Which of the following statements is true?

-the freezing and boiling temperatures of a substance are the same.
-the freezing and condensation temperatures of a substance are the same.
-the freezing and melting temperatures of a substance are the same.
-the freezing, melting, and boiling temperatures of a substance are the same.

Please help!!

Answers

Answer 1

Correct answer choice is :


C) The freezing and melting temperatures of a substance are the same.


Explanation:


Fluids have a particular temperature at which they convert into solids, identified as their freezing point. In theory, the melting point of a solid should be the same as the freezing point of the liquid. In practice, small variations among these measures can be seen. The freezing point of a matter is the same as that substance's melting point. At this distinct temperature, the substance can exist as either a solid or a liquid. At temperatures below the freezing/ melting point, the substance is a solid.


Answer 2

Answer: The correct answer is "The freezing and melting temperatures of a substance are the same".

Explanation:

Freezing temperature: It is the temperature at which the liquid becomes the solid.

Melting temperature: It is the temperature at which the solid starts converted into liquid.

The freezing point of a substance is the same as the melting point of the substance. During melting and freezing of the substance, the temperature remains same as the energy is spent in changing the phase of the substance not in changing the temperature.

Latent heat is there. It is a hidden heat. It is required to change phase of the substance without showing temperature on thermometer.

Boiling temperature: It is the temperature at which liquid gets converted into vapors. At this temperature, vapor pressure of the liquid equals to the pressure surrounding the liquid.


Related Questions

Because cosmologists can't go out into space and test all of their theories, they must depend on the cosmological principle. This principle assumes that _____.
the universe stays at a steady state
any physical laws are the same for the entire universe
the universe is going to eventually collapse
the universe is cooling down

Answers

This principle assumes that any physical laws are the same for the entire universe.

It can also be said that physical laws are the same for everybody at any place in universe.

B.) Any physical laws are the same for the entire universe.

how does the volume occupied by a cubic centimeter compare with the volume occupied by a millimeter

Answers

One cubic centimeter and one milliliter are equal volumes.

The acceleration due to gravity on Earth is 9.80 m/s2. An African elephant can have a mass up to 6,050 kg. What is its weight?

Answers

The weight on earth is equal to m*g, where m is the mass and g is the gravitational force. 6050 (m) * 9.8 (g) = 59290 Newtons.
Final answer:

The weight of an object is calculated by multiplying its mass by the acceleration due to gravity. With the mass of the African elephant as 6050 kg and Earth's gravity at 9.80 m/s², the elephant's weight would be 59,290 Newtons.

Explanation:

The weight of an object is the force exerted on it due to gravity. It can be calculated using the formula Weight = Mass × Gravity. In this case, the mass of the African elephant is given as 6,050 kg, and the acceleration due to gravity on Earth is 9.80 m/s².

Thus by multiplying the mass of the elephant with the acceleration due to gravity, we get: Weight = 6,050 kg × 9.80 m/s² = 59,290 N. So the weight of the African elephant on Earth would be 59,290 Newtons.

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What two organelles should be labeled that WOULD NOT be found in an animal cell?

Answers

chloroplasts and vacuoles 

according to newton's first law of motion what is required to make an object slow down

Answers

Final answer:

According to Newton's first law of motion, an object at rest will remain at rest and an object in motion will continue moving at a constant velocity unless acted upon by an external force. To make an object slow down, an external force in the opposite direction of its motion, such as friction, is required.

Explanation:

According to Newton's first law of motion, an object will continue moving at a constant velocity unless acted upon by an external force. To make an object slow down, an external force in the opposite direction of its motion is required. This force is called friction. Friction can be caused by various factors, such as air resistance or contact with a surface.

Learn more about Newton's first law of motion

The velocity v of the flow of blood at a distance "r" from the central axis of an artery of radius "R" is: v = k(R^2^ - r^2^) where k is the constant of proportionality. Find the average rate of flow of blood along a radius of the artery. (use 0 and R as the limits of integration) ...?

