If x=450 mm, determine the mass of the counterweight s required to balance a 90-kg load, l.

To find the electric field at [tex]22.3 cm[/tex]  from the center, use the given electric field at [tex]7.8 cm[/tex]  to first calculate the charge, then reapply the electric field formula at the new distance. The result is approximately [tex]3684.2 N/C[/tex].

The problem involves calculating the electric field at a different distance from a point charge. We can use the formula for the electric field due to a point charge, which is given by:

[tex]E = \frac{k \cdot |q|}{r^2}[/tex]

Here,

The magnitude of the electric field at [tex]7.8 cm (0.078 m)\\ \\[/tex] is [tex]30500 N/C[/tex] . First, we calculate the charge q.

Rearrange the formula to find [tex]q: \quad q = \frac{E \cdot r^2}{k}[/tex]

Substitute the known values:[tex]q = 30500 \, \text{N/C} \times (0.078 \, \text{m})^2 / (8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2)[/tex]

Simplify:[tex]q \approx 2.04 \times 10^{-11} \, \text{C}[/tex]

Now, we use this charge to find the electric field at [tex]22.3 cm (0.223 m)[/tex]:

Substitute the values back into the electric field formula:[tex]E = \frac{k \cdot q}{r^2}[/tex]

[tex]E = \frac{(8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2) \times (2.04 \times 10^{-11} \, \text{C})}{(0.223 \, \text{m})^2}[/tex]

Calculate the electric field: [tex]E \approx 3684.2 \, \text{N/C}[/tex]

Therefore, the magnitude of the electric field at [tex]22.3 cm[/tex]  from the center is [tex]3684.2 N/C[/tex].

The biker's change in velocity from point B to point C is 0 m/s, indicating that there is no change in velocity. Consequently, the biker's acceleration between these points is also 0 m/s
to the power of 2; there is no acceleration.

The change in velocity of the biker as they travel from point B to point C is determined by subtracting the initial velocity at point B from the final velocity at point C. As given, the biker's velocity at point B is 8 m/s, and at point C, it remains 8 m/s. Therefore, the change in velocity (Δv) is:

Δv = final velocity - initial velocity

Δv = 8 m/s - 8 m/s

Δv = 0 m/s

Since the velocity does not change, the acceleration
a) from point B to point C is:

a = Δv/Δt

a = 0 m/s ÷ 1 s

a = 0 m/s²

Thus, there is no change in velocity and no acceleration as the biker moves from point B to point C.

This physics problem involves the principle of kinetic energy and work-energy. Given the situation presented, the increase in the car's kinetic energy due to a doubling of initial speed means that the braking stopping distance quadruples from 3 meters to 12 meters.

This Physics problem concerns the relationship between velocity, mass, and stopping distance under braking conditions. It's dealing with the principle of kinetic energy (1/2*m*v²) and the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.

If the initial speed is doubled, as it is in this case from 70 m/s to 140 m/s, the kinetic energy (and thus the work needing to be done to stop the vehicle) quadruples, assuming the mass stays constant. This means, due to the direct relationship between work done and distance when force is held constant, the stopping distance will also quadruple from the original 3 meters.

Therefore, the 1000-kilogram car, when moving at 140 m/s, will take 12 meters to stop under full braking in similar conditions.

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Answer:

Team A exert more force on ground.

Explanation:

In Tug of war since both teams are pulling two ends of a string or rope so here the net force on the string along with two teams would be zero

So in order to win the game each team has to exert force on the ground.

When team exert more force on the ground then due to the reaction force of ground on the team in opposite direction will help the team to pull the rope towards them

So here if Team A wins the game then the force exerted by that team on the ground must be more due to which the reaction force by ground on the team is of larger magnitude and hence they wins the game

In a tug-of-war, Team A's victory means they exerted a larger force than Team B, creating a net force that caused the movement of the rope towards their side.

In a tug-of-war challenge, if Team A wins, it can be said that Team A exerted a larger force on the rope than Team B. This is because the winning team in a tug-of-war is the one that pulls the rope towards their side over the center line, overcoming the opposing team's efforts. Force in physics is a measure of the interaction between two objects, and in this case, the interacting objects are the two teams exerting forces on the rope. The team that wins is the one that manages to exert a net force that is greater than that of the opposing team, resulting in the movement of the rope towards the winning team's side.

