Answer:
Explanation:
Properties of DNA polymerase I:
Removes RNA primer and polymerizes nucleotides from 5' to 3' in okazaki fragments
3' to 5' exonuclease activity
5' to 3' exonuclease activity
Properties of DNA polymerase II. mainly in DNA repair
3' to 5' exonuclease activity
Elongates existing DNA strands
Polymerizes nucleotides from 5' to 3'
Properties of DNA polymerase III
elongates existing DNA strands
polymerizes nucleotides from 5' to 3'
3' to 5' exonuclease activity
For which of the following pairs does the molecule given as the first term on the left contribute to the synthesis of
the molecule that is the second term on the right?
Select one:
a fatty acid - starch
b. amino acid - protein
C. nucleotides - glycogen
d glucose - fat
e urea - DNA
Answer: B) amino acid - protein
Explanation:
From your experiences with the lawn and the butterfly garden, you can affirm that ________. higher biodiversity of plants means a lower biodiversity of animals pesticides need to be used to maintain a diversity of native species once natural habitats are altered or destroyed they can never be restored, even in part native plants are more likely than exotic species to support local herbivores native plant landscaping can be done so that no predators or parasites are present
Answer:
native plants are more likely than exotic species to support local herbivores native plant landscaping can be done so that no predators or parasites are present
native plants are more likely to support local herbivorous animals than are exotic plant species
Explanation:
Exotic species are known to perform well and survive/thrive due to the fact that they lack natural enemies in their new environment making it obvious that the native species will likely support more of local herbivores
a land manager proposes planting shrubs to help restore land damaged by erosion. describe a study or experiment that you could carry out to evaluate whether this proposal will work
Answer:
Yes, this proposal which was presented by a land manager will work.
Explanation:
Land with no vegetation has high rate of erosion as compared to those having more vegetative cover. This is because grasses, shrubs and trees have large root system in which soil particles stick to the roots which prevent erosion. If more vegetation is present in an area so these is very low chance of soil erosion due to wind and water. So the proposal which is presented by the land manager will work perfectly.
Pyruvate kinase catalyzes the transfer of a phosphoryl group from phosphoenolpyruvate to ADP in the last step of glycolysis, forming pyruvate in the process. Vertebrates have several isozymes of pyruvate kinase, which can be allosterically inhibited by compounds including ATP and acetyl-CoA. What is an effect of cAMP-dependent protein kinase (PKA) inactivation of the liver isozyme but not the muscle isozyme
Answer:
By inhibiting pyruvate kinase in the liver isoenzyme, the muscle will initiate the lactic acid fermentation process that will provide NAD to allow glycolysis
Final answer:
The effect of cAMP-dependent protein kinase A (PKA) inactivating the liver isozyme but not the muscle isozyme of pyruvate kinase is to conserve blood glucose levels during fasting by inhibiting liver glycolysis, while muscle glycolysis continues to function normally.
Explanation:
Pyruvate kinase is an enzyme crucial for the last step of glycolysis, facilitating the conversion of phosphoenolpyruvate (PEP) to pyruvate and producing ATP in the process. The isozyme found in the liver, known as L-PK, can be inactivated by PKA which is triggered by hormones like glucagon, signifying a state of fasting. This downregulation ensures that when energy or glucose is scarce, the liver conserves glucose and releases it into the bloodstream rather than using it for glycolysis internally. In contrast, muscle pyruvate kinase is not affected by PKA, allowing glycolysis to proceed in the muscles even during fasting.
While ATP serves as a negative allosteric regulator for both muscle and liver isozymes, reflecting a condition of high energy within the cell, the liver isozyme is regulated additionally through hormonal signals, coupling the body's metabolic state with the enzyme's activity. Dephosphorylation of the liver isozyme by phosphatase reactivates the enzyme, which is promoted by insulin after a carbohydrate-rich meal, signifying an ample glucose supply and energy abundance.
Write a complete step-by-step plan for dealing with broken glassware on the floor or lab table. Write your plan in list form in the order in which steps should be taken.
