the answer to that question is the second option
Drawing from Newton's first law of motion, a rock thrown in space, distant from any significant gravitational field, would continue at the same speed in perpetuity.
Explanation:
In the context of Physics, and in particular Newton's first law of motion, the rock you throw in space, far from any gravitational field, will continue at the same speed forever. This law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. In space, far from any significant gravitational field, there are essentially no external forces to slow the rock down or change its direction, so it will keep moving at the speed it had when it left your hand.
Learn more about Newton's first law of motion here:https://brainly.com/question/974124
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A 1.0 kg book is at rest on a table top diagram the forces acting on the book
Answer:
In the diagram attached, we will be able to see that the total force [tex]F[/tex] acting on the book is zero, according to the First Newton law, which states that an object is in equilibrium is the total force exerted on it is zero:
[tex]F=F_{T}-W=0[/tex] (1)
Which is the same as:
[tex]F_{T}=W[/tex] (2)
Where [tex]W[/tex] is the weight of the book, which is the product of the mass [tex]m[/tex] of the book and the gravity acceleration [tex]g[/tex]:
[tex]W=mg[/tex] (3)
Being [tex]m=1.0kg[/tex] and [tex]9.8\frac{m}{s^{2}}[/tex], the weight of the book is:
[tex]W=(1.0kg)(9.8\frac{m}{s^{2}})[/tex]
[tex]W=9.8N[/tex] (4)
Then, equation (2) means that the force [tex]W[/tex] due to the weight acting on the book is the same in magnitude but in opposite direction to the force [tex]F_{T}[/tex] the table exerts on the book, which is in accordance with the third Newton law of action and reaction.
What is true about the refractive index of a medium?
The refractive index of a medium is independent of (not related to) the angles of incidence or refraction. It's just a property of the medium. (D)
jose buys a new moped. He travels 3km south and then 4 km east. How far does he need to go to get back to where he started?
Answer: 5km by straight line, 7km by route.
Explanation:
The distance by route is 3km south and then 4km east, notice that the distances are perpendicular to each other, so the total distance traveled (by a straight line) is:
D = √((3km)^2 + (4km)^2) = √(9km^2 + 16km^2) = (√25)km = 5km
So the distance by a straight line that he needs to go back to where he started is 5km, and if he wants to get back by route, he must do 4km to the west and then 3km to the north, so a total of 7km
A race car starting from rest accelerates uniformly at a rare of 4.90 meters per second^2. What is the cars speed after it has traveled 200 meters?
From the law of Galileo Galilei :v²=v₀²+2ad we take the speed
v²=0+2*4.90*200=1960=>v=√1960=44.27 m/s
A 67kg stove is located on the 70th floor of a building (230m above ground). The stove has _______ energy. Calculate it.
Answer:
[tex]1.51\cdot 10^5 J[/tex] of gravitational potential energy
Explanation:
the gravitational potential energy of an object is given by:
[tex]U=mgh[/tex]
where
m is the mass of the object
g is the acceleration due to gravity
h is the heigth of the object above the ground
In this problem, we have:
- m = 67 kg is the mass of the stove
- g = 9.8 m/s^2 is the acceleration due to gravity
- h = 230 m is the height of the stove above the ground
Substituting into the equation, we find
[tex]U=(67 kg)(9.8 m/s^2)(230 m)=1.51\cdot 10^5 J[/tex]
What is an example of potential energy to kinetic energy?
Potential energy is the store she energy from an object this could include rubber bands. Kinetic energy is the energy that deals with motion a good example is a person running
Hello There!
Potential energy is energy that is stored in an object. Kinetic energy involves motion so an object that has potential energy turns into kinetic energy.
An example could be a roller coaster going up a hill and it's building potential energy so when it goes down the hill, the potential energy will turn into kinetic energy.
To determine the speed of a wave, you must know the waves wavelength and_____
You must know the wavelength and the frequency.
A 1500.0 kg car hits a brick wall with a force of 60.0 N in 1.75 seconds. What is the change in the momentum of the car?
Answer:
Change in the momentum of the car = 105 kgm/s
Explanation:
We have the Newton's second law, that is rate of change of momentum is force.
