Leon watched a beetle and a spider on the sidewalk the beetle crawled 2 yards and the spider crawled 1/6 of the yard how much further did the beetle crawled in the spider

Answers

Answer 1
The spider crawled 1/6 of a yard and the beetle crawled 2 yards. To find how much further the beetle crawled, you need to find the difference between these two numbers.

2yards - 1/6 yards = 1 5/6 yards

This means that the beetle crawled 1 whole yard and 5/6 of another yard further than the spider.
Answer 2

The beetle crawled 11/6 yards, or 1 and 5/6 yards, further than the spider.

The question asks how much further the beetle crawled compared to the spider. The beetle crawled 2 yards, and the spider crawled 1/6 of a yard. To find out how much further the beetle crawled, we subtract the distance the spider crawled from the distance the beetle crawled.

Step 1: Convert the distances to the same unit, if necessary. Here, both distances are already in yards, so no conversion is needed.

Step 2: Subtract the spider's distance from the beetle's distance: 2 yards - 1/6 yard.

Step 3: Calculate the difference: 2 yards - 1/6 yard = 12/6 yards - 1/6 yard = 11/6 yards.

Therefore, the beetle crawled 11/6 yards, or 1 and 5/6 yards, further than the spider.


Related Questions

Find the number of interest periods required to achieve the conditions set forth. A = $5,000 P = $2,000 interest is 5% compounded semiannually

Answers

The formula is
A=p (1+r/k)^n
A 5000
P 2000
R interest rate 0.05
K compounded semiannually 2
N number of interest periods=kt= 2t
5000=2000 (1+0.05/2)^2t
Solve for t
5000/2000=(1+0.05/2)^2t
Log (5000/2000)=2t×log (1+0.05/2)
2t=Log (5000/2000)÷log (1+0.05/2)
T=(log(5,000÷2,000)÷log(1+0.05÷2))÷2
T=18.55 years round your answer to get 19 years

So the number of interest periods required to achieve the conditions set forth is
N=kt
N=2×19
N=38

vito just put some money into a cd that pays 12.7 interest compound quarterly. according to the rule of 72,in the approximately how years will he have 4 times the amount of money that he has now

Answers

Answer:

11.34 years.

Step-by-step explanation:

We have been Vito put some money into a cd that pays 12.7 interest compound quarterly.

Since the rule of 72 states that to find the number of years it will take an amount to double, we need to divide 72 by annual interest rate.

First of all let us find the number of years it will take to double Vito's money by dividing 72 by 12.7.

[tex]\text{Time it will take to double Vito's money}=\frac{72}{12.7}[/tex]

[tex]\text{Time it will take to double Vito's money}=5.66929133858\approx 5.669[/tex]    

Since it will take 5.669 years to double Vito's money, so to find the time it will take Vito to have 4 times the money, we will multiply 5.669 by 2.

[tex]\text{Time it will take to have 4 times Vito's money}=5.669*2[/tex]

[tex]\text{Time it will take to have 4 times Vito's money}=11.338\approx 11.34[/tex]  

Therefore, approximately in 11.34 years Vito will have 4 times the amount of money that he has now.

Write the ratio of 4 teachers to 134 students in simplest form.?

Answers

It would be 4/134, and simplified that is 2/67.

So it would be 2 teachers to 67 students

divide 134/4 = 33.5 that would be 1/33.5

since you can't have .5 student, multiply each side by 2

33.5*2 = 67

 so 2/67 would be the simplest form using whole numbers


A Way to write numbers by using the digits 0-9, with each digit havin a place value
______ ?

Answers

Standard Form is a way to write numbers by using the digits 0-9, with each digit having a place value.

This way is the common way we usually use to write numbers. Other ways include the written form and the expanded form.

Take 100 as an example:
Standard form : 100
Written form : one hundred
Expanded form :  50 + 30 + 20

The surface areas of two similar solids are 340 yd2 and 1,158 yd2. The volume of the larger solid is 1,712 yd3. What is the volume of the smaller solid?

