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Compare and contrast angular momentum and linear momentum. Include two ways that they are alike and two ways that they are different. Be sure to discuss how mass affects both angular and linear momentum.

Answers

Answer 1
Linear momentum of an object is the product of the object’s mass and velocity. Linear momentum is a vector quantity, and the direction of momentum is taken to be the direction of the object’s velocity.

or an object with mass  moving at a velocity , the angular momentum  with respect to a reference point is defined using the cross product as:

where  is the position vector of the object that describes the object’s position with respect to the reference point. The units for measuring angular momentum is kg m2 s-1. Since angular momentum is defined in terms of a cross product, the direction of the angular momentum vector is taken to be in a direction perpendicular to both the particle’s position vector  and its velocity vector .

Answer 2

Imma answer so other dude can have brainliest.  

<3 :p


Related Questions

A 0.24-kg stone is held 1.2 m above the top edge of a water well and then dropped into it. the well has a depth of 4.8 m. (a) relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stoneâearth system before the stone is released? 14.112 incorrect: your answer is incorrect. your response differs from the correct answer by more than 100%. j (b) relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stoneâearth system when it reaches the bottom of the well? 0 incorrect: your answer is incorrect. the correct answer is not zero. j (c) what is the change in gravitational potential energy of the system from release to reaching the bottom of the well?

Answers

Ans : a) E1 = 0.21*9.81*1.2 = 2.47 J b) E2 = 0.21*9.81*(-5.3) = -10.92 J c) Change = E2 - E1 = -10.92 - 2.47 = 13.39 J

An object is suspended from the ceiling with two wires that make an angle of 40° with the ceiling. The weight of the body is 150 N. What is the tension in each wire?

41.6 newtons
82.3 newtons
150 newtons
117 newtons

Answers

Refer to the diagram shown below.

Let T =  the tension in each wire.
For equilibrium,
2T cos(50°) = 150 N
1.2856T = 150
T = 116.677 N ≈ 117 N

Answer: 117 N

Answer:

the Answer is D 117 newtons

Explanation:

A car traveling at a steady 20 m/s rounds an 80-m radius horizontal unbanked curve with the tires on the verge of slipping. what is the maximum speed with which this car can round a second unbanked curve of radius 320 m if the coefficient of static friction between the car's tires and the road surface is the same in both cases?

Answers

Refer to the diagram shown below.

r = the radius of the curve
m =  the mass of the car
μ = the coefficient of kinetic friction
N = normal reaction

When rounding the curve, the centripetal acceleration is
[tex]a = \frac{v^{2}}{r} [/tex]

The inertial force tending to make the car skid is balanced by the frictional force, therefore
[tex]\mu mg = m \frac{v^{2}}{r} \\ \mu = \frac{v^{2}}{rg} [/tex]

When r = 80 m and v = 20 m/s, obtain
[tex]\mu = \frac{(20 m/s)^{2}}{(80 \, m)*(9.8 \, m/s^{2})} = 0.51[/tex]

When r = 320 m and μ remains the same, obtain
[tex] \frac{(v \, m/s)^{2}}{(320 \, m)*(9.8 \, m/s^{2})} =0.51 \\\\ v^{2} = 1.6 \times 10^{3} \\\\ v = 40 \, m/s[/tex]

Answer: 40 m/s

The maximum speed with which this car can round a second unbanked curve is 40 m/s

[tex]\texttt{ }[/tex]

Further explanation

Centripetal Acceleration can be formulated as follows:

[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]

a = Centripetal Acceleration ( m/s² )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

[tex]\texttt{ }[/tex]

Centripetal Force can be formulated as follows:

[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]

F = Centripetal Force ( m/s² )

m = mass of Particle ( kg )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial speed of the car = v₁ = 20 m/s

radius of first curve = R₁ = 80 m

radius of second curve = R₂ = 320 m

Asked:

final speed of the car = v₂ = ?

