Answer:
a. x² + x - 30 = (x + 6)(x - 5)
b. -3x² + 23x - 14 = -[(3x - 2)(x - 7)]
c. 2x² - 5x + 4 can not factorize by this way
d. 6x² + 10x - 24 = 2[(3x - 4)(x + 3)]
Step-by-step explanation:
* To factor a trinomial in the form ax² ± bx ± c:
- Look at the c term
# If the c term is positive
∵ c = r × s ⇒ r and s are the factors of c
∴ r and s will have the same sign (sign of b)
∵ a = h × k ⇒ h , k are the factors of a
∴ rk + hs = b
∴ (hx + r)(kx + s) ⇒ if b +ve OR (hx - r)(kx - s) ⇒ if b -ve
# If the c term is negative
∵ c = r × s ⇒ r and s are the factors of c
∴ r and s will not have the same sign
∵ a = h × k ⇒ h and k are the factors of a
∴ rk - hs = b OR hs - rk = b
(hx + r)(kx - s) OR (hx - r)(kx + s)
* Now lets solve the problem
a. x² + x - 30
∵ ax² + bx + c
∴ a = 1 , b = 1 , c = -30
∵ c is negative
∴ r and s have different signs
∵ a = h × k
∵ 1 = 1 × 1
∴ h = 1 , k = 1
∵ c = r × s
∵ c = -30
∴ r × s = -30
∵ 6 × -5 = -30
∴ r = 6 , s = -5
∴ hs = 6
∴ rk = -5
∵ hs - rk = 6 - 5 = 1 ⇒ same value of b
∴ (x + 6)(x - 5)
* x² + x - 30 = (x + 6)(x - 5)
b. -3x² + 23x - 14 ⇒ take -1 as a common factor
∴ -(3x² - 23x + 14)
∵ ax² + bx + c
∴ a = 3 , b = -23 , c = 14
∵ c is positive
∴ r and s have same sign (-ve) because b is negative
∵ a = h × k
∵ 3 = 3 × 1
∴ h = 3 , k = 1
∵ c = r × s
∵ 14 = 2 × 7
∴ r = 2 , s = 7
∴ hs = 3 × 7 = 21
∴ rk = 2 × 1 = 2
∵ hs + rk = 21 + 2 = 23 ⇒ same value of b
∴ (3x - 2)(x - 7)
* -3x² + 23x - 14 = -[(3x - 2)(x - 7)]
c. 2x² - 5x + 4
∵ ax² + bx + c
∴ a = 2 , b = -5 , c = 4
∵ c is positive
∴ r and s have same sign (-ve) because b is negative
∵ a = h × k
∵ 2 = 2 × 1
∴ h = 2 , k = 1
∵ c = r × s
∵ 4 = 2 × 2
∴ r = 2 , s = 2
∴ hs = 2 × 2 = 4
∴ rk = 2 × 1 = 2
∵ hs + rk = 4 + 2 = 6 ⇒ not same value of b
∴ We can not factorize it
* 2x² - 5x + 4 can not factorize by this way
d. 6x² + 10x - 24 ⇒ take 2 as a common factor
∴ 2(3x² + 5x - 12)
∵ ax² + bx + c
∴ a = 3 , b = 5 , c = -12
∵ c is negative
∴ r and s have different signs
∵ a = h × k
∵ 3 = 3 × 1
∴ h = 3 , k = 1
∵ c = r × s
∵ -12 = -4 × 3
∴ r = -4 , s = 3
∴ hs = 3 × 3 = 9
∴ rk = -4 × 1 = -4
∵ hs - rk = 9 - 4 = 5 ⇒ same value of b
∴ (3x - 4)(x + 3)
* 6x² + 10x - 24 = 2[(3x - 4)(x + 3)]
rahm spent 2 1\2 hoirs writing a n essay. it took hime 4 times as long to finish his science project. how long did it take him to complete both the essay and the science project?
Rahm spent 2 1/2 hours writing an essay and 4 times longer on his science project, totaling 12.5 hours for both.
Explanation:Rahm spent 2 1/2 hours writing an essay. Since it took him 4 times as long to finish his science project, we calculate the time spent on the science project by multiplying 2.5 (which is the decimal equivalent of 2 1/2 hours) by 4. This gives us 10 hours for the science project. To determine how long it took him to complete both the essay and the science project, we add the time spent on both activities:
Time spent on essay: 2.5 hoursTime spent on science project: 10 hoursThe total time Rahm spent on both the essay and the science project is 12.5 hours.
