Justin, with a mass of 30 g, is going down a 8.0 m high water slide. he starts at rest, and his speed at the bottom is 11 m/s. how much thermal energy is created by friction during his descent

Answer:

Acceleration of the train is 0.07 m/s²            

Explanation:

Initial speed of the train, u = 22 m/s

Final speed of the train, v = 32 m/s

Time taken by the train to do the process is 142 seconds

We have to find the acceleration of the train. It is given by the rate of change of speed of the train i.e.

[tex]a=\dfrac{v-u}{t}[/tex]

[tex]a=\dfrac{32\ m/s-22\ m/s}{142\ s}[/tex]

[tex]a=0.07\ m/s^2[/tex]

So, the acceleration of the car is 0.07 m/s². Hence, the correct option is (d) 0.07 m/s²

The coefficient of performance (COP) of a heat pump is a measure of its effectiveness and is defined as the ratio of the heat transfer into the warm space to the work input required by the heat pump.

The coefficient of performance (COP) of a heat pump is a measure of its effectiveness and is defined as the ratio of the heat transfer (Qh) into the warm space to the work input (W) required by the heat pump. Mathematically, COP = Qh/W.

In this case, the heat pump absorbs heat from the cold outdoors at 3°C and supplies heat to a house at 20°C. The rate of heat transfer is given as 30,000 kJ/h and the power consumed is 3 kW.

To find the COP, we need to convert the rate of heat transfer and power consumed to the same units. Since 1 W = 1 J/s and 1 kJ = 1000 J, we have Qh = 30,000 kJ/h x 1000 J/kJ / 3600 s/h = 8333.33 J/s and W = 3kW x 1000 J/W = 3000 J/s.

Substituting these values into the formula, we get COP = 8333.33 J/s / 3000 J/s = 2.78.

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The shortest time in which a car could accelerate from 0 mph to 60 mph is [tex]13.7s[/tex].

Further explanation:

The opposite force acting on the body is known as frictional force. It always acts in the opposite direction of motion of body.

Concept used:

The force applied to a body to keep it at rest is known as the static friction force. It always acts opposite to the direction of motion of body. It is defined as the product of coefficient of friction and the normal force acting on the body.

The expression for the normal reaction of the body is given as.

[tex]N = mg[/tex]  

The expression for the net force is given as.

[tex]{F_{net}} = ma[/tex]                                 …… (1)

The expression for the static friction is given as.

[tex]{F_s} = {\mu _s}N[/tex]

The expression for the balanced forces is given as.

[tex]{F_{net}} = {F_s} - {F_r}[/tex]

Substitute[tex]{\mu _s}N[/tex] for [tex]{F_s}[/tex] and  for[tex]{F_r}[/tex] in the above expression.

[tex]\begin{aligned}{F_{net}}&={\mu _s}N-{\mu _r}N\\&= \left( {{\mu _s} - {\mu _r}} \right)N \\ \end{aligned}[/tex]

Substitute [tex]mg[/tex] for [tex]N[/tex] in above expression.

[tex]{F_{net}}=\left({{\mu _s}-{\mu _r}}\right)\left( {mg}\right)[/tex]       …… (2)

Compare equation (1) and (2) we get.

[tex]a=g\left({{\mu _s}-{\mu _r}}\right)[/tex]                              …… (3)

Here, [tex]a[/tex] is the acceleration of the body, g is the acceleration due to gravity, [tex]{\mu _s}[/tex] is the coefficient of static friction and  is the coefficient of reactive force.

The expression for the first equation of motion is given as.

[tex]v = u + at[/tex]      

Rearrange the above expression for time is given as.

[tex]\fbox{\begin\\t = \dfrac{{\left( {v - u} \right)}}{a}\end{minispace}}[/tex]                              …… (4)

Here, [tex]v[/tex] is the final velocity, [tex]u[/tex] is the initial velocity and [tex]t[/tex] is the time.

Substitute [tex]1[/tex] for [tex]{\mu _s}[/tex], [tex]0.8[/tex] for[tex]{\mu _r}[/tex] and [tex]9.8\,{\text{m/}}{{\text{s}}^{\text{2}}}[/tex] for [tex]g[/tex] in equation (3).

