Iron cannot release energy by fusion.
Explanation;Supernovae are some of the most magnificent events in the cosmos. When a massive star dies, it can result in a spectacular explosion many times that of man's total nuclear arsenal.When a star has used up all the lighter elements and has just iron left, it has no more nuclear "fuel". That causes the star to contract then explode very violently as a supernova.
Some forces require direct contact,while others, like gravity, act at a distance
Yes sirree ! Uh huh, uh huh. Truer words are rarely spoken.
What causes different colors to appear in the sky?
Answer : the scattering and reflection of light by dust particles
The sky appears blue because the blue wavelength of light from the sun is scattered more by the air molecules that the other colors. The sky appears with a red hue at dawn and sunsets because the red spectrum is able to pass through the longer atmosphere in the oblique angle while blue light is scattered well before.
Answer: the scattering and reflection of light by dust particles
Explanation:
A skydiver is falling at constant velocity. If a force of 600 N is pulling down on the skydiver, how much force must be acting upward on the skydiver?
exactly 600 N
slightly more than 600 N
slightly less than 600 N
exactly 0 N
Well, if the skydiver is at constant velocity, than there’s no acceleration, as stated by Newton’s first law. Thus the total net force would equate to 0. In order to make this statement true, the answer would have to be exactly 600 N.
Force is defined as the product of mass and acceleration .it is a vector quantity. The force acting on the skydiver must be 600 N which should be acting upward.
what is force?Force is defined as the action on any object that has the ability to change the shape, size, and direction of an object is in motion or in static condition.
It is a vector quantity defined as the product of mass and acceleration. Acceleration is the rate change of velocity with respect to the time
Force is given by;
[tex]\rm {Force = Mass \times Acceleration}[/tex]
As the definition of acceleration if the velocity change is zero in that condition the force acting is zero. that's why force will also be zero
[tex]\rm {F +ma+mg =0 }[/tex]
If acceleration is zero in that condition
[tex]\rm {F =-mg }[/tex]
[tex]\rm {F = -600 N }[/tex]
where - ve shows the direction of force is negative
therefore a force of exactly 600 N is acting upward on the skydiver.
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A force that pushes or pulls is known as A. A reaction force. B. An expected force. C. A positive force. D. An applied force.
I believe it’s D, an applied force.
A reaction force seems to refer to Newton’s third law, but is relatively vague to be the answer to this question.
An expected force isn’t a concept nor the name of any subject of forces that is taught within the physics textbooks.
A positive force refers to direction, a negative force can have less, equal, or even more magnitude than the positive force, thus it contradicts itself. As that’s still a force that can push or pull.
So I believe it to be D.
A force that pushes or pulls is known as an applied force. Option D is correct.
What is force?Force is defined as an object in motion, and its rate of change of momentum is called force.
here,
A force applied to an object is one that is exerted on it by another object or by an external agent. This force can cause the object to accelerate or change direction. Pushing a book across a table, pulling a sled across the snow, or lifting a weight with a pulley are all examples of applied forces.
It is important to note that for every applied force, there is an equal and opposite reaction force, according to Newton's third law of motion. This means that when an object exerts a force on another object, the second object exerts an equal and opposite force back on the first object. This reaction force is also an applied force, and it can affect the motion of both objects involved.
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A _____ is a particle with a positive charge and the mass of an electron.
A positron, or an anti-electron, is a particle with a positive charge and the mass of an electron.
Water thtat is returned to the environment after secondary treatment is known as _____.
The answer is C) Effluent
Which equation is used to calculate the electric potential in an electric field from a point charge?
Answer:
The electric potential (voltage) [tex]V[/tex] produced by a point charge [tex]Q[/tex], at any point in space, is given by the following equation:
[tex]V=k\frac{Q}{r}[/tex]
Where:
[tex]k=8.99(10)^{9} Nm^{2}/C^{2}[/tex] is the Coulomb's constant
[tex]r[/tex] is the distance
The result is a scalar quantity, is defined as the electric potential energy per unit of charge and determines the electric influence exerted by the charge on that point of space.
Answer:
v=k*q/d
Explanation:
The formula v=k*q/r is also correct but in this case v=k*q/d was given as a choice.
