which property of congruence would prove that BD ≈ BD?
the reflexive property of congruence
the symmetric property of congruence
the transitive property of congruence
None of the choices are correct.
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Related Questions
value for X^2 left for 95% confidence interval when n=18
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From the table of Chi Square [tex](X^2)[/tex]
The value of [tex](X^2)[/tex] to the left for 95% confidence interval given a degree of freedom of 17 is 8.672
hey can you just please help me solve these two problems
1- according to the bipartisan policy center (BPC), 57.5% of all eligible voted in the 20112 presidential elections. while there are over 350 million Americans, the BPC estimates that only 219 million are eligible to vote. how many eligible voters in 2012 election?
2-sarah's sandwich shop sells a specialty sandwich for $4.95 that contains a quarter of a pound of turkey. if sarah buys 12 pounds of turkey meat but eats a tenth of a pound on the way to her sandwich shop, what is the maximum number of sandwiches she can make?
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well, she needs 1/4lb to make a sandwich, well, she bought 12lbs and then she couldn't resist, because she got some ketchup also I gather, she couldn't resist giving it a nibble and ate 1/10lb
so.. is 12 - 1/10, and how many times 1/4 goes into that difference
[tex]\bf 12-\cfrac{1}{10}\implies \cfrac{120-1}{10}\implies \cfrac{119}{10} \\\\\\ \textit{how many times }\frac{1}{4}\textit{ goes in to }\frac{119}{10}? \\\\\\ \cfrac{\frac{119}{10}}{\frac{1}{4}}\implies \cfrac{119}{10}\cdot \cfrac{4}{1}\implies \cfrac{238}{5}\implies \boxed{47\frac{3}{5}} \\\\\\ \cfrac{47\cdot 5+3}{5}\implies \cfrac{238}{5}[/tex]
well, noone is going to buy a half-eaten sandwich or 3/5 of a sandwich, so, she can only make 47 whole sandwiches, hmmmm I'm thinking she can just give the 3/5 to the dogs.
Quadrilateral ABCD is similar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 60 feet, 40 feet, and 30 feet long. If the two shortest sides of quadrilateral EFGH are 6 feet long and 12 feet long, how long is the 4th side on quadrilateral ABCD?
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Final answer:
The length of the fourth side on quadrilateral ABCD is 120 feet.
Explanation:
Given that quadrilateral ABCD is similar to quadrilateral EFGH, we can use the property of similar figures to find the length of the fourth side on quadrilateral ABCD.
If the two shortest sides of quadrilateral EFGH are 6 feet and 12 feet long, we can set up a proportion using the corresponding sides of the two quadrilaterals.
Let x be the length of the fourth side on quadrilateral ABCD.
Using the property of similar figures, we have:
(60/6) = (x/12)
Cross multiplying, we get:
6x = 720
Dividing both sides by 6, we find:
x = 120
Therefore, the length of the fourth side on quadrilateral ABCD is 120 feet.
Each figure is filled with unit cubes. Drag 22 figures whose combined volume is equal to 45 unit cubes.
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To solve this problem, what we have to do first is to calculate for the volumes of each figure. Let us start from the figure on the left going to the right. Let us call the figures 1 to 4. Formula for volume is:
V = l * w * h
Figure 1:
V1 = 4 * 3 * 1 = 12 unit cubes
Figure 2:
V2 = 3 * 2 * 3 = 18 unit cubes
Figure 3:
V3 = 2 * 2 * 4 = 16 unit cubes
Figure 4:
V4 = 3 * 3 * 3 = 27 unit cubes
The two combinations that would result in 45 total unit cubes would be:
V = V2 + V4 = 18 unit cubes + 27 unit cubes = 45 unit cubes
So the answers are:
Figure 2 and Figure 4
Find the value of x in 4000(1.5x) = 25,000. show all work
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25000/4000 = 1.5x
6.25 = 1.5x
25/6 = x
1.5x=6.25 divide both sides by 1.5
x=25/6
x=4 1/6
But that is pretty simplistic, I suspect that you actually meant this was an exponential function of the form:
4000(1.5^x)=25000 divide both sides by 4000
1.5^x=6.25 take the natural log of both sides
xln(1.5)=ln(6.25) divide both sides by ln(1.5)
x=ln(6.25)/ln(1.5)
x≈4.52 (to nearest hundredth)
Find the rectangular coordinates of the point with the polar coordinates. ordered pair negative 5 comma 5 pi divided by 3
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A ship traveled for 4 hours heading east and for 3 hours heading north. If the total distance traveled was 149 miles, and the ship traveled 3 miles per hour faster heading north, at what speed was the ship traveling east?
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if the ship travelled a total of 149 miles, then let's say it travelled East "d" miles and thus it travelled North the slack of 149 and "d", thus " 149 - d".
now, if the rate travelling East is say "r", then the faster rate going North is " r + 3".