Answer:
Notify the teacher and follow his or her instructions.
Wash the cut with soap and water.
Treat the cut with antiseptic from the first-aid kit.
Put a bandage over the cut.
Explanation:
The step-by-step plan for dealing with broken glassware on the floor or lab table has been stated below:
1 tell the person in charge or the teacher
2 make sure u did not get cut
3 get the large pieces and put them into glass waist container
4 get broom or brush weep area and get small pieces depose in same place
5 take a wet wipe and cover area to pick up anything that as missed.
What is glassware?Glassware has been refer to the any laboratory apparatus made of glass. When you are done using a glassware, wipe down the glassware to remove any cleaning solvent. They are often washed with a solvent and particles of the cleaning solvent adheres to the glassware.
A lot of our laboratory apparatus are made of glass e.g beakers, conical flask, measuring cylinders etc. These glassware must be properly cleaned after use.
These particles of the solvent must be wiped to remove these particles of cleaning solvent that could contaminate a sample placed in the glassware.
Therefore, The step-by-step plan for dealing with broken glassware on the floor or lab table has been stated below:
1 tell the person in charge or the teacher
2 make sure u did not get cut.
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Which of these modes of transmission require a bodily opening either natural or artificial?
Answer:
Answer:
Vectors-These are diseases transmission which involves the piercing of the skin-vectors penetration e.g by mosquito. ticks.
Air borne which involves entry through the nasal passages, mouth, eyes to reach the body the respiratory tracts and the blood.
Blood borne diseases are transmitted from e.g piercing of the skin by contaminated objects needles, broken glass. If there is an opening in the skin these transmission is also possible.
Sexual can be transmitted through open sores at the genitals.or use of contaminated needle by infected subject. Sores in the mouth during kissing may be another route
food borne or water borne needs to enter through natural opening of the mouth to reach the body fluids and the blood through the GIT.
Contact diseases does not necessarily need a direct opening for transmission . rather there should be a direct contact between the infected individual and the other. Sometimes a direct contact between the two is not need. e.g common cold, chicken pox , influenza , etc.
Explanation:
A population of 150 fish have two alleles for the size of a black spot on their sides: large spot alleles and small spot alleles. The large spot allele is dominant.
For each situation listed below, identify the mechanism of evolution at work. Select whether it is an example of natural selection, genetic drift, or gene flow.
1. A fish net captures twenty fish, all who happened to have large spots.
2. Small spotted fish escape from predators better.
3. 15 large spotted fish move into this population.
4. Fish-eating birds catch large spotted fish more easily
Options:
A. Gene flow
B. Genetic Drift
C. Natural Selection
Answer:
1. genetic drift; 2. natural selection; 3. gene flow; 4. natural selection
Explanation:
1. A fish net captures twenty fish, all who happened to have large spots:
The mechanism of evolution that is playing out in this situation is most likely genetic drift. Genetic drift occurs when a random change occurs, resulting in the selection of a number of individuals by chance, rather than based on their level of fitness. The fish with large spots allele were selected against by chance, not necessarily because the fish with the small spot alleles were better fitted.
2. Small spotted fish escape from predators better:
The situation here is natural selection. The small spotted fish possess a greater fitness as they become well adapted to escaping from predators better than the large spotted fish, which gives confers on them a greater fitness to be selected for against the large spotted fish.
3. 15 large spotted fish move into this population:
The movement or introduction of new individuals i nto a population is what is referred to as gene flow in evolution, which is another mechanism of evolution that changes the allele frequency of the original population.
4. Fish-eating birds catch large spotted fish more easily:
This is another example of natural selection. The small spotted fish possess a greater fitness which makes them not easily preyed upon by Fish-eating bird easily, compared to large spotted fish. Natural selection favors the fish with small spotted alleles against the large spotted fish, and as a result, more small spotted fish would survive and reproduce more offspring with the small spotted alleles compared to those with large spotted alleles.
