Which of the following expressions is equal to ?

Answer:

374.1

Step-by-step explanation:

Area of Hexagon = [tex]\frac{3\sqrt{3} }{2} * a^{2}[/tex]

The ' a ' is the side length.

So now we just plug in the values

[tex]\frac{3\sqrt{3} }{2} *12^{2}[/tex] = 374.12

The values of x and y, when the smaller triangle has an area of 10 cm² are x = 4cm and y = 5cm.

In the given triangle, the area can be expressed as [tex]\( \frac{1}{2} \times x \times y \)[/tex], where x and y represent the base and height of the triangle, respectively. Since the area is given as 10 cm², the equation becomes [tex]\( \frac{1}{2} \times x \times y = 10 \)[/tex].

To find x and y, we can rearrange the equation:

[tex]\[ x \times y = \frac{10 \times 2}{1} \][/tex]

[tex]\[ x \times y = 20 \][/tex]

Now, we need to find two numbers whose product is 20. The pair x = 4 and y = 5 satisfies this condition, as 4 × 5 = 20. Therefore, the values of x and y that satisfy the given area are x = 4cm and y = 5cm.

In conclusion, the solution x = 4cm and y = 5cm satisfies the given area condition. This is determined by substituting these values into the area formula, resulting in an area of 10 cm².

Answer:

w = 93°

Step-by-step explanation:

The angle with measure 142° forms a straight angle with the third angle in the triangle and are supplementary, thus

third angle = 180° - 142° = 38°

The sum of the 3 angles in the triangle = 180°

w = 180° - (38 + 49)° = 180° - 87° = 93°

Answer:

1/9

Step-by-step explanation:

(1/3)^2 = 1/3 x 1/3 =1/9

plus I checked the answer after I got it wrong so...

Answer:

[tex]\frac{1}{9}[/tex]

Step-by-step explanation:

This is a case of enlargement of a figure of scale factor [tex]\frac{1}{3}[/tex].

In any enlargement, [tex]Area(F')=k^2 Area(F)[/tex], where the transformation maps F onto F'.

In this case, let F be polygon XXX and let F' be polygon YYY. Hence,

[tex]Area(YYY) = k^2 Area (XXX)[/tex]

[tex]Area(YYY) = (\frac{1}{3})^2 Area(XXX)[/tex]

[tex]Area(YYY) = \frac{1}{9} Area(XXX)[/tex]

Therefore, the area of polygon YYY is [tex]\frac{1}{9}[/tex] of the area of polygon XXX.

Answer:

-2u + w ⇒ answer B

Step-by-step explanation:

* To solve this problem you must find the result from the graph

- The ray move from the origin 6 units to the left and then 1 unit up

∴ The result is <-6 , 1>

* Now lets check which answer give the same result

∵ u = <5 , -5> , v = <1 , -4> , w = <4 , -9>

# Answer A: w - 2v

∵ w = <4 , -9>

- Find 2v by multiply v by 2

∵ 2v = 2<1 , -4> = <2 , -8>

- Subtract 2v from w

∴ w - 2v = <4 , -9> - <2 , -8> = <(4 - 2) , (-9 - -8)> = <2 , -1> ≠ <-6 , 1>

# Answer B: -2u + w

∵ u = <5 , -5>

- Find -2u by multiply u by -2

∵ -2u = -2<5 , -5> = <-10 , 10>

- Add -2u and w

∵ w = <4 , -9>

∴ -2u + w = <-10 , 10> + <4 , -9> = <(-10 + 4) , (10 + -9)> = <-6 , 1> = <-6 , 1>

∴ The answer is B

Answer:

your answer would be b

Step-by-step explanation:

Answer:

16 ft²

Step-by-step explanation:

The area (A) of a triangle is calculated using the formula

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )

here b = 8 and h = 4, thus

A = [tex]\frac{1}{2}[/tex] × 8 × 4 = 16 ft²

Answer:

I believe the answer is B

Step-by-step explanation:

Answer:

the answer is B  

Step-by-step explanation:

[tex]\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ r=6.5\\ s=5.7 \end{cases}\implies 5.7=\cfrac{\theta \pi (6.5)}{180}\implies 1026=6.5\pi \theta \\\\\\ \cfrac{1026}{6.5\pi }=\theta \implies \stackrel{\textit{rounded up, using }\pi =3.14}{50.27=\theta }[/tex]

The measure of the angle at the centre of the circle made by the arc of length 5.7 cm that has a radius of 6.5 cm is 50.27°.