Pike's peak in colorado is approximately 4,300 m above sea level (0). what is the boiling point of water at the summit?
Answer:
The boiling point of water is around 185.9ºF or 85.5ºC
Explanation:
The boiling point of water depends on the atmospheric pressure. So, the higher the elevation, the lower the atmospheric pressure, therefore the boiling point of water is lower as well. Assuming that sea level pressure is constant ,(760 mmHg, 29.92inches Hg or 14.69psi) the boiling point of water is 212ºF (100ºC). Approximately, for every 500 foot (150m) of elevation increase, the boiling point temperature decreases 1ºF (0.55ºC).
Help DUE TONIGHT!
use the picture below to answer the question. What is the total length of one complete wave (the distance from one point on a wave to the next similar point) called?
amplitude
frequency
pitch
wavelength
I have found this tool to hep you solve your question.
https://quizlet.com/76366884/ch15ch16physical-science-waves-sound-flash-cards/
Use the table below to answer the following questions. Substance Specific Heat (J/g•°C) water 4.179 aluminum 0.900 copper 0.385 iron 0.450 granite 0.790 1. When 3.0 kg of water is cooled from 80.0C to 10.0C, how much heat energy is lost? 2. How much heat is needed to raise a 0.30 kg piece of aluminum from 30.C to 150C? 3. Calculate the temperature change when: a) 10.0 kg of water loses 232 kJ of heat. b) 1.96 kJ of heat are added to 500. g of copper. 4. When heated, the temperature of a water sample increased from 15°C to 39°C. It absorbed 4300 joules of heat. What is the mass of the sample? 5. 5.0 g of copper was heated from 20°C to 80°C. How much energy was used to heat Cu? 6. The temperature of a sample of iron with a mass of 10.0 g changed from 50.4°C to 25.0°C with the release of 47 Joules of heat. What is the specific heat of iron? 7. The temperature of a sample of water increases
1. [tex]-8.78 \cdot 10^5 J[/tex]
The energy lost by the water is given by:
[tex]Q=m C_s \Delta T[/tex]
where
m = 3.0 kg = 3000 g is the mass of water
Cs = 4.179 J/g•°C is the specific heat
[tex]\Delta T=10.0C-80.0C=-70.0 C[/tex] is the change in temperature
Substituting,
[tex]Q=(3000 g)(4.179 J/gC)(-70.0 C)=-8.78 \cdot 10^5 J[/tex]
2. [tex]3.24 \cdot 10^4 J[/tex]
The energy added to the aluminium is given by:
[tex]Q=m C_s \Delta T[/tex]
where
m = 0.30 kg = 300 g is the mass of aluminium
Cs = 0.900 J/g•°C is the specific heat
[tex]\Delta T=150.0 C-30.0C =120.0 C[/tex] is the change in temperature
Substituting,
[tex]Q=(300 g)(0.900 J/gC)(120.0 C)=3.24 \cdot 10^4 J[/tex]
3a. [tex]-5.6^{\circ}C[/tex]
The temperature change of the water is given by
[tex]\Delta T=\frac{Q}{m C_s}[/tex]
where
[tex]Q = -232 kJ=-2.32\cdot 10^5 J[/tex] is the heat lost by the water
[tex]m=10.0 kg=10000 g[/tex] is the mass of water
Cs = 4.179 J/g•°C is the specific heat
Substituting,
[tex]\Delta T=\frac{-2.32\cdot 10^5 J}{(10000g)(4.179 J/gC)}=5.6^{\circ}C[/tex]
3b. [tex]+10.2^{\circ}C[/tex]
The temperature change of the copper is given by
[tex]\Delta T=\frac{Q}{m C_s}[/tex]
where
[tex]Q = 1.96 kJ=1960[/tex] is the heat added to the copper
[tex]m= 500 g[/tex] is the mass of copper
Cs = 0.385 J/g•°C is the specific heat
Substituting,
[tex]\Delta T=\frac{1960 J}{(500g)(0.385 J/gC)}=10.2^{\circ}C[/tex]
4. 42.9 g
The mass of the water sample is given by
[tex]m=\frac{Q}{C_S \Delta T}[/tex]
where
[tex]Q=4300 J[/tex] is the heat added
[tex]\Delta T=39 C-15 C=24C[/tex] is the temperature change
Cs = 4.179 J/g•°C is the specific heat
Substituting,
[tex]m=\frac{4300 J}{(4.179 J/gC)(24 C)}=42.9 g[/tex]
5. 115.5 J
The heat used to heat the copper is given by:
[tex]Q=m C_s \Delta T[/tex]
where
m = 5.0 g is the mass of copper
Cs = 0.385 J/g•°C is the specific heat
[tex]\Delta T=80.0 C-20.0C =60.0 C[/tex] is the change in temperature
Substituting,
[tex]Q=(5.0 g)(0.385 J/gC)(60.0 C)=115.5 J[/tex]
6. 0.185 J/g•°C
