Answer: 2 protons and 2 neutrons.
Explanation: this means that it contains 2 negatively charged elections and 2 positively charged protons which cancels each other to make the atom electrically neutral.
If a particle spends 8 seconds in the air and travels 320 m forward and to a height of 64 m what is the horizontal velocity
he speed up the incline is 300m/5s = 60m/s
the horizontal component of that is 60 cos 15 = 57.95m/s
Explain why do conductors and insulators are both required to construct electrical wiring in your home
the research of a social physiologist Vincent Hsu determined that americans tend to fulfill their ideal of self-reliance through
A. developing personal ideals
B.rebellion against social norms
C. confirming to role models
D. strong individualism
Vincent Hsu’s research shows that Americans tend to full their ideal of self-reliance by (B) rebellion against the social norms. These are quite commonly found throughout each American generations, where counter-culture is a way for them to establish self-reliance.
Though individualism is a value that is an embodiment of American culture back then and now, it is not how Americans establish self-reliance. Nor do they develop personal ideals or confirm to a role model.
The position equation for a particle is s of t equals the square root of the quantity 2 times t plus 1 where s is measured in feet and t is measured in seconds. find the acceleration of the particle at 4 seconds. 3 ft/sec2 one third ft/sec2 negative 1 over 27 ft/sec2 none of these
The acceleration of the particle at 4 seconds is -1/15 ft/sec².
Explanation:The position equation for the particle is s(t) = √(2t+1). In order to find the acceleration at t = 4 seconds, we need to differentiate the position equation twice with respect to time, t. First, differentiate the position equation to find the velocity equation, v(t). Then, differentiate the velocity equation to get the acceleration equation, a(t). Finally, substitute t = 4 into the acceleration equation to find the acceleration of the particle at 4 seconds.
Step 1: Differentiate s(t) with respect to t to find v(t)
v(t) = d/dt(√(2t+1)) = 1/(2√(2t+1)) * d/dt(2t+1) = 1/(2√(2t+1)) * 2 = 1/√(2t+1)
Step 2: Differentiate v(t) with respect to t to find a(t)
a(t) = d/dt(1/√(2t+1)) = (-1/2)(2t+1)^(-3/2) * d/dt(2t+1) = (-1/2)(2t+1)^(-3/2) * 2 = -1/(t+1)√(2t+1)
Step 3: Substitute t = 4 into a(t)
a(4) = -1/(4+1)√(2(4)+1) = -1/5√9 = -1/5 * 1/3 = -1/15 ft/sec²
Therefore, the acceleration of the particle at 4 seconds is -1/15 ft/sec².
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To find the acceleration of a particle, we first and second derivative of the position equation. Substituting time t=4s into this equation yields the acceleration: -1/108 ft/sec², which is not among the given options.
Explanation:To find the acceleration of a particle whose position equation is given, it's necessary to compute the first and second derivatives of s with respect to t. In this case, the equation is s(t) = sqrt(2t+1). Its derivative, v(t), represents the velocity of the particle, and the derivative of v(t) gives a(t), the acceleration.
First find the derivative of s(t):
v(t) = ds/dt = 1 / 2*sqrt(2t+1)
Then, find the second derivative, which will yield the acceleration:
a(t) = dv/dt = -1 / 4*(2t+1)^(3/2)
By substituting t=4s into the acceleration equation a(t), we get a(4) = -1/108 ft/sec², which reduces to approximately -0.00926 ft/sec². Therefore, the correct answer is none of the given options.
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During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the top of the science building. Determine distance the ball has traveled after falling for 1.0 second, ignoring air resistance and given the gravitational acceleration of 9.8 m/sec^2.
A) 4.9 m
B) 11 m
C) 20 m
D) 32 m
The instant it was dropped, the ball had zero speed.
After falling for 1 second, its speed was 9.8 m/s straight down (gravity).
Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.
Falling for 1 second at an average speed of 4.9 m/s, is covered 4.9 meters.
ANYTHING you drop does that, if air resistance doesn't hold it back.
