Which of the follow is NOT equivalent to -9-8
A. -9+-8
B. -8+-9
C. -17
D. -8-9
A pro shop in a bowling center decreases the price of a urethane bowling ball by 22% to a sale price of $88.14. What is the former price
Tammy's take-home pay is $800 a month. She spends 7% of her take-home pay on her cell phone bill. How much is Tammy's monthly cell phone bill? A. $76 B. $69 C. $56 D. $109
Answer:56
Step-by-step explanation:
What two consecutive whole numbers that square root of 86 lies between
sqrt(86) = 9.273
which is between 9 & 10
Find the minimum length of u × v when u = 5 j and v is a position vector of length 4 in the xy-plane.
3 divided by what equals 5
The bird house in your friend's yard casts a shadow that is 14 feet long. Your friend is 5 feet tall and casts a shadow that is 3.5 feet long. What is the height of the bird house?
a sporting good store sells golf balls and boxes each box has 4 compartments of golf balls each compartment has three golf balls the store sold 37 boxes on Friday and 42 boxes on Saturday how many golf balls did the store sell in all
The store sold a total of 948 balls on Saturday and Friday.
Given that,
A sporting good store sells golf balls and boxes each box has 4 compartments of golf balls each compartment has three golf balls the store sold 37 boxes on Friday and 42 boxes on Saturday how many golf balls did the store sell is to be detrmined.
In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,
Here,
A sporting goods store sells golf balls and boxes each box has 4 compartments of golf balls each compartment has three golf balls
Implies
each box has = 3 x 4 = 12 balls
Total box sold = 37 + 42 = 79
Total balls = 79 * 12 = 948
Thus, the store sold a total of 948 balls on Saturday and Friday.
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If x2 - 4 = 45, then x could be equal
During strenuous exercise, an athlete can burn 12 calories per minute on a treadmill and 8.5 calories per minute on an elliptical machine. If an athlete uses both machines and burns 325 calories In a 30- minute workout, how many minutes does the athlete spend on each machine?
The athlete spends 20 minutes on the treadmill and 10 minutes on the elliptical machine. This is determined by setting up and solving a system of linear equations based on the calorie burn rate of each machine and the total calories burned during the workout.
To solve the problem of how many minutes an athlete spends on each machine during their workout, we must set up a system of linear equations. The athlete burns 12 calories per minute on a treadmill and 8.5 calories per minute on an elliptical machine. In a 30-minute workout, the athlete burns a total of 325 calories. Let's denote the time spent on the treadmill as t minutes and the time spent on the elliptical machine as e minutes.
The total time spent on both machines is 30 minutes: t + e = 30The total calories burned is 325: 12t + 8.5e = 325We now have two equations and two unknowns, which can be solved simultaneously.
Subtract the second equation from 12 times the first equation to eliminate eSolve the resulting equation for t to find the number of minutes on the treadmillSubstitute the value of t in the first equation to find the number of minutes on the elliptical machineUsing these steps, we find that:
12t + 12e = 360 (by multiplying the first equation by 12)12t + 8.5e = 325 (second equation as is)Subtracting these equations, we get 3.5e = 35Solving for e, we find that e = 10 (the athlete spends 10 minutes on the elliptical machine)Plugging e = 10 into the first equation, we find that t = 20 (the athlete spends 20 minutes on the treadmill)Therefore, the athlete spends 20 minutes on the treadmill and 10 minutes on the elliptical machine during their 30-minute workout.
the angle of elevation to the top of a 20 story sky scraper is measured to be 2 degrees from a point on the ground 5,280 from the building what is the height of the sky scraper to the nearest hundred foot
Hich equation correctly applies the distributive property?
A. −2.5⋅0.6⋅5.8=−2.5⋅5.8⋅0.6
B. −1.5⋅(6⋅1.25)=(−1.5⋅6)⋅1.25
C. (0.7⋅0.7)+(0.7⋅0.9)+(0.7⋅0.2)=0.7⋅(0.7+0.9+0.2)
D. 70+2.028=(70⋅2)+(70⋅0.02)+(70⋅0.008)
Please answer fast!
Identify a counterexample to disprove n3 ≤ 3n2, where n is a real number.