The specific heat of iron is given by:
[tex]C_s = \frac{Q}{m \Delta T}[/tex]
where
Q = -47 J is the heat released by the iron
m = 10.0 g is the mass of iron
[tex]\Delta T=25.0-50.4 C=-25.4 C[/tex] is the change in temperature
Substituting,
[tex]C_s = \frac{-47 J}{(10.0 g)(-25.4 C)}=0.185 J/gC[/tex]
These questions relate to calculating heat energy changes using the concept of specific heat. Specific heat, an intensive property, is used to calculate how much heat is lost or gained during temperature changes of different substances. The formula q=mcΔT, where 'q' is heat energy, 'm' is mass, 'c' is specific heat and 'ΔT' is the temperature change, is used for the calculations.
Explanation:The specific heat of a substance is an intensive property that defines how much heat energy is needed to raise 1 gram of the substance by 1 degree Celsius.
For the first question, when 3.0 kg of water is cooled from 80.0°C to 10.0°C, we use the formula q=mcΔT, where m is mass, c is specific heat and ΔT is the change in temperature. Substituting the given values, we get q = 3000g * 4.179 J/g°C *(10.0°C - 80.0°C) which gives -881,940 Joules (roughly -882 kJ). The negative sign indicates that heat energy is lost.
For the second question, we apply the same formula, with m=0.30 kg, c=0.900 J/g°C and ΔT = 150.0°C - 30.0°C, giving 32.4 kJ heat energy needed.
For the third question, we reverse the equation to solve for temperature. For 10.0 kg of water losing 232 kJ, ΔT = q / (mc), or 232,000J / (10,000g * 4.179 J/g°C), resulting in an approximately 5.54°C temperature loss. For 500g of copper gaining 1.96 kJ of heat, the equation gives a temperature change of about 10°C.
The same principles are applied to answer the remaining questions.
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A parallel-plate capacitor with circular plates is charged by a constant current i. the radius a of the plates is much larger than the distance d between them, so fringing effects are negligible. calculate b(r), the magnitude of the magnetic field inside the capacitor as a function of distance from the axis joining the center points of the circular plates. express your answer in terms of μ0 and given quantities.
1. The problem statement, all variables and given/known data A parallel-plate capacitor of capacitance C with circular plates is charged by a constant current I. The radius a of the plates is much larger than the distance d between them, so fringing effects are negligible. Calculate B(r), the magnitude of the magnetic field inside the capacitor as a function of distance from the axis joining the center points of the circular plates. 2. Relevant equations When a capacitor is charged, the electric field E, and hence the electric flux Φ, between the plates changes. This change in flux induces a magnetic field, according to Ampère's law as extended by Maxwell: ∮B⃗ ⋅dl⃗ =μ0(I+ϵ0dΦdt). You will calculate this magnetic field in the space between capacitor plates, where the electric flux changes but the conduction current I is zero.
The electric field E, and consequently the electric flux, between the plates of a capacitor vary as it charges.
What is electric flux?Electric flux is defined as the quantity of electric lines of force or electric field lines that cross a specific region is a property of an electric field. According to this theory, electric field lines begin with positive electric charges and end with negative charges. An electric field's important characteristic is its electric flux. It can be thought of as the quantity of forces interacting in a particular space.
As a function of distance from the axis, the strength of the magnetic field B(r) inside the capacitor is
∫ Bdl = μ₀ I enclosed
B x 2λr = μ₀ I (λ r² / λ a²)
Br = μ₀ In / 2λa²
Thus, the electric field E, and consequently the electric flux, between the plates of a capacitor vary as it charges.
