At t=0, a rock is dropped from rest from the top of a building 256 ft high. With what velocity will it strike the ground? What is it acceleration

Answer: option c

Step-by-step explanation:

By definition, you can calculate the slope of  line by applying the formula shown below:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Then:

You can see that in the option C the equation of the slope is applied correctly:

[tex]\frac{9-(-3)}{1-(-2)}[/tex]

Where:

[tex]y_2=9\\y_1=-3\\\\x_2=1\\x_1=-2[/tex]

Then, you obtain the following value of the slope of the line:

[tex]m=\frac{9-(-3)}{1-(-2)}=4[/tex]

Answer: Your correct answer should be C, [tex]\frac{(9 - (-3))}{(1 - (-2))}[/tex]

Step-by-step explanation:

Recall the slope equation is: (y2 - y1)/(x2 - x1) or [tex]\frac{(y2 - y1)}{(x2 - x1)}[/tex]. You need two points: point one (x1, y1) and point two (x2, y2).

* The first answer choice is flawed because not only is it in a different formula (xs are in the numerator instead of the denominator area), but it says 1 - 2 when it should be 1 - (-2) or 1 + 2.

* The second answer choice is flawed because it is in a different formula (this time, x1 - x2/y3 - y2) and 2 - 1 is suppose to be -2 - 1.

* The last answer is flawed because it should be -3 - (-) 11 and -2 - (-)4, or -3 + 11 and -2 + 4.

Note: If you had a negative operation and a negative number behind it, you can either formulate the equation like x - (-) y or drop the negative sign from said number and change the minus operation sign to the plus one (x + y).

The only answer choice that checks out and is not flawed is C.

1<x<6 or its x>1 and x>6

The solution to the compound inequality is given by:

                       [tex]1\leq x<6[/tex]

The compound inequality is given by:

[tex]3x-8\geq -5[/tex] and

[tex]2x-7<5[/tex]

[tex]3x-8\geq -5[/tex]

on adding both side of the inequality by 8 we get:

[tex]3x\geq -5+8\\\\i.e.\\\\3x\geq 3[/tex]

Now on dividing both side of the inequality by 3 we get:

[tex]x\geq 1[/tex]

[tex]2x-7<5[/tex]

On adding both side of the inequality by 7 we get:

[tex]2x<5+7\\\\i.e.\\\\2x<12[/tex]

on dividing both side of the inequality by 2 we get:

[tex]x<6[/tex]

Hence, the solution of the compound inequality is:

                    [tex]1\leq x<6[/tex]

Answer:

13 / 204; No, they are dependent events

Step-by-step explanation:

Total number of cards in the deck = 52

Total number of spades in the deck = 13

Total number of hearts in the deck = 13

Part 1: Calculating the Probability

Picking up the first card:

When picking the first card i.e spade, we have the option to pick 13 cards out of 52. So the probability will be 13/52

When first card is picked, the total number of cards will be reduced to 51 because we are not placing the card back in the deck

Picking up the second card:

When picking up the second card i.e. heart, we have the option to pick 13 cards out of 51. So the probability will be 13/51

The probability of picking a spade and then a heart is = 13/52 x 13/51 = 13/204

Part 2: Independent or Not

Note that, picking up a spade and not replacing it back is changing the probability of picking up a heart. In normal cases, picking up a heart from a deck will have the probability of 13/52, but since the we are not placing the card back the probability is changed to 13/51

Since, the probability of picking a heart is being changed by the previous event, we say that the two events are dependent.

Therefore, the correct answer will be final option: 13 / 204; No, they are dependent events

Answer:

The correct answer option is P (both green) = 91 / 435

Step-by-step explanation:

We are given that in a jar containing 30 marbles, 10 are red, 6 are black and 14 are green.

Two marbles are drawn and the second one is drawn without returning the first marble and we are to find the probability of getting green marbles both time.

P (both green) = [tex] \frac { 1 4 } { 3 0 } \times \frac { 1 3 } { 2 9 } [/tex] = 91 / 435

the next step would be add x to both sides to get x isolated

Answer:

i thought it was a but its b

Step-by-step explanation:

got it right on my test

Answer is C

If x=0, f(x) (or y) is 2^(0+2)=2²=4

So find the graph that runs through the point (0,4)

Graph C is the graph that represents the exponential function f(x) = 2ˣ⁺²

Which graph matches the function?