Find the slope of the line on the graph.
Write your answer as a fraction or a whole
number, not a mixed number or decimal.
Answer:
-1/3
Step-by-step explanation:
You can do rise over run, and, in this case is going to be 1\3.
The slope of the line is 1.
To do this, we'll use the coordinates of two points on the line: Point 1 at (0,6) and Point 2 at (-6,0).
The slope of a line is given by the formula:
[tex]\[ m = \frac{{y_2 - y_1}}{{x_2 - x_1}} \][/tex]
1. Identify the coordinates:
- Point 1: [tex]\( (x_1, y_1) = (0, 6) \)[/tex]
- Point 2: [tex]\( (x_2, y_2) = (-6, 0) \)[/tex]
2.Calculate the change in x and change in y:
- Change in x: [tex]\( x_2 - x_1 = -6 - 0 = -6 \)[/tex]
- Change in y:[tex]\( y_2 - y_1 = 0 - 6 = -6 \)[/tex]
3. Apply the slope formula:
[tex]\[ m = \frac{{y_2 - y_1}}{{x_2 - x_1}} = \frac{{-6}}{{-6}} = 1 \][/tex]
Therefore, the slope of the line is 1.
origami is the Japanese art of paper folding the diagram below represents an unfolded paper kabuto a samuri warriors helmet which of the following are pairs of congruen segments? check all that apply
Answer: FR and NR
NO and NM
RC and RO
Step-by-step explanation: just did it on apex. good luck!
Answer:
The correct options are A, C and D.
Step-by-step explanation:
The given figure shows an unfolded paper. It is a square sheet.
Here the line of symmetry are diagonals FN, AK and midline CM, OI. All of these lines are intersecting at point R.
Diagonals of square bisect each other, therefore R is midpoint of FN.
[tex]FR\cong NR[/tex]
[tex]AO\cong ON[/tex] (OI is line of symmetry)
[tex]PO\neq ON[/tex]
[tex]RC\cong RO[/tex] (AK is line of symmetry)
[tex]NO\cong NM[/tex] (FN is line of symmetry)
[tex]DV\cong HV[/tex] (FN is line of symmetry)
[tex]DV\neq EW[/tex]
Therefore the correct options are A, C and D.
In a freshman high school class of 80 students, 22 students take Consumer Education, 20 students take French, and 4 students take both. Which equation can be used to find the probability, P, that a randomly selected student from this class takes Consumer Education, French, or both?
Answer:
First subtract the number of students who take both subjects from the number of students who take Consumer Education
22-4=18
Then,
subtract the number of students who take both subjects from the number of students who take French
20-4=16
Now,
Add 18,16 and 4 and subtract the sum from the total number of students in the class
=80-(18+16+4)
=80-38
=42
Step-by-step explanation:
Answer: P= 11/40 + 1/4 + 1/20
Rotation 90 clokwise HELP PLEASE
Answer:
Step-by-step explanation:
I assume you want to rotate each point about the origin.
To rotate a point (x, y) 90° clockwise about the origin:
(x, y) → (y, -x)
For point A:
(-5, 0) → (0, 5)
For point B:
(-5, 3) → (3, 5)
For point C:
(0, 4) → (4, 0)
Having trouble with add or subtracting the given polynomials
7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
Problem 7:
(2b² + 7b² + b) + (2b² - 4b - 12)
= 11b²-3b-12
Problem 8:
(7g³ + 4g - 1) + (2g² - 6g + 2)
= 7g³ + 2g² - 2g + 1
if 5lb of cheese cost 18.50, how much would 1 lb cost
Answer:
3.70
Step-by-step explanation:
18.50 ÷ 5 = 3.70
fairly simple math but can be confusing depending upon how its asked, you just have to find the words that describe what you have to do and check your math to make sure
How do I simplify this?
Answer:
(c) 9x^2.
Step-by-step explanation:
(a) and (b) are correct.
(c) (3x)^2 = 3^2 * x^2
= 9x^2.
The table below shows the three-day rain forecast
for Friday, Saturday and Sunday in Aberystwyth.