[tex]\frac{dP}{dt}=F\\\\\frac{mv-mu}{dt}=F\\\\mv-mu=Fdt[/tex]
That is rate of change of momentum is impulse.
Here we need to find rate of change of momentum = Fdt
dP = Fdt
dP = 60 x 1.75 = 105 kgm/s
Change in the momentum of the car = 105 kgm/s
The history of Sir Isaac Newton’s study of gravity does which of the following?
A. Illustrates how a theory becomes a law
B. Provides an example of a theory that has been discredited
C. Demonstrates the importance of gravity in marine science
D. Shows that theories have long been an important part of science
A. Illustrates how a theory becomes a law
Answer:
A. Illustrates how a theory becomes a law
Explanation:
Newtons studied about the gravity for a very long time and proposed theory about it.
Later on, based on his theories comes the gravitational law. His theory were based on various assumptions and examples that he related to explain the structure of universe.
His work shows how theories can become laws which are universally obeyed.
Which of the following parts of the eye is located at the back of the eye, receives focused light waves from the lens, and is composed of tiny, light-sensitive nerves? A. the retina B. the cornea C. the convex lens D. the optic nerve
That's the retina. (A)
If you think of your eye like a film camera, the retina is the film.
If you think of your eye like a digital camera, the retina is the CCD.
The diagram shows a pot sitting on a gas stove burner. Which shows the order in which thermal energy is transferred by conduction? stove burner pan bottom of pan handle top of pan handle top of pan handle bottom of pan handle pan stove burner pan stove burner bottom of pan handle top of pan handle top of pan handle bottom of pan handle stove burner pan
Answer:
stove burner --> pan -- > bottom of pan handle --> top of pan handle
Explanation:
Conduction is one of the three methods of transfer of heat, and it occurs when the heat is transferred by contact/collisions between the molecules of two different mediums/objects (or also between molecules of different parts of the same object).
In this case, the transfer of heat by conduction occurs as follows:
- The stove burner is heated, and it is in contact with the pan --> the molecules of the stove burner move faster (they have more kinetic energy), so they transfer thermal energy (heat) by conduction to the molecules of the pan
- The pan is heated, and the same process occurs, but this time the heat is transferred to the bottom of the pan handle, which is attached to the pan
- Then, the bottom of the pan handle becomes hot, and by conduction heat is transferred also the part of the handle which is farther from the pan, so to the top part of the handle
Which law describes the magnetic field in a nonlinear wire?
A.
Faraday's law
B.
Gauss's law
C.
Ohm's law
D.
Ampère's law
Ampère's law is the proper law to describe the magnetic field in a nonlinear wire, relating the circulation of the magnetic field to the electric current passing through the circuit. Hence option D is correct.
The law that describes the magnetic field in a nonlinear wire is Ampère's law. Ampère's law states that the magnetic field around an electric current is proportional to the current, with each segment of current contributing to the magnetic field. Specifically, it describes how the circulation of the magnetic field, or the line integral around a closed curve (denoted as C), is related to the electric current passing through the surface (denoted as S) that is bounded by the curve C. Importantly, the surface can be of any shape, allowing for the application of Ampère's law to wires of arbitrary configurations, including nonlinear wires.
The _______ is broken up into tectonic plates, which make up the hard and rigid surface of the Earth. A. solid core B. convective mantle C. liquid core D. lithosphere
Should be the Lithosphere
How does the electric force between two charged particles change if particle's charge is reduced by a factor of 3?
The force between two charges is proportional to the product of the charges.
If only one of the charges is reduced by a factor of 3, then the force is reduced by a factor of 3.
If both charges are reduced by a factor of 3, then the force is reduced by a factor of 9.
Answer: It is reduced by a factor of 3.
Explanation:
1200 j of work was done to move a 20m What Force was applied to the box?
Given data :
Work (W) = 1200 J ,
distance (S) = 20 m ,
Determine the Force applied to the box = ?
Work done = F. S
1200 = F . 20
F = 60 N
Force applied to the box is 60 N
how is momentum conserved when a cue ball moving with a velocity of 1.5 m/s strikes another billiard ball white playing pool? Show the work.
according to conservation of momentum , total sum of momentum of the objects taking part in a collision is same before and after the collision.