Answers

As the  The average rate of flow is given by 
(1/(R - 0)) * ∫(r = 0 to R) k(R^2 − r^2) dr 
So what we do is that we proceed like this:
= (k/R) * ∫(r = 0 to R) (R^2 − r^2) dr 
= (k/R) * (R^2 r − r^3/3) {for r = 0 to R} 
= (k/R) * (R^2 * R − R^3/3) - 0 
= (k/R) * (2R^3/3) 
= (2k/3) R^2. 
I hope this can help you for good

Final answer:

The average rate of flow of blood along the radius of an artery is found by integrating the velocity equation v = k(R² - r²) from 0 to R, which results in an average velocity formula of (2/3)kR after integration and simplification.

Explanation:

The question asks to find the average rate of flow of blood along a radius of the artery using the given velocity equation v = k(R² - r²) and integrating between the limits 0 and R. To find the average velocity, we integrate the given equation across the artery's radius and then divide by the radius R to calculate the average.

The integration process involves calculating the integral of k(R² - r²) with respect to r, over the interval from 0 to R, which gives us kR²r - (kr³)/3 evaluated between 0 and R. Substituting the limits and simplifying, the result is (2/3)kR². To find the average velocity, we divide this by R, resulting in an average velocity of (2/3)kR.

The stress force that causes a mass of rock to pull or twist in opposite directions in called ______.

Answers

Shearing

The stress force that causes a mass of rock to pull or twist in opposite directions is called shearing.

Hope this helps! :)

All waves consist of a continuous series of _____.

pulses

circles

compressions

rarefactions

Answers

Answer: The correct answer is pulses.

Explanation:

Wave is a disturbance which carries energy from one particle to another. Wave is a continuous disturbance.

Pulse is a single disturbance. It travels through one point to another.

Sound wave consists of rarefaction and compression. It need medium to travel.

In the circular wave, the particles move both parallel and perpendicular to the motion of the wave.

Therefore, all waves consist of a continuous series of the pulses.

Which of the following best illustrates the role that gravity played in the formation of our solar system?
A. Gravity allowed the nebula to expand and move outward.
B. Gravity caused the nebula to cool enough for planets to form.
C. Gravity removed excess gas and dust from the cores of the planets.
D. Gravity pulled particles of dust and gas together to form planets.

Answers

D. Gravity forced dust and gas together to form the planets and our earth

Answer:

Option D

Explanation:

Gravity is a force of attraction by virtue of mass of a body. It is an attractive force. It is due to gravity that the planets and hence, the solar system was formed. Starting from the nebula, the gravity caused the nebula to contract and form start. From rest of the material, the dust and gas were pulled in together due to gravity to form planet. The gravity of the Sun holds the planets in their respective orbits.

Thus, option D is correct.

Elements used to make semiconductors for computers include germanium and

Answers

Elements used to make semiconductors for computers include germanium and "Silicon"

They mixed, when we need to make semi-conductors by the process of "Doping"

Hope this helps!

a particle moves along a straight line OX. at a time t(in seconds) the distance X(in metres) from the particle O is given by x=40+12t-t3. how long would the particle travel before coming to rest ...?

Answers

You should consider when the velocity is zero

first i would take the derivative of the equation motion, leaving you with :
x = 12 - 3t^2

next, set the velocity to zero and solve t, which will give you 
√4 = t = +/- 2

Hope this helps

Answer:

16m

Explanation:

Brittany is changing the tire of her car on a steep hill 22.4 m high. She stumbles and drops the 10.5-kg spare tire, which rolls down the hill, starting with an initial speed of 2.10 m/s.
What is the speed of the tire at the top of the next hill, which is 8.59 m high?