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What is the melting point of substance A?
°C
Answer:
200
Explanation:
Melting point of a substance is 200.
What is Melting point?The temperature at which a solid and liquid phase can coexist in equilibrium and the point at which matter transforms from a solid to a liquid is known as a substance's melting point. Pure solutions and liquids fall within this definition.
It is important to specify melting point because it relies on pressure. Melting point tables frequently use standard pressures like 100 kPa or 1 atmosphere. The liquefaction point is another name for the melting point.
The temperature at which a liquid changes to a solid (the reverse of melting) is the freezing point or crystallization point. The freezing point and the melting point do not necessarily occur at the same temperature.
Therefore, Melting point of a substance is 200.
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How does the electric force between two charged particles change if the distance between them is decreased by a factor of 3?
It makes them be three forces
The contrabassoon is the wind instrument capable of sounding the lowest pitch in an orchestra. It is folded over several times to fit its impressive 18 ft length into a reasonable size instrument.The actual fundamental frequency of the contrabassoon is 27.5 Hz , which should be different from your answer in part A. This means the model of the instrument as an open-closed tube is a bit too simple. But if you insist on using that model, what is the "effective length" of the instrument?
Answer:
3.12 m
Explanation:
The fundamental frequency of an open-closed tube is given by
[tex]f_1 = \frac{v}{4L}[/tex]
where
f1 is the fundamental frequency
v is the speed of sound in air (343 m/s)
L is the length of the tube
If we use the model mentioned, we can consider L to be the effective length of the instrument. This means we can re-arrange the formula and use the fundamental frequency, f1 = 27.5 Hz, to find L:
[tex]L=\frac{v}{4 f_1}=\frac{343 m/s}{4(27.5 Hz)}=3.12 m[/tex]
In a pig-calling contest, a caller produces a sound with an intensity level of 60 db. how many such callers would be required to reach the pain level of 120 db? 2 incorrect: your answer is incorrect.
The imaginary second level is 60 dB more intense than the real level of the caller.
60 dB means a multiplication of 10⁶ = 1 million.
That's how many equally-talented callers it would take to be 60 dB louder than him.
The number of callers would be required to reach the pain level of 120 db is 10⁶ , that is, one million.
What is one decibel?
Decibel is the unit of sound. Its symbol is ‘dB’. We can define decibel as:
A unit of measurement used to express the ratio of one value of a power or field quantity to another on a logarithmic scale, the logarithmic quantity being called the power level or field level, respectively.
60 dB = 10 log₁₀ (P₁/P)
120 dB = 10 log₁₀( P₂/P₀)
The man have to produce square of his intensity level to reach the pain level of 120 dB.
The number of callers would be required to reach the pain level of 120 db is 10⁶ , that is, one million.
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Based on the second law of thermodynamics why must a machine always be less than 100% efficient?
A.Heat never moves from cold to hot.
B.Heat is never converted completely into mechanical energy.
C.Heat never flows from hot to cold.
D.Entropy never increases.
Answer: B.Heat is never converted completely into mechanical energy.
Explanation:
According to the second principle of thermodynamics:
"The amount of entropy in the universe tends to increase over time"
However the first formulation of this law (by Sadi Carnot) states:
"There is an upper limit to the efficiency of conversion of heat to work, in a heat engine "
This means the heat cannot be completely transformed into mechanical energy in a machine. That is why a machine's effieciency is always less than 100%
Answer:
B
Explanation:
Use logic
Chet believes that electric fields can impact objects only when the objects are in direct contact. Tonya disagrees with Chet. What evidence can Tonya use to prove Chet incorrect? A) A balloon will stick to a wall only if the balloon has no overall charge. B) Two negatively charged balloons will repel each other when brought close together without touching. C) An atom's neutrons and electrons are located in its nucleus. D) Rubbing a plastic rod with a silk cloth transfers neutrons from the cloth to the rod.
B because it is the only evidence that displays an effect from the field without contact
An electron travels with speed 6.0 106m/s between the two parallel charged plates shown in the figure. The plates are separated by 1.0 cm and are charged by a200 V battery.What magnetic field strength will allow the electron to pass between the plates without being deflected?