Total momentum before collision = Total momentum after the collision
when a cue ball moving at velocity 1.5 m/s hits a billiard ball , transfer of momentum takes place between the balls such that total sum of momentum of cue ball and billiard ball remain same before and after the collision.
hence we say that the momentum is conserved.
in the problem below, what is the student showing?
[tex]3 \times 3 \times 3 = 27 {cm}^{3} [/tex]
Answer:
Student showing the volume of cube
V = a³
if a = 3 cm
Then volume is a³ = 3 ×3 × 3
= 27 cm³
A Level Physics. Momentum questions.
kinematic equation used, g=10m/s/s approx
(a) 39.6 m/s and 30.7 m/s
Explanation:
Use the formula for speed as a function of distance made in a uniformly decelerated motion:
[tex]v_s^2 = v_0^2 -2sa[/tex]
with v_s the instantaneous speed at distance s and v_0 the initial speed (right after the explosion). "a" is the acceleration due to friction force, with negative sign in front of that term reflecting the fact the friction force acts against the direction of the motion. The scene after the explosion implies the fragments have come to a halt with the respective distances shown in the figure, i.e., for each fragment:
[tex]0 = v_0^2 -2sa[/tex]
and the initial speed v_0 remains to be determined:
[tex]v_0=\sqrt{2sa}[/tex]
The deceleration "a" due to friction can be found using the information we are given: the mass of a fragment and the coefficient of dynamic friction of 0.4:
[tex]F_{friction} = \mu\cdot m\cdot g \implies a = \mu\cdot g = 0.4\cdot 9.8\frac{m}{s^2}=3.92\frac{m}{s^2}[/tex]
So the initial velocities just after the explosion, as implied by the distances of 200m (v01) and 120m (v02) are, respectively:
[tex]v_{01}=\sqrt{2\cdot200m\cdot 3.92\frac{m}{s^2}}=39.6\frac{m}{s}\\v_{02}=\sqrt{2\cdot120m\cdot 3.92\frac{m}{s^2}}=30.7\frac{m}{s}[/tex]
(b) The speed of the third fragment is 31.7 m/s
Explanation:
Use the law of conservation of the momentum. At the time of the explosion there were three fragments. For two of them we have determined the initial speed in (a). Now we know that the total momentum of the system (container) right before the fragments were set into motion was 0. The total of the moment vectors (magnitudes with their directions) should still be 0 right after the explosion. Given the angle between the paths of fragment 0.5kg and 1kg, the total vector of their momentum can be calculated
[tex]\overline{p}_{12} = m_1 \overline{v}_1 +m_2\overline{v}_2\\[/tex]
and from the conservation law we know that the momentum of the third piece must be
[tex]\overline{p}_3=-\overline{p}_{12}[/tex]
in particular, its magnitude will be same as the magnitude of the resultant vector, counteracting (at an angle 180 degrees from the resultant). This will eventually allow us to determine the speed of the third fragment. The magnitudes are:
[tex] |\overline{p}_{1}| = 0.5kg\cdot 39.6 \frac{m}{s} = 19.8 kg\frac{m}{s}\\|\overline{p}_{2}|=1.0kg\cdot 30.7\frac{m}{s}=30.7kg\frac{m}{s}[/tex]
and the resulting moment:
[tex] |\overline{p}_{12}| = \sqrt{|\overline{p}_1|^2+|\overline{p}_2|^2+2|\overline{p}_1||\overline{p}_2|\cos 40^\circ}=47.6 kg\frac{m}{s}=|\overline{p}_3|[/tex]
and so the speed of the third fragment is
[tex]v_{03} = \frac{|\overline{p}_3|}{1.5kg}=\frac{47.6kg\frac{m}{s}}{1.5kg}=31.7\frac{m}{s}[/tex]
(c) The total kinetic energy is 1617 Joules
Explanation:
[tex]E_k = \frac{1}{2}\sum_{i=1}^3 m_i v_{0i}^2 = 0.5\cdot(0.5\cdot 39.6^2+1\cdot 30.7^2+1.5\cdot 31.7^2)kg\frac{m^2}{s^2}=1617.0J[/tex]
(d) The area will be proportional to the fourth power of the initial velocities.