Answers

The speed of the tire at the top of the next hill, which is 8.59 m high, is approximately 15.12 m/s.

a) Variables:

  - [tex]\( h_1 \)[/tex] = Initial height of the hill (22.4 m)

  - [tex]\( h_2 \)[/tex] = Height of the next hill (8.59 m)

  - [tex]\( v_{i1} \)[/tex] = Initial speed of the tire (2.10 m/s)

  -[tex]\( v_{f1} \)[/tex] = Final speed at the top of the first hill

  - [tex]\( v_{f2} \)[/tex] = Final speed at the top of the next hill

  - g = Acceleration due to gravity (-9.8 m/s²)

b) Equation for the first hill:

[tex]\[ v_{f1}^2 = v_{i1}^2 + 2gh_1 \][/tex]

c) Calculate [tex]\( v_{f1} \)[/tex]:

[tex]\[ v_{f1}^2 = (2.10 \, \text{m/s})^2 + 2(-9.8 \, \text{m/s}^2)(22.4 \, \text{m}) \][/tex]

[tex]\[ v_{f1} \approx 16.83 \, \text{m/s} \][/tex]

d) Equation for the next hill:

[tex]\[ v_{f2}^2 = v_{f1}^2 + 2gh_2 \][/tex]

e) Solve for [tex]\( v_{f2} \)[/tex]:

[tex]\[ v_{f2}^2 = (16.83 \, \text{m/s})^2 + 2(-9.8 \, \text{m/s}^2)(8.59 \, \text{m}) \][/tex]

[tex]\[ v_{f2} \approx 15.12 \, \text{m/s} \][/tex]

The speed of the tire at the top of the next hill, which is 8.59 m high, is approximately 15.12 m/s.

Final answer:

The speed of the tire at the top of the next hill is 21.2 m/s.

Explanation:

To find the speed of the tire at the top of the next hill, we can use the principle of conservation of energy.

According to the principle of conservation of energy, the initial potential energy of the tire at the top of the first hill is equal to the final potential energy of the tire at the top of the next hill.

Therefore, we have:

mgh = 1/2 × mv²

Where m is the mass of the tire, g is the acceleration due to gravity, h is the height difference between the two hills, and v is the final velocity of the tire at the top of the next hill.

Plugging in the values, we get:

10.5 × 9.8 × 22.4 = 1/2 × 10.5 × v²

Solving for v, we find:

v = sqrt((2 × 10.5 × 9.8 × 22.4) / 10.5)

v = 21.2 m/s

A cyclist maintains a constant velocity of
4 m/s headed away from point A. At some
initial time, the cyclist is 253m from point A.
What will be his displacement from his
starting position after 64 s?
Answer in units of m

What will be his position from point A after
that time?
Answer in units of m

Answers

The answer is 509 m.

Let point B be 253 m from point A. Let point C be 64 s away from point B.
Let d1 be the displacements from point A to point B and d2 and be the displacements from point B to point C
Step 1. Calculate the displacement from the point B after 64 s.
Step 2. Calculate the displacement from the point A by summing up two distances (d1 and d2).

Step 1.
v = d2/t
v = 4 m/s
d2 = ?
t = 64s
____
4 = d2/64
d2 = 64 * 4 = 256 m


Step 2:
d = d1 + d2
d1 = 253 m
d2 = 256 m
d = 253 + 256 = 509m

Final answer:

The cyclist's displacement from the starting position after 64 seconds is 256 meters. Their position from point A after that time is 509 meters.

Explanation:

If a cyclist maintains a constant velocity of 4 m/s headed away from point A, their displacement after any given time can be calculated using the formula Δx = vt, where Δx is the displacement, v is the velocity, and t is the time. For a time of 64 seconds, the displacement would be Δx = (4 m/s) × (64 s) = 256 meters.

Since the cyclist starts 253 meters away from point A, the new position (total distance from point A) after 64 seconds can be found by adding the initial distance to the displacement. This gives us a total distance = 253 m + 256 m = 509 meters from point A.

What is the milky way?;

Answers

The Milky Way is the galaxy that contains our Solar System. Its name "milky" is derived from its appearance as a dim glowing band arching across the night sky whose individual stars cannot be distinguished by the naked eye.
Age: 13.21 billion years

Our galaxy, the Milky Way, appears to be a band of stars in the sky, but it's actually a disk. Hundreds of billions of stars are clumped into lines called spiral arms. Earth is located about half-way between the center of the Milky Way and its outer edge.