Any smooth curve connecting two points is called an arc. The arc length is the measurement of how long an arc is. The length of an arc is given by the formula,

[tex]\rm{ Length\ of\ an\ Arc = 2\times \pi \times(radius)\times\dfrac{\theta}{360} = 2\pi r \times \dfrac{\theta}{2\pi}[/tex]

where

θ is the angle, that arc creates at the centre of the circle in degree.

As we know that the length of an arc is given by the formula,

[tex]\rm{ Length\ of\ an\ Arc = 2\pi r \times \dfrac{\theta}{360^o}[/tex]

Given the length of the arc is 5.7 cm, while the radius of the circle is 6.5cm, therefore, the angle made by the arc at the centre of the circle is,

[tex]5.7 = 2\pi (6.5) \times \dfrac{\theta}{360^o}\\\\[/tex]

θ = 50.27°

Hence, the measure of the angle at the centre of the circle made by the arc of length 5.7 cm that has a radius of 6.5 cm is 50.27°.

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Answer:

an = 600,000 (1.15)^(n-1)

Step-by-step explanation:

So the first year, a₁ = 600,000.  The next year, a₂ = 690,000.  So:

r = a₂ / a₁

r = 690,000 / 600,000

r = 1.15

So an = 600,000 (1.15)^(n-1).

Your answer is correct!

Surface area is square units, so you would need to square the scale factor.

The length was tripled, which means it is a scale factor of 3

3^2 = 9

The surface area would increase by a factor of 9.

The answer is B.

Answer:

A

Step-by-step explanation:

You take the number of shirts you have and are focusing on. In this case concert (12) and divide it by the total number of shirts to get the expected.

You can use the fact when random picking of t shirts happen, the probability of picking the Concert shirt can be taken by number of concert t shirts in total number of shirt since there is no bias towards a particular t shirt except their frequency.

The frequency of  concert shirts obtained out of selected shirts compare to the expected frequency of the concert shirt as:

Option A: The frequency is 1 fewer that expected.

Suppose there are 100 fruits and 50 of them are apples and 50 other are mangoes. Then we can say that each one of the two fruit is apple and other one is mango. This 1 apple per 2 fruit is telling frequency of apples in selected 2 fruits.

Frequency is number of amount that item is present in the selected group.

The expected frequency can be obtained by seeing how many such objects are available to how many total objects.

You can think of expected frequency as how many of the considered object we expect to be present in the total amount of objects.

Thus, we have:
Expected frequency for concert shirt is 12 per 30 shirts or 4 per 10( i divided by 3) shirts or 2 per 5 shirts ( divided by 2). You can convert this to percent or probability too or ratio too like

2:5 = 2/5 = 0.4 = 40% (all four represent how many of the concert shirts are expected to be present out of amount of total shirts selected).

The frequency obtained from the selection contains 3 concert shirts out  of 10 selected shirts.

Since the expected frequency of the concert shirts per 10 shirts selected is 4, and the frequency we obtained is 3, thus. the frequency obtained is 1 fewer than the expected.

Thus,

Option A: The frequency obtained is 1 fewer than expected.

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The store will have 29 pizzas.

This is because:

D is the correct answer

Answer:

10 pounds

Step-by-step explanation:

You forgot the inequality sing, but since Antoine can't spend more than $18.20, I am positive that the sign is [tex]\leq[/tex] (Antony can spend $18.20 or less than $18.20).

Therefore, our inequality is: [tex]1.30x+5.20\leq 18.20[/tex]

where [tex]x[/tex] is the pounds of oranges

Let's solve step-by-step to find how many pounds of oranges he can buy

Step 1. Subtract 5.20 fro both sides of the inequality

[tex]1.30x+5.20-5.20\leq 18.20-5.20[/tex]

[tex]1.30x\leq 13[/tex]

Step 2. Divide both sides of the inequality by 1.30

[tex]\frac{1.30x}{1.30} \leq \frac{13}{1.30}[/tex]

[tex]x\leq 10[/tex]

We can conclude that Antony can buy 10 pounds of oranges.