Answer:
3.3 mT
Explanation:
First of all, we need to find the strength of the electric field between the two parallel plates.
We have:
[tex]\Delta V=200 V[/tex] (potential difference between the two plates)
[tex]d=1.0 cm=0.01 m[/tex] (distance between the plates)
So, the electric field is given by
[tex]E=\frac{\Delta V}{d}=\frac{200 V}{0.01 m}=2\cdot 10^4 V/m[/tex]
Now we want the electron to pass between the plates without being deflected; this means that the electric force and the magnetic force on the electron must be equal:
[tex]F_E = F_B\\qE=qvB[/tex]
where
q is the electron charge
E is the electric field strength
v is the electron's speed
B is the magnetic field strength
In this case, we know the speed of the electron: [tex]v=6.0\cdot 10^6 m/s[/tex], so we can solve the formula to find B, the magnetic field strength:
[tex]B=\frac{E}{v}=\frac{2\cdot 10^4 V/m}{6.0\cdot 10^6 m/s}=0.0033 T=3.3 mT[/tex]
The magnetic field strength will allow the electron to pass between the plates without being deflected is 0.0033 T.
Electric field strengthThe electric field strength of the electron is calculated as follows;
E = V/d
E = 200/(0.01)
E = 20,000 V/m
Magnetic field strengthThe magnetic field strength is related to electric field in the following formula;
qvB = qE
vB = E
B = E/v
B = (20,000)/(6 x 10⁶)
B = 0.0033 T
Thus, the magnetic field strength will allow the electron to pass between the plates without being deflected is 0.0033 T.
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Doubling an objects speed will have what effect on its potential energy due to gravity
An object's gravitational potential energy is
(mass) x (gravity) x (height above ground) .
I don't see the object's speed anywhere in that formula, do you ?
An object's speed has no effect whatsoever on its potential energy ... only if it changes the object's height above ground.
While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find the motion somewhat unpleasant. To take your mind off your stomach, you wonder about the motion of the ride. You estimate the radius of the big wheel to be 15 m, and you use your watch to find that each loop around takes 25 s. What are your speed and magnitude of your acceleration? What is the ratio of your apparent weight to your true weight at the top of the ride? What is the ratio of your apparent weight to your true weight at the bottom?
ahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh this confused mee
What type of electromagnetic radiation travels the fastest?a) radio waves b) sound waves c) X-rays d) infrared rays e) All of the above
All electromagnetic waves have the same speed when they're all in the same medium.
Note: Sound waves don't belong on this list, because they're not electromagnetic waves. The speed of sound in air is only about 0.0001 percent of the speed of electromagnetic waves in air.
If the kinetic and potential energy in a system are equal, then the potential energy increases
Answer: less
Explanation:
A 1.2 nf parallel-plate capacitor has an air gap between its plates. Its capacitance increases by 3.0 nf when the gap is filled by a dielectric
What is the dielectric constant of that dielectric?
The dielectric constant of the dielectric material is 3.5.
Explanation:Given that the capacitance of the parallel-plate capacitor without the dielectric is 1.2 nF, and the capacitance increases by 3.0 nF when the gap is filled with the dielectric, we can find the dielectric constant using the equation:
C' = KC
Since the original capacitance is 1.2 nF and the increased capacitance is 1.2 + 3.0 = 4.2 nF, we can plug these values into the equation and solve for K:
KC = C'
K * 1.2 nF = 4.2 nF
K = 4.2 nF / 1.2 nF = 3.5
Therefore, the dielectric constant of the dielectric material is 3.5.
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Natalia is studying a wave produced in her magnetics lab. This wave can move through the empty space in a vacuum and carries a lot of energy.
Answer:
You forgot to put the question it's asking but its Gamma ray
Explanation:
Natalia is studying a wave produced in her magnetics lab. This wave can move through the empty space in a vacuum and carries a lot of energy.
What wave is Natalia most likely studying?
Gamma ray is the answer
could i possibly have a brainlist pwease
The magnetic field lines of a bar magnet spread out from the north end to the south end. South end to the north end. Edges to the center. Center to the edges.
the north end to the south end.