Day Probability of rain
Friday
70%
Saturday
70%
Sunday
70%
a) Work out the probability that it will rain on all three days.
b) Work out the probability that it will rain on exactly two consecutive days.
Answer:
a=0.343
Step-by-step explanation:
70/100=0.7
0.7x0.7x0.7=0.343
Iola has $75. She buys a pair of shoes on sale for one-half off and a pair of socks for $6. She has $32 left. Which equation can be used to find x, the regular price of the shoes?
The correct equation to find the original price of the shoes that Iola bought is [tex]\frac{x}{2}[/tex] + 6 + 32 = 75, where x represents the regular price of the shoes.
The student is looking for an equation to find the regular price of the shoes that Iola bought. Since Iola has $32 left after buying the shoes and socks, and the socks cost $6, we can state that she spent $75 - $32 - $6 on the shoes on sale. If we represent the regular price of the shoes as x, then the sale price is [tex]\frac{x}{2}[/tex]. The equation that represents this scenario is:
[tex]\frac{x}{2}[/tex] + 6 + 32 = 75
taxidistance between (0,0) and (7,3)
For this case we have that by definition, the distance between two points is given by:
[tex]d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}[/tex]
We have to:
[tex](x_ {1}, y_ {1}) = (0,0)\\(x_ {2}, y_ {2}) = (7,3)[/tex]
Substituting:
[tex]d = \sqrt {(7-0) ^ 2 + (3-0) ^ 2}\\d = \sqrt {(7) ^ 2 + (3) ^ 2}\\d = \sqrt {49 + 9}[/tex]
[tex]d = \sqrt {58}\\d = 7.62[/tex]
ANswer:
[tex]d = 7.62[/tex]
Answer:
The Answer Is 10.
Step-by-step explanation:
| x2-x1 | + | y2-y1 | = taxidistance.
(0, x1), (0, y1), (7, x2), (3, y2)
Substitute.
| 7-0| + | 3-0 | = 10
Give the scale factor, perimeter ratio, and area ratio of figure A to figure B
Answer:
Scale factor: 4/7
perimeter ratio: 4:7
area: I don't know the height of the two
Step-by-step explanation:
How many one-thirds are there in three-fourths?
Answer:
there are 2.25 one-thirds in a three-fourth.
Hope this helps you out!
In the given Fractions there are 2 and 1/4 (or 2.25) one-thirds in three-fourths.
To find out how many one-thirds are in three-fourths, we need to represent both fractions using a common denominator. In this case, we can see that the smallest common denominator is 12.
So, we can convert both fractions to twelfths by multiplying the numerator and denominator of one-third by 4, and the numerator and denominator of three-fourths by 3. This gives us:
1/3 = 4/12
3/4 = 9/12
Now, we can simply divide the numerator of three-fourths by the numerator of one-third to get our answer:
(9/12) ÷ (4/12) = (9/12) × (12/4) = 27/4 = 2.25
Therefore, there are 2 and 1/4 (or 2.25) one-thirds in three-fourths.
In conclusion, determining how many one-thirds are there in three-fourths requires us to represent both fractions using a common denominator and then dividing the numerator of three-fourths by the numerator of one-third. The answer is 2.25
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Each year a town holds a winter carnival this year 40% of the attendees were children under the age of 10 if 304 children under the age of 10 attended the carnival how many attendees were there
Answer:
760 attendees
Step-by-step explanation:
40% of the attendees is 304. That means you can add 304 to 304 (304 x 2) to get 608. To get the last 20%, divide 304 by 2, because 40(%) divided by 2 is 20(%). The answer to that is 152. Now, add it all up. 608 + 152 = 760.
In conclusion, there were 760 attendees at the carnival.
144^14/144^2
A.144^16
B.144^12
C.144^28
D.144^14/244^2
Answer:
B. 144^12
Step-by-step explanation:
[tex]{144}^{14} \div {144}^{2} \\ = {144}^{14 - 2} \\ = {144}^{12} [/tex]
The simplified exponent form of the given expression 144^14/144^2 would be 144^12.
What are exponential functions?When the expression of function is such that it involves the input to be present as an exponent (power) of some constant, then such function is called exponential function. There usual form is specified below. They are written in several such equivalent forms.