The answer is:

The second option,

[tex]SU=13.02=13[/tex]

We are working with a right triangle, it means that we can use the following trigonometric property:

[tex]Tan(\alpha)=\frac{Opposite}{Adjacent}[/tex]

Which applied to our problem, will be:

[tex]Tan(\alpha)=\frac{TU}{SU}[/tex]

We are given:

m∠S, equal to 21°

The side TU (opposite) equal to 5 units.

So, substituting and calculating we have:

[tex]SU=\frac{TU}{Tan(\alpha)}[/tex]

[tex]SU=\frac{5units}{Tan(21\°)}[/tex]

[tex]SU=13.02=13[/tex]

Hence, the answer is the second option

[tex]SU=13.02=13[/tex]

Have a nice day!

Answer:

13.0

Step-by-step explanation:

The given angle is m<S=21.

The given side length UT=5 units.

This side length is opposite to the given angle.

Since we want to find SU, the adjacent side; we use the tangent ratio to obtain;

[tex]\tan 21\degree=\frac{opposite}{adjacent}[/tex]

[tex]\tan 21\degree=\frac{5}{SU}[/tex]

This implies that;

[tex]SU=\frac{5}{\tan 21\degree}[/tex]

Therefore SU=13.025

The nearest tenth

SU=13.0

Answer:

The answer is C

Step-by-step explanation:

I just took the exact same test and got a 100% on it, I had previously answered this question when echo2155 rudely claimed that I didn't show any work, most people just answer the question and don't show work because most people just want the answer not the work for it. IF YOU AGREE WITH ME GIVE A THANKS AND 5-STARS, AND COMMENT "BOO echo2155!"

Thank you all who do this!

Answer:

Difference

Step-by-step explanation:

Remember that the therms of any subtraction problem are minuend, subtrahend, and difference.

- The minuend is the number from which you subtract something. For example, in the subtraction problem 4 -3 = 1, 4 is the minuend (you are subtracting 3 form it).

- The subtrahend is the number you subtract (from the minuend). For example, in 4 - 3 = 1, 3 is the subtrahend (you are subtracting 3 from the minuend 4).

- The difference is the result of subtracting the subtrahend form the minuend, in other words, the result of the subtraction problem. For example, in 4 - 3 = 1, 1 is the difference (the result)

We can conclude that the result of a subtraction problem is called the difference.

. In mathematics, the answer to a subtraction problem is called the difference.

For example, when you subtract 3 from 5, you perform the following calculation:

5 - 3 = 2

Here, 2 is the difference. Similarly, if you subtract -6 from 2, you change the sign of the number being subtracted and then add:

2 - (-6) = 2 + 6 = 8

The answer, 8, is the difference as well.

The concept of difference holds true for both scalar and vector quantities. For both types, the difference is the result of the subtraction operation.

Answer:

  see below

Step-by-step explanation:

You want terms that have a common ratio of 3, so the term in the summation will be 3 to some power. Only the first expression matches that requirement.

You can try different values of n to see if they fit the problem description.

  n = 1: 1(3)^0 = 1(1) = 1

  n = 2: 1(3)^1 = 1(3) = 3

  n = 3: 1(3)^2 = 1(9) = 9 . . . . . the third triangle in the set has 9 shaded triangles, as this expression predicts. Thus, we see the problem description being matched by the first answer choice shown.

Answer:

A

Step-by-step explanation:

egde 2020

Answer:

1). Option C

2). Option A

Step-by-step explanation:

The given vertices of polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8) and E(6, 6)

After reflection new polygon formed MNOPQ has the vertices M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8) and Q(-6, 6).

By comparing the vertices we find the x-coordinates of polygon ABCDE have been changed to MNOPQ by negative notation only.Y- coordinates are same.

Therefore, polygon ABCDE has been reflected across the y-axis.

Option C. is the answer.

If polygon MNOPQ is translated 3 units right and 5 units down then the new vertices of congruent polygon VWXYZ will be

M(-2, 8) = [(-2 - 3), (8 + 5)] = (-5, 13)

N(-4, 12) = [(-4 - 3), (12 + 5)] = (-7, 17)

O(-10, 12) = [(-10 - 3),(12 + 5)] = (-13, 17)

P(-8, 8) = [(-8 - 3), (8 + 5)] = (-11, 13)

Q(-6, 6) = [(-6 -3),(6 + 5)] = (-9, 11)

Therefore, Option A. is the correct option.

To find the change in the temperature, solve for the equation below.

