XYZ Corp makes widgets 1% of the widgets are defective XYZ manufacturers 100000 widgets the number of defective widgets is expected to be

ANSWER

Extraneous solution: x=6

Real solution: x=11

EXPLANATION

The given expression is

[tex] \sqrt{x - 2} + 8 = x[/tex]

Add -8 to both sides:

[tex]\sqrt{x - 2} + 8 + - 8= x + - 8[/tex]

[tex] \implies\sqrt{x - 2} = x - 8[/tex]

Square both sides.

[tex]\implies(\sqrt{x - 2} )^{2} =( x - 8)^{2} [/tex]

[tex]x - 2=( x - 8)^{2} [/tex]

We expand the to get

[tex]x - 2 = {x}^{2} - 16x + 64[/tex]

Write in standard quadratic form.

[tex] {x}^{2} - 16x - x + 64 + 2 = 0[/tex]

[tex] {x}^{2} - 17x + 66 = 0[/tex]

Factor to get:

[tex](x - 6)(x - 11) = 0[/tex]

[tex]x = 6 \: or \: \: x = 11[/tex]

We check for extraneous solutions by substituting each value of x into the original equation.

When x=6

[tex]\sqrt{6 - 2} + 8 = 6[/tex]

[tex]\sqrt{4} + 8 =6[/tex]

[tex]2 + 8 = 10 \ne8[/tex]

Hence x=6 is an extraneous solution.

When x=11

[tex]\sqrt{11- 2} + 8 = 11[/tex]

[tex]\sqrt{9} + 8 = 11[/tex]

[tex]3 + 8 = 11[/tex]

This statement is true.

Hence x=11 is the only solution.

Answer:

b. (-1,3)

Step-by-step explanation:

the  image of the point (x ; y)  by symmetry about x-axis is : ( x ;-  y)

so the answer "b" : (-1,3)

Answer:

  sin(2θ) = 0.96

Step-by-step explanation:

In the third quadrant, both sin(θ) and cos(θ) are negative. Then the double-angle trig identity tells us ...

  sin(2θ) = 2·sin(θ)·cos(θ) = -2cos(θ)√(1 -cos(θ)²) . . . . using the negative root

Filling in the given value, we have

  sin(2θ) = -2·(-0.6)(√(1-(-0.6)²) = 2·0.6·0.8 = 0.96

Answer:

A

Step-by-step explanation:

Volume varies directly with the square of the radius, so:

V = k r²

When V = 80, r = 4.

80 = k (4)²

k = 5

V = 5r²

When r = 3:

V = 5 (3)²

V = 45

The flow is 45 L/min.

Answer: The probability that 3 or more belong to the ruling clique is 0.34.

Step-by-step explanation:

Since we have given that

Number of total members = 50

Number of belonging to ruling clique = 10

Number of belonging to second class member = 40

We need to find the probability that 3 or more belong to the ruling clique.

Let X be the number of outcomes belong to ruling clique.

So, it becomes,

P(X≥3)=1-P(X<3)

[tex]P(X\geq 3)=1-P(X=1)-P(X=2)\\\\P(X\geq 3)=1-\dfrac{^{10}C_1\times ^{40}C_5}{^{50}C_6}-\dfrac{^{10}C_2\times ^{40}C_4}{^{50}C_6}\\\\P(X\geq 3)=1-0.41-0.25\\\\P(X\geq 3)=0.34[/tex]

Hence, the probability that 3 or more belong to the ruling clique is 0.34.

The probability of selecting 3 or more members from the ruling clique when choosing 6 members randomly from a club of 50 members (10 in ruling clique, 40 second-class) is 8.56%.

This probability problem can be solved using the concepts of Combinations and Binomial Theorem. You need to determine the number of ways to choose 3, 4, 5, or 6 members from the ruling clique (10 members) and the remaining from the second-class members (40 members). For each case, divide by the total number of ways to choose 6 members from all 50 members to get the probability. Sum up all the probabilities for each case to get the total probability of having 3 or more from the ruling clique.

