Which statement is TRUE? Group of answer choices a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration. b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration. c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels. d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels. e) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.

Answers

Answer 1

Answer:

d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels.

Explanation:

a ) a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration.

It has negative acceleration in  the negative x-direction.

b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration.

It has a positive acceleration in the negative x-direction'

c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels.

It has a positive  acceleration in opposite direction.

e ) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.

It has a positive acceleration only in opposite direction .


Related Questions

An autotransformer is used to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer, to supply a 100-kilovolt amp load with 277 volts. What size autotransformer is needed? (Use the co-ratio to determine the size.)

Answers

An autotransformer is a type of electrical transformer that has only one winding, and portions of the same winding act as both the primary and secondary winding sides of the transformer. A 33.9 kVA autotransformer is needed to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer to supply a 100-kilovolt amp load with 277 volts, using the co-ratio method.

To determine the size of an autotransformer needed to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer to supply a 100-kilovolt amp load with 277 volts, we can use the co-ratio method.

The co-ratio is the ratio of the number of turns on the primary winding to the number of turns on the secondary winding of the transformer.

Secondary voltage: 480 V

Load voltage: 277 V

Load current: 100 kVA

To calculate the co-ratio, we can use the formula:

Co-ratio = Secondary voltage / Load Voltage

Co-ratio = 480 V / 277 V

Co-ratio ≈ 1.734

The co-ratio is approximately 1.734. To determine the size of the autotransformer needed, we can use the formula:

Size of autotransformer = Load kVA / (Co-ratio)²

Size of autotransformer = 100 kVA / (1.734)²

Size of autotransformer ≈ 33.9 kVA

Therefore, a 33.9 kVA autotransformer is needed to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer to supply a 100-kilovolt amp load with 277 volts, using the co-ratio method.

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Final answer:

To supply a 100 kilovolt-ampere load with 277 volts from a 480-volt secondary, an autotransformer that is roughly 1.73 times smaller than the original isolated type transformer is required. The size calculation is derived from the co-ratio (the ratio of primary to secondary voltages), which here equals to 480/277 = 1.73.

Explanation:

The subject in question is regarding the use of an autotransformer, specifically, what size is needed to reduce the voltage from 480 volts to 277 volts in order to supply a 100 kilovolt-ampere load. First, we need to handle the co-ratio. The co-ratio of a transformer is the ratio of primary to secondary voltages, often used to calculate the size of a transformer. In this case the co-ratio would be 480/277 = 1.73.

Utilizing the transformer equation, we can comprehend that the voltage reduction from 480 to 277 volts that undergoes in an autotransformer proposes a comparable reduction in size of the transformer. Based on this, the autotransformer needed should be around 1.73 times smaller than the original isolated type transformer.

As a brief primer on the functioning of the transformers, they operate on the principle of electromagnetic induction and are used in power distribution systems to step-up or step-down the voltages. This allows the efficient transmission of power over long distances and also the provision of the correct voltage levels suitable for different uses.

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The multi-link mechanism in the Variable Compression Turbo Engine _____, thus varying the compression ratio.

A. Adjusts how far down the piston travels
B. Can change one individual piston's operation independent of the other three
C. Acts like a fixed-length connecting rod

Answers

Answer:

A. Adjusts how far down the piston travels

Explanation:

This type of engine changes the possition of the piston in order to modify the compression chamber volume and therefore the compression ratio of the engine. The volume of the chamber is proportional to the run of the piston (how far down the piston travels)

This engine is used to achive the optimal compression rate in each individual stage.

The multi-link mechanism in a Variable Compression Turbo Engine adjusts the piston travel to vary the compression ratio, providing efficient operation under different conditions but does not change individual pistons independently.

The multi-link mechanism in the Variable Compression Turbo Engine adjusts the angle of the connecting rods, which in turn adjusts how far down the piston travels in the cylinder. This adjustment changes the volume of the cylinder when the piston is at the top of its stroke, thus varying the compression ratio. The multi-link mechanism does not act like a fixed-length connecting rod nor can it change one individual piston's operation independent of the others, as all pistons in a multi-cylinder engine are generally interconnected and move synchronously.