The speed of the bullet before impact is 0 m/s.

To determine the velocity of the bullet before impact, we can use the principle of conservation of momentum. The momentum before the impact is equal to the momentum after the impact. The momentum of the bullet is given by its mass times its velocity, and the momentum of the block is given by its mass times its final velocity. Since the block comes to a stop after sliding, its final velocity is 0 m/s. The equation for conservation of momentum becomes:

(m_bullet * v_bullet) = (m_block * 0)

Simplifying the equation gives: v_bullet = 0 m/s

Therefore, the speed of the bullet before impact is 0 m/s. None of the given answers (a) 106 m/s, (b) 166 m/s, (c) 226 m/s, (d) 286 m/s are correct.

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Final answer:

The student's problems require applying the concepts of work and energy to determine the effects of tension, friction, and gravity on a block moving on a surface and up an incline.

Explanation:

The student's question pertains to the work done by various forces on a block which is initially pulled along a horizontal surface and then up an incline. To solve problems like these, we rely on concepts from physics including work, energy, and the effects of forces on motion.

Work done by Tension on a Horizontal Surface

On a horizontal surface with no friction, the work done by tension is given by Work = force × distance. Since the force of tension is parallel to the displacement, the work done is simply the product of tension (T) and the distance (d).

Speed Before Incline

The speed of the block before it goes up the incline can be found using the work-energy principle. The work done on the block is equal to the change in its kinetic energy.

Work Done by Friction and Gravity on an Incline

When the block is pulled up an incline with friction, both the force of friction and gravity do work against the direction of motion. The work done by friction is the product of frictional force, distance, and the cosine of the angle between the force and the displacement (which is 180 degrees, so cos(180°) = -1).

Distance Traveled Up the Incline Before Rest

To find how far up the incline the block travels before coming to rest, we need to equate the work done against friction and gravity with the initial kinetic energy of the block. This will require solving for distance in the work-energy equation.

The energy required to remove second electron from lithium is more as compared to removing fourth electron from carbon

EXPLANATION:

The amount of energy required to remove an electron from an isolated atom is called as ionization energy of the electron.

The second ionization energy of lithium atom is more as compared to fourth ionization energy of carbon atom. It is so because the second electron which is to be emitted from the K-shell of lithium atom, is tightly bound by the nucleus as the orbit is very closer to the nucleus.

In case of carbon, the fourth electron is present in the valence shell.The radius of valence shell is not so close as compared to lithium.The screening effect is also more for carbon as compared to lithium.

Hence, the energy required to remove a second electron from lithium is more that the energy required to remove fourth electron from carbon.

It is easier to take out 4th electron from carbon than 2nd electron from lithium because 2nd electron of lithium is closer to the nucleus.

The electronic configuration for,

[tex]\rm \bold{ Li_3 - 1s^2 2s^2}\\\\\rm \bold{ C_6- 1s^2 2s^2 2p^2}[/tex]

Therefore, we can conclude that the it is easier to take out 4th electron from carbon than 2nd electron from lithium.

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The best example of translation motion is a soccer ball passed between two players.

Motion in which a moving body's points travel uniformly in one direction. We can observe that there is no change in the object's orientation if it is moving in a translatory manner. Motion that is translated is sometimes referred to as translational motion.

A body is considered to be in linear motion when it moves in a straight line (or rectilinear motion). A body is considered to be in translational motion when all of its points move the same distance in the same period of time.

Given that in question that to find best example of translational motion which is basically the change in the position of the body under observation.

The best example of the translational motion is a soccer ball passed between two players.

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These are your answers:

A is Insulin (7)

B is Obesity (5)

C is Diabetes (1)

D is Type 1 (6)

E is Hyperglycemia (3)

F is Regular aerobic exercise (10)

G is Pancreas (9)

H is HDL (4)

I is Type 2 (8)

J is atherosclerosis(2)

Here is why:

A. Hormone that helps the body control the level of glucose in the blood.

Insulin is a hormone. It helps regulate the levels of glucose in the blood by turning glucose into energy. This is why it plays an important role in metabolism. This hormone is produced by the pancreas.

