Answer:
If the speed would be doubled, the distance traveled by the vehicle will be FOUR times. It can be proved by 3rd equation of motion.
Explanation:
When the brakes are applied, frictional force acts on the tires which decreases the speed. Eventually the car will stop. This frictional force is nearly independent of the speed hence by applying 3rd equation of motion, we can find the distance traveled.
2aS = Vf²-Vi²
[tex]S=\frac{Vf^{2}-Vi^{2}}{2a}[/tex]
For Vf=0
S=-Vi²/2a
Vi-new = 2*Vi
S-new = -(Vi-new)²/2a
S-new = -(2*Vi)²/2a
S-new = -4Vi²/2a
S-new = 4.S
Here
Vf= Final Velocity i.e. 0m/s²
Vi= Initial Velocity
a= Deceleration (Negative Acceleration)
S= Distance covered by vehicle
A meteoroid is traveling east through the atmosphere at 18.3 km/s while descending at a rate of 11.5 km/s. what is its speed, in km/s?
The speed of the meteoroid is calculated by using the Pythagorean theorem and considering its horizontal and vertical speeds as vectors. Plugging in the given values, the meteoroid's speed is approx 21.72 km/s.
Explanation:To calculate the speed of the meteoroid, we can use the concept of vectors and Pythagorean theorem. The meteoroid has a horizontal speed (eastward movement) and a vertical speed (downward movement). The total speed is the magnitude of the resultant vector. This can be calculated using Pythagorean theorem as follows:
The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Speed = sqrt[(Horizontal speed)^2 + (Vertical speed)^2]
Plugging in the given values:
Speed = sqrt[(18.3 km/s)^2 + (11.5 km/s)^2]
After calculating, we found that the speed is approx 21.72 km/s.
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A horizontal compass is placed 21 cm due south from a straight vertical wire carrying a 36 a current downward. in what direction does the compass needle point at this location? assume the horizontal component of the earth's field at this point is 0.45 â 10-4 t and the magnetic declination is 0°.
The needle of a compass will always lies along the magnetic
field lines of the earth.
A magnetic declination at a point on the earth’s surface
equal to zero implies that
the horizontal component of the earth’s magnetic field line
at that specific point lies along
the line of the north-south magnetic poles.
The presence of a
current-carrying wire creates an additional
magnetic field that combines with the earth’s magnetic field.
Since magnetic
fields are vector quantities, therefore the magnetic field of
the earth and the magnetic field of the vertical wire must be
combined vectorially.
Where:
B1 = magnetic field of the earth along the x-axis = 0.45 × 10 ⁻ ⁴ T
B2 = magnetic field due to the straight vertical wire along the y-axis
We can calculate for B2 using Amperes Law:
B2 = μ₀ i / [ 2 π R ]
B2 = [ 4π × 10 ⁻ ⁷ T • m / A ] ( 36 A ) / [ 2 π (0.21 m ) ]
B2 = 5.97 × 10 ⁻ ⁵ T = 0.60 × 10 ⁻ ⁴ T
The angle can be
calculated using tan function:
tan θ = y / x = B₂ / B₁ = 0.60 × 10 ⁻ ⁴ T / 0.45 × 10 ⁻ ⁴ T
tan θ = 1.326
θ = 53°
The compass needle points along the direction of 53° west of
north.
The compass needle near a current-carrying wire aligns northwest due to the combined influence of the Earth's northward magnetic field and the wire's westward magnetic field at that location.
A compass needle, which is a tiny bar magnet, aligns with the magnetic field it experiences. In this scenario, both the Earth's magnetic field and the magnetic field created by a vertical current-carrying wire influence the needle.
The magnetic field produced by a straight current-carrying wire is given by the right-hand rule: point your thumb in the direction of the current (downward) and curl your fingers around the wire.
Your fingers show the direction of the magnetic field; moving in circles around the wire.
At the position of the compass (21 cm south of the wire), the wire's magnetic field will circulate clockwise when viewed from above.Thus, directly south of the wire, the magnetic component from the wire is directed towards the west.The Earth's magnetic field at this location points northward with a horizontal component of 0.45 × 10⁻⁴T.The resultant magnetic field at the compass position is the vector sum of the Earth's northward field and the wire's westward field.Therefore, the compass needle will align with this resultant field, pointing in a direction northwest.