Which Are characteristics of natural selection
What effects do ocean currents have on short-term climate change? Check all that apply.
Ocean currents can carry warm water, which can raise the temperature of the air and land.
Ocean currents increase the strength of prevailing winds, which can cool the air and land.
Ocean currents can carry cold water, which can cool the air and land.
Ocean currents increase hurricane activity, which can raise the temperature of the air and land.
Ocean currents can carry warm water, which causes hurricane activity and raises the temperature of the air and land.
Answer:
1) Ocean currents can carry warm water, which can raise the temperature of the air and land.
2) Ocean currents can carry cold water, which can cool the air and land.
The effects that ocean currents have on short-term climate change are as follows:
Ocean currents can carry warm water, which can raise the temperature of the air and land.Ocean currents can carry cold water, which can cool the air and land.Thus, the correct options for this question are A and B.
What is Climate change?Climate change may be characterized as the significant alterations in global temperature, precipitation, wind patterns, and other measures of climate that occur over several decades or longer. It generally involves the long-term shifting of temperature and weather patterns.
Ocean currents act like conveyer belts that particularly transport warm water and precipitation from the equator toward the poles and cold water from the poles back to the tropics. Thus, currents regulate global climate, helping to counteract the uneven distribution of solar radiation reaching the Earth's surface.
Therefore, the correct options for this question are A and B.
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In humans the gene for brown eyes is dominate over the gene for blue eyes which is recessive. If two blue eyed parents have six children how many of their children will have blue eyes?
Answer:
three or four
Explanation:
if you think about it parent with both blu eyed doesn't exactly mean that because of that all their children will have blue eyes...
three out of six of them will have it the remaining four will probably have light or dark brown
All children of two blue-eyed parents will have blue eyes because both parents only carry the recessive allele responsible for blue eyes, resulting in a genotype of bb for each child.
In humans, the gene for brown eyes takes precedence over the gene for blue eyes, which is recessive. If two blue-eyed parents have six children, everyone of them will have blue eyes. This is because blue-eyed parents only carry the recessive allele for eye color, denoted as 'b'.
Thus, both the mother and father have the genotype bb. Because each parent can only pass on one 'b' gene, all offspring will have the bb genotype, resulting in a phenotype with blue eyes. This is consistent with Mendelian genetics principles, which state that in order for a child to have brown eyes, one of their parents must possess and pass down a dominant 'B' allele.
Spiders and lobsters?!? Juan was surprised that spiders and lobsters were similar in at least two ways. Juan also noted that all insects were similar to each other because they all had A) wings. B) 6 legs. Eliminate C) 8 legs. D) two body segments
Answer:
B
Explanation:
Answer:
The correct answer would be B. 6 legs
Explanation:
Insects are similar because they all have 6 legs
The graph shows the petroleum reserves that remain in five regions of Europe. Arrange the regions by decreasing amount of petroleum reserves
Answer:
B>A>C>D>E
Explanation:
The graph in the question shows the amount of petroleum reserves (on y-axis) in five regions of Europe (on x-axis). To arrange the amount of reserves in a decreasing order, this means we arrange from the most amount to the least amount of petroleum reserves (million of barrels of oil equivalent).
The height of the the bar graph represents the amount of petroleum reserves in each region. Hence, the tallest and shortest bar represents the most and least respectively.
According to the graph in the image, Region B has the most amount of petroleum reserves. Region A is next to it. Region C follows A. Region D follows and the least amount is Region E. Based on this, the descending or decreasing order is:
B>A>C>D>E
Which statements describe transform boundaries? Select two options,
The given question is incomplete. The complete question is:
Which statements describe transform boundaries? Select two options.
Rift valleys are formed.
Mountains are created.
Faults form in the lithosphere.
Plates move toward each other.
Plates slide in opposite directlồns.
Answer:
The correct options are that formation of faults takes place in the lithosphere and the sliding of the plates takes place in the opposite direction.
