Answers
1) Lithium and fluorine:
Ionic charges: lithium cation Li⁺ and fluorine anion F⁻.
Chemical formula LiF.
In ionic salt lithium fluoride (LiF), fluorine has electronegativity approximately χ = 4 and lithium χ = 1 (Δχ = 4 - 1; Δχ = 3).
Fluorine attracts electron and it has negative charge and lithium has positive charge.
2) Beryllium and oxygen:
Ionic charges cation Be²⁺ and anion O²⁻.
Chemical formula is BeO.
Beryllium is metal from group 2 and oxygen is nonmetal from group 16.
Electron configuration of beryllium: ₄Be: 1s² 2s², it has two valence electrons in 2s orbital.
Beryllium lose two electrons and to gain electron configuration as noble gas helium (He).
Electron configuration of oxygen atom: ₈O 1s² 2s² 2p⁴.
Oxygen gain two valence electron to form anion with stable electron configuration as noble gas neon (atomic number 10).
3) Magnesium and fluorine:
Ionic charges cation Mg²⁺ and anion F⁻.
Chemical formula is MgF₂.
Magnesium fluoride (MgF₂) is salt, ionic compound.
Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).
Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.
Fluorine (F) is nonmetal with greatest electronegativity, which means it easily gain electrons.
Fluorine has atomic number 9, which means it has 9 protons and 9 electrons. It gain one electron to form fluorine anion (F⁻) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.
4) Aluminum and chlorine:
Ionic charges cation Al³⁺ and anion Cl⁻.
Chemical formula is AlCl₃.
The right name for AlCl₃ is aluminium chloride.
Aluminium chloride is a salt with ionic bonds.
Aluminium (metal from group 13) has oxidation number +3 and chlorine (nonmetal from group 17) has oxidation number -1, chemical compound has neutral charge (+3 + 3 · (-1) = 0).
5) Beryllium and nitrogen:
Ionic charges cation Be²⁺ and anion N³⁻.
Chemical formula is Be₃N₂.
Atomic number of nitrogen is 7, it has 7 protons and 7 electrons.
Electron configuration of nitrogen atom: ₇N 1s² 2s² 2p³.
Nitrogen gain three electrons to form anion with stable electron configuration as noble gas neon (atomic number 10).
The ionic charges and chemical formulas are Li⁺ and F⁻ making lithium fluoride,Be²⁺and O²⁻giving BeO,Mg²⁺ and F⁻ forming MgF₂,Al³⁺and Cl⁻ forming AlCl₃,Be²⁺and N³⁻ forming Be₃N₂.
In LiF ,lithium is Li⁺ and fluorine is F⁻,giving chemical formula LiF.
In BeO beryllium is Be²⁺ and oxygen is O²⁻making chemical formula BeO. In MgF₂ magnesium is Mg²⁺and fluorine is F⁻giving chemical formula MgF₂ .
In AlCl₃ aluminium is Al³⁺while chlorine is Cl⁻ thus AlCl₃ is formed.In Be₃N₂,beryllium is Be²⁺and nitrogen is N³⁻ thus chemical formula is Be₃N₂.
Thus, the name of chemical formula along with ionic charges is given in the attached image.
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Related Questions
What is the simplest formula of a solid containing a, b, and c atoms in a cubic lattice in which the a atoms occupy the corners, the b atoms the body-center position, and the c atoms the faces of the unit cell?
a. a4bc3
b. abc6
c. abc3
d. abc
e. a8bc6?
Answers
Answer:
c. abc₃
Step-by-step explanation:
1. a atoms
There are eight corners, each containing an a atom.
No. of a atoms = 8 × ⅛
No. of a atoms = 1
=====
2. b atoms
There is one central b atom.
=====
3. c atoms
There are six faces, each containing a c atom.
No. of a atoms = 6 × ½
No. of c atoms = 3
=====
4. Formula
The simplest formula is abc₃.
The simplest formula of a solid containing a, b, and c atoms in a cubic lattice is: c. [tex]abc_3[/tex]
A unit cell can be defined as a repetitive unit of solid structures with equivalent edge points and opposite faces.
In crystal lattices, there are three (3) main types of unit cell and these include:
Body-centered cubic (BCC)Face-centered cubic (FCC)Simple cubicA simple cubic unit cell is the simplest repetitive unit cell because the lattice points are only at the corners.
To calculate the simplest formula of a solid containing a, b, and c atoms in a cubic lattice:
For a atoms:
[tex]a = 8 \times \frac{1}{8}[/tex]
a = 1 atom
For b atoms:
[tex]b = 1 \times 1[/tex]
b = 1 atom
For c atoms:
[tex]c = 6 \times \frac{1}{2}[/tex]
c = 3 atoms
Simplest formula = [tex]abc_3[/tex]
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Copper has been used in electrical wiring for two hundred years. Identify which molecular level property does not contribute to copper's usefulness a material for wiring.
A) high ductility
B) high malleability
C) high conductivity
D) high crystallinity
Answers
Answer:D
Explanation:
Copper is considered as a transition metal on the periodic table. It is highly malleable, shiny and soft. It is often mixed with other metals like tin and zinc to make brass and bronze for electrical wiring. The high crystallinity does not contribute to wiring. The correct option is D.
What is crystallinity?The term crystallinity refers to the degree of structural order and regularity in the molecular arrangements of a material. The degree of crystallinity has a significant influence on material properties like hardness, density, melting point and diffusion.
Copper is a crystalline solid. The solids which have a sharp melting point and definite heat of fusion are called crystalline solids. Electron mobility is the reason why most metals conduct electricity. The electrons can move freely within the metal.
So ductility and conductivity of copper is responsible for it to use in wiring.
Thus the correct option is D.
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