Solution:

Firstly , we will derive the formula to calculate the maximum speed of the car:

[tex]\Sigma F = ma[/tex]

[tex]f = m \frac{v^2}{R}[/tex]

[tex]\mu N = m \frac{v^2}{R}[/tex]

[tex]\mu m g = m \frac{v^2}{R}[/tex]

[tex]\mu g = \frac{v^2}{R}[/tex]

[tex]v^2 = \mu g R[/tex]

[tex]\boxed {v = \sqrt { \mu g R } }[/tex]

[tex]\texttt{ }[/tex]

Next , we will compare the maximum speed of the car on the first curve and on the second curve:

[tex]v_1 : v_2 = \sqrt { \mu g R_1 } : \sqrt { \mu g R_2 }[/tex]

[tex]v_1 : v_2 = \sqrt { R_1 } : \sqrt { R_2 }[/tex]

[tex]20 : v_2 = \sqrt { 80 } : \sqrt { 320 }[/tex]

[tex]20 : v_2 = 1 : 2[/tex]

[tex]v_2 = 2(20)[/tex]

[tex]\boxed {v_2 = 40 \texttt{ m/s}}[/tex]

[tex]\texttt{ }[/tex]

Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441

[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Physics

Chapter: Circular Motion

One mole of helium atoms has a mass of 4 grams. if a helium atom in a balloon has a kinetic energy of 1.224e-21 j, what is the speed of the helium atom? (the speed is much lower than the speed of light.) v = 6.12e-19 incorrect: your answer is incorrect. m/s

Answers

607 m/s First, let's calculate the mass of a helium atom. You do that by dividing the mass of 1 mole of helium atoms by avogadro's number. So 4 / 6.0221409e23 = 6.6422e-24 g = 6.6422e-27 kg The equation for kinetic energy is E = 0.5 M V^2 And we have 1.224e-21 J, which is 1.224e-21 kg*m^2/s^2 So substitute the known values into the equation for kinetic energy and solve for V 1.224e-21 kg*m^2/s^2 = 0.5 6.6422e-27 kg V^2 1.224e-21 kg*m^2/s^2 = 3.32108e-27 kg V^2 368555 m^2/s^2 = V^2 607 m/s = V

Why might it be necessary to ignore some of the data points just before and just after the collision?

Answers

Final answer:

In physics, some data points may need to be ignored just before and after a collision. This is done to remove errors and focus on the specific moment of collision.

Explanation:

In physics, it may be necessary to ignore some of the data points just before and just after a collision for various reasons. One reason is to remove outliers or errors in the measurements that could skew the results. For example, if there is a sudden spike or dip in the data due to a measurement error, it would be necessary to exclude those points to ensure accurate analysis.

Another reason is to focus on the specific moment of collision. By excluding the data points surrounding the collision, it allows for a clearer observation and analysis of the collision itself. This is important for understanding the dynamics and effects of the collision.

Therefore, it is not necessary to ignore both sets of data equally, but rather selectively remove data points that may introduce errors or hinder the analysis of the collision.

Kepler used the observations and data of which scientist to formulate his laws of planetary motion?

Answers

Kepler used the observations of Tycho Brahe to formulate his laws of planetary motion. Kepler worked for Tycho in his lab during his younger years. Tycho liked Kepler's intelligence, and he respected his spunk, so he gradually showed him more and more of his precious measurements. This data was crucial in the development of Kepler's laws of planetary motion. 

The findings of Henri Becquerel and the Curies helped to discredit what notion held for a very long time? That matter can never be created or destroyed. Matter is made up of any smaller parts. Matter is radioactive and decays over time. That matter is invisible and indestructible.

Answers

Matter is radioactive and decays over time



Henri Becquerel discovered that uranium salts spontaneously emit a penetrating radiation that can be registered on a photographic plate.

hope this helps

The answer is: That matter is indivisible and indestructible

Through his experiment, Henri Becquerel found that matters can be stored within another object, (He took potassium uranyl sulfate and put it under the sun and then put the substance within photographic plates that he cover with black paper, ) . Curie found that over time matters would decay and eventually gone.