[tex]\begin{aligned}a&=\left( {9.8\,{\text{m/}}{{\text{s}}^{\text{2}}}}\right)\left( {1 - 0.8}\right)\\&=1.96\,{\text{m/}}{{\text{s}}^{\text{2}}} \\ \end{aligned}[/tex]

Substitute [tex]0\,{\text{mph}}[/tex] for [tex]u[/tex], [tex]60\,{\text{mph}}[/tex] for [tex]v[/tex] and [tex]1.96\,{\text{m/}}{{\text{s}}^{\text{2}}}[/tex] for [tex]a[/tex] in equation (4).

[tex]\begin{aligned}t&=\frac{{\left( {60\,{\text{mph}}-0\,{\text{mph}}}\right)}}{{1.96\,{\text{m/}}{{\text{s}}^{\text{2}}}}}\\&=\frac{{60\,{\text{mph}}\left( {\frac{{0.447\,{\text{m/s}}}}{{1\,{\text{mph}}}}} \right)}}{{1.96\,{\text{m/}}{{\text{s}}^{\text{2}}}}}\\&= 13.7\,{\text{s}} \\ \end{aligned}[/tex]

Thus, the time required to accelerate a car is [tex]\fbox{\begin\\13.7\, {\text{s}}\end{minispace}}[/tex].

Learn more:

1.  Conservation of momentum https://brainly.com/question/9484203.

2.  Motion under friction https://brainly.com/question/7031524.

3. Net force on the body https://brainly.com/question/4033012.

Answer Details:

Grade: College

Subject: Physics

Chapter: Kinematics

Keywords:

Force, friction, Acceleration, acceleration due to gravity, normal, weight, mass, motion, sliding, sled, hill, inclined, plane, coefficient of friction, angle of inclination, 13.68 s, 13.69 s.  

Final Answer:

So, under ideal conditions with the assumption of maximum static friction being available throughout the acceleration, the shortest time in which a typical car could accelerate from 0 to 60 mph on rubber-on-concrete would be approximately 2.734 seconds.

Explanation:

To solve this problem, we need to understand how the force of friction allows a car to accelerate and then apply the equations of motion to determine the shortest time it would take for the car to accelerate from 0 to 60 miles per hour (mph).

First, we need to define our variables and constants:
- The static friction coefficient between rubber and concrete, μs, which is 1.00. This is the factor that will limit our acceleration since it represents the maximum frictional force that can be exerted before sliding begins.
- The acceleration due to gravity, g, which is 9.81 m/s^2.
- The initial speed of the car, 0 mph, which needs to be converted to meters per second (m/s).
- The final speed of the car, 60 mph, which also needs to be converted to meters per second.

The force of static friction (f_friction) responsible for the acceleration can be calculated by multiplying the static friction coefficient (μs) with the normal force (N). The normal force, in this case, is equal to the weight of the car, which is the mass (m) times the acceleration due to gravity (g). Since we are looking for the highest possible acceleration, we can assume that the force of static friction is at its maximum value.

f_friction = μs * m * g

However, we don't need to know the mass of the car because it will cancel out in the equation of motion. The maximum possible acceleration (a_max) happens when the force of static friction is at its highest, and it can be calculated using:

a_max = f_friction / m = μs * g

Now we have the maximum possible acceleration the tires can provide on concrete, which is:

a_max = 1.00 * 9.81 m/s^2
a_max = 9.81 m/s^2

Next, let's convert the final velocity from mph to m/s:

v_final(mph) = 60 mph
v_final(m/s) = v_final(mph) * 0.44704 (conversion factor from mph to m/s)
v_final(m/s) = 60 * 0.44704
v_final(m/s) ≈ 26.8224 m/s

With the initial velocity (v_initial) being 0 m/s (since we start from rest), we can use one of the kinematic equations to find the time (t):

v_final = v_initial + a_max * t
26.8224 m/s = 0 m/s + 9.81 m/s^2 * t

Solving for t, we get:

t = v_final / a_max
t ≈ 26.8224 m/s / 9.81 m/s^2

t ≈ 2.734 seconds

So, under ideal conditions with the assumption of maximum static friction being available throughout the acceleration, the shortest time in which a typical car could accelerate from 0 to 60 mph on rubber-on-concrete would be approximately 2.734 seconds.