Answers

Let us say that,

1 = smaller solid

2 = larger solid

We must remember that the surface area of an object is proportional to the square of their sides, therefore,

SA = k s^2

where k is the constant of proportionality.

By taking the ratio of the 2 similar solids:

SA2 / SA1 = k s2^2 / k s1^2

SA2 / SA1 = s2^2 / s1^2

sqrt (SA2 / SA1) = s2 / s1

s2 / s1 = sqrt (1158 / 340)


While the volume of an object is proportional to the cube of their sides, therefore:

V = k’ s^3
where k’ is the constant of proportionality.

By taking the ratio of the 2 similar solids:

V2 / V1 = k’ s2^3/ k’ s1^3

V2 / V1 = s2^3/ s1^3

1712 / V1 = [sqrt (1158 / 340)]^3

1712/V1 = 6.28556705

V1 = 272.37 yd^3

A 34 - m tall building casts a shadow. The distance from the top of the building to the tip of the shadow is 36 m . Find the length of the shadow. If necessary, round your answer to the nearest tenth.

Answers

a^2 + b^2 = c^2
34^2 + b^2 = 36^2
1156 + b^2 = 1296
b^2 = 1296 - 1156
b2 = 140
b = sqrt 140
b = 11.8 m <==

Answer:

Length of the shadow is 11.8 meters.

Step-by-step explanation:

In the figure attached,

AB is a 34 meter tall building casting a shadow BC.

Let the measure of BC = x meters

It is given that the distance between A and C is 36 meters.

To find the length of BC we will apply Pythagoras theorem in the triangle.

AB² + BC² = AC²

(34)² + x² = (36)²

1156 + x² = 1296

x² = 1296 - 1156

x² = 140

x = √140

x = 11.832 meters

  ≈ 11.8 meters

Therefore, length of the shadow will be 11.8 meters.

A league of 19 teams is playing a "round-robin" style tournament, where each team plays every other team exactly once. How many games total need to be played? Justify your answer using a graph model—say what the vertices and edges of your graph represent, and what (if any) theorems you use. (Upload your file below.)

Answers

[tex]_{19}\text{C}_2=171[/tex] games. For your graph, put 19 vertices and connect them all together once. The vertices are the teams and the edges are the games.

what is the least common multiple of 20 and 52

Answers

The LCM of 20 and 52 is 260
hope this helps:)

The least common multiple of 20 and 52 is, 420

What is Least common multiple?

The Least common multiple of two or more numbers are the smallest number that is multiple of two or more numbers.

Given that;

The numbers are,

⇒ 20 and 52

Now, The factors of numbers are,

⇒ 20 = 2 × 2 × 5

⇒ 42 = 2 × 3 × 7

Hence, The least common multiple of 20 and 52 is,

⇒ LCM of {20, 52} = 2 × 2 × 5 × 3 × 7

                             = 420

Thus, The least common multiple of 20 and 52 is, 420

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4.4 mi/h how many ft/s

Answers

Answer:

  about 6.45 ft/s

Step-by-step explanation:

The conversion factor for mph to fps is ...

  1 mph = 22/15 fps

Multiplying by 4.4 gives ...

  4.4 mph = 96.8/15 fps = 484/75 fps = 6 34/75 fps

  ≈ 6.4533333... ft per second

an ellipse has a center at the origin, a vertex along the major axis at (13, 0), and a focus at (12, 0). What is the equation of the ellipse?

Answers

Answer:  The equation of the ellipse is

[tex]\dfrac{x^2}{169}+\dfrac{y^2}{25}=1.[/tex]

Step-by-step explanation:  We are given to find the equation of an ellipse that has a center at the origin, a vertex along the major axis at (13, 0) and a focus at (12, 0).