Explanation:
The transform boundaries signify towards the site where sliding of the plates takes place past each other, it is also called transform plate boundaries. In the process of the formation of the transform boundaries, neither the formation nor the destruction of the lithosphere takes place, however, in the process formation of thin rift valleys occurs.
The majority of the formation of the transform boundaries are witnessed on the floor of the sea. These boundaries possess the tendency of giving rise to earthquakes of high intensity that imparts a deleterious influence on the ecosystem. California's San Andrea is an illustration of transform boundaries.
Answer:
Rift valleys are formed, and mountains are created.
Explanation:
Lisa is made of _______________, these multiply and create ____________________, they group together and create __________________, which together form organ ________________, and then create an _____________________.
Answer:
Cells, tissues, organ, organ systems, organism
Explanation:
All living organisms including Lisa as used in this question is made up of fundamental and basic unit called CELLS.
In multicellular organisms (more than one cell), these cells undergo multiplication by dividing repeatedly and the ones that perform similar functions forms the TISSUE. For example, in humans like Lisa, we have the blood tissue formed by blood cells performing similar functions e.g erythrocytes, leukocytes etc.
The tissues that work together to perform a certain function groups together to form an ORGAN. An organ performs a specific function in the body. Examples of organs in a living organism like Lisa is heart, Kidney, liver etc. These organs, whose, functions are in synchrony collectively forms the ORGAN SYSTEM, which helps maintain the internal environment of an organism. Organ systems include; circulatory system, digestive system etc. Each organ system is made up of certain organs.
The collaboration of many organ systems working together ultimately forms the full ORGANISM like Lisa who is a human.
A particular fibroblast mutation fails to move to the site of infection. It is discovered that this mutation causes a particular protein to be absent, which leads to premature actin mRNA translation. Which protein is most likely absent due to the mutation
A). Src
B). ZBP1 (Zip-code bindinf protein)
C). CPEB
D). General transcription factor
E). Poly-A polymerase
Answer: B. ZBP1 (zip code binding protein)
Explanation:
ZBP1 is necessary for the prevention of premature translation, this protein is responsible for the transcription of beta-actin in the nucleus, since it is mutated, the effects will be observed because there will be no movement of fibroblasts to the infection site
the CPEB is false because it has the function of regulating the translation of mRNA, the SCR is not correct because its main role is the activation of protein kinases, thus also ruling out the general transcription factor which is It is responsible for the initiation of transcription in eukaryotes and poly A polymerase is also ruled out because its function is found in the production of poly A tail.
Identify the following as biotic or abiotic.
Sunlight and heat:
Insects:
Rotting log:
Bacteria:
Water:
Rocks
Answer:
Answer:
sunlight and heat: Abiotic
insects: Biotic
rotting log: Biotic
bacteria: Biotic
water: Abiotic
rocks: Abiotic
Explanation:
Explanation:
The categories of biotic or abiotic things are:
Sunlight and heat:
Insects: biotic factor
Rotting log: biotic factor
Bacteria: biotic factor
Water: abiotic factor
Rocks: abiotic factor
What are biotic and abiotic factors?Biotic factors are those that are living, growing, and reproducing. These are plants, animals, fungi, etc.
Abiotic factors are those which are nonliving. Like a rock, or water.
Thus, the categories are:
Sunlight and heat: abiotic factor
Insects: biotic factor
Rotting log: biotic factor
Bacteria: biotic factor
Water: abiotic factor
Rocks: abiotic factor
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You know that the narrow-sense heritability of milk production in Ayrshire cattle is 0.587. You perform an experiment where you take a parental population of cattle with a mean milk production of 5.1L/hr and selectively breed only the top 10% of cows in this population, who have a mean milk production of 8.9L/hr, what is the response to selection (R) in your experiment
Answer:
Explanation:
Narrow sense heritability - h2
selection differential - S
Selection differential is calculated from the difference between the population average and the parental population.