The Answer is A)
nvfobovbb
Which of these statements correctly describe the atom? Check all that apply. All matter on Earth is made up of atoms. The subatomic particles of an element retain the properties of that element. The neutron has no charge and identifies the element. The electron is negatively charged and is located in a cloud surrounding the nucleus. The proton is positively charged and is found in the nucleus.
Answer:
All matter on Earth is made up of atoms.
The electron is negatively charged and is located in a cloud surrounding the nucleus.
The proton is positively charged and is found in the nucleus.
Explanation:
As we know that the atom is made up of three sub atomic particles give as
1). Electrons
2). Protons
3). Neutrons
Now we know that neutrons do not have any charge but it stays inside the nucleus and more than 50% of mass of the nucleus is due to neutrons.
Protons are of positive charge and it also stays inside the nucleus and number of protons inside the nucleus is same as atomic number.
Electrons are always of negative charge and it stays outside the nucleus in form of electron cloud and total negative charge of electron must be equal to total positive charge of proton in neutral atom.
Atoms are the basic building blocks of all matter on Earth. The subatomic particles retain the properties of the element, and the electron is negatively charged and located in a cloud surrounding the nucleus.
Explanation:The statements that correctly describe the atom are:
All matter on Earth is made up of atoms. Atoms are the basic building blocks of all matter. Everything around us, including ourselves, is made up of atoms.The subatomic particles of an element retain the properties of that element. The three subatomic particles of an atom are protons, neutrons, and electrons. Protons identify the element and determine its atomic number, while neutrons and electrons contribute to the atom's mass and charge. Each element has a unique combination of these subatomic particles that give it its specific properties.The electron is negatively charged and is located in a cloud surrounding the nucleus. The proton is positively charged and is found in the nucleus. Electrons are negatively charged particles that orbit the nucleus in specific energy levels or shells. Protons, on the other hand, are positively charged particles located within the nucleus of the atom.Learn more about Atom here:https://brainly.com/question/30735712
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pitbulllover101
Rutherford's famous gold foil experiments shot heavy particles at a thin sheet of gold foil. What did he observe, and why did these observations eventually result in the addition of a nucleus to the atomic model?
Some of the heavy particles bounced off the foil, because there are positive particles spread throughout the atom.
Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.
The heavy particles all passed straight through the foil, because the atoms are mostly empty space.
The heavy particles all bounced off the foil, because the subatomic particles have mass and volume.
Answer:
Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.
Explanation:
As per the observation of experiment he observed that very few heavy particles in this experiment bounced off in opposite direction.
Due to this reverse direction motion we can conclude that there must be a small dense region in which there is same charge concentrated which will repel the heavy particle
This region is concluded in very small space because major proportion move out the foil without any deviation only few of the particles will return back.
So here we can say that correct option must be
Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.
Which is a way that acoustic engineers attempt to limit the destructive interference of reflected sound waves in an auditorium?
designing a space with a lower ceiling
designing a space with sound-absorbing tiles
designing a smaller space
designing a larger space
Correct answer is B. Designing a space with sound-absorbing tiles.
In order to limit the destructive interference of reflected sound waves in an auditorium, the acoustic engineers needs to provide sound-absorbing tiles in that area. Due to reflection of sound waves, destructive interference is created in the hall of auditorium. Sound-absorbing tiles have ability to absorb those waves and provide good sound ecosystem to the auditorium room.
When matter and energy change forms within a closed system, A. The total amount of energy changes, but the total amount of matter does not. B. The total amount of both matter and energy changes. C. The total amount of matter changes, but the total amount of energy does not. D. The total amount of both matter and energy does not change.
Answer: Option D. The total amount of both matter and energy does not change.
Explanation:
From Law of conservation of energy and Einstein's mass-energy relation, we know that, energy neither is formed not is destroyed. It converts from one form to another. Einstein's mass-energy relation: E = mc². It means, Matter is a form of energy i.e. matter holds energy equivalent to product of its mass and square of speed of light. Matter and energy can change forms but the total amount does not change in a closed system. Thus, correct option is D.