[tex]\bf \begin{array}{lccclll} &distance&rate&time\\ &-----&-----&-----\\ East&d&r&4\\ North&149-d&r+3&3 \end{array} \\\\\\ \begin{cases} \boxed{d}=4r\\ 149-d=(r+3)3\\ ----------\\ 149-\boxed{4r}=3(r+3) \end{cases}[/tex]
solve for "r".
Can someone please help me solve this triangle problem, picture is shown.
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3(4t) (multiplication form)
these are two forms you can use to get your answer
answer: 12t
hope this helps
and
perimeter = 4t * 3
Which expression is equivalent to (7^3)−2
A- 1 over 7 times 7 times 7 times 7 times 7 times 7
B- 7
C- 1 over 7
D-negative 1 over 7 times 7 times 7 times 7 times 7 times 7
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The graph of a limacon curve is given. Without using your graphing calculator, determine which equation is correct for the graph.[-5, 5] by [-5, 5] (1 point)
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[tex]r = Acos \theta + B[/tex]
Now find A,B given 2 points:
[tex]r(0) = 5, r(\pi) = 1[/tex]
[tex]A +B = 5 \\ \\ -A+B = 1[/tex]
Solving this system yields:
[tex]A = 2, B = 3 \\ \\ r = 2cos \theta + 3[/tex]
Answer:
r = 2 - 3 cos θ
Step-by-step explanation:
This is the best I could come up with.
Please I'm stuck in this problem
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Without solving, decide what method you would use to solve each system: graphing, substitution, or elimination. Explain. 4s-3t=8 ; t=-2s-1
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4s-3(-2s-1)=8
Which figure has the correct lines of symmetry drawn in?
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The figure which has the correct lines of symmetry drawn is figure D.
What is line of symmetry?A line of symmetry refers to the line that divides a shape or an object into two equal and symmetrical parts.
The figure given is a five sided shape referred to as a pentagon.
A pentagon has five lines of symmetry.
Therefore, the correct line of symmetry is 5 lines drawn from each angle respectively.
Read more on line of symmetry:
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Sidney made $26 more than seven times Casey's weekly salary. If x represents Casey's weekly salary, write an expression for sidney's weekly salary
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Pediatric asthma survey, n = 50. suppose that asthma affects 1 in 20 children in a population. you take an srs of 50 children from this population. can the normal approximation to the binomial be applied under these conditions? if not, what probability model can be used to describe the sampling variability of the number of asthmatics?
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n=50, p=1/20, q=(1-p)=19/20, and npq=19/8=2.4
We would like np and npq to be a large number, at least greater than 10.
The normal approximation can always be applied, but the result will be very approximate, depending on the values of np and npq.
Situations are favourable for the normal approximation when p is around 0.5, say between 0.3 and 0.7, and n>30.
"Normal approximation" is using normal probability distribution to approximate the binomial distribution, when n is large (greater than 70) or exceeds the capacity of most hand-held calculators. The binomial distribution can be used if the following conditions are met:
1. Bernoulli trials, i.e. exactly two possible outcomes.2. Number of trials is known before and constant throughout the experiment, i.e. independent of outcomes.3. All trials are independent of each other.4. Probability of success is known, and remain constant throughout trials.
If all criteria are satisfied, we can model with binomial distribution, where the probability of x successes out of N trials each with probability of success p is given byP(x)=C(N,x)(p^x)(1-p)^(N-x)and,C(N,x) is number of combinations of selecting x objects out of N.
The mean is np, and variance is npq.
For the given situation, np=2.5, npq=2.375, so standard deviation=sqrt(2.375)=1.54.
n=50, p=1/20, q=(1-p)=19/20, and npq=19/eight=2.4
We would like np and npq to be a huge range, at least extra than 10.
The ordinary approximation can usually be carried out, but the result might be very approximate, relying on the values of np and npq.
conditions are favorable for the normal approximation when p is around 0.5, say among 0.3 and 0.7, and n>30.
For the given scenario, np=2.five, npq=2.375, so widespread deviation=sqrt(2.375)=1.54.
underneath what conditions binomial distribution tends to be everyday distribution?the theory states that any distribution becomes normally allotted whilst the variety of variables is satisfactorily massive. for example, the binomial distribution has a tendency to alternate into the regular distribution with suggest and variance.
Learn more about binomial distribution here: https://brainly.com/question/15246027
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A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in 30 minutes. How much faster does she have to work to grade the remaining papers in the allotted time?
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the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6
now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.
now if we take 1/6 as the 100%, what is 1/5 in percentage then?
[tex]\bf \begin{array}{ccllll} rate&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{1}{6}&100\\\\ \frac{1}{5}&x \end{array}\implies \cfrac{\frac{1}{6}}{\frac{1}{5}}=\cfrac{100}{x}\implies \cfrac{1}{6}\cdot \cfrac{5}{1}=\cfrac{100}{x}\implies \cfrac{5}{6}=\cfrac{100}{x} \\\\\\ x=\cfrac{6\cdot 100}{5}\implies x=120[/tex]
so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.
simplify the expression below. show your work. -(-7y+12)
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What is the distance between (–6, 2) and (8, 10) on a coordinate grid?