Breeder's equation:
Response to selection - R = h2S
Mean milk production of 10% cows for experiment = 8.9L/hr
Mean milk production of parental population = 5.1L/hr
Selection differential S= 8.9 - 5.1 = 3.8 L/hr
Response to selection = 0.587 × 3.8 = 2.23
Suggest reasons why the information represented in the pyramid of numbers of animals of one of the ecosystems you studied may not truly represent that ecosystem. 2. According to your data, what is the ratio of third-order consumers to producers? Explain your answer. 3. Compare and contrast two of the ecosystems you studied. How is the energy conversion efficiency similar or different? 4. Does the population size increase or decrease at higher trophic levels in the pyramid of numbers of an ecosystem consisting of a tree, insects (that are herbivores) and birds feeding on the insects? Explain your answer. 5. What might happen to an ecological pyramid of numbers in a forest ecosystem if most of the deer were killed due to hunting by people and disease? 6. What would happen to an ecosystem if the decomposers disappeared? 7. Could there be a food chain without herbivores and carnivores?
Answer:
1. Because the ecosystem is changing every day that affects the numbers of animals. The numbers would also be estimated and not the true number of the animals in the ecosystem.
2.100:0.1 is the ratio of the third order consumer because only 10% of energy is transfered as the producer are eaten by the first order consumer. When the first order consumer eaten by second order, it only gets 1% of the total energy, and so on; therefor; the ratio is 100:1.
3. Lets consider two ecosystems water and forest an both are similar because both the ecosystem has more numbers of producers than that of consumers. But the number of products and consumption is different.
4. Yes, the populaton size decreases at higher trophic levels because the population of producers decline as the first orders producer require to eat lot of plants for their survival, so that the first order would soon consume all the producers and die of nutrition shortages.
5. Death of deer in the forest ecosystem will disturb the food chain as it will reduces the number of second order animals due to starving and die. It will also result in teh inrease the producers population becuase deer are not present to balance that.
6. If the decomposers will get disaaperaed thatn the dead plants and animals will not be able to decompose and affect the soil fertility. The soil will not get enough nutrition to grow new plants an remaisn of dead bodies can produce harmful gases which can affect the health of other living organisms.
7. No, because food chain represent the flow of energy between different levels and herbivores and carnivores are two important pillars of food chain.
Which material is a part of bed rock? Silk plants wood water
Answer:
I think you meant 'silt'
The slit is a part of the bedrock.
What is bedrock?The deposit of solid rock that is essentially buried beneath the soil and other fractured or segregated substances is referred to as bedrock.
The parent substance (the source of rock and mineral particles) for soil and regolith is the bedrock, which is made up of igneous, metamorphic, or sedimentary rock.
Bedrock is a source of nitrogen in the Earth's nitrogen cycle. An outcrop is a bedrock accumulation that occurs at the Earth's surface.
Thus, we can conclude that option A, the slit is correct.
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Why is the sickle cell allele a nuisance trait rather than an advantage in most of the modern world?
Answer:
Sickle cell anaemia is a generic disorder which affects the red blood cells. The red blood cells assumes a sickle shape and contains lesser amount of the protein hemoglobin. Hemoglobin helps in the necessary transport of oxygen to other parts of the body.
The sickle cell allele is known to be advantageous to mainly people who stay in developing/underdeveloped counties who malaria endemic . People with the sickle cell allele have a higher chance of survival against malaria than people without this allele.
In modern countries malaria isn’t prevalent there due to the lack of vectors, poverty and environmental conditions which tends to support the survival of the mosquito. This means the sickle cell allele isn’t advantageous in this region.
Edward Jenner is considered the founder of vaccines in the western world. In 1796, he inoculated a 13 year-old-boy with the virus that caused cowpox. Since cowpox and smallpox are closely related, the result was a demonstrated immunity to smallpox. Later, the first smallpox vaccine was developed. During the next two centuries, systematic implementation of mass smallpox immunizations culminated in its global eradication in 1979. Using the cowpox virus to create a virus for smallpox ... A) ...allowed only expectant mothers to pass the immunity on to their unborn children. B) ... induced a secondary response because the body immediately recognized cowpox as smallpox due to the similarities in their genetic blueprints. C) ...induced a primary immune response and immunological memory. Because of this, an encounter with the pathogen would trigger a rapid and strong secondary response. D) ...allowed the virus to lie dormant within the cells of the person. When introduced to the virus again, the body could use the dormant pathogen as a point of reference. Eliminate
Answer:
c
Explanation:
i got it right!