We want to find the graph that matches the function:

f(x) = 2ˣ⁺²

First, we can see that when x = 0 we have:

f(0) = 2² = 4

So we need to find the graph that intercepts the y-axis at y = 4. From the given options we can see a single graph that does that, which is option B, so we can conclude that B is the correct option.

Answer:

60

Step-by-step explanation:

Since it turns 30 degrees each hour, it is simply 2 * 30 which is 60.

Answer:

6.63 cm

Step-by-step explanation:

The segments within the circle form a right angle. Triangle CRS as a right triangle must follow the Pythagorean theorem which says the square of each leg adds to the square of the hypotenuse.

a² + b² = c²

Here a is unknown, b = 10 and c = 12.

a² + 10² = 12²

a² + 100 = 144

a² = 44

a = √44 = 6.63

Answer:

y = -1/2 x

Step-by-step explanation:

Follow the directions "Complete the steps to write the equation of direct variation. Start with the equation of direct variation y = kx. Substitute in the given values for x and y to get . Solve for k to get . Write the direct variation equation with the value found for k."

y = kx substitute y = -4 and x = 8.

-4 = k*8

-4/8 = k

-1/2 = k

So the equation is y = -1/2(x).

Answer:

1. Start with the equation of direct variation y = kx.

2.Substitute in the given values for x and y to get: -4=k(8)

3. Solve for k to get: -1/2

4. Write the direct variation equation with the value found for k. The equation is: y=(-1/2)x

Step-by-step explanation:

I just did it on e2020

To create 16.25 gallons of a certain shade of blue paint, based on a ratio of 1.5 quarts of blue to 5 quarts of white, one would need to mix 15 quarts of blue paint with 50 quarts of white paint.

The student is asking how to scale a recipe for paint, which involves a ratio of blue paint to white paint, to create a specific amount of a new shade of blue. Given that the original ratio is 1.5 quarts of blue paint to 5 quarts of white paint, and the goal is to mix up 16.25 gallons of this shade, we need to calculate the amount of each color needed.

Step-by-Step Explanation:

First, identify the total number of quarts needed since the question includes quarts and gallons. Since there are 4 quarts in a gallon, multiply 16.25 gallons by 4 to convert to quarts.
16.25 gallons  imes 4 = 65 quarts

Next, calculate the ratio of blue to total quarts, and white to total quarts. The original recipe has 1.5 quarts of blue paint out of a total of 6.5 quarts, as 1.5 quarts of blue plus 5 quarts of white equals 6.5 quarts.

Determine the proportions: Blue Paint = (1.5 / 6.5) times Total Quarts and White Paint = (5 / 6.5) times Total Quarts.

Calculate the required amounts: Blue Paint = (1.5 / 6.5) times 65 quarts = 15 quarts and White Paint = (5 / 6.5) times 65 quarts = 50 quarts.

In conclusion, to mix 16.25 gallons of the shade of blue paint, 15 quarts of blue paint and 50 quarts of white paint are required.

You would need 19.5 quarts of blue paint and 65 - 19.5 = 45.5 quarts of white paint to make a total of 16.25 gallons of the shade of blue paint.

To find out how much of each color should be mixed, we first need to convert the total amount needed into quarts.

16.25 gallons * 4 quarts/gallon = 65 quarts

Now, since the ratio of blue paint to white paint is 1.5:5, we can set up a proportion to find out how much of each color should be used:

1.5/5 = x/65

Cross multiplying:

5x = 1.5 * 65

5x = 97.5

x = 97.5 / 5

x = 19.5

So, you would need 19.5 quarts of blue paint and 65 - 19.5 = 45.5 quarts of white paint to make a total of 16.25 gallons of the shade of blue paint.

Answer:

A) 0.335; B) 0.343; C) 0.599

Step-by-step explanation:

For part A,

To find the probability that the user has more than one infection per year, we can either add together the probabilities for 2, 3, 4 and 5; or we can add together the probabilities for 0 and 1 and subtract them from 1:

1-(P(X = 0)+P(X = 1))

= 1-(0.343+0.322) = 1-0.665 = 0.335

For part B,

The probability that the user has no infections per year is P(X = 0); this is 0.343.