"The correct counterexample to disprove the inequality [tex]\( n^3 \leq 3n^2 \)[/tex]for real numbers [tex]\( n \)[/tex]is any real number[tex]\( n \)[/tex]greater than 3.
To find a counterexample, we need to show that there exists at least one real number[tex]\( n \)[/tex] for which the inequality [tex]\( n^3 \leq 3n^2 \)[/tex] does not hold. Let's solve the inequality to find the values of[tex]\( n \)[/tex] that satisfy it:
[tex]\[ n^3 \leq 3n^2 \][/tex]
[tex]\[ n^3 - 3n^2 \leq 0 \][/tex]
[tex]\[ n^2(n - 3) \leq 0 \][/tex]
The critical points of this inequality are [tex]\( n = 0 \) and \( n = 3 \)[/tex]. We can divide the real number line into three intervals:[tex]\( n < 0 \), \( 0 \leq n \leq 3 \)[/tex], and[tex]\( n > 3 \).[/tex]Let's test each interval:
1. For[tex]\( n < 0 \), \( n^2 \)[/tex] is positive, but [tex]\( n - 3 \)[/tex] is negative, so the product [tex]\( n^2(n - 3) \)[/tex]is negative, and the inequality holds.
2. For [tex]\( 0 \leq n \leq 3 \)[/tex], both [tex]\( n^2 \) and \( n - 3 \)[/tex] are non-negative, so the product [tex]\( n^2(n - 3) \)[/tex]is non-positive, and the inequality holds.
3. For [tex]\( n > 3 \)[/tex], both [tex]\( n^2 \)[/tex] and [tex]\( n - 3 \)[/tex] are positive, so the product[tex]\( n^2(n - 3) \)[/tex] is positive, and the inequality does not hold.
Therefore, any real number [tex]\( n \)[/tex] greater than 3 will serve as a counterexample to the inequality[tex]\( n^3 \leq 3n^2 \)[/tex]. For instance, if we take [tex]\( n = 4 \),[/tex] we get:
[tex]\[ 4^3 \leq 3 \cdot 4^2 \][/tex]
[tex]\[ 64 \leq 48 \][/tex]
This statement is false, as 64 is not less than or equal to 48. Thus, \( n = 4 \)[tex]\( n = 4 \)[/tex] is a valid counterexample."
What value of x makes the equation below true?
6x - 9 = 39
A. 13
B. 5
C. 8
D. 24
A map has a scale of 1 inch to 15 miles . If 2 cities are 3.4 inches apart on the map , what is the actual distance between the 2 cities ?
Factor the polynomial. x2 - 6x + 9 A) (x - 9)(x - 1) B) (x - 3)(x + 3) C) (x + 9)(x + 1) D) (x - 3)(x - 3)
A keycode must contain 2 letters and 3 numbers. The letters may be any letter of the alphabet. The numbers should be any number from 0 to 9. How many different keycode combinations are there?
Answer:
There is 676,000 combinations
Step-by-step explanation:
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What is the future value of $1400 saved at i=11.41%, compounded annually in 1 year?
What is the LCM of 4,8,14?
Answer:
The LCM of 4, 8, and 14 = 56
Step-by-step explanation:
Find and list multiples of each number until the first common multiple is found. This is the lowest common multiple.
Multiples of 4:
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, (56), 60, 64
Multiples of 8:
8, 16, 24, 32, 40, 48, (56), 64, 72
Multiples of 14:
14, 28, 42, (56), 70, 84
Hope this helps!
Which expression is equivalent to 18a+12b+9a+24b ?
Answer Choices
* 63ab
* 30a+33b
* 27a+36b
* 21a+42b
The correct expression is equivalent to 18a+12b+9a+24b is,
⇒ 27a + 36b
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
The expression is,
⇒ 18a + 12b + 9a + 24b
Now, We can simplify as;
⇒ 18a + 12b + 9a + 24b
⇒ 18a + 9a + 12b + 24b
⇒ 27a + 36b
Thus, The correct expression is equivalent to 18a+12b+9a+24b is,
⇒ 27a + 36b
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Solve the equation. What does “m” equal?
what 3 digits are in the units period?