Final answer:
Using the cowpox virus to create a vaccine for smallpox induced a primary immune response and immunological memory in the individual, enabling a strong secondary response upon exposure to smallpox.
Explanation:
The use of the cowpox virus to create a vaccine for smallpox by Edward Jenner in 1796 represents a crucial development in the field of immunology and vaccine development. When Jenner inoculated a 13-year-old boy with the cowpox virus, it induced a primary immune response and the subsequent development of immunological memory. As such, upon later exposure to the smallpox pathogen, the body was able to mobilize a rapid and robust secondary immune response, protecting the individual from getting sick with smallpox. The correct answer to the question is Option C, as exposure to cowpox antigens gave rise to a primary response and memory cells ready to recognize and respond to similar antigens presented by the smallpox viruses upon future encounters.
The accumulation of high-energy protons creates an H gradient between the Energy released blank is used to move H ions into the blank. The accumulation of high-energy protons creates an H gradient between the blank and the blank. and the Energy released blank is used to move H ions into the blank. The accumulation of high-energy protons creates an H gradient between the ___ and the ___
Answer:
This is refers to the sequence of events which occurs during chemiosmosis for ATPs Synthesis.
1. the released during electron transport along the cytochrome carries. as proton motive force(PMF), is used to move H+ into the intramembrane space from the matrix, The accumulation of high -energy protons creates an H gradient (electochemical gradients )between the Intramembrane space and the mitochrondrial matrix.
The elctrochemical gradients produced from the Proton accumulation produced energy for the influx of H+ back into the matrix, and this energy (produced from the gradient) is used by ATPase synthase to synthesis ATPs from ADP and Pi.
High-energy protons create an H+ gradient, and the energy released moves these ions from a higher concentration area to a lower one. This ATP synthesis from potential energy stored in a gradient is termed chemiosmosis and relies on ATP synthase.
Explanation:The accumulation of high-energy protons creates an H+ gradient between the thylakoid space (in cellular respiration, between the mitochondrial matrix and the intermembrane space) and the stroma of the chloroplast. Energy released is used to move H+ ions from a high concentration area to a low concentration area. This movement, termed as chemiosmosis, relies on ATP synthase, a transmembrane enzyme that helps to convert potential energy stored in this gradient into chemical energy, stored in ATP molecules. Because of H+ ions positive charge and their higher concentration on one side of the membrane, an electrochemical gradient is established which powers ATP synthesis. The current of hydrogen ions powers the catalytic action of ATP synthase, which phosphorylates ADP, thereby producing ATP.
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Imagine that you could microinject cytochrome c into the cytosol of both wild-type cells and cells that were lacking both Bax and Bak, which are apoptosis-promoting members of the Bcl-2 family of proteins. Would you expect one, both, or neither of the cell lines to undergo apoptosis?
Answer:
In the given case, if the cytochrome c was administered within the cytosol of both the cells that were defective doubly for Bax and Bak and the wild type cells then the cell lines would go through the process of apoptosis. Both the Bax and Bak refer to the proteins that come under the Bcl-2 family and plays an essential role in triggering the process of apoptosis.
The cytochrome c administered in the process combines with an adapter protein that further stimulates a procaspase. Thus, due to the combination, the beginning of the caspase cascade takes place, which eventually results in apoptosis.
Though the cells that were devoid of both Bax and Bak fails to discharge cytochrome c from the mitochondria even after attaining the upstream signals, however, due to no issue in the pathway's downstream section because of the stimulation done by the cytosolic cytochrome c, the microinjection of cytochrome c nulls the effect of the doubly defective cells, and starts the process of apoptosis.