In a nuclear power plant, mechanical energy is created by turning a turbine from steam created by heating water from which of the following?
A)the burning of uranium
B)the fusion of uranium
C)the fission of uranium
Answer:
The answer is C)the fission of uranium.
Explanation:
The nuclear plant is an industrial installation that generates electrical energy from nuclear energy. Nuclear plants have reactors that are responsible for the fission of nuclear fuel atoms. such as uranium, thus transforming mechanical work into electrical energy.
Which of the answer choices correctly describes covalent bonds?
A) An attraction between oppositely charged ions
B) A force that holds atoms or ions together in a fixed structure or unit
C) A sharing of four pairs (eight valence electrons) between two atoms
D) A sharing of an electrons pair between two atoms
describe an electromagnet and how it is used
An electromagnet is a type of magnet in which the magnetic field is produced by an electric current. The magnetic field disappears when the current is turned off. Electromagnets usually consist of insulated wire wound into a coil. A current through the wire creates a magnetic field which is concentrated in the hole in the center of the coil. The wire turns are often wound around a magnetic core made from a ferromagnetic or ferrimagnetic material such as iron; the magnetic core concentrates the magnetic flux and makes a more powerful magnet.
The main advantage of an electromagnet over a permanent magnet is that the magnetic field can be quickly changed by controlling the amount of electric current in the winding. However, unlike a permanent magnet that needs no power, an electromagnet requires a continuous supply of current to maintain the magnetic field.
Electromagnets are widely used as components of other electrical devices, such as motors, generators, relays, loudspeakers, hard disks, MRI machines, scientific instruments, and magnetic separation equipment. Electromagnets are also employed in industry for picking up and moving heavy iron objects such as scrap iron and steel.[2]
Electromagnets are temporary magnets powered by electric current with versatile applications in different fields.
**An electromagnet** is a piece of wire that generates a magnetic field when an electric current passes through it. Unlike permanent magnets, **electromagnets** can be turned on and off by controlling the flow of electricity. They are widely used in various applications such as electric motors, generators, MRI machines, and even in scrapyard cranes.
where do the three rays in a ray diagram start
In a ray diagram, the three rays usually originate from the same point on the object. Following predefined ray-tracing rules, these rays pass through or reflect off a lens or mirror, converging or diverging to form an image. The point where these rays intersect represents the location of the image.
Explanation:In a ray diagram, the three rays typically start from the same point on the object. This point on the object is the source from which the rays emanate. As the rays travel towards the lens or mirror involved, they will follow particular paths based on a set of simple ray-tracing rules. For example, one ray might pass through the focal point on its way to the lens and exit the lens parallel to the optical axis. These rays will then converge or diverge to form an image, depending on the lens or mirror set-up.
It is important to note that although three rays are often drawn for clarity and verification, only two are necessary to locate a point in the image. The point at which these rays intersect on the other side of the lens or mirror is where the image of the point from which they originated is located. Following these ray-tracing rules correctly will provide an accurate representation of how light behaves in the given optical system, illustrating the fundamental principles of geometric optics.
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Unit 3 quiz / question 10 of 10 question 10 you are operating a pwc. what is most likely to create a blind spot that blocks other boats from seeing you?
A gasoline engine operates at a temperature of 270°c and exhausts at 180°c. calculate the maximum efficiency of this engine. (note that the celsius scale is used.)
16.6 is the answer. Not 17.0 do not round.
Give an example in which a small force exerts a large torque. give another example in which a large force exerts a small torque.
Answer:
Explanation:
Torque is defined as the product of force and the perpendicular distance.
If we take a screw driver of small length then we need to apply a large force to open or tighten the screw.
If a screw driver of long arm, then we need to apply small force to open or tighten the screw.
A mass oscillates on the end of a spring, both on earth and on the moon. where is the period the greatest?
Final answer:
The period of oscillation of a mass on a spring is the same on both Earth and the Moon, as it is independent of gravity.
