A car initially traveling at 60 km/h accelerates at a constant rate of 2.0 m/s2. how much time is required for the car to reach a speed of 90 km/h?4

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

Kinetic energy, which may be seen in the movement of an object, particle, or group of particles, is the energy of motion. Any moving item uses kinetic energy, such as a person walking, a baseball being thrown, a piece of food falling from a table, or a charged particle in an electric field.

Explaination

Work may be bad, yes. -ve Work is considered to be completed when the system is functioning well and when your force is bearing fruit. When you exert force and the work is completed in the direction you intended, the work is considered successful. However, if there is an opposing force and the object moves in the opposite direction from where it was supposed to go, then the work done by U is negative but the work done by the opposing force is said to be positive.  If the object does not move and remains in place, then 0 work is done. force = work * The travel distance spose Because of the job you made, the object should move a short distance.

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The density of a [tex]36 g[/tex] object with a volume of [tex]15 cm^{3}[/tex] is [tex]2.4 g/cm^{3}[/tex].

Density of substance is defined as its mass per unit volume. Density gives information about how tightly the substance is packed together. The formula for density is

[tex]\rho = \frac{m}{V}[/tex]

Where,

[tex]\rho =[/tex]density

[tex]m =[/tex]mass

[tex]V =[/tex]volume

Unit of density is grams per cubic centimetre.

One of the most common uses of density is in how different materials interact when mixed together.

Given

[tex]m = 36 g[/tex]

[tex]V = 15 cm^3[/tex]

The density of substance is

[tex]\rho = \frac{m}{V}\\\rho = \frac{36}{15}\\\rho = 2.4 g/cm^3[/tex]

Hence, The density of a substance is [tex]2.4 g/cm^3[/tex].

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The displacement of the jogger is 20m.

The displacement of the jogger can be calculated using the formula for the circumference of a circle. The circumference of a circle is given by the formula: C = 2πr, where r is the radius of the circle. In this case, the radius is 10m, so the circumference is 2π(10m) = 20πm.

Since the jogger runs halfway around the circular path, the distance traveled is half the circumference of the circle. Therefore, the jogger travels a distance of 10πm. However, the question asks for the displacement, which is a vector quantity that represents the change in position from the starting point to the ending point. In this case, since the jogger runs halfway around the circle, the displacement is the diameter of the circle, which is equal to twice the radius. Therefore, the displacement of the jogger is 2(10m) = 20m.

The displacement of a runner who runs halfway around a circular path with a radius of 10m is 20 meters, as the displacement is the diameter of the circle.

The question pertains to physics, specifically involving concepts of displacement and circular motion. When a runner runs halfway around a circular path with a radius of 10m, their displacement is the straight-line distance from their starting point to the point directly opposite on the circle. Since displacement is a vector quantity, it does not take the path into consideration, but rather the shortest distance between two points.

In this case, the runner's displacement forms a straight line that passes through the center of the circle, effectively forming the diameter. The length of the diameter can be calculated using the radius of the circle, which is given as 10m. The displacement, in this case, would therefore be twice the radius, which is 20 meters.

Answer:

anime

Explanation:

anime=LIFE

Answer:

Reverse osmosis

Explanation:

In order to purify the water which has been contaminated with salt and microorganisms, reverse osmosis will be the best way. In reverse osmosis a pressure is applied on the salt side of the impure water using a pump. Doing this prompts the pure water to leave the salt side so pure water moves another side of the semi permeable membrane. The semi permeable also filters the microorganisms. Hence, pure water can be obtained easily from this impure sample. The RO at our houses use this process to purify water.

The speed of the snowball thrown downward when it is 5.0 m above the ground is 11.82 m/s, and the speed of the snowball thrown upward when it is 5.0 m above the ground is 13.44 m/s.

To find the speed of each snowball when it is 5.0 m above the ground, we can use the equations of motion for projectiles. For the snowball thrown downward, we can use the equation:

vf = sqrt(vi^2 + 2gh)

where vf is the final velocity, vi is the initial velocity, g is the acceleration due to gravity, and h is the vertical distance. For the snowball thrown upward, we can use the same equation with a negative value for h. Substituting the given values:

For the snowball thrown downward: vf = sqrt((13 m/s)^2 + 2*(-9.8 m/s^2)×(15 m - 5 m)) = 11.82 m/s

For the snowball thrown upward: vf = sqrt((13 m/s)^2 + 2×(-9.8 m/s^2)×(-15 m + 5 m)) = 13.44 m/s

TO solve this problem, we simply have to find for the temperature of saturated water when the external pressure is 31 kPa. When the atmospheric pressure above a liquid equals its vapour pressure, then that liquid will boil. From the tables, the temperature at 31 kPa is about:

70 °C

To solve this we must be knowing each and every concept related to photon. Therefore, the energy of a photon of light emitted by an electron is equal to Energy difference between two levels.