Since the focus lies on the X-axis, so the standard equation of an ellipse with major axis as X-axis is given by

[tex]\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

According to given information, we have

a vertex along the major axis, (a, 0) = (13, 0)  

⇒ length of the major axis, a = 13,

co-ordinates of focus, (c, 0) = (12, 0)

⇒ c = 12.

We know that

[tex]c^2=a^2-b^2.[/tex]

Therefore,

[tex]12^2=13^2-b^2\\\\\Rightarrow 144=169-b^2\\\\\Rightarrow b^2=169-144\\\\\Rightarrow b^2=25\\\\\Rightarrow b=5.[/tex]

Thus, from equation (i), we get

[tex]\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\\\\\\\Rightarrow \dfrac{x^2}{13^2}+\dfrac{y^2}{5^2}=1\\\\\\\Rightarrow \dfrac{x^2}{169}+\dfrac{y^2}{25}=1.[/tex]

The equation of the ellipse is

[tex]\dfrac{x^2}{169}+\dfrac{y^2}{25}=1.[/tex]

The equation of the ellipse along the major axis at (13, 0), and a focus at (12, 0) is; x²/169 + y²/25 = 1

Equation of an ellipse

The equation of an ellipse whose center is the origin, (0,0) usually takes the form;

x²/a² + y²/b² = 1

The coordinates of the vertex on the major axis is given as; (13,0) and the focus at (12,0)

Hence, the square of the length of the minor axis;

b² = a² - c²

b² = 169 - 144

b² = 25.

Hence, the equation of the described ellipse is;

x²/169 + y²/25 = 1

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What is the eighth term of the geometric sequence 4,-20,100,...?

Answers

The eighth term of the geometric sequence 4, -20, 100,... is 9600, calculated using the formula aₙ = arⁿ⁻¹ with a = 4, r = -5, and n = 8.

The eighth term of the geometric sequence 4, -20, 100,... is 9600.

To find the eighth term of a geometric sequence, you can use the formula: aₙ = arⁿ⁻¹, where a is the first term, r is the common ratio, and n is the term number. In this case, a = 4, r = -5, and n = 8.

Plug the values into the formula: 4 x (-5)⁸⁻¹ = 9600.

if the GCF of two numbers is 1, they are called relatively prime. Find three sets of relatively prime numbers

Answers

The GCF can be obtained by taking the prime factors of two numbers then multiplying the common prime factors. IF there are none, then the GCF is 1 and the numbers are called relatively prime.

There are a lot of relatively prime numbers. To name three sets:

3 and 19

7 and 20

15 and 28

 

For these sets, we see that there are no other common factors except 1. To illustrate the factors:

3 = 1, 3

19 = 1, 19

 

7 = 1, 7

20 = 1, 2, 2, 5

 

15 = 1, 3, 5

28 = 1, 2, 2, 7

 

So we see that only the number 1 is the factor in each set.

Final answer:

Three sets of relatively prime numbers are 9 and 16, 14 and 25, and 8 and 21, as they do not share any common prime factors other than 1.

Explanation:

If the Greatest Common Factor (GCF) of two numbers is 1, they are indeed referred to as relatively prime. To find sets of relatively prime numbers, we need to identify pairs of numbers that do not have any prime factors in common other than 1.

9 and 16: The prime factors of 9 are 3· 3, and the prime factors of 16 are 2· 2· 2· 2. They share no common prime factors, so they are relatively prime.

14 and 25: The prime factors of 14 are 2· 7, and the prime factors of 25 are 5· 5. Since they have no common factors, these numbers are also relatively prime.

8 and 21: The prime factors of 8 are 2· 2· 2, and the prime factors of 21 are 3· 7. With no prime factors in common, 8 and 21 are relatively prime.

Therefore, we have found three sets of relatively prime numbers: 9 and 16, 14 and 25, and 8 and 21.

the slope of a line is 2/3. what is the slope of a line that is perpendicular to this line? Type a numerical answer in the space provided. do not include spaces in your answer. if necessary, use the / key to represent a fraction bar and only type improper fractions (no mixed numbers).