Answer;

A legislative body oversees city departments directly.

Explanation;

City commission government is a form of local government in the United States. In a city commission government, voters elect a small commission, typically of five to seven members, on a plurality-at-large voting basis.

The commissioners constitute the legislative body of the city and, as a group, are responsible for taxation, appropriations, ordinances, and other general functions.

Answer:

a legislative body oversees city departments directly

Explanation:

To find the time it takes for the box to fall off the truck, we use the equation of motion and the acceleration of the box relative to the truck. By setting the displacement equal to the distance from the rear of the truck and solving for time, we find that it takes approximately 1.34 seconds for the box to fall off.

To find the time it takes for the box to fall off the truck, we need to first find the acceleration of the box relative to the truck. Given that the truck is accelerating forward at 5.0 m/s² and the crate is accelerating forward at 2.94 m/s², we can subtract these accelerations to find the crate's acceleration relative to the truck, which is -2.06 m/s². Since the box falls off when it reaches a certain distance from the rear of the truck, we can use the equation of motion to find the time it takes to travel that distance.

The equation is:

d = ut + 1/2at²

Where:

Plugging in the values, we have:

1.81 m = 0 * t + 0.5 * (-2.06) * t²

Simplifying the equation:

1.81 = -1.03t²

Multiplying both sides by -1:

-1.81 = 1.03t²

Dividing both sides by 1.03:

t² = -1.81/1.03

When we take the square root of each side, we obtain:

t = ±√(-1.81/1.03)

The negative value of time implies an event before the start of motion, so we discard it. Therefore, the time it takes for the box to fall off the truck is approximately 1.34 seconds.

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The problem is about finding the reaction components at a ball-and-socket joint and the tension in wires supporting a sign. You can do this by breaking the forces and moments into their x,y,z components, setting up force balance and moment balance equations, and solving for the unknowns.

This problem pertains to static equilibrium, where both the sum of forces and the sum of torques are zero. To begin, let's establish a coordinate system where the ball-and-socket joint 'a' is considered the origin.

Assuming the tension in the wires is T and the angles of the wires to the x, y, z axes are known, you can break the tensions into their respective components using trigonometric principles. Let's consider Tbc and Tbd to be the tensions in the strings.

For the x-component we would sum up the forces in the x-direction and set it equal to zero. This can be represented as ∑Fx = Tbc,x + Tbd,x=0

The same goes for the y and z components with the z component taking into account the force due to gravity on the sign. Hence, ∑Fy = Tbc,y + Tbd,y=0 and ∑Fz = Tbc,z + Tbd,z - weight of the sign = 0. Here, the weight of the sign is 100kg*9.81m/s2

By balancing torques about each axis, you can find the tensions in the strings. The tension force should be the same in each wire if they make the same angles with the axes and are of equal length.

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This problem in Physics requires setting up equilibrium equations based on the given mass and calculating forces at the ball-and-socket joint and cable pressures.

The subject of this question falls under the branch of

Physics

referred to as statics, specifically the study of systems in equilibrium. Equilibrium implies that an object is neither accelerating nor rotating, meaning the sum of all forces and the sum of all torques acting on the object must both be zero. The 'x', 'y' and 'z' components referred to are likely part of a coordinate system used to describe the forces at work on the sign.

To determine these, one would need to set up equilibrium equations based on the known details about the system, which could include the known weight (provided by the mass of the sign and gravity), any relevant distances for calculating torques, and any other forces present such as tension in wires. The process of solving this system of equations would then yield the desired reaction components at the ball-and-socket joint and the tensions in the wires.

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The percent uncertainty of a 5 lb bag with an uncertainty of ±0.4 lb is calculated using the formula (SA / A) x 100%, resulting in a percent uncertainty of 8%.

To calculate the percent uncertainty for a 5 lb bag with an uncertainty of ±0.4 lb, you would use the following formula:

% uncertainty = (SA / A) × 100%

Where A is the expected value (5 lb in this case) and SA is the uncertainty in the value (0.4 lb). Plugging in the numbers:

% uncertainty = (0.4 lb / 5 lb) × 100% = 8%

This means the percent uncertainty of the bag's weight is 8%.