Explanation:
The question asks where the period of oscillation of a mass on a spring is the greatest, either on Earth or on the Moon. The period of a spring-mass system, according to the formula T = 2π√(m/k), where T is the period, m is the mass, k is the spring constant, and π (pi) is approximately 3.14159, is independent of gravity. Hence, the gravitational differences between the Earth and the Moon do not affect the period directly. However, external forces like gravity can influence the amplitude of the oscillation, not the period itself. Therefore, the period of oscillation will be the same on both the Earth and the Moon, assuming no other factors are changed.
A scientific _______ is a unifying explanation for a set of observations that has been verified by multiple testing. hypothesis belief law theory
The main purpose of a service panel in a house is to A. keep the meter working correctly. B. connect the service drop to the house. C. provide automatic circuit protection and prevent fires. D. keep electrical hazards localized.
keep electrical hazards localized
A charge Q generates an electric field of strength E at a distance d away. Determine the electric field strength at d and 2d, respectively:
The electric field strength at a distance 2d from a charge Q is one-fourth the electric field strength at a distance d, due to the inverse square nature of the electric field with respect to distance.
Explanation:The question pertains to the concept of the electric field created by point charges in physics. To determine the electric field strength E at a distance d and at a distance 2d from a charge Q, we use Coulomb's law, which relates the electric field E to the charge Q and the distance r from the charge as E = kQ/r², where k is Coulomb's constant (approximately 8.99 × 10⁹ Nm²/C²).
For the charge Q generating a field strength E at a distance d, the electric field at distance d is simply E. However, at a distance 2d, since the distance from the charge is doubled, the electric field strength is reduced by a factor of four (since it's inversely proportional to the square of the distance). Therefore, the electric field strength at 2d is E/4.
Example Calculation: If the original distance is 2.00 × 10⁻² m and charge is 5.00 × 10⁻¹ C, the electric field at distance d can be calculated using the formula provided. If E is known initially at distance d, to find the field at 2d, simply divide that E by 4.
Final answer:
The electric field strength at a distance 2d from a charge Q is one-fourth the electric field strength at a distance d, according to the equation E = kQ/r², where E is electric field strength, k is Coulomb's constant, Q is the charge, and r is the distance.
Explanation:
The question deals with determining the electric field strength at distances d and 2d from a charge Q. The electric field strength created by a point charge is given by the equation E = kQ/r², where k is Coulomb's constant, Q is the charge, and r is the distance from the charge.
At a distance d, the electric field strength is E. To find the electric field strength at 2d, we simply plug in the new distance into the equation, which results in E = kQ/(2d)². Because 2d is simply twice the original distance, the denominator becomes four times as large, resulting in an electric field strength at 2d that is ¼ of what it was at d. Therefore, the electric field strength at 2d will be E/4.
Explain why the mean and standard deviation are not appropriate for particle size distributions
The mean and standard deviation are not appropriate for particle size distributions due to non-normal distributions, irregular particle shapes, discrete measurement methods, and differences in weighting methods that aren't captured by standard parametric statistics like mean and deviation.
The mean and standard deviation are not always appropriate for describing particle size distributions because particle sizes are often not normally distributed. In the case of particle size distribution, there can be significant skewness or a high level of kurtosis, leading to a distribution that significantly deviates from normality. Additionally, particles may be irregularly shaped, which affects how their size is represented and measured. When particle size is based on sieves, the analysis becomes discrete rather than continuous, which can limit the utility of standard deviation. Furthermore, different weighting methods, like number weighted distribution or intensity weighted distribution, significantly affect the representation of particle size, which the mean and standard deviation do not properly account for.
Moreover, in dynamic light scattering (DLS) methods, the assumption is made that particles are spherical and the distribution is monomodal, which might not hold true for all particle systems. Since the mass of a particle is proportional to the cube of its radius, if particles are crushed to become smaller, a sample with the same number of particles represents a significantly different mass, affecting the representativeness of mean and standard deviation.
Particle shape also influences the determination of size as particles often deviate from sphericity. The equivalent spherical diameter (ESD) used in dynamic measurements may vary, reflecting a limitation for standard mean and deviation metrics. Due to these complexities, particle size distributions are often better described using median particle sizes (such as D50) and span, a dimensionless number that provides insight into the width of size distribution.
When jump starting a vehicle, once the stalled vehicle is successfully started, remove the cables in the same order in which they were connected?