Explanation:
Consider the area of a circle with radius equal to the distance a fragment traveled. We can choose a fragment with largest such distance or choose the average of the areas for each fragment, or another geometric measure, however, this choice won't affect the qualitative answer.
The distance of a fragment "i" traveled as a function of the initial speed is
[tex]s_i = \frac{v_{0i}^2}{2a}[/tex]
The circular area is then
[tex]A_i = \pi(\frac{v_{0i}^2}{2a})^2\implies A_i \propto v_{0i}^4[/tex]
The area due to a fragment with initial velocity is proportional to the fourth power of that velocity. This can be generalized to all fragments by assuming a common factor amplifying the velocities. Such factor will also show up in the fourth power in the area formula above, justifying the answer: the effect of an amplification of the initial speed has a fourth-power effect on the area of spread.
At a distance of 1 A.U., the earth takes one year to travel around the sun. How far away is a planet that takes eight years to go around the sun?
Answer:
4 AU
Explanation:
We can solve the problem by using Kepler's third law, which states that the ratio between the square of the period of revolution of a planet around the Sun and the cube of its average distance from the Sun is constant for every planet orbiting the Sun:
[tex]\frac{T^2}{r^3}=k[/tex]
where
T is the orbital period
r is the average distance of the planet from the Sun
If we take two planets 1 and 2, the equation can be rewritten as
[tex]\frac{T_1^2}{r_1^3}=\frac{T_2^2}{r_2^3}[/tex]
In this problem, we have:
[tex]T_1 = 1 y[/tex] is the orbital period of the Earth
[tex]r_1 = 1 AU[/tex] is the distance of the Earth from the Sun
[tex]T_2 = 8 y[/tex] is the orbital period of the second planet
Therefore, we can re-arrange the equation to calculate r2, the averag distance of the other planet from the Sun:
[tex]\frac{r_2^3}{T_2^2}=\frac{r_1^3}{T_1^2}\\r_2 = \sqrt[3]{\frac{r_1 ^2 T_2^2}{T_1^2}}=\sqrt[3]{\frac{(1 AU)^3(8 y)^2}{(1 y)^2}} =4 AU[/tex]
Answer:
4
Explanation:
write an word problem about perimeter
The word problem is about finding the dimensions of a garden using a given amount of fencing material, applying the formula for the perimeter of a rectangle, and considering that the length is twice the width.
Imagine you have a small garden in the shape of a rectangle. The length of the garden is twice its width. You want to put a fence around the entire garden to keep the rabbits out. If you have 30 meters of fencing material available, what are the dimensions of your garden?
To solve this problem, we need to set up an equation using the formula for the perimeter of a rectangle, which is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width. Since the length is twice the width, we can express the length as l = 2w. Substituting this into the perimeter formula gives us P = 2(2w) + 2w, which simplifies to P = 6w. Knowing the total perimeter is 30 meters, we can find the width using 30 = 6w, which yields w = 5 meters. The length, being twice the width, is then l = 10 meters.
A person weighing 490N stands on a scale in an elevator. What does the scale read (normal force) when the elevator rises at a constant velocity of 5 m/s?
Answer:
490 N
Explanation:
The elevator is rising at constant velocity: this means the acceleration of the system is zero, so according to Newton's second law, the net force on the system is also zero:
[tex]F_{net} = ma =0[/tex]
There are two forces acting on the person standing on the scale:
- its weight, downward, whose magnitude is W=490 N
- The normal force of the scale on the person, N, which is upward
Since the net force must be zero, we have:
[tex]W-N=0[/tex]
From which we find the normal force:
[tex]N=W=490 N[/tex]
How much force does it take to accelerate a 2000-kg car at 4m/s2
A) 500N
B) 19,600 N
C) .002
D) 8000
Answer:
Force acting on the car, F = 8000 N
Explanation:
It is given that,
Mass of the car, m = 2000 kg
Acceleration of the car, [tex]a=4\ m/s^2[/tex]
We need to find the force used to accelerate the car. The product of mass and acceleration is called the force exerted to an object. It is given by :
[tex]F=m\times a[/tex]
[tex]F=2000\ kg\times 4\ m/s^2[/tex]
F = 8000 N
So, the force acting on the car is 8000 N. Hence, this is the required solution.