1. Number of ways of choosing 3 from the ruling clique and 3 from the second class: C(10,3)*C(40,3) = 120*9880 = 1,185,600 ways

2. Number of ways of choosing 4 from the ruling clique and 2 from the second class: C(10,4)*C(40,2) = 210*780 = 163,800 ways

3. Number of ways of choosing 5 from the ruling clique and 1 from the second class: C(10,5)*C(40,1) = 252*40 = 10,080 ways

4. Number of ways of choosing 6 from the ruling clique and 0 from the second class: C(10,6)*C(40,0) = 210*1 = 210 ways

Total ways to choose 3 or more from the ruling clique: 1,185,600 + 163,800 + 10,080 +210 = 1,359,690 ways

From 50 members, the total ways to choose 6: C(50,6) = 15,890,700 ways

The Probability of 3 or more from the ruling clique = 1,359,690 / 15,890,700 = 0.0856 or 8.56%

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The solution to the system of equations is [tex]\(x = -1\) and \(y = 2\)[/tex].

To solve the system of equations:

[tex]\[ \begin{cases} -5x + 2y = 9 \\ 3x + 5y = 7 \end{cases} \][/tex]

We can use either the substitution method or the elimination method. Let's use the elimination method here.

First, let's rewrite the equations in standard form:

Equation 1: [tex]\( -5x + 2y = 9 \)[/tex]

Equation 2: [tex]\( 3x + 5y = 7 \)[/tex]

To eliminate one of the variables, let's multiply Equation 1 by 3 and Equation 2 by 5 to make the coefficients of x the same:

[tex]\[ \begin{cases} -15x + 6y = 27 \\ 15x + 25y = 35 \end{cases} \][/tex]

Now, let's add the two equations:

[tex]\[ (-15x + 6y) + (15x + 25y) = 27 + 35 \]\[ -15x + 6y + 15x + 25y = 62 \]\[ 31y = 62 \][/tex]

Now, let's solve for y:

[tex]\[ y = \frac{62}{31} \][/tex]

y=2

Now that we have found the value of y, let's substitute it back into one of the original equations to find x. Let's use Equation 1:

[tex]\[ -5x + 2(2) = 9 \]\[ -5x + 4 = 9 \]\[ -5x = 9 - 4 \]\[ -5x = 5 \]\[ x = \frac{5}{-5} \][/tex]

[tex]\[ x = -1 \][/tex]

Complete question: Find the solution of the following system of equations

-5x+2y=9

3x+5y=7

\[ x = -\frac{28}{3} \] and \( y = 7 \) are the solutions to the system of equations.

To solve the system of equations:

1. -5 + 2y = 9

2. 3x + 5y = 7

We can start by solving equation 1 for [tex]\( y \):[/tex]

[tex]\[ -5 + 2y = 9 \][/tex]

Add 5 to both sides:

[tex]\[ 2y = 9 + 5 \]\[ 2y = 14 \][/tex]

Divide both sides by 2:

[tex]\[ y = \frac{14}{2} \]\[ y = 7 \][/tex]

Now that we have the value of [tex]\( y \)[/tex], we can substitute it into equation 2 and solve for [tex]\( x \):[/tex]

[tex]\[ 3x + 5(7) = 7 \]\[ 3x + 35 = 7 \][/tex]

Subtract 35 from both sides:

[tex]\[ 3x = 7 - 35 \]\[ 3x = -28 \][/tex]

Divide both sides by 3:

[tex]\[ x = \frac{-28}{3} \][/tex]

So, the solution to the system of equations is [tex]\( x = -\frac{28}{3} \) and \( y = 7 \).[/tex]

Answer: (a) 0.37

Step-by-step explanation:

Given: The speed of cars on a stretch of road is normally distributed with an average 48 miles per hour with a standard deviation of 5.9 miles per hour.

i.e. Mean : [tex]\mu = 48\text{ miles per hour} [/tex]

Standard deviation : [tex]\sigma = 5.9\text{ miles per hour}[/tex]

The formula to calculate z is given by :-

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For the probability that a randomly selected car is violating the speed limit of 50 miles per hour (X≥ 50).