The statement “When you jump start a vehicle, if the stalled vehicle started, then you remove the cables in the same order in which they were connected”, is false.
Go through these steps before you even connect the cables:
1. Both batteries should have the same polarity and same voltage.
2. Never let the vehicles touch each other and your cars should be near enough to connect the cables.
3. Turn off the lights, accessories, and ignition switch in both cars. Put the vehicles in neutral mode and make sure the parking brake is set. Also wear safety glasses.
4. Never smoke. An explosion is possible if sparks and ear a battery.
5. Don’t try to it the battery if the weak battery is frozen because it can explode.
6. Be sure to be able to identify the positive and negative terminals of both batteries. You need to have enough room to clamp to the cable terminals.
A force of 110 N is applied horizontally to the handles of a lawnmower to move it at a speed of 0.80 m/s across a lawn. Find the power used to mow the lawn.
The power used to mow the lawn, with a force of 110 N applied to move the lawnmower at 0.80 m/s, is calculated using the formula P = F × v and results in 88 Watts.
Explanation:To calculate the power used to mow the lawn, we use the formula for power, which is the rate of doing work. Power (P) is equal to the work done (W) divided by the time taken (t), or P = W/t. In this case, work done can also be described as the force applied (F) times the distance moved (d) in the direction of the force, but since the problem doesn't provide the distance and only provides the speed at which the lawnmower is moving, we can use another formula for power: P = F × v where v is velocity.
Given that the force (F) is 110 N and the velocity (v) is 0.80 m/s, we can find the power with P = 110 N × 0.80 m/s giving us:
P = 88 Watts.
This is the power used by the person to mow the lawn while applying a constant horizontal force to move the lawnmower at a constant speed.
Your friend just challenged you to a race through an obstacle course. You know in order to beat him, you must run 30 meters within 60 seconds in a southern direction. What does your average velocity need to be to win the race?
Answer:
velocity = 0.5 m/s Towards South
Explanation:
As we know that velocity is the ratio of displacement and time
so here it is given that object displaced by total displacement of d = 30 m
also we know that time taken is 60 seconds
now we know the formula as
[tex]v = \frac{displacement}{time}[/tex]
now plug in the values in it
[tex]v = \frac{30}{60}[/tex]
[tex]v = 0.5 m/s[/tex] Towards South
So the average velocity must be 0.5 m/s Towards South
If the distance between two masses is tripled, the gravitational force between them changes by a factor of
The gravitational force between them changes by a factor if, the distance between two masses is tripled, is 1 / 9.
What is gravitational force?In mechanics, the force of attraction that acts on all matter is known as gravity, also known as gravitation. It does not affect how daily stuff behaves internally because it is by far the weakest known force in nature. In contrast, it regulates the paths of objects in the solar system and elsewhere in the universe, as well as the architecture and evolution of stars, galaxies, and the entire universe, through its extensive and universal action.
Given:
If the distance between two masses is tripled,
Calculate the initial gravitational force as shown below,
Initial gravitational force = Gravitation constant × m₁ × m₂ / d²
Here, d is the distance between objects,
Final gravitational force = Gravitation constant × m₁ × m₂ / d²
Final gravitational force = Gravitation constant × m₁ × m₂ / (3d)²
Final gravitational force = Gravitation constant × m₁ × m₂ / 9d²
Thus, the gravitational force between them changes by a factor of 1 / 9.
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If a road does not have a bicycle lane, where must a bicyclist ride their bicycle?
Mikes car can accelerate from 0 mph to 40mph in 5 seconds what is the acceeration of his car in miles per hour per second
A child has legs that are each 0.500 m long. What is her maximum walking speed?
A. 2.21 m/s
B. 2.19 m/s
C. 2.6 m/s
D. 5.58 m/s
The elements required for a fire to start are
An object floats on water with 80% of its volume below the surface. the same object when placed in another liquid floats on that liquid with 72% of its volume below the surface. determine the density of the unknown fluid.
a ball is tossed int the air and rises to a height of 12m. How long is the ball in the air?
If the force of gravity between a book of mass 0.50 kg and a calculator of 0.100 kg is 1.5 × 10-10 N, how far apart are they? (___/ 2)
A steel cylinder with a moveable piston on top is filled with helium (He) gas. The force that the piston exerts on the gas is constant, but the volume inside the cylinder doubles, pushing the piston up. Which of the following answers correctly states the cause for the change described in the scenario? The temperature increased. The density of the helium atoms decreased. The pressure decreased. The helium atoms increased in size.