B. Main cause of Type 2 Diabetes

Obesity is the main cause of Type 2 diabetes. Unhealthy eating and lack of exercise are often listed as causes of Diabetes 2, and this kind of lifestyle collectively leads to obesity.

C. Condition that makes it hard for the body to control the level of glucose in the blood.

Diabetes is a condition where the levels of glucose in the blood is high. This happens because the body cannot produce enough insulin, which is the hormone that controls glucose levels.

D. Damage to the pancreas caused by ones own antibodies.

In Diabetes Type 1, the immune system attacks the panceatic beta cells, which produce insulin. Unlike Type 2, Type 1 Diabetes is unavoidable and hereditary. So if you have it, you have it.

E. The elevation of glucose levels in the blood.

Hyperglycemia - Hyper means high or elevated. Gly means glucose or sugar. -cemia means blood. Put together, elevated glucose in the blood.  

F. Found to help with treatment of clinical depression

Studies have shown that aerobic exercise can help with clinical depression. It helps elevate moods and lessen tension. This helps relieve stress.

G. Organ where insulin is produced

Like mentioned above, insulin is produced by the pancreas.

H. "Good" Cholesterol

HDL is High-density Lipoprotein. HDL is considered as good cholesterol because it actually assists in removing other forms of cholesterol from the blood.

I. 90% to 95% of the case of diabetes in America

Studies have shown that in America Diabetes 2 is the most common case. Like mentioned above, cause of Diabetes type 2 is eating habits and lack of exercise and many foods today are full of processed sugars and are consumed in great amounts because of convenience.

J. Hardening of the arteries caused by a build up of fatty materials.

Fatty materials create plaque and they accumulate in the blood vessels. This leads to constriction and hardening in arteries specifically. This constriction makes the vessel more narrow and it can limit the flow of oxygen to the other organs of the body.

Knowing how to graph motion helps in understanding kinematics properties by deriving motion characteristics from the graph, visualizing equations in a comprehendible form, and revealing underlying relationships between physical quantities.

Knowing how to graph movement can be practically beneficial for several reasons, these include:

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The internal resistance of the 9.0 V battery is 3.54 Ω.

The internal resistance of the battery can be calculated using Ohm's Law. Ohm's Law states that the voltage (V) across a resistor is equal to the current (I) through the resistor multiplied by the resistance (R). In this case, the voltage across the battery terminals is 8.5 V and the resistance of the load is 60 Ω.

Using Ohm's Law, we can set up the following equation:

8.5 V = I * 60 Ω

Solving for I gives us:

I = 8.5 V / 60 Ω = 0.1417 A

The internal resistance of the battery can then be calculated using the formula:

Internal Resistance = (Emf - Terminal Voltage) / Current

Substituting the given values:

Internal Resistance = (9.0 V - 8.5 V) / 0.1417 A = 3.54 Ω

Final answer:

To find the car's constant acceleration, we use the formula s = ½at², substituted with the given values to calculate the acceleration, which is found to be 2.5 m/s².

Explanation:

The question involves finding the constant acceleration of a car that starts from rest and travels 20 m in 4 s along a straight line. To find the acceleration, we can use the formula for motion under uniform acceleration, s = ut + ½at², where s is the distance covered, u is the initial velocity, t is the time, and a is the acceleration. Given that the car starts from rest, u is 0, which simplifies the formula to s = ½at².

Rearranging the formula to solve for acceleration (a), we get a = 2s/t². Plugging in the values, a = 2*20/4² = 2.5 m/s². Therefore, the acceleration of the car is 2.5 m/s².

The voltage drop across a 3 kΩ resistor connected to a 9V power source is 9V, as calculated using Ohm's law.

To calculate the voltage drop across a resistor, we use Ohm's law, which states that V = IR, where V is the voltage, I is the current, and R is the resistance. Since we know the resistance (R = 3 kΩ) and the power source voltage (V = 9V), we first need to calculate the current (I) using the formula I = V/R.