Expanded form of 6985062 using exponential notation
Are the functions linear or nonlinear? Column A Column B 1. 72 = x3 + y 2. y + 1 = 5(x – 9) 3. 7y + 2x = 12 4. 4y = 24 A. linear B. nonlinear
Answer:
72=x3+y: nonlinear
y+1=5(x−9): linear
7y + 2x = 12: linear
4y = 24: linear
I know because I took the k12 test.
5836197 to the nearest hundred
Under what conditions can the t-distribution be correctly employed to test the difference between two population means?
Final answer:
The t-distribution is employed when testing the difference between two population means if the data come from a simple random sample and the population is approximately normally distributed or the sample size is large. It is also used when the population standard deviation is unknown, and a one-tailed or two-tailed test is conducted based on expectations about the direction of the mean difference.
Explanation:
Conditions for Using the t-Distribution to Test Differences Between Two Means
The t-distribution is appropriately used to test the difference between two population means under specific conditions. Firstly, your data must be obtained from a simple random sample. Secondly, the sample should come from a population that is approximately normally distributed, or the sample size should be large enough to compensate for non-normality. This is because the t-test relies on the assumption of normality, especially with smaller sample sizes (<30). If the sample size is small and the population distribution is unknown or not normal, the use of a t-test may not be appropriate without transformation or other techniques to meet the assumptions.
It is also essential to use the t-distribution when the population standard deviation is unknown, and as a result, the sample standard deviation is used as an estimate. Moreover, the t-test can adapt to various research scenarios, considering that it is designed to handle different levels of variability and data types. This flexibility makes the t-distribution a key tool for many scientific studies where the variance is not known ahead of time.
In hypothesis testing, the direction of the mean difference is considered, such as when conducting a one-tailed test or a two-tailed test. A one-tailed test is conducted when an expectation about the direction of the difference exists, while a two-tailed test is used to determine if there is any statistically significant difference between group means without a predefined direction. Lastly, when employing the t-test for paired data, the assumption is that the population from which the differences are drawn is normally distributed.
Divide (67 gallons 2 quarts)÷3
A) 21 gallons 1 quart
B) 22 gallons 3 quart
C) 21 gallons 3 quart
D) 22 gallons 1 quart
E) NONE
E) None is correct.
To solve this problem, we need to divide the total volume of 67 gallons 2 quarts by 3.
Convert the total volume to only quarts since both gallons and quarts are involved in the problem. There are 4 quarts in a gallon.
67 gallons = 67 * 4 quarts = 268 quarts
Add the additional 2 quarts: 268 quarts + 2 quarts = 270 quarts
Divide the total quarts by 3 to find the result:
270 quarts ÷ 3 = 90 quarts
Convert the result back to gallons and quarts. Since there are 4 quarts in a gallon:
90 quarts ÷ 4 = 22 gallons with a remainder of 2 quarts
suppose you have 192 marbles in groups of 15 marbles each. find the number of groups of marbles that you have. write the quotient with the remainder written as a fraction. explain what the fraction part of your answer means
cory earns 52.50 in 7 hours. find the unit rate
divide the two:
52.50 / 7 = 7.50 per hour
A grey squirrel population was introduced in a certain county of Great Britain 35 years ago. Biologists observe that the population doubles every 7 years, and now the population is 60,000.
(a) What was the initial size of the squirrel population?
To find the initial size of the grey squirrel population, we used the exponential growth formula. After calculating, we determined that the initial population size was 1,875 squirrels.
Explanation:The student asked how to find the initial size of a grey squirrel population that doubles every 7 years and now has a population of 60,000 after 35 years.
To calculate the initial population size, we'll use the formula for exponential growth: P(t) = P0 × (2t/T), where P(t) is the population at time t, P0 is the initial population size, 2 is the base because the population doubles, t is the number of years, and T is the time it takes for the population to double.
The problem gives us 35 years (t) and a doubling time (T) of 7 years. Plugging these into the equation, we have 60,000 = P0 × (235/7). Simplifying, we get 60,000 = P0 × 25 or 60,000 = P0 × 32. Dividing both sides by 32, we find the initial population size is 1,875 squirrels.
Thus, the initial size of the grey squirrel population was 1,875.