1in.). if the plate is exposed to a tensile stress of 345 mpa (50,000 psi) during service use, determine the minimum length of a surface crack that will lead to fracture. assume a value of 1.0 for y.
Fracture toughness, minimum crack length calculation for fracture under stress.
Fracture toughness is the ability of a material to resist brittle fracture when a crack is present. In this scenario, we are given a fracture toughness value of 82.4 MPa√m.
To determine the minimum length of a surface crack that will lead to fracture when exposed to a tensile stress of 345 MPa, we can use the plane strain fracture toughness formula.
By plugging in the given values and solving the equation, we can find the minimum length of the surface crack that will cause fracture.
To find the minimum crack length that could lead to fracture in a steel plate, the plane strain fracture toughness equation is used, incorporating the values for fracture toughness, applied stress, and the geometric factor Y.
To determine the minimum length of a surface crack that will lead to fracture in a steel plate subjected to a tensile stress during service, we can use the plane strain fracture toughness equation:
\[a = \left(\frac{1}{\pi} \cdot \left(\frac{K_{IC}}{\sigma \cdot Y}\right)^{2}\right)
\]
Where:
a is the crack lengthKIC is the plane strain fracture toughness, which is 82.4 MPa√m (75.0 ksi√in.) in this casesigma is the stress applied during service, given as 345 MPa (50,000 psi)
Plugging in the values, the minimum crack length a can be calculated as follows:
\[a = \left(\frac{1}{\pi} \cdot \left(\frac{82.4 \, \text{MPa}\sqrt{m}}{345 \, \text{MPa} \cdot 1.0}\right)^{2}\right)
\]
After calculating the expression inside the parenthetical first and then squaring it, you would divide by π to get the minimum crack length a.
Water (2510 g ) is heated until it just begins to boil. if the water absorbs 5.01×105 j of heat in the process, what was the initial temperature of the water?\
Which of the following is an appropriate unit for speed? *note: you can choose more than one.
A. miles/hour
B. meters/second
C. blocks/min
D. newtons/sec
Jack tries to place magnets on the door of his refrigerator. He observes that the magnets don’t stick. He guesses that the door of the refrigerator is made of a nonmagnetic substance. What stage of scientific investigation does his guess represent?