For part C,

The probability that the user has between 1 and 3 infections (inclusive) per year is

P(1 ≤ X ≤ 3) = 0.322+0.201+0.076 = 0.599

The probabilities are as follows: A. An echinacea user is likely to experience more than one infection per year with probability 0.335. B. The likelihood of an echinacea user having no infections per year is 0.343. C. The probability that an echinacea user has between one and three infections, inclusive, is 0.599.

This question relates to probability distribution in mathematics. Here's how to find the probabilities:

https://brainly.com/question/32733554

#SPJ3

Answer:

The value of x = -0.46

Step-by-step explanation:

∵ [tex]4e^{5x}-e^{-x}=-3e^{2x}[/tex] ÷ [tex]e^{-x}[/tex]

∴ [tex]\frac{4e^{5x}}{e^{-x}}-\frac{e^{-x}}{e^{-x}}=\frac{-3e^{2x}}{e^{-x}}[/tex]

* Subtract the power of the same bases

∴ [tex]4e^{6x}-1=-3e^{3x}[/tex]

* Let [tex]e^{3x}=y[/tex]

∴ [tex]e^{6x}=y^{2}[/tex]

∴ 4y² - 1 = -3y

∴ 4y² + 3y - 1 = 0 ⇒ factorize

∴ (4y - 1)(y + 1) = 0

∴ y + 1 = 0 ⇒ y = -1

∴ 4y - 1 = 0 ⇒ 4y = 1 ⇒ y = 1/4

∵ [tex]y=e^{3x}[/tex]

∴ y = -1 refused ([tex]e^{ax}[/tex] never gives -ve value)

∴ [tex]e^{3x}=1/4[/tex] ⇒ insert ln in both sides

∵ [tex]lne^{ax}=axln(e)=ax[/tex] ⇒ ln(e) = 1

∴ 3xln(e) = ln(1/4)

∴ 3x = ln(1/4)

∴ x = [ln(1/4)] ÷ 3 = -0.46

First set up birds is +3 than 2x the number of birds Rhonda saw

Rhonda's birds = r

Current set of birds = c

c = 2r + 3

Current birds are equal to three more than double the amount of birds rhonda saw

Answer:

B. -12

Step-by-step explanation:

The given limit are;

[tex]\lim_{x \to -11} f(x)=-3[/tex] and [tex]\lim_{x \to -11} g(x)=4[/tex]

We want to find;

[tex]\lim_{x \to -11} (fg)(x)=\lim_{x \to -11} f(x)\times \lim_{x \to -11} g(x)[/tex]

We substitute the given limits to obtain;

[tex]\lim_{x \to -11} (fg)(x)=-3\times 4[/tex]

[tex]\lim_{x \to -11} (fg)(x)=-12[/tex]

Answer:

B

Step-by-step explanation: EDGE 2020

Answer:

In repeated sampling, 95% of the intervals constructed would contain the population mean.

Answer:

The number of adult tickets sold is a=202\ tickets

The number of student tickets sold is c=310\ tickets

Step-by-step explanation:

c------>  the number of student tickets sold

a----->  the number of adult tickets sold

we know that

a+c=512 -----> equation A

5c+10a=3,70-----> equation B

therefore

the solution is

the number of adult tickets sold is a= 202 tickets

the number of student tickets sold is c= 310 tickets

Answer:

Step-by-step explanation: If w is hours at Westside, then (18-w) is the number of hours taken at Pinewood.

Cost to westside = 98w. Cost to Pinewood = 115(18-w).

Total cost = 98w + 115(18 - w) = 2070 - 17w.

[I guess there should be some constraints like 0 > w > 18]

I put it as "greater than" rather than "greater than or equal" because the problem states he takes classes at both schools, hence he has to take at least something at Westside, and similarly he has to take something at Pinewood so he would not take all 18 hours at Westside.