It is expected that the wild-type cells would undergo apoptosis, while the cells lacking both Bax and Bak would not.
Cytochrome c is a key component in the induction of apoptosis, particularly in the intrinsic pathway. When released from the mitochondria into the cytosol, cytochrome c binds to Apaf-1 and procaspase-9 to form the apoptosome, leading to the activation of caspase-9 and subsequent activation of effector caspases, such as caspase-3, which execute the apoptotic process.
In wild-type cells, the injection of cytochrome c into the cytosol would bypass the normal mitochondrial control mechanisms and directly trigger the formation of the apoptosome, thus initiating apoptosis. This is because all the necessary components for apoptosis execution are present and functional in wild-type cells.
On the other hand, Bax and Bak are pro-apoptotic proteins that are essential for the release of cytochrome c from the mitochondria into the cytosol during apoptosis. Cells lacking both Bax and Bak have a defect in their ability to release cytochrome c from the mitochondria in response to apoptotic stimuli. Therefore, even if cytochrome c is artificially introduced into the cytosol of these double-knockout cells, the absence of Bax and Bak would mean that the cells are unable to initiate the apoptotic program effectively, as the signal for apoptosome formation would not be properly transmitted.
In summary, microinjecting cytochrome c into the cytosol of wild-type cells would lead to apoptosis because the downstream apoptotic machinery is intact and functional. However, in cells lacking both Bax and Bak, the apoptotic pathway is disrupted, and these cells would be resistant to apoptosis induction by cytochrome c microinjection.
When would gluconeogenesis be most active, after a meal or when you wake up in the morning? Explain your reasoning. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.
Answer:
Gluconeogenesis would be more active when you wake up in the morning.
Explanation:
The words and the sentences to match are missing but the reason why gluconeogenesis is more active when we wake up in the morning is that gluconeogenesis is the process by which our body produces glucose, the main fuel of the body, from non-carbohydrate carbon elements, such as proteins and lipids, when there are no carbohydrate carbon elements present in the body, since a long time has passed since our last meal, and the body has already consumed the glucose that was obtained from the ingested food, the system produces glucose from other elements.
Answer: Gluconeogenesis would be more active when you wake up in the morning.
Explanation:
Gluconeogenesis is the metabolic process by which living organisms produce sugars (namely glucose) for catabolic reactions from non-carbohydrate precursors (non carbohydrate elements). This is why gluconeogenesis is more active when we wake up in the morning due to the fact that a long time has passed since our last meal, and the body has already consumed the glucose that was obtained from the ingested food hours ago, the system tends to produces glucose from other elements available in the body.
The words and the sentences to match are missing.
Evidence supporting E.coli DNA polymerase III having the major role in nucleotide incorporation during replication includes:
a) A point mutation can inactivate DNA pol III and inhibit replication.
b) DNA polymerase III has a high Vmax.
c) Replication is blocked at high temperatures in temperature sensitive mutants with a thermolabile form of DNA polymerase III.
d) There are ten or fewer molecules of enzyme per cell.
e) All of the above.
Answer:
c
Explanation:
Large stars with high mass also have high luminosity
O True
O False
Answer:
false
Explanation:
because the gas is not strong enough to be
done right
Describe all the forces acting on the ice cream in the root beer float relate these forces to the fact that the ice cream is floating
Answer: The density of the ice cream and buoyant.
Explanation:
The density of the ice cream plus buoyant will cause the carbonation in root bear will cause gravity to push down on the ice cream and buoyant pushes the ice cream upwards, the ice cream floats because the buoyant force is greater than the weight of the ice cream.
Answer: The root beer exerts a force on all sides of the ice cream. These forces are all equal and cancel each other out. Gravity pushes downward on the ice cream. This can also be called the weight of the ice cream. Buoyant force pushes the ice cream upward. The ice cream floats because the buoyant force is greater than the weight of the ice cream.