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The speed of sound within a substance depends on the bulk modulus and density of the material. An increase in bulk modulus, with density remaining constant, would increase the speed of sound within the material, given that the speed of sound is proportional to the square root of the bulk modulus.

The speed of sound within a substance is primarily determined by two physical properties of the material, namely the bulk modulus and density. The bulk modulus measures a substance’s resistance to uniform compression. The formula used to calculate the speed of sound within a substance is v = sqrt(B/p), where 'v' represents the speed of sound, 'B' signifies the bulk modulus of the material, and 'p' indicates the density of the material.

As such, if the bulk modulus of a material were to increase while the density remained constant, the speed of sound within that material would also increase because the speed of sound is directly proportional to the square root of the bulk modulus. For instance, since solids and liquids are generally more rigid (i.e., have higher bulk modulus values) than gases, the speed of sound tends to be greater in these media than in gases, assuming density remains constant.

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The correct answer is a) droughts. Hurricanes are typically associated with heavy rain and high winds, which can lead to flooding.

Hurricanes are powerful storms that cause a variety of hazards, including inland flooding, storm surges, and tornadoes.

Inland flooding can occur when the heavy rainfall associated with a hurricane overflows rivers and streams. Storm surges are the rise in sea level that happens when a hurricane's strong winds push water onshore. This can cause significant flooding and damage in coastal areas. Tornadoes can be produced by hurricanes when thunderstorms present within the hurricane system become severe.

However, droughts are not typically a direct result of hurricanes. In fact, the heavy rainfall associated with hurricanes often alleviates drought conditions.

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The elevation difference is 55.3 mm when a pressure of 98.0 Pa (gage) is applied to the right tube of the manometer, displacing water downward and kerosene upward.

When a pressure of 98.0 Pa (gage) is applied to the right tube of the manometer, the water in the right tube is displaced downward by the same distance that the kerosene in the left tube is displaced upward, maintaining equilibrium.

To find the elevation difference, we can use the hydrostatic pressure formula:

P = ρgh

Where:

P = pressure difference (98.0 Pa in this case)

ρ = density of the fluid (for water, ρ_water ≈ 1000 kg/m³, for kerosene, ρ_kerosene ≈ 820 kg/m³)

g = acceleration due to gravity (approximately 9.81 m/s²)

h = elevation difference

Since the water and kerosene columns have opposite elevation changes, we can write:

98.0 Pa = (ρ_water * g * h) - (ρ_kerosene * g * h)

Now, solve for h:

98.0 Pa = (1000 kg/m³ * 9.81 m/s² * h) - (820 kg/m³ * 9.81 m/s² * h)

98.0 Pa = (9810 h) - (8034 h)

98.0 Pa = 1776 h

h = 98.0 Pa / 1776 = 0.0553 meters = 55.3 mm

So, when a pressure of 98.0 Pa (gage) is applied to the right tube, the elevation difference between the two free surfaces in the manometer is 55.3 mm.

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Answer: Option (c) is the correct answer.

Explanation:

Compounds which contain carbon and hydrogen atoms are known as organic compounds.

As general chemical formula of alcohols is R-OH, where R = any alkyl or aryl group.

For example, [tex]CH_{2}CH_{2}OH[/tex] is known as ethanol and it is an alcohol as it contains the functional group "-OH".

So, alcohols contains elements carbon, hydrogen and oxygen.

Thus, we can conclude that alcohols are organic compounds that contain carbon, oxygen, and hydrogen.

To solve this problem, we use the formula:

I100 / I1 = [P / 4π(100m)^2] / [P / 4π(1m)^2]

I100 / I1 = 1 / 100^2

I100 / I1 = 10^-4

Therefore the change in intensity from 1m to 100m in decibels is:

B100 – B1 = 10 log(10^-4) dB = -40 dB

So the intensity at 100m is calculated as:

B100 = B1 – 40 dB = 140 dB – 40 dB = 100 dB

Answer:

100 dB

The intensity of the sound produced due to the firecracker at the distance of [tex]100\text{ m}[/tex] is [tex]\fbox{\begin\\100\text{ dB}\end{minispace}}[/tex].

Further Explanation:

The vibration, produced in the medium, which travels as an wave of pressure or density through a medium is known as sound. The sound is a longitudinal wave and it requires a medium for its propagation.  