For x= 80

[tex]z=\dfrac{50-48}{5.9}=0.338983050847\approx0.34[/tex]

The P Value =[tex]P(z>0.34)=1-P(z<0.34)=1-0.6330717\approx0.3669283\approx0.37[/tex]

Hence,  the probability that a randomly selected car is violating the speed limit of 50 miles per hour =0.37

Answer:

The point of intersection [tex]P\left(\dfrac{1133}{122},\dfrac{149}{122},\dfrac{699}{122}\right)[/tex]

Step-by-step explanation:

Equation of line:

[tex]x=7+9t[/tex]

[tex]y=3-7t[/tex]

[tex]z=7-5t[/tex]

Equation of plane:

[tex]5x-6y-7z=-1[/tex]

We need to find the point of intersection of line and plane.

Point of intersection: When both line and plane meet at single point.

So, put the value of x, y and z into plane.

[tex]5(7+9t)-6(3-7t)-7(7-5t)=-1[/tex]

[tex]35+45t-18+42t-49+35t=-1[/tex]

[tex]122t=-1+32[/tex]

[tex]t=\dfrac{31}{122}[/tex]

Substitute the value of t into x, y and z

[tex]x=7+9\cdot \dfrac{31}{122}=\dfrac{1133}{122}[/tex]

[tex]y=3-7\cdot \dfrac{31}{122}=\dfrac{149}{122}[/tex]

[tex]z=7-5\cdot \dfrac{31}{122}=\dfrac{699}{122}[/tex]

Point of intersection:

[tex]\left(\dfrac{1133}{122},\dfrac{149}{122},\dfrac{699}{122}\right)[/tex]

Hence, The point of intersection [tex]P\left(\dfrac{1133}{122},\dfrac{149}{122},\dfrac{699}{122}\right)[/tex]

Answer: 0.1093

Step-by-step explanation:

Given: Mean : [tex]\mu=93[/tex]

Standard deviation : [tex]\sigma = 22[/tex]

Sample size : [tex]n=30[/tex]

The formula to calculate z-score is given by :_

[tex]z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]

For x= 97.95, we have

[tex]z=\dfrac{97.95-93}{\dfrac{22}{\sqrt{30}}}\approx1.23[/tex]

The P-value = [tex]P(z>1.23)=1-P(z<1.23)=1-0.8906514=0.1093486\approx0.1093[/tex]

Hence, the  probability that the sample mean would be greater than 97.95 WPM =0.1093

Answer:

  $16,479

Step-by-step explanation:

The table tells you Ed's tax is ...

  14,138.50 + 0.31×(70,000 -62,450) = 16,479 . . . . dollars

The probability that exactly one customer dines on the first floor is:

                     0.26337  

We need to use the binomial theorem to find the probability.

The probability of k success in n experiments is given by:

       [tex]P(X=k)=n_C_k\cdot p^k\cdot (1-p)^{n-k}[/tex]

where p is the probability of success.

Here p=1/3

( It represents the probability of choosing first floor)

k=1 ( since only one customer has to chose first floor)

n=6 since there are a total of 6 customers.

This means that:

[tex]P(X=1)=6_C_1\times (\dfrac{1}{3})^1\times (1-\dfrac{1}{3})^{6-1}\\\\\\P(X=1)=6\times (\dfrac{1}{3})\times (\dfrac{2}{3})^5\\\\\\P(X=1)=0.26337[/tex]

Using the binomial distribution, it is found that there is a 0.2634 = 26.34% probability that exactly one customer dines on the first floor.

----------------

For each customer, there are only two possible outcomes, either they dine on the first floor, or they do not. The probability of a customer dining on the first floor is independent of any other customer, which means that the binomial probability distribution is used to solve this question.

----------------

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of a success on a single trial.

----------------

----------------

The probability that exactly one customer dines on the first floor is P(X = 1), thus:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 1) = C_{6,1}.(0.3333)^{1}.(0.6667)^{5} = 0.2634[/tex]

0.2634 = 26.34% probability that exactly one customer dines on the first floor.