A photon is indeed an elementary particles which is a quantum of a electromagnetic field, comprising electromagnetic radiations like as light but also radio waves, and the electromagnetic force's force carrier.

Electrons are negative charges subatomic particles that spin in their separate sub orbitals outside the nucleus. Every electron is characterized by it's own energy level and is electrostatically attracted to the nucleus.

Therefore, the energy of a photon of light emitted by an electron is equal to Energy difference between two levels.

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Answer:

0.143

Explanation:

m = F/a

   = (4.719 N)/(33 m/s²)

   = 0.143 kg

The man's upward acceleration is found using Newton's second law, calculating the man's weight and combining that with the force he exerts on the rope. The resulting net force is divided by his mass, giving a result inclusive of gravity. Subtracting gravity's acceleration gives his actual upward acceleration, 5.15 m/s².

The subject of the question falls under the domain of Physics, specifically Newton's second law of motion. The 72.0-kg man throwing the rope over the tree and pulling down with a force of 371 N creates a force that works against his weight. To find the acceleration, we use the equation: net force = mass x acceleration (Net F = ma).

First, calculate the man's weight. Weight is the force due to gravity and is calculated as mass x gravity. So the man's weight is 72.0 kg x 9.80 m/s² = 705.60 N.

The force the man exerts on the rope is 371 N. But remember, he is pulling down, so his force and gravity are working together. Thus, the net force is 371 N (the man's pull) + 705.60 N (the man's weight) = 1076.60 N.

Then, to find the acceleration, we rearrange the equation to a = net force/mass. So, this becomes 1076.60 N / 72.0 kg = 14.95 m/s². But this includes the acceleration due to gravity. So to get the upward acceleration, we subtract gravity: 14.95 m/s² - 9.80 m/s² = 5.15 m/s² upward. Therefore, the man's upward acceleration due to his pull is 5.15 m/s².

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The Bohr Atom wavelength is shorter when an electron moves from the n = 2 to the n = 3 energy level than when it moves from the n = 2 to the n = 4 energy level.

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Final answer:

To convert the density of uranium from g/cm³ to kg/m³, multiply the density by the factors to convert grams to kilograms and then cubic centimeters to cubic meters, resulting in a density of 18,800 kg/m³.

Explanation:

To convert the density of uranium from grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³), we will use the conversion factors of 1 kg being equal to 1000 grams and 1 m³ being equal to 1,000,000 cm³. The density of uranium given is 18.8 g/cm³.

Step 1: Convert grams to kilograms.

Multiply the density value by the conversion factor to change grams to kilograms:

Density in kg/cm³ = 18.8 g/cm³ * 0.001 kg/g.

So, Density in kg/cm³ = 0.0188 kg/cm³.

Step 2: Convert cubic centimeters to cubic meters.

Now, multiply the density in kg/cm³ by the conversion factor to change cubic centimeters to cubic meters:

Density in kg/m³ = 0.0188 kg/cm³ * 1,000,000 cm³/m³.

So, Density in kg/m³ = 18,800 kg/m³.

Answer:

P = 4.0794 atm or  413,345.2 Pa

Explanation:

Given

Mass m = 14.0 g

Volume 3.5 L

Temperature T = 75° C = 75 + 273 = 348 K

Known Values

Molar mass of CO = 28 g/mol

Universal gas constant R = [tex]0.082057 L.atm/mol.K[/tex]

Solution

Number of moles in 14 g of CO is

[tex]\\n=\frac{mass}{molar.mass} \\\\n = \frac{14}{28} \\\\n = 0.5 mole[/tex]

[tex]PV = nRT\\\\P = \frac{nRT}{V} \\\\P = \frac{0.5 \times 0.082057 \times 348}{3.5} \\\\P = 4.0794 atm\\\\P = 4.0794 \times 101325\\\\P = 413,345.2 Pa[/tex]

The statement that contradicts with the big bang theory is Over time, distant galaxies move progressively closer to Earth.

In 1927, the Belgian Catholic priest Georges Lemaître proposed an expanding model for the universe to explain the observed redshifts of spiral nebulae, and calculated the Hubble law. Hence he laid the foundation of Big Bang Theory according to which the universe is expanding. There is no such statement that says about the contraction of all heavenly bodies towards the earth.

Hydrogen bonds in water lead to the expansion of ice, allowing it to float and serve as insulation in bodies of water.

Hydrogen bonds are crucial in water's unique properties: When water freezes, it expands due to hydrogen bonding, creating a less dense solid form compared to its liquid state. This expansion allows ice to float on water, insulating the liquid below and allowing life to exist.