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(-6 , 2) and (8 , 10)
x₁ y₁ x₂ y₂
d = √(8 - (-6))² + (10 - 2)²
d = √(8+6)² + (10 - 2)²
d = √(14)² + (8)²
d = √(196) + (64)
d = √ 260
d = 2√65
I think this is right, but I am not sure.
Answer:
D. √260
Step-by-step explanation:
Use the distance formula then input the points (–6, 2) and (8, 10) into it to get √(-6 −2)^2 + (2 −10)^2. Finaly simplify/solve and you get √260.
Steve can complete the 100m dash in 10 seconds while Paul can run it in 12 seconds. How does Steve's time compare to Paul's?
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A geometry class has a total of 34 students. The number of males is 14 more than the number of females. How many males and how many females are in the class?
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one way is to substitute teh first into the second to get, 14+2f=34, or 7+f=17, or f=10. Since f is 10 and m+f=34, m=34-10=24.
Good luck!
What is the value of k in the equation below? 5k - 2k = 12? 1 1/5, 1 5/7, 3, 4
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5k - 2k = 12
Solve for K
3k = 12
Divide both sides by 3
3k/3 = 12/3
k = 4
The correct answer is : 4
I hope that helps!
Brainliest answer :)
Answer:4
Step-by-step explanation:
The principal $3000 is accumulated with 3% interest, compounded semiannually for 6 years.
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A=p (1+r/k)^kt
A accumulated amount?
P principle 3000
R interest rate 0.03
K compounded semiannually 2
T time 6 years
A=3,000×(1+0.03÷2)^(2×6)
A=3,586.85
simplify the expression I-30I
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How many inches are in a foot?
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find two consecutive even integers such that the smaller added to five times the larger give you a sum of 46.
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Second consecutive integer: n + 2 (next even integer)
n + 5(n + 2) = 46
n + 5n + 10 = 46
6n + 10 = 46
6n = 36
n = 6
n + 2 = 8
Your answer is 6 and 8
An earthquake with a rating of 3.2 is not usually felt. What is the value of x when the Richter scale rating is 3.2? Round your answer to the nearest hundredth.
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A bag of fruit contains 3 apples and 2 oranges and 1 banana and 4 pears.Gerald will randomly selected two pieces of fruit one at a time from the bag and not put is back. What is the probability that the first piece of fruit Gerald selects will be a banana and the second piece of fruit will be a pear??
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Final answer:
The probability that Gerald will first select a banana and then a pear from the bag without replacement is 2/45.
Explanation:
To determine the probability that Gerald selects a banana first and then a pear without replacement, we have to consider the total number of possible outcomes for each draw and the favorable outcomes for the event.
For the first draw, the total number of fruits is 10 (3 apples + 2 oranges + 1 banana + 4 pears). The favorable outcome of drawing a banana is 1 since there's only one banana.
The probability of drawing a banana on the first draw is therefore 1/10. After drawing the banana, there are 9 fruits left in the bag with 4 pears among them.
The probability of then drawing a pear is 4/9. To find the total probability of both events happening in sequence (a banana first and then a pear), multiply the two probabilities:
P(banana first and pear second) = P(banana first) × P(pear second)
= (1/10) × (4/9)
= 4/90
= 2/45.
The simplification process shows that the probability Gerald will first select a banana and then a pear is 2/45.
Write an equation for the function. Tells what each variable you use represents. A plant's height is 1.6 times its age in months.
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Since the growth rate of height for the plant is 1.6 times the independent variable and there is no starting point (so assume 0), our equation should look like this:
y = 1.6x
The plant's height is y and its age in months is x.
Hope my answer helped clear things up a bit.
A taxi cab charges $0.55 per mile in addition to a $1.75 flat rate fee. Susie has $10 to spend on a taxi cab ride. The taxi driver will not give anyone a ride unless they are going somewhere that is more than 2 miles away. Model Susie’s situation with a system of inequalities.
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1.75+(0.55x2)=2.85
As Susie only has 10 dollars to spend, she can't exceed that. So Susie must spend more than $2.85(minimum from the taxi) and less than $10(her money)
so,
$2.85<Susie<$10
5 times the difference of 29 and a number is 215. Which equation below can be used to find the unknown number?
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Answer:
The required equation is [tex]5(29-n)=215[/tex]
Step-by-step explanation:
Given : 5 times the difference of 29 and a number is 215.
To find : Which equation can be used to find the unknown number?
Solution :
Let the number be 'n'.
The difference of 29 and a number i.e. [tex]29-n[/tex]
5 times the difference of 29 and a number i.e. [tex]5(29-n)[/tex]
5 times the difference of 29 and a number is 215 i.e. [tex]5(29-n)=215[/tex]
Therefore, the required equation is [tex]5(29-n)=215[/tex]