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Answer:

The probability of the sample mean foot length less than 23 cm is 0.120

Step-by-step explanation:

* Lets explain the information in the problem

- The eighth-graders asked to measure the length of their right foot at

  the beginning of the school year, as part of a science project

- The foot length is approximately Normally distributed, with a mean of

 23.4 cm

∴ μ = 23.4 cm

- The standard deviation of 1.7

∴ σ = 1.7 cm

- 25 eighth-graders from this population are randomly selected

∴ n  = 25

- To find the probability of the sample mean foot length less than 23

∴ The sample mean x = 23, find the standard deviation σx

- The rule to find σx is σx = σ/√n

∵ σ = 1.7 and n = 25

∴ σx = 1.7/√25 = 1.7/5 = 0.34

- Now lets find the z-score using the rule z-score = (x - μ)/σx

∵ x = 23 , μ = 23.4 , σx = 0.34

∴ z-score = (23 - 23.4)/0.34 = -1.17647 ≅ -1.18

- Use the table of the normal distribution to find P(x < 23)

- We will search in the raw of -1.1 and look to the column of 0.08

∴ P(X < 23) = 0.119 ≅ 0.120

* The probability of the sample mean foot length less than 23 cm is 0.120

Answer: The mean and the standard error of the distribution of the sample mean are 200 and 2.

Step-by-step explanation:

Given: Sample size : n= 81

Mean of infinite population : [tex]\mu=200[/tex]

We know that the mean of the distribution of the sample mean is same as the mean of the population.

i.e. [tex]\mu_x=\mu=200[/tex]

The standard error of the distribution of the sample mean is given by :-

[tex]S.E.=\dfrac{\sigma}{\sqrt{n}}[/tex]

[tex]\Rightarrow\ S.E.=\dfrac{18}{\sqrt{81}}=\dfrac{18}{9}=2[/tex]

Hence, the mean and the standard error of the distribution of the sample mean are 200 and 2.

The mean of the sample mean distribution for a random sample of size 81 from a population with a mean of 200 and a standard deviation of 18 is 200, and the standard error is 2.

The question is about determining the mean and the standard error of the distribution of the sample mean. According to the Central Limit Theorem, regardless of the distribution of the original population, the distribution of the sample mean tends to form a normal distribution as the sample size increases. In this case, the mean of the sample mean distribution is the same as the population mean, which is 200.

The standard error of the mean is calculated as the population standard deviation divided by the square root of the sample size. So, the standard error in this scenario would be 18/√81 = 2.

Therefore, in a random sample of size 81 taken from an infinite population with a mean of 200 and a standard deviation of 18, the mean of the sample mean distribution is 200, and the standard error is 2.

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Answer:

The volume of the prism is 27√3/2

Step-by-step explanation:

* Lets revise the triangular prism properties

- The triangular prism has five faces

- Two bases and three side faces

- The two bases are triangles

- The three side faces are rectangles

- The rule of its volume is Area of its base × its height

* Lets solve the problem

- The triangular prism has two bases which are equilateral triangles

- The length of each side of the triangular base is 3"

- The height of the prism is 6"

∵ The volume of the prism = area of the base × its height

∵ The base is equilateral triangle of side length 3"

- The area of any equilateral triangle is √3/4 s²

∴ The area of the base of the prism = √3/4 × (3)² = 9√3/4

∵ The length of the height of the prism is 6"

∴ The volume of the prism = 9√3/4 × 6 = 27√3/2

* The volume of the prism is 27√3/2

Let assume that [tex]\sqrt3[/tex] is rational. Therefore we can express it as [tex]\dfrac{a}{b}[/tex] where [tex]a,b\in \mathbb{Z}[/tex] and [tex]\text{gcd}(a,b)=1[/tex].

[tex]\dfrac{a}{b}=\sqrt3\\\dfrac{a^2}{b^2}=3\\a^2=3b^2[/tex]

It means that [tex]3|a^2[/tex] and so also [tex]3|a[/tex].

Therefore [tex]a=3k[/tex] where [tex]k\in\mathbb{Z}[/tex].

[tex](3k)^2=3b^2\\9k^2=3b^2\\b^2=3k^2[/tex]

It means that [tex]3|b^2[/tex] and so also [tex]3|b[/tex].

If both [tex]a[/tex] and [tex]b[/tex] are divisible by 3, then it contradicts our initial assumption that [tex]\text{gcd}(a,b)=1[/tex]. Therefore [tex]\sqrt3[/tex] must be an irrational number.

Final answer:

The problem requires formulating a linear programming model to maximize the profit function Z = 9x + 7y with constraints on machine time for product A and B (2x + 3y ≤ 6 for machine M and 4y ≤ 8 for machine L) and the non-negativity restrictions (x, y ≥ 0).