By varying the compression ratio, the engine can operate efficiently under a variety of conditions, offering more power when needed or improving fuel efficiency when less power is required. This mechanism is a sophisticated mechanical linkage that transforms the linear motion of the pistons into the rotary motion of the crankshaft, similar to the operation of conventional connecting rods, but with the added capability of adjusting the compression ratio.

A spring has an equilibrium length of 2.0 meters and a spring constant of 10 newtons/meter. Alice is pulling on
one end of the spring with a force of 3.0 newtons. Bob is pulling on the opposite end of the spring with a force of

3.0 newtons, in the opposite direction. What is the resulting length of the spring?
(A) 1.7 m
(B) 2.0 m
(C) 2.3 m (correct answer)
(D) 2.6 m
(E) 8.0 m

Answers

Final answer:

When equal forces of 3.0 newtons are applied on both ends of a spring with an equilibrium length of 2.0 meters, the resulting length of the spring remains 2.0 meters because the forces cancel each other out.

Explanation:

To find the resulting length of the spring, we should first determine the amount of stretch or compression caused by the forces applying on the spring. Since Alice and Bob are both pulling with a force of 3.0 newtons each in opposite directions, the net force on the spring is zero. Therefore, the spring neither stretches nor compresses from its equilibrium length.

The spring has an equilibrium length of 2.0 meters and remains at this length because the forces applied by Alice and Bob cancel each other out. So, the resulting length of the spring when 3.0 newtons is applied at each end in opposite directions is 2.0 meters, which is answer (B).

Julie runs 2 miles every day after school because it reduces the stress she feels from schoolwork. Julie's running habit is maintained by a ________ reinforcer.

Answers

Answer:

negative

Explanation:

The term reinforce means to strengthen, and is used in psychology to refer to any stimulus which strengthens or increases the probability of a specific response.

Negative Reinforcement  can be seen as the act of taking something negative away in order to increase a response.

Julie runs 2 miles every day after school because it reduces the stress (negative) she feels from school work (in order to increase her response in her school work).

Some cities now implement signal lights designed to specifically apply to _____ rather than motorized vehicles.
A) Pedestrians
B) Trucks
C) Bicycles
D) Motorcycles
E) All of the above

Answers

The correct answer is C; Bicycles.

Further Explanation:

In major cities, in the United States, have implemented signal lights specifically designed for bicycle riders. The riders also have their own designated bike lanes in many large cities. Drivers in vehicles, are to give the right of way to people on bicycles.

Bicycle riders are to follow the same laws and laws specifically for the riders or they can face fines and tickets.

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In which one of the following circumstances could mechanical energy not possibly be conserved, even if friction and air resistance are absent?
A car moves down a hill, its velocity continually increasing alongthe way.
A car moves up a hill at a constant velocity.
A car moves along level ground at a constant velocity.
A car moves up a hill, its velocity continually decreasing alongthe way.

Answers

Answer:

A car moves up a hill at a constant velocity

Explanation:

Since the velocity is constant, the speed is also constant and so is the kinetic energy. However, total mechanical energy is sum of gravitational potential energy and kinetic energy, and the car is moving up the hill so its potential energy rises.

Thus, in the circumstances described the mechanical energy cannot be conserved.

The correct answer is A car moving up the hill with constant velocity.

Which of the following statements are true. (Justify your answer to get credit) (5 points)

1. Mechanical energy is conserved before and after the string is cut.
2. Mechanical energy is conserved before the string is cut.
3. Mechanical energy is conserved after the string is cut
4. Linear momentum is conserved 5. Angular momentum is conserved.

Answers

Answer:

2 & 3

Explanation:

Since they are all vector quantities, if they remain in a closed system where no external force acts on the system, the vector sum of the momentum remains constant.

When there is no loss or gain in the total vector sum of the energy of the system means it's energy is conserved.

You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.90 A , even for an instant. What is the largest root-mean-square current you can run through this bulb? _______A

Answers

Answer: 1.34A

Explanation:

Since the wire will break if it exceeds 1.90A current, this will be the maximum current needed.

The root mean square current

Irms = I0/√2

Where I0 is the maximum current given

Irms = 1.90/√2

Irms = 1.34A

A length of copper wire has a resistance 44 Ω. The wire is cut into three pieces of equal length, which are then connected as parallel lengths between points A and B. What resistance will this new "wire" of length L0 3 have between points A and B? Answer in units of Ω.