Answers

-3/2 is the perpendicular slope since thats the opposite reciprocal of 2/3

A tree is 6 feet 4 inches tall. How tall is it in inches?

Answers

 1 feet has 12 inches...so 6feet multiply by 12 inches is equal to 72 inches....But Be Careful!!! We also have 4 inches...so, we are suppose to add those 4 inches to 72 inches as well. So, 72+4 =76 inches....Hence, 76 inches is your final answer..


The number of inches in 6 feet 4 inches tall is 76 inches.

Given that, a tree is 6 feet 4 inches tall.

Metric Conversion refers to the conversion of the given units to desired units for any quantity to be measured.

We know that, 1 feet = 12 inches

So, 6 feet = 6×12

= 72 inches

Now, in inches = 72+4

= 76 inches

Therefore, the number of inches in 6 feet 4 inches tall is 76 inches.

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can someone pls answer

Answers

9y = -11x +36

 y = -11/9 +4

y = 4

which number is a factor of 20, but not a multiple of 2? 12, 5, 10 or 4?

Answers

5 is your answer

20/4 = 5 however,

2 x 2.5 = 5 (it doesn't work, cannot have decimals)

so 5 is your answer

hope this helps
factors of 20 are: 1,20:2,10:4,5.
So 1 or 20 is that number

Rewrite sin 15 degree in terms of a 75 degree angle and in terms of the reciprocal of a trigonometric function.

Answers

[tex]\bf csc(\theta)=\cfrac{1}{sin(\theta)} \\\\\\ sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})\\\\ -------------------------------\\\\ sin(15^o)\implies sin(45^o-30^o) \\\\\\ sin(45^o)cos(30^o)-cos(45^o)sin(30^o)[/tex]

[tex]\bf \cfrac{\sqrt{2}}{2}\cdot \cfrac{\sqrt{3}}{2}-\cfrac{\sqrt{2}}{2}\cdot \cfrac{1}{2}\implies \cfrac{\sqrt{6}}{4}-\cfrac{\sqrt{2}}{4}\implies \cfrac{\sqrt{6}-\sqrt{2}}{4}\\\\ -------------------------------\\\\ csc(15^o)=\cfrac{1}{sin(15^o)}\implies csc(15^o)=\cfrac{1}{\frac{\sqrt{6}-\sqrt{2}}{4}} \\\\\\ csc(15^o)=\cfrac{4}{\sqrt{6}-\sqrt{2}}[/tex]

and now, we can rationalize the denominator by using its conjugate and difference of squares.

[tex]\bf \cfrac{4}{\sqrt{6}-\sqrt{2}}\cdot \cfrac{\sqrt{6}+\sqrt{2}}{\sqrt{6}+\sqrt{2}}\implies \cfrac{4(\sqrt{6}+\sqrt{2})}{(\sqrt{6}-\sqrt{2})(\sqrt{6}+\sqrt{2})} \\\\\\ \cfrac{4(\sqrt{6}+\sqrt{2})}{(\sqrt{6})^2-(\sqrt{2})^2}\implies \cfrac{4(\sqrt{6}+\sqrt{2})}{6-2}\implies \boxed{\sqrt{6}+\sqrt{2}}[/tex]

Would you measure walls using inches or yards

Answers

Yards because inches are too small walls are normally really long and wide and using inches wouldn't be wise in this case.
Well what would u rather use, inches or feet. I think feet is a better option. There are 3 feet in a yard which makes yards the best option between inches and yards. Inches is just way too small

Two parallel lines are crossed by a transversal. What is the value of x?
A. x = 12
B. x = 14
C. x = 22
D. x = 24

Answers

5x + 5 + 115 = 180
5x + 120 = 180
5x = 180 - 120
5x = 60
x = 60/5
x = 12

Answer

x = 12


Explanation

The two given angles are supplementary angles. That means that the add up to 180 degrees.