What is the magnitude of the frictional force exerted on the mug?

Answers

I can;t answer this question without any context. However, I found a similar problem with a given illustration as shown in the first picture attached. The angle is said to be 17°. The free body diagram is constructed as shown in the second picture attached. The solution is as follows:

∑Fy = 0
Fn = Wy
Fn = Wcos17° = (0.27 kg)(cos 17°) = 0.258 N

∑Fx = 0
Ff - Wx = 0
Ff = Wsin17° = (0.27 kg)(sin 17°) = 0.079 N

Thus, the magnitude of the frictional force is 0.079 N.

The pressure 75.0 meters underwater is 837 kpa. what is this pressure in atm

Answers

Note that
1 atm = 101.325 kPa

The given pressure is
[tex]837 \, kPa = (837 \, kPa)*( \frac{1}{101.325} \, \frac{atm}{kPa} ) = 8.26 \, atm[/tex]

Answer: 8.26 atm (nearest hundredth)

The mixture you separated was mixture of iron filings, sand, and salt. Based on your understanding of matter, is this mixture a homogeneous mixture or heterogeneous mixture? How do you know?

Answers

The answer is "Heterogeneous mixture because the filings and particles of sand and salt are distributed randomly in the mixture."

A mixture is a mix of at least two substances in any extent. This is not quite the same as a compound, which comprises of substances in settled extents.

A heterogeneous mixture is formed when the chemicals in the blend are not consistently conveyed all through the blend. For example, on the off chance that you add sand to salt, no measure of crushing can make sand and salt frame a homogeneous blend like salt and water. In this way, we can state that a blend of sand and salt will shape a heterogeneous mixture.

Answer;

-Heterogeneous mixture because the filings and particles of sand and salt are distributed randomly in the mixture

Explanation;A mixture is a substance that is made up of two or more substances.  Mixtures are not pure substances like the case of elements and compounds. A mixture may be either homogeneous or heterogeneous. A homogeneous mixture is a mixture in which the components are uniformly distributed. This means there is only one phase of matter, hence a homogeneous mixture can exist as a solid, gas or liquid. A heterogeneous mixture on the other hand is a type of mixture in which the components making the mixture are not uniform. A heterogeneous mixture contains more than one phases of matter. These types of mixtures may be either suspensions or colloids.

A skier leaves a ski jump with a horizontal velocity of 29.4 m/s. the instant before she lands three seconds later, the magnitudes of the horizontal and vertical components of her velocity are:

Answers

Answer:

The horizontal and vertical velocity of the skier are both 29.4 m/s.

Explanation:

If no forces are acting in the horizontal direction, then the horizontal component of the velocity remains constant in time:

Vx = 29.4 m/s

For the vertical component the gravity acceleration must be considered, and the vertical velocity can be written as:

Vy = g*t

Here the value for g is 9,8 m/s2. Note that the initial vertical velocity is zero.  

Evaluating in the velocity’s expressions for a time of 3 seconds we obtain:

Vx = 29.4 m/s

Vy = 9.8 m/s2 * 3 s = 29.4 m/s

Express 4,560 m in km. Remember to keep the same number of significant figures in your answer as was in the original measurement.

Answers

Just divide by 1000. So 4560/1000 = 4.560m

Answer:

4560m=4.560km

Explanation:

Analysis conceptual

We know that:

1km=1000m

Then, the conversion factor from meters to kilometers is: 1km/1000m

Known data:

4560 m

problem development

We multiply the amount given in m by the conversion factor (1km/1000m ):

[tex]4560 m(\frac{1km}{1000m} )=4.560km[/tex]

4560m=4.560km

Suppose a person standing on the top of a building of 160 ft high throws a ball directly upward with an initial speed of 48 ft/s.
a.find the ball's height, velocity and acceleration at time t.
b.when does the ball hit the ground and what is its impact velocity?
c.how far does the ball travel during its fligh

Answers

see images below for the solution

A man stands out at the end of the diving board, which is supported by two springs a and b, each having a stiffness of k = 15 kn/m. in the position shown the board is horizontal. if the man has a mass of 40kg, determine the angle of tilt which the board makes with the horizontal after he jumps off. neglect the weight of the board and assume it is rigid.