Audio frequency range of a human ear is 20Hz - 20000 Hz. Express the range in terms of time period ? Answer needed urgently. Pl. help. Thanks ! S.Ramya ...?

Answers

Using the term c in this case is a little confusing. It is more generic to use a general velocity, v. That way, in this case, we know to use the speed of sound. 

wavelength*frequency=v 

wavelength_20Hz = (345 m/s)/(1/20s) 

wavelength_20kHz = (345 m/s)/(1/20000s)


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The figure below shows an acceleration-versus-force graph for three objects pulled by rubber bands. The mass of object 2 is 0.20 kg. What are the masses of objects 1 and 3?

Answers

Final answer:

Without the graph, we can't calculate the exact masses. However, by finding the slope of the line representing each object on a force-versus-acceleration graph, and using Newton's Second Law (F=ma), we can solve for the objects' masses.

Explanation:

The question refers to an acceleration-versus-force graph for three objects but unfortunately no graph was provided. However, in order to calculate the mass of the objects from an acceleration-versus-force graph, we could potentially use Newton's Second Law (F = ma), where F is the force, m is the mass, and a is the acceleration. Here's how it would be done:

For each object, find the slope of the line connecting it to the origin. The slope will give you the acceleration of the object.If you are given the force (F), use Newton's Second law to solve for mass (m).Note that if you see a higher slope for one object compared to another, it means that the object has a lesser mass, because a lesser mass will lead to a greater acceleration under the same force.

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The masses of objects 1 and 3 are 0.25 kg and 1.5 kg, respectively.

To find the masses of objects 1 and 3, we can use Newton's second law of motion, which states that force is equal to mass times acceleration:

F = ma

We can rewrite this equation to solve for mass:

m = F / a

Step 1: Find the slope of the line for each object

The slope of a line is equal to rise over run. In an acceleration-versus-force graph, the rise is the acceleration and the run is the force.

For object 1, the slope of the line is 4a / 1 = 4a. This means that object 1 has an acceleration of 4a for every 1 unit of force.

For object 2, the slope of the line is 3a / 2 = 1.5a. This means that object 2 has an acceleration of 1.5a for every 1 unit of force.

For object 3, the slope of the line is 2a / 3 = 0.67a. This means that object 3 has an acceleration of 0.67a for every 1 unit of force.

Step 2: Calculate the mass of each object

Now that we know the acceleration of each object, we can use Newton's second law to calculate their masses.

Mass of object 1:

m1 = F / a1 = 1 / 4a = 0.25 kg

Mass of object 2:

m2 = F / a2 = 1 / 1.5a = 0.67 kg

Mass of object 3:

m3 = F / a3 = 1 / 0.67a = 1.5 kg

Conclusion

The masses of objects 1 and 3 are 0.25 kg and 1.5 kg, respectively.

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A car has a mass of 1,200 kg. What is its acceleration when the engine exerts a force of 600 N? (Formula: F=ma) 0.5 m/s2 2 m/s2 600 m/s2 1,800 m/s2

Answers

F=ma
just substitute everything you know
600 = 1200 a
a = 600 /1200 = 0.5 m/s^2

As per the question the car has a mass of 12,00 kg.

The engine exerts a force of 600 N.  [ here newton i.e N is the unit of force]

We are asked to calculate the acceleration of the particle .

From Newton's second law of motion we know that force acting on a particle is mass times the acceleration of the particle . Mathematically it can be written as-

                                   F = ma             [Here F is the applied force,m is the mass which is constant here and ' a' is the acceleration]

Here m =1200 kg

        F = 600 N

Hence the acceleration produced due to the force exerted by the engine on car is-                                        

                                     [tex]a =\frac{F}{m}[/tex]

                                           [tex]=\frac{600 N}{1200 kg}[/tex]

                                             [tex]=0.5 m/s^2[/tex]      [ans]  

A speeding car collides with a wall (attached to Earth). Consider the car-Earth system to be isolated. A loud sound is produced in the collision, and the car is deformed. What can you say about the momentum of the car-Earth system in this case? ...?