Explanation;Magnetic field lines from a bar magnet form lines that are closed. The direction of magnetic field is taken to be outward from the North pole of the magnet and in to the South pole of the magnet. A magnetic field refers to the area surrounding a magnet where a force is exerted on certain objects. These lines are spread out of the north end of the magnet.The magnetic field lines resemble a bubble.Answer
the answer is option A/ "north end to the south end"
Explanation:
A certain atom has 26 protons, 26 electrons, and 30 neutrons. It mass number is?
The most common atom of iron has 26 protons and 30 neutrons in its nucleus. What are its atomic number, atomic mass, and number of electrons if it is electrically neutral? This atom has atomic number 26, atomic mass 56, and has 26 electrons.
Answer :The mass number is 56.
Explanation:
Mass number is defined as the sum of number of protons and neutrons that are present in an atom.
Mass number = Number of protons + Number of neutrons = 26+ 30 =56
Atomic number is defined as the number of protons or number of electrons that are present in an atom.
Atomic number = Number of electrons = Number of protons = 26
Hence, neutrons and protons affects the mass number and thus the mass number will be 56.
Each croquet ball in a set has a mass of 0.53 kg. The green ball, traveling at 14.4 m/s, strikes the blue ball, which is at rest. Assuming that the balls slide on a frictionless surface and all collisions are head-on, find the final speed of the blue ball in each of the following situations: a) The green ball stops moving after it strikes the blue ball. Answer in units of m/s.b) The green ball continues moving after the collision at 2.4 m/s in the same direction. Answer in units of m/s. c) The green ball continues moving after the collision at 0.9 m/s in the same direction. Answer in units of m/s.
a) 14.4 m/s
The problem can be solved by using the law of conservation of total momentum; in fact, the total initial momentum must be equal to the final total momentum:
[tex]p_i = p_f[/tex]
So we have:
[tex]m_g u_g + m_b u_b = m_g v_g + m_b v_b[/tex] (1)
where
[tex]m_b = m_g = m = 0.53 kg[/tex] is the mass of each ball
[tex]u_g = 14.4 m/s[/tex] is the initial velocity of the green ball
[tex]u_b = 0[/tex] is the initial velocity of the blue ball
[tex]v_g=0[/tex] is the final velocity of the green ball
[tex]v_b[/tex] is the final velocity of the blue ball
Simplifying the mass in the equation and solving for [tex]v_b[/tex], we find
[tex]v_b = u_g = 14.4 m/s[/tex]
b) 12.0 m/s
This time, the green ball continues moving after the collision at
[tex]v_g = 2.4 m/s[/tex]
So the equation (1) becomes
[tex]u_g = v_g + v_b[/tex]
And solving for [tex]v_b[/tex] we find
[tex]v_b = u_g - v_g = 14.4 m/s-2.4 m/s=12.0 m/s[/tex]
c) 13.5 m/s
This time, the green ball continues moving after the collision at
[tex]v_g = 0.9 m/s[/tex]
So the equation (1) becomes
[tex]u_g = v_g + v_b[/tex]
And solving for [tex]v_b[/tex] we find
[tex]v_b = u_g - v_g = 14.4 m/s-0.9 m/s=13.5 m/s[/tex]
Final answer:
To find the final speeds of the blue ball after the green ball collides with it, the conservation of momentum principle is used, considering the green ball's various final speeds post-collision for each situation. The final speeds of the blue ball are 14.4 m/s, 12.0 m/s, and 13.5 m/s, respectively.
Explanation:
The problem involves conservation of momentum during collisions, as the surface is considered frictionless, and energy is conserved during perfectly inelastic collisions (although the question does not specify if the collisions are perfectly elastic or inelastic).
