Write the domain of the function given in the graph in set builder notation.
a. {x|x<=10}
b. {x|x<=0}
c. {x|x>10}
d. {x|x>0}
I can't get a picture of the graph so I'll try to explain. Y axis 0-5, going up by 1's, x axis 0-50, going up by 5's. Line starts at 10 on the x axis, goes up at an angle and stops at 40.
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Related Questions
Mindy is 36 years old. Mindy’s age is 3 years older than two times Jake’s age. Let j represent Jake’s age.
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(36 - 3)/2 = jakes age
33/2 = jakes age
jakes age = 16 1/2
hope this helps
at 3:00a.m,the temperature is -5°F. Between 3:00a.m. and 6:00 a.m.,the temperature drops by 12°F. Between 6:00a.m. and 9:00a.m., the temperature rises by 4°F. What is the temperature at 9:00a.m.?
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Hope this helps!
What will it cost to tile a kitchen floor that is 12 feet wide by 20 feet long if the tile cost $8.91 per square yard?
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Answer:
Step-by-step explanation:
What you have todo is to multiply the length by the width
Which is 20×12 = 240
Then multiply 240 by 8.91
This should give you $2,138.4
Joe practiced his trumpet 3/4 hour on Monday and 7/12 hour on Tuesday. How long did he practice all together
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45+35= 80minues if 60 minutes is an hour then its 1 hour and 20 minutes.
3/4 = 9/12
9/12 + 7/12 = 16/12 = 1 4/12 = 1 1/3 hours
How to factor: 15x^2y^3 + 10xy^2z
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Deangelo has $7 worth of dimes and quarters in a jar. He has 7 more quarters than dimes.
How many of each coin does he have?
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q=number of quarters
let's count everything in cents
dimes are worth 10 cents
quarters are worth 25 cents
10d+25q=700
divide both sides by 5
2d+5q=140
he has 7 more quarters than dimes
q=7+d
subsitute 7+d for q in other equation
2d+5q=140
2d+5(7+d)=140
2d+35+5d=140
7d+35=140
minus 35 both sides
7d=105
divide both sides by 7
d=15
sub back
q=7+d
q=7+15
q=22
22 quarters and 15 dimes
Hope this helps
Which equation can be used to solve this problem?
Molly bought 6 packs of trading cards. Each pack cost $3. She also bought 1 pack of gum. It cost $2. How much did Molly spend altogether?
A.
6 ÷ 2 × 3 = x
B.
6 + 3 × 2 = x
C.
6 × 3 ÷ 2 = x
D.
6 × 3 + 2 = x
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solve this equation 3\5(x-10)=18-4x-1
Simplify using distributive property. Which number can be distributed across two terms inside parentheses?
Answer choices:
-10
3\5
x
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3/5 is the number which can be distributed across two terms inside parentheses
What is Equation?Two or more expressions with an Equal sign is called as Equation.
The given equation is 3/5 (x-10) = 18-4x-1
According to the distributive property, multiplying the sum of two or more addends by a number produces the same result as when each addend is multiplied individually by the number and the products are added together.
To solve the above equation we have to distribute 3/5 on LHS
3/5x-30/5 = 18-4x-1
3/5x-6 = 17-4x
Hence, 3/5 is the number which can be distributed across two terms inside parentheses
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Shilo is trying to compute the value of 27 + 55 + 13. She adds 27 + 13 to get 40, and then adds on 55. Which of the following properties is Shilo using? commutative distributive associative identity
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the answer is commutative. hope this helps!
Shilo is using commutative and associative
What is commutative property?"For any numbers 'a' and 'b', a + b = b + a"
What is distributive property?"For any real numbers 'a', 'b' and 'c',
a × (b + c) = a × b + a × c"
What is associative property?For any numbers 'a', 'b' and 'c',
(a + b) + c = a + (b + c)
What is identity?For any real number a,
the additive identity is a + 0 = 0 + a = a
For given question,
Shilo is trying to compute the value of 27 + 55 + 13.
She adds 27 + 13 to get 40, and then adds on 55.
⇒ 27 + 55 + 13
= 27 + 13 + 55 ...........(commutative property, 55 + 13 = 13 + 55)
= (27 + 13) + 55 ...........(associative property)
= 40 + 55
= 95
Therefore, Shilo is using commutative and associative property.
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Two cars start at the same time, but travel in opposite directions. one car's average speed is 20 miles per hour (mph). at the end of 4 hours, the two cars are 320 miles apart. find the average speed in mph of the other car. (enter an exact number.)
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Final answer:
The question asks for the average speed of the second car given that two cars travel in opposite directions and the total distance between them after 4 hours. By calculating the distance one car traveled at 20 mph after 4 hours, it's possible to determine that the other car must have traveled at an average speed of 60 mph to cover the remaining distance.
Explanation:
The student's question is a problem involving distance, speed, and time, which are fundamental concepts in mathematics. To find the average speed of the other car, we can use the formula distance = speed times time. Since the two cars travel in opposite directions, their distances add up to the total separation distance after a certain time.