Answer:

98 × w + $115(19-w)

Step-by-step explanation:

We are given that Alan takes classes at both Westside Community College, where class fees are $98 per credit hour, and Pinewood Community College, where class fees are $115 per credit hour.

If Alan is taking a total of 19 credit hours at the two mentioned schools, we are to write an expression for the combined total dollar amount he paid for his class fees.

Considering the fees per credit hour mentioned for each school, we can write the total payed fees as:

[tex]98 \times w + $115(19-w)[/tex]

Answer:

5 foot 8

Step-by-step explanation:

ANSWER

y=7

EXPLANATION

The horizontal asymptote of an exponential function

[tex]f(x)= a {(b)}^{x} + c[/tex]

is y=c.

The given exponential function is

[tex]f(x)= 4 {(52)}^{x} + 7[/tex]

When we compare to

[tex]f(x)= a {(b)}^{x} + c[/tex]

c=7, therefore the horizontal asymptote is y=7.

See the attached picture:

did you mean to put. y= -1/2x+2 for choice b? because that's what I got as a solution

[tex]f'(x)\ge0[/tex] for all [tex]x[/tex] in [-3, 0], so [tex]f(x)[/tex] is non-decreasing over this interval, and in particular we know right away that its minimum value must occur at [tex]x=-3[/tex].

From the plot, it's clear that on [-3, 0] we have [tex]f'(x)=-x[/tex]. So

[tex]f(x)=\displaystyle\int(-x)\,\mathrm dx=-\dfrac{x^2}2+C[/tex]

for some constant [tex]C[/tex]. Given that [tex]f(0)=7[/tex], we find that

[tex]7=-\dfrac{0^2}2+C\implies C=7[/tex]

so that on [-3, 0] we have

[tex]f(x)=-\dfrac{x^2}2+7[/tex]

and

[tex]f(-3)=\dfrac52=2.5[/tex]

Answer:

Part 1) [tex]m<ECF=90\°[/tex]

Part 2) [tex]m<AKB=77.5\°[/tex]

Part 3) [tex]m<ACF=75\°[/tex]

Step-by-step explanation:

Part 1) Find the measure of angle ECF

we know that

CF is tangent at point C

so

the radius EC is perpendicular to the tangent CF

therefore

[tex]m<ECF=90\°[/tex]

Part 2) Find the measure of angle AKB

we know that

The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite

[tex]m<AKB=\frac{1}{2}(arc\ AB+arc\ DC)[/tex]

substitute the values

[tex]m<AKB=\frac{1}{2}(50\°+105\°)=77.5\°[/tex]

Part 3) Find the measure of angle ACF

we know that

The inscribed angle is half that of the arc it comprises

[tex]m<ACF=\frac{1}{2}(arc\ AB+arc\ BF)[/tex]

substitute the values

[tex]m<ACF=\frac{1}{2}(50\°+100\°)=75\°[/tex]

Answer:

∠ ECF = 90°

∠AKB = 77.5°

∠ACF = 75°

Step-by-step explanation:

The given figure is a circle E.

Line CF is tangent at point C.

(1) To find measures of angle ECF

Since line FC is tangent at point C and radius ECis always perpendicular to the tengent.

So ∠ ECF = 90°

(2) Measure of angle AKB

By theorem of angle formed by two interesting chords.

∠ AKB = [tex]\frac{1}{2}[/tex] (arc AB + arc CD)

= [tex]\frac{1}{2}[/tex] (50 + 105) = [tex]\frac{1}{2}(155)[/tex]

∠AKB = 77.5°

(3) Measure of angle ACF

Since tangent chord angle = [tex]\frac{1}{2}[/tex] (intercepted arc)

m (∠ACF) = [tex]\frac{1}{2}[/tex] (m arc AB + m arc BC)

= [tex]\frac{1}{2}(50+100)[/tex]

[tex]\frac{1}{2}(150)[/tex]

∠ACF = 75°

Answer:The Time (period) is 0.003 s

Step-by-step explanation:

The period is equal to Time.

the formula for calculating Time (period) is:

Time (period)= 1/frequency

frequency= 293 hz

Time (period) = 1/293

                      = 0.003 s

Answer:

Period = 0.0034 seconds

Step-by-step explanation:

It is given that,

The d string on a violin has a frequency of 293 Hz when it is in tune. We have to find its period. The relationship between the time period and the frequency is given by :

[tex]T=\dfrac{1}{\nu}[/tex]

Here, [tex]\nu=293\ Hz[/tex]

So,

[tex]T=\dfrac{1}{293\ Hz}[/tex]  

T = 0.0034 seconds

Hence, the period of the d string on a violin is 0.0034 seconds.