To solve for the final speed of the blue ball in each given situation, we'll apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Calculating the Final Speeds
When the green ball stops: Conservation of momentum implies that the momentum of the green ball before the collision is transferred entirely to the blue ball. Therefore, the blue ball's final speed will be the same as the initial speed of the green ball, i.e., 14.4 m/s.When the green ball continues at 2.4 m/s: The momentum lost by the green ball is gained by the blue ball. By conserving momentum, the final speed of the blue ball can be found and is calculated to be 12.0 m/s.When the green ball continues at 0.9 m/s: Again, by conserving momentum, the final speed of the blue ball is calculated to be 13.5 m/s.A 4.0 kilogram object is dropped from a height of 1.0 meter onto a spring with a spring constant of 850 newtons per meter. Approximately what distance will the spring compress when the object lands on it? (1) 3.0 dm
(2) 9.0 cm
(3) 9.0 mm
(4) 2.0 dm
Show calculations
To determine the compression of the spring when a 4.0 kg object is dropped from 1.0 meter, we use the conservation of energy principle. The gravitational potential energy of the dropped object is converted into the spring's elastic potential energy. Calculations show the spring will compress approximately 9.0 cm.
Explanation:We can solve the problem of the 4.0 kilogram object being dropped onto a spring by considering the conservation of energy. The gravitational potential energy at the height of 1.0 meter will convert into the elastic potential energy of the spring once the spring is compressed and the system momentarily comes to rest.
The gravitational potential energy (PE) can be calculated using the formula PE = mgh, where m is the mass, g is the acceleration due to gravity (9.8 m/s2), and h is the height from which the object is dropped. Therefore, PE = 4.0 kg * 9.8 m/s2 * 1.0 m = 39.2 Joules.
The elastic potential energy stored in a compressed spring is given by the formula PEspring = 1/2 * k * x2, where k is the spring constant and x is the compression distance. Setting the gravitational potential energy equal to the spring's elastic potential energy gives 39.2 J = 1/2 * 850 N/m * x2. Solving for x gives x = sqrt((2 * 39.2) / 850) which approximately equals 0.09 meters or 9.0 cm.
Una esfera homogénea de radio r y peso W resbala en un piso bajo la acción de una fuerza horizontal constante P aplicada a una cuerda, como se muestra en la Fig. 1. (a) Demostrar que, si ? es el coeficiente de rozamiento entre la esfera y el piso, la altura h está dada por h = r (1 – ?W/P). (b) Demostrar que la esfera no se encuentra en equilibrio de traslación bajo estas circunstancias. (c) Si se escoge un valor diferente de h, ?se puede lograr que la esfera se encuentre tanto en equilibrio de rotación como de traslación? ?Y si se escoge una dirección diferente para P? Dar una explicación de lo que ocurre.
Squid rely on jet propulsion when a rapid escape is necessary A 1.5 kg squid at rest pulls 0.10 kg of water into its mantle, then ejects this water at a remarkable 45 m/s. Right after this ejection, how fast is the squid moving? Express your answer with the appropriate units.
Answer:
-3 m/s
Explanation:
The problem can be solved by using the law of conservation of momentum.
In fact, the system squid+water inside is initially at rest, so the total momentum is zero:
[tex]p_i=0[/tex]
while the final momentum is:
[tex]p_f = m_s v_s + m_w v_w[/tex]
where
[tex]m_s=1.5 kg[/tex] is the mass of the squid
[tex]v_s[/tex] is the velocity of the squid
[tex]m_w = 0.10 kg[/tex] is the mass of water
[tex]v_w = 45 m/s[/tex] is the water velocity
Since the total momentum must be conserved,
[tex]p_i = p_f = 0[/tex]
So we have
[tex]m_s v_s + m_w v_w =0\\v_s = -\frac{m_w v_w}{m_s}=-\frac{(0.10 kg)(45 m/s)}{1.5 kg}=-3 m/s[/tex]
where the negative sign means the direction is opposite to that of the water.
The final velocity of the squid after the ejection of the water is 3 m/s backwards.
The given parameters;
mass of the squid, m₁ = 1.5 kginitial velocity of the squid, u₁ = 0mass of water, m₂ = 0.1 kginitial velocity of the water, u₂ = 0final velocity of the ejection, v₂ = 45 m/sApply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
1.5(0) + 0.1(0) = 1.5v₁ + 45(0.1)
0 = 1.5v₁ + 4.5
1.5v₁ = -4.5
[tex]v_1 = \frac{-4.5}{1.5} \\\\v_1 = -3 \ m/s[/tex]
Thus, the final velocity of the squid after the ejection of the water is 3 m/s backwards.
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