In this case, one car travels at 20 mph, so in 4 hours it covers 20 mph times 4 h = 80 miles. The total distance between them after 4 hours is 320 miles. Therefore, the distance covered by the second car is 320 miles - 80 miles = 240 miles. To find the average speed of the second car, we divide the distance it covered by the time it traveled which is 240 miles / 4 h = 60 mph. Hence, the average speed of the other car is 60 mph.
The value for ss can never be less than zero.
a. True
b. False
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For example, S= -3
-3(-3)= 9
Another example, S= 3
3(3)=9
Therefore, it is true that the value of ss can never be less than a zero.
Hopefully, this helps!
Please explain the answer.
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If the measure of Angle AXC=8x-7 and Angle AXB = 3x+10 find the measure of ANGLE AXC
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To find the measure of ANGLE AXC, we assume Angle AXB is supplementary to Angle AXC. Solving the supplementary angle equation with the given expressions, we find x = 16. Substituting x back into the expression for Angle AXC, we determine its measure to be 121 degrees.
The question asks to find the measure of ANGLE AXC given that the measure of Angle AXC is represented by the expression 8x-7 and Angle AXB is represented by the expression 3x+10. Without additional context, it is not clear whether Angle AXB is related to Angle AXC in a way that would allow us to solve for x. However, if we assume Angle AXC and Angle AXB are supplementary angles (which sum to 180 degrees), we could set up the equation 8x - 7 + 3x + 10 = 180. If we solve this equation, we get:
Combine like terms: 8x + 3x - 7 + 10 = 180Simplify: 11x + 3 = 180Subtract 3 from both sides: 11x = 177Divide by 11: x = 16Once we have found that x = 16, we can substitute it back into the expression for Angle AXC:
AXC = 8x - 7 = 8(16) - 7Calculate the value: AXC = 128 - 7Simplify: AXC = 121 degreesTherefore, the measure of ANGLE AXC is 121 degrees.
what is the name of the line that the function approaches?
a. y-axis
b. there is no such line
c. the unknown line
d. asymptote
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In the attached graph, the function has two asymptotes, one horizontal (the x-axis) and one vertical (the line x = 2).
Find the perimeter of △ABC with vertices A(−5, −5), B(3, −5), and C(−5, 1).
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so notice, the sides AB and AC you can pretty much count them off the grid.
now, to get the CB side.
[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) C&({{ -5}}\quad ,&{{ 1}})\quad % (c,d) B&({{ 3}}\quad ,&{{ -5}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ CB=\sqrt{[3-(-5)]^2+[-5-1]^2}\implies CB=\sqrt{(3+5)^2+(-5-1)^2} \\\\\\ CB=\sqrt{8^2+(-6)^2}\implies CB=\sqrt{100}\implies CB=10[/tex]
sum all three sides up, and that's the perimeter of the triangle.
The ratio of male students to female students is 4 to 5. if there is a total of 6192 students, find the number of male syudents to the number of female students
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16,200/12=1350 value of each element.
5+1350=6,750 males.
7*1,350=9,450 females.
Proofs:
6,750+9,450=16,200
5/7=6,750/9,450
5*9,450=7*6,750
47,250=47,250
A student must have an average (the mean) on five tests that is greater than or equal to 80% but less than 90% to receive a final grade of
b. devon's grades on the first four tests were 92%, 82%, 88%, and 92%. what range of grades on the fifth test would give him a b in the course?
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The requried, Devon needs to score between 46% and 95% on the fifth test to receive a final grade of a B in the course.
To find the range of grades Devon needs on the fifth test to receive a final grade of a B (between 80% and 90% inclusive), we need to consider the average of all five tests.
Let's denote the grade on the fifth test as "x" (in percentage).
The average of the five tests will be:
Average = (92% + 82% + 88% + 92% + x) / 5
To achieve a final grade of a B, the average must be greater than or equal to 80% but less than 90%:
80% ≤ Average < 90%
Now, substitute the given grades and the variable "x" into the average equation:
(92% + 82% + 88% + 92% + x) / 5 ≥ 80%
(92 + 82 + 88 + 92 + x) / 5 ≥ 80
(354 + x) / 5 ≥ 80
354 + x ≥ 400
x ≥ 400 - 354
x ≥ 46
Now, for the upper limit:
(92 + 82 + 88 + 92 + x) / 5 < 90
(354 + x) / 5 < 90
354 + x < 450
x < 450 - 354
x < 96
So, Devon needs to score between 46% and 95% on the fifth test to receive a final grade of a B in the course.
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Devon must score between 46% and 91% on his fifth test to achieve a B average in the course.
Explanation:To determine the range of grades on the fifth test that would give Devon a final grade of B, we need to calculate the average of the five test scores. For an average to fall between 80% and 90%, the total sum of the five test grades must be between 400% and 449%, since 5 tests × 80% = 400% and 5 tests × 89% (just below 90%) = 445%. Devon's current grades add up to 92% + 82% + 88% + 92% = 354%. Therefore, to achieve a B, his fifth test score needs to be between 400% - 354% = 46% and 445% - 354% = 91%.