[tex]x - 13 = -4[/tex]

We now know that the temperature changed by 9 degrees.

[tex]x = 9[/tex]

So, we are looking for the answer which indicates that the temperature changed by 9 degrees.

[tex]-4 + 13 = 9[/tex]

The equation that would be used to show the difference in temperature from Saturday to Sunday is -4 + 13 = 9.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

The temperature Saturday is -13°, and on Sunday it is -4°.

The change in the temperature, solve the equation below.

x - 13 = -4

Now, we know that the temperature changed by 9 degrees.

x = 9

The answer indicates that the temperature changed by 9 degrees.

-4 + 13 =9

The equation that would be used to show the difference in temperature from Saturday to Sunday is -4 + 13 = 9.

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The area of a right triangle with side lengths 7 and 7 is [tex]\frac{bh}{2} = \frac{7*7}{2} = \frac{49}{2} = 24.5[/tex]

Answer: ≈ 13.98 in2

Step-by-step explanation:

A segment of a circle is a region bounded by an arc and its chord.

To determine the area of the segment, begin by finding the area of the sector defined by the central angle.

A sector of a circle is a region bounded by two radii of the circle and their intercepted arc.

The formula for the sector area is A = πr2 (m∘/360∘).

It is given in the figure that central angle MNO is a right angle. So, m∠MNO = 90∘. It is also given that r = 7 in.

Substitute the given values into the formula and simplify.

A = π(7)2 (90∘/360∘) = 49/4π in2

Find the area of △MNO.

Since the radii in a circle are congruent, NO = NM = 7.                                  To find the area of △MNO, use the formula for the area of a triangle, A = 1/2bh.

Substitute 7 for b and 7 for h, then simplify.

A = 1/2 (7) (7) = 24.5 in2

The area of the segment is the difference between the two areas, the area of the sector and the area of the triangle.

A = 49/4π − 24.5 ≈ 13.98 in2

Therefore, the area of segment MNO is ≈ 13.98 in2.

Answer:

Expand the polynomial using the FOIL method.

− 8 x^ 2- 26 x − 15

[tex]\bf \begin{array}{|cl|ll} \cline{1-2} term&value\\ \cline{1-2} f(1)&\\ f(2)&\\ f(3)&7\\ f(4)&7r\\ f(5)&7rr\\ &252\\ \cline{1-2} \end{array}\qquad \qquad 7rr=252\implies 7r^2=252\implies r^2=\cfrac{252}{7} \\\\\\ r^2=36\implies r=\sqrt{36}\implies r=6 \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{|cl|ll} \cline{1-2} term&value\\ \cline{1-2} f(1)&\stackrel{\frac{7}{6}\div 6}{\cfrac{7}{36}}\\ &\\ f(2)&\stackrel{7\div 6}{\cfrac{7}{6}}\\ &\\ f(3)&7\\ f(4)&42\\ f(5)&252\\ f(6)&1512\\ \cline{1-2} \end{array}[/tex]

notice, once we know what the common factor "r" is, from the 3rd term we can simply multiply it by "r" to get the next term, and divide the 3rd term by "r" in order to get the previous term, namely the 2nd term, and then divide the 2nd by "r" to get the 1st one.

Answer:

16^3 is 16^(3/9) = 16^(1/3) = 2 ³√2

Step-by-step explanation:

is it 9 times square root of 16 cubed, or is it really 9th root? I think it's

9th root of 16^3 is 16^(3/9) = 16^(1/3) = 2 ³√2

Answer:

3sqr(x) root is 0

Step-by-step explanation:

the awnser should be -x^2 +2

Answer:

y = -x^2+2

Step-by-step explanation:

shift down y=x^2 for 2 units then it becomes y = x^2-2

reflect across x-axis then it becomes y = -(x^2-2) which is y = -x^2+2

Answer:

Step-by-step explanation:

(look at the picture)

We have opposite and adjacent. Therefore we must use the tangent:

[tex]\tangent=\dfrac{opposite}{adjacent}[/tex]

[tex]adjacent=500\\opposite=x\\\tan10^o\approx0.1763[/tex]

Substitute:

[tex]\dfrac{x}{500}\approx0.1763[/tex]       multiply both sides by 500

[tex]x\approx88.15\to x\approx88.2[/tex]

Probability=number of favorable outcomes/ number of all possible outcomes

P(1st green and 2nd blue) = 2/6 x 3/6 = 1/6

Answer:

Choice A. [tex]\frac{7\sqrt{x}}{6}[/tex] is the correct choice.