Explanation:

The linear programming problem can be stated in mathematical terms with an objective function and constraints for a firm making products A and B. The objective is to maximize profit, which is the sum of 9 dollars per unit of product A and 7 dollars per unit of product B. Let the number of products A and B produced be represented by variables x and y, respectively.

The objective function to maximize is Z = 9x + 7y.

Constraints:

Answer:

  b = 1.098

Step-by-step explanation:

Each year, the GDP is 9.8% higher than the year before, so the multiplier each year is 1 + 9.8% = 1.098. This is the value of b.

  b = 1.098

Answer:

3/5

Step-by-step explanation:

Total tossed : 30

# of times landed on tails : 18

Experimental probability of tails = 18/30 = 3/5

Answer:

218.75 miles / 12.5 hours

437.5 miles / 25 hours

656.25 miles / 37.5 hours

Step-by-step explanation:

35 miles / 2 hours = 87.5 miles / 5 hours

This is the  ratio of 2.5. So, the other proportions are

87.5 x 2.5 miles / 5 x 2.5 hours = 218.75 miles / 12.5 hours

87.5 x 5 miles / 5 x 5 hours = 437.5 miles / 25 hours

87.5 x 7.5 miles / 5 x 7.5 hours = 656.25 miles / 37.5 hours

Answer: the answer to this question is B

Step-by-step explanation: Hope This Helps

Formula to find the margin of error :

[tex]E=z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex] , where n= sample size  , [tex]\hat{p}[/tex] is the sample proportion and z*= critical z-value.

Let p be the proportion of 19-year-olds had a driver’s license.

A) As per given , In 1983

[tex]\hat{p}=0.87[/tex]

n=  1200

Critical value for 95% confidence level is 1.96 (By z-table)

So ,Margin of error : [tex]E=(1.96)\sqrt{\dfrac{0.87(1-0.87)}{1200}}\approx0.019[/tex]

Interval : [tex](\hat{p}-E , \ \hat{p}+E)=(0.87-0.019 ,\ 0.87+0.019)[/tex]

[tex]=(0.851,\ 0.889)[/tex]

B) In 2008 ,

[tex]\hat{p}=0.75[/tex]

Margin of error :    [tex]E=(1.96)\sqrt{\dfrac{0.75(1-0.75)}{1200}}\approx0.0245[/tex]

Interval : [tex](\hat{p}-E, \hat{p}+E)=(0.75-0.0245,\ 0.75+0.0245)[/tex]

[tex]=(0.7255,\ 0.7745)[/tex]

c. The margin of error is not the same in parts (a) and (b) because the sample proportion of 19-year-olds had a driver’s license are not same in both parts.

Answer:

Step-by-step explanation:

The 2 numbers that are not in the domain of the function are the 2 numbers that cause the denominator of the function to equal 0.  In order to find those 2 numbers, we have to factor the quadratic that is in the denominator. When you factor, you get x = 2.79 and x = -1.79

Those are the values of x that cause the denominator to equal 0, which of course is NEVER allowed in math!

Answer:

5 units

Step-by-step explanation:

This is a circle with a center of (0, 0).  The square root of 25 represents the radius of the circle which is 5.  The radius represents the distance that the outside of the circle is from the center.

Answer:

14.6328% , $5836.03

Step-by-step explanation:

Here we are going to use the formula

[tex]A_{0}(1-r)^n = A_{n}[/tex]

[tex]A_{0}[/tex] = 39000

r=?

[tex]A_{8}[/tex] = 11000

n=8

Hence

[tex]39000(1-r)^8 = 11000[/tex]

[tex](1-r)^8 = \frac{11000}{39000}[/tex]

[tex](1-r)^8 = 0.2820[/tex]

[tex](1-r) = 0.2820^{\frac{1}{8}[/tex]

[tex](1-r) = 0.2820^{0.125}[/tex]

[tex](1-r) = 0.8536[/tex]

[tex](1-0.8536=r[/tex]

[tex]r = 0.1463[/tex]

Hence r= 0.1463

In percentage form r = 14.63%

Now let us see calculate the value of car in 2003 that is after 12 years

we use the main formula again

[tex]A_{0}(1-r)^n = A_{n}[/tex]

[tex]A_{0}[/tex] = 39000

r=0.1463

[tex]A_{12}[/tex] = ?

n=12

[tex]39000(1-0.14634)^{(12} = A_{12}[/tex]

[tex]39000(0.8536)^{12} = A_{12}[/tex]

[tex]39000*0.1497 = A_{12}[/tex]

[tex]A_{12}=5840.34[/tex]

Hence the car's value will be depreciated to $5840.34 (approx) by 2003.

