which of these is a physical property? a. malleable b. easy to digest c.ddoes not burn d. becomes moldy quickly

The scientific method includes making observations, asking questions, researching, formulating a hypothesis, and testing the hypothesis through experimentation.

Steps of the Scientific Method

The scientific method is a process typically followed during a scientific investigation to gain knowledge and test ideas. The basic steps are:

Following these steps correctly helps ensure that the conclusions drawn are based on reliable evidence and logical reasoning. If the hypothesis is not supported by the experiment, alternative hypotheses should be proposed and tested. The method encourages iterative testing and refinement of hypotheses.

1. Mg₃N₂: Magnesium nitride

charge Mg = +2

charge N = -3

2. Al₂S₃: Aluminum sulfide

charge Al = +3

charge S = -2

The naming of chemical compounds is giving a special name to a compound that aims to facilitate the classification of compounds and facilitate the identification of a compound. The rules for naming chemical compounds have been determined by the IUPAC (International Union of Pure and Applied Chemistry)

This nomenclature includes the naming of ion compounds, covalent compounds, and polyatomic

For ionic compounds consisting of cations (ions +) and anions (ions -)

The naming is preceded by the cation then the anion with the -ide suffix added

Generally for this ion compound consists of metal elements as cations and non-metals as anions

Metal: cation, positively charged.

Nonmetal: negative anion.

The anion cation's charge is crossed

Example:

Fe₂S₃

Fe charge = +3

S charge = -2

The name: metal + non-metal + -ide

Example: BaCl₂ -> Barium chloride

For transition metals, which have several oxidation charges / numbers, write the oxidation number in roman numbers

Example: SnO: lead (II) oxide

SnO₂: lead (IV) oxide

The naming: name non-metal + non-metal + suffix -ide

In the elements given the prefix mono, di, tri, tetra, penta if more than one element is formed

Example:

SO₂: Sulfur dioxide

SO₃: Sulfur trioxide

The question that needs to be completed is

Determine the charge on each ion in the following compounds, and name the compound. Spelling counts! (a) Mg₃N₂ Name: Charges: Mg N (b) Al₂S₃ Name: Charges: Al S

1. In the compound Mg₃N₂

load Mg = +2

charge N = -3

Name: Magnesium nitride

2. In the Al₂S₃ compound

Al load = +3

load S = -2

Name: Aluminum sulfide

the chemical formula for each ionic compound.

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two functional groups that contain ionic charges

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Binary ionic compounds

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Keywords: ionic compound, the naming of chemical compounds

a. creative

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The solution which contains the largest number of moles of Chlorine ions is Choice D: 7.50 ml of 0.500m fecl3.

Definition:

The molarity of a solution is simply the ratio of the number of moles of the solute to the liters of solution.

For Choice (a):

For Choice (b):

For Choice (c):

For Choice (d):

For Choice (e):

Ultimately, The solution which contains the largest number of moles of Chlorine ions is Choice D: 7.50 ml of 0.500m FeCl3.

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Final answer:

To measure the mass of an unknown metal using only a graduated cylinder, dropper, dish, ruler, funnel, and scoopula, you can use the displacement method.

Explanation:

To measure the mass of an unknown metal using only a graduated cylinder, dropper, dish, ruler, funnel, and scoopula, you can use the displacement method. Here are the steps:

Weigh the empty dish using a balance.

Fill the graduated cylinder with water up to a certain level and record the initial volume.

Carefully lower the metal into the graduated cylinder using the dropper, making sure it is fully immersed in water.

Measure the new volume of the water and metal in the graduated cylinder.

Calculate the volume of the metal by subtracting the initial volume from the final volume.

Determine the density of the metal by dividing its mass (obtained from the weighed dish) by its volume.

The mass of the unknown metal can then be obtained by multiplying its density by its volume.

Nitrogen element makes protein different from carbohydrate and fat

d. nitrogen

Proteins differ from carbohydrates and fats in that they contain the element nitrogen. While carbohydrates and fats are composed of carbon, hydrogen, and oxygen, proteins also contain nitrogen in addition to these elements.

Nitrogen is an essential component of amino acids, which are the building blocks of proteins. This nitrogen-containing structure allows proteins to have unique properties and functions that are distinct from carbohydrates and fats.