What is the rate of change of the volume of a ball with respect to the radius when the radius is?
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dV/dr=4/3*pi*d(r^3)/dr =4/3*pi*(3*r^2)=4*pi*r^2
Marcus has $40 in his pocket. Joseph has twice as much as Marcus; Jenna has half as much as Marcus, and Sam has 1/3 as much as Marcus. Order the individuals based on the amount of money they have from least to greatest
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Suppose M is the midpoint of FG. Use the given info. to find the missing measure or value. FM=3X-4, MG=5X-26, FG=?
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surely you know how much that is.
Answer:FG=29+29
Step-by-step explanation:
help me pls I'm stuck......
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subtracting the smaller number from the larger number
ex. 1+ -5 becomes 5-1 = 4, since the larger number is the negative, the answer is negatives oit is -4
ex2. -5+7 = 7-5 = 2, since the larger number is positive, the answer is positive 2
What is the reason for each step in the solution of the equation? 2x−1=4(x+1)2x−1=4(x+1)
Drag and drop the reasons into the boxes to correctly complete the table.
2x−1=4(x+1)2x−1=4(x+1)-
2x−1=4x+42x−1=4x+4-
2x=4x+52x=4x+5-
−2x=5−2x=5-
x=−52-
Given
Distributive property
Commutative property
Addition or suptraction property of equality
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2x - 1 = 4 (x + 1) ; GIVEN
2x - 1 = 4x + 4 ; Distributive property (as we can see, 4 is multiplied to each of the terms found inside the parentheses)
2x = 4x + 5 : Addition property of equality (both sides of the equation are added with 1)
-2x = 5 : Subtraction property of equality (both sides of the equation are subtracted with 4x)
x = -5/2 : Division Property of equality (both sides are divided by -2)
How to get "4" of 4s to equal 4 using any order of operation
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You can think of this problem in multiple ways. First of all, you can use three 4s to equal zero; then, you add four and the final product will be 4. Any number times zero is always zero. So we subtract 4 from 4 to equal zero. Finally, we add four.
max is four years younger than his sister brenda. the total of their age is 16. write and solve an equation to find their ages.
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X - 4 is Max
X + (X - 4) = 16
2X -4 = 16
2X = 20
X = 10
This means that Max is 6 and Brenda is 10
A cube has eight congruent faces.
true
false
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2/11 x 5/7 = ? PLEASE ALSO EXPLAIN THAAAANKS
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2/11 * 5/7
When we do a multiplications of two fractions, we should keep in mind that we are multiplying the numerators (2 and 5) and the denominators (11 and 7).
Firstly, we check if there are numbers to simplify by cross-multipling.
In this case, we don't have to simplify.
So 2*5 = 10
11*7 = 77
Final answer 10/77
The question is above
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For 13, we can solve for y in the first equation by subtracting 14 from both sides and therefore getting 2x-14=y. For the next one, we can subtract 4x from both sides to get 10-4x=2y. Dividing both sides by 2, we get 10-2x=y. Since for the equations to be parallel they must be the same and for perpendicular they must be -1/(slope), this fits neither.
Using those two explanations, I implore you to solve the other two on your own!
X and y are supplementary angles y measures 97
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A wire is first bent into the shape of a rectangle with width 5in and length 13in. Then the wire is unbent and reshaped into a triangle. If each side of the triangle has equal length, what is this length?
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so length of each side of the triangle would be 36/3 = 12 ins.
Length of each side of a triangle with equal measurements is equals to [tex]12in[/tex].
What is perimeter?" Perimeter is defined as the total length around the boundary of any two dimensional geomertic shape."
Formula used
Perimeter of a rectangle [tex]= 2 ( L + W)[/tex]
[tex]L =[/tex] length of the rectangle
[tex]W =[/tex] Width of the rectangle
Perimeter of a triangle with equal length [tex]= 3s[/tex]
[tex]s =[/tex] side length of a triangle
According to the question,
Given,
Length of a rectangle [tex]'L'= 13 in[/tex]
Width of a rectangle [tex]'W' = 5 in[/tex]
Substitute the value in the formula we get,
Perimeter of a rectangle [tex]= 2( 13 + 5)[/tex]
[tex]= 36 in[/tex]
Substitute the value in the perimeter of a triangle with equal side length,
[tex]3s = 36 in\\\\\implies s = \frac{36}{3} \\\\\implies s = 12in[/tex]
Hence, Length of each side of a triangle with equal measurements is equals to [tex]12in[/tex].
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For the above table:
x . 0.5 Y. 3 x.2 ,y 6, x 2, y 9 , x 2.5 y 12 , x 3, y 15
a. State the domain.
b. State the range.
c. Is this relation a function? Why or why not?
(2 points)
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a) domain are the x's
so 0.5, 2, 2,2.5, 3
b) range is the y's so:
3, 6, 9, 12,15
c) it is not a function, since there are 2 x's that equal 2 but the 2 y's that go with them are different numbers (2,6) & (2,9)