The annual rate of change between 1995 and 2003 is -0.1463

The annual rate of change between 1995 and 2003 is -14.63%

The value of the car in 2007 would be $5,844.24

The value of the car decreases as the years go by. This is referred to as depreciation. Depreciation is the decline in value of an asset as a result of wear and tear.

In order to determine the annual rate of change, use this formula:

g = [tex](FV / PV) ^{\frac{1}{n} } - 1[/tex]

Where:

g = depreciation rate

FV = value of the car in 2003 = $11,000

PV = value of the car in 1995 = $39,000

n = number of years = 2003 - 1995 = 8

[tex](11,000 / 39,00)^{\frac{1}{8} } - 1[/tex] = -0.1463 = -14.63%

The value of car in 7 years can be determined using this formula:

FV = P (1 + g)^n

$39,000 x (1 - 0.1463)^12

$39,000 x 0.8537^12 = $5,844.24

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Answer:

C. 106

Step-by-step explanation:

Angles 2 and 6 are corresponding angles so they're both 74. So you just subtract 74 from 180 to get 106.

Answer:

C. 106 is the answer

Step-by-step explanation:

angle 3 = angle 2 (vertically opp. angle)

angle 3+ angle 5 = 180

74+ angle 5 = 180

angle 5 = 106

Answer:

(g-h)=x^2+5-8-x

=x^2-x-3

(g-h)(-9) means x= -9

x^2-x-3

=(-9)^2-(-9)-3

=81+9-3

=90-3

=87

Answer:

[tex]\large\boxed{A=153\ cm^2}[/tex]

Step-by-step explanation:

Look at the picture.

We have

square with side length a = 9

trapezoid with base lengths b₁ = 9 and b₂ = 6 and the height length h = 6

right triangle with legs lengths l₁ = 3 + 6 = 9 and l₂ = 6

The formula of an area of a square

[tex]A=a^2[/tex]

Substitute:

[tex]A_I=9^2=81\ cm^2[/tex]

The formula of an area of a trapezoid:

[tex]A=\dfrac{b_1+b_2}{2}\cdot h[/tex]

Substitute:

[tex]A_{II}=\dfrac{9+6}{2}\cdot6=\dfrac{15}{2\!\!\!\!\diagup_1}\cdot6\!\!\!\!\diagup^3=(15)(3)=45\ cm^2[/tex]

The formula of an area of a right triangle:

[tex]A=\dfrac{l_1l_2}{2}[/tex]

Substitute:

[tex]A_{III}=\dfrac{(9)(6)}{2}=\dfrac{54}{2}=27\ cm^2[/tex]

The area of the shape:

[tex]A=A_I+A_{II}+A_{III}\\\\A=81+45+27=153\ cm^2[/tex]

Answer:

  1763 ft²

Step-by-step explanation:

Using the given conversion factor, ...

  (164 m²)(1 ft/(.305 m))² = 165/.093025 ft² ≈ 1763 ft²

_____

The exact conversion factor is 1/0.3048, so the area is closer to 1765 ft². For a 4-significant digit answer, you need to use a conversion factor accurate to 4 significant digits.

To convert square meters to square feet, you must square the feet to meter conversion factor, resulting in approximately 10.764 sq ft/sq m. You then multiply this by the square meter measurement to get the equivalent in square feet. Therefore, the house's area, which was provided as 164 square meters, translates to approximately 1765.736 square feet.

The measure of the area in square feet can be derived using the conversion factor for feet to meters, 1 ft = 0.305 m. However, when you deal with areas, you must square the conversion factor. We then apply the conversion factor to the known area in reference, which in our case is 164 square meters.

So our conversion factor becomes (1/0.305)² sq ft/sq m = 10.764 sq ft/sq m.

To use the conversion factor, we multiply it by the metric unit measurement, like this: 164 m²*(10.764 ft²/m²) = 1765.736 square feet.

So, the house's area is approximately 1765.736 square feet.

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