(5x + 5) + 115 = 180

5x +5 + 115 = 180

5x + 120 = 180

5x= 180 - 120

5x = 60

x = 12

Find the amount of time to the nearest day it would take a deposit of $1300 to grow to 1 million at 17% compounded continuously. The amount of time it would take to grow the deposit to $1 million is____ years ___ days

Answers

[tex]\bf \qquad \textit{Simple Interest Earned}\\\\ A = Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\to 1000000\\ P=\textit{original amount deposited}\to& \$1300\\ r=rate\to 17\%\to \frac{17}{100}\to &0.017\\ t=years \end{cases}[/tex]

[tex]\bf 1000000=1300e^{0.17t}\implies \cfrac{1000000}{1300}=e^{0.17t}\implies \cfrac{10000}{13}=e^{0.17t} \\\\\\ ln\left( \frac{1000000}{1300} \right)=ln(e^{0.17t})\implies ln\left( \frac{1000000}{1300} \right)=0.17t \\\\\\ \cfrac{ln\left( \frac{1000000}{1300} \right)}{0.17}=t\impliedby years[/tex]

now, how many days? simply multiply t * 365.

It would take approximately 39 years and 183 days for the deposit to grow to $1 million.

Use the concept of compound interest defined as:

The interest that is computed using both the principal and the interest that has accrued during the previous period is called compound interest. It differs from simple interest in that the principal is not taken into account when determining the interest for the subsequent period with simple interest.

Given that,

Initial deposit: $1300

Target amount: $1 million

Interest rate: 17%

Compounding: Continuous

Time to calculate: To the nearest day

To find the amount of time it would take,

Use the formula:

[tex]t = \dfrac{ln(\frac{M}{P})}{r}[/tex]

Where,

t = time in years

M = final amount ($1 million)

P = initial deposit ($1300)

r = interest rate (17% or 0.17)

Find the natural logarithm of the ratio M/P:

ln(1,000,000 / 1,300) ≈ 6.64

Divide the result by the interest rate:

t = 6.64 / 0.17

t ≈ 39.05 years

So, it would take approximately 39 years to grow the deposit to $1 million.

To determine the number of days,

Multiply the decimal part of the years by 365 (assuming a non-leap year):

0.05 x 365 ≈ 183 days

Hence,

Rounding to the nearest day, it would take approximately 39 years and 183 days for the deposit to grow to $1 million.

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There are 9 more pencils then pens in a container. There are 25 writing utensils in the container in all. How many pens are there in the container?

Answers

In order to determine the number of pens present in the container, we need to set up equations from the given in the problem statement. We do as follows:

let x the number of pencils
    y the number of pens

From the statement, 9 more pencils then pens in a container,

x = y + 9

From the statement, there are 25 writing utensils in the container in all,

x + y = 25

We use substitution method to calculate for x and y,

y + 9 + y = 25
2y = 16
y = 8
x = 17

Therefore, there are 8 pens in the container and 17 pencils.

The Canadian $1 coin has a diameter of 26.5 mm.what is the circumference of the coin?use 3.14 for pie

Answers

circumference = diameter x PI

26.5*3.14 = 83.21 mm

Answer: 83.21 mm

Step-by-step explanation:

The circumference of a circle is given by :-

[tex]\text{Circumference }=\pi d[/tex]

Given : The Canadian $1 coin has a diameter of 26.5 mm.

Then , the circumference of the coin will be :-

[tex]\text{Circumference of coin}=\pi (26.5)=(3.14)(26.5)\\\\\Rightarrow\text{Circumference of coin}=83.21\text{ mm}[/tex]

Hence, the circumference of the coin is 83.21 mm

Six years from today you need $10,000. you plan to deposit $1,500 annually, with the first payment to be made a year from today, in an account that pays an 8% effective annual rate. your last deposit, which will occur at the end of year 6, will be for less than $1,500 if less is needed to reach $10,000. how large will your last payment be?