Answers

Answer:

[tex]\frac{R}{1} = \frac{44}{9}\ohm[/tex]

Explanation:

Let us imagine that there are three wire of length equal length having equal resistances each of 44/3 Ω

Now connect these wires in parallel to so that their equivalent resistance is R.

then

[tex]\frac{1}{R} = \frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}[/tex]

[tex]\frac{1}{R} = \frac{3}{44}+\frac{3}{44}+\frac{3}{44}[/tex]

[tex]\frac{1}{R} = \frac{9}{44}[/tex]

⇒[tex]\frac{R}{1} = \frac{44}{9}\ohm[/tex]

Answer:

4.89 Ω

Explanation:

we know that resistance is directly proportional to length. hence as the wire is cut in three pieces, the resistance of each piece becomes one-third of the original resistance of the wire.

[tex]R[/tex] = Resistance of wire = 44 Ω

[tex]r[/tex] = resistance of each piece

Resistance of each piece  is given as

[tex]r = \frac{R}{3}\\r = \frac{44}{3}[/tex]

The three pieces are connected in parallel,

[tex]R_{p}[/tex] = Resistance of parallel combination of three pieces

Resistance of parallel combination is given as

[tex]\frac{1}{R_{p}}= \frac{1}{r} +  \frac{1}{r} +  \frac{1}{r} \\\frac{1}{R_{p}}= \frac{3}{r}\\R_{p}= \frac{r}{3}\\R_{p} = \frac{\frac{44}{3} }{3}\\R_{p} = \frac{44}{9} \\R_{p} = 4.89 ohm[/tex]

Two speakers are spaced 15 m apart and are both producing an identical sound wave. You are standing at a spot as pictured. What would be the frequency produced by the speakers to create perfectly constructive interference? Assume n = 1 and v = 343 m/s
213.04 Hz
256.70 Hz
186.68 Hz
233.14 Hz

Answers

Answer:

213.04

Explanation:

Answer:

The correct answer is option 213.04 Hz

Explanation:

Hello!

Let's solve this!

In this link we will find the image of the problem.

https://smart-answers.com/physics/question14138735

Regarding that image, we will first calculate the distance from my position to S1 and then to S2. Then the difference between these results.

We will use pitagoras.

S1 = [tex]\sqrt{10^{2}+22^{2} }[/tex]

S1 = 24.17

S2 = [tex]\sqrt{5^{2}+22^{2} }[/tex]

S2 = 22.56

The difference will be:

24.17-22.56 = 1.61 m

Constructive interference:

Δr=n*λ

λ=1.61 m (for n = 1)

Then we will calculate the frequency:

f = v / λ

f = (343m / s) /1.61m

f = 213.04 Hz

So the correct answer is option 213.04 Hz

A falling object of weight 10 N encounters 10 N of air resistance. The net force on the object is____________.

Answers

An object of weight 10 N that is falling on the ground, and it experiences a 10 N air resistance, then the net force on the object will be 0 N.

What is Force?

A force in physics is an input that has the power to change an object's motion.

A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe forces. Being such a vector quantity, a force does have magnitude and direction. The SI unit metric newton is used to measure it (N). The letter F stands for force.

According to Newton's second law's original formulation, an object's net force is equal to the speed that its momentum is changing over time.

As per the given information in the question,

Weight of the object = 10 N

Friction due to air resistance = 10 N

Then, the net force will be,

10 N - 10 N = 0 N

Therefore, the net force will be 0 N.

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The net force on the object is zero.

When an object is falling, it experiences two main forces: gravity (its weight) pulling it downward and air resistance pushing upward. In this case, the object has a weight of 10 N (newtons), which is a force acting downward due to gravity, and it encounters 10 N of air resistance, which is a force acting upward against the motion of the falling object.

To find the net force on the object, you need to calculate the difference between the two forces:

Net Force = Weight - Air Resistance

Net Force = 10 N - 10 N

Net Force = 0 N

So, the net force on the object is 0 N. This means that the forces of gravity and air resistance are equal in magnitude and opposite in direction, resulting in a net force of zero. In this situation, the object is in a state of dynamic equilibrium, and its velocity remains constant (it doesn't accelerate further).