Step-by-step explanation:

Given expression for the quotient is [tex]\frac{\sqrt{98x^3}}{\sqrt{72x^2}}[/tex].

Now we need to find the equivalent choice of [tex]\frac{\sqrt{98x^3}}{\sqrt{72x^2}}[/tex].

So let's find that by rewriting them inside same radical

[tex]\frac{\sqrt{98x^3}}{\sqrt{72x^2}}[/tex]

[tex]=\sqrt{\frac{98x^3}{72x^2}}[/tex]

[tex]=\sqrt{\frac{49x^3}{36x^2}}[/tex]

[tex]=\sqrt{\frac{49x}{36}}[/tex]

[tex]=\frac{7\sqrt{x}}{6}[/tex]

Hence choice A. [tex]\frac{7\sqrt{x}}{6}[/tex] is the correct choice.

Answer:

Step-by-step explanation:

Answer:

23.32 degrees

Step-by-step explanation:

We set up a large right triangle that has 2 triangles within it.  The large triangle is a right triangle.  The height of it is the height of the tower, the base angle is 62, the hypotenuse is 95, and the base measure is y.  The other triangle has the same height which is the height of the tower, the angle is what we are looking for, and the base measure is 150 feet beyond y, so its measure is y + 150.  We have enough information to find the height of the tower, so let's do that first.  Going back to the first smaller triangle.  

[tex]sin62=\frac{x}{95}[/tex] so the height of the tower is 83.88 feet.  Now we need to solve for y.  Using that same triangle and the tangent ratio, we find that [tex]tan62=\frac{83.88}{y}[/tex].  Now let's do the same thing for the other triangle with the unknown angle.

[tex]tan\beta =\frac{83.88}{y+150}[/tex]

Solve both of these for y.  The first one solved for y:

[tex]y=\frac{83.88}{tan62}[/tex]

The second one solved for y will simplify to:

[tex]y=\frac{83.88-150tan\beta }{tan\beta }[/tex]

Now that these are both solved for y, and y = y, we can set them equal to each other by the transitive property of equality:

[tex]\frac{83.88-150tan\beta }{tan\beta }=\frac{83.88}{tan62}[/tex]

Cross multiply to get this big long messy looking thing:

[tex]tan62(83.88-150tan\beta )=83.88tan\beta[/tex]

Distribute through the parenthesis to get

[tex]83.88tan62-[(tan62)(150tan\beta)]=83.88tan\beta[/tex]

Get the unknown angles on the same side so it can be factored out:

[tex]83.88tan62=83.88tan\beta +[(tan62)(150tan\beta )][/tex]

And then factoring it out gives you:

[tex]83.88tan62=tan\beta(83.88+150tan62)[/tex]

Divide to get

[tex]tan\beta =\frac{83.88tan62}{83.88+150tan62}[/tex]

Do this on your calculator in degree mode to give you an angle measure of 23.32°.  I know this is really hard to follow without being able to draw the pics for you like I do in my classroom, but hopefully you can follow my description and draw your own triangles and follow from that!

An angle of elevation is formed by two reference lines; the horizontal line and the line from the reference point to the point in view

The angle of elevation from the point on the ground where Joey is standing to the top of the tower is approximately 23.318°

Reason:

Given parameter;

Length of the wire = 95 ft.

Angle formed by the wire and the ground = 62°

Location Joey is standing behind the wire, L = 150 feet

Required:

The angle of elevation from the ground at the point where Joey is standing to the top of the tower

Solution:

The height of the tower, h = 95 × sin(62°) ≈ 83.88 feet

Distance of the tower to the point the wire touches the ground, d, is given as follows;

d = 95 × sin(62°) ≈ 44.6 ft.

The distance of of Joey from the base of the tower, D = L + d

D = 150 ft. + 44.6 ft. = 194.6 ft.

Distance of Joey from the base of the tower, D = 194.6 ft.

Let θ represent the angle of elevation from the point on the ground where Joey is standing to the top of the tower, we have;

[tex]tan(\theta ) = \dfrac{h}{D}[/tex]

Therefore;

Which gives;

The angle of elevation from the point on the ground where Joey is standing to the top of the tower, θ ≈ 23.318°

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