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Answer:

[tex]N_{2}O[/tex]

Explanation:

1. First suppose that the mass of the compound is 100g, so:

mass of N + mass of O = 100g

2. Multiply the percentages of N and O by the total mass of the compound:

For the N:

[tex]63.65*100g=63.65g[/tex] of N

For the O:

[tex]100-63.65=36.35g[/tex] of O

3. Divide the mass of each atom between the molar mass:

For the N:

[tex]\frac{63.65g}{14g}=4.54[/tex]

For the O:

[tex]\frac{36.35g}{16g}=2.27[/tex]

4. Divide each value by the smallest:

For the N:

[tex]\frac{4.54}{2.27}=2[/tex]

For the O:

[tex]\frac{2.27}{2.27}=1[/tex]

5. Write each atom with its number to obtain the molecular formula:

[tex]N_{2}O[/tex]

Ribosomes are cellular structures that facilitate protein synthesis by linking amino acids to form a protein. They are composed mainly of rRNA and proteins, with the rRNA playing a crucial role in the alignment during synthesis and catalysis of peptide bond formation. The abundance of ribosomes in certain cells like pancreatic cells indicates their significant role in high-rate protein production.

Ribosomes are essential cellular structures that are responsible for protein synthesis. The term synthesis indicates the process of combining various amino acids to produce a complete protein. These ribosomes link amino acids in a specific sequence, forming a polypeptide chain that will fold into a functional 3-dimensional protein structure. The size and shape of a protein determine its function, highlighting the direct relationship between structure and function in ribosomal activity.

Composed mainly of ribosomal RNA (rRNA) and protein, ribosomes have subunits that work together during protein synthesis. The rRNA plays a critical role in ensuring the proper alignment of the messenger RNA (mRNA), transfer RNA (tRNA), and the ribosome itself during this process. Additionally, the rRNA possesses enzymatic activity and catalyzes the formation of peptide bonds, which are essential in linking amino acids.

Ribosomes are abundantly found in cells that produce substantial amounts of proteins, such as pancreatic cells. Since these cells are responsible for creating digestive enzymes, numerous ribosomes are required to meet the high demand for protein synthesis. This abundance exemplifies the concept that the form, or structure, of a cell or cellular component reflects its function.

The structure of ribosomes, which consists of ribosomal RNA (rRNA) and proteins, allows them to efficiently synthesize proteins by facilitating the translation of messenger RNA (mRNA) into polypeptides.

Composition and Structure:

Ribosomes are composed of two subunits: a larger subunit and a smaller subunit. These subunits are made up of ribosomal RNA (rRNA) and proteins. The large subunit typically contains enzymatic activity essential for forming peptide bonds, while the small subunit is responsible for reading the sequence of mRNA.

Binding Sites:

Ribosomes have three critical binding sites: the A (aminoacyl) site, the P (peptidyl) site, and the E (exit) site. This specific arrangement allows for the sequential addition of amino acids to the growing polypeptide chain. The A site holds the incoming aminoacyl-tRNA, the P site holds the tRNA attached to the growing polypeptide chain, and the E site is where the empty tRNA exits.

Translation Process:

During translation, ribosomes move along the mRNA strand, facilitating the pairing of tRNA anticodons with the corresponding mRNA codons. This ensures that the correct amino acids are incorporated in the proper sequence to form proteins.

Efficiency and Functionality:

The ribosomal structure allows for high efficiency in protein synthesis. The close proximity of the A and P sites enables rapid transfer of the growing polypeptide chain from one tRNA to another, speeding up the translation process.

The mass of [tex]{\text{3}}{\text{.09}} \times {\text{1}}{{\text{0}}^{{\text{24}}}}[/tex] atoms of sulfur is [tex]\boxed{{\text{164}}{\text{.528 g}}}[/tex].

Further explanation:

Avogadro law:

According to Avogadro law, one mole of any substance contains [tex]{\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}[/tex] particles. These particles can be atoms or molecules.

Firstly the number of moles of sulfur is to be calculated. This is done by using equation (1).

The formula to calculate the moles of sulfur is as follows:

[tex]{\text{Number of moles of S}} = \frac{{{\text{Number of atoms of S}}}}{{{\text{Avogadro's Number}}}}[/tex]             …… (1)

The number of atoms of S is [tex]{\text{3}}{\text{.09}} \times {\text{1}}{{\text{0}}^{{\text{24}}}}[/tex].

The value of Avogadro’s number is [tex]{\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ atoms}}[/tex].

Substitute these values in equation (1).

[tex]\begin{aligned}{\text{Number of moles of S}}&{\mathbf{=}}\left( {{\text{3}}{\text{.09}} \times {\text{1}}{{\text{0}}^{{\text{24}}}}{\text{ atoms}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ atoms}}}}}\right) \\&={\text{5}}{\text{.1311}}\;{\text{mol}}\\\end{aligned}[/tex]

Now the moles calculated from equation (1) are used to evaluate the mass of sulfur. This is done by using equation (2).