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if you were to look for a cut on the palmar surface of a dog's leg where would you look?

Answers

Answer:

If you were to look for a cut on the palmar surface of a dog's leg then you should look at the back area of the front leg below the carpus.

Explanation:

Final answer:

To find a cut on the palmar surface of a dog's leg, you would check the underside of the foreleg where the paw pads are located.

Explanation:

If you want to locate a cut on the palmar surface of a dog's leg, you would look at the underside of the dog's foreleg. In humans, the palmar surface refers to the palm of the hand, and similarly, in quadrupeds like dogs, it refers to the analogous area - the bottom of their paws on the forelegs, where dogs have pads that contact the ground. This is analogous to the palm of the human hand although covered with different skin and touch pads.

What is the specific fuel requirement for flight under VFR at night in an airplane?
A) Enough to fly to the first point of intended landing and to fly after that for 45 minutes at normal cruising speed.
B) Enough to complete the flight at normal cruising speed with adverse wind conditions.
C) Enough to fly to the first point of intended landing and to fly after that for 30 minutes at normal cruising speed.

Answers

Answer:

A). Enough to fly to the first point of intended landing and to fly after that for 45 minutes at normal cruising speed

Explanation:

Here are Fuel requirements for flight in VFR conditions

No person may begin a flight in an airplane under VFR conditions unless  there is enough fuel to fly to the first point of intended landing and, assuming normal cruising speed -

During the day, to fly after that for at least 30 minutes; or At night, to fly after that for at least 45 minutes.

The force that causes your car to gain momentum when going downhill is known as gravity.True / False.

Answers

Answer:

TRUE.   The weight component is responsible for acceleration and therefore the increase in vehicle speed,

Explanation:

Let's write Newton's second law for the car down a slope

Y Axis

         N-Wy = 0

         N = Wy

X axis

        Wx -fr= m a

Using trigonometry

        sin θ = Wx / W

        cos θ = Wy / W

         Wx = W sin θ

         Wy = W cos θ

We replace

             W sin θ - fr = m a

The weight component is responsible for acceleration and therefore the increase in vehicle speed,

fr is the force of car brakes

Consequently, of the above TRUTH

A ski jumper has 1.2 x 10 4 J of potential energy at the top of the ski jump. The friction on the jump slope is small, but not negligible. What can you conclude about the ski jumpers kinetic energy at the bottom of the jump?

Answers

Answer

kinetic energy will be less than 1.2×10^4 J

Explanation:

as some of this potential energy will be used to over come force of friction , hence by law of conservation of energy  , kinetic energy will be less than potential energy at top and will be less than 1.2×10^4 J

Final answer:

The ski jumper's kinetic energy at the bottom of the ski jump will be slightly less than the initial potential energy of 1.2 x 10⁴ J due to the small but non-negligible work done by friction, which converts some of the mechanical energy into other forms like heat and sound.

Explanation:

If a ski jumper has 1.2 x 10⁴ J of potential energy at the top of the ski jump and we take into account that friction is small but not negligible, we can conclude that the ski jumper's kinetic energy at the bottom will be slightly less than 1.2 x 10⁴ J. According to the conservation of energy principle, the sum of potential and kinetic energy in a system should be constant if there is no external work done. However, friction does perform negative work (it removes energy from the system), converting some mechanical energy into heat and sound, and therefore the actual kinetic energy at the bottom will be the initial potential energy minus the energy lost due to friction.

For example, in the given scenario where a ski jumper starts from rest, their initial kinetic energy is zero, and all the energy is in the form of potential energy. As they descend, potential energy is converted into kinetic energy. When friction is present, it will do negative work on the system, represented by a slight decrease in the total mechanical energy by the time the skier reaches the bottom. The kinetic energy of the ski jumper at the bottom would be the initial potential energy minus the work done by friction during the descent.

In a theoretical scenario without friction, the skier's kinetic energy at the bottom would equal their initial potential energy minus zero (since no work is done by friction), resulting in the skier having kinetic energy equal to 1.2 x 10⁴ J at the bottom.

