we know that
The combined capacity of the pools is equal to the capacity of the olympic size pool plus the capacity of the smaller pool
so
Capacity of the olympic size pool
[tex]8.12*10^{5}\ gallons[/tex]
Capacity of the smaller pool
[tex]5.27*10^{5}\ gallons[/tex]
Adds the two capacities
[tex]8.12*10^{5}\ gallons+5.27*10^{5}\ gallons=13.39*10^{5}\ gallons[/tex]
[tex]13.39*10^{5}\ gallons=1.339*10^{6}\ gallons[/tex]
therefore
the answer is
[tex]1.339*10^{6}\ gallons[/tex]
The combined capacity of the pools is [tex]\fbox{\begin\\\ 1.339\times 10^{6}\text{ gallons}\\\end{minispace}}[/tex].
Further explanation:
Given:
The capacity of Olympic size pool is [tex]8.12\times 10^{5}[/tex] gallons of water.
The capacity of smaller size pool is [tex]5.27\times 10^{5}[/tex] gallons of water.
Concept used:
The combined capacity of water in the Olympic pools and smaller pool is obtained by the addition of both the capacity of the pools.
In the other words combined capacity of pools is equal to the sum of the capacity of water in Olympic pools and the capacity of water in the smaller pools.
Calculation:
Consider the combined capacity of pool as [tex]C[/tex], the capacity of the Olympic size pools as [tex]X[/tex] and the capacity of smaller size pools as [tex]Y[/tex].
Therefore the combined capacity of the pool is obtained as,
[tex]\fbox{\begin\\\ \math C=X+Y\\\end{minispace}}[/tex] .....(1)
Substitute [tex]8.12\times10^{5}[/tex] for [tex]X[/tex] and [tex]5.27\times10^{5}[/tex] for [tex]Y[/tex] in equation (1) to obtain the combined capacity.
[tex]\begin{aligned}C&=(8.12\times10^{5})+(5.27\times10^{5})\\&=(8.12+5.27)\times10^{5}\\&=13.39\times10^{5}\\&=1.339\times10^{6}\end{aligned}[/tex]
Therefore, the combined capacity of the pools is [tex]\fbox{\begin\\\ 1.339\times 10^{6}\text{ gallons}\\\end{minispace}}[/tex].
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Answer details:
Grade: Middle school
Subject: Mathematics
Chapter: Mensuration
Keywords: Capacity, gallons, pools, water, Olympic size, smaller, combined capacity, mensuration, addition.
PLEASE HELP!
Write an algebraic expression for 9 groups of w
It is 9w hope this helps
Determine the length of the hypotenuse
21^2 + 28^2 = Hypotenuse^2
441 + 784 = 1225
sqrt (1225) = 35
hypotenuse = 35
Evaluate the expression and prove your answer by using a model. 5/8 divide by 1/2
Identify the type of function represented by f(x)=3/8(4)^x
A. Exponential Growth
B. Quadratic
C.Linear
D.Exponential Decay
In Apex its A. Exponetial Growth
Answer:
Option A - Exponential Growth
Step-by-step explanation:
Given : [tex]f(x)=\frac{3}{8} (4)^x[/tex]
To find : Identify the type of function given ?
Solution :
The given function is in the form [tex]f(x)=ab^x[/tex]
This form is an exponential form in which a is the initial value and b is the growth/decay rate factor.
If we compare the given expression, [tex]f(x)=\frac{3}{8} (4)^x[/tex]
The initial value is [tex]a=\frac{3}{8}[/tex]
and the growth/decay rate factor [tex]b=4[/tex]
Since b>1 then it is a growth factor.
Refer the attached figure below.
Therefore, Option A is correct.
The function [tex]f(x)=\frac{3}{8} (4)^x[/tex] is an exponential growth function.
Which number supports the given conjecture?
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A.
19
B.
54
C.
87
D.
109
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The original vertices of the triangle is at A(4, 4), B(2, 4) and C(3, 1)
Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, rotation, reflection and dilation.
Rotation is the rotation of a figure about a point. If point A(x, y) is rotation 180 degrees about the origin, the new point is at A'(-x, -y).
Given the vertices of the final triangle are A'(-4,-4), B'(-2, -4), and C'(-3, -1) after a 180 degrees rotation. Therefore the original vertices of the triangle is:
A(4, 4), B(2, 4) and C(3, 1)
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At the market, 8 batteries cost $10 .How much do 6 batteries cost
divide 10 by 8 to get price per battery
10/ 8 =1.25 per battery
now multiply 1.25 x 6 for total
1.25 * 6 = $7.50 for 6 batteries
Given that eight batteries cost $10, six batteries will cost $7.5
How much do 6 batteries cost?Given that;
8 batteries cost $101 battery = ?If 8 batteries cost $10, 1 battery will be;
1 battery = $10 / 8
1 battery = $1.25
Now, given that;
1 battery cost $1.256 batteries = ?If 1 battery cost $1.25, 6 batteries will be;
6 batteries = $1.25 × 6
6 batteries = $7.5
Given that eight batteries cost $10, six batteries will cost $7.5.
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How to multiply fractions
Hello There!
To multiply fractions, you first want to line up the numerator and the denominator together so they line up with each other.
Next, you want to multiply across. This includes multiplying the numerators together and then multiplying the denominators together.
Finally, you want to find the greatest common factor but only if the fraction can be simplified.
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Step-by-step explanation:
Answer is the third question
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What is an expression in mathematics?Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation. An expression's structure is as follows: Expression: (Math Operator, Number/Variable, Math Operator)
Given, The pace of the temperature decline has been steady. It dropped 15 degrees in 3 hours. Hence
in three hours temperature drops by 15 degrees
in one hour temperature drops = 15/3 = 5 degrees
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Explanation:In the field of
Mathematics
, a circle is divided into an angle of 360 degrees or 100 percent. If we want to find out what percent of a circle is 2/5 of a circle, we need to perform a simple calculation.
Firstly, note that 1 whole circle (or 360 degrees) is equivalent to 100%.
When we say 2/5 of a circle, we are referring to 2/5 parts of the whole circle.
To find out what percent 2/5 of the circle is, we multiply 2/5 by 100%:
(2/5) * 100% = 40%
This means that 2/5 of a circle is 40% of the whole circle.
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Answer:
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Step-by-step explanation:
Damian wrote the number four and twenty three thousandths as 4.23 describe and correct hi number
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Answer:
a nonprofit organization
Step-by-step explanation:
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[tex] \text{The domain}\\2x-6\neq0\ \wedge\ 6x-18\neq0\to x\neq3\\\\\dfrac{x^2}{2x-6}=\dfrac{9}{6x-18}\\\\\dfrac{x^2}{2(x-3)}=\dfrac{9}{6(x-3)}\ \ \ |\cdot6\\\\\dfrac{3x^2}{x-3}=\dfrac{9}{x-3}\iff3x^2=9\ \ \ |:3\\\\x^2=3\to x=\pm\sqrt3 [/tex]
Answer:
A on edge/e2020
Step-by-step explanation:
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