A ray diagram shows that an object is placed between the focal point and the vertex of a convex mirror. What are the characteristics of the image produced by the object? inverted, smaller than object, real upright, smaller than object, virtual inverted, larger than object, real upright, larger than object, virtual
Answer:
B on EDGE2k21
Explanation:
trust me bih
Baseball player swings and hits a pop fly straight up in the air to the catcher. the height of the baseball in meters t seconds after it is hit is given by the quadratic function h left parenthesis t right parenthesis equals negative 4.9 t squared plus 34.3 t plus 1h(t)=â4.9t2+34.3t+1. how long does it take for the baseball to reach its maximumâ height? what is the maximum height obtained by theâ baseball?
If air resistance can be neglected, how does the acceleration of a ball that has been tossed straight upward compare with its acceleration if simply dropped?
If air resistance can be neglected, the acceleration will be the same for both the thrown ball and dropped ball which is 9.8 m/s² as only gravity is working on it.
What is air resistance?Air resistance can be defined as a force that is caused by air. The air strikes the front of an object, leading to decelerating its motion. The lesser the face area of a body, the lesser air striking the body, and the lesser the overall air resistance.
Air resistance opposes motion that occurs between air and another object. The object can exploit as it passes through the air because of air resistance. Gravity and air resistance are the only two forces of nature that shift on anything on Earth.
Air resistance force exerts in the opposite direction to an object moving in the air. Air resistance is a frictional force so the faster the body’s motion, the more will be air resistance.
In the absence of air resistance, only force due to gravity will act on an object and the gravitational acceleration will be the same for both upward and downward directions.
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A 5.0 cm object is 6.0 cm from a convex lens, which has a focal length of 7.0 cm.
What is the distance of the image from the lens?
cm
What is the height of the image?
cm
Answer : The distance of the image from the lens is, -42 cm
The height of the image is, 35 cm
Solution :
First we have to calculate the image distance.
Formula used :
[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]
where,
f = focal length = 7 cm
p = object distance = 6 cm
q = image distance = ?
Now put all the given values in the above formula, we get the distance of the image from the lens.
[tex]\frac{1}{7cm}=\frac{1}{6cm}+\frac{1}{q}[/tex]
[tex]q=-42cm[/tex]
Therefore, the distance of the image from the lens is, 42 cm and the negative sign indicates that the image is virtual.
Now we have to calculate the height of the image.
Formula used :
[tex]\frac{h}{h'}=\frac{p}{q}[/tex]
where,
h = height of object = 5 cm
h' = height of image = ?
Now put all the given values in this formula, we get the height of the image.
[tex]\frac{5cm}{h'}=\frac{6cm}{-42cm}=-35cm[/tex]
Therefore, the height of the image is, 35 cm and the negative sign indicates that the image is inverted.
A. The distance of the image from the lens is –42 cm.
B. The height of the image is 35 cm
Data obtained from the question Height of object (Hₒ) = 5 cmObject distance (u) = 6 cmFocal length (f) = 7 cmImage distance (v) =? Height of image (Hᵢ) =? A. How to determine the image distanceThe image distance is defined as the distance of the image from the lens. Thus, it can be obtained as follow:
Object distance (u) = 6 cmFocal length (f) = 7 cmImage distance (v) =?1/v = 1/u – 1/f (convex lens
v = (uf) / (u –f)
v = (6 × 7) / (6 – 7)
v = 42 / – 1
v = –42 cm
B. How to determine the height of the image.The height of the image is the height of the image as displayed by the lens. It can be obtained as follow:
Height of object (Hₒ) = 5 cmObject distance (u) = 6 cmFocal length (f) = 7 cmImage distance (v) = –42 cmHeight of image (Hᵢ) =?v / u = Hᵢ / Hₒ
–42 / 6 = Hᵢ / 5
–7 = Hᵢ / 5
Cross multiply
Hᵢ = –7 × 5
Hᵢ = –35 cm
NOTE: The negative sign indicates that the image is a virtual image.
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