Answers

Answer: The spring force at A and B can be obtained directly by summing moments_aJx)ut points B and A. respectively. (+ IM, = 0; F A (1)- 392.4(3) =0 F A = 1 177.2 N C+ 1M a = 0; F, (1) -392.4(4) = 0 F, = 1569.6 N Spring Formula : Applying A = - , we have Inn I S , A a = - 1 . 177 ' -- = 0.07*48 m A, = 156 ~ = 0. 10464 ra x 15(103) 15(103) Geometry : The angle of tilt a is a - tan' 1 ^ 0.10464 + 0.07848 1 10.4° v * F Z te

How are all paths that have a displacement of zero similar?

Answers

Displacement is known as the net movement of an object with respect to its original position. One may travel out of his city and return. Despite having covered many miles, he will have a displacement of 0.
This is true for all paths that have zero displacement, that they all return to their original position.
They all end where they began.

When baseball players throw the ball in from the outfield they usually allow?

Answers

The ball is usually allowed one bounce before it reaches the infielder on the thought that it will reach him faster. Throwing the ball all the way to the infielder or catcher typically takes a short time longer, which can be vital depending on the speed of the runner.

A car speeds up as it rolls down a hill. which is this an example of? positive acceleration negative acceleration relative velocity

Answers

positive acceleration
Positive acceleration

A typical set of stairs is angled at 38 degrees. You climb a set of stairs at a speed of 3.1m/s. 1.) How much height will you gain in 4.4 seconds? 2.) How much horizontal distance will you cover in 4.4 second

Answers

This one is easy once you see that this can be represented by a vector diagram. Believe it or not, vectors are really really simple to do once you know this neat trick i'm about to show you. It's based on the SOH, CAH, TOA system but is a brilliant for very quickly solving the problem. Imagine the vertical part is the y component and the horizontal part is the x component.

To find the 'x' component, use:
x = V * cos(Ф)
to find the y component, use:
y = V * sin(Ф)

where V = the vector length (here this is calculated as (3.1m/s x 4.4s),
and,
Ф = the angle of the stairs.

If you break down all vector type questions into these parts you will solve them very quickly which is very useful in an exam :)

Let me know if you have any questions, since i have assumed some knowledge in my answer.

you ask people to rate there depression on a scale of 1 to 10 their respnses are a (n)___in your study. a.variable b.discrete v c.observation d.hidden v

Answers

The answer is A) variable. The depression level is a value that varies with the respondents and may inform you about the relationship between depression and other variables, such as alcohol use or sleep habits. It is also likely a discrete variable, since the answer is probably an integer (1, 2, ... 10), rather than a continuous spectrum (virtually any number between 1 and 10). 

When an experiment is replicated, how should the results of the two experiments compare?

Answers

When the experiment is replicated, this means the conduction of the second experiment, should be related, or similar, to your first results. 

Answer:

Should be same

Explanation:

An experiment is conducted to test a theory. It is expected that the result of the experiment would match with the theoretical result. Also, if the experiment is repeated by the same or another person, it should give the same result. If not, then either there is error in conduction of experiment or in the theory.

Which properties of plastics allow them to be solutions to many complex problems in the world? Check all that apply. A.chemically resistant B. durable C. non-reactive D. high weight E. easy to manufacture

Answers

Answer: A, B, C, E

Explanation:

Plastics have a number of properties that make them useful solutions to many complex problems in the world, such as being chemically resistant, durable, non-reactive, and easy to manufacture, which are options A, B, C, and E.

What is plastic?

Plastics have a number of properties that make them a popular choice in many industries, such as chemical resistance, which is one of the most important properties of plastics, as they can resist a wide range of chemicals, including acids, bases, and solvents, which makes them ideal for use in chemical processing, pharmaceuticals, and food packaging. Durability is another important property of plastics.