An object of unknown mass is hung on the end of an unstretched spring and is released from rest. The acceleration of gravity is 9.81 m/s 2 . If the object falls 2.75 cm before first coming to rest, find the period of the motion. Answer in units of s

Answers

Final answer:

The question relates to Simple Harmonic Motion of a mass-spring system, and asks to calculate the period of the motion. The approach involves the use of Hooke's law and Newton's second law, and understanding that at maximum amplitude, gravitational potential energy converts to elastic potential energy.

Explanation:

The question discusses a concept in physics known as Simple Harmonic Motion, specifically in relation to a mass attached to a spring. The object of unknown mass is hung on the unstretched spring, let go and then allowed to move down under the force of gravity. This object comes to rest for the first time when it has moved to its maximum amplitude, which is given as 2.75 cm. The period of the motion is what we are required to find.

The period of oscillation for a simple harmonic oscillator (in this case, a mass-spring system) can be calculated using the formula T = 2π√(m/k), where m is the mass and k is the spring constant. However, from the given information, we do not have the mass or the spring constant and need an alternative approach.

Let's use Hooke's law (F = kx) and Newton's second law (F = ma). We know that at the maximum amplitude, all the gravitational potential energy is converted to elastic potential energy. We can write mgx = 0.5 kx^2, where g is the acceleration due to gravity and x is the displacement (2.75 cm). From here we can calculate k. Then we substitute this value of k obtained into the formula for T, we could then find the period of the motion of the object.

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Suppose we imagine the Sun to be about the size of a grapefruit. How big an area would the orbits of the nine planets of the Solar System cover?

Answers

Answer:

size at this scale of the solar system is 10⁸ m²

Explanation:

For this exercise we can use a direct proportions rule or rule of three.

If the radius of the Sun is 7 10⁸ m is equal to the radius of a grapefruit is on average about 5 cm, the radius of the orbit of the plant is x

Mercury

     r1 = 5.8 10¹⁰m

    x = r1 / r_Sum  5

    x = 5.8 10¹⁰/7 10⁸

    x = 82 m

We repeat the same formula with all the radii of the orbit, the results in the table

Numb    name      r_orbit (m)      x (m)         A (m2)

0             Sun          7 10⁸              1                 3.14

1              mercury   5.8 10¹⁰         8.2 10¹       2.0 10⁴

2             venus       1 10¹¹              1.4 10²       6.2 10⁴

3             Earth        1.5 10¹¹           2.1 10²        1.4 10⁵

4             Mars        2.3 10¹¹          3.2 10²        3.2 10⁵

5             Jupiter    7.8 10¹¹          1.1 10³          3.8 10⁶

6            Saturn      1.4 10¹²          2 10³           1.3 10⁷

7            Uranus     2.9 10¹²         4.1 10³         5.3 10⁷

8            Neptune   4.5 10¹²        6.4 10³        1.3 10⁸

9            Pluto         5.9 10¹²        8.4 10³        2.2 10⁸

The area of ​​a circle is

      A = π R²

Mercury

      A = π 80²

      A = 2.0 14 m²

The other values ​​are in the table

The size at this scale of the solar system is 10⁸ m²

why doesnt the moon get pulled into the sun

Answers

Answer:

The moon does not get pulled into the sun because of gravitational pull.

Explanation:

Gravitational pull is a force that pulls things down or into i guess you can say. Like are orbit, all of the planets (even the dwarf planet "pluto") are circling around are sun but we have things called moons that circle are planets. Are moon is orbiting us like we (are earth) are orbiting the sun. So to get into a little more detail, i will add that we circle the sun or the moon circles us because the action of earth pulling away from the suns gravitational pull is causing it to either rotate or revolve.So we are stuck in the gravitational force of the sun and the moon is stuck in ares. But as someone who LOVES astronamy will say that i watched a video about are earth, sun, and moon and it said that each year are moon is slowly pulling away from the earth. sooner or later we might not have a solar or lunar eclipse anymore.

Answer:

But the path of the Moon is always concave towards the Sun; the gravitational force exerted by the Sun on the Moon is always greater than the pull of the Earth on the Moon

Explanation:

An adult generates 72 W of power as she pulls a sled forward across a flat snowy surface with a force of 80 N. The adult pulls with this force for 4.5 minutes. What distance does the sled move?