Answers

Like this variation of the problem! :)

We calculate the future value of the 6 annual deposits of $1500 at 8%:
F=1500(1.08^6-1)/(0.08)=11003.89
Since the last payment is due on the day of withdrawal, he would have paid $1500 to get back $11003.89, i.e. with an excess of 1003.89.
Therefore his last payment is 1500-1003.89=$496.11

Amount of last payment is approximately $497

Given that;

Number of year = 6 year

Annual deposit = $1,500

Annual rate = 8% = 0.08

Find:

Amount of last payment

Computation:

[tex]Future\ value = Annual\ deposit[(1+r)^n - 1]/r[/tex]

[tex]Future\ value\ of\ the\ 6\ annual\ deposits = 1500[\frac{(1+0.08)^6 - 1}{0.08}][/tex]

[tex]Future\ value\ of\ the\ 6\ annual\ deposits = 1500[(1.08)^6 - 1]/0.08\\\\Future value of the 6 annual deposits = 1500[0.58687]/0.08[/tex]

Future value of the 6 annual deposits = 11,003.25

Future value of the 6 annual deposits = $11,003 (Approx.)

Extra payment = 11,003 - 10,000

Extra payment = $1,003

So,

Amount of last payment = 1,500-1,003

Amount of last payment = $497

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For what value of a does 9=(1/27)^a+3

Answers

Given: 9=(1/27)^(a+3)

[Note:  Please review rules of PEMDAS.  
The question posted as is means
9=[(1/27)^a]+3 which is probably not what you mean.  It has been interpreted with (a+3) as the exponent, please check.]

Need to find value of a that satisfies above.

We will first isolate a in order to solve for its value.
9=(1/27)^(a+3)
Switch unknown to the left
(1/27)^(a+3) = 9
Since both 27 and 9 are powers of 3, we can take log to base 3.
take log (base 3) on both sides, applying rule of logarithm of exponents.
(a+3)log_3(1/27)=log_3(9)
(a+3)log_3(3^(-3))=log_3(3^2)
Apply definition of logarithm [log_a(a^k)=k]
(a+3)(-3)=2
(a+3)=-2/3
a=-3 2/3=-11/3

Check: (1/27)^(-11/3+3)=(1/27)^(-2/3)=(3^(-3))^(-2/3)=3^(-3(-2/3))=3^2=9 ok

Answer: a=-11/3 or a=-3.667 (approx.)

The value of a in the equation [tex]9=(\frac{1}{27})^{a+3}[/tex] is a = -11/3

Solving indical equations

The given equation is:

[tex]9=(\frac{1}{27})^{a+3}[/tex]

This can be rewritten as:

[tex]9=27^{-1(a+3)}[/tex]

Which can be further simplified as:

[tex]3^2=3^{-3(a+3)}[/tex]

Since the bases are equal, they cancel out

The equation becomes:

2  =  -3(a  +  3)

2  =  -3a  -  9

2+9  =  -3a

-3a  =  11

a  =  -11/3

Therefore, the value of a in the equation [tex]9=(\frac{1}{27})^{a+3}[/tex] is a = -11/3

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f(x) = 2/3 x -5 what is the value f(6)?

Answers

f(6)=2/3(6)-5
f(6)=4-5
f(6)=-1

Final answer: f(6)= -1

(1 point) suppose that the trace of a 2×22×2 matrix aa is tr(a)=−4tr(a)=−4, and the determinant is det(a)=0det(a)=0. find the eigenvalues of aa.

Answers

Suppose

[tex]\mathbf A=\begin{bmatrix}a&b\\c&d\end{cases}[/tex]

with [tex]\mathrm{tr}\,\mathbf A=a+d=-4[/tex] and [tex]\det\mathbf A=ad-bc=0[/tex]. We can find the eigenvalues of [tex]\mathbf A[/tex] in the usual way, by taking the determinant of [tex]\mathbf A-\lambda\mathbf I[/tex] and setting it equal to 0.