Answer: the total amount of both matter and energy does not change (d)
Explanation:
i just got this question on Study Island
Give the electron geometry, molecular geometry, and hybridization for cbr−3. give the electron geometry, molecular geometry, and hybridization for . eg = trigonal pyramidal; mg = trigonal pyramidal; sp3 eg = octahedral; mg = octahedral, sp3 eg = trigonal planar; mg = trigonal planar; sp2 eg = tetrahedral; mg = linear; sp3 eg = tetrahedral; mg = trigonal pyramidal; sp3
Answer: Electronic geometry is tetrahedral, molecular geometry is trigonal pyramidal and hybridization is [tex]sp_3[/tex]
Explanation: Formula used for calculating the no of electrons:
[tex]:{\text{Number of electrons}} =\frac{1}{2}[V+N-C+A][/tex]
where, V = number of valence electrons present in central atom i.e. carbon = 4
N = number of monovalent atoms bonded to central atom=3
C = charge of cation = 0
A = charge of anion = -1
[tex]CBr_3^{-}:[/tex]
[tex]{\text{Number of electrons}} =\frac{1}{2}[4+3-0+1]=4[/tex]
The number of electrons is 4 that means the hybridization will be [tex]sp^3[/tex] and the electronic geometry of the molecule will be tetrahedral.
But as there are three atoms around the central carbon, the fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be trigonal pyramidal.
The CBr₃ compound has a tetrahedral electron geometry and molecular geometry because it has four regions of electron density. As a result, the carbon atom undergoes sp3 hybridization. The structure and chemical bonding of a molecule, which are indicated by its electron pair geometry, molecular geometry, and hybridization, are key in predicting its properties and reactivity.
Explanation:The compound CBr₃ has an electron geometry and molecular geometry that are both tetrahedral due to the presence of four regions of electron density (three for the bonded Bromine atoms and one for the lone pair). This also results in the carbon atom undergoing sp3 hybridization. As a result, the electron pair geometries and molecular structures for CBr₃ are tetrahedral.
An easy way to figure this out is by using the valence shell electron pair repulsion (VSEPR) theory, where the molecular structure is largely determined by the repulsion between the electron pairs in the valence shell of the atoms in the molecule. Overall, the electron pair geometry, molecular geometry, and hybridization of a molecule provide key information about its structure and chemical bonding which are crucial to predicting its properties and reactivity.
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An object's natural frequency depends partially on the material from which it is made.
Yes. Partly. Also on the size and shape of the object, and also on what material it's IN at the time ... like air, water, Helium, Jello, etc.
An object's natural frequency depends partially on the material from which it is made.
true - material determines its strength, hardness, elasticity n other physical properties dat affect its natural frequency. other factors include the shape n size of the object.
This image shows a stream of positively charged particles being directed at gold foil. The positively charged particles are called "alpha particles” and each one is like a nucleus without any electrons.
What is the best explanation for why a particle is striking point X?
it is colliding with a proton or neutron, it is deflecting toward point X. is the best explanation for why a particle is striking point X.
What is an alpha particle?Alpha particles, also known as alpha rays or alpha radiation, are made up of two protons and two neutrons bonded together to form a helium-4 nucleus-like particle.
The experiment demonstrates Rutherford's atomic model, and he reasoned that every atom has a nucleus that holds all of its positive charge and the majority of its mass.
it means that most of the space inside it is vacant, but when it strikes the nucleus directly, it returns at 180°, and when it passes through the nucleus, it bends away at a 90°.
Hence it is colliding with a proton or neutron, it is deflecting toward point X. is the best explanation for why a particle is striking point X.
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The center on a high school basketball team wants to increase the maximum height of his jump. What statement correctly describes how he could achieve this goal?
A) Wearing lighter shoes would increase the height of his jump.
B) Jumping at a 45° angle would increase the height of his jump.
C) Jumping with greater acceleration would increase the height of his jump.
D) Jumping with greater initial velocity would increase the height of his jump.
Answer:
D) Jumping with greater initial velocity would increase the height of his jump.
Explanation:
As the center of the team jumps, his motion is an accelerated motion with initial velocity [tex]v_0[/tex] upward and constant acceleration [tex]g=9.8 m/s^2[/tex] (acceleration due to gravity) towards the ground.