Given:

The distance between the place where firecracker is set off by a child and the family house is [tex]100\text{ m}[/tex].  

The intensity of the sound produced by the firecracker at the distance [tex]1\text{ m}[/tex] is[tex]140\text{ dB}[/tex].

Concept:

The intensity of the sound wave is defined as the power carried by the sound waves in the direction perpendicular to the direction of propagation per unit time.

The intensity of the sound wave is:

[tex]\fbox{\begin\\I=\dfrac{P}{4\pi r^2}\end{minispace}}[/tex]                                                        ...... (1)

Here, [tex]I[/tex] is the intesnity of the sound wave, [tex]P[/tex] is the power carried by the sound wave and [tex]r[/tex] is the distance between source and the listener.

The intensity of the sound in decible at the house is:

[tex]\fbox{\begin\\\beta _{100}=\beta _{1}+10\log \dfrac{I_{100}}{I_{1}}\end{minispace}}[/tex] ...... (2)

Here, [tex]\beta _{100}[/tex] is the intensity of the sound at the distance of [tex]100\text{ m}[/tex], [tex]\beta _{1}[/tex] is the intensity of sound produced by the firecracker at the distance of [tex]1\text{ m}[/tex], [tex]I_{100}[/tex] is the intensity of sound produced by firecracker at [tex]100\text{ m}[/tex] and [tex]I_{1}[/tex] is the intensity of sound produced by firecracker at [tex]1\text{ m}[/tex].

The ratio of the intensity of sound at distance [tex]100\text{ m}[/tex] and [tex]1\text{ m}[/tex] is:

[tex]\fbox{\begin\\\dfrac{{{I_{100}}}}{{{I_1}}}=\frac{{r_1^2}}{{r_2^2}}\end{minispace}}[/tex]                                                                                     …… (3)

Calculation:

Substitute the values in equation (3).

[tex]\begin{aligned}\frac{{{I_{100}}}}{{{I_1}}}&=\frac{{{{\left( 1 \right)}^2}}}{{{{\left( {100} \right)}^2}}}\\&={10^{ - 4}}\\\end{aligned}[/tex]

Substitute the values in equation (2).

[tex]\begin{aligned}{\beta _{100}}&=140\,{\text{dB}} - 40\,{\text{dB}} \\&=100\,{\text{dB}}\\\end{aligned}[/tex].

Thus, the intensity of the sound produced due to the firecracker at the distance of [tex]100\text{ m}[/tex] is [tex]\fbox{\begin\\100\text{ dB}\end{minispace}}[/tex]

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1.  The motion of a body under friction brainly.com/question/4033012

2.  A ball falling under the acceleration due to gravity brainly.com/question/10934170

3. Conservation of energy brainly.com/question/3943029

Answer Details:

Grade: College

Subject: Physics

Chapter: Waves and Oscillation

Keywords:

Intensity of sound, sound waves, vibration, firecracker, power carried by sound waves, 100db, 100 dB, 100dB, 100 m, bursting of firecrackers, sound inside the house, 140 db, 140 dB.

A star with an initial mass of 10 solar masses will likely form a neutron star instead of a black hole after a supernova due to the mutual repulsion between densely packed neutrons that can support the core against its own gravitational weight.

Given a star with initial 10 solar masses that ends its life in a supernova explosion, it is more likely to form a neutron star rather than a black hole. Most stars end their life as white dwarfs or neutron stars. In the case of a very massive star, if the core's remaining mass is more than about three times that of the Sun, it may collapse into a black hole. However, if the mass is less than about three solar masses, the mutual repulsion between densely packed neutrons can support the core against its own weight, preventing it from becoming a black hole.

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The compression forces acting on both sides of the center board = 70.338 N

The force acting on a system with static equilibrium is 0

[tex] \large {\boxed {\bold {\sum F = 0}} [/tex]

(forces acting as translational motion only, not including rotational forces)

[tex] \displaystyle \sum F_x = 0 \\\\\ sum F_y = 0 [/tex]

For objects undergoing rotation, the equilibrium must be met

[tex] \large {\boxed {\bold {\sum \tau = 0}} [/tex]

The force acting on the touchpad between the two fields is called the normal force  (N)

While the frictional force arises because of 2 objects that come into direct contact, especially when there is motion between two objects that are in direct contact.