The given expression can be solved by exponentially
[tex]\dfrac{144^{14}}{144^2}\\\\144^{14} \times144^{-2}}\\\\144^{14-2} \\\\144^{12}[/tex]
Therefore the simplified exponent form of the given expression would be 144^12.
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Justin walked his dog 5 miles in
5
4 hours. How many miles per hour did Justin and his dog walk?
Answer:
Is the 5 separate or to gather like 45
Justin and his dog walked at approximately 0.093 miles per hour.
Explanation:To find the number of miles per hour, Justin and his dog walked, we need to divide the total distance walked (5 miles) by the total time taken (54 hours). So, 5 miles / 54 hours = 0.093 miles per hour.To find out how many miles per hour Justin and his dog walked, we need to divide the total distance walked by the total time spent. In this case, Justin walked 5 miles in 54 hours. Therefore, the speed is calculated as follows: 5 miles ÷ (54) hours = 4 miles per hour. This means Justin and his dog walked at a speed of 4 miles per hour.
Therefore, Justin and his dog walked at approximately 0.093 miles per hour.
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Someone please answer this
The two lines with the equations are the same length.
Set the two equations to equal and solve:
3x +3 = 6x - 57
Add 57 to each side:
3x +60 = 6x
Subtract 3x from each side:
60 = 3x
Divide both sides by 3:
x = 20
Answer:
x= 20
Step-by-step explanation:
Jane had R Beanie Babies. She gave 8 of them to her friend. Later her grandma bought her 5 more Beanie Babies than she had in the beginning. How many Beanie Babies did Jane have in the beginning, if now she has 27 of them?
Jane had 10 Beanie Babies in the beginning.
The number of Beanie Babies Jane had in the beginning.
- She gave 8 to her friend, leaving her with [tex]\( x - 8 \)[/tex] Beanie Babies.
- Her grandma bought her 5 more, so she then had [tex]\( x + 5 \)[/tex] Beanie Babies.
- Combining the Beanie Babies she had at the beginning, the ones she gave away, and the ones her grandma bought her, the total is 27.
- Solving the equation [tex]\( x - 8 + (x + 5) = 27 \)[/tex], we find [tex]\( x = 10 \)[/tex], the number of Beanie Babies Jane had in the beginning.
Jane had 20 Beanie Babies in the beginning.
To calculate:
1. Let's denote the number of Beanie Babies Jane had in the beginning as [tex]\( x \).[/tex]
2. She gave 8 of them to her friend, leaving her with [tex]\( x - 8 \)[/tex] Beanie Babies.
3. Her grandma bought her 5 more Beanie Babies than she had in the beginning, so she now has [tex]\( x + 5 \)[/tex] Beanie Babies.
4. Given that she now has 27 Beanie Babies, we can set up the equation:
[tex]\[ x - 8 + (x + 5) = 27 \][/tex]
Now, let's solve for [tex]\( x \):[/tex]
[tex]\[ 2x - 3 = 27 \][/tex]
[tex]\[ 2x = 30 \][/tex]
[tex]\[ x = 15 \][/tex]
However, this is the number of Beanie Babies Jane had after her grandma bought her 5 more. To find out how many she had in the beginning, we need to subtract 5 from [tex]\( x \):[/tex]
[tex]\[ x = 15 - 5 = 10 \][/tex]
So, Jane had 10 Beanie Babies in the beginning.
- Let [tex]\( x \)[/tex] be the number of Beanie Babies Jane had in the beginning.
- She gave 8 to her friend, leaving her with [tex]\( x - 8 \)[/tex] Beanie Babies.
- Her grandma bought her 5 more, so she then had [tex]\( x + 5 \)[/tex] Beanie Babies.
- Combining the Beanie Babies she had at the beginning, the ones she gave away, and the ones her grandma bought her, the total is 27.
- Solving the equation [tex]\( x - 8 + (x + 5) = 27 \)[/tex], we find [tex]\( x = 10 \)[/tex], the number of Beanie Babies Jane had in the beginning.
Complete question
Jane had R Beanie Babies. She gave 8 of them to her friend. Later her grandma bought her 5 more Beanie Babies than she had in the beginning. How many Beanie Babies did Jane have in the beginning, if now she has 27 of them?
Find an n-degree polynomial function with real coefficients satisfying the given condition.
