Write a real world situation that can be modeled by the inequality
834 + 14s > 978 - 10s. Then solve the inequality.

Answers

Answer 1
Final answer:

The inequality 834 + 14s > 978 - 10s can represent a situation involving saving and spending money over time. To solve it, you perform a series of operations to isolate variable 's', which in this case results in s > 6, indicating more than six weeks required for savings to exceed spending.

Explanation:

A real world situation that can be modelled by this inequality 834 + 14s > 978 - 10s could be a scenario involving saving and spending money. Say you start with $834 and each week you save $14 (s represents the number of weeks). On the other hand, you have $978 and you spend $10 each week. You want to figure out how many weeks it will take for the amount you have from saving to be more than the amount left from spending.

Now, to solve the inequality: subtract 834 from both sides which gives 14s > 144 - 10s, then combine like terms to get 24s > 144. Finally, divide both sides by 24 to solve for s: s > 6. Therefore, it will take more than six weeks for the money you save to exceed what remains from your starting amount of $978 after spending $10 each week.

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Related Questions

Differentiate: x√(x+4)

Answers

[tex]\bf y=x\sqrt{x+4}\implies y=x\left( x+4 \right)^{\frac{1}{2}} \\\\\\ \cfrac{dy}{dx}=1\cdot \left( x+4 \right)^{\frac{1}{2}}~~+~~x\cdot \cfrac{1}{2}\left( x+4 \right)^{-\frac{1}{2}}\implies \cfrac{dy}{dx}=\sqrt{x+4}+\cfrac{x}{2\sqrt{x+4}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2(x+4)~~+~~x}{2\sqrt{x+4}}\implies \cfrac{dy}{dx}=\cfrac{2x+8+x}{2\sqrt{x+4}}\implies \cfrac{dy}{dx}=\cfrac{3x+8}{2\sqrt{x+4}}[/tex]

The top of a 15-foot ladder leans against a wall, and the bottom of the ladder slides away from the wall at a rate of 4 ft/sec. find the velocity of the top of the ladder at time t = 1 sec if the bottom of the ladder is 5 feet away from the wall at time t = 0.

Answers

Final answer:

The velocity of the top of the ladder at time t = 1 sec is -4 ft/sec.

Explanation:

To find the velocity of the top of the ladder at time t = 1 sec, we can use the concept of similar triangles. Let x be the distance between the bottom of the ladder and the wall at time t = 1 sec. Since the bottom of the ladder slides away from the wall at a rate of 4 ft/sec, we have x = 5 + 4t.

The height of the ladder remains constant at 15 ft, so if we consider the triangle formed by the ladder, the wall, and the ground, we have the ratio of the height to the base is always 15 / x. Therefore, the velocity of the top of the ladder can be found by taking the derivative of the height with respect to time.

Let h be the height of the ladder at time t. Since h = 15, we have 15 / x = 15 / (5 + 4t). Taking the derivative of both sides, we get d/dt (15 / x) = d/dt (15 / (5 + 4t)). Using the quotient rule, we have d/dt (15 / x) = (0 - 15)(0 - (5 + 4t)-2)(4) = -60 / (5 + 4t)². This gives us the velocity of the top of the ladder at time t = 1 sec: v = -60 / (5 + 4(1))² = -4 ft/sec.

In a certain town, the wind speed, x, in km/h on a certain day is described by two statements: If 2 times the wind speed is increased by 2, the wind speed is still less than 46 km/h. Twice the wind speed minus 27 is greater than 11 km/h. Part A: Create a compound inequality to represent the wind speed range. (3 points) Part B: Can the wind speed in this town be 20 km/h? Justify your answer by solving the inequalities in Part A. (3 points) Part C: The average wind speed in another town is 23 km/h, but the actual wind speed is within 4 km/h of the average. Write and solve an inequality to find the range of wind speed in this town.

Answers

1) if 2 times the wind speed is increased by 2, the wind speed is still less than 46 km/h.

=> 2x + 2 < 46

2) Twice the wind speed minus 27 is greater than 11 km/h.