A spring with a spring constant value of 2500 is compressed 32 cm. A 1.5-kg rock is placed on top of it, then the spring is released. Approximately how high will the rock rise? 9 m 17 m 27 m 85 m
Answer:
9 m
Explanation:
The elastic potential energy initially stored in the spring is given by:
[tex]U=\frac{1}{2}kx^2[/tex]
where
k = 2500 N/m is the spring constant
x = 32 cm = 0.32 m is the compression of the spring
Substituting:
[tex]U=\frac{1}{2}(2500 N/m)(0.32 m)^2=128 J[/tex]
Due to the law of conservation of energy, when the spring is released all this energy is converted into kinetic energy of the rock, which starts moving upward. As the rock reaches its maximum height, all the energy has been converted into gravitational potential energy:
[tex]U=mgh[/tex]
where
m = 1.5 kg is the rock's mass
g = 9.8 m/s^2 is the gravitational acceleration
h = ? is the maximum height reached by the rock
Using U=128 J, we find h:
[tex]h=\frac{U}{mg}=\frac{128 J}{(1.5 kg)(9.8 m/s^2)}=8.7 m \sim 9 m[/tex]
Answer:
9m
Explanation:
got right on edg
A 2.0-kg mass is projected from the edge of the top of a 20-m tall building with a velocity of 24 m/s at some unknown angle above the horizontal. Disregard air resistance and assume the ground is level. What is the kinetic energy of the mass just before it strikes the ground? Answer: 0.97 kJ.
Ox:vₓ=v₀
x=v₀t
Oy:y=h-gt²/2
|vy|=gt
tgα=|vy|/vₓ=gt/v₀=>t=v₀tgα/g
y=0=>h=gt²/2=v₀²tg²α/2g=>tgα=√(2gh/v₀²)=√(2*10*20/24²)=√(400/576)=0.83=>α=tg⁻¹0.83=39°
cosα=vₓ/v=v₀/v=>v=v₀/cosα=24/cos39°=24/0,77=31.16 m/s
Ec=mv²/2=2*31.16²/2=971.47 J=>Ec≈0.97 kJ
What must happen to the temperature of a material for thermal expansion to occur.
Thermal expansion occurs when the temperature of a material increases, leading to greater kinetic energy and separation between atoms, causing the material to expand in all dimensions.
For thermal expansion to occur in a material, the temperature of that material must increase. This increase in temperature results in an increase in the kinetic energy of the material's atoms or molecules. As discussed in the Kinetic Theory, in a solid, this kinetic energy manifests as small, rapid vibrations which cause atoms to push neighboring atoms or molecules slightly farther apart from each other.
An increase in the average separation between particles translates into an expansion of the material in all dimensions. This behavior is observed in everyday phenomena, such as the buckling of railroad tracks due to thermal expansion. The degree to which a material expands in response to temperature change can be quantified by its coefficient of thermal expansion, which generally varies with temperature.
The gravitational force acting on various masses is measured on different planets. Measured values for the forces acting on the corresponding masses are shown in the data table. Analyze the data and develop a method for comparing the gravitational field strengths on the different planets. Use your method to compare the gravitational field strengths, and report your conclusions.
Plant force(N) Mass(kg)
A 10 0.50
B 30 2.0
C 45 3.0
D 60 6.0
we Know that gravitational field strength(g) at a point on a planet is equal to gravitational force exerted per unit mass placed at that point.
It Means,
g=F/m
Here,
g=gravitational field strength
F=Gravitational force
m=Mass
Case A
planet force =10 and mass= .5
g1=F/m
g1=10/.5
=100/5
g1=20m/s
case B
F=30 and m=2
therefore g2=30/2
g2=15m/s^2
case C
F=45 and m=3
g3=45/3
=15m/s^2
case D
g4=60/6
g4=10m/s^2
from above results it is clear that the gravitational field strength of planet D is minimum which is 10m/s^2 and gravitational field strength of planet A is maximum which is 20m/s^2
5. Where would a roller coaster have the greatest potential energy? A. at the top of a hill B. halfway up the hill C. halfway down the hill D. at the bottom of the hill
A. at the top of a hill
Final answer:
The roller coaster would have the greatest potential energy at the top of a hill, as potential energy is greatest at the highest point. Option A
Explanation:
The roller coaster would have the greatest potential energy at the top of a hill (option A). At the top of the hill, the roller coaster has the most potential energy because it is at the highest point and has the greatest ability to do work.