1. n=3; 4 and 2i are zeros; f(-1)=50
2. n=3; 4 and -5+2i are zeros; f(2)= -636
3. n=4; -2, -1/2, and i are zeros; f(1)=18
4. n=4; -4, 1/3, and 2+3i are zeros; f(1)=100
5. n=4; 1+i and i are zeros; f(1)=2
In all cases, if [tex]f[/tex] has real coefficients, then any complex roots occur in conjugate pairs, so if [tex]a+bi[/tex] is a root, then so is [tex]a-bi[/tex]. Also, by the fundamental theorem of algebra, if [tex]r_1,\ldots,r_n[/tex] are roots to [tex]f[/tex], then for some constant [tex]a\in\mathbb R[/tex],
[tex]f(x)=a(x-r_1)\cdots(x-r_n)[/tex]
1. If [tex]n=3[/tex] and [tex]f(3)=f(2i)=0[/tex], then
[tex]f(x)=a(x-3)(x-2i)(x+2i)=ax^3-3ax^2+4ax-12a[/tex]
Given that [tex]f(-1)=50[/tex], we have
[tex]f(-1)=a(-1-3)(-1-2i)(-1+2i)=-20a=50\implies a=-\dfrac52[/tex]
[tex]\implies\boxed{f(x)=-\dfrac52x^3+\dfrac{15}2x^2-10x+30}[/tex]
2.
[tex]f(x)=a(x-4)(x-(-5+2i))(x-(-5-2i))=a x^3 + 6 a x^2 - 11 a x - 116 a[/tex]
With [tex]f(2)=-636[/tex], we have
[tex]f(2)=a(2-4)(2+5-2i)(2+5+2i)=-106a=-636\implies a=6[/tex]
[tex]\implies\boxed{f(x)=6x^3+36x^2-66x-696}[/tex]
The rest are done in the same exact way.
Find the common difference of the following arithmetic sequence 35,32,29,26...
Answer: they are all being subtracted by 3
Step-by-step explanation:
35-3=32
32-3=29
29-3=26
The common difference in the arithmetic sequence 35, 32, 29, 26... is 3.
To find the common difference in an arithmetic sequence, you subtract one term from the following term. In this case, the sequence is 35, 32, 29, 26... To find the common difference, subtract 32 from 35, which equals 3. Therefore, the common difference in this sequence is 3.
What is the expanded form of the series represented below?
A. -3 + 2 + 7 + 12 + 17
B. -3 + 3 + 8 + 13 + 18
C. 2 + 7 + 12 + 17 + 22
D. 5 + 2 + (-1) + (-4) + (-7)
Answer:
See below
Step.-by-step explanation:
Choice A has first term -3 and common difference 5. The formula for the kth term is -3 + (k - 1)5. It is an arithmetic series.
The required expanded form for the Sum is:
5
S5 = ∑ [-3 + (k - )5)]
k = 1
Answer:
Expanded form of the series is:
A. -3 + 2 + 7 + 12 + 17
Step-by-step explanation:
when k=1 -3+(k-1)5= -3
when k=2 -3+(k-1)5= -3+5=2
when k=3 -3+(k-1)5= -3+10=7
when k=4 -3+(k-1)5= -3+15=12
when k=5 -3+(k-1)5= -3+20=17
Hence, value of [tex]S_{5}= -3+2+7+12+17[/tex]
Hence, expanded form of the series is:
A. -3 + 2 + 7 + 12 + 17
What is the value of x
Answer:
x = 40
Step-by-step explanation:
According to the Supplementary Angles Theorem, set 4x - 20 and x equal to 180. Once done, combine like-terms to get 5x - 20 = 180. So, straight off the bat, we know that 5x has to equal 200 [bringing 20 over to the right side of the equivalence symbol], therefore 40 is equal to x.
I am joyous to assist you anytime.
Which of the following is not a property of the sample standard deviation s?
A. Sensitive to changes in the distribution
B. Calculated based on the mean
C. Larger than the population standard deviation o D. Resistant to extreme data values
E. All of the above.
The property of the sample standard deviation that is not accurate is 'D. Resistant to extreme data values'. The sample standard deviation is indeed sensitive to extreme data values. The other properties listed are true about the sample standard deviation.
Explanation:The property of the sample standard deviation (s) that is not accurate from the given options is 'D. Resistant to extreme data values'. The sample standard deviation is sensitive to extreme values, not resistant. In other words, if there are outliers or extreme values in the data, the sample standard deviation will tend to be larger, reflecting the increased variability.