=> 2x - 27 > 11

Part A: Create a compound inequality to represent the wind speed range. (3 points)


from 2x + 2 < 46

=> 2x < 44

=> x < 22

from 2x - 27 > 11

=> 2x > 11 + 27

=> 2x > 38

=> x > 19

The set of inequalities is

2x + 2 <46
2x - 27 > 11

The solution is x < 22 and x > 19, which is:

19 < x < 22 <----- answer

Part B: Can the wind speed in this town be 20 km/h? Justify your answer by solving the inequalities in Part A. (3 points)

Yes, the wind speed can be 20 km/h, because the solution of the inequality is the range (19,22).

Part C: The average wind speed in another town is 23 km/h, but the actual wind speed is within 4 km/h of the average. Write and solve an inequality to find the range of wind speed in this town.

x ≥ 23 - 4 => x ≥ 19

x ≤ 23 + 4=> x ≤ 27

=> 19 ≤ x ≤ 27

=> [19,27]

Find the fractional notation for the ratio 5 to 9

Answers

5:9 is just 5/9
Hope this helps!

help quick. first person with the right answer gets brainiest

Answers

The last option is the correct answer.
Counter clockwise 180-degree rotation

A multivitamin tablet contains 0.16g of vitamin C. How much vitamin C does a bottle of 60 tablets contain?

Answers

9.6 
0.16 tims 60 is 9.6

divide 28 cans of soda into two groups so the ratio is 3 to 4

Answers

First you add the ratio so 3+4=7. Then, divide 28 by 7 and you get 4. Next, you multiply 4 x 3=12 and 4 x 4=16. So it would be 12 : 16.

What is the trigonometric derivative of Y=2sinx-tanx

Answers

[tex]\bf y=2sin(x)-tan(x)\implies \cfrac{dy}{dx}=2cos(x)-sec^2(x)[/tex]

Tabitha found the side length of a cube with a volume of 512 cubic centimeters using the following steps. Cube V = s3

Answers

Answer:

the answer is 3cm

HOPE THIS WORKED

Step-by-step explanation:

I JUST ANSWERED THIS ON EDG

The volume of a cube is given as 512 cubic cm then the side length of the cube is 8 mm.

What is the volume of a cube?

The volume of a cube can be calculated as the cube of the sides of a given figure.

The volume of a cube = [tex]sides^3[/tex]

We have been given that the volume of a cube is 512 cubic cm. We need to find the side length of the cube.

The volume of a cube = [tex]sides^3[/tex]

                                64  =  [tex]sides^3[/tex]

Now we will take cube-root on both sides of the equation;

∛ 512 = ∛ s^3

∛ 8^3 = ∛ s^3

8 = s

Therefore, the side length of the cube is 8 cm.

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Which expression has a positive value A.(-5)(-9) B.2-4 C.12/(-4) D. -3+(-7)

Answers

A. Since a negative times a negative is a positive, (-5)(-9) would be 45.
B. 2 - 4 = -2
C. 12/(-4) = -3
D. Adding a negative is essentialy the same thing as subtracting, so -3 + (-7) is the same thing as -3 - 7, which equals -10.

Therefore, the only equation that results in a positive value is A.
Final answer:

Out of given expressions, only expression A results in a positive value. Expression B, C, and D all result in a negative value.

Explanation:

To determine which expression results in a positive value, evaluate each:

A. (-5)(-9): Here, a negative times a negative results in a positive value, so this equals 45.B. 2-4: This equals -2, which is not a positive value.C. 12/(-4): This equals -3, which is also not a positive value.D. -3+(-7): This equals -10, which is not a positive value.

So, "only expression A results in a positive value".

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Jose rented a truck for one day. There was a base fee of $14.99 , and there was an additional charge of 83 cents for each mile driven. Jose had to pay $238.26 when he returned the truck. For how many miles did he drive the truck?

Answers

Hi! So, the base fee was $14.99, which is the price you only pay one time. $0.83 was charged per mile driven, so the price changes constantly per mile driven. He had to pay $238.26 total when he returned the truck. To make this problem easier to solve, let's make an equation in this form: 14.99 + 0.83m = 238.26. In these kinds of formulas, suntract 14.99 from both sides to make the "m" by itself. When you do that, you get 0.83m = 223.27. Now to find the answer, divide each side by 0.83 to isolate the "m". 223.27/0.83 is 269. Let's plug it in to see if it works. 269 * 0.83 is 223.27. 223.27 + 14.99 is 238.26. There. Jose drove 269 miles with the truck. m = 269.