Answers

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below are the choices that can be found from other source:

A. The total momentum of the system is conserved.
B. The total momentum of the system is not conserved.
C. The total momentum of the system is zero.
D. The total momentum of the system is negative.

The answer is A. 

Answer:

A. The total momentum of the system is conserved.

A sled and rider, gliding over horizontal, frictionless ice at 4.7 m/s , have a combined mass of 80 kg . The sled then slides over a rough spot in the ice, slowing down to 3.4 m/s . What impulse was delivered to the sled by the friction force from the rough spot? Express your answer to two significant figures and include the appropriate units.

Answers

Impulse is the change in momentum.
All we need is the momentum before and after.

Momentum  =  (mass) x (speed)

Before:        =  (80 kg) x (4.7 m/s)  =  376 kg-m/s

After:           =  (80 kg) x (3.4 m/s)  =  272 kg-m/s

Change in momentum  =  (376 - 272) =  104 kg-m/s


Notice that when you work with impulse, you're USUALLY calculating

                           (force) x (time).

The force is in Newtons, and the time is in seconds,
so the impulse is usually in units of

                             Newton-seconds .

So how can I say that impulse and change of momentum are
the same thing ?  Am I trying to pull a fast one on you ?

Remember that    1 Newton is  1 kg-m/s²

So                       (force) x (time) 

                     =  (Newton) x (second) 

                     =  (kg-m/s²) x (second)  =  kg-m/s .

and  Momentum = (mass) x (speed)  =  (kg) x (m/s)

The units of impulse are the same as the units of momentum !

So when you give an object some impulse, you give it exactly
that much momentum.

A 3858 N piano is to be pushed up a(n) 3.49 m frictionless plank that makes an angle of 31.6 ◦ with the horizontal. Calculate the work done in sliding the piano up the plank at a slow constant rate. Answer in units of J.

Answers

the work done will be equal to the potential energy of the piano at the final position

P.E=m.g.h

.consider the plank the hypotenuse of the right triangle formed with the ground
.let x be the angle with the ground=31.6°
.h be the side opposite to the angle x (h is the final height of the piano)
.let L be the length of the plank

sinx=opposite side / hypotenuse
= h/L

then h=L.sinx=3.49×sin31.6°=0.638m

weight w=m.g
m=w/g=3858/10=385.8kg

Consider Gravity g=10m/s2

then P.E.=m.g.h=385.8kg×10×0.638=2461.404J

then Work W=P.E.=2451.404J

Answer:

7055.13 J

Explanation:

Step 1: identify the given parameters

Applied force on the piano = 3858NLength of plank = 3.49mangle between the plank and horizontal surface = 31.6⁰

Note: frictional force between the piano and horizontal surface is zero since the plank is frictionless.

Step 2: work done in sliding the piano up the plank = applied force X distance moved by the piano.

The distance moved by the piano is equal to the height above ground when the piano reach top of the plank.

make a sketch of right angle trianglelength of the plank is the hypotenuse sideangle between the hypotenuse and the horizontal is 31.6⁰height of the triangle is the height above ground , let it be the unknown  

Height of the triangle = 3.49m X sine31.6⁰

Height of the triangle = 1.8287m

Recall, height of the triangle is the height above ground which is equal to the distance moved by the piano

work done in sliding the piano up the plank = applied force X distance moved by the piano.

work done in sliding the piano up the plank = 3858N X 1.8287M

                                                                           = 7055.13 J

what is Initial temperature and final temperature equations??
...?

Answers

One that can help you is:
ΔT=TFinal−TInitial
That is of course adding both tmepratures. There is one more that is a lil bit more complex 
Tf=Ti−ΔHrxn∗nrxn/(Cp,water∗mwater)
This one is taking into account that yu can find temperature and that there could be a change with a chemical reaction. Hope this helps

Continental climates have _______ summers and ________ winters.

warm; cold
cool; cool
warm; warm
cool; warm

Answers

Continental climates have WARM summers and COLD winters. People who live with areas that experience continental climates must be prepared for the seasonal changes.

Answer:

Continental climates have WARM summers and COLD winters. People who live with areas that experience continental climates must be prepared for the seasonal changes.