Let's quickly review the other options for clarity. 'A. Sensitive to changes in the distribution' and 'B. Calculated based on the mean' are true properties of the sample standard deviation. The standard deviation, whether for a sample or a population, measures the spread or dispersion of the data points about the mean. Therefore, it changes with the distribution and is calculated based on the mean. 'C. Larger than the population standard deviation σ' is typically true, unless the sample perfectly represents the population.
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The sample standard deviation is C. larger than the population standard deviation o.
Explanation:The sample standard deviation, denoted as s, is a measure of spread that quantifies how much the data values deviate from the mean. It is calculated based on the mean. However, it is not necessarily larger than the population standard deviation, o, as it depends on the specific data set.
The other options are not correct:
A. The sample standard deviation is sensitive to changes in the distribution, as it considers the individual data values and their deviations from the mean.B. The sample standard deviation is calculated based on the mean, as it involves calculating the deviations of individual data values from the mean.D. The sample standard deviation is not resistant to extreme data values, as it considers each data value and its deviation from the mean.E. All of the above is not the correct answer, as the correct answer is C.
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#18 please help me thank you
Answer:
The solutions of the equation is 0 , π , 2π
Step-by-step explanation:
* Lets revise some identities in the trigonometry
- tan²x + 1 = sec²x
- tan²x = sec²x - 1
* Now lets solve the equation
∵ tan²x sec²x + 2sec²x - tan²x = 2
* Lets replace tan²x by sec²x - 1
∴ (sec²x - 1) sec²x + 2sec²x - (sec²x - 1) = 2 ⇒ open the brackets
∴ sec^4 x - sec²x + 2sec²x - sec²x + 1 = 2 ⇒ add the like terms
∴ sec^4 x -2sec²x + 2sec²x + 1 = 2 ⇒ cancel -2sec²x with +2sec²x
∴ sec^4 x + 1 = 2 ⇒ subtract 1 from both sides
∴ sec^4 x = 1 ⇒ take root four to both sides
∴ sec x = ± 1 ⇒ x is on the axes
∵ sec x = 1/cos x
∵ sec x = 1 , then cos x = 1
∵ sec x = -1 , then cos x = -1
∵ 0 ≤ x ≤ 2π
∵ x = cos^-1 (1)
∴ x = 0 , 2π ⇒ x is on the positive part of x-axis
∵ x = cos^-1 (-1)
∴ x = π ⇒ x is on the negative part of x-axis
* The solutions of the equation is 0 , π , 2π
5600 dollars is placed in an account with an annual interest rate of 8.5%. To the nearest year, how long will it take for the account value to reach 15000 dollars?
It takes about 20 years
It will take approximately 13 years for the account value to reach $15,000.
To find the time it takes for the account value to reach $15,000, we used the formula for compound interest and rearranged it to solve for [tex]\(t\).[/tex] Then, we substituted the given values into the formula and calculated the time to be approximately 12.82 years. Rounding to the nearest year gives us 13 years.
To calculate the time it takes for the account value to reach $15,000 with an annual interest rate of 8.5%, we can use the formula for compound interest:
[tex]\[A = P(1 + r/n)^{nt}\][/tex]
Where:
- [tex]\(A\)[/tex] is the future value of the investment/loan, including interest.
- [tex]\(P\)[/tex] is the principal investment amount (the initial deposit or loan amount).
- [tex]\(r\)[/tex] is the annual interest rate (in decimal).
- [tex]\(n\)[/tex] is the number of times that interest is compounded per year.
- [tex]\(t\)[/tex] is the time the money is invested for, in years.
In this case, [tex]\(P = 5600\)[/tex], [tex]\(A = 15000\)[/tex], [tex]\(r = 0.085\)[/tex] (8.5% expressed as a decimal), and [tex]\(n = 1\)[/tex] (compounded annually).
We need to solve for [tex]\(t\)[/tex], so rearranging the formula:
[tex]\[t = \frac{\log(A/P)}{n \cdot \log(1 + r/n)}\][/tex]
Substituting the given values:
[tex]\[t = \frac{\log(15000/5600)}{1 \cdot \log(1 + 0.085/1)}\][/tex]
[tex]\[t[/tex] ≈ [tex]\frac{\log(2.6786)}{\log(1.085)}[/tex]
[tex]\[t[/tex] ≈ [tex]\frac{0.4285}{0.0334}[/tex]
[tex]\[t[/tex] ≈ [tex]12.82[/tex]
To the nearest year, it will take approximately 13 years for the account value to reach $15,000.