According to the law of conservation of energy, the gravitational potential energy of the center as it reaches its maximum height (h) is equal to the initial kinetic energy just after he starts the jump:
[tex]U=K\\mgh=\frac{1}{2}mv_0^2[/tex]
where
m is the mass of the center
g is the acceleration due to gravity
h is the maximum height
v0 is the initial velocity
Re-arranging the formula, we find:
[tex]h=\frac{v_0^2}{2g}[/tex]
Therefore, we see that the greater the initial velocity v0, the higher the center will jump.
Your dog sleeps on the floor. He has a mass of 14 kg. The coefficient of static friction between him and the floor is 0.3, and the coefficient of kinetic friction is 0.25.
a. What is the weight of your dog?
b. What is the normal force acting on your dog?
c. What is the maximum force of static friction?
d. You push horizontally on your dog with a force of 50 N. Does your dog slide?
e. Later, you are sliding your dog across the floor at a speed of 2 m/s. What is the force of kinetic friction acting on your dog?
Answer:
A.137.2N
B 137.2N
C.41.16 N
D.Yes
E. 34.3N
Explanation:
THe weight of any object is calculated by multiplying the mass of the object by the gravity of where they are in, in this case is the earth, the gravity of earth is [tex]9.8\frac{m}{s^{2} }[/tex], so the weight of the dog would be:
[tex]w=(14kg)(9.8\frac{m}{s^{2}})[/tex]
[tex]m=137.2 N[/tex]
Now the normal force is the same as the weight.
[tex]Nf=w= 137.2N[/tex]
The maximum force of static friction is calculated by multiplying the weight by the coefficient of static friction:
[tex]Sf=(w)(coefficient)[/tex]
[tex]Sf=(137.2N)(0.3)[/tex]
[tex]Sf=41.16[/tex]
To know this you just have to know the total static force to know if the dog moves, since the force pulling the dog towards the floor is on the Y axis and you are pushing on the x axis, that force is nulified, but you have the friction froce, which is 41.16N, since the force you are pushing with is 50N the dog moves.
When you are sliding somthing over any surface you just have to multiply the weight of the object by the coefficient kinetic friction.
[tex]Kf=(w)(coefficient)[/tex]
[tex]Kf=(137.2N)(.25)[/tex]
[tex]Kf=34.3N[/tex]
The resultant of 3 forces in equilibrium is equal to the vector sum of any 2 of the forces.
True or False?
Answer:
False
Explanation:
When 3 (non zero) forces are in equilibrium, the resultant (net) force is 0. The sum of any two components will therefore be non-zero and consequently not equal to the original resultant.
A golf club hits a stationary 0.05kg golf ball with and average force of 5.0 x 10^3 newtons accelerating the ball at 44 meters per second. What is the magnitude of impulse imparted to the ball by the golf club?
Answer: The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds
Explanation:
Force applied on the golf ball = [tex]5.0\times 10^3 N[/tex]
Mass of the ball = 0.05 kg
Velocity with which ball is accelerating = 44 m/s
Time period over which forece applied = t
[tex]f=ma=\frac{m\times v}{t}[/tex]
[tex]t=\frac{0.05 kg\times 44m/s}{5.0\times 10^3 N}=4.4\times 10^{-4} seconds[/tex]
[tex]Impulse=(force)\times (time)=f\times t = 5.0\times 10^3\times 4.4\times 10^{-4} seconds=2.2[/tex] Newton seconds
The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds
The magnitude of impulse imparted to the ball by the golf club is 2.2 N-s.
Given data:
The mass of golf is, m = 0.05 kg.
The magnitude of average force on ball is, [tex]F = 5.0 \times 10^{-3} \;\rm N[/tex].
The velocity of the ball is, v = 44 m/s.
Apply the impulse-momentum theorem, which says that the average force acting on the body is equal to the change in momentum with respect to time. therefore,
[tex]F = \dfrac{dp}{dt} \\\\F = \dfrac{m \times v}{t} \\F \times t = m \times v[/tex]
Here, t is the impact time and the expression [tex](F \times t)[/tex] is known as impulse (I).
Solving as,
[tex]F \times t = m \times v\\I = 0.05 \times 44\\I = 2.2 \;\rm N-s[/tex]
Thus, the magnitude of impulse imparted to the ball by the golf club is 2.2 N-s.