130 m

280 m

240 m

180 m

Answers

Answer:

240 m

Explanation:

Gradpoint

Final answer:

To calculate the distance the sled moves, use the formula Work = Force x Distance and substitute the given values to find the answer as 240 meters.

Explanation:

Power is a physical quantity that represents the rate at which work is done or energy is transferred or converted. Mathematically, power is defined as the amount of energy transferred or converted per unit time. It is typically measured in watts (W), where 1 watt is equivalent to 1 joule per second. In other words, power indicates how quickly work is done or energy is transferred.

To find the distance the sled moves, we can use the formula:

Work = Force x Distance

Given: Power = 72 W, Force = 80 N, Time = 4.5 minutes = 270 seconds

Work = Power x Time = 72 W x 270 s = 19440 J

Distance = Work / Force = 19440 J / 80 N = 243 m

Therefore, the sled moves a distance of 240 meters.

When stopped at an intersection and your light turns green, you should __________ before accelerating.

A: look right then left
B: look left then right
C: look left then right then left again
D: look straight ahead
E: look behind you

Answers

Answer:

C: look left then right then left again

Explanation:

At an intersection, there three routes, the left, the right and straight ahead.

For a car stopped at an intersection, once the light turn green, it is advisable that the driver should watch the left and right then left again before accelerating. This is because there might be any car coming from any of the sides unnoticed which might leads to accident especially the first side u looked at (left) must be take much cognisance of hence the need to look left again before accelerating.

Final answer:

When stopped at an intersection and your light turns green, you should A. look right and then left before accelerating.

Explanation:

When stopped at an intersection and your light turns green, you should look left, then right, then left again before accelerating. This practice ensures that you are aware of any vehicles that may not have stopped at their red light or are trying to beat a yellow light, as well as any pedestrians or cyclists that may be crossing.

Remember that while traffic signals are there to regulate flow, driver vigilance is crucial in preventing accidents and ensuring safety. Thus, it is important to check both directions to ensure the intersection is clear before proceeding. Safe driving practices include being cautious and aware of potential risks on the road.

What is the average cost for a severe injury in a collision?
A. $4,000
B. $15,000
C. $47,000
D. $247,000

Answers

Answer:

D

Explanation:

According to research and data, the average cost for a severe injury in a collision is $247,000.

These include traumatic brain injury, severe damage to limbs which could result to loss of the limbs, spinal cord injuries that could result to partial or total paralysis as well as internal damage to organs in the collision.

When driving through standing water at high speed water may build up beneath the wheels and cause the vehicle to skid is commonly referred to as:________

Answers

Answer: Hydroplaning

Explanation: Hydroplaning is the skiding of a high speed vehicle when water builds beneath the wheels when driving through standing water.

It is usually caused by factors such as High speed,Standing water,deflated tyres. It is strongly recommended that when driving in standing water a driver should drive at a slow and steady speed and always to ensure that the vehicle tyres are adequately inflated with air,this is one of the causes of vehicular accidents during rainy season or flood.

Water can pile up a short distance above a container's rim due to: a. high capillary action. b. low viscosity. c. low surface tension. d. high surface tension. e. high viscosity.

Answers

Answer: a. high capillary action.

Explanation:

Water can pile up a short distance above a container's rim due to high capillary action. Capillarity is process by which water falls or rise through a narrow capillary tube. The concept allows water to rise to a certain height through the container before dropping.

Tectonic plates are pieces of the ________ that float on the more fluid ________ below.

Answers

Answer:

lithosphere and asthenosphere

Explanation:

Lithosphere is the part of the earth surface which is rigid and hard. It consists of whole crust and the upper mantle.It comprises of number of plates called plate tectonic.

The asthenosphere is the Earth's upper mantle's extremely viscous, mechanically fragile and ductile area. This sits below the lithosphere, some 80 to 200 km below the ground at depths. The boundary between lithosphere and asthenosphere is commonly referred to as LAB.

As a way of determining the inductance of a coil used in a research project, a student first connects the coil to a 9.7 V battery and measures a current of 0.742 A. The student then connects the coil to a 27.3 V(rms), 51.1 Hz generator and measures an rms current of 0.429 A. What is the inductance?