They are resistant to wear and tear, impact, and weathering, which makes them suitable for use in various applications, such as building materials, automotive parts, and toys. Plastics are also non-reactive, which means that they do not react with other materials.

Hence, the correct answers are chemically resistant, durable, non-reactive, and easy to manufacture, which are options A, B, C, and E.

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If x=450 mm, determine the mass of the counterweight s required to balance a 90-kg load, l.

Answers

Final answer:

To balance the 90-kg load, a counterweight with a mass of 90 kg is required.

Explanation:

To balance the system, the torque exerted by the 90-kg load, l, must be equal to the torque exerted by the counterweight, s. The torque is given by the product of the force and the lever arm. Since the distance from the fulcrum to the load is x=450 mm, the torque exerted by the load is (90 kg)(9.8 m/s^2)(0.45 m). To balance this torque, the counterweight must exert an equal torque but in the opposite direction. Therefore, the mass of the counterweight can be calculated using the equation:

 

torque load = torque counterweight
(90 kg)(9.8 m/s^2)(0.45 m) = mass counterweight(9.8 m/s^2)(0.45 m)

 

Simplifying and solving for the mass of the counterweight, we have:

 

mass counterweight = (90 kg)(0.45 m) / 0.45 m = 90 kg

 

Therefore, the mass of the counterweight required to balance the 90-kg load is 90 kg.

a 3,000kg truck runs into the rear of a 1000kg car that was stationary. The truck and car are locked together after the collision and move with speed 9m/s what was the speed of the truck before the collision?

Answers

Final answer:

Using the law of conservation of momentum, which states that initial momentum equals final momentum in a closed system, the initial speed of the truck before it collided with the stationary car is calculated to have been 12 m/s.

Explanation:

This question pertains to the concept of momentum in physics. The law of conservation of momentum states that the total momentum of a system of objects is constant if no external forces are acting on it. In this case, the truck and the car form the system of objects.

The initial momentum of the system before the collision is given by the momentum of the truck, since the car is stationary. The final momentum after the collision is given by the combined mass of the truck and car, multiplied by their common speed.

So, if we denote the initial speed of the truck as V, we have: 3000kg * V (initial momentum of truck) = (3000kg + 1000kg) * 9m/s (final momentum of the system)

Solving for V, we find the initial speed of the truck to have been 12 m/s.

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A position vector with magnitude 10 m points to the right and up. its x-component is 6.0 m. part a what is the value of its y-component?

Answers

The position vector with magnitude [tex]10 \ m[/tex] points to the right and up. its x-component is  [tex]6.0\ m[/tex] and its y-component is  [tex]8\ m[/tex].

A vector is a physics term for a quantity with both magnitude (size) and direction. Physical quantities including each of these properties are represented by vectors, such as displacement, velocity, force, and acceleration.

The resultant vector is the vector that is created when two or more vectors are added together. It depicts the final result of mixing the various vectors. The vector addition of the various vectors yields the resultant vector.

Given:

Magnitude = [tex]10 \ m[/tex]

x- component = [tex]6\ m[/tex]

The resultant vector is given as:

[tex]r = sqrt(x^2+y^2)\\10 = sqrt(6^2+y^2)\\y^2 = 100-36\\y = 8\ m[/tex]

Hence, the position vector with magnitude  [tex]10 \ m[/tex] points to the right and up. its x-component is [tex]6.0\ m[/tex] and its y-component is [tex]8\ m[/tex].

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A little boy sitting on the floor tosses a ball in such a way that it reaches the level of a tabletop several meters away, moving horizontally, and rolls across the tabletop at constant speed if friction with the air and the tabletop can be ignored, with what speed does the ball roll across the tabletop?

Answers

Let
u = the horizontal component of the launch velocity,
v = the vertical component of the launch velocity.

Because air resistance is ignored, the horizontal velocity remains unchanged.
The vertical velocity diminishes to zero due to gravitational acceleration.
Therefore the ball rolls across the tabletop with horizontal velocity, u.