The formula to calculate the mass of sulfur is as follows:

[tex]{\text{Mass of S}} = \left( {{\text{Moles of S}}} \right)\left( {{\text{Molar mass of S}}} \right)[/tex]           …… (2)

The moles of sodium are 5.1311 mol.

The molar mass of S is 32.065 g/mol.

Substitute 5.1311 mol for the moles of S and 32.065 g/mol for the molar mass of S in equation (2).

[tex]\begin{aligned}{\text{Mass of S}}&=\left({{\text{5}}{\text{.1311 mol}}}\right)\left({\frac{{{\text{32}}{\text{.065 g}}}}{{{\text{1 mol}}}}}\right)\\&=164.52{\text{8 g}}\\\end{aligned}[/tex]

Therefore the mass of sulfur is 164.528 g.

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1. How many moles of Cl are present in 8 moles of [tex]{\text{CC}}{{\text{l}}_4}[/tex]? https://brainly.com/question/3064603

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: sulfur, mass, atoms, Avogadro’s law, 164.528 g, 32.065 g/mol, S, molar mass of S, moles of S, 5.1311 mol, moles.

Final answer:

The mass of 3.09 x 10²⁴ atoms of sulfur can be calculated by first determining the number of moles using Avogadro's number, then multiplying by sulfur's molar mass, resulting in 164.16 grams.

Explanation:

To find the mass of 3.09 x 10²⁴ atoms of sulfur in grams, we first need to use Avogadro's number, which tells us that one mole of any substance contains approximately 6.022 x 10²³ atoms. Knowing that the molar mass of sulfur (S) is 32 g/mol, we can calculate the mass of the given number of sulfur atoms.

Calculate the number of moles of sulfur atoms: Number of moles = (3.09 x 10²⁴ atoms) / (6.022 x 10²³ atoms/mol) = 5.13 moles.

Calculate the mass of sulfur: Mass = (5.13 moles) x (32 g/mol) = 164.16 g.

Therefore, the mass of 3.09 x 10²⁴ atoms of sulfur is 164.16 grams.

A Triglyceride is the compound composed of three fatty acids and glycerol, and serves as the main form of fat storage in the bodies of humans and other animals.

The compound composed of three fatty acids  and glycerol is known as a Triglyceride. Triglyceride is the main form of fat stored in the bodies of humans and other animals. During digestion, the body breaks down fats into fatty acids and glycerol, which can then be absorbed into the bloodstream. The body can use these components to produce energy or to reassemble them into triglycerides for storage and later use.

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The number of electrons in the isotope of oxygen is eight. The atomic mass of sodium with 2 extra electrons is 25.

Isotopes are atoms of an element that have the same atomic number but a different atomic mass. Isotopes of an element carry the same number of electrons and protons. The numbers of neutrons in their respective nucleus is different.

For example, the isotope of oxygen is given as oxygen- 16, oxygen - 17, and oxygen-18 they all have eight electrons or protons.

If the number of neutrons in oxygen increase by one, it becomes the isotope of oxygen. As for isotope, the number of electrons is the same. So the electrons in the isotope of oxygen are equal to eight.

The mass number of sodium is 23 and If two extra neutrons are added to it. As we know, the mass number is equal to the sum of protons and neutrons. So atomic weight of the isotope will be equal to 25 i.e.(23 + 2).

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A carbon atom that exhibits sp2 hybridization is connected to three other atoms. This is due to the three regions of electron density surrounding the carbon atom in a trigonal planar arrangement.

In sp2 hybridization, the carbon atom is surrounded by three regions of electron density, positioned in a trigonal planar arrangement. This hybridized carbon atom is bonded to three other atoms. This situation can be seen in molecules like ethene (H2C=CH2) in which the carbon atom forms two single bonds with two hydrogen atoms and a double bond with another carbon atom. Therefore, an sp2 hybridized carbon atom is connected to three other atoms.

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Formic acid, HCOOH, is a weak electrolyte. In an aqueous solution, the solutes present are HCOOH molecules, H+ ions, and HCOO- ions. The chemical equation for the ionization of formic acid is HCOOH(aq) → H+ (aq) + HCOO- (aq). Only a small fraction of formic acid molecules dissociate into ions in solution.

HCOOH is formic acid, a weak acid. In an aqueous solution of formic acid, the solutes present are HCOOH molecules and the dissociated ions, H+ and HCOO-. The chemical equation for the ionization of formic acid is:

HCOOH(aq) → H+ (aq) + HCOO- (aq)

This equation shows that only a small fraction of formic acid molecules dissociate into ions in solution.

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