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A wave travels at a speed of 34 cm/s. It’s wavelength is 18 cm. What is the period of the wave?
0.75 s
1.2 s
0.66 s
0.53 s
Regions of compression and rarefaction help define _______.
Electromagnetic waves
Longitudinal waves, but not transverse waves
Transverse waves, but not longitudinal waves
All mechanical waves
The period of a wave with a speed of 34 cm/s and a wavelength of 18 cm is 0.53 seconds. Regions of compression and rarefaction define longitudinal waves, not transverse waves.
Calculate the period of a wave, we can use the relationship between speed (v), wavelength (λ) , and period (T). This relationship is expressed as
v = λ / T
which can be rearranged to find T
Given that the speed of the wave is 34 cm/s and its wavelength is 18 cm, we substitute these values into the equation to find the period:
T = 18 cm / 34 cm/s.
Calculating this gives us T = 0.5294117647 seconds, which rounds to 0.53 seconds.
As for the second part of your question, the regions of compression and rarefaction help define longitudinal waves, but not transverse waves. Transverse waves have crests and troughs, while longitudinal waves consist of compressions and rarefactions.
You are in a planet where the acceleration due to gravity is known to be 3.28 m/s^2. You drop a ball and record that the ball takes 2.40 s to reach the ground. How fast is the ball moving just as it lands? Neglect air resistance.
A.) 1.12 m/s
B.) 7.87 m/s
C.) 3.55 m/s
D.) 2.81 m/s
Which metal is the most abundant in the Earth’s crust
aluminum (Al)
iron (Fe)
copper (Cu)
zinc (Zn)
The metal that is the most abundant in the earths crust is Aluminum
I believe it is iron (Fe).
Iron + oxygen are usually found together.
The density of an object has the equation d = m/v. If an object has a mass of 2.5 g and a volume of 1.3 cm^3, what is its density?
A. 0.59 g/cm^3
B. 3.8 g/cm^3
C. 1.93 g/cm^3
D. 1.2 g/cm^3
Equation
d = m/v
Givens
m = 2.5 gramsV = 1.3 cm^3d = ??Solution
d = m/vd = 2.5 / 1.3d = 1.92 g/cm^3Answer C
please help on this one?
Number c is right answer because it doesn't talk about forces rather it talks about planetary motions and orbits
There are multiple tuning forks present in the room, and Annie strikes one with a natural frequency of 400 Hz. Which of these other tuning forks will begin to vibrate through resonance and make the sound louder?
a 200 Hz tuning fork
a 400 Hz tuning fork
a 800 Hz tuning fork
a 1600 Hz tuning fork
B. a 400Hz tuning fork
Answer: The correct answer is 400 Hz tuning fork.
Explanation:
Resonance occurs when the natural frequency of the object matches with frequency of the others.
In the given problem, there are multiple tuning forks present in the room, and Annie strikes one with a natural frequency of 400 Hz.
Therefore, the tuning fork having frequency of 400 Hz will begin to vibrate through resonance and the sound louder.
a rocket blasts off and moves away (distance is increasing) form earth. how is the rocket affected by the earths gravitational pulls as it moves further away?
the right answer is C
What is the difference between brake horsepower and thrust horsepower?
1. HP is the output horsepower rating of an engine, while Brake horse power is the input brake horsepower of an engine. ... Brake horse power is the measurement of an engine's power without any power losses, while HP is less the power losses Brake horse power
Final answer:
Brake horsepower (BHP) and thrust horsepower (THP) are two different measurements of power in engines. BHP refers to the power output of an engine, while THP is the power generated by a jet engine or propeller to produce thrust.
Explanation:
In physics, brake horsepower (BHP) and thrust horsepower (THP) are two different measurements of power, particularly in the context of engines.
Brake horsepower refers to the power output of an engine measured at the engine's crankshaft, before any losses due to friction or other factors. It is commonly used to describe the power of internal combustion engines in vehicles.
On the other hand, thrust horsepower is a measurement of power specifically for jet engines or propellers. It is the power that the engine or propeller generates in order to produce thrust and propel the aircraft forward.