The clown Also bought 5 bags of heart shaped Balloons with 14 Balloons in each Bag

Answers

299 blown-up balloons; possible explanation: fi rst I found the number of heart-shaped balloons, 5 × 14 = 70. Next, I added that number to the number of round balloons and long balloons, 70 + 144 + 108 = 322 balloons in all. Last, I subtracted the number of burst balloons, so 322 – 23 = 299 balloons left.
Final answer:

The clown bought a total of 70 heart-shaped balloons. This is found by multiplying the number of bags (5) by the number of balloons in each bag (14).

Explanation:

The question involves a basic multiplication operation in mathematics. The clown bought 5 bags of heart-shaped balloons and each bag contains 14 balloons. To find the total number of balloons, you multiply the number of bags (5) by the number of balloons in each bag (14). This is done as follows:

Identify the numbers in the question: 5 bags, 14 balloons in each. Perform the multiplication: 5 (bags) x 14 (balloons in each bag) = 70 balloons.

So, the clown bought a total of 70 heart-shaped balloons.

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1 2 3 4 5 6 7 8 9 10
TIME REMAINING
48:54
What number should be added to both sides of the equation to complete the square?

x2 + 3x = 6



3
62

Answers

Answer:

2.25

Explanation:

Consider the square ...

... (x+a)² = x² +2ax +a²

The constant term (a²) is the square of half the x-coefficient: a² = (2a/2)².

The x-coefficient in your expression is 3. The square of half that is ...

... (3/2)² = 9/4 = 2.25

Adding 2.25 to both sides gives ...

... x² +3x + 2.25 = 6 + 2.25

... (x +1.5)² = 8.25 . . . . completed square

(3/2)^2

I believe it is (3/2)^2 because I tried working it out and got something like it. I did get an answer of x = ±[tex]\sqrt{33}[/tex] over 2.

Most sources appear to give 2.25, which is equal to 3/2 squared.

Attached some work.

An equation that represents the set of points that are 2 units from (-2,-6)

Answers

If the set of points have a constant distance (radius, r) from a point, the set of points form a circle, which has the standard equation:

(x-x0)^2+(y-y0)^2=r^2

where (x0,y0) is the given point (-2,-6), and r=radius=2.

Substituting, the equation is then
(x-(-2))^2+(y-(-6))^2=2^2, or

(x+4)^2+(y+6)^2=4......(1)

The equation representing the set of points that are 2 units from the point (-2,-6) is a circle with equation (x + 2)^2 + (y + 6)^2 = 4

The question asks for an equation that represents the set of points that are exactly 2 units from the point (-2,-6) in a coordinate system. This set of points forms a circle with a radius of 2 units centered at (-2,-6). The equation for a circle with radius r and center (h, k) is (x - h)² + (y - k)² = r². Thus, the equation of the circle is (x + 2)² + (y + 6)² = 2² or (x + 2)² + (y + 6)² = 4

Find the work done by the force field f(x, y, z) = x − y2, y − z2, z − x2 on a particle that moves along the line segment from (0, 0, 1) to (3, 1, 0).

Answers

The path can be parameterized by [tex]\mathbf r(t)=\langle0,0,1\rangle(1-t)+\langle3,1,0\rangle t=\langle3t,t,1-t\rangle[/tex] with [tex]0\le t\le1[/tex]. So, the work done by [tex]\mathbf F(x,y,z)=\langle x-y^2,y-z^2,z-x^2\rangle[/tex] is given by the line integral

[tex]\displaystyle\int_C\mathbf F\cdot\mathrm d\mathbf r[/tex]

where [tex]C[/tex] is the line segment. Equivalently,

[tex]\displaystyle\int_{t=0}^{t=1}\langle3t-t^2,t-(1-t)^2,1-t-9t^2\rangle\cdot\langle3,1,-1\rangle\,\mathrm dt[/tex]
[tex]=\displaystyle\int_0^1(5t^2+13t-2)\,\mathrm dt[/tex]
[tex]=\dfrac{37}6[/tex]
Final answer:

The work done by force field on a particle moving from one point to another in space is calculated using the concept of dot-product. The force field is represented as a function and the movement of the particle is treated as a path. By integrating the dot product of the force field and the derivative of path over the interval, we get the work done.