Which of the following objects have the LEAST momentum?
a. A large car going extremely slowly
b. A tiny car going extremely slowly
c. A large car going super fast
d. A tiny car going super fast
Answer:
b
Explanation: It has the least weight/mass (less for gravity to pull on) and is going slow so
Final answer:
A tiny car going extremely slowly has the least momentum because momentum is the product of mass and velocity and both are low in this case.
Explanation:
The question relates to the concept of momentum in physics. Momentum is the product of an object's mass and its velocity. If two objects have the same momentum, the object with the smaller mass must have a higher velocity to compensate. In contrast, if two objects have the same kinetic energy, the one with the smaller mass will have a higher velocity, but not necessarily a higher momentum, since momentum also depends on mass.
Now, considering the options provided:
A larger car going extremely slowly will have more momentum than a tiny car going extremely slowly due to its larger mass.
A tiny car going extremely slowly will have the least momentum since both its mass and velocity are small.
A large car going super fast has a high level of momentum due to its large mass and high velocity.
A tiny car going super fast will have significantly less momentum than the large car at high speed, but more than the same tiny car going slowly.
Therefore, option b. A tiny car going extremely slowly has the least momentum.
Below are six statements about proteins being translated in the cytosol. A. Proteins that are fully translated in the cytosol do NOTend up in the cytosol. B. Proteins that are fully translated in the cytosol do NOTend up in the mitochondria. C. Proteins that are fully translated in the cytosol do NOTend up in the interior of the nucleus. D. Proteins that are fully translated in the cytosol do NOTend up in transport vesicles. E. Proteins that are fully translated in the cytosol do NOTend up in plasma membrane F. Proteins that are fully translated in the cytosol do NOTend up in the Golgi apparatus Which statements are true?
Answer:
option d: Proteins that are fully translated in the cytosol do not end up in transport vesicles
Explanation:
in the human body it is very essential that the protein should be moved/directed to different area of the human body and wit this, a lot of proteins of different kinds are sent to various part of the body
proteins translation in a eukaryotic cell starts in the cytosol exempted in some few cases.mostly, when protein are made, it passes a step by step process and at various stages reached, the protein is usually checked for molecular tags.
The correct answers are: D. Proteins that are fully translated in the cytosol do not end up in transport vesicles, E. Proteins that are fully translated in the cytosol do not end up in the plasma membrane and F. Proteins that are fully translated in the cytosol do not end up in the Golgi apparatus
Analyzing each statement:
A. False: Proteins fully translated in the cytosol can stay in the cytosol and may function there.B. False: Proteins translated in the cytosol can end up in the mitochondria if they contain the appropriate signal sequences.C. False: Proteins can be transported into the nucleus if they have nuclear localization signals.D. True: Proteins that are translated in the cytosol typically do not end up in transport vesicles, as these are generally used for proteins synthesized in the ER.E. True: Proteins that will end up in the plasma membrane are usually synthesized on ribosomes bound to the rough endoplasmic reticulum (RER).F. True: Proteins that end up in the Golgi apparatus are initially synthesized in the rough endoplasmic reticulum, not in the cytosol.Which of the following address(es) the problems posed by chromatin during transcription?
a) In some instances, protein factors can interfere with chromatin structure at specific locations, opening sensitive sites.
b) The action of chromatin remodeling factors is involved, which require ATP hydrolysis to allow the promoter regions to accept the complex.
c) In some cases, the chromatin structure rearranges at the time of replication.
d) All of the listed statements are true.
Answer:
Option D All of the listed statements are true
Explanation:
the major problem posed by chromatin during transcription includes its state at that moment in time. The chromatin might exist in a state that prevent the transcription machinery from accessing the DNA to carry out transcription and bring about gene expression. thus, its state can either allow for gene expression or not.
Thus, some factors/processes have been put in place to regulate this. This includes chromatin remodeling complexes that utilize the energy supplied by ATP hydrolysis to affect nucleosomes causing structure alterations, covalent histone modification that allows for unwinding of the DNA from nucleosome to allow for transcription to take lace.