A train traveling at a constant speed covers a distance of 960 meters in 30 seconds. What is the train's speed?
32 meters per second
Answer:
32 m/sec
Explanation:
Given,
⇒ Distance that is covered= 960 meters
⇒ Time taken= 30 seconds
We know that,
⇒ [tex]Speed=\frac{distance}{time taken}[/tex]
⇒ [tex]Speed =\frac{960}{30}[/tex]
Therefore, speed = 32 m/sec.
In this lab you will use a cart and a track to explore Newton's second law of motion. You will vary two different variables and determine how each one affects how quickly the cart moves along the track. In the space below, write a scientific question that you can answer by doing this experiment.
Answer:
Newtons II law:
It is defined as "the net force acting on the object is a product of mass and acceleration of the body" . Also it defines that the "acceleration of an object is dependent on net force and mass of the body".
Let us assume that,a string is attached to the cart, which passes over a pulley along the track. At another end of the string a weight is attached which hangs over the pulley. The hanging weight provides tension in the spring, and it helps in accelerating the cart. We assume that the string is massless and no friction between pulley and the string.
Whenever the hanging weight moves downwards, the cart will accelerate to right side.
For the hanging weight/mass
When hanging weight of mass is m₁ and accelerate due to gravitational force g.
Therefore we can write F = m₁ .g
and the tension acts in upward direction T (negetive)
Now, Fnet = m₁ .g - T
= m₁.a
So From Newtons II law F = m.a
Answer:
Sample Response: How do force and mass affect the acceleration of an object?
Explanation:
About 90 percent of the stars in space are a. Nebula c. Main sequence b. Giant d. White dwarf Please select the best answer from the choices provided A B C D
About 90 percent of the stars in space are Main Sequence stars. (c)
Answer:
c. Main Sequence
Explanation:
90% of the stars in space are in the main sequence stage.
Nebula is a cloud of dust and hot gases where stars are born. Giant and white dwarf are types of stars.
A plot of star temperature vs luminosity is used to classify all the stars. This plot is known as HR diagram. When plotted on the HR diagram, 90% of the known stars lie on the main sequence stage of the HR Diagram.
A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. What is the maximum height attained by the ball? Round the answer to the nearest tenth of a meter
Answer:
8.6 m
Explanation:
The motion of a soccer ball is a motion of a projectile, with a uniform motion along the horizontal (x-) direction and an accelerated motion along the vertical (y-) direction, with constant acceleration [tex]a=g=-9.8 m/s^2[/tex] towards the ground (we take upward as positive direction, so acceleration is negative).
The initial velocity along the vertical direction is
[tex]v_{y0} = v_0 sin \theta = (26 m/s)(sin 30^{\circ})=13 m/s[/tex]
Now we can consider the motion along the vertical direction only. the vertical velocity at time t is given by:
[tex]v_y(t)=v_{y0} +at[/tex]
At the point of maximum height, [tex]v_y(t)=0[/tex], so we can find the time t at which the ball reaches the maximum height:
[tex]0=v_{y0}+at\\t=-\frac{v_{y0}}{a}=-\frac{13 m/s}{-9.8 m/s^2}=1.33 s[/tex]
And now we can use the equation of motion along the y-axis to find the vertical position of the ball at t=1.33 s, which corresponds to the maximum height of the ball:
[tex]y(t)=v_{y0}t + \frac{1}{2}at^2=(13 m/s)(1.33 s)+\frac{1}{2}(-9.8 m/s^2)(1.33 s)^2=8.6 m[/tex]
What is the velocity in meters per second of a runner who runs exactly 110 m towards the beach in 72 seconds
v=d/t=110/72=1.5277 m/s
The scientist who discovered the laws of motion was _____.
A.Aristotle
B.Albert Einstein
C.Galileo Galilei
D.Isaac Newton
Sir Isaac Newton discovered and described the laws of motion in his book Principia Mathematica published on July 5th, 1687.
D. Isaac Newton
Answer:
D, Isaac Newton.
Explanation:
Newton's laws of motion, relations between the forces acting on a body and the motion of the body, first formulated by English physicist and mathematician Sir Isaac Newton.