Explanation:

To calculate the work done by force field on a particle, you need to apply the concept of dot product in vector calculus. The force field is defined as f(x, y, z) = x − y², y - z², z - x² and the movement of the particle is from (0, 0, 1) to (3, 1, 0). We treat this movement as a line segment in the 3-dimensional space.

The work done by the force field on the particle is calculated as W = F . dr = ∫ F(r(t)) . r'(t) dt from t1 to t2. In this case, the force field F is f(x, y, z) and the line segment can be treated as a path r(t) = t * (3, 1, 0) + (1 - t) * (0, 0, 1) and t varies from 0 to 1. Hence, r'(t) = (3, 1, 0) - (0, 0, 1).

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Expression for the following phrase,"an hourly wageof $13.50 plus $75 bounes

Answers

Earnings (total) = $75 (bonus) + wt, where w are the hourly wages (a unit rate) and t represents the number of hours worke.

Example:  John works 17 hours at $8.90 per hour.

John's wages will be $75 + ($8.90 / hour) (17 hours) = $75 + $151.30.


Christopher made 3 1/4 dozen cupcakes. He added vanilla icing to 1/3 of the cupcakes and added chocolate icing to the rest. How many cupcakes, in dozens, have chocolate icing?

Answers

1 dozen = 12

First you would multiply.

3.25 x 12 = 39 cupcakes total
1/3 x 12 = 4 cupcakes with vanilla icing

Then you subtract.

39 - 4 = 35 cupcakes with chocolate icing

Then to get the answer back in to terms of dozens, divide by 12.

35/12 = 2 11/12

Hope this helped
a dozen is 12 so 3 and 1/4 dozen would be 39 cupcakes
1/3 of 39 is 13 
39 - 13 is 26 
so, 26 cupcakes would have chocolate icing which would be 2 1/6 dozen 

A model for my number has 2 hundreds blocks no tens blocks and 3 ones blocks

Answers

2 hundreds + 0 tens + 3 ones
200 + 0 + 3
203

Sample of 3 items is selected at random from a box containing 20 items of which 4 aredefective. find the expected number of defective items in the sample.

Answers

That's 54 I think. 20x3=60-4=54

Need help with problem, been stuck on it for a while

Answers

well, if you look at the picture, the "radius" is 1/4, so r = 1/4.

[tex]\bf \textit{diameter of a circle}\\\\ d= 2r\qquad \boxed{r=\frac{1}{4}}\implies d=2\cdot \cfrac{1}{4}\implies d=\cfrac{1}{2}\\\\ -------------------------------\\\\ \textit{circumference of a circle}\\\\ C=2\pi r\qquad \boxed{r=\frac{1}{4}~,~\pi =\cfrac{22}{7}}\implies C=2\left( \frac{22}{7} \right)\left( \frac{1}{4} \right) \\\\\\ C=\cfrac{2\cdot 22\cdot 1}{7\cdot 4}\implies C=\cfrac{11}{7}\\\\ -------------------------------\\\\[/tex]

[tex]\bf \textit{area of a circle}\\\\ A=\pi r^2\qquad \boxed{r=\frac{1}{4}~,~\pi =\cfrac{22}{7}}\implies A=\left( \frac{22}{7} \right)\left( \frac{1}{4} \right)^2 \\\\\\ A=\cfrac{22}{7}\cdot \cfrac{1^2}{4^2}\implies A=\cfrac{22}{7}\cdot \cfrac{1}{16}\implies A=\cfrac{11}{56}[/tex]

The nurse develops a plan to prevent atelectasis in a postsurgical client. which intervention will be effective?

Answers

Final answer:

Using incentive spirometry is an effective intervention to prevent atelectasis in a postsurgical client.

Explanation:

To prevent atelectasis in a postsurgical client, the nurse can implement the following intervention:

Incentive spirometry: This technique involves deep breathing exercises using a device called an incentive spirometer. It helps to expand the lungs, improve lung volumes, and prevent atelectasis.