To find the time it takes for the account value to reach $15,000, we used the formula for compound interest and rearranged it to solve for \(t\). Then, we substituted the given values into the formula and calculated the time to be approximately 12.82 years. Rounding to the nearest year gives us 13 years.
Complete question
5600 dollars is placed in an account with an annual interest rate of 8.5%. To the nearest year, how long will it take for the account value to reach 15000 dollars?
How do i solve this
Check the picture below.
using the 30-60-90 rule.
Use the given information to match the answers. ABC is a right triangle. 1. If a = 3 and c = 6, then b = 2. If a = 4 and b = 6, then c = 3. If b = 2 and c = 3, then a =
i need the answers quickly please
Final answer:
Using the Pythagorean theorem, we solved for the missing sides of a right triangle in three scenarios, finding b approximately as 5.20, c approximately as 7.21, and a approximately as 2.24.
Explanation:
To solve for the missing sides of a right triangle, we use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). The theorem is mathematically represented as a² + b² = c². Let's use this to solve the given problems.
For a = 3 and c = 6, to find b, we use the equation 3² + b² = 6². After calculation, b = √(36 - 9), which simplifies to b = √27 or approximately 5.20.
If a = 4 and b = 6, to find c, the equation is 4² + 6² = c². Solving for c gives us c = √(16 + 36), which is c = √52 or approximately 7.21.
For b = 2 and c = 3, to find a, we apply the formula a² + 2² = 3². This leads to a² = 9 - 4, so a = √5 or about 2.24.
Write a recursive formula for the sequence –2, 4, –8, 16, ...
please help and thank you
Answer:
see explanation
Step-by-step explanation:
A recursive formula allows us to calculate any term in the sequence from the previous term.
These are the terms of a geometric sequence with r being the common ratio between consecutive terms.
r = 4 ÷ - 2 = - 8 ÷ 4 = 16 ÷ - 8 = - 2
Multiplying a particular term by - 2 gives the next term in the sequence.
Hence recursive formula is
[tex]a_{n+1}[/tex] = - 2 [tex]a_{n}[/tex] with a₁ = - 2
-2,4,-8,16,...
a₁ = -2
a₂ = -2a₁
a₃ = -2a₂
..................
=> aₙ₊₁ = -2•aₙ, with a₁ = -2
Find the total surface area of this object.
Answer:
60
Step-by-step explanation:
Use the formula for the surface area and plug in the given numbers. See work for more.
PLEASE SOLVE
If 5a+3b=35 and a/b = 2/5 , what is the value of a?
(A) 14/5 (B) 7/2 (C) 5 (D) 7 (E) 9
Answer:
14/5
Step-by-step explanation:
So first i manipulated a/b= 2/5. i multiplied both sides by 5 making it 5a/b=2. Then i multiplied both sides by b making it 5a=2b. Then i substituted 2b into 5a+3b=35. Making it 2b+3b=35. then i simplified it making it 5b=35. Then i solved for b making it b=7. Then i substituted b into 5a+3b=35. So that it looked like this 5a+3*7=35. then it became 5a+21=35. Then you subtract 21 making it 5a=14. You then divide by 5 making it a=14/5
Answer:
[tex]a = \frac{14}{5} [/tex]
Step-by-step explanation:
[tex]5a + 3b = 35 \\ 3b = 35 - 5a \\ b = \frac{35}{3} - \frac{5}{3} a \\ put \: b\: = \frac{35}{3} - \frac{5}{3} a \: into \: \frac{a}{b} = \frac{2}{5} \\ \frac{a}{ \frac{35}{3} - \frac{5}{3} a} = \frac{2}{5} \\ \frac{a}{ \frac{35 - 5a}{3} } = \frac{2}{5} \\ \frac{3a}{35 - 5a} = \frac{2}{5} \\ 5(3a) = 2(35 - 5a) \\ 15a = 70 - 10a \\ 15a + 10a = 70 \\ 25a = 70 \\ a = \frac{70}{25} \\ a = \frac{14}{5} [/tex]