There are 2 friction forces

The board sandwiched between two other boards will not fall if

a downward force = an upward force

or ΣFy = 0 (idle / equilibrium)

so that

A downward force = weight of the board sandwiched = 87.5 N

An upward force = arises from two static friction forces namely: us.N (N =  reaction force of the compression forces=F) ---> us.F

then the force that works can be stated:

EFy = 0

W = 2fs

W = 2 (us.F)

87.5 N = 2 (0.622. F)

F = 70,338 N

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In Texas, the speed limit in urban districts is generally set at 30 mph unless otherwise posted. This means that unless there are signs indicating a different speed limit, drivers are expected to adhere to a maximum speed of 30 miles per hour when traveling through urban areas. Therefore, the correct answer is A. 30 mph.

The rationale behind setting a default speed limit for urban districts is to promote safety for both motorists and pedestrians. Urban areas typically have higher population densities, increased pedestrian activity, and more complex traffic patterns compared to rural or suburban areas. As a result, lower speed limits help reduce the risk of accidents, particularly those involving pedestrians and cyclists.

By setting a default speed limit of 30 mph in urban districts, Texas law aims to create safer environments for all road users. However, it's essential for drivers to remain vigilant and observant of posted speed limit signs, as speed limits may vary depending on factors such as road conditions, proximity to schools or residential areas, and construction zones.

Overall, the default speed limit of 30 mph in urban districts reflects a balance between ensuring efficient traffic flow and prioritizing the safety of all individuals on the road. Therefore, the correct answer is A. 30 mph.

The complete question is:

In Texas, the speed limit in urban districts is _______ unless otherwise posted.

A. 30 mph

B. 50 mph

C. 40 mph

D. 25 mph

The sunlight is absorbed more on to the black color and no color is reflected back therefore, heat energy is released by the black color and make more hot.

When a light ray is incident on a transparent or translucent material, the light ray will return back after some fraction of it is absorbed on the material and the light ray travel in the straight direction from the material make it gleams.

White light absorbs all colors and reflects back all colors. Thus, the mixing of all reflected colors make the material white in color. A black light absorbs all colors and reflect no color.

The absorbed light energy in the black body is released as heat energy instead. This make the black colored material more hotter than other colors. Hence, a black shirt is most affected by sunlight.

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The loss in kinetic energy in an inelastic collision is equal to 251104 J.

According to the law of conservation of linear momentum, the sum of the momentum before and after an inelastic collision must be equal.

m₁u₁ + m₂ u₂ =   m₁ v₁ + m₂ v₂

where m₁ and m₂ is the mass of the collided bodies, u₁ & u₂ are their initial speed while v₁ & v₂ is their final speed.

Given the initial velocity of the truck is v₁ = 27 m/s and the other car is at rest, u₂ = 0 m/s.

The mass of the truck, m₁ = 1490 Kg

The mass of the stationary car, m₂ = 1280 Kg

From the law of conservation of momentum, find the final speed after a collision:

m₁ u₁ + m₂ u₂ = (m₁ + m₂)v'

1490 × 27 + 1280 ×0 = (1490 + 1280) v'

v' = 14.52 m/s

The loss in the kinetic energy = [tex]=\frac{1}{2} mv_1^2-\frac{1}{2} (m_1+m_2)^2v^'^2[/tex]

[tex]==\frac{1}{2} \times 1490\times(27)^2-\frac{1}{2} (2770)^2(14.52)^2[/tex]

[tex]= 543105 -292000\\=251104 J[/tex]

Therefore, the loss in the kinetic energy in the collision is equal to 251104 J.

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Answer:

Speed is slightly greater than 14 m/s.          

Explanation:

The ball will under go projectile motion. The horizontal velocity remains constant while there would be increase in vertical velocity due to acceleration due to gravity in downward direction.

Using first equation of motion, after 1 s, vertical velocity will be:

v = u +at

v=0+(9.8 m/s²)(1 s) = 9.8 m/s

Horizontal velocity = 10 m/s

Net velocity:

[tex]V= \sqrt{(9.8)^2+(10)^2}=\sqrt{196.04}=14.001 m/s[/tex]

Speed is slightly greater than 14 m/s.