Answer:

y = -3

Step-by-step explanation:

First, subtract 44 from both sides of the equation to set it equal to 0. This will give you 6 + 2y = 0. Then, subtract 6 from both sides, leaving you with 2y = -6. Then just divide both sides by 2 to isolate the y and give you your answer. -6 divided by 2 is -3. y = -3

Answer:

B) A rectangle with a length of 15 cm and a width of 9 cm

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

Verify each cases

case A) A rectangle with a length of 9 cm and a width of 6 cm

[tex]\frac{10}{9}\neq \frac{6}{6}[/tex]

therefore

The rectangle case A) is not similar to rectangle A

case B) A rectangle with a length of 15 cm and a width of 9 cm

[tex]\frac{10}{15}=\frac{6}{9}[/tex]

[tex]\frac{2}{3}=\frac{2}{3}[/tex]

therefore

The rectangle case B) is  similar to rectangle A

case C) A rectangle with a length of 14 cm and a width of 7 cm

[tex]\frac{10}{14}\neq \frac{6}{7}[/tex]

therefore

The rectangle case C) is not similar to rectangle A

case D) A rectangle with a length of 12 cm and a width of 8 cm

[tex]\frac{10}{12}\neq \frac{6}{8}[/tex]

therefore

The rectangle case D) is not similar to rectangle A

Answer:

A rectangle with a length of 15 cm and a width of 9 cm.

Step-by-step explanation:

In similar rectangles, the ratios of the corresponding sides are equal.In similar rectangles, the ratios of the corresponding sides are equal.

[tex]\frac{length}{width}[/tex] → [tex]\frac{10}{6}[/tex] = [tex]\frac{5}{3}[/tex]  and [tex]\frac{15}{9}[/tex] = [tex]\frac{5}{3}[/tex]

Answer:

p:a

Step-by-step explanation:

given: AB=c, BC=a, CA=b

          PQ=r, QP=p, PR=q

  also , ∠CAB ≅ ∠RPQ,--------- (1)

          , ∠ABC ≅ ∠RQP,---------(2)

    and, ∠ACB ≅ ∠QRP,---------(3)

FROM (1), (2) AND (3),

we can say that a=p, b=q, c=r

therefore, the triangles are congruent (S.S.S congruence criteria),

also then, r:c=1

then the ratio equal to r:c, will be p:a ( since p=a and p:a would be =1)    

Answer:

i believe that the answer is P:A if it is not I'm sorry

Step-by-step explanation:

360 is the answer for sure

Answer:

Choice B is correct

Step-by-step explanation:

The eccentricity of the conic section is given as 4 and thus the conic section is a hyperbola. Hyperbolas are the only conic sections with an eccentricity greater than 1.

Next, the directrix of this hyperbola is located at y = -6 implying that the hyperbola will be opening upwards. Consequently, the polar equation of this hyperbola will be of the form;

[tex]r=\frac{k}{1-4sin(theta)}[/tex]

The value of k in the numerator is the product of eccentricity and the absolute value of the directrix;

k= 4*6 = 24

The polar equation is thus given by alternative B

Answer:

B

Step-by-step explanation:

edge

Answer:

4

Step-by-step explanation:

Given in the question a logarithm expression

[tex]7^(log_{49}16 )[/tex]

We will use Exponent of Log Rule

[tex]b^(log_{b}k ) = k[/tex]

here b = 7

        k = 16

So suppose

[tex]7^(log_{49}16 ) = x\\Take square on both sides\\(7^(log_{49}16 ) )^{2} = x^2\\49^(log_{49}16)= x^2[/tex]

Now, according to the rule

16 = x²

to find x only take square root on both sides of the equation

x = √16

x = 4

so [tex]7^(log_{49}16 )[/tex] = 4