Explanation:

Static, sliding and rolling are types of friction true or false

Answers

True because friction happens when two things are rubbed against each other and it creates force and sliding something vigorously against something else can create force.
its true because of all its friction durng movement

Let v(t)=t^2−3t be the velocity, in feet per second, of an object at time t, in seconds.

a) What is the initial velocity? ___ ft/sec

b) When does the object have a velocity of zero? If there is more than time, list all answers in a comma separated list. ___ seconds

Answers

initial velocity means v(0)so 0..
velocity of zero so equate v(t) to zero
0 = t^2 - 3tt(t-3) = 0
at t= 0 (as we found at a) and t = 3

Final answer:

The initial velocity of the object is 0 ft/sec. The points in time when the object has a velocity of zero are at t=0 and t=3 seconds.

Explanation:

To answer these questions, it's important to understand what the variables represent in this equation. The object's velocity is given by v(t)=t^2−3t where v is the velocity in feet per second and t is the time in seconds.

a) The initial velocity is the velocity of the object at the start, which means at time t=0. By substituting t=0 in the equation, we obtain v(0)=(0)^2 - 3(0) = 0 feet/sec.

b) The object has a velocity of zero when v(t) = 0. In other words, we need to solve the equation t^2−3t = 0 for t. Factoring, we get t(t - 3) = 0, thus t = 0, 3 seconds are the moments at which the object's velocity is zero.

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A push or pull that gives energy to an ob-
ject, causing that object to start moving, stop
moving, or change its motion is
1. friction.
2. pressure.
3. inertia.
4. a force. ...?

Answers

The answer is a force
The best and most correct answer among the choices provided by your question is the fourth choice or letter D.

A force is a push or pull that gives energy to an object, causing that object to start moving, stop moving, or change its motion.

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What do tennis and volleyball have in common?

Answers

Well it all depends on the speed and strength.

Democritus thought that matter was made of tiny particles
A. of earth, air, fire, and water.
B. that could not be divided.
C. that could be divided.
D. that were all round and smooth.

Answers

Democritus thought that matter was made of tiny particles that could not be divided.

Correct answer choice is :


B) That could not be divided.


Explanation:


Democritus was a Greek scholar who lived within 470-380 B.C. He elaborated the theory of the atom, Greek for permanent. Democritus thought that everything in the world was made up of atoms, which were tiny and durable. They assumed that matter was made up of very small particles. They named these particles atoms, which comes from an antique Greek word signifying permanent. These atoms were supposed to be absolutely indivisible and forever.

What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons?

Answers

1.8x10 sqaured newtons for all plato users

The value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 Newtons would be 181.81 Newtons.

What is friction?

The friction force prevents any two surfaces of objects from easily sliding over each other or slipping across one another. It depends upon the force applied to the object.

As given in the problem we have to find the  value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons,

Friction force =(coefficient of friction)*Normal force

40 = 0.22* Normal force

Normal Force = 40/0.22

                       =181.81 Newtons

Thus, the normal force comes out to be 181.81 Newtons.

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An airplane heads northeast at an airspeed of 700 km/hr, but there is a wind blowing from the west at 60 km/hr. In what direction does the plane end up flying? What is its speed relative to the ground?

Answers

Final answer:

The plane ends up flying northeast. To find its speed relative to the ground, use vector addition to calculate the resultant velocity as 694 km/hr.

Explanation:

Direction: The plane ends up flying northeast.

Speed Relative to the Ground: To find the speed relative to the ground, we need to calculate the resultant velocity. The plane's velocity relative to the air is northeast at an angle, while the wind blows from the west. Using vector addition, we determine the speed relative to the ground to be 694 km/hr.

Vector Addition: Vector addition is essential to determine the resultant velocity of the plane with respect to the ground, taking into account both the airspeed and the wind speed.

Which of the following is distance divided by the change in time?


displacement

acceleration

speed


velocity

Answers

Answer:

the correct answer is speed, velocity scored incorrectly on my quiz

Explanation:

Other Questions
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