[tex]\begin{vmatrix}a-\lambda&b\\c&d-\lambda\end{vmatrix}=(a-\lambda)(d-\lambda)-bc=\lambda^2-(a+d)\lambda+(ad-bc)[/tex]

and we observe that the characteristic polynomial has linear coefficient [tex]-\mathrm{tr}\,\mathbf A[/tex] and constant coefficient [tex]\det\mathbf A[/tex]. Thus in this case we have the characteristic polynomial equation,

[tex]\lambda^2+4\lambda=\lambda(\lambda+4)=0\implies\lambda_1=0,\lambda_2=-4[/tex]

Which is least? 0.105 0.501 0.015 or 0.15

Answers

0.015 is the least. 

Because it is the farthest away from the one's place.
Final answer:

The lowest decimal number from 0.105, 0.501, 0.015, and 0.15 is 0.015. This is because when we compare the numbers from left to right, 0.015 has the smallest digit (0) at the second decimal place which is the hundredths place.

Explanation:

To determine which decimal number is the lowest, it's helpful to compare these numbers digit by digit from the left. The four numbers are 0.105, 0.501, 0.015, and 0.15. Each of them starts with 0. The second digit of 0.105, 0.501, and 0.15 is 1, but the second digit for 0.015 is 0. So, 0.015 is the lowest number because it has the smallest digit (0) in the second decimal place (hundredths place). Remember, these numbers are read as decimals and not as whole numbers, so the digit at each decimal place has a different significance.

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How is inductive reasoning used in geometry?

Answers

Answer:

Inductive reasoning draws general conclusions from specific details / observations - in other words, going from specific --> general.

Example:

Specific: I break out when I eat peanuts.

Observation: This is a symptom of being allergic.

General Conclusion: I am allergic to peanuts.

hope this helps! <3

Final answer:

Inductive reasoning in geometry involves observing patterns in specific instances and formulating general rules or hypotheses, such as the sum of angles in a triangle or the properties of parallel lines intersected by a transversal.

Explanation:

Inductive reasoning in geometry is used to derive broad generalizations from specific observations or instances. One way inductive reasoning is applied is by observing patterns or properties in a set of geometric figures and then formulating a hypothesis or general rule that applies to all similar figures. For example, after measuring the angles of several triangles and finding that they always add up to 180 degrees, one might assume that all triangles have this property. Another example is when looking at multiple parallel lines cut by a transversal and noticing the corresponding angles are equal, thus generalizing that this is the case for any parallel lines intersected by a transversal.



Scientists, including mathematicians, use inductive reasoning to construct hypotheses, which are then tested using deductive reasoning. The conclusions drawn from inductive reasoning may not always be correct, but they are essential for advancing scientific and mathematical knowledge by suggesting relationships and rules that can be rigorously tested.

81.54 is what percent of 75.5

Answers

Percent literally means per one hundred....

(p/100)(75.5)=81.54

75.5p/100=81.54  multiply both sides by 100

75.5p=8154  divide both sides by 75.5

p=8154/75.5

p=108%

....

check

75.5(108/100)=81.54

75.5(1.08)=81.54

81.54=81.54

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A vehicle factory manufactures cars. The unit cost C (the cost in dollars to make each car) depends on the number of cars made. If x cars are made, then the unit cost is given by the function C(x) =x^2-320x+40,052 . What is the minimum unit cost? Do not round your answer.

Answers

the C(x) equation is a parabola with a squared "x" and a positive leading term coefficient, meaning, is a vertical parabola and it opens upwards

the lowest point, or lowest cost value, it reaches, is the U-turn point, or vertex

[tex]\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\ \begin{array}{llccll} y = &{{ 1}}x^2&{{ -320}}x&{{ +40052}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)[/tex]

so, the lowest cost is at   [tex]\bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}[/tex]
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