Therefore, the voltage drop across the 3 kΩ resistor connected to a 9V power source is 9V.

The maximum possible speed of the ball at the top of the loop is 4.50 m/s

Acceleration is rate of change of velocity.

[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]

[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]

a = acceleration (m / s²)

v = final velocity (m / s)

u = initial velocity (m / s)

t = time taken (s)

d = distance (m)

Centripetal Acceleration of circular motion could be calculated using following formula:

[tex]\large {\boxed {a_s = v^2 / R} }[/tex]

a = centripetal acceleration ( m/s² )

v = velocity ( m/s )

R = radius of circle ( m )

Let us now tackle the problem!

Given:

mass = m = 0.34 kg

length of string = R = 0.52 m

maximum tension = Tmax = 9.9 N

Unknown:

v = ?

Solution:

[tex]mg + T = ma[/tex]

[tex]mg + T = m\frac{v^2}{R}[/tex]

[tex]0.34 \times 9.8 + 9.9 = 0.34 \times \frac{v^2}{0.52}[/tex]

[tex]13.232 = \frac{0.34}{0.52} \times v^2[/tex]

[tex]v^2 = 20.2372[/tex]

[tex]\large {\boxed {v \approx 4.50 ~ m/s} }[/tex]

Grade: High School

Subject: Physics

Chapter: Circular Motion

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Circular , Ball , Centripetal

The maximum possible speed of the baseball at the top of the loop is approximately 3.17 m/s. This is calculated by using the maximum tension the string can support, and the gravitational force acting on the baseball.

To find the maximum possible speed of the baseball at the top of the loop without breaking the string, we need to consider the forces acting on the baseball. Two key forces are at play here: the gravitational force pulling the ball downward and the tension in the string that counteracts this pull. At the top of the loop, for minimum speed, the tension in the string can be zero because the gravitational force provides the necessary centripetal force. However, the question states that the string can only support a maximum tension (Tmax) before breaking which means we must find the speed where the tension does not exceed Tmax.

The maximum tension is the sum of the centripetal force needed to keep the ball moving in a circular path and the force due to gravity. Mathematically, this is expressed as Tmax = m * v^2 / l + m * g, where v is the velocity, m is the mass of the baseball, l is the length of the string, and g is the acceleration due to gravity (9.8 m/s^2).

Rearranging the formula to solve for v gives us v = sqrt((Tmax - m * g) * l / m). Plugging in the values Tmax = 9.9 N, m = 0.34 kg, l = 0.52 m, we get:

v = sqrt((9.9 N - (0.34 kg * 9.8 m/s^2) * 0.52 m) / 0.34 kg)

Calculating the above expression, we find the maximum velocity:

v = sqrt((9.9 - 3.332) * 0.52 / 0.34)

v = sqrt(6.568 * 0.52 / 0.34)

v = sqrt(3.4152 / 0.34)

v = sqrt(10.0447)

v ≈ 3.17 m/s

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Options:

Answer:

Option-(3):Customers would not receive electricity.

Explanation:

Power lines breakage:

The power lines are required to supply power or electricity to the households and the different consumers i.e industries. If the lines are broken then there will be no more power or electricity supply to the consumers.

Toaster oven:

Power: [tex]P=1.20 kW[/tex]

Time: [tex]t=6.20 min \cdot \frac{1}{60 min/h}=0.103 h[/tex]

So, the energy consumed by the oven is

[tex]E=Pt=(1.20 kW)(0.103 h)=0.124 kWh[/tex]

Fluorescent light:

Power: [tex]P=11.0 W=0.011 kW[/tex]

Time: [tex]t=8.50 h[/tex]

So, the energy consumed by the light is

[tex]E=Pt=(0.011 kW)(8.50 h)=0.094 kWh[/tex]

So, the toaster oven has consumed more energy than the fluorescent light.

Answer: clock radio, toaster, hair dryer, tv, lamp, fridge

Explanation:

Just did it

B) Chemical energy thermal energy mechanical energy electrical energy.

Electricity sequence is an intelligence web platform that allows quit customers to recognize electricity-saving measures and achieve greater electricity performance with a price and time this is an 80% decrease over manual strategies and other tracking structures.

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