Answer:
The speed of the ball remains constant at u on the tabletop (see the diagram shown below) because rolling friction is ignored.

where do you bump into neon in everyday life

Answers

beer signs jk on signs an stuff tho 
signs, nail polish, glow sticks, glow lamps, electron tubes, clothing

A rollercoaster car, 300 kg with passengers, accelerates down a 65 degree hill. we will assume that friction is small enough that it can be ignored. 1) determine the value of the component of the gravitational force parallel to the hill. 2) what is the acceleration of the rollercoaster down t

Answers

Refer to the diagram shown below.

m = 300 kg, the mass of the rollercoaster
θ = 60°
g = 9.8 m/s²
Friction is ignored.

The component of the weight acting down the incline (no friction) is
F = mg sinθ
   = (300 kg)*(9.8 m/s²)*sin(65°)
   = 2664.5 N

If the acceleration down the incline, then
(300 kg)*(a m/s²) = 2664.5 N
a = 2664.5/300 = 8.882 m/s²

Answers:
(1) F = 2664.5 N acting down the hill
(2) a = 8.882 m/s²


Final answer:

The component of the gravitational force parallel to the hill is mg⋅sin(65°). The acceleration of the rollercoaster down the hill is (mg⋅sin(65°))/m.

Explanation:

To determine the value of the component of the gravitational force parallel to the hill, we can use trigonometry. The component of the weight parallel to the hill is given by the equation mg⋅sinθ. In this case, θ is 65 degrees. So the value of the component of the gravitational force parallel to the hill is mg⋅sin(65°).

To find the acceleration of the rollercoaster down the hill, we can use Newton's second law, which states that force equals mass times acceleration. In this case, the force is the component of the gravitational force parallel to the hill, and the mass is given as 300 kg with passengers. So the acceleration is a = F/m = (mg⋅sin(65°))/m.

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Write a hypothesis about how the height of the cylinder affects the temperature of the water. Use the "if . . . then . . . because . . .” format and be sure to answer the lesson question: "How is potential energy converted to thermal energy in a system?”

Answers

The statement that can be used to answer this  question is:

"If the cylinder is brought higher then, its temperature when brought down becomes higher because a greater amount of potential energy is converted to thermal energy."

The potential energy is converted to thermal energy when the object is released the velocity becomes higher because of the acceleration due to gravity.

Sample Response: If the height of the cylinder increases, the temperature of the water increases, because a greater height means the cylinder has more potential energy that can be converted to thermal energy, increasing the temperature of the water.

A sports car accelerates from rest to 95km/h in 4.3 seconds. What is its average acceleration in m/s^2?

Answers

Change 95 km/hr to m/sec

Suppose that data are stored on 8.54-gbyte single-sided, double-layer dvds that weigh 15 g each. suppose that an eurostar rail service train, london to paris via chunnel, carries 10 4 kg of these dvds. the great circle distance of the line is 640 km and the traveling time is 2 hours, 15 minutes. what is the data transmission rate in bits per second of this system?

Answers

we get answer this quation


The data transmission rate of the Eurostar rail service train, London to Paris via Chunnel  is  11516003 bite/second.

What is  transfer rate?

Transfer rate is a common metric for gauging how quickly data or information moves from one place to another.

Amount of of data stored in single-side = 8.54-gbyte.

Mass of the one double-layer DVDs= 0.015 g.

Total mass of DVDs = 10⁴ kg.

Total number of DVDs = 10⁴  ÷ 0.015  = 666667

Total amount of data =  666667 × 2 × 8.54 × 1024 × 8 bite

Total time taken = 2 hour 15 min = 2.25 hour = (2.25 × 3600) s = 8100 second

The data transmission rate is = (666667 × 2 × 8.54 × 1024 × 8) ÷ 8100 bite/second

= 11516003 bite/second.

Therefore, the data transmission rate of the Eurostar rail service train, London to Paris via Chunnel is  11516003 bite/second.

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