Using the incentive spirometer, the client is instructed to exhale normally, place their lips around the mouthpiece, and take a slow, deep breath. They should hold the breath for a few seconds before exhaling and repeating the process multiple times throughout the day.

This intervention is effective because it encourages deep breathing and lung expansion, preventing the collapse of alveoli in the lungs and promoting better gas exchange.

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Final answer:

To prevent atelectasis in a postsurgical client, the nurse can implement interventions such as deep breathing exercises, mobilization and ambulation, and pain medication.

Explanation:

To prevent atelectasis in a postsurgical client, the nurse can implement several interventions:

Encouraging deep breathing exercises to expand the lungs.Assisting with mobilization and ambulation to improve lung expansion.Administering pain medication to ensure the client can take deep breaths without discomfort.

These interventions help prevent the collapse of alveoli and promote proper lung function after surgery.

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What is the equation of the horizontal line through (-7,-3)

Answers

The equation of a horizontal line is y = c and in this case, y = -3

Josie has $47 left on her checking account. If she writes a check for $55, what ill josie's balance be?

Answers

Well technically the check will not go through because she does not have a balance greater than or equal to $55, but if you need an answer it would be $47-$55= $-8. 

Answer:

Step-by-step explanation:

Josie's balance would be -8 dollars.

47-55=-8

Is 124 a prime number or not explain why (u can do division to)

Answers

it is not a prime number 'cause 124 can be divided by 2,4 which makes 124 a composite number instead of a prime number

Find all local extrema and saddle points of the function ,

Answers

OROAOROAOzsgunawengNjna nuanvbuangre

What is 49.2532 to 1 decimal place

Answers

the second number to the right of the decimal point is 5 so you need to round the 2 up to 3

 so the number becomes 49.3

Bertie is x years old now. Four years ago, Chloe was twice as old as Bertie. Write an expression for Chloe's age now.

Answers

Bertie is x years old now.
Four years ago, Bertie was x - 4 years old.
Chloe was twice Bertie's age 4 years ago, so 4 years ago,
Chloe was 2(x - 4), and 2(x - 4) = 2x - 8.
Now, Chloe is 4 years older than she was 4 years ago,
so now, Chloe is (2x - 8) + 4 = 2x - 4 years old.

The present Age of Chloe is 2x - 4 years old.

What is Algebra?

A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.

Variables are the name given to these symbols because they lack set values.

In order to determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations.

Given:

Bertie is x years old now.

Four years Ago,

Chloe was twice as old as Bertie.

Bertie Age four years ago = x - 4

So, Chloe  Age four years ago = 2(x- 4) = 2x- 8

Now, Chloe is 4 years older than she was 4 years ago,

Then, Chloe present age is  (2x - 8) + 4 = 2x - 4 years old.

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Can someone help me with these two questions?

Answers

The answer to the first one is '2/3' and the answer to the second one is '8 days'
A & D I believers the right answer

a rectangle is 4 centimeters longer than it is wide. the area is 117 square centimeters. find the dimensions of the rectangle

Answers

Answer:

width: 9 cmlength: 13 cm

Step-by-step explanation:

Integer factors of 117 include ...

... 117 = 1×117 = 3×39 ≈ 9×13

The last factor pair is two factors that differ by 4. We can take these to be the dimensions of the rectangle.

_____

If you want to write an equation for width (w), it might be ...

... w(w+4) = 117

... w² +4w -117 = 0

The factorization problem for this quadratic is the problem of finding two factors of 117 that differ by 4. That is what we have done, above.

If you want to solve this by completing the square, you can to this:

... w² +4w = 117

... w² +4w +4 = 121 . . . . . add 4 = (4/2)² to complete the square

... (w+2)² = 121

... w + 2 = ±√121 = ±11 . . . . take the square root

... w = -2 ± 11 . . . . . we're only interested in the positive solution

... w = 9, then w+4 = 13 and the dimensions are 9 cm by 13 cm.

Is the converse of the following conditional true?
If b≤2, then b≥2.
yes
or
no



Answers

Heck Noooooo lol. That sign means its Greater or equil too. facing opposite ways means a total difference.
nooooooooooooooooooooo
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