As the roller coaster goes down the hill, its potential energy is converted into kinetic energy, which is the energy of motion.
In terms of energy, potential energy is at its maximum at the top of the hill and decreases as the roller coaster moves down, while kinetic energy is at its minimum at the top of the hill and increases as the roller coaster gains speed. Option A
describe at least 2 reasons (pieces of evidence) for why we know that the continents were once joined together and have since drifted apart.
1 Continental drift
2 the layers of rock
One peice of evidence is fossils. If similar fossils are in different continents like one is in soutch america and he other is in africa then how would the dino bones be apart? they can't swim...
The other is climates and land forms. Palentologist have found tropical plant fossils in an island of the Arctic ocean where it is way to cold for plants to even grow... Plants can't telaport....
#sHoOk ! EVIDENCE!!
An 8.0newton block is accelerating down a frictionless ramo inclined at 15 degrees to the horizontal. What is the magnitude of the net force causing the blocks acceleration?
1. 0N
2. 2.1N
3. 7.7N
4. 8.0N
The magnitude of the net force causing the block's acceleration can be found using Newton's second law of motion. For a block on a frictionless ramp inclined at 15 degrees, the net force is equal to the weight of the block multiplied by the sine of the angle of incline. In this case, the magnitude of the net force is approximately 2.1 newtons.
Explanation:The magnitude of the net force causing the block's acceleration can be determined using Newton's second law of motion, which states that the net force on an object is equal to its mass multiplied by its acceleration. Since the ramp is frictionless, the only force acting on the block is its weight. We can break the weight into two components: the force along the ramp (parallel) and the force perpendicular to the ramp.
The force along the ramp can be found by multiplying the weight by the sine of the angle of incline, which is 15 degrees. The force perpendicular to the ramp is the weight multiplied by the cosine of the angle of incline. Since there is no force perpendicular to the ramp, we only need to consider the force along the ramp. Given that the weight of the block is 8.0 newtons, the magnitude of the net force causing the block's acceleration is 8.0 newtons multiplied by the sine of 15 degrees, which is approximately 2.1 newtons. Therefore, the correct option is 2.1N.
Final answer:
The magnitude of the net force causing the block's acceleration down a 15-degree frictionless incline is 2.1N, calculated using the gravitational force component along the incline.
Explanation:
The student is asking about the magnitude of the net force causing acceleration in a block sliding down a frictionless incline. The block has a weight of 8.0 newtons, and the incline is at a 15-degree angle to the horizontal. To find the net force, we need to calculate the component of the gravitational force that acts along the incline. This is done by multiplying the weight of the block by the sine of the angle of the incline.
Here's the calculation: net force (F_net) = weight (mg) × sin(θ), where g is the acceleration due to gravity (9.8 m/s²) and θ is the incline angle. Plugging in the known values, F_net = 8.0 N × sin(15°). The sine of 15 degrees is approximately 0.2588. So, F_net = 8.0 N × 0.2588 ≈ 2.07 N.
Therefore, the correct answer is 2.1N, which is the magnitude of the net force causing the block's acceleration down the incline.
This roller coaster has potential energy when it is sitting at the top of this loop. As the cars move down, the potential energy changes into energy of motion. What kind of potential energy does the roller coaster have at the top of the loop?
A) potential chemical energy
B) potential elastic energy
C) potential electrical energy
D) potential gravitational energy
D) Potential gravitational energy. Since the roller coaster cars are a the top of the roller coaster they have potential energy due to the gravity's downwards pull on them.
D) potential gravitational energy
What is potential gravitational energy ?Potential gravitational energy is the energy possessed or acquired by an object due to a change in its position when it is present in a gravitational field. In simple terms, it can be said that potential gravitational energy is an energy that is related to gravitational force or to gravity.
There are a many types of potential energy but when we talk about the height , when something is kept on a certain height their occur a gravitational force acting on that object and potential gravitational energy can be calculated as U = m*g*h , since roller coaster has potential energy when it is sitting at the top of this loop
hence , correct answer is D) potential gravitational energy
learn more about potential gravitational energy
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