Answers

Answer:

L = 0.194 H

Explanation:

given,

Voltage = 9.7 V

current = 0.742 A

R = 9.7 V / 0.742 A

R = 13.07 Ohms.

the A.C. impedance of the inductor, like this:

Z = V / I

Z = 27.3 V / 0.429 A

Z = 63.64 Ohms.

now,

inductive reactance, X_L

[tex]X_L = \sqrt{Z^2 - R^2}[/tex]

[tex]X_L = \sqrt{63.64^2 - 13.07^2}[/tex]

[tex]X_L =62.28\ \Omega[/tex]

[tex]X_L = 2\pi f \times L[/tex]

[tex]L = \dfrac{X_L}{2\pi f}[/tex]

[tex]L = \dfrac{62.28}{2\pi \times 51.1}[/tex]

L = 0.194 H

A novice skier, starting from rest, slides down a frictionless 29.0∘ incline whose vertical height is 185 mm. How fast is she going when she reaches the bottom?

Answers

Answer:

Her speed when she reaches the bottom of the incline is 1.90 m/s.

Explanation:

Hi there!

To solve this problem, let´s use the energy conservation theorem:

Initially, the skier is at rest at a height of 0.185 m. Since she is at rest, her kinetic energy will be zero and her gravitational potential energy (PE) will be:

PE = m · g · h

Where

m = mass of the skier.

g = acceleration due to gravity.

h = height.

When she reaches the bottom, the height is zero and then the potential energy will be zero. Since there is no friction, the initial potential energy had to be converted into kinetic energy because the total energy of the skier remains constant, i.e., it is conserved.

Then, the final kinetic energy (KE) of the skier has to be equal to the initial potential energy:

PE = KE

The equation of kinetic energy is the following:

KE = 1/2 · m · v²

Then:

KE = PE

1/2 · m · v² = m · g · h

1/2 · m · v² = m · 9.8 m/s² · 0.185 m

v² = 2 · 9.8 m/s² · 0.185 m

v = 1.90 m/s

Her speed when she reaches the bottom of the incline is 1.90 m/s.

Antoinette was diagnosed with hypertension, a noncommunicable disease in which her blood pressure is higher than normal. What is the most likely explanation for why she is hypertensive? She was obese and had a diet high in salt intake. She did not wash her hands enough. She was bitten by a mosquito. She was never vaccinated against hypertension.

Answers

Answer:

She was obese and had a diet high in salt intake.

Explanation:

higher blood pressure is condition known as hypertension which is the main cause of many heart problems which can be life threatening. In obese people. high level of fats inside the blood vessels which can cause blockage inside and can lead to heart problems.

high concentration of salts intake also disturbs the salts concentration in the blood vessels. The disturbance in salt concentration is the function of the kidney to remove it. the increase concentration also  cause increase in blood pressure which leads to hypertension.  

Answer:

She had a diet high in salt intake.

Explanation:

Sodium is medically known to raise blood pressure.

Washing hands and mosquitos are not related to blood pressure.

There is no vaccination against high blood pressure.

A fan connected to a 120-volt electrical system by an extension cord was worn through and exposed the bare, energized conductor, which made contact with the ladder. The ground wire was not attached to the male end of the cord's plug. When the energized conductor made contact with the ladder, the path to ground included the worker's body, resulting in death. What contributed to the electrocution?

Answers

Answer:

The worker completed the circuit.

Explanation:

Thinking process:

Electricity is the flow of electrons in a circuit. There is one condition for the electrons to flow - the completion of a circuit. In order for that to be established, there must be a side with low electron concentration or affinity for electrons.

The earth has an infinite affinity for electrons. Thus, earth wires are used to channel an excess amount of electrons there. This prevents the short circuiting injuring a person. Hence, a three-pin plug.

Because there was not insulation, like rubber, an alternative pathway could not be found for electrons. Hence the worker was electrocuted as the electric current passed through him.

Final answer:

The electrocution occurred due to a lack of proper safety measures, specifically an improper grounding connection. When the bare, energized conductor of the fan connected with the ladder, the electrical current sought the path of least resistance to ground which included the worker's body.

Explanation:

The factors contributing to the fatal electrocution in this scenario are mainly faulty or inadequate safety measures and the behavior of electricity. Electricity always seeks the path of least resistance to the ground and in the absence of a proper ground wire connection, the electricity from the exposed conductor of the extension cord sought alternative grounding routes, in this case, through the worker's body.

Thermal and shock hazards are two primary dangers of electricity. A thermal hazard can cause fires due to excessive electric power resulting in unwanted thermal effects. A shock hazard is where electric current passes through a person, potentially causing harm ranging from a mild shock to death.

The system lacked a vital safety feature, which is a functioning ground connection. A three-wire system that includes live, neutral, and ground wires helps to avoid such scenarios. With a proper ground connection, any fault currents would be safely directed to the ground, and a circuit breaker would usually trip, cutting off the electricity. In this case, the lack of a proper ground connection contributed to the fatal electrocution.

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An automobile is depreciating at 11% per year, every year. A $30,000 car depreciating at this rate can be modeled by the equation V(t) = 30,000(0.89)t. What is an equivalent equation for this vehicle at a daily depreciation and what is it worth (rounded to the nearest thousand dollar) 5 years after purchase?

Answers

Answer:

a.V(t/365)=30,000(0.89)^(t/365).

b. V(5)=$17000

Explanation:

An automobile is depreciating at 11% per year, every year. A $30,000 car depreciating at this rate can be modeled by the equation V(t) = 30,000(0.89)t. What is an equivalent equation for this vehicle at a daily depreciation and what is it worth (rounded to the nearest thousand dollar) 5 years after purchase?

i will like to work back from te question by solving questin 2 first

V(t) = 30,000(0.89)^t

let t=5

V(5) = 30,000(0.89)^5

V(5)=$17000

2.yearly depreciation will be

30,000(0.89)^1

26700=it amounts to tis after a year,

so it depreciates by 3300 for one year

daily depreciation will be 3300/365 ,

since there are 365 days in a year

$9.041

the equation that satisfy this is

V(t/365)=30,000(0.89)^(t/365).

Final answer:

Mathematically, an automobile depreciating at 11% annually can be modeled for daily depreciation, but for the calculation of value after 5 years, we use the original annual model V(t) = 30,000(0.89)^t to find the car is worth approximately $13,000.

Explanation:

The student's question about the depreciation of an automobile can be classified under Mathematics, specifically dealing with exponential decay and depreciation models. To find the daily depreciation rate equivalent to 11% annual depreciation, we can use the formula for continuous compounding, where the annual rate is converted into a daily rate using the expression (1 + annual rate)^(1/365) - 1. However, since the problem does not ask for continuous daily depreciation but rather the equivalent discrete daily rate, we can instead divide the annual rate by 365, assuming each day the car depreciates by an equal fraction of the annual rate. Therefore, the daily depreciation rate would be 11% / 365.

However, because the student is seeking the value of the car after 5 years, we can directly use the provided equation V(t) = 30,000(0.89)^t, where t is the number of years. After 5 years, this gives us V(5) = 30,000(0.89)^5. Calculating this we get V(5) ≈ $13,000 when rounded to the nearest thousand.

If you place a teaspoon of sugar in the bottom of a glass of water, it will dissolve completely over time. Left longer, eventually the water will disap- pear and the sugar crystals will reappear. Explain these observations in terms of entropy.

Answers

Explanation:

It is known that entropy is the degree of randomness. More is the speed of molecules of a substance more will be its degree of randomness. Hence, more will be the entropy of substance.

When we place a teaspoon of sugar in the bottom of a glass of water, it will dissolve completely over time. This dissolution will cause the sugar molecules to spread out in the water.

And, with time water will evaporate and this will lead to the formation of crystals again. This reappearance of sugar crystals will cause a decrease in entropy as there occurs decrease in randomness.

But this decrease in entropy is balanced by increase in the entropy of water molecules as they are evaporating.

Final answer:

The process of sugar dissolving and reappearing in water can be explained in terms of entropy.

Explanation:

The process described in the question can be explained in terms of entropy, which is a measure of the disorder or randomness in a system. When the teaspoon of sugar is placed in the water, the sugar crystals break down and mix with the water molecules, increasing the entropy of the system. With time, the water molecules continue to move and mix, increasing the disorder even further.

However, if the water is left to evaporate, the water molecules will escape into the air, and the sugar molecules will not be able to dissolve in the evaporating water